patterns/idioms/dtor-finally.md
Kinsey Favre 396ae01fdd
Rewrite mentions of try! macro to use ? operator
The `try!` macro has been [deprecated since Rust 1.39.0][1] in favor of
the `?` operator; update text using it to reflect this.

[1]: https://doc.rust-lang.org/std/macro.try.html
2020-02-06 16:56:39 -06:00

3.5 KiB

Finalisation in destructors

Description

Rust does not provide the equivalent to finally blocks - code that will be executed no matter how a function is exited. Instead an object's destructor can be used to run code that must be run before exit.

Example

fn bar() -> Result<(), ()> {
    // These don't need to be defined inside the function.
    struct Foo;

    // Implement a destructor for Foo.
    impl Drop for Foo {
        fn drop(&mut self) {
            println!("exit");
        }
    }

    // The dtor of _exit will run however the function `bar` is exited.
    let _exit = Foo;
    // Implicit return with `?` operator.
    baz()?;
    // Normal return.
    Ok(())
}

Motivation

If a function has multiple return points, then executing code on exit becomes difficult and repetitive (and thus bug-prone). This is especially the case where return is implicit due to a macro. A common case is the ? operator which returns if the result is an Err, but continues if it is Ok. ? is used as an exception handling mechanism, but unlike Java (which has finally), there is no way to schedule code to run in both the normal and exceptional cases. Panicking will also exit a function early.

Advantages

Code in destructors will (nearly) always be run - copes with panics, early returns, etc.

Disadvantages

It is not guaranteed that destructors will run. For example, if there is an infinite loop in a function or if running a function crashes before exit. Destructors are also not run in the case of a panic in an already panicking thread. Therefore destructors cannot be relied on as finalisers where it is absolutely essential that finalisation happens.

This pattern introduces some hard to notice, implicit code. Reading a function gives no clear indication of destructors to be run on exit. This can make debugging tricky.

Requiring an object and Drop impl just for finalisation is heavy on boilerplate.

Discussion

There is some subtlety about how exactly to store the object used as a finaliser. It must be kept alive until the end of the function and must then be destroyed. The object must always be a value or uniquely owned pointer (e.g., Box<Foo>). If a shared pointer (such as Rc) is used, then the finaliser can be kept alive beyond the lifetime of the function. For similar reasons, the finaliser should not be moved or returned.

The finaliser must be assigned into a variable, otherwise it will be destroyed immediately, rather than when it goes out of scope. The variable name must start with _ if the variable is only used as a finaliser, otherwise the compiler will warn that the finaliser is never used. However, do not call the variable _ with no suffix - in that case it will be again be destroyed immediately.

In Rust, destructors are run when an object goes out of scope. This happens whether we reach the end of block, there is an early return, or the program panics. When panicking, Rust unwinds the stack running destructors for each object in each stack frame. So, destructors get called even if the panic happens in a function being called.

If a destructor panics while unwinding, there is no good action to take, so Rust aborts the thread immediately, without running further destructors. This means that desctructors are not absolutely guaranteed to run. It also means that you must take extra care in your destructors not to panic, since it could leave resources in an unexpected state.

See also

RAII.