remove extra `that`

09/README.md

@@ -67,7 +67,7 @@ To determine if our thread is in an odd or even row, we are going to use [```mod
 // y = mod(x,2.0) < 1.0 ? 0. : 1. ;
 // y = step(1.0,mod(x,2.0));"></div>
 
-As you can see we can use a [ternary operator](https://en.wikipedia.org/wiki/%3F:) to check if the [```mod()```](../glossary/?search=mod) of ```2.0``` is under ```1.0``` (second line) or similarly we can use a [```step()```](../glossary/?search=step) function which does that the same operation, but faster. Why? Although is hard to know how each graphic card optimizes and compiles the code, it is safe to assume that built-in functions are faster than non-built-in ones. Everytime you can use a built-in function, use it!
+As you can see we can use a [ternary operator](https://en.wikipedia.org/wiki/%3F:) to check if the [```mod()```](../glossary/?search=mod) of ```2.0``` is under ```1.0``` (second line) or similarly we can use a [```step()```](../glossary/?search=step) function which does the same operation, but faster. Why? Although is hard to know how each graphic card optimizes and compiles the code, it is safe to assume that built-in functions are faster than non-built-in ones. Everytime you can use a built-in function, use it!
 
 So now that we have our odd number formula we can apply an offset to the odd rows to give a *brick* effect to our tiles. Line 14 of the following code is where we are using the function to "detect" odd rows and give them a half-unit offset on ```x```. Note that for even rows, the result of our function is ```0.0```, and multiplying ```0.0``` by the offset of ```0.5``` gives an offset of ```0.0```. But on odd rows we multiply the result of our function, ```1.0```, by the offset of ```0.5```, which moves the ```x``` axis of the coordinate system by ```0.5```.