Handle high fees better during probing

pull/1/head
rkfg 2 years ago
parent b83a23d693
commit 245d17ca8e

@ -130,8 +130,9 @@ func (r *regolancer) probeRoute(ctx context.Context, route *lnrpc.Route, goodAmo
if probedRoute.TotalFeesMsat > maxFeeMsat {
if steps == 1 {
bestAmount := hiWhiteColor(goodAmount)
if goodAmount == 0 {
if goodAmount <= 0 {
bestAmount = hiWhiteColor("unknown")
goodAmount = 0
}
log.Printf("%s requires too high fee %s (max allowed is %s), best amount is %s", hiWhiteColor(amount),
hiWhiteColor(probedRoute.TotalFeesMsat/1000), hiWhiteColor(maxFeeMsat/1000), bestAmount)
@ -141,7 +142,9 @@ func (r *regolancer) probeRoute(ctx context.Context, route *lnrpc.Route, goodAmo
log.Printf("%s requires too high fee %s (max allowed is %s), increasing amount to %s, %s steps left",
hiWhiteColor(amount), hiWhiteColor(probedRoute.TotalFeesMsat/1000), hiWhiteColor(maxFeeMsat/1000),
hiWhiteColor(nextAmount), hiWhiteColor(steps-1))
return r.probeRoute(ctx, route, goodAmount, badAmount, nextAmount, steps-1, ratio)
// returning negative amount as "good", it's a special case which means this is
// rather the lower bound and the actual good amount is still unknown
return r.probeRoute(ctx, route, -amount, badAmount, nextAmount, steps-1, ratio)
}
fakeHash := make([]byte, 32)
rand.Read(fakeHash)
@ -170,13 +173,19 @@ func (r *regolancer) probeRoute(ctx context.Context, route *lnrpc.Route, goodAmo
if result.Failure.Code == lnrpc.Failure_TEMPORARY_CHANNEL_FAILURE {
if steps == 1 {
bestAmount := hiWhiteColor(goodAmount)
if goodAmount == 0 {
if goodAmount <= 0 {
bestAmount = hiWhiteColor("unknown")
goodAmount = 0
}
log.Printf("%s is too much, best amount is %s", hiWhiteColor(amount), bestAmount)
return goodAmount, nil
}
nextAmount := amount + (goodAmount-amount)/2
var nextAmount int64
if goodAmount >= 0 {
nextAmount = amount + (goodAmount-amount)/2
} else {
nextAmount = amount + (goodAmount+amount)/2
}
log.Printf("%s is too much, lowering amount to %s, %s steps left",
hiWhiteColor(amount), hiWhiteColor(nextAmount), hiWhiteColor(steps-1))
return r.probeRoute(ctx, route, goodAmount, amount, nextAmount, steps-1, ratio)

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