mirror of
https://github.com/rust-lang/rustlings
synced 2024-11-05 00:00:12 +00:00
c859550e6c
👍 👍 👍 Connects to #6
54 lines
1.3 KiB
Rust
54 lines
1.3 KiB
Rust
// Make me compile without changing line 9! Scroll down for hints :)
|
|
|
|
pub fn main() {
|
|
let vec0 = Vec::new();
|
|
|
|
let mut vec1 = fill_vec(vec0);
|
|
|
|
// Do not change the following line!
|
|
println!("{} has length {} content `{:?}`", "vec0", vec0.len(), vec0);
|
|
|
|
vec1.push(88);
|
|
|
|
println!("{} has length {} content `{:?}`", "vec1", vec1.len(), vec1);
|
|
|
|
}
|
|
|
|
fn fill_vec(vec: Vec<i32>) -> Vec<i32> {
|
|
let mut vec = vec;
|
|
|
|
vec.push(22);
|
|
vec.push(44);
|
|
vec.push(66);
|
|
|
|
vec
|
|
}
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
// So `vec0` is being *moved* into the function `fill_vec` when we call it on
|
|
// line 6, which means it gets dropped at the end of `fill_vec`, which means we
|
|
// can't use `vec0` again on line 9 (or anywhere else in `main` after the
|
|
// `fill_vec` call for that matter). We could fix this in a few ways, try them
|
|
// all!
|
|
// 1. Make another, separate version of the data that's in `vec0` and pass that
|
|
// to `fill_vec` instead.
|
|
// 2. Make `fill_vec` borrow its argument instead of taking ownership of it,
|
|
// and then copy the data within the function in order to return an owned
|
|
// `Vec<i32>`
|
|
// 3. Make `fill_vec` *mutably* borrow its argument (which will need to be
|
|
// mutable), modify it directly, then not return anything. Then you can get rid
|
|
// of `vec1` entirely -- note that this will change what gets printed by the
|
|
// first `println!`
|