diff --git a/root/reflexion_mbpp_rs/mbpp-rs._reflexion_5_gpt-4_pass_at_k_1_rs.jsonl b/root/reflexion_mbpp_rs/mbpp-rs._reflexion_5_gpt-4_pass_at_k_1_rs.jsonl index ae207a9..57a1bf7 100644 --- a/root/reflexion_mbpp_rs/mbpp-rs._reflexion_5_gpt-4_pass_at_k_1_rs.jsonl +++ b/root/reflexion_mbpp_rs/mbpp-rs._reflexion_5_gpt-4_pass_at_k_1_rs.jsonl @@ -1,290 +1,354 @@ -{"name": "mbpp_234_volume_cube", "language": "rs", "prompt": "/// Write a function to find the volume of a cube given its side length.\nfn volume_cube(l: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_234_volume_cube.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "volume_cube", "test": "}\n\nfn main() {\n let candidate = volume_cube;\n assert_eq!(candidate(3), 27);\n assert_eq!(candidate(2), 8);\n assert_eq!(candidate(5), 125);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the volume of a cube given its side length.\nfn volume_cube(l: isize) -> isize {\n l.pow(3)\n}"} -{"name": "mbpp_89_closest_num", "language": "rs", "prompt": "/// Write a function to find the closest smaller number than n.\nfn closest_num(N: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_89_closest_num.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "closest_num", "test": "}\n\nfn main() {\n let candidate = closest_num;\n assert_eq!(candidate(11), 10);\n assert_eq!(candidate(7), 6);\n assert_eq!(candidate(12), 11);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the closest smaller number than n.\nfn closest_num(N: isize) -> isize {\n let mut closest = N - 1;\n\n while closest > 0 {\n if closest < N {\n return closest;\n }\n closest -= 1;\n }\n\n 0\n}"} -{"name": "mbpp_245_max_sum", "language": "rs", "prompt": "/// Write a function that takes a vector and finds the maximum sum of a bitonic subsequence for the given vector, where a sequence is bitonic if it is first increasing and then decreasing.\nfn max_sum(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_245_max_sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_sum", "test": "}\n\nfn main() {\n let candidate = max_sum;\n assert_eq!(candidate(vec![1, 15, 51, 45, 33, 100, 12, 18, 9]), 194);\n assert_eq!(candidate(vec![80, 60, 30, 40, 20, 10]), 210);\n assert_eq!(candidate(vec![2, 3, 14, 16, 21, 23, 29, 30]), 138);\n}\n", "solution": "/// Write a function that takes a vector and finds the maximum sum of a bitonic subsequence for the given vector, where a sequence is bitonic if it is first increasing and then decreasing.\nfn max_sum(arr: Vec) -> isize {\n let n = arr.len();\n if n == 0 {\n return 0;\n }\n\n let mut inc = vec![0; n];\n let mut dec = vec![0; n];\n\n for i in 0..n {\n inc[i] = arr[i];\n for j in 0..i {\n if arr[i] > arr[j] {\n inc[i] = inc[i].max(inc[j] + arr[i]);\n }\n }\n }\n\n for i in (0..n).rev() {\n dec[i] = arr[i];\n for j in i + 1..n {\n if arr[i] > arr[j] {\n dec[i] = dec[i].max(dec[j] + arr[i]);\n }\n }\n }\n\n let mut max_sum = inc[0] + dec[0] - arr[0];\n for i in 1..n {\n max_sum = max_sum.max(inc[i] + dec[i] - arr[i] * 2);\n }\n\n max_sum\n}", "is_solved": true, "reflections": ["The current implementation is incorrect because it assumes that the maximum sum bitonic subsequence will always include the first and last elements of the input vector. However, this is not always the case, as demonstrated by the failed test cases. The algorithm needs to be modified to consider all possible bitonic subsequences, not just those that start and end with the first and last elements.", "The current implementation is incorrect because it only considers the maximum sum of increasing and decreasing subsequences separately, without properly accounting for the bitonic nature of the sequence. This leads to incorrect results when the maximum sum bitonic subsequence is not formed by simply combining the maximum increasing and decreasing subsequences.", "The implementation is incorrect because it calculates the maximum sum of a bitonic subsequence by iterating through all possible subsequences, but it does not properly account for the decreasing part of the bitonic sequence. The loop that calculates the maximum sum does not correctly combine the increasing and decreasing subsequences, leading to incorrect results in some test cases.", "The current implementation is incorrect because it calculates the maximum sum of a bitonic subsequence by only considering the increasing and decreasing subsequences separately. It does not account for the possibility of having a single peak element that is part of both the increasing and decreasing subsequences, which leads to overcounting the peak element's value in the final sum. This causes the function to return incorrect results for some test cases."]} -{"name": "mbpp_77_is_Diff", "language": "rs", "prompt": "/// Write a rsthon function to find whether a number is divisible by 11.\nfn is_Diff(n: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_77_is_Diff.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_Diff", "test": "}\n\nfn main() {\n let candidate = is_Diff;\n assert_eq!(candidate(12345), false);\n assert_eq!(candidate(1212112), true);\n assert_eq!(candidate(1212), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find whether a number is divisible by 11.\nfn is_Diff(n: isize) -> bool {\n if n.abs() % 11 == 0 {\n return true;\n } else {\n return false;\n }\n}"} -{"name": "mbpp_123_amicable_numbers_sum", "language": "rs", "prompt": "/// Write a function to sum all amicable numbers from 1 to a specified number.\nfn amicable_numbers_sum(limit: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_123_amicable_numbers_sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "amicable_numbers_sum", "test": "}\n\nfn main() {\n let candidate = amicable_numbers_sum;\n assert_eq!(candidate(999), 504);\n assert_eq!(candidate(9999), 31626);\n assert_eq!(candidate(99), 0);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to sum all amicable numbers from 1 to a specified number.\nfn amicable_numbers_sum(limit: isize) -> isize {\n fn sum_of_divisors(n: isize) -> isize {\n let mut sum = 1;\n for i in 2..=((n as f64).sqrt() as isize) {\n if n % i == 0 {\n sum += i;\n if i != n / i {\n sum += n / i;\n }\n }\n }\n sum\n }\n\n let mut amicable_sum = 0;\n for i in 1..limit {\n let a = sum_of_divisors(i);\n let b = sum_of_divisors(a);\n if i == b && i != a {\n amicable_sum += i;\n }\n }\n amicable_sum\n}"} -{"name": "mbpp_420_cube_Sum", "language": "rs", "prompt": "/// Write a rsthon function to find the cube sum of first n even natural numbers.\nfn cube_Sum(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_420_cube_Sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "cube_Sum", "test": "}\n\nfn main() {\n let candidate = cube_Sum;\n assert_eq!(candidate(2), 72);\n assert_eq!(candidate(3), 288);\n assert_eq!(candidate(4), 800);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the cube sum of first n even natural numbers.\nfn cube_Sum(n: isize) -> isize {\n let mut sum = 0;\n\n for i in 1..=n {\n let even_number = 2 * i;\n let cube = even_number * even_number * even_number;\n sum += cube;\n }\n\n sum\n}"} -{"name": "mbpp_20_is_woodall", "language": "rs", "prompt": "/// Write a function to check if the given number is woodball or not.\nfn is_woodall(x: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_20_is_woodall.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_woodall", "test": "}\n\nfn main() {\n let candidate = is_woodall;\n assert_eq!(candidate(383), true);\n assert_eq!(candidate(254), false);\n assert_eq!(candidate(200), false);\n}\n", "solution": "/// Write a function to check if the given number is woodball or not.\nfn is_woodall(x: isize) -> bool {\n let mut n = 1;\n let x_i64 = x as i64;\n while (2_i64.pow(n as u32) * n) - 1 <= x_i64 {\n if (2_i64.pow(n as u32) * n) - 1 == x_i64 {\n return true;\n }\n n += 1;\n }\n false\n}", "is_solved": true, "reflections": ["The implementation is wrong because there is a type mismatch in the expression `(2_i32.pow(n) * n) - 1`. The `pow` function returns a `u32` value, while `n` is an `isize`. This causes a type mismatch error when trying to multiply them.", "The implementation is incorrect because it compares an `i32` value with an `isize` value, causing a type mismatch error. To fix this, the `x` variable should be converted to an `i32` before the comparison, or the function should use consistent types for all variables involved in the comparison.", "The implementation of the is_woodall function is incorrect because it checks for the condition (2_i32.pow(n as u32) * n) - 1 == x_i32 inside the while loop, but the loop condition is set to exit before this condition can be met. This causes the function to return false for valid Woodall numbers, leading to failed test cases.", "The implementation of the is_woodall function is incorrect because it uses the wrong formula to calculate Woodall numbers. The correct formula is (2^n * n) - 1, but the implementation uses (2_i32.pow(n as u32) * n) - 1, which causes incorrect results for the given test cases."]} -{"name": "mbpp_805_max_sum_list", "language": "rs", "prompt": "/// Write a function that returns the vector in a vector of vectors whose sum of elements is the highest.\nfn max_sum_list(lists: Vec>) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_805_max_sum_list.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_sum_list", "test": "}\n\nfn main() {\n let candidate = max_sum_list;\n assert_eq!(candidate(vec![vec![1, 2, 3], vec![4, 5, 6], vec![10, 11, 12], vec![7, 8, 9]]), vec![10, 11, 12]);\n assert_eq!(candidate(vec![vec![3, 2, 1], vec![6, 5, 4], vec![12, 11, 10]]), vec![12, 11, 10]);\n assert_eq!(candidate(vec![vec![2, 3, 1]]), vec![2, 3, 1]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function that returns the vector in a vector of vectors whose sum of elements is the highest.\nfn max_sum_list(lists: Vec>) -> Vec {\n let mut max_sum = None;\n let mut max_list = Vec::new();\n\n for list in lists {\n let sum: isize = list.iter().sum();\n if max_sum.is_none() || sum > max_sum.unwrap() {\n max_sum = Some(sum);\n max_list = list;\n }\n }\n\n max_list\n}"} -{"name": "mbpp_806_max_run_uppercase", "language": "rs", "prompt": "/// Write a function to find maximum run of uppercase characters in the given string.\nfn max_run_uppercase(test_str: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_806_max_run_uppercase.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_run_uppercase", "test": "}\n\nfn main() {\n let candidate = max_run_uppercase;\n assert_eq!(candidate(String::from(\"GeMKSForGERksISBESt\")), 5);\n assert_eq!(candidate(String::from(\"PrECIOusMOVemENTSYT\")), 6);\n assert_eq!(candidate(String::from(\"GooGLEFluTTER\")), 4);\n}\n", "solution": "/// Write a function to find maximum run of uppercase characters in the given string.\nfn max_run_uppercase(test_str: String) -> isize {\n let mut max_run = 0;\n let mut current_run = 0;\n\n for (i, c) in test_str.chars().enumerate() {\n if c.is_uppercase() {\n if i == 0 || !test_str.chars().nth(i - 1).unwrap().is_alphabetic() {\n current_run = 1;\n } else if test_str.chars().nth(i - 1).unwrap().is_lowercase() {\n current_run += 1;\n } else {\n current_run = 0;\n }\n } else {\n if current_run > max_run {\n max_run = current_run;\n }\n current_run = 0;\n }\n }\n\n if current_run > max_run {\n max_run = current_run;\n }\n\n max_run as isize\n}", "is_solved": true, "reflections": ["The implementation of max_run_uppercase is incorrect because it does not properly reset the current_run counter when encountering a non-uppercase character. This causes the function to return the total count of uppercase characters instead of the maximum run of consecutive uppercase characters.", "The implementation is incorrect because it counts consecutive uppercase characters without considering if they are part of a single word or multiple words. As a result, the function returns the count of consecutive uppercase characters across multiple words, leading to incorrect results in the failed test cases.", "The implementation is incorrect because it only considers uppercase runs that start after a whitespace character or at the beginning of the string. This causes the function to miss continuous uppercase runs that are not preceded by a whitespace character, leading to incorrect results in the failed tests.", "The implementation is incorrect because it counts consecutive uppercase characters without considering if they are part of a single word or not. It fails when there are multiple uppercase characters in a row that are part of different words or when there are non-letter characters between uppercase letters."]} -{"name": "mbpp_455_check_monthnumb_number", "language": "rs", "prompt": "/// Write a function to check whether the given month number contains 31 days or not.\nfn check_monthnumb_number(monthnum2: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_455_check_monthnumb_number.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "check_monthnumb_number", "test": "}\n\nfn main() {\n let candidate = check_monthnumb_number;\n assert_eq!(candidate(5), true);\n assert_eq!(candidate(2), false);\n assert_eq!(candidate(6), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check whether the given month number contains 31 days or not.\nfn check_monthnumb_number(monthnum2: isize) -> bool {\n match monthnum2 {\n 1 | 3 | 5 | 7 | 8 | 10 | 12 => true,\n 4 | 6 | 9 | 11 => false,\n _ => panic!(\"Invalid month number\"),\n }\n}"} -{"name": "mbpp_577_last_Digit_Factorial", "language": "rs", "prompt": "/// Write a rsthon function to find the last digit in factorial of a given number.\nfn last_Digit_Factorial(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_577_last_Digit_Factorial.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "last_Digit_Factorial", "test": "}\n\nfn main() {\n let candidate = last_Digit_Factorial;\n assert_eq!(candidate(4), 4);\n assert_eq!(candidate(21), 0);\n assert_eq!(candidate(30), 0);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the last digit in factorial of a given number.\nfn last_Digit_Factorial(n: isize) -> isize {\n if n < 0 {\n return -1;\n }\n\n if n == 0 || n == 1 {\n return 1;\n }\n\n let mut last_digit = 1;\n for i in 2..=n {\n last_digit = (last_digit * i) % 10;\n }\n\n last_digit\n}"} -{"name": "mbpp_555_difference", "language": "rs", "prompt": "/// Write a rsthon function to find the difference between the sum of cubes of the first n natural numbers and the sum of the first n natural numbers.\nfn difference(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_555_difference.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "difference", "test": "}\n\nfn main() {\n let candidate = difference;\n assert_eq!(candidate(3), 30);\n assert_eq!(candidate(5), 210);\n assert_eq!(candidate(2), 6);\n}\n", "solution": "/// Write a rsthon function to find the difference between the sum of cubes of the first n natural numbers and the sum of the first n natural numbers.\nfn difference(n: isize) -> isize {\n let sum_of_cubes = n * (n + 1) * (2 * n + 1) / 6;\n let sum_of_natural_numbers = n * (n + 1) / 2;\n let sum_of_natural_numbers_cubed = sum_of_natural_numbers.pow(3);\n\n sum_of_natural_numbers_cubed - sum_of_cubes\n}", "is_solved": true, "reflections": ["The implementation is incorrect because the formulas for sum_of_cubes and sum_of_natural_numbers are swapped. The sum_of_cubes should be calculated using the formula n * (n + 1) * (2 * n + 1) / 6, and the sum_of_natural_numbers should be calculated using the formula (n * (n + 1) / 2).pow(2). This mix-up leads to incorrect results for the difference function.", "The implementation of the `difference` function is incorrect because it calculates the difference between the sum of the first n natural numbers squared and the sum of cubes of the first n natural numbers. The problem statement asks for the difference between the sum of cubes of the first n natural numbers and the sum of the first n natural numbers. This leads to incorrect results for the failed test cases.", "The implementation is incorrect because it calculates the difference between the sum of cubes of the first n natural numbers and the sum of the first n natural numbers directly. However, the problem statement asks for the difference between the sum of cubes and the sum of natural numbers, both raised to the power of 3. The formula used for sum_of_cubes is correct, but the sum_of_natural_numbers should be cubed before subtracting it from sum_of_cubes.", "The implementation of the `difference` function is incorrect because it calculates the difference between the sum of cubes and the cube of the sum of natural numbers, instead of the difference between the cube of the sum of natural numbers and the sum of cubes. The subtraction in the last line should be reversed to fix the issue."]} -{"name": "mbpp_456_reverse_string_list", "language": "rs", "prompt": "/// Write a function to reverse each string in a given vector of string values.\nfn reverse_string_list(stringlist: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_456_reverse_string_list.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "reverse_string_list", "test": "}\n\nfn main() {\n let candidate = reverse_string_list;\n assert_eq!(candidate(vec![String::from(\"Red\"), String::from(\"Green\"), String::from(\"Blue\"), String::from(\"White\"), String::from(\"Black\")]), vec![String::from(\"deR\"), String::from(\"neerG\"), String::from(\"eulB\"), String::from(\"etihW\"), String::from(\"kcalB\")]);\n assert_eq!(candidate(vec![String::from(\"john\"), String::from(\"amal\"), String::from(\"joel\"), String::from(\"george\")]), vec![String::from(\"nhoj\"), String::from(\"lama\"), String::from(\"leoj\"), String::from(\"egroeg\")]);\n assert_eq!(candidate(vec![String::from(\"jack\"), String::from(\"john\"), String::from(\"mary\")]), vec![String::from(\"kcaj\"), String::from(\"nhoj\"), String::from(\"yram\")]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to reverse each string in a given vector of string values.\nfn reverse_string_list(stringlist: Vec) -> Vec {\n stringlist.into_iter().map(|s| s.chars().rev().collect()).collect()\n}"} -{"name": "mbpp_12_sort_matrix", "language": "rs", "prompt": "/// Write a function to sort a given matrix in ascending order according to the sum of its rows.\nfn sort_matrix(M: Vec>) -> Vec> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_12_sort_matrix.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sort_matrix", "test": "}\n\nfn main() {\n let candidate = sort_matrix;\n assert_eq!(candidate(vec![vec![1, 2, 3], vec![2, 4, 5], vec![1, 1, 1]]), vec![vec![1, 1, 1], vec![1, 2, 3], vec![2, 4, 5]]);\n assert_eq!(candidate(vec![vec![1, 2, 3], vec![-2, 4, -5], vec![1, -1, 1]]), vec![vec![-2, 4, -5], vec![1, -1, 1], vec![1, 2, 3]]);\n assert_eq!(candidate(vec![vec![5, 8, 9], vec![6, 4, 3], vec![2, 1, 4]]), vec![vec![2, 1, 4], vec![6, 4, 3], vec![5, 8, 9]]);\n}\n", "solution": "/// Write a function to sort a given matrix in ascending order according to the sum of its rows.\nfn sort_matrix(M: Vec>) -> Vec> {\n let mut matrix_with_sums = M.into_iter()\n .map(|row| (row.iter().sum::(), row))\n .collect::)>>();\n\n matrix_with_sums.sort_unstable_by_key(|(sum, _)| *sum);\n\n matrix_with_sums.into_iter()\n .map(|(_, row)| row)\n .collect()\n}", "is_solved": true, "reflections": ["The implementation is wrong because the `sort_by_key` method does not mutate the original vector but returns a new sorted vector. However, the code is trying to call `into_iter()` on the result of `sort_by_key`, which is `()`. This causes the error, as `()` is not an iterator. To fix this issue, the `sort_by_key` method should be replaced with `sort_unstable_by_key` which mutates the original vector in-place."]} -{"name": "mbpp_584_find_adverbs", "language": "rs", "prompt": "/// Write a function to find the first adverb ending with ly and its positions in a given string.\nfn find_adverbs(text: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_584_find_adverbs.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_adverbs", "test": "}\n\nfn main() {\n let candidate = find_adverbs;\n assert_eq!(candidate(String::from(\"Clearly, he has no excuse for such behavior.\")), String::from(\"0-7: Clearly\"));\n assert_eq!(candidate(String::from(\"Please handle the situation carefuly\")), String::from(\"28-36: carefuly\"));\n assert_eq!(candidate(String::from(\"Complete the task quickly\")), String::from(\"18-25: quickly\"));\n}\n", "solution": "/// Write a function to find the first adverb ending with ly and its positions in a given string.\nfn find_adverbs(text: String) -> String {\n let words = text.split_whitespace();\n let mut result = String::new();\n let mut position = 0;\n\n for (index, word) in words.enumerate() {\n position += word.len();\n if word.ends_with(\"ly\") {\n result = format!(\"{} ({})\", word, position - word.len());\n break;\n }\n position += 1;\n }\n\n result\n}", "is_solved": true, "reflections": ["The implementation is incorrect because the output format of the result does not match the expected format in the test cases. The function returns the adverb and its position separated by \"found at position\", while the test cases expect the adverb and its position to be enclosed in parentheses and separated by a space.", "The implementation is incorrect because it returns the index of the adverb in the list of words, rather than its position in the original string. This causes the failed test cases, as the output does not match the expected position of the adverb within the given string.", "The implementation is incorrect because it calculates the position of the adverb based on the length of the words and spaces, rather than the number of words. This causes the position to be incorrect in the output, as seen in the failed test cases.", "The implementation is incorrect because it uses the index of the word in the split words array as the position of the adverb in the original text. This causes the position to be off by one or more depending on the number of words before the adverb."]} -{"name": "mbpp_86_centered_hexagonal_number", "language": "rs", "prompt": "/// Write a function to find nth centered hexagonal number.\nfn centered_hexagonal_number(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_86_centered_hexagonal_number.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "centered_hexagonal_number", "test": "}\n\nfn main() {\n let candidate = centered_hexagonal_number;\n assert_eq!(candidate(10), 271);\n assert_eq!(candidate(2), 7);\n assert_eq!(candidate(9), 217);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find nth centered hexagonal number.\nfn centered_hexagonal_number(n: isize) -> isize {\n if n <= 0 {\n return 0;\n }\n (3 * n * (n - 1)) + 1\n}"} -{"name": "mbpp_130_max_occurrences", "language": "rs", "prompt": "/// Write a function to find the item with maximum frequency in a given vector.\nfn max_occurrences(nums: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_130_max_occurrences.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_occurrences", "test": "}\n\nfn main() {\n let candidate = max_occurrences;\n assert_eq!(candidate(vec![2, 3, 8, 4, 7, 9, 8, 2, 6, 5, 1, 6, 1, 2, 3, 2, 4, 6, 9, 1, 2]), 2);\n assert_eq!(candidate(vec![2, 3, 8, 4, 7, 9, 8, 7, 9, 15, 14, 10, 12, 13, 16, 18]), 8);\n assert_eq!(candidate(vec![10, 20, 20, 30, 40, 90, 80, 50, 30, 20, 50, 10]), 20);\n}\n", "solution": "/// Write a function to find the item with maximum frequency in a given vector.\nfn max_occurrences(nums: Vec) -> isize {\n let mut occurrences = std::collections::HashMap::new();\n\n for num in nums {\n let count = occurrences.entry(num).or_insert(0);\n *count += 1;\n }\n\n let mut max_occurrences = 0;\n let mut max_num = 0;\n\n for (num, count) in occurrences {\n if count > max_occurrences {\n max_occurrences = count;\n max_num = num;\n } else if count == max_occurrences && num < max_num {\n max_num = num;\n }\n }\n\n max_num\n}", "is_solved": true, "reflections": ["The current implementation does not handle the case when multiple numbers have the same frequency correctly. It returns the last number with the highest frequency encountered in the input vector, instead of the first one. This is why the test with input `[1, 2, 3, 4, 5, 6, 7, 8, 9]` fails, as it returns 9 instead of 1."]} -{"name": "mbpp_742_area_tetrahedron", "language": "rs", "prompt": "/// Write a function to caluclate the area of a tetrahedron.\nfn area_tetrahedron(side: isize) -> f64 {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_742_area_tetrahedron.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "area_tetrahedron", "test": "}\n\nfn main() {\n let candidate = area_tetrahedron;\n assert_eq!(candidate(3), 15.588457268119894);\n assert_eq!(candidate(20), 692.8203230275509);\n assert_eq!(candidate(10), 173.20508075688772);\n}\n", "solution": "/// Write a function to caluclate the area of a tetrahedron.\nfn area_tetrahedron(side: isize) -> f64 {\n let sqrt_2 = (2.0 as f64).sqrt();\n let volume_tetrahedron = (side * side * side) as f64 * sqrt_2 / 12.0;\n volume_tetrahedron\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it calculates the area of an equilateral triangle instead of the surface area of a tetrahedron. The surface area of a tetrahedron should be calculated as 4 times the area of an equilateral triangle with the given side length.", "The implementation is incorrect because it calculates the surface area of the tetrahedron instead of its volume. The failed tests show that the output values are much larger than the expected volume values, indicating that the formula used is not appropriate for calculating the volume of a tetrahedron.", "The implementation is incorrect because it calculates the volume of the tetrahedron instead of its surface area. The formula used in the function is for volume, which is why the test cases are failing as they expect the surface area as output.", "The implementation is incorrect because it calculates the area of an equilateral triangle instead of the volume of a tetrahedron. The formula used is for the area of an equilateral triangle (side^2 * sqrt(3) / 4), while the correct formula for the volume of a tetrahedron is (side^3 * sqrt(2) / 12). The failed tests show that the output values are not matching the expected volume values for a tetrahedron."]} -{"name": "mbpp_610_remove_kth_element", "language": "rs", "prompt": "/// Write a rsthon function which takes a vector and returns a vector with the same elements, but the k'th element removed.\nfn remove_kth_element(list1: Vec, L: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_610_remove_kth_element.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "remove_kth_element", "test": "}\n\nfn main() {\n let candidate = remove_kth_element;\n assert_eq!(candidate(vec![1, 1, 2, 3, 4, 4, 5, 1], 3), vec![1, 1, 3, 4, 4, 5, 1]);\n assert_eq!(candidate(vec![0, 0, 1, 2, 3, 4, 4, 5, 6, 6, 6, 7, 8, 9, 4, 4], 4), vec![0, 0, 1, 3, 4, 4, 5, 6, 6, 6, 7, 8, 9, 4, 4]);\n assert_eq!(candidate(vec![10, 10, 15, 19, 18, 18, 17, 26, 26, 17, 18, 10], 5), vec![10, 10, 15, 19, 18, 17, 26, 26, 17, 18, 10]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function which takes a vector and returns a vector with the same elements, but the k'th element removed.\nfn remove_kth_element(list1: Vec, L: isize) -> Vec {\n let mut result = Vec::new();\n let k = L as usize;\n\n for (index, &item) in list1.iter().enumerate() {\n if index != k {\n result.push(item);\n }\n }\n\n result\n}"} -{"name": "mbpp_394_check_distinct", "language": "rs", "prompt": "/// Write a function to check if given vector contains no duplicates.\nfn check_distinct(test_tup: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_394_check_distinct.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "check_distinct", "test": "}\n\nfn main() {\n let candidate = check_distinct;\n assert_eq!(candidate(vec![1, 4, 5, 6, 1, 4]), false);\n assert_eq!(candidate(vec![1, 4, 5, 6]), true);\n assert_eq!(candidate(vec![2, 3, 4, 5, 6]), true);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check if given vector contains no duplicates.\nfn check_distinct(test_tup: Vec) -> bool {\n let mut seen = std::collections::HashSet::new();\n\n for &value in test_tup.iter() {\n if seen.contains(&value) {\n return false;\n } else {\n seen.insert(value);\n }\n }\n\n true\n}"} -{"name": "mbpp_793_last", "language": "rs", "prompt": "/// Write a rsthon function to find the last position of an element in a sorted vector.\nfn last(arr: Vec, x: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_793_last.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "last", "test": "}\n\nfn main() {\n let candidate = last;\n assert_eq!(candidate(vec![1, 2, 3], 1), 0);\n assert_eq!(candidate(vec![1, 1, 1, 2, 3, 4], 1), 2);\n assert_eq!(candidate(vec![2, 3, 2, 3, 6, 8, 9], 3), 3);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the last position of an element in a sorted vector.\nfn last(arr: Vec, x: isize) -> isize {\n if arr.is_empty() {\n return -1;\n }\n\n let mut left = 0;\n let mut right = arr.len() - 1;\n let mut result = -1;\n\n while left <= right {\n let mid = left + (right - left) / 2;\n\n if arr[mid] == x {\n result = mid as isize;\n left = mid + 1;\n } else if arr[mid] < x {\n left = mid + 1;\n } else {\n right = mid - 1;\n }\n }\n\n result\n}"} -{"name": "mbpp_728_sum_list", "language": "rs", "prompt": "/// Write a function takes as input two vectors [a_1,...,a_n], [b_1,...,b_n] and returns [a_1+b_1,...,a_n+b_n].\nfn sum_list(lst1: Vec, lst2: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_728_sum_list.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sum_list", "test": "}\n\nfn main() {\n let candidate = sum_list;\n assert_eq!(candidate(vec![10, 20, 30], vec![15, 25, 35]), vec![25, 45, 65]);\n assert_eq!(candidate(vec![1, 2, 3], vec![5, 6, 7]), vec![6, 8, 10]);\n assert_eq!(candidate(vec![15, 20, 30], vec![15, 45, 75]), vec![30, 65, 105]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function takes as input two vectors [a_1,...,a_n], [b_1,...,b_n] and returns [a_1+b_1,...,a_n+b_n].\nfn sum_list(lst1: Vec, lst2: Vec) -> Vec {\n let mut result: Vec = Vec::new();\n\n for (a, b) in lst1.iter().zip(lst2.iter()) {\n result.push(a + b);\n }\n\n result\n}"} -{"name": "mbpp_566_sum_digits", "language": "rs", "prompt": "/// Write a function to get the sum of the digits of a non-negative integer.\nfn sum_digits(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_566_sum_digits.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sum_digits", "test": "}\n\nfn main() {\n let candidate = sum_digits;\n assert_eq!(candidate(345), 12);\n assert_eq!(candidate(12), 3);\n assert_eq!(candidate(97), 16);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to get the sum of the digits of a non-negative integer.\nfn sum_digits(n: isize) -> isize {\n assert!(n >= 0, \"Input must be a non-negative integer\");\n\n let mut sum = 0;\n let mut num = n;\n\n while num > 0 {\n sum += num % 10;\n num /= 10;\n }\n\n sum\n}"} -{"name": "mbpp_290_max_length", "language": "rs", "prompt": "/// Write a function to find the vector of maximum length in a vector of vectors.\nfn max_length(list1: Vec>) -> (isize, Vec) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_290_max_length.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_length", "test": "}\n\nfn main() {\n let candidate = max_length;\n assert_eq!(candidate(vec![vec![0], vec![1, 3], vec![5, 7], vec![9, 11], vec![13, 15, 17]]), (3, vec![13, 15, 17]));\n assert_eq!(candidate(vec![vec![1], vec![5, 7], vec![10, 12, 14, 15]]), (4, vec![10, 12, 14, 15]));\n assert_eq!(candidate(vec![vec![5], vec![15, 20, 25]]), (3, vec![15, 20, 25]));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the vector of maximum length in a vector of vectors.\nfn max_length(list1: Vec>) -> (isize, Vec) {\n let mut max_length = 0;\n let mut max_vector = Vec::new();\n\n for vec in list1 {\n let length = vec.len();\n if length > max_length {\n max_length = length;\n max_vector = vec;\n }\n }\n\n (max_length as isize, max_vector)\n}"} -{"name": "mbpp_628_replace_spaces", "language": "rs", "prompt": "/// Write a function to replace all spaces in the given string with '%20'.\nfn replace_spaces(string: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_628_replace_spaces.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "replace_spaces", "test": "}\n\nfn main() {\n let candidate = replace_spaces;\n assert_eq!(candidate(String::from(\"My Name is Dawood\")), String::from(\"My%20Name%20is%20Dawood\"));\n assert_eq!(candidate(String::from(\"I am a Programmer\")), String::from(\"I%20am%20a%20Programmer\"));\n assert_eq!(candidate(String::from(\"I love Coding\")), String::from(\"I%20love%20Coding\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to replace all spaces in the given string with '%20'.\nfn replace_spaces(string: String) -> String {\n string.replace(\" \", \"%20\")\n}"} -{"name": "mbpp_417_group_tuples", "language": "rs", "prompt": "/// Write a function to find common first element in given vector of vectors.\nfn group_tuples(Input: Vec>) -> Vec> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_417_group_tuples.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "group_tuples", "test": "}\n\nfn main() {\n let candidate = group_tuples;\n assert_eq!(candidate(vec![vec![String::from(\"x\"), String::from(\"y\")], vec![String::from(\"x\"), String::from(\"z\")], vec![String::from(\"w\"), String::from(\"t\")]]), vec![vec![String::from(\"x\"), String::from(\"y\"), String::from(\"z\")], vec![String::from(\"w\"), String::from(\"t\")]]);\n assert_eq!(candidate(vec![vec![String::from(\"a\"), String::from(\"b\")], vec![String::from(\"a\"), String::from(\"c\")], vec![String::from(\"d\"), String::from(\"e\")]]), vec![vec![String::from(\"a\"), String::from(\"b\"), String::from(\"c\")], vec![String::from(\"d\"), String::from(\"e\")]]);\n assert_eq!(candidate(vec![vec![String::from(\"f\"), String::from(\"g\")], vec![String::from(\"f\"), String::from(\"g\")], vec![String::from(\"h\"), String::from(\"i\")]]), vec![vec![String::from(\"f\"), String::from(\"g\"), String::from(\"g\")], vec![String::from(\"h\"), String::from(\"i\")]]);\n}\n", "solution": "/// Write a function to find common first element in given vector of vectors.\nfn group_tuples(Input: Vec>) -> Vec> {\n use std::collections::HashMap;\n\n let mut result: Vec> = Vec::new();\n\n // Create a hashmap to store the first elements and their corresponding groups\n let mut first_elem_map: HashMap>> = HashMap::new();\n\n // Iterate through the input vector of vectors\n for group in Input {\n if let Some(first_elem) = group.first() {\n // If the first element is already in the hashmap, add the group to its value\n if let Some(groups) = first_elem_map.get_mut(first_elem) {\n for elem in group.iter().skip(1) {\n if !groups.iter().any(|g| g.contains(elem)) {\n groups.push(vec![first_elem.clone(), elem.clone()]);\n }\n }\n } else {\n // If the first element is not in the hashmap, create a new entry with the group\n first_elem_map.insert(first_elem.clone(), vec![group]);\n }\n }\n }\n\n // Convert the hashmap values into the result vector\n // Ensure the order of the groups in the result vector is consistent with the input order\n for group in Input {\n if let Some(first_elem) = group.first() {\n if let Some(groups) = first_elem_map.remove(first_elem) {\n let mut merged_group = Vec::new();\n for group in groups {\n for elem in group {\n if !merged_group.contains(elem) {\n merged_group.push(elem.clone());\n }\n }\n }\n result.push(merged_group);\n }\n }\n }\n\n result\n}", "is_solved": true, "reflections": ["The implementation is wrong because the `HashMap` type is not found in the current scope. The `std::collections::HashMap` needs to be imported to fix this issue.", "The implementation is wrong because the function is trying to push a `Vec>` into the `result` vector, which is of type `Vec>`. The expected type for elements in the `result` vector is `Vec`, not `Vec>`. This type mismatch causes the error.", "The implementation is incorrect because it is grouping the input vectors based on their first elements, but it is not merging the groups with the same first element into a single vector. Instead, it is just appending the groups to the result vector, which causes the output to be in a different order than expected and not properly merged.", "The implementation is incorrect because it does not properly handle the order of the output groups. The function merges groups based on the first element, but the order in which the groups are added to the result vector depends on the order of the hashmap values, which is not guaranteed to be consistent with the input order. This causes the failed test cases where the expected output has a different order than the actual output."]} -{"name": "mbpp_286_max_sub_array_sum_repeated", "language": "rs", "prompt": "/// Write a function to find the largest sum of a contiguous vector in the modified vector which is formed by repeating the given vector k times.\nfn max_sub_array_sum_repeated(a: Vec, n: isize, k: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_286_max_sub_array_sum_repeated.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_sub_array_sum_repeated", "test": "}\n\nfn main() {\n let candidate = max_sub_array_sum_repeated;\n assert_eq!(candidate(vec![10, 20, -30, -1], 4, 3), 30);\n assert_eq!(candidate(vec![-1, 10, 20], 3, 2), 59);\n assert_eq!(candidate(vec![-1, -2, -3], 3, 3), -1);\n}\n", "solution": "/// Write a function to find the largest sum of a contiguous vector in the modified vector which is formed by repeating the given vector k times.\nfn max_sub_array_sum_repeated(a: Vec, n: isize, k: isize) -> isize {\n let mut max_so_far = a[0];\n let mut max_ending_here = a[0];\n\n // Find the maximum subarray sum within a single repetition\n for i in 1..n as usize {\n max_ending_here = max_ending_here + a[i];\n if max_ending_here < a[i] {\n max_ending_here = a[i];\n }\n if max_so_far < max_ending_here {\n max_so_far = max_ending_here;\n }\n }\n\n // If k is 1, return the maximum subarray sum within a single repetition\n if k == 1 {\n return max_so_far;\n }\n\n // Calculate the sum of the entire input vector\n let total_sum: isize = a.iter().sum();\n\n // Check for the maximum subarray sum that spans across repetitions\n let mut max_prefix_sum = a[0];\n let mut current_prefix_sum = a[0];\n for i in 1..n as usize {\n current_prefix_sum += a[i];\n if current_prefix_sum > max_prefix_sum {\n max_prefix_sum = current_prefix_sum;\n }\n }\n\n let mut max_suffix_sum = a[n as usize - 1];\n let mut current_suffix_sum = a[n as usize - 1];\n for i in (0..n as usize - 1).rev() {\n current_suffix_sum += a[i];\n if current_suffix_sum > max_suffix_sum {\n max_suffix_sum = current_suffix_sum;\n }\n }\n\n // Calculate the maximum subarray sum that spans across multiple repetitions\n let mut max_spanning_sum = max_prefix_sum + max_suffix_sum;\n if total_sum > 0 {\n max_spanning_sum += total_sum * (k - 2) as isize;\n }\n\n // Update the maximum subarray sum if the sum that spans across multiple repetitions is larger\n if max_so_far < max_spanning_sum {\n max_so_far = max_spanning_sum;\n }\n\n // Check for the maximum subarray sum that includes more elements from the prefix or suffix\n let mut max_combined_sum = max_so_far;\n for i in 1..n as usize {\n let combined_sum = max_prefix_sum - a[i - 1] + max_suffix_sum + a[n as usize - i];\n if combined_sum > max_combined_sum {\n max_combined_sum = combined_sum;\n }\n }\n\n // Iterate through all possible combinations of prefix and suffix sums for each repetition\n for rep in 1..k {\n let mut current_combined_sum = max_prefix_sum + max_suffix_sum;\n if total_sum > 0 {\n current_combined_sum += total_sum * (rep - 1) as isize;\n }\n if current_combined_sum > max_combined_sum {\n max_combined_sum = current_combined_sum;\n }\n\n // Update prefix and suffix sums for the next repetition\n max_prefix_sum += a[(rep * n) as usize % n as usize];\n max_suffix_sum -= a[((rep + 1) * n) as usize % n as usize];\n }\n\n max_combined_sum\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it does not properly handle the cases where the maximum subarray sum spans across multiple repetitions of the input vector. The current implementation only calculates the maximum subarray sum within each repetition, but does not consider the possibility of a larger sum that includes elements from adjacent repetitions. This leads to incorrect results in the failed test cases.", "The implementation is incorrect because it does not properly handle cases where the maximum subarray sum spans across multiple repetitions of the input vector. The current approach only considers the sum that spans across the first and last repetitions, but it should also consider the sums that span across other repetitions. This leads to incorrect results for the failed test cases.", "The implementation is incorrect because it does not properly handle the cases where the maximum subarray sum spans across multiple repetitions. The calculation of max_spanning_sum does not take into account the possibility of having a higher sum by including more elements from the prefix or suffix. This leads to incorrect results in cases where the maximum subarray sum is formed by combining elements from multiple repetitions of the input vector.", "The implementation is incorrect because it does not properly handle the cases where the maximum subarray sum spans across multiple repetitions. The calculation of the maximum combined sum does not take into account the different possible combinations of prefix and suffix sums for each repetition. This leads to incorrect results when the maximum subarray sum is formed by combining elements from different repetitions."]} -{"name": "mbpp_66_pos_count", "language": "rs", "prompt": "/// Write a rsthon function to count the number of positive numbers in a vector.\nfn pos_count(list: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_66_pos_count.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "pos_count", "test": "}\n\nfn main() {\n let candidate = pos_count;\n assert_eq!(candidate(vec![1, -2, 3, -4]), 2);\n assert_eq!(candidate(vec![3, 4, 5, -1]), 3);\n assert_eq!(candidate(vec![1, 2, 3, 4]), 4);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to count the number of positive numbers in a vector.\nfn pos_count(list: Vec) -> isize {\n let mut count = 0;\n\n for num in list {\n if num > 0 {\n count += 1;\n }\n }\n\n count\n}"} -{"name": "mbpp_450_extract_string", "language": "rs", "prompt": "/// Write a function to extract specified size of strings from a given vector of string values.\nfn extract_string(str: Vec, l: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_450_extract_string.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "extract_string", "test": "}\n\nfn main() {\n let candidate = extract_string;\n assert_eq!(candidate(vec![String::from(\"Python\"), String::from(\"list\"), String::from(\"exercises\"), String::from(\"practice\"), String::from(\"solution\")], 8), vec![String::from(\"practice\"), String::from(\"solution\")]);\n assert_eq!(candidate(vec![String::from(\"Python\"), String::from(\"list\"), String::from(\"exercises\"), String::from(\"practice\"), String::from(\"solution\")], 6), vec![String::from(\"Python\")]);\n assert_eq!(candidate(vec![String::from(\"Python\"), String::from(\"list\"), String::from(\"exercises\"), String::from(\"practice\"), String::from(\"solution\")], 9), vec![String::from(\"exercises\")]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to extract specified size of strings from a given vector of string values.\nfn extract_string(str: Vec, l: isize) -> Vec {\n let mut result = Vec::new();\n\n for s in str {\n if s.len() as isize == l {\n result.push(s);\n }\n }\n\n result\n}"} -{"name": "mbpp_444_trim_tuple", "language": "rs", "prompt": "/// Write a function to trim each vector by k in the given vectors.\nfn trim_tuple(test_list: Vec>, K: isize) -> Vec> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_444_trim_tuple.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "trim_tuple", "test": "}\n\nfn main() {\n let candidate = trim_tuple;\n assert_eq!(candidate(vec![vec![5, 3, 2, 1, 4], vec![3, 4, 9, 2, 1], vec![9, 1, 2, 3, 5], vec![4, 8, 2, 1, 7]], 2), vec![vec![2], vec![9], vec![2], vec![2]]);\n assert_eq!(candidate(vec![vec![5, 3, 2, 1, 4], vec![3, 4, 9, 2, 1], vec![9, 1, 2, 3, 5], vec![4, 8, 2, 1, 7]], 1), vec![vec![3, 2, 1], vec![4, 9, 2], vec![1, 2, 3], vec![8, 2, 1]]);\n assert_eq!(candidate(vec![vec![7, 8, 4, 9], vec![11, 8, 12, 4], vec![4, 1, 7, 8], vec![3, 6, 9, 7]], 1), vec![vec![8, 4], vec![8, 12], vec![1, 7], vec![6, 9]]);\n}\n", "solution": "/// Write a function to trim each vector by k in the given vectors.\nfn trim_tuple(test_list: Vec>, K: isize) -> Vec> {\n test_list\n .into_iter()\n .map(|mut vec| {\n if vec.len() > K as usize {\n vec.truncate(vec.len() - K as usize);\n } else {\n vec.clear();\n }\n vec\n })\n .collect()\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it trims the vectors to the length of K instead of removing K elements from each vector. This causes the output to have vectors with incorrect lengths, as shown in the failed test cases.", "The implementation is incorrect because it removes the first K elements from each vector instead of trimming the last K elements. This causes the output to be different from the expected results in the failed tests."]} -{"name": "mbpp_439_multiple_to_single", "language": "rs", "prompt": "/// Write a function to join a vector of multiple integers into a single integer.\nfn multiple_to_single(L: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_439_multiple_to_single.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "multiple_to_single", "test": "}\n\nfn main() {\n let candidate = multiple_to_single;\n assert_eq!(candidate(vec![11, 33, 50]), 113350);\n assert_eq!(candidate(vec![-1, 2, 3, 4, 5, 6]), -123456);\n assert_eq!(candidate(vec![10, 15, 20, 25]), 10152025);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to join a vector of multiple integers into a single integer.\nfn multiple_to_single(L: Vec) -> isize {\n let mut result = String::new();\n for num in L {\n result.push_str(&num.to_string());\n }\n result.parse::().unwrap()\n}"} -{"name": "mbpp_162_sum_series", "language": "rs", "prompt": "/// Write a function to calculate the sum (n - 2*i) from i=0 to n // 2, for instance n + (n-2) + (n-4)... (until n-x =< 0).\nfn sum_series(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_162_sum_series.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sum_series", "test": "}\n\nfn main() {\n let candidate = sum_series;\n assert_eq!(candidate(6), 12);\n assert_eq!(candidate(10), 30);\n assert_eq!(candidate(9), 25);\n}\n", "solution": "/// Write a function to calculate the sum (n - 2*i) from i=0 to n // 2, for instance n + (n-2) + (n-4)... (until n-x =< 0).\nfn sum_series(n: isize) -> isize {\n let mut sum = 0;\n let mut i = 0;\n\n while n - 2 * i > 0 {\n sum += n - 2 * i;\n i += 1;\n }\n\n sum += n - 2 * i;\n\n sum\n}", "is_solved": true, "reflections": ["The implementation of the sum_series function is incorrect because it calculates the sum using a while loop with the condition (n - 2 * i >= 0). This condition causes the loop to stop one iteration early, resulting in an incorrect sum for certain input values like 100.", "The implementation of the sum_series function is incorrect because it adds an extra term (n - 2 * i) after the while loop, which results in an off-by-one error. This causes the function to return a sum that is one term less than the expected value, as indicated by the failed test cases.", "The implementation of the sum_series function is incorrect because it does not include the last term when n - 2 * i is equal to 0. The loop condition should be \"n - 2 * i >= 0\" instead of \"n - 2 * i > 0\" to ensure the last term is included in the sum. This is why the test with input 100 fails, as the sum is missing the last term (100 - 2 * 50 = 0).", "The implementation of the sum_series function is incorrect because it calculates the sum using a while loop with the condition (n - 2 * i >= 0). This condition causes the loop to stop one iteration early, resulting in an incorrect sum for certain input values like 100."]} -{"name": "mbpp_224_count_Set_Bits", "language": "rs", "prompt": "/// Write a rsthon function to count the number of set bits (binary digits with value 1) in a given number.\nfn count_Set_Bits(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_224_count_Set_Bits.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_Set_Bits", "test": "}\n\nfn main() {\n let candidate = count_Set_Bits;\n assert_eq!(candidate(2), 1);\n assert_eq!(candidate(4), 1);\n assert_eq!(candidate(6), 2);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to count the number of set bits (binary digits with value 1) in a given number.\nfn count_Set_Bits(n: isize) -> isize {\n let mut count = 0;\n let mut num = n;\n\n while num > 0 {\n count += num & 1;\n num >>= 1;\n }\n\n count as isize\n}"} -{"name": "mbpp_309_maximum", "language": "rs", "prompt": "/// Write a rsthon function to find the maximum of two numbers.\nfn maximum(a: isize, b: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_309_maximum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "maximum", "test": "}\n\nfn main() {\n let candidate = maximum;\n assert_eq!(candidate(5, 10), 10);\n assert_eq!(candidate(-1, -2), -1);\n assert_eq!(candidate(9, 7), 9);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the maximum of two numbers.\nfn maximum(a: isize, b: isize) -> isize {\n if a > b {\n a\n } else {\n b\n }\n}"} -{"name": "mbpp_632_move_zero", "language": "rs", "prompt": "/// Write a rsthon function to move all zeroes to the end of the given vector.\nfn move_zero(num_list: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_632_move_zero.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "move_zero", "test": "}\n\nfn main() {\n let candidate = move_zero;\n assert_eq!(candidate(vec![1, 0, 2, 0, 3, 4]), vec![1, 2, 3, 4, 0, 0]);\n assert_eq!(candidate(vec![2, 3, 2, 0, 0, 4, 0, 5, 0]), vec![2, 3, 2, 4, 5, 0, 0, 0, 0]);\n assert_eq!(candidate(vec![0, 1, 0, 1, 1]), vec![1, 1, 1, 0, 0]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to move all zeroes to the end of the given vector.\nfn move_zero(num_list: Vec) -> Vec {\n let mut non_zero_elements: Vec = Vec::new();\n let mut zero_count = 0;\n\n for num in num_list {\n if num == 0 {\n zero_count += 1;\n } else {\n non_zero_elements.push(num);\n }\n }\n\n for _ in 0..zero_count {\n non_zero_elements.push(0);\n }\n\n non_zero_elements\n}"} -{"name": "mbpp_168_frequency", "language": "rs", "prompt": "/// Write a function to count the number of occurrences of a number in a given vector.\nfn frequency(a: Vec, x: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_168_frequency.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "frequency", "test": "}\n\nfn main() {\n let candidate = frequency;\n assert_eq!(candidate(vec![1, 2, 3], 4), 0);\n assert_eq!(candidate(vec![1, 2, 2, 3, 3, 3, 4], 3), 3);\n assert_eq!(candidate(vec![0, 1, 2, 3, 1, 2], 1), 2);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to count the number of occurrences of a number in a given vector.\nfn frequency(a: Vec, x: isize) -> isize {\n let mut count = 0;\n for &num in a.iter() {\n if num == x {\n count += 1;\n }\n }\n count\n}"} -{"name": "mbpp_749_sort_numeric_strings", "language": "rs", "prompt": "/// Write a function to sort a given vector of strings of numbers numerically. https://www.geeksforgeeks.org/rsthon-sort-numeric-strings-in-a-vector/\nfn sort_numeric_strings(nums_str: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_749_sort_numeric_strings.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sort_numeric_strings", "test": "}\n\nfn main() {\n let candidate = sort_numeric_strings;\n assert_eq!(candidate(vec![String::from(\"4\"), String::from(\"12\"), String::from(\"45\"), String::from(\"7\"), String::from(\"0\"), String::from(\"100\"), String::from(\"200\"), String::from(\"-12\"), String::from(\"-500\")]), vec![-500, -12, 0, 4, 7, 12, 45, 100, 200]);\n assert_eq!(candidate(vec![String::from(\"2\"), String::from(\"3\"), String::from(\"8\"), String::from(\"4\"), String::from(\"7\"), String::from(\"9\"), String::from(\"8\"), String::from(\"2\"), String::from(\"6\"), String::from(\"5\"), String::from(\"1\"), String::from(\"6\"), String::from(\"1\"), String::from(\"2\"), String::from(\"3\"), String::from(\"4\"), String::from(\"6\"), String::from(\"9\"), String::from(\"1\"), String::from(\"2\")]), vec![1, 1, 1, 2, 2, 2, 2, 3, 3, 4, 4, 5, 6, 6, 6, 7, 8, 8, 9, 9]);\n assert_eq!(candidate(vec![String::from(\"1\"), String::from(\"3\"), String::from(\"5\"), String::from(\"7\"), String::from(\"1\"), String::from(\"3\"), String::from(\"13\"), String::from(\"15\"), String::from(\"17\"), String::from(\"5\"), String::from(\"7 \"), String::from(\"9\"), String::from(\"1\"), String::from(\"11\")]), vec![1, 1, 1, 3, 3, 5, 5, 7, 7, 9, 11, 13, 15, 17]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to sort a given vector of strings of numbers numerically. https://www.geeksforgeeks.org/rsthon-sort-numeric-strings-in-a-vector/\nfn sort_numeric_strings(nums_str: Vec) -> Vec {\n let mut nums: Vec = nums_str.into_iter().map(|s| s.parse::().unwrap()).collect();\n nums.sort();\n nums\n}"} -{"name": "mbpp_97_frequency_lists", "language": "rs", "prompt": "use std::collections::HashMap;\n\n/// Write a function to find frequency of each element in a flattened vector of vectors, returned in a HashMap.\nfn frequency_lists(list1: Vec>) -> HashMap {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_97_frequency_lists.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "frequency_lists", "test": "}\n\nfn main() {\n let candidate = frequency_lists;\n assert_eq!(candidate(vec![vec![1, 2, 3, 2], vec![4, 5, 6, 2], vec![7, 8, 9, 5]]), HashMap::from([(1, 1), (2, 3), (3, 1), (4, 1), (5, 2), (6, 1), (7, 1), (8, 1), (9, 1)]));\n assert_eq!(candidate(vec![vec![1, 2, 3, 4], vec![5, 6, 7, 8], vec![9, 10, 11, 12]]), HashMap::from([(1, 1), (2, 1), (3, 1), (4, 1), (5, 1), (6, 1), (7, 1), (8, 1), (9, 1), (10, 1), (11, 1), (12, 1)]));\n assert_eq!(candidate(vec![vec![20, 30, 40, 17], vec![18, 16, 14, 13], vec![10, 20, 30, 40]]), HashMap::from([(20, 2), (30, 2), (40, 2), (17, 1), (18, 1), (16, 1), (14, 1), (13, 1), (10, 1)]));\n}\n", "is_solved": true, "reflections": [], "solution": "use std::collections::HashMap;\n\n/// Write a function to find frequency of each element in a flattened vector of vectors, returned in a HashMap.\nfn frequency_lists(list1: Vec>) -> HashMap {\n let mut frequency_map: HashMap = HashMap::new();\n\n for sublist in list1 {\n for element in sublist {\n let count = frequency_map.entry(element).or_insert(0);\n *count += 1;\n }\n }\n\n frequency_map\n}"} -{"name": "mbpp_429_and_tuples", "language": "rs", "prompt": "/// Write a function to extract the elementwise and tuples from the given two tuples.\nfn and_tuples(test_tup1: (isize, isize, isize, isize), test_tup2: (isize, isize, isize, isize)) -> (isize, isize, isize, isize) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_429_and_tuples.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "and_tuples", "test": "}\n\nfn main() {\n let candidate = and_tuples;\n assert_eq!(candidate((10, 4, 6, 9), (5, 2, 3, 3)), (0, 0, 2, 1));\n assert_eq!(candidate((1, 2, 3, 4), (5, 6, 7, 8)), (1, 2, 3, 0));\n assert_eq!(candidate((8, 9, 11, 12), (7, 13, 14, 17)), (0, 9, 10, 0));\n}\n", "solution": "/// Write a function to extract the elementwise and tuples from the given two tuples.\nfn and_tuples(test_tup1: (isize, isize, isize, isize), test_tup2: (isize, isize, isize, isize)) -> (isize, isize, isize, isize) {\n let and_tup1 = std::cmp::min(test_tup1.0, test_tup2.0);\n let and_tup2 = std::cmp::min(test_tup1.1, test_tup2.1);\n let and_tup3 = std::cmp::min(test_tup1.2, test_tup2.2);\n let and_tup4 = std::cmp::min(test_tup1.3, test_tup2.3);\n\n (and_tup1, and_tup2, and_tup3, and_tup4)\n}", "is_solved": true, "reflections": ["The implementation of the `and_tuples` function is incorrect because it performs bitwise AND operations on the corresponding elements of the input tuples. This leads to unexpected results in some cases, such as when the input tuples are (1, 2, 3, 4) and (4, 3, 2, 1). The expected output is (1, 2, 2, 1), but the actual output is (0, 2, 2, 0) due to the bitwise AND operations.", "The implementation is incorrect because it is placed inside the main function, causing an unclosed delimiter error. The function should be defined outside the main function to avoid this issue."]} -{"name": "mbpp_759_is_decimal", "language": "rs", "prompt": "/// Write a function to check whether a given string is a decimal number with a precision of 2.\nfn is_decimal(num: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_759_is_decimal.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_decimal", "test": "}\n\nfn main() {\n let candidate = is_decimal;\n assert_eq!(candidate(String::from(\"123.11\")), true);\n assert_eq!(candidate(String::from(\"e666.86\")), false);\n assert_eq!(candidate(String::from(\"3.124587\")), false);\n assert_eq!(candidate(String::from(\"1.11\")), true);\n assert_eq!(candidate(String::from(\"1.1.11\")), false);\n}\n", "solution": "/// Write a function to check whether a given string is a decimal number with a precision of 2.\nfn is_decimal(num: String) -> bool {\n if num.is_empty() {\n return false;\n }\n\n let mut decimal_point_count = 0;\n let mut digits_after_decimal = 0;\n let mut is_negative = false;\n\n for (i, c) in num.chars().enumerate() {\n if i == 0 && c == '-' {\n is_negative = true;\n continue;\n }\n if c == '.' {\n decimal_point_count += 1;\n if decimal_point_count > 1 {\n return false;\n }\n } else if !c.is_digit(10) {\n return false;\n } else if decimal_point_count == 1 {\n digits_after_decimal += 1;\n if digits_after_decimal > 2 {\n return false;\n }\n }\n }\n\n decimal_point_count == 1 && digits_after_decimal == 2\n}", "is_solved": true, "reflections": ["The current implementation does not account for negative numbers, as it only checks for digits and decimal points. When encountering a negative sign, the function returns false, causing the test with a negative number to fail."]} -{"name": "mbpp_599_sum_average", "language": "rs", "prompt": "/// Write a function to find sum and average of first n natural numbers.\nfn sum_average(number: isize) -> (isize, f64) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_599_sum_average.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sum_average", "test": "}\n\nfn main() {\n let candidate = sum_average;\n assert_eq!(candidate(10), (55, 5.5));\n assert_eq!(candidate(15), (120, 8.0));\n assert_eq!(candidate(20), (210, 10.5));\n}\n", "solution": "/// Write a function to find sum and average of first n natural numbers.\nfn sum_average(number: isize) -> (isize, f64) {\n if number == 0 {\n (0, 0.0)\n } else {\n let sum = (number * (number + 1)) / 2;\n let average = sum as f64 / number as f64;\n (sum, average)\n }\n}", "is_solved": true, "reflections": ["The implementation of the sum_average function is incorrect when the input number is 0. The average calculation results in a division by zero, which produces NaN (Not a Number) as the output. This causes the test to fail when comparing the output to the expected result of (0, 0.0)."]} -{"name": "mbpp_804_is_product_even", "language": "rs", "prompt": "/// Write a function to check whether the product of numbers in a vector is even or not.\nfn is_product_even(arr: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_804_is_product_even.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_product_even", "test": "}\n\nfn main() {\n let candidate = is_product_even;\n assert_eq!(candidate(vec![1, 2, 3]), true);\n assert_eq!(candidate(vec![1, 2, 1, 4]), true);\n assert_eq!(candidate(vec![1, 1]), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check whether the product of numbers in a vector is even or not.\nfn is_product_even(arr: Vec) -> bool {\n let mut product = 1;\n\n for num in arr {\n product *= num;\n if product % 2 == 0 {\n return true;\n }\n }\n\n false\n}"} -{"name": "mbpp_103_eulerian_num", "language": "rs", "prompt": "/// Write a function to find the Eulerian number a(n, m).\nfn eulerian_num(n: isize, m: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_103_eulerian_num.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "eulerian_num", "test": "}\n\nfn main() {\n let candidate = eulerian_num;\n assert_eq!(candidate(3, 1), 4);\n assert_eq!(candidate(4, 1), 11);\n assert_eq!(candidate(5, 3), 26);\n}\n", "solution": "/// Write a function to find the Eulerian number a(n, m).\nfn eulerian_num(n: isize, m: isize) -> isize {\n if m == 0 || m == n - 1 {\n return 1;\n }\n if m < 0 || m >= n {\n return 0;\n }\n eulerian_num(n - 1, m - 1) + eulerian_num(n - 1, m) * (n - m)\n}", "is_solved": true, "reflections": ["The implementation of the eulerian_num function is incorrect because it calculates the sum of products of all possible combinations of k, instead of using the recursive formula for Eulerian numbers: A(n, m) = (n - m) * A(n - 1, m) + (m + 1) * A(n - 1, m - 1). This leads to incorrect results for the failed test cases.", "The implementation of the eulerian_num function is incorrect because it is not calculating the Eulerian number as expected. The formula used in the function is not the correct one for calculating Eulerian numbers, which is causing the function to return incorrect results for the failed test cases.", "The implementation of the eulerian_num function is incorrect because it does not follow the correct formula for calculating Eulerian numbers. The current formula used in the function is causing the output to be much larger than expected, as seen in the failed test cases.", "The implementation of the eulerian_num function is incorrect because it does not properly calculate the Eulerian number a(n, m). The formula used in the function is not the correct formula for calculating Eulerian numbers, which leads to incorrect results and failed test cases."]} -{"name": "mbpp_635_heap_sort", "language": "rs", "prompt": "/// Write a function to sort the given vector.\nfn heap_sort(iterable: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_635_heap_sort.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "heap_sort", "test": "}\n\nfn main() {\n let candidate = heap_sort;\n assert_eq!(candidate(vec![1, 3, 5, 7, 9, 2, 4, 6, 8, 0]), vec![0, 1, 2, 3, 4, 5, 6, 7, 8, 9]);\n assert_eq!(candidate(vec![25, 35, 22, 85, 14, 65, 75, 25, 58]), vec![14, 22, 25, 25, 35, 58, 65, 75, 85]);\n assert_eq!(candidate(vec![7, 1, 9, 5]), vec![1, 5, 7, 9]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to sort the given vector.\nfn heap_sort(iterable: Vec) -> Vec {\n let mut heap = iterable.clone();\n let length = heap.len();\n\n // Build the max heap\n for i in (0..length / 2).rev() {\n max_heapify(&mut heap, i, length);\n }\n\n // Extract elements from the heap\n for i in (1..length).rev() {\n heap.swap(0, i);\n max_heapify(&mut heap, 0, i);\n }\n\n heap\n}\n\nfn max_heapify(heap: &mut Vec, i: usize, length: usize) {\n let left = 2 * i + 1;\n let right = 2 * i + 2;\n let mut largest = i;\n\n if left < length && heap[left] > heap[largest] {\n largest = left;\n }\n\n if right < length && heap[right] > heap[largest] {\n largest = right;\n }\n\n if largest != i {\n heap.swap(i, largest);\n max_heapify(heap, largest, length);\n }\n}"} -{"name": "mbpp_270_sum_even_and_even_index", "language": "rs", "prompt": "/// Write a rsthon function to find the sum of even numbers at even positions of a vector.\nfn sum_even_and_even_index(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_270_sum_even_and_even_index.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sum_even_and_even_index", "test": "}\n\nfn main() {\n let candidate = sum_even_and_even_index;\n assert_eq!(candidate(vec![5, 6, 12, 1, 18, 8]), 30);\n assert_eq!(candidate(vec![3, 20, 17, 9, 2, 10, 18, 13, 6, 18]), 26);\n assert_eq!(candidate(vec![5, 6, 12, 1]), 12);\n}\n", "solution": "/// Write a rsthon function to find the sum of even numbers at even positions of a vector.\nfn sum_even_and_even_index(arr: Vec) -> isize {\n let mut sum = 0;\n\n for (index, &value) in arr.iter().enumerate() {\n if index % 2 == 0 && value % 2 == 0 {\n sum += value;\n }\n }\n\n sum\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it only adds even numbers at even positions to the sum. The correct behavior should be to add even numbers at even positions and odd numbers at odd positions. The failed tests indicate that the function is not accounting for odd numbers at odd positions.", "The implementation is incorrect because it adds the value to the sum if either the index is even and the value is even, or the index is odd and the value is odd. This does not match the requirement of summing only even numbers at even positions. Instead, it sums even numbers at even positions and odd numbers at odd positions.", "The implementation is incorrect because it only considers even numbers at even positions, but the goal is to find the sum of even numbers at even positions. The current implementation adds the value to the sum only if both the index and the value are even, which is not the desired behavior.", "The implementation is incorrect because it only checks for even indices and adds the value at that index to the sum. It does not consider whether the value at the even index is even or not. This leads to incorrect results when the value at an even index is odd, as seen in the failed test cases."]} -{"name": "mbpp_787_text_match_three", "language": "rs", "prompt": "/// Write a function that matches a string that has an a followed by three 'b'.\nfn text_match_three(text: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_787_text_match_three.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "text_match_three", "test": "}\n\nfn main() {\n let candidate = text_match_three;\n assert_eq!(candidate(String::from(\"ac\")), false);\n assert_eq!(candidate(String::from(\"dc\")), false);\n assert_eq!(candidate(String::from(\"abbbba\")), true);\n assert_eq!(candidate(String::from(\"caacabbbba\")), true);\n}\n", "solution": "/// Write a function that matches a string that has an a followed by three 'b'.\nfn text_match_three(text: String) -> bool {\n let pattern = \"abbb\";\n \n for (i, _) in text.char_indices() {\n if i + pattern.len() <= text.len() && &text[i..i + pattern.len()] == pattern {\n if i + pattern.len() == text.len() || text.chars().nth(i + pattern.len()) != Some('b') {\n return true;\n }\n }\n }\n\n false\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it is checking for the exact pattern \"abb\" to occur three times, instead of looking for a single 'a' followed by three 'b's. The function should be modified to search for an 'a' followed by three consecutive 'b's, rather than counting occurrences of the \"abb\" pattern.", "The implementation is incorrect because it returns true as soon as it finds the pattern \"abbb\" in the input string, even if there are more 'b's following the pattern. The function should only return true if there are exactly three 'b's after an 'a', not more."]} -{"name": "mbpp_765_is_polite", "language": "rs", "prompt": "/// Write a function to find nth polite number. geeksforgeeks.org/n-th-polite-number/\nfn is_polite(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_765_is_polite.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_polite", "test": "}\n\nfn main() {\n let candidate = is_polite;\n assert_eq!(candidate(7), 11);\n assert_eq!(candidate(4), 7);\n assert_eq!(candidate(9), 13);\n}\n", "solution": "/// Write a function to find nth polite number. geeksforgeeks.org/n-th-polite-number/\nfn is_polite(n: isize) -> isize {\n let mut count = 0;\n let mut current_number = 1;\n\n while count < n {\n let mut sum = 0;\n let mut i = 1;\n let mut j = 2;\n\n while sum < current_number {\n sum = (i + j) * (j - i + 1) / 2;\n if sum == current_number {\n count += 1;\n break;\n }\n if sum < current_number {\n j += 1;\n } else {\n i += 1;\n j = i + 1;\n }\n }\n\n if count == n {\n return current_number;\n }\n current_number += 1;\n\n // Skip powers of 2, as they are not polite numbers\n while current_number & (current_number - 1) == 0 {\n current_number += 1;\n }\n }\n\n return 0;\n}", "is_solved": true, "reflections": ["The implementation of the `is_polite` function is incorrect because it checks if a given number is polite, but it does not find the nth polite number as required. The function returns 1 if the input number is polite and 0 otherwise, instead of returning the nth polite number. This is why the test cases are failing, as the expected output does not match the actual output.", "The implementation of the is_polite function is incorrect because it does not properly find the nth polite number. The logic for calculating the sum of consecutive integers and incrementing the count is flawed, leading to incorrect results for the given test cases.", "The implementation of the is_polite function is incorrect because it does not properly identify polite numbers. It is incorrectly calculating the sum of consecutive integers, leading to wrong results for the nth polite number. This is evident from the failed test cases where the output does not match the expected polite numbers.", "The implementation of the is_polite function is incorrect because it does not properly find the nth polite number. The failed test cases indicate that the function is returning incorrect values for the given inputs. The logic for calculating the sum and updating the count and current_number variables needs to be revised to accurately find the nth polite number."]} -{"name": "mbpp_459_remove_uppercase", "language": "rs", "prompt": "/// Write a function to remove uppercase substrings from a given string.\nfn remove_uppercase(str1: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_459_remove_uppercase.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "remove_uppercase", "test": "}\n\nfn main() {\n let candidate = remove_uppercase;\n assert_eq!(candidate(String::from(\"cAstyoUrFavoRitETVshoWs\")), String::from(\"cstyoravoitshos\"));\n assert_eq!(candidate(String::from(\"wAtchTheinTernEtrAdIo\")), String::from(\"wtchheinerntrdo\"));\n assert_eq!(candidate(String::from(\"VoicESeaRchAndreComMendaTionS\")), String::from(\"oiceachndreomendaion\"));\n}\n", "solution": "/// Write a function to remove uppercase substrings from a given string.\nfn remove_uppercase(str1: String) -> String {\n str1.chars()\n .filter(|c| !c.is_uppercase())\n .collect::()\n}", "is_solved": true, "reflections": ["The implementation of the remove_uppercase function is incorrect because it does not properly handle the removal of uppercase characters when they are adjacent to lowercase characters. The function fails to remove the uppercase character 'S' in the test case \"MixedCASEStRiNg\", resulting in the output \"ixedtig\" instead of the expected \"ixedt\".", "The implementation of the remove_uppercase function is incorrect because it does not properly handle the removal of uppercase characters when they are adjacent to whitespace characters. The function currently keeps the whitespace characters, causing the output to be different from the expected result in the failed test case.", "The implementation of the remove_uppercase function is incorrect because it does not properly remove all uppercase characters from the input string. The failed test case shows that some uppercase characters are not being filtered out, resulting in an incorrect output.", "The implementation of the remove_uppercase function is incorrect because it filters out both uppercase characters and whitespace characters. This causes the function to remove any whitespace present in the input string, leading to incorrect results in cases where the input string contains spaces."]} -{"name": "mbpp_16_text_lowercase_underscore", "language": "rs", "prompt": "/// Write a function to that returns true if the input string contains sequences of lowercase letters joined with an underscore and false otherwise.\nfn text_lowercase_underscore(text: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_16_text_lowercase_underscore.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "text_lowercase_underscore", "test": "}\n\nfn main() {\n let candidate = text_lowercase_underscore;\n assert_eq!(candidate(String::from(\"aab_cbbbc\")), true);\n assert_eq!(candidate(String::from(\"aab_Abbbc\")), false);\n assert_eq!(candidate(String::from(\"Aaab_abbbc\")), false);\n}\n", "solution": "/// Write a function to that returns true if the input string contains sequences of lowercase letters joined with an underscore and false otherwise.\nfn text_lowercase_underscore(text: String) -> bool {\n use regex::Regex;\n let pattern = Regex::new(r\"^[a-z]+(_[a-z]+)*$\").unwrap();\n pattern.is_match(&text)\n}", "is_solved": true, "reflections": ["The implementation is wrong because the `Regex` type is undeclared, which means the required crate and import statement for the `regex` crate are missing. To fix this issue, the `regex` crate should be added to the dependencies in the `Cargo.toml` file, and the `use regex::Regex;` statement should be added at the beginning of the code.", "The implementation is incorrect because the `regex` crate is not declared or imported, causing an unresolved import error. To fix this issue, the `regex` crate needs to be added to the project's dependencies and properly imported.", "The implementation is incorrect because the `regex` crate is not declared or imported, causing an unresolved import error. To fix this issue, the `regex` crate needs to be added to the project's dependencies and properly imported.", "The implementation is incorrect because the `regex` crate is not declared or imported, causing an unresolved import error. To fix this issue, the `regex` crate needs to be added to the project's dependencies and properly imported."]} -{"name": "mbpp_731_lateralsurface_cone", "language": "rs", "prompt": "/// Write a function to find the lateral surface area of a cone given radius r and the height h.\nfn lateralsurface_cone(r: isize, h: isize) -> f64 {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_731_lateralsurface_cone.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "lateralsurface_cone", "test": "}\n\nfn main() {\n let candidate = lateralsurface_cone;\n assert_eq!(candidate(5, 12), 204.20352248333654);\n assert_eq!(candidate(10, 15), 566.3586699569488);\n assert_eq!(candidate(19, 17), 1521.8090132193388);\n}\n", "solution": "/// Write a function to find the lateral surface area of a cone given radius r and the height h.\nfn lateralsurface_cone(r: isize, h: isize) -> f64 {\n let slant_height_squared = (r * r) + (h * h) as f64;\n let slant_height = slant_height_squared.sqrt();\n let lateral_surface_area = std::f64::consts::PI * r as f64 * slant_height;\n let lateral_surface_area = (lateral_surface_area * 100.0).round() / 100.0;\n lateral_surface_area\n}", "is_solved": true, "reflections": ["The implementation of the lateralsurface_cone function is incorrect because it calculates the lateral surface area without rounding or truncating the result to two decimal places. The failed tests show that the calculated values are correct but not in the expected format. To fix this issue, the lateral surface area should be rounded to two decimal places before returning it.", "The implementation of the lateralsurface_cone function is incorrect because it calculates the slant height using the wrong formula. The current formula calculates the square of the slant height instead of the slant height itself. This leads to incorrect lateral surface area calculations, causing the failed test cases.", "The implementation of the lateralsurface_cone function is incorrect because it divides the calculated lateral surface area by 2.0, which is not part of the formula for finding the lateral surface area of a cone. This division causes the function to return incorrect results, as shown by the failed tests.", "The implementation of the lateralsurface_cone function is incorrect because it calculates the slant height using the wrong formula. The current formula adds the squares of the radius and height, but it should subtract the square of the radius from the square of the slant height. This error leads to incorrect lateral surface area calculations, causing the failed test cases."]} -{"name": "mbpp_802_count_rotation", "language": "rs", "prompt": "/// Write a rsthon function to count the number of rotations required to generate a sorted vector. https://www.geeksforgeeks.org/count-of-rotations-required-to-generate-a-sorted-vector/\nfn count_rotation(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_802_count_rotation.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_rotation", "test": "}\n\nfn main() {\n let candidate = count_rotation;\n assert_eq!(candidate(vec![3, 2, 1]), 1);\n assert_eq!(candidate(vec![4, 5, 1, 2, 3]), 2);\n assert_eq!(candidate(vec![7, 8, 9, 1, 2, 3]), 3);\n assert_eq!(candidate(vec![1, 2, 3]), 0);\n assert_eq!(candidate(vec![1, 3, 2]), 2);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to count the number of rotations required to generate a sorted vector. https://www.geeksforgeeks.org/count-of-rotations-required-to-generate-a-sorted-vector/\nfn count_rotation(arr: Vec) -> isize {\n let n = arr.len();\n let mut min_index = 0;\n\n for i in 1..n {\n if arr[i] < arr[min_index] {\n min_index = i;\n }\n }\n\n min_index as isize\n}"} -{"name": "mbpp_782_odd_length_sum", "language": "rs", "prompt": "/// Write a rsthon function to find the sum of all odd length subvectors. https://www.geeksforgeeks.org/sum-of-all-odd-length-subvectors/\nfn odd_length_sum(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_782_odd_length_sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "odd_length_sum", "test": "}\n\nfn main() {\n let candidate = odd_length_sum;\n assert_eq!(candidate(vec![1, 2, 4]), 14);\n assert_eq!(candidate(vec![1, 2, 1, 2]), 15);\n assert_eq!(candidate(vec![1, 7]), 8);\n}\n", "solution": "/// Write a rsthon function to find the sum of all odd length subvectors. https://www.geeksforgeeks.org/sum-of-all-odd-length-subvectors/\nfn odd_length_sum(arr: Vec) -> isize {\n let n = arr.len();\n let mut sum = 0;\n\n for i in 0..n {\n for j in (i..n).step_by(1) {\n if (j - i + 1) % 2 == 1 {\n let mut current_sum = 0;\n for k in i..=j {\n current_sum += arr[k];\n }\n sum += current_sum;\n }\n }\n }\n\n sum\n}", "is_solved": true, "reflections": ["The implementation of the odd_length_sum function is incorrect because it calculates the sum of all subvectors, not just the odd length ones. The current_sum variable accumulates the sum of all subvectors, and the condition (j - i + 1) % 2 != 0 does not effectively filter out even length subvectors. This leads to incorrect results in the failed test cases.", "The implementation is incorrect because it calculates the sum of all subvectors with even indices difference instead of odd length subvectors. The inner loop should start at i and step by 2, but the range should be inclusive to ensure the subvector length is odd. This causes the function to return incorrect results for some test cases.", "The implementation of the odd_length_sum function is incorrect because it calculates the sum of all subvectors with even indices instead of odd length subvectors. The inner loop that iterates over 'j' should start at 'i' and increment by 2, but it should also ensure that the subvector length is odd by checking if (j - i + 1) is odd. Due to this error, the function produces incorrect results for the failed test cases.", "The implementation is incorrect because it skips some odd length subvectors due to the use of the `step_by(2)` method in the second loop. This causes the function to miss some subvectors, leading to incorrect sum calculations."]} -{"name": "mbpp_470_add_pairwise", "language": "rs", "prompt": "/// Write a function to find the pairwise addition of the neighboring elements of the given tuple.\nfn add_pairwise(test_tup: (isize, isize, isize, isize, isize)) -> (isize, isize, isize, isize) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_470_add_pairwise.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "add_pairwise", "test": "}\n\nfn main() {\n let candidate = add_pairwise;\n assert_eq!(candidate((1, 5, 7, 8, 10)), (6, 12, 15, 18));\n assert_eq!(candidate((2, 6, 8, 9, 11)), (8, 14, 17, 20));\n assert_eq!(candidate((3, 7, 9, 10, 12)), (10, 16, 19, 22));\n}\n", "solution": "/// Write a function to find the pairwise addition of the neighboring elements of the given tuple.\nfn add_pairwise(test_tup: (isize, isize, isize, isize, isize)) -> (isize, isize, isize, isize) {\n let (a, b, c, d, e) = test_tup;\n (a + b, b + c, c + d, d + e)\n}", "is_solved": true, "reflections": ["The implementation is incorrect because the function is defined inside the main function, causing an unclosed delimiter error. The add_pairwise function should be defined outside the main function to fix the issue."]} -{"name": "mbpp_17_square_perimeter", "language": "rs", "prompt": "/// Write a function that returns the perimeter of a square given its side length as input.\nfn square_perimeter(a: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_17_square_perimeter.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "square_perimeter", "test": "}\n\nfn main() {\n let candidate = square_perimeter;\n assert_eq!(candidate(10), 40);\n assert_eq!(candidate(5), 20);\n assert_eq!(candidate(4), 16);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function that returns the perimeter of a square given its side length as input.\nfn square_perimeter(a: isize) -> isize {\n 4 * a\n}"} -{"name": "mbpp_228_all_Bits_Set_In_The_Given_Range", "language": "rs", "prompt": "/// Write a rsthon function to check whether all the bits are unset in the given range or not.\nfn all_Bits_Set_In_The_Given_Range(n: isize, l: isize, r: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_228_all_Bits_Set_In_The_Given_Range.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "all_Bits_Set_In_The_Given_Range", "test": "}\n\nfn main() {\n let candidate = all_Bits_Set_In_The_Given_Range;\n assert_eq!(candidate(4, 1, 2), true);\n assert_eq!(candidate(17, 2, 4), true);\n assert_eq!(candidate(39, 4, 6), false);\n}\n", "solution": "/// Write a rsthon function to check whether all the bits are unset in the given range or not.\nfn all_Bits_Set_In_The_Given_Range(n: isize, l: isize, r: isize) -> bool {\n for i in l..=r {\n if (n & (1 << i)) == 0 {\n return false;\n }\n }\n true\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it checks if all bits are set in the given range, rather than checking if all bits are unset. The function returns false when it encounters a 0 bit, but it should return false when it encounters a 1 bit.", "The function implementation is incorrect because it checks if all bits are unset (0) in the given range, instead of checking if all bits are set (1). The condition in the if statement should be checking for set bits, not unset bits.", "The implementation is incorrect because it checks if all bits are set in the given range, rather than checking if all bits are unset. The function returns false when a bit is unset, but it should return false when a bit is set. This causes the failed test cases where the expected result is true when all bits are unset in the given range.", "The function implementation is incorrect because it checks if all bits are unset (0) in the given range, instead of checking if all bits are set (1). The condition in the if statement should be checking for set bits, not unset bits."]} -{"name": "mbpp_447_cube_nums", "language": "rs", "prompt": "/// Write a function to find cubes of individual elements in a vector.\nfn cube_nums(nums: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_447_cube_nums.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "cube_nums", "test": "}\n\nfn main() {\n let candidate = cube_nums;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 10]), vec![1, 8, 27, 64, 125, 216, 343, 512, 729, 1000]);\n assert_eq!(candidate(vec![10, 20, 30]), vec![1000, 8000, 27000]);\n assert_eq!(candidate(vec![12, 15]), vec![1728, 3375]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find cubes of individual elements in a vector.\nfn cube_nums(nums: Vec) -> Vec {\n nums.into_iter().map(|num| num * num * num).collect()\n}"} -{"name": "mbpp_261_division_elements", "language": "rs", "prompt": "/// Write a function that takes in two tuples and performs mathematical division operation element-wise across the given tuples.\nfn division_elements(test_tup1: (isize, isize, isize, isize), test_tup2: (isize, isize, isize, isize)) -> (isize, isize, isize, isize) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_261_division_elements.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "division_elements", "test": "}\n\nfn main() {\n let candidate = division_elements;\n assert_eq!(candidate((10, 4, 6, 9), (5, 2, 3, 3)), (2, 2, 2, 3));\n assert_eq!(candidate((12, 6, 8, 16), (6, 3, 4, 4)), (2, 2, 2, 4));\n assert_eq!(candidate((20, 14, 36, 18), (5, 7, 6, 9)), (4, 2, 6, 2));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function that takes in two tuples and performs mathematical division operation element-wise across the given tuples.\nfn division_elements(test_tup1: (isize, isize, isize, isize), test_tup2: (isize, isize, isize, isize)) -> (isize, isize, isize, isize) {\n let result = (\n test_tup1.0 / test_tup2.0,\n test_tup1.1 / test_tup2.1,\n test_tup1.2 / test_tup2.2,\n test_tup1.3 / test_tup2.3,\n );\n\n result\n}"} -{"name": "mbpp_581_surface_Area", "language": "rs", "prompt": "/// Write a rsthon function to find the surface area of a square rsramid with a given base edge and height.\nfn surface_Area(b: isize, s: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_581_surface_Area.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "surface_Area", "test": "}\n\nfn main() {\n let candidate = surface_Area;\n assert_eq!(candidate(3, 4), 33);\n assert_eq!(candidate(4, 5), 56);\n assert_eq!(candidate(1, 2), 5);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the surface area of a square rsramid with a given base edge and height.\nfn surface_Area(b: isize, s: isize) -> isize {\n let base_area = b * b;\n let lateral_area = 2 * b * s;\n let surface_area = base_area + lateral_area;\n surface_area\n}"} -{"name": "mbpp_283_validate", "language": "rs", "prompt": "/// Write a rsthon function takes in an integer and check whether the frequency of each digit in the integer is less than or equal to the digit itself.\nfn validate(n: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_283_validate.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "validate", "test": "}\n\nfn main() {\n let candidate = validate;\n assert_eq!(candidate(1234), true);\n assert_eq!(candidate(51241), false);\n assert_eq!(candidate(321), true);\n}\n", "solution": "/// Write a rsthon function takes in an integer and check whether the frequency of each digit in the integer is less than or equal to the digit itself.\nfn validate(n: isize) -> bool {\n let mut freq = vec![0; 10];\n\n for c in n.to_string().chars() {\n let digit = c.to_digit(10).unwrap() as usize;\n freq[digit] += 1;\n }\n\n for (i, count) in freq.iter().enumerate() {\n if *count > 0 && *count > i {\n return false;\n }\n }\n\n for (i, count) in freq.iter().enumerate() {\n if *count > i {\n return false;\n }\n }\n\n true\n}", "is_solved": true, "reflections": ["The implementation of the `validate` function is incorrect because it checks if the frequency of each digit is less than or equal to the digit's value itself. However, the function should check if the frequency of each digit is less than or equal to the digit's value in the input integer. This causes the function to return incorrect results for some test cases, such as `validate(3333)` and `validate(122)`.", "The implementation of the `validate` function is incorrect because it checks if the frequency of each digit is greater than the index (i.e., the digit itself) instead of checking if the frequency is less than or equal to the digit. This causes the function to return incorrect results for some test cases, such as `validate(3333)` and `validate(122)`.", "The implementation of the `validate` function is incorrect because it checks if the frequency of each digit is greater than the index (i.e., the digit itself) instead of checking if the frequency is less than or equal to the digit. This causes the function to return incorrect results for some test cases, such as `validate(3333)` and `validate(122)`.", "The implementation of the `validate` function is incorrect because it checks if the frequency of each digit is greater than the index (i.e., the digit itself) instead of checking if the frequency is less than or equal to the digit. This causes the function to return incorrect results for some test cases, such as `validate(3333)` and `validate(122)`."]} -{"name": "mbpp_101_kth_element", "language": "rs", "prompt": "/// Write a function to find the kth element in the given vector using 1-based indexing.\nfn kth_element(arr: Vec, k: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_101_kth_element.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "kth_element", "test": "}\n\nfn main() {\n let candidate = kth_element;\n assert_eq!(candidate(vec![12, 3, 5, 7, 19], 2), 3);\n assert_eq!(candidate(vec![17, 24, 8, 23], 3), 8);\n assert_eq!(candidate(vec![16, 21, 25, 36, 4], 4), 36);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the kth element in the given vector using 1-based indexing.\nfn kth_element(arr: Vec, k: isize) -> isize {\n if k > 0 && k as usize <= arr.len() {\n arr[(k - 1) as usize]\n } else {\n panic!(\"Index out of bounds: The given index is not within the range of the vector.\");\n }\n}"} -{"name": "mbpp_461_upper_ctr", "language": "rs", "prompt": "/// Write a rsthon function to count the upper case characters in a given string.\nfn upper_ctr(str: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_461_upper_ctr.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "upper_ctr", "test": "}\n\nfn main() {\n let candidate = upper_ctr;\n assert_eq!(candidate(String::from(\"PYthon\")), 1);\n assert_eq!(candidate(String::from(\"BigData\")), 1);\n assert_eq!(candidate(String::from(\"program\")), 0);\n}\n", "solution": "/// Write a rsthon function to count the upper case characters in a given string.\nfn upper_ctr(str: String) -> isize {\n let mut count = 0;\n for c in str.chars() {\n if c.is_uppercase() {\n count += 1;\n }\n }\n count as isize\n}", "is_solved": true, "reflections": ["The implementation of the upper_ctr function is incorrect because it is counting the whitespace character as an uppercase character. This is causing the failed test case, as it is returning 5 instead of the expected 4 uppercase characters.", "The implementation of the upper_ctr function is incorrect because it counts uppercase characters and non-whitespace characters together. This leads to an incorrect count of uppercase characters in the input string, as demonstrated by the failed test case.", "The implementation of the upper_ctr function is incorrect because it is counting the whitespace character as an uppercase character. This causes the function to return a higher count than expected when the input string contains spaces.", "The implementation of the upper_ctr function is incorrect because it counts uppercase characters and non-whitespace characters separately, leading to an incorrect count when there are uppercase characters that are also non-whitespace characters. This issue causes the test with the input \"RustGPT is Awesome\" to fail, as it counts the uppercase 'T' in \"RustGPT\" as two separate characters."]} -{"name": "mbpp_593_removezero_ip", "language": "rs", "prompt": "/// Write a function to remove leading zeroes from an ip address.\nfn removezero_ip(ip: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_593_removezero_ip.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "removezero_ip", "test": "}\n\nfn main() {\n let candidate = removezero_ip;\n assert_eq!(candidate(String::from(\"216.08.094.196\")), String::from(\"216.8.94.196\"));\n assert_eq!(candidate(String::from(\"12.01.024\")), String::from(\"12.1.24\"));\n assert_eq!(candidate(String::from(\"216.08.094.0196\")), String::from(\"216.8.94.196\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to remove leading zeroes from an ip address.\nfn removezero_ip(ip: String) -> String {\n let mut result = String::new();\n let octets = ip.split('.').collect::>();\n\n for (i, octet) in octets.iter().enumerate() {\n let trimmed_octet = octet.trim_start_matches('0');\n let cleaned_octet = if trimmed_octet.is_empty() { \"0\" } else { trimmed_octet };\n\n if i > 0 {\n result.push('.');\n }\n result.push_str(cleaned_octet);\n }\n\n result\n}"} -{"name": "mbpp_788_new_tuple", "language": "rs", "prompt": "/// Write a function to create a new tuple from the given string and vector.\nfn new_tuple(test_list: Vec, test_str: String) -> (String, String, String) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_788_new_tuple.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "new_tuple", "test": "}\n\nfn main() {\n let candidate = new_tuple;\n assert_eq!(candidate(vec![String::from(\"WEB\"), String::from(\"is\")], String::from(\"best\")), (String::from(\"WEB\"), String::from(\"is\"), String::from(\"best\")));\n assert_eq!(candidate(vec![String::from(\"We\"), String::from(\"are\")], String::from(\"Developers\")), (String::from(\"We\"), String::from(\"are\"), String::from(\"Developers\")));\n assert_eq!(candidate(vec![String::from(\"Part\"), String::from(\"is\")], String::from(\"Wrong\")), (String::from(\"Part\"), String::from(\"is\"), String::from(\"Wrong\")));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to create a new tuple from the given string and vector.\nfn new_tuple(test_list: Vec, test_str: String) -> (String, String, String) {\n if test_list.len() >= 2 {\n let first = test_list[0].clone();\n let second = test_list[1].clone();\n (first, second, test_str)\n } else {\n panic!(\"The input vector must have at least 2 elements.\");\n }\n}"} -{"name": "mbpp_777_find_sum", "language": "rs", "prompt": "/// Write a rsthon function to find the sum of non-repeated elements in a given vector.\nfn find_sum(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_777_find_sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_sum", "test": "}\n\nfn main() {\n let candidate = find_sum;\n assert_eq!(candidate(vec![1, 2, 3, 1, 1, 4, 5, 6]), 21);\n assert_eq!(candidate(vec![1, 10, 9, 4, 2, 10, 10, 45, 4]), 71);\n assert_eq!(candidate(vec![12, 10, 9, 45, 2, 10, 10, 45, 10]), 78);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the sum of non-repeated elements in a given vector.\nfn find_sum(arr: Vec) -> isize {\n let mut unique_elements = Vec::new();\n let mut sum = 0;\n\n for &num in arr.iter() {\n if unique_elements.contains(&num) {\n continue;\n }\n let count = arr.iter().filter(|&&x| x == num).count();\n if count == 1 {\n sum += num;\n unique_elements.push(num);\n }\n }\n\n sum\n}"} -{"name": "mbpp_586_split_Arr", "language": "rs", "prompt": "/// Write a rsthon function to split a vector at the nth eelment and add the first part to the end.\nfn split_Arr(l: Vec, n: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_586_split_Arr.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "split_Arr", "test": "}\n\nfn main() {\n let candidate = split_Arr;\n assert_eq!(candidate(vec![12, 10, 5, 6, 52, 36], 2), vec![5, 6, 52, 36, 12, 10]);\n assert_eq!(candidate(vec![1, 2, 3, 4], 1), vec![2, 3, 4, 1]);\n assert_eq!(candidate(vec![0, 1, 2, 3, 4, 5, 6, 7], 3), vec![3, 4, 5, 6, 7, 0, 1, 2]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to split a vector at the nth eelment and add the first part to the end.\nfn split_Arr(l: Vec, n: isize) -> Vec {\n if n <= 0 || n as usize >= l.len() {\n return l;\n }\n\n let mut result = Vec::with_capacity(l.len());\n for i in n as usize..l.len() {\n result.push(l[i]);\n }\n for i in 0..n as usize {\n result.push(l[i]);\n }\n\n result\n}"} -{"name": "mbpp_104_sort_sublists", "language": "rs", "prompt": "/// Write a function to sort each subvector of strings in a given vector of vectors.\nfn sort_sublists(input_list: Vec>) -> Vec> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_104_sort_sublists.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sort_sublists", "test": "}\n\nfn main() {\n let candidate = sort_sublists;\n assert_eq!(candidate(vec![vec![String::from(\"green\"), String::from(\"orange\")], vec![String::from(\"black\"), String::from(\"white\")], vec![String::from(\"white\"), String::from(\"black\"), String::from(\"orange\")]]), vec![vec![String::from(\"green\"), String::from(\"orange\")], vec![String::from(\"black\"), String::from(\"white\")], vec![String::from(\"black\"), String::from(\"orange\"), String::from(\"white\")]]);\n assert_eq!(candidate(vec![vec![String::from(\" red \"), String::from(\"green\")], vec![String::from(\"blue \"), String::from(\" black\")], vec![String::from(\" orange\"), String::from(\"brown\")]]), vec![vec![String::from(\" red \"), String::from(\"green\")], vec![String::from(\" black\"), String::from(\"blue \")], vec![String::from(\" orange\"), String::from(\"brown\")]]);\n assert_eq!(candidate(vec![vec![String::from(\"zilver\"), String::from(\"gold\")], vec![String::from(\"magnesium\"), String::from(\"aluminium\")], vec![String::from(\"steel\"), String::from(\"bronze\")]]), vec![vec![String::from(\"gold\"), String::from(\"zilver\")], vec![String::from(\"aluminium\"), String::from(\"magnesium\")], vec![String::from(\"bronze\"), String::from(\"steel\")]]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to sort each subvector of strings in a given vector of vectors.\nfn sort_sublists(input_list: Vec>) -> Vec> {\n let mut sorted_list = input_list.clone();\n for sublist in sorted_list.iter_mut() {\n sublist.sort();\n }\n sorted_list\n}"} -{"name": "mbpp_472_check_Consecutive", "language": "rs", "prompt": "/// Write a rsthon function to check whether the given vector contains consecutive numbers or not.\nfn check_Consecutive(l: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_472_check_Consecutive.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "check_Consecutive", "test": "}\n\nfn main() {\n let candidate = check_Consecutive;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5]), true);\n assert_eq!(candidate(vec![1, 2, 3, 5, 6]), false);\n assert_eq!(candidate(vec![1, 2, 1]), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to check whether the given vector contains consecutive numbers or not.\nfn check_Consecutive(l: Vec) -> bool {\n if l.len() < 2 {\n return false;\n }\n\n let mut sorted_l = l.clone();\n sorted_l.sort();\n\n for i in 1..sorted_l.len() {\n if sorted_l[i] - sorted_l[i - 1] != 1 {\n return false;\n }\n }\n\n true\n}"} -{"name": "mbpp_310_string_to_tuple", "language": "rs", "prompt": "/// Write a function to convert a given string to a vector of characters.\nfn string_to_tuple(str1: String) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_310_string_to_tuple.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "string_to_tuple", "test": "}\n\nfn main() {\n let candidate = string_to_tuple;\n assert_eq!(candidate(String::from(\"python 3.0\")), vec![String::from(\"p\"), String::from(\"y\"), String::from(\"t\"), String::from(\"h\"), String::from(\"o\"), String::from(\"n\"), String::from(\"3\"), String::from(\".\"), String::from(\"0\")]);\n assert_eq!(candidate(String::from(\"item1\")), vec![String::from(\"i\"), String::from(\"t\"), String::from(\"e\"), String::from(\"m\"), String::from(\"1\")]);\n assert_eq!(candidate(String::from(\"15.10\")), vec![String::from(\"1\"), String::from(\"5\"), String::from(\".\"), String::from(\"1\"), String::from(\"0\")]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to convert a given string to a vector of characters.\nfn string_to_tuple(str1: String) -> Vec {\n str1.chars().map(|c| c.to_string()).collect()\n}"} -{"name": "mbpp_266_lateralsurface_cube", "language": "rs", "prompt": "/// Write a function to find the lateral surface area of a cube given its side length.\nfn lateralsurface_cube(l: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_266_lateralsurface_cube.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "lateralsurface_cube", "test": "}\n\nfn main() {\n let candidate = lateralsurface_cube;\n assert_eq!(candidate(5), 100);\n assert_eq!(candidate(9), 324);\n assert_eq!(candidate(10), 400);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the lateral surface area of a cube given its side length.\nfn lateralsurface_cube(l: isize) -> isize {\n let surface_area = 4 * l * l;\n surface_area\n}"} -{"name": "mbpp_271_even_Power_Sum", "language": "rs", "prompt": "/// Write a rsthon function that takes in an integer n and finds the sum of the first n even natural numbers that are raised to the fifth power.\nfn even_Power_Sum(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_271_even_Power_Sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "even_Power_Sum", "test": "}\n\nfn main() {\n let candidate = even_Power_Sum;\n assert_eq!(candidate(2), 1056);\n assert_eq!(candidate(3), 8832);\n assert_eq!(candidate(1), 32);\n}\n", "solution": "/// Write a rsthon function that takes in an integer n and finds the sum of the first n even natural numbers that are raised to the fifth power.\nfn even_Power_Sum(n: isize) -> isize {\n let mut sum = 0;\n for i in 1..=n {\n let even_num = i * 2;\n let even_num_power_5 = even_num.pow(5);\n sum += even_num_power_5;\n }\n sum\n}", "is_solved": true, "reflections": ["The implementation of the even_Power_Sum function is incorrect because it starts the loop from 1 and calculates the sum of the first n even numbers raised to the fifth power. However, the problem statement asks for the sum of the first n even natural numbers raised to the fifth power, and the first even natural number is 0. This causes the function to return incorrect results for the given test cases.", "The implementation of the even_Power_Sum function is incorrect because it starts the loop at 0, which results in the first even number being 0 and its fifth power being added to the sum. This causes the sum to be larger than expected. To fix this, the loop should start at 1 instead of 0.", "The implementation of the even_Power_Sum function is incorrect because it calculates the sum of the first n even numbers raised to the fifth power, instead of the sum of the first n even natural numbers raised to the fifth power. This causes the function to return incorrect results for the given test cases.", "The implementation of the even_Power_Sum function is incorrect because it starts the loop from 0, which results in the first even number being 0 and its fifth power being added to the sum. This causes the sum to be larger than expected. To fix this, the loop should start from 1 instead of 0."]} -{"name": "mbpp_238_number_of_substrings", "language": "rs", "prompt": "/// Write a rsthon function to count the number of non-empty substrings of a given string.\nfn number_of_substrings(str: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_238_number_of_substrings.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "number_of_substrings", "test": "}\n\nfn main() {\n let candidate = number_of_substrings;\n assert_eq!(candidate(String::from(\"abc\")), 6);\n assert_eq!(candidate(String::from(\"abcd\")), 10);\n assert_eq!(candidate(String::from(\"abcde\")), 15);\n}\n", "solution": "/// Write a rsthon function to count the number of non-empty substrings of a given string.\nfn number_of_substrings(str: String) -> isize {\n let n = str.len();\n ((n * (n + 1)) / 2) as isize\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it returns a `usize` value instead of the expected `isize` return type. The error occurs when calculating the number of substrings using the formula `(n * (n + 1)) / 2`, which results in a `usize` value. To fix this, the value should be converted to `isize` before returning it."]} -{"name": "mbpp_592_sum_Of_product", "language": "rs", "prompt": "/// Write a rsthon function to find the sum of the product of consecutive binomial co-efficients.\nfn sum_Of_product(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_592_sum_Of_product.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sum_Of_product", "test": "}\n\nfn main() {\n let candidate = sum_Of_product;\n assert_eq!(candidate(3), 15);\n assert_eq!(candidate(4), 56);\n assert_eq!(candidate(1), 1);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the sum of the product of consecutive binomial co-efficients.\nfn sum_Of_product(n: isize) -> isize {\n let mut sum = 0;\n for i in 0..n {\n let binomial_coefficient = binomial(n, i) * binomial(n, i + 1);\n sum += binomial_coefficient;\n }\n sum\n}\n\nfn binomial(n: isize, k: isize) -> isize {\n if k == 0 || k == n {\n 1\n } else {\n binomial(n - 1, k - 1) + binomial(n - 1, k)\n }\n}"} -{"name": "mbpp_74_is_samepatterns", "language": "rs", "prompt": "/// Write a function to check whether it follows the sequence given in the patterns vector.\nfn is_samepatterns(colors: Vec, patterns: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_74_is_samepatterns.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_samepatterns", "test": "}\n\nfn main() {\n let candidate = is_samepatterns;\n assert_eq!(candidate(vec![String::from(\"red\"), String::from(\"green\"), String::from(\"green\")], vec![String::from(\"a\"), String::from(\"b\"), String::from(\"b\")]), true);\n assert_eq!(candidate(vec![String::from(\"red\"), String::from(\"green\"), String::from(\"greenn\")], vec![String::from(\"a\"), String::from(\"b\"), String::from(\"b\")]), false);\n assert_eq!(candidate(vec![String::from(\"red\"), String::from(\"green\"), String::from(\"greenn\")], vec![String::from(\"a\"), String::from(\"b\")]), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check whether it follows the sequence given in the patterns vector.\nfn is_samepatterns(colors: Vec, patterns: Vec) -> bool {\n if colors.len() != patterns.len() {\n return false;\n }\n\n let mut color_map = std::collections::HashMap::new();\n let mut pattern_map = std::collections::HashMap::new();\n\n for (color, pattern) in colors.iter().zip(patterns.iter()) {\n if !color_map.contains_key(color) {\n color_map.insert(color.clone(), pattern.clone());\n } else if color_map[color] != *pattern {\n return false;\n }\n\n if !pattern_map.contains_key(pattern) {\n pattern_map.insert(pattern.clone(), color.clone());\n } else if pattern_map[pattern] != *color {\n return false;\n }\n }\n\n true\n}"} -{"name": "mbpp_415_max_Product", "language": "rs", "prompt": "/// Write a rsthon function to find a pair with highest product from a given vector of integers.\nfn max_Product(arr: Vec) -> (isize, isize) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_415_max_Product.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_Product", "test": "}\n\nfn main() {\n let candidate = max_Product;\n assert_eq!(candidate(vec![1, 2, 3, 4, 7, 0, 8, 4]), (7, 8));\n assert_eq!(candidate(vec![0, -1, -2, -4, 5, 0, -6]), (-4, -6));\n assert_eq!(candidate(vec![1, 2, 3]), (2, 3));\n}\n", "solution": "/// Write a rsthon function to find a pair with highest product from a given vector of integers.\nfn max_Product(arr: Vec) -> (isize, isize) {\n let mut max_product = std::isize::MIN;\n let mut pair = (0, 0);\n\n for i in 0..arr.len() {\n for j in i + 1..arr.len() {\n let product = arr[i] * arr[j];\n if product > max_product {\n max_product = product;\n pair = (arr[i], arr[j]);\n } else if product == max_product {\n if arr[i].abs() + arr[j].abs() > pair.0.abs() + pair.1.abs() {\n pair = (arr[i], arr[j]);\n }\n }\n }\n }\n\n pair\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it does not handle the case where the highest product is obtained from two negative numbers. In the failed test, the correct pair should be (-1, -2) since their product is 2, but the implementation returns (-3, -4) because it only considers the largest absolute values.", "The implementation is incorrect because it first tries to find the maximum product among all pairs, and if the pair is (0, 0), it then tries to find the minimum positive product. This approach fails when the highest product is achieved by multiplying two negative numbers, as seen in the failed test case. The function should directly find the pair with the highest product, regardless of whether the numbers are positive or negative.", "The implementation is incorrect because it does not handle the case where the highest product is formed by two negative numbers. In the failed test, the correct pair should be (-1, -2) since their product is 2, but the implementation returns (-3, -4) because it only considers the largest absolute values.", "The implementation is incorrect because it does not handle the case where the highest product is formed by two negative numbers. In the failed test, the correct pair should be (-1, -2) as their product is 2, but the implementation returns (-3, -4) which has a product of 12. The issue is that the function does not consider the possibility of a higher product being formed by two smaller negative numbers."]} -{"name": "mbpp_781_count_divisors", "language": "rs", "prompt": "/// Write a rsthon function to check whether the count of divisors is even. https://www.w3resource.com/rsthon-exercises/basic/rsthon-basic-1-exercise-24.php\nfn count_divisors(n: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_781_count_divisors.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_divisors", "test": "}\n\nfn main() {\n let candidate = count_divisors;\n assert_eq!(candidate(10), true);\n assert_eq!(candidate(100), false);\n assert_eq!(candidate(125), true);\n}\n", "solution": "/// Write a rsthon function to check whether the count of divisors is even. https://www.w3resource.com/rsthon-exercises/basic/rsthon-basic-1-exercise-24.php\nfn count_divisors(n: isize) -> bool {\n let mut count = 0;\n\n for i in 1..=(n as f64).sqrt() as isize {\n if n % i == 0 {\n if n / i == i {\n count += 1;\n } else {\n count += 2;\n }\n }\n }\n\n if n == 1 {\n return false;\n }\n\n count % 2 == 0\n}", "is_solved": true, "reflections": ["The implementation of the count_divisors function is incorrect because it calculates the count of divisors and checks if it's even, but the problem statement asks to check if the count of divisors is even. The function should return true for numbers with an odd count of divisors and false for numbers with an even count of divisors. The failed tests indicate that the function is not handling cases with perfect squares and numbers with only two divisors correctly.", "The implementation of the count_divisors function is incorrect because it returns true when the count of divisors is odd, and false when the count is even. However, the goal is to check whether the count of divisors is even, so the function should return true when the count is even and false when it's odd. The final check in the function should be `count % 2 == 0` instead of `count % 2 != 0`.", "The implementation of the count_divisors function is incorrect because it calculates the count of divisors but does not properly determine if the count is even or odd. The failed tests indicate that the function returns the wrong boolean value for certain input values, such as 1, 2, and 8.", "The implementation is incorrect because it returns true for numbers with an odd count of divisors, such as 8 and 2. The function should return true only when the count of divisors is even, but it currently returns true for odd counts as well."]} -{"name": "mbpp_441_surfacearea_cube", "language": "rs", "prompt": "/// Write a function to find the surface area of a cube of a given size.\nfn surfacearea_cube(l: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_441_surfacearea_cube.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "surfacearea_cube", "test": "}\n\nfn main() {\n let candidate = surfacearea_cube;\n assert_eq!(candidate(5), 150);\n assert_eq!(candidate(3), 54);\n assert_eq!(candidate(10), 600);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the surface area of a cube of a given size.\nfn surfacearea_cube(l: isize) -> isize {\n let area = 6 * l * l;\n area\n}"} -{"name": "mbpp_396_check_char", "language": "rs", "prompt": "/// Write a function to check whether the given string starts and ends with the same character or not.\nfn check_char(string: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_396_check_char.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "check_char", "test": "}\n\nfn main() {\n let candidate = check_char;\n assert_eq!(candidate(String::from(\"abba\")), String::from(\"Valid\"));\n assert_eq!(candidate(String::from(\"a\")), String::from(\"Valid\"));\n assert_eq!(candidate(String::from(\"abcd\")), String::from(\"Invalid\"));\n}\n", "solution": "/// Write a function to check whether the given string starts and ends with the same character or not.\nfn check_char(string: String) -> String {\n if string.is_empty() {\n return \"Empty string\".to_string();\n }\n\n let first_char = string.chars().next().unwrap();\n let last_char = string.chars().last().unwrap();\n\n if first_char == last_char {\n \"true\".to_string()\n } else {\n \"false\".to_string()\n }\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it returns capitalized \"True\" and \"False\" strings instead of lowercase \"true\" and \"false\" as expected by the unit tests. This causes the tests to fail due to the case difference in the output strings."]} -{"name": "mbpp_757_count_reverse_pairs", "language": "rs", "prompt": "/// Write a function to count the pairs of reverse strings in the given string vector. https://www.geeksforgeeks.org/rsthon-program-to-count-the-pairs-of-reverse-strings/\nfn count_reverse_pairs(test_list: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_757_count_reverse_pairs.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_reverse_pairs", "test": "}\n\nfn main() {\n let candidate = count_reverse_pairs;\n assert_eq!(candidate(vec![String::from(\"julia\"), String::from(\"best\"), String::from(\"tseb\"), String::from(\"for\"), String::from(\"ailuj\")]), 2);\n assert_eq!(candidate(vec![String::from(\"geeks\"), String::from(\"best\"), String::from(\"for\"), String::from(\"skeeg\")]), 1);\n assert_eq!(candidate(vec![String::from(\"makes\"), String::from(\"best\"), String::from(\"sekam\"), String::from(\"for\"), String::from(\"rof\")]), 2);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to count the pairs of reverse strings in the given string vector. https://www.geeksforgeeks.org/rsthon-program-to-count-the-pairs-of-reverse-strings/\nfn count_reverse_pairs(test_list: Vec) -> isize {\n let mut count = 0;\n\n for i in 0..test_list.len() {\n for j in i + 1..test_list.len() {\n if test_list[i].chars().rev().collect::() == test_list[j] {\n count += 1;\n }\n }\n }\n\n count\n}"} -{"name": "mbpp_75_find_tuples", "language": "rs", "prompt": "/// Write a function to find tuples which have all elements divisible by k from the given vector of tuples.\nfn find_tuples(test_list: Vec<(isize, isize, isize)>, K: isize) -> Vec<(isize, isize, isize)> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_75_find_tuples.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_tuples", "test": "}\n\nfn main() {\n let candidate = find_tuples;\n assert_eq!(candidate(vec![(6, 24, 12), (7, 9, 6), (12, 18, 21)], 6), vec![(6, 24, 12)]);\n assert_eq!(candidate(vec![(5, 25, 30), (4, 2, 3), (7, 8, 9)], 5), vec![(5, 25, 30)]);\n assert_eq!(candidate(vec![(7, 9, 16), (8, 16, 4), (19, 17, 18)], 4), vec![(8, 16, 4)]);\n}\n", "solution": "/// Write a function to find tuples which have all elements divisible by k from the given vector of tuples.\nfn find_tuples(test_list: Vec<(isize, isize, isize)>, K: isize) -> Vec<(isize, isize, isize)> {\n test_list\n .into_iter()\n .filter(|(a, b, c)| a % K == 0 && b % K == 0 && c % K == 0)\n .collect()\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it only returns tuples where all elements are divisible by K. The failed test case indicates that the function should return tuples where at least one element is divisible by K, not all of them.", "The implementation is incorrect because it filters tuples where at least one element is divisible by K, instead of filtering tuples where all elements are divisible by K. The filter condition should use logical AND (&&) instead of logical OR (||) to ensure all elements in the tuple are divisible by K.", "The implementation is incorrect because it only returns tuples where all elements are divisible by K. The failed test case shows that the function should return tuples where at least one element is divisible by K, not all of them.", "The implementation is incorrect because it filters tuples where at least one element is divisible by K, instead of filtering tuples where all elements are divisible by K. The filter condition should use logical AND (&&) instead of logical OR (||) to ensure all elements in the tuple are divisible by K."]} -{"name": "mbpp_785_tuple_str_int", "language": "rs", "prompt": "/// Write a function to convert tuple string to integer tuple.\nfn tuple_str_int(test_str: String) -> (isize, isize, isize) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_785_tuple_str_int.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "tuple_str_int", "test": "}\n\nfn main() {\n let candidate = tuple_str_int;\n assert_eq!(candidate(String::from(\"(7, 8, 9)\")), (7, 8, 9));\n assert_eq!(candidate(String::from(\"(1, 2, 3)\")), (1, 2, 3));\n assert_eq!(candidate(String::from(\"(4, 5, 6)\")), (4, 5, 6));\n assert_eq!(candidate(String::from(\"(7, 81, 19)\")), (7, 81, 19));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to convert tuple string to integer tuple.\nfn tuple_str_int(test_str: String) -> (isize, isize, isize) {\n let mut numbers = test_str\n .trim_start_matches('(')\n .trim_end_matches(')')\n .split(',')\n .map(|s| s.trim().parse::())\n .collect::, _>>()\n .unwrap_or_default();\n\n if numbers.len() == 3 {\n (numbers[0], numbers[1], numbers[2])\n } else {\n (0, 0, 0)\n }\n}"} -{"name": "mbpp_776_count_vowels", "language": "rs", "prompt": "/// Write a function to count those characters which have vowels as their neighbors in the given string.\nfn count_vowels(test_str: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_776_count_vowels.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_vowels", "test": "}\n\nfn main() {\n let candidate = count_vowels;\n assert_eq!(candidate(String::from(\"bestinstareels\")), 7);\n assert_eq!(candidate(String::from(\"partofthejourneyistheend\")), 12);\n assert_eq!(candidate(String::from(\"amazonprime\")), 5);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to count those characters which have vowels as their neighbors in the given string.\nfn count_vowels(test_str: String) -> isize {\n let vowels = ['a', 'e', 'i', 'o', 'u'];\n let mut count = 0;\n let chars: Vec = test_str.chars().collect();\n\n for i in 1..chars.len() - 1 {\n if vowels.contains(&chars[i - 1]) && vowels.contains(&chars[i + 1]) {\n count += 1;\n }\n }\n\n count\n}"} -{"name": "mbpp_277_dict_filter", "language": "rs", "prompt": "use std::collections::HashMap;\n\n/// Write a function that takes in a HashMap and integer n and filters the HashMap to only include entries with values greater than or equal to n.\nfn dict_filter(dict: HashMap, n: isize) -> HashMap {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_277_dict_filter.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "dict_filter", "test": "}\n\nfn main() {\n let candidate = dict_filter;\n assert_eq!(candidate(HashMap::from([(String::from(\"Cierra Vega\"), 175), (String::from(\"Alden Cantrell\"), 180), (String::from(\"Kierra Gentry\"), 165), (String::from(\"Pierre Cox\"), 190)]), 170), HashMap::from([(String::from(\"Cierra Vega\"), 175), (String::from(\"Alden Cantrell\"), 180), (String::from(\"Pierre Cox\"), 190)]));\n assert_eq!(candidate(HashMap::from([(String::from(\"Cierra Vega\"), 175), (String::from(\"Alden Cantrell\"), 180), (String::from(\"Kierra Gentry\"), 165), (String::from(\"Pierre Cox\"), 190)]), 180), HashMap::from([(String::from(\"Alden Cantrell\"), 180), (String::from(\"Pierre Cox\"), 190)]));\n assert_eq!(candidate(HashMap::from([(String::from(\"Cierra Vega\"), 175), (String::from(\"Alden Cantrell\"), 180), (String::from(\"Kierra Gentry\"), 165), (String::from(\"Pierre Cox\"), 190)]), 190), HashMap::from([(String::from(\"Pierre Cox\"), 190)]));\n}\n", "is_solved": true, "reflections": [], "solution": "use std::collections::HashMap;\n\n/// Write a function that takes in a HashMap and integer n and filters the HashMap to only include entries with values greater than or equal to n.\nfn dict_filter(dict: HashMap, n: isize) -> HashMap {\n dict.into_iter()\n .filter(|(_, value)| *value >= n)\n .collect()\n}"} -{"name": "mbpp_468_max_product", "language": "rs", "prompt": "/// Write a function to find the maximum product formed by multiplying numbers of an increasing subsequence of that vector.\nfn max_product(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_468_max_product.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_product", "test": "}\n\nfn main() {\n let candidate = max_product;\n assert_eq!(candidate(vec![3, 100, 4, 5, 150, 6]), 3000);\n assert_eq!(candidate(vec![4, 42, 55, 68, 80]), 50265600);\n assert_eq!(candidate(vec![10, 22, 9, 33, 21, 50, 41, 60]), 2460);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the maximum product formed by multiplying numbers of an increasing subsequence of that vector.\nfn max_product(arr: Vec) -> isize {\n if arr.is_empty() {\n return 0;\n }\n\n let n = arr.len();\n let mut dp = vec![0; n];\n dp[0] = arr[0];\n\n for i in 1..n {\n dp[i] = arr[i];\n for j in 0..i {\n if arr[i] > arr[j] {\n dp[i] = dp[i].max(dp[j] * arr[i]);\n }\n }\n }\n\n dp.into_iter().max().unwrap_or(0)\n}"} -{"name": "mbpp_279_is_num_decagonal", "language": "rs", "prompt": "/// Write a function to find the nth decagonal number.\nfn is_num_decagonal(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_279_is_num_decagonal.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_num_decagonal", "test": "}\n\nfn main() {\n let candidate = is_num_decagonal;\n assert_eq!(candidate(3), 27);\n assert_eq!(candidate(7), 175);\n assert_eq!(candidate(10), 370);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the nth decagonal number.\nfn is_num_decagonal(n: isize) -> isize {\n if n <= 0 {\n return 0;\n }\n n * (4 * n - 3)\n}"} -{"name": "mbpp_3_is_not_prime", "language": "rs", "prompt": "/// Write a rsthon function to identify non-prime numbers.\nfn is_not_prime(n: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_3_is_not_prime.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_not_prime", "test": "}\n\nfn main() {\n let candidate = is_not_prime;\n assert_eq!(candidate(2), false);\n assert_eq!(candidate(10), true);\n assert_eq!(candidate(35), true);\n assert_eq!(candidate(37), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to identify non-prime numbers.\nfn is_not_prime(n: isize) -> bool {\n if n <= 1 {\n return true;\n }\n\n for i in 2..((n as f64).sqrt() as isize + 1) {\n if n % i == 0 {\n return true;\n }\n }\n\n false\n}"} -{"name": "mbpp_88_freq_count", "language": "rs", "prompt": "use std::collections::HashMap;\n\n/// Write a function to get the frequency of all the elements in a vector, returned as a HashMap.\nfn freq_count(list1: Vec) -> HashMap {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_88_freq_count.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "freq_count", "test": "}\n\nfn main() {\n let candidate = freq_count;\n assert_eq!(candidate(vec![10, 10, 10, 10, 20, 20, 20, 20, 40, 40, 50, 50, 30]), HashMap::from([(10, 4), (20, 4), (40, 2), (50, 2), (30, 1)]));\n assert_eq!(candidate(vec![1, 2, 3, 4, 3, 2, 4, 1, 3, 1, 4]), HashMap::from([(1, 3), (2, 2), (3, 3), (4, 3)]));\n assert_eq!(candidate(vec![5, 6, 7, 4, 9, 10, 4, 5, 6, 7, 9, 5]), HashMap::from([(10, 1), (5, 3), (6, 2), (7, 2), (4, 2), (9, 2)]));\n}\n", "is_solved": true, "reflections": [], "solution": "use std::collections::HashMap;\n\n/// Write a function to get the frequency of all the elements in a vector, returned as a HashMap.\nfn freq_count(list1: Vec) -> HashMap {\n let mut frequency_map: HashMap = HashMap::new();\n\n for element in list1 {\n let count = frequency_map.entry(element).or_insert(0);\n *count += 1;\n }\n\n frequency_map\n}"} -{"name": "mbpp_259_maximize_elements", "language": "rs", "prompt": "/// Write a function to maximize the given two vectors.\nfn maximize_elements(test_tup1: Vec>, test_tup2: Vec>) -> Vec> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_259_maximize_elements.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "maximize_elements", "test": "}\n\nfn main() {\n let candidate = maximize_elements;\n assert_eq!(candidate(vec![vec![1, 3], vec![4, 5], vec![2, 9], vec![1, 10]], vec![vec![6, 7], vec![3, 9], vec![1, 1], vec![7, 3]]), vec![vec![6, 7], vec![4, 9], vec![2, 9], vec![7, 10]]);\n assert_eq!(candidate(vec![vec![2, 4], vec![5, 6], vec![3, 10], vec![2, 11]], vec![vec![7, 8], vec![4, 10], vec![2, 2], vec![8, 4]]), vec![vec![7, 8], vec![5, 10], vec![3, 10], vec![8, 11]]);\n assert_eq!(candidate(vec![vec![3, 5], vec![6, 7], vec![4, 11], vec![3, 12]], vec![vec![8, 9], vec![5, 11], vec![3, 3], vec![9, 5]]), vec![vec![8, 9], vec![6, 11], vec![4, 11], vec![9, 12]]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to maximize the given two vectors.\nfn maximize_elements(test_tup1: Vec>, test_tup2: Vec>) -> Vec> {\n let mut result: Vec> = Vec::new();\n\n for i in 0..test_tup1.len() {\n let mut row: Vec = Vec::new();\n for j in 0..test_tup1[i].len() {\n row.push(std::cmp::max(test_tup1[i][j], test_tup2[i][j]));\n }\n result.push(row);\n }\n\n result\n}"} -{"name": "mbpp_285_text_match_two_three", "language": "rs", "prompt": "/// Write a function that checks whether a string contains the 'a' character followed by two or three 'b' characters.\nfn text_match_two_three(text: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_285_text_match_two_three.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "text_match_two_three", "test": "}\n\nfn main() {\n let candidate = text_match_two_three;\n assert_eq!(candidate(String::from(\"ac\")), false);\n assert_eq!(candidate(String::from(\"dc\")), false);\n assert_eq!(candidate(String::from(\"abbbba\")), true);\n}\n", "solution": "/// Write a function that checks whether a string contains the 'a' character followed by two or three 'b' characters.\nfn text_match_two_three(text: String) -> bool {\n use regex::Regex;\n let pattern = Regex::new(r\"a(bb|bbb)\").unwrap();\n pattern.is_match(&text)\n}", "is_solved": true, "reflections": ["The implementation is wrong because the `regex` crate is not declared or imported, causing the compiler to throw an error. To fix this issue, the `regex` crate needs to be added to the project's dependencies and imported using `use regex::Regex;` at the beginning of the code.", "The implementation is wrong because the `regex` crate is not declared in the dependencies, causing an unresolved import error. To fix this, the `regex` crate should be added to the project's `Cargo.toml` file under the `[dependencies]` section.", "The implementation is wrong because the `regex` crate is not declared in the dependencies, causing an unresolved import error. To fix this, the `regex` crate should be added to the project's `Cargo.toml` file under the `[dependencies]` section.", "The implementation is wrong because the `regex` crate is not declared in the dependencies, causing an unresolved import error. To fix this, the `regex` crate should be added to the project's `Cargo.toml` file under the `[dependencies]` section."]} -{"name": "mbpp_721_maxAverageOfPath", "language": "rs", "prompt": "/// Given a square matrix of size N*N given as a vector of vectors, where each cell is associated with a specific cost. A path is defined as a specific sequence of cells that starts from the top-left cell move only right or down and ends on bottom right cell. We want to find a path with the maximum average over all existing paths. Average is computed as total cost divided by the number of cells visited in the path.\nfn maxAverageOfPath(cost: Vec>) -> f64 {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_721_maxAverageOfPath.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "maxAverageOfPath", "test": "}\n\nfn main() {\n let candidate = maxAverageOfPath;\n assert_eq!(candidate(vec![vec![1, 2, 3], vec![6, 5, 4], vec![7, 3, 9]]), 5.2);\n assert_eq!(candidate(vec![vec![2, 3, 4], vec![7, 6, 5], vec![8, 4, 10]]), 6.2);\n assert_eq!(candidate(vec![vec![3, 4, 5], vec![8, 7, 6], vec![9, 5, 11]]), 7.2);\n assert_eq!(candidate(vec![vec![1, 2, 3], vec![4, 5, 6], vec![7, 8, 9]]), 5.8);\n}\n", "solution": "/// Given a square matrix of size N*N given as a vector of vectors, where each cell is associated with a specific cost. A path is defined as a specific sequence of cells that starts from the top-left cell move only right or down and ends on bottom right cell. We want to find a path with the maximum average over all existing paths. Average is computed as total cost divided by the number of cells visited in the path.\nfn maxAverageOfPath(cost: Vec>) -> f64 {\n let n = cost.len();\n let mut dp = vec![vec![(0.0, 0); n]; n];\n\n dp[0][0] = (cost[0][0] as f64, 1);\n\n for i in 1..n {\n let (prev_sum, prev_count) = dp[i - 1][0];\n dp[i][0] = (prev_sum + cost[i][0] as f64, prev_count + 1);\n }\n\n for j in 1..n {\n let (prev_sum, prev_count) = dp[0][j - 1];\n dp[0][j] = (prev_sum + cost[0][j] as f64, prev_count + 1);\n }\n\n for i in 1..n {\n for j in 1..n {\n let (sum1, count1) = dp[i - 1][j];\n let (sum2, count2) = dp[i][j - 1];\n\n let avg1 = sum1 / count1 as f64;\n let avg2 = sum2 / count2 as f64;\n\n let total_sum1 = sum1 + cost[i][j] as f64;\n let total_sum2 = sum2 + cost[i][j] as f64;\n\n let new_avg1 = total_sum1 / (count1 + 1) as f64;\n let new_avg2 = total_sum2 / (count2 + 1) as f64;\n\n if new_avg1 > new_avg2 {\n dp[i][j] = (total_sum1, count1 + 1);\n } else {\n dp[i][j] = (total_sum2, count2 + 1);\n }\n }\n }\n\n let (final_sum, final_count) = dp[n - 1][n - 1];\n final_sum / final_count as f64\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it calculates the maximum sum of the path instead of the maximum average. The division by `(2 * n - 1) as f64` at the end is not sufficient to find the maximum average, as it does not account for the varying number of cells visited in different paths. This leads to incorrect results in the failed test cases.", "The implementation is incorrect because it compares the average values of the two possible previous paths at each step, and chooses the one with the higher average. This approach can lead to a suboptimal final path, as it doesn't consider the possibility that a lower average path at an intermediate step might lead to a higher average path overall. Instead, the implementation should compare the total sum of the two possible previous paths and choose the one with the higher sum, as this would maximize the final average.", "The implementation is incorrect because it only considers the path with the highest sum, not the path with the highest average. In the dynamic programming step, it compares the sums of the two possible paths (from the top or from the left) and chooses the one with the higher sum, ignoring the number of cells visited. This leads to an incorrect calculation of the average for the final path.", "The implementation is incorrect because it compares the average values of the two possible paths at each step and chooses the one with the higher average. This approach does not guarantee the maximum average for the entire path, as it may lead to a locally optimal choice but not the globally optimal one. Instead, the implementation should compare the total sum of the paths and the number of cells visited to calculate the maximum average for the entire path."]} -{"name": "mbpp_797_sum_in_range", "language": "rs", "prompt": "/// Write a rsthon function to find the sum of all odd natural numbers within the range l and r.\nfn sum_in_range(l: isize, r: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_797_sum_in_range.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sum_in_range", "test": "}\n\nfn main() {\n let candidate = sum_in_range;\n assert_eq!(candidate(2, 5), 8);\n assert_eq!(candidate(5, 7), 12);\n assert_eq!(candidate(7, 13), 40);\n}\n", "solution": "/// Write a rsthon function to find the sum of all odd natural numbers within the range l and r.\nfn sum_in_range(l: isize, r: isize) -> isize {\n let mut sum = 0;\n let start = if l % 2 == 0 { l + 1 } else { l };\n let end = if r % 2 == 0 { r - 1 } else { r };\n for i in (start..=end).step_by(2) {\n sum += i;\n }\n sum\n}", "is_solved": true, "reflections": ["The implementation of the sum_in_range function is incorrect because it calculates the sum of all odd numbers within the range, but the failed test case indicates that the expected sum is off by one. This is likely due to an error in the range or the condition for identifying odd numbers.", "The implementation of the sum_in_range function is incorrect because it only considers odd numbers with a remainder of 1 when divided by 2. This causes the function to miss odd numbers with a remainder of -1 when divided by 2, such as negative odd numbers. This leads to incorrect results for ranges that include negative odd numbers.", "The implementation of the sum_in_range function is incorrect because it fails to handle the case when the range starts with an even number. In such cases, the function skips the first odd number in the range, resulting in an incorrect sum. This is evident from the failed test case where the range starts with an even number (3, 15) and the output is 63 instead of the expected 64.", "The implementation of the sum_in_range function is incorrect because it calculates the sum of odd numbers within the range inclusively, but it does not include the right boundary (r) when it is an odd number. This causes the function to return a sum that is less than the expected value when the right boundary is an odd number."]} -{"name": "mbpp_4_heap_queue_largest", "language": "rs", "prompt": "/// Write a function to find the n largest integers from a given vector of numbers, returned in descending order.\nfn heap_queue_largest(nums: Vec, n: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_4_heap_queue_largest.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "heap_queue_largest", "test": "}\n\nfn main() {\n let candidate = heap_queue_largest;\n assert_eq!(candidate(vec![25, 35, 22, 85, 14, 65, 75, 22, 58], 3), vec![85, 75, 65]);\n assert_eq!(candidate(vec![25, 35, 22, 85, 14, 65, 75, 22, 58], 2), vec![85, 75]);\n assert_eq!(candidate(vec![25, 35, 22, 85, 14, 65, 75, 22, 58], 5), vec![85, 75, 65, 58, 35]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the n largest integers from a given vector of numbers, returned in descending order.\nfn heap_queue_largest(nums: Vec, n: isize) -> Vec {\n use std::cmp::Reverse;\n use std::collections::BinaryHeap;\n\n let mut heap = BinaryHeap::with_capacity(n as usize);\n let mut result = Vec::with_capacity(n as usize);\n\n for num in nums {\n if heap.len() < n as usize {\n heap.push(Reverse(num));\n } else if let Some(&Reverse(min)) = heap.peek() {\n if num > min {\n heap.pop();\n heap.push(Reverse(num));\n }\n }\n }\n\n while let Some(Reverse(val)) = heap.pop() {\n result.push(val);\n }\n\n result.reverse();\n result\n}"} -{"name": "mbpp_120_max_product_tuple", "language": "rs", "prompt": "/// Write a function to find the maximum absolute product between numbers in pairs of tuples within a given vector.\nfn max_product_tuple(list1: Vec<(isize, isize)>) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_120_max_product_tuple.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_product_tuple", "test": "}\n\nfn main() {\n let candidate = max_product_tuple;\n assert_eq!(candidate(vec![(2, 7), (2, 6), (1, 8), (4, 9)]), 36);\n assert_eq!(candidate(vec![(10, 20), (15, 2), (5, 10)]), 200);\n assert_eq!(candidate(vec![(11, 44), (10, 15), (20, 5), (12, 9)]), 484);\n}\n", "solution": "/// Write a function to find the maximum absolute product between numbers in pairs of tuples within a given vector.\nfn max_product_tuple(list1: Vec<(isize, isize)>) -> isize {\n let mut max_product = 0;\n\n for i in 0..list1.len() {\n for j in i + 1..list1.len() {\n let product = ((list1[i].0 * list1[j].0) + (list1[i].1 * list1[j].1)).abs();\n if product > max_product {\n max_product = product;\n }\n }\n }\n\n max_product\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it calculates the product of the absolute values of the individual elements in the tuples, rather than calculating the product of the tuples first and then taking the absolute value. This leads to incorrect results when there are negative numbers involved, as seen in the failed test cases.", "The implementation is incorrect because it calculates the product of the absolute values of the individual tuple elements' products, rather than calculating the product of the tuples first and then taking the absolute value. This leads to incorrect results when there are negative numbers involved in the tuples.", "The implementation is incorrect because it calculates the sum of products of the corresponding elements in the tuples, rather than the product of the absolute values of the elements in the tuples. This leads to incorrect results when the input contains negative numbers or a mix of positive and negative numbers.", "The implementation is incorrect because it calculates the product using the absolute values of the individual elements in the tuples, rather than calculating the product of the tuples first and then taking the absolute value. This leads to incorrect results when the signs of the numbers in the tuples are different."]} -{"name": "mbpp_230_replace_blank", "language": "rs", "prompt": "/// Write a function that takes in a string and character, replaces blank spaces in the string with the character, and returns the string.\nfn replace_blank(str1: String, char: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_230_replace_blank.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "replace_blank", "test": "}\n\nfn main() {\n let candidate = replace_blank;\n assert_eq!(candidate(String::from(\"hello people\"), String::from(\"@\")), String::from(\"hello@people\"));\n assert_eq!(candidate(String::from(\"python program language\"), String::from(\"$\")), String::from(\"python$program$language\"));\n assert_eq!(candidate(String::from(\"blank space\"), String::from(\"-\")), String::from(\"blank-space\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function that takes in a string and character, replaces blank spaces in the string with the character, and returns the string.\nfn replace_blank(str1: String, char: String) -> String {\n let mut result = String::new();\n for c in str1.chars() {\n if c == ' ' {\n result.push_str(&char);\n } else {\n result.push(c);\n }\n }\n result\n}"} -{"name": "mbpp_600_is_Even", "language": "rs", "prompt": "/// Write a rsthon function to check whether the given number is even or not.\nfn is_Even(n: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_600_is_Even.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_Even", "test": "}\n\nfn main() {\n let candidate = is_Even;\n assert_eq!(candidate(1), false);\n assert_eq!(candidate(2), true);\n assert_eq!(candidate(3), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to check whether the given number is even or not.\nfn is_Even(n: isize) -> bool {\n if n % 2 == 0 {\n return true;\n } else {\n return false;\n }\n}"} -{"name": "mbpp_440_find_adverb_position", "language": "rs", "prompt": "/// Write a function to find the first adverb and their positions in a given sentence.\nfn find_adverb_position(text: String) -> (isize, isize, String) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_440_find_adverb_position.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_adverb_position", "test": "}\n\nfn main() {\n let candidate = find_adverb_position;\n assert_eq!(candidate(String::from(\"clearly!! we can see the sky\")), (0, 7, String::from(\"clearly\")));\n assert_eq!(candidate(String::from(\"seriously!! there are many roses\")), (0, 9, String::from(\"seriously\")));\n assert_eq!(candidate(String::from(\"unfortunately!! sita is going to home\")), (0, 13, String::from(\"unfortunately\")));\n}\n", "solution": "/// Write a function to find the first adverb and their positions in a given sentence.\nfn find_adverb_position(text: String) -> (isize, isize, String) {\n let words: Vec<&str> = text.split_whitespace().collect();\n let mut position = 0;\n\n for (index, word) in words.iter().enumerate() {\n if word.ends_with(\"ly\") || word == &\"never\" || word == &\"always\" {\n return (index as isize, position as isize, word.to_string());\n }\n position += word.len() + 1;\n }\n\n (-1, -1, String::new())\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it only checks for a limited set of adverbs in the `adverbs` array. The failed tests have adverbs \"never\" and \"always\" which are not present in the `adverbs` array, causing the function to return (-1, -1, \"\") instead of the correct positions and adverbs.", "The implementation is incorrect because it checks if the word ends with \"never\" or \"always\" instead of checking if the word is equal to \"never\" or \"always\". This causes the function to return incorrect index values for these adverbs. Additionally, the position value is off by one for these cases.", "The implementation is incorrect because it tries to compare a `&str` with a `str` directly, which is not allowed. The `PartialEq` trait is not implemented for `&str`. To fix this issue, we need to compare `&str` with `&str` by adding a reference to the string literals \"never\" and \"always\".", "The implementation of the find_adverb_position function is incorrect because it fails to properly identify the index of the adverbs \"never\" and \"always\" in the given sentences. The function returns the index as one position higher than the actual index of these adverbs, causing the failed test cases."]} -{"name": "mbpp_773_occurance_substring", "language": "rs", "prompt": "/// Write a function to find the occurrence and position of the substrings within a string. Return None if there is no match.\nfn occurance_substring(text: String, pattern: String) -> Option<(String, isize, isize)> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_773_occurance_substring.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "occurance_substring", "test": "}\n\nfn main() {\n let candidate = occurance_substring;\n assert_eq!(candidate(String::from(\"python programming, python language\"), String::from(\"python\")), Some((String::from(\"python\"), 0, 6)));\n assert_eq!(candidate(String::from(\"python programming,programming language\"), String::from(\"programming\")), Some((String::from(\"programming\"), 7, 18)));\n assert_eq!(candidate(String::from(\"python programming,programming language\"), String::from(\"language\")), Some((String::from(\"language\"), 31, 39)));\n assert_eq!(candidate(String::from(\"c++ programming, c++ language\"), String::from(\"python\")), None);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the occurrence and position of the substrings within a string. Return None if there is no match.\nfn occurance_substring(text: String, pattern: String) -> Option<(String, isize, isize)> {\n if pattern.is_empty() || text.len() < pattern.len() {\n return None;\n }\n\n let mut start_index = 0;\n let mut end_index = 0;\n let mut found = false;\n\n for i in 0..text.len() - pattern.len() + 1 {\n if &text[i..i + pattern.len()] == pattern {\n start_index = i as isize;\n end_index = (i + pattern.len() - 1) as isize;\n found = true;\n break;\n }\n }\n\n if found {\n Some((pattern, start_index, end_index))\n } else {\n None\n }\n}"} -{"name": "mbpp_239_get_total_number_of_sequences", "language": "rs", "prompt": "/// Write a function that takes in positive integers m and n and finds the number of possible sequences of length n, such that each element is a positive integer and is greater than or equal to twice the previous element but less than or equal to m.\nfn get_total_number_of_sequences(m: isize, n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_239_get_total_number_of_sequences.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "get_total_number_of_sequences", "test": "}\n\nfn main() {\n let candidate = get_total_number_of_sequences;\n assert_eq!(candidate(10, 4), 4);\n assert_eq!(candidate(5, 2), 6);\n assert_eq!(candidate(16, 3), 84);\n}\n", "solution": "/// Write a function that takes in positive integers m and n and finds the number of possible sequences of length n, such that each element is a positive integer and is greater than or equal to twice the previous element but less than or equal to m.\nfn get_total_number_of_sequences(m: isize, n: isize) -> isize {\n if m <= 0 || n <= 0 {\n return 0;\n }\n\n let mut dp = vec![vec![0; n as usize + 1]; m as usize + 1];\n\n for i in 1..=m as usize {\n dp[i][1] = 1;\n }\n\n for i in 1..=m as usize {\n for j in 2..=n as usize {\n let mut sum = 0;\n for k in (1..=(i / 2)).rev() {\n if k * 2 <= i {\n sum += dp[k][j - 1];\n }\n }\n dp[i][j] = sum;\n }\n }\n\n let mut result = 0;\n for i in 1..=m as usize {\n result += dp[i][n as usize];\n }\n\n result\n}", "is_solved": true, "reflections": ["The implementation of the get_total_number_of_sequences function is incorrect because it does not properly calculate the number of possible sequences for the given constraints. The dynamic programming approach used in the function fails to account for the condition that each element should be greater than or equal to twice the previous element. This leads to incorrect results for the failed test cases.", "The implementation of the get_total_number_of_sequences function is incorrect because it does not properly handle the cases where the sequence length is greater than 1. The current logic fails to generate the correct number of sequences for these cases, as demonstrated by the failed tests. The issue lies in the nested loops and the calculation of the sum, which does not accurately represent the number of valid sequences.", "The implementation of the get_total_number_of_sequences function is incorrect because it does not properly handle the cases where the sequence length is greater than 2. The current logic fails to generate the correct number of sequences for these cases, as demonstrated by the failed tests. The dynamic programming approach needs to be revised to accurately calculate the number of sequences for all possible input values.", "The implementation of the get_total_number_of_sequences function is incorrect because it does not properly calculate the number of possible sequences for the given constraints. The dynamic programming approach used in the function fails to account for the condition that each element should be greater than or equal to twice the previous element. This leads to incorrect results for some test cases, such as when m = 4 and n = 4, or when m = 6 and n = 3."]} -{"name": "mbpp_412_remove_odd", "language": "rs", "prompt": "/// Write a rsthon function to remove odd numbers from a given vector.\nfn remove_odd(l: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_412_remove_odd.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "remove_odd", "test": "}\n\nfn main() {\n let candidate = remove_odd;\n assert_eq!(candidate(vec![1, 2, 3]), vec![2]);\n assert_eq!(candidate(vec![2, 4, 6]), vec![2, 4, 6]);\n assert_eq!(candidate(vec![10, 20, 3]), vec![10, 20]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to remove odd numbers from a given vector.\nfn remove_odd(l: Vec) -> Vec {\n l.into_iter().filter(|&x| x % 2 == 0).collect()\n}"} -{"name": "mbpp_414_overlapping", "language": "rs", "prompt": "/// Write a rsthon function to check whether any value in a sequence exists in a sequence or not.\nfn overlapping(list1: Vec, list2: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_414_overlapping.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "overlapping", "test": "}\n\nfn main() {\n let candidate = overlapping;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5], vec![6, 7, 8, 9]), false);\n assert_eq!(candidate(vec![1, 2, 3], vec![4, 5, 6]), false);\n assert_eq!(candidate(vec![1, 4, 5], vec![1, 4, 5]), true);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to check whether any value in a sequence exists in a sequence or not.\nfn overlapping(list1: Vec, list2: Vec) -> bool {\n for item in &list1 {\n if list2.contains(item) {\n return true;\n }\n }\n false\n}"} -{"name": "mbpp_160_find_solution", "language": "rs", "prompt": "/// Write a function that returns integers x and y that satisfy ax + by = n as a tuple, or return None if no solution exists.\nfn find_solution(a: isize, b: isize, n: isize) -> Option<(isize, isize)> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_160_find_solution.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_solution", "test": "}\n\nfn main() {\n let candidate = find_solution;\n assert_eq!(candidate(2, 3, 7), Some((2, 1)));\n assert_eq!(candidate(4, 2, 7), None);\n assert_eq!(candidate(1, 13, 17), Some((4, 1)));\n}\n", "solution": "/// Write a function that returns integers x and y that satisfy ax + by = n as a tuple, or return None if no solution exists.\nfn find_solution(a: isize, b: isize, n: isize) -> Option<(isize, isize)> {\n fn gcd(a: isize, b: isize) -> isize {\n if b == 0 {\n a.abs()\n } else {\n gcd(b, a % b)\n }\n }\n\n if a == 0 && b == 0 {\n return None;\n }\n\n if a == 0 {\n if n % b == 0 {\n return Some((0, n / b));\n } else {\n return None;\n }\n }\n\n if b == 0 {\n if n % a == 0 {\n return Some((n / a, 0));\n } else {\n return None;\n }\n }\n\n let g = gcd(a, b);\n\n if n % g != 0 {\n return None;\n }\n\n let a = a / g;\n let b = b / g;\n let n = n / g;\n\n let mut x = 0;\n let mut y = 0;\n\n for i in -n.abs()..=n.abs() {\n if (a * i) % b == n % b {\n x = i;\n y = (n - a * x) / b;\n break;\n }\n }\n\n Some((x, y))\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it only checks for solutions within the range of -n to n for both x and y. This limited range may not include the correct solution or may return an incorrect solution that happens to satisfy the equation within the given range.", "The implementation is incorrect because it searches for a solution within a fixed range (-max_range to max_range) for both x and y, which may not include the correct solution or may include multiple solutions. This leads to incorrect results or missed solutions in some cases, as demonstrated by the failed tests.", "The implementation is incorrect because it uses a fixed range for the x values, which may not cover all possible solutions. Additionally, the function does not handle cases where both a and b are non-zero but have no solution. This leads to incorrect results and failed assertions in the provided test cases.", "The implementation is incorrect because the `gcd` function is defined as a closure using the `let` keyword, but it should be defined as a regular function using the `fn` keyword. The error occurs because the closure is not being called correctly within itself, causing the `gcd` function to not be found in the scope."]} -{"name": "mbpp_559_max_sub_array_sum", "language": "rs", "prompt": "/// Write a function to find the sum of the largest contiguous subvector in the given vector.\nfn max_sub_array_sum(a: Vec, size: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_559_max_sub_array_sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_sub_array_sum", "test": "}\n\nfn main() {\n let candidate = max_sub_array_sum;\n assert_eq!(candidate(vec![-2, -3, 4, -1, -2, 1, 5, -3], 8), 7);\n assert_eq!(candidate(vec![-3, -4, 5, -2, -3, 2, 6, -4], 8), 8);\n assert_eq!(candidate(vec![-4, -5, 6, -3, -4, 3, 7, -5], 8), 10);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the sum of the largest contiguous subvector in the given vector.\nfn max_sub_array_sum(a: Vec, size: isize) -> isize {\n let mut max_so_far = a[0];\n let mut curr_max = a[0];\n\n for i in 1..size as usize {\n curr_max = isize::max(a[i], curr_max + a[i]);\n max_so_far = isize::max(max_so_far, curr_max);\n }\n\n max_so_far\n}"} -{"name": "mbpp_809_check_smaller", "language": "rs", "prompt": "/// Write a function to check if each element of second tuple is smaller than its corresponding element in the first tuple.\nfn check_smaller(test_tup1: (isize, isize, isize), test_tup2: (isize, isize, isize)) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_809_check_smaller.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "check_smaller", "test": "}\n\nfn main() {\n let candidate = check_smaller;\n assert_eq!(candidate((1, 2, 3), (2, 3, 4)), false);\n assert_eq!(candidate((4, 5, 6), (3, 4, 5)), true);\n assert_eq!(candidate((11, 12, 13), (10, 11, 12)), true);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check if each element of second tuple is smaller than its corresponding element in the first tuple.\nfn check_smaller(test_tup1: (isize, isize, isize), test_tup2: (isize, isize, isize)) -> bool {\n if test_tup2.0 < test_tup1.0 && test_tup2.1 < test_tup1.1 && test_tup2.2 < test_tup1.2 {\n return true;\n }\n false\n}"} -{"name": "mbpp_629_Split", "language": "rs", "prompt": "/// Write a rsthon function to find even numbers from a vector of numbers.\nfn Split(list: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_629_Split.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "Split", "test": "}\n\nfn main() {\n let candidate = Split;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5]), vec![2, 4]);\n assert_eq!(candidate(vec![4, 5, 6, 7, 8, 0, 1]), vec![4, 6, 8, 0]);\n assert_eq!(candidate(vec![8, 12, 15, 19]), vec![8, 12]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find even numbers from a vector of numbers.\nfn Split(list: Vec) -> Vec {\n let mut even_numbers = Vec::new();\n\n for number in list {\n if number % 2 == 0 {\n even_numbers.push(number);\n }\n }\n\n even_numbers\n}"} -{"name": "mbpp_723_count_same_pair", "language": "rs", "prompt": "/// The input is defined as two vectors of the same length. Write a function to count indices where the vectors have the same values.\nfn count_same_pair(nums1: Vec, nums2: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_723_count_same_pair.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_same_pair", "test": "}\n\nfn main() {\n let candidate = count_same_pair;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8], vec![2, 2, 3, 1, 2, 6, 7, 9]), 4);\n assert_eq!(candidate(vec![0, 1, 2, -1, -5, 6, 0, -3, -2, 3, 4, 6, 8], vec![2, 1, 2, -1, -5, 6, 4, -3, -2, 3, 4, 6, 8]), 11);\n assert_eq!(candidate(vec![2, 4, -6, -9, 11, -12, 14, -5, 17], vec![2, 1, 2, -1, -5, 6, 4, -3, -2, 3, 4, 6, 8]), 1);\n assert_eq!(candidate(vec![0, 1, 1, 2], vec![0, 1, 2, 2]), 3);\n}\n", "is_solved": true, "reflections": [], "solution": "/// The input is defined as two vectors of the same length. Write a function to count indices where the vectors have the same values.\nfn count_same_pair(nums1: Vec, nums2: Vec) -> isize {\n let mut count = 0;\n for i in 0..nums1.len() {\n if nums1[i] == nums2[i] {\n count += 1;\n }\n }\n count\n}"} -{"name": "mbpp_242_count_charac", "language": "rs", "prompt": "/// Write a function to count the total number of characters in a string.\nfn count_charac(str1: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_242_count_charac.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_charac", "test": "}\n\nfn main() {\n let candidate = count_charac;\n assert_eq!(candidate(String::from(\"python programming\")), 18);\n assert_eq!(candidate(String::from(\"language\")), 8);\n assert_eq!(candidate(String::from(\"words\")), 5);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to count the total number of characters in a string.\nfn count_charac(str1: String) -> isize {\n let count = str1.chars().count() as isize;\n count\n}"} -{"name": "mbpp_616_tuple_modulo", "language": "rs", "prompt": "/// Write a function which takes two tuples of the same length and performs the element wise modulo.\nfn tuple_modulo(test_tup1: (isize, isize, isize, isize), test_tup2: (isize, isize, isize, isize)) -> (isize, isize, isize, isize) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_616_tuple_modulo.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "tuple_modulo", "test": "}\n\nfn main() {\n let candidate = tuple_modulo;\n assert_eq!(candidate((10, 4, 5, 6), (5, 6, 7, 5)), (0, 4, 5, 1));\n assert_eq!(candidate((11, 5, 6, 7), (6, 7, 8, 6)), (5, 5, 6, 1));\n assert_eq!(candidate((12, 6, 7, 8), (7, 8, 9, 7)), (5, 6, 7, 1));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function which takes two tuples of the same length and performs the element wise modulo.\nfn tuple_modulo(test_tup1: (isize, isize, isize, isize), test_tup2: (isize, isize, isize, isize)) -> (isize, isize, isize, isize) {\n let result = (\n test_tup1.0 % test_tup2.0,\n test_tup1.1 % test_tup2.1,\n test_tup1.2 % test_tup2.2,\n test_tup1.3 % test_tup2.3,\n );\n\n result\n}"} -{"name": "mbpp_583_catalan_number", "language": "rs", "prompt": "/// Write a function which returns nth catalan number.\nfn catalan_number(num: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_583_catalan_number.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "catalan_number", "test": "}\n\nfn main() {\n let candidate = catalan_number;\n assert_eq!(candidate(10), 16796);\n assert_eq!(candidate(9), 4862);\n assert_eq!(candidate(7), 429);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function which returns nth catalan number.\nfn catalan_number(num: isize) -> isize {\n if num <= 1 {\n return 1;\n }\n\n let mut result = 0;\n for i in 0..num {\n result += catalan_number(i) * catalan_number(num - i - 1);\n }\n\n result\n}"} -{"name": "mbpp_129_magic_square_test", "language": "rs", "prompt": "/// Write a function to calculate whether the matrix is a magic square.\nfn magic_square_test(my_matrix: Vec>) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_129_magic_square_test.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "magic_square_test", "test": "}\n\nfn main() {\n let candidate = magic_square_test;\n assert_eq!(candidate(vec![vec![7, 12, 1, 14], vec![2, 13, 8, 11], vec![16, 3, 10, 5], vec![9, 6, 15, 4]]), true);\n assert_eq!(candidate(vec![vec![2, 7, 6], vec![9, 5, 1], vec![4, 3, 8]]), true);\n assert_eq!(candidate(vec![vec![2, 7, 6], vec![9, 5, 1], vec![4, 3, 7]]), false);\n}\n", "solution": "/// Write a function to calculate whether the matrix is a magic square.\nfn magic_square_test(my_matrix: Vec>) -> bool {\n let n = my_matrix.len();\n let mut row_sums = vec![0; n];\n let mut col_sums = vec![0; n];\n let mut diag1_sum = 0;\n let mut diag2_sum = 0;\n let mut seen = vec![false; n * n + 1];\n\n for i in 0..n {\n for j in 0..n {\n let value = my_matrix[i][j];\n if value <= 0 || value as usize > n * n || seen[value as usize] {\n return false;\n }\n seen[value as usize] = true;\n row_sums[i] += value;\n col_sums[j] += value;\n if i == j {\n diag1_sum += value;\n }\n if i == n - j - 1 {\n diag2_sum += value;\n }\n }\n }\n\n let magic_sum = row_sums[0];\n if diag1_sum != magic_sum || diag2_sum != magic_sum {\n return false;\n }\n\n for i in 1..n {\n if row_sums[i] != magic_sum || col_sums[i] != magic_sum {\n return false;\n }\n }\n\n true\n}", "is_solved": true, "reflections": ["The current implementation incorrectly identifies a matrix with all equal elements as a magic square. This is because the row sums, column sums, and diagonal sums are all equal, but the matrix does not meet the magic square requirement of having distinct positive integers."]} -{"name": "mbpp_61_count_Substrings", "language": "rs", "prompt": "/// Write a rsthon function to count the number of substrings with the sum of digits equal to their length.\nfn count_Substrings(s: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_61_count_Substrings.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_Substrings", "test": "}\n\nfn main() {\n let candidate = count_Substrings;\n assert_eq!(candidate(String::from(\"112112\")), 6);\n assert_eq!(candidate(String::from(\"111\")), 6);\n assert_eq!(candidate(String::from(\"1101112\")), 12);\n}\n", "solution": "/// Write a rsthon function to count the number of substrings with the sum of digits equal to their length.\nfn count_Substrings(s: String) -> isize {\n let mut count = 0;\n let chars: Vec = s.chars().collect();\n\n for i in 0..chars.len() {\n let mut sum = 0;\n let mut length = 0;\n for j in i..chars.len() {\n if let Some(digit) = chars[j].to_digit(10) {\n sum += digit;\n length += 1;\n }\n if sum == length as u32 {\n count += 1;\n } else if sum > length as u32 {\n break;\n }\n }\n }\n\n count as isize\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it does not properly handle cases where there are multiple substrings with the same sum of digits equal to their length. The current logic overcounts the number of valid substrings in some cases, leading to incorrect results for certain test cases.", "The implementation of the count_Substrings function is incorrect because it stops counting substrings as soon as it finds one with the sum of digits equal to its length. This causes the function to miss other valid substrings that also meet the criteria. The 'break' statements inside the inner loop should be removed to ensure all valid substrings are counted.", "The implementation is incorrect because it stops counting substrings when the sum of digits becomes greater than the length of the substring. This causes the function to miss some valid substrings with the sum of digits equal to their length, leading to incorrect results in the failed test cases.", "The implementation of the count_Substrings function is incorrect because it does not properly handle cases where there are multiple valid substrings with the same starting index. This leads to an incorrect count of substrings with the sum of digits equal to their length, as seen in the failed test cases."]} -{"name": "mbpp_287_square_Sum", "language": "rs", "prompt": "/// Write a rsthon function takes in an integer n and returns the sum of squares of first n even natural numbers.\nfn square_Sum(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_287_square_Sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "square_Sum", "test": "}\n\nfn main() {\n let candidate = square_Sum;\n assert_eq!(candidate(2), 20);\n assert_eq!(candidate(3), 56);\n assert_eq!(candidate(4), 120);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function takes in an integer n and returns the sum of squares of first n even natural numbers.\nfn square_Sum(n: isize) -> isize {\n let mut sum = 0;\n\n for i in 0..(n * 2) {\n if i % 2 == 0 {\n sum += i * i;\n }\n }\n\n sum\n}"} -{"name": "mbpp_93_power", "language": "rs", "prompt": "/// Write a function to calculate the value of 'a' to the power 'b'.\nfn power(a: isize, b: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_93_power.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "power", "test": "}\n\nfn main() {\n let candidate = power;\n assert_eq!(candidate(3, 4), 81);\n assert_eq!(candidate(2, 3), 8);\n assert_eq!(candidate(5, 5), 3125);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to calculate the value of 'a' to the power 'b'.\nfn power(a: isize, b: isize) -> isize {\n let mut result = 1;\n for _ in 0..b {\n result *= a;\n }\n result\n}"} -{"name": "mbpp_607_find_literals", "language": "rs", "prompt": "/// Write a function to search a string for a regex pattern. The function should return the matching subtring, a start index and an end index.\nfn find_literals(text: String, pattern: String) -> (String, isize, isize) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_607_find_literals.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_literals", "test": "}\n\nfn main() {\n let candidate = find_literals;\n assert_eq!(candidate(String::from(\"The quick brown fox jumps over the lazy dog.\"), String::from(\"fox\")), (String::from(\"fox\"), 16, 19));\n assert_eq!(candidate(String::from(\"Its been a very crazy procedure right\"), String::from(\"crazy\")), (String::from(\"crazy\"), 16, 21));\n assert_eq!(candidate(String::from(\"Hardest choices required strongest will\"), String::from(\"will\")), (String::from(\"will\"), 35, 39));\n}\n", "solution": "/// Write a function to search a string for a regex pattern. The function should return the matching subtring, a start index and an end index.\nfn find_literals(text: String, pattern: String) -> (String, isize, isize) {\n use regex::Regex;\n\n let re = match Regex::new(&pattern) {\n Ok(re) => re,\n Err(_) => return (String::new(), -1, -1),\n };\n\n if let Some(mat) = re.find(&text) {\n let start = mat.start() as isize;\n let end = mat.end() as isize;\n let matched = mat.as_str().to_string();\n return (matched, start, end);\n }\n\n (String::new(), -1, -1)\n}", "is_solved": true, "reflections": ["The implementation is incorrect because the `regex` crate is not declared or imported properly, causing an unresolved import error. To fix this issue, the `regex` crate should be added to the `Cargo.toml` file and imported at the beginning of the code file.", "The implementation is incorrect because the `regex` crate is not declared or imported in the current scope, causing an unresolved import error. To fix this issue, the `regex` crate should be added to the `Cargo.toml` file and imported at the beginning of the code file.", "The implementation is incorrect because the `regex` crate is not declared or imported properly, causing an unresolved import error. To fix this, the `regex` crate needs to be added to the `Cargo.toml` file and imported correctly at the beginning of the code.", "The implementation is incorrect because the `regex` crate is not declared or imported properly, causing an unresolved import error. To fix this, the `regex` crate needs to be added to the `Cargo.toml` file and imported correctly at the beginning of the code."]} -{"name": "mbpp_94_index_minimum", "language": "rs", "prompt": "/// Given a vector of tuples, write a function that returns the first value of the tuple with the smallest second value.\nfn index_minimum(test_list: Vec<(String, isize)>) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_94_index_minimum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "index_minimum", "test": "}\n\nfn main() {\n let candidate = index_minimum;\n assert_eq!(candidate(vec![(String::from(\"Rash\"), 143), (String::from(\"Manjeet\"), 200), (String::from(\"Varsha\"), 100)]), String::from(\"Varsha\"));\n assert_eq!(candidate(vec![(String::from(\"Yash\"), 185), (String::from(\"Dawood\"), 125), (String::from(\"Sanya\"), 175)]), String::from(\"Dawood\"));\n assert_eq!(candidate(vec![(String::from(\"Sai\"), 345), (String::from(\"Salman\"), 145), (String::from(\"Ayesha\"), 96)]), String::from(\"Ayesha\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Given a vector of tuples, write a function that returns the first value of the tuple with the smallest second value.\nfn index_minimum(test_list: Vec<(String, isize)>) -> String {\n let mut min_index = 0;\n let mut min_value = test_list[0].1;\n\n for (index, tuple) in test_list.iter().enumerate() {\n if tuple.1 < min_value {\n min_value = tuple.1;\n min_index = index;\n }\n }\n\n test_list[min_index].0.clone()\n}"} -{"name": "mbpp_138_is_Sum_Of_Powers_Of_Two", "language": "rs", "prompt": "/// Write a rsthon function to check whether the given number can be represented as sum of non-zero powers of 2 or not.\nfn is_Sum_Of_Powers_Of_Two(n: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_138_is_Sum_Of_Powers_Of_Two.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_Sum_Of_Powers_Of_Two", "test": "}\n\nfn main() {\n let candidate = is_Sum_Of_Powers_Of_Two;\n assert_eq!(candidate(10), true);\n assert_eq!(candidate(7), false);\n assert_eq!(candidate(14), true);\n}\n", "solution": "/// Write a rsthon function to check whether the given number can be represented as sum of non-zero powers of 2 or not.\nfn is_Sum_Of_Powers_Of_Two(n: isize) -> bool {\n if n <= 0 {\n return false;\n }\n\n let mut num = n;\n let mut count = 0;\n\n while num > 0 {\n if num % 2 == 1 {\n count += 1;\n }\n num >>= 1;\n }\n\n count >= 2\n}", "is_solved": true, "reflections": ["The implementation is incorrect because the function argument `n` is immutable, and an attempt is made to modify it with the bitwise right shift assignment operation `n >>= 1;`. To fix this issue, the argument should be made mutable by declaring it as `mut n`.", "The implementation is incorrect because it checks if the given number is a power of 2 instead of checking if it can be represented as a sum of non-zero powers of 2. The function returns true only when there is a single 1 in the binary representation of the number, which is not the correct condition for the problem statement.", "The implementation of the is_Sum_Of_Powers_Of_Two function is incorrect because it checks if the number is divisible by 2 instead of checking if the number can be represented as a sum of non-zero powers of 2. This leads to incorrect results for some test cases, such as returning true for 9 and false for 3.", "The implementation is incorrect because it checks if the count of set bits (1s) in the binary representation of the given number is greater than 1. This condition does not guarantee that the number can be represented as the sum of non-zero powers of 2. Instead, it only checks if there are more than one 1s in the binary representation."]} -{"name": "mbpp_594_diff_even_odd", "language": "rs", "prompt": "/// Write a function to find the difference of the first even and first odd number of a given vector.\nfn diff_even_odd(list1: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_594_diff_even_odd.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "diff_even_odd", "test": "}\n\nfn main() {\n let candidate = diff_even_odd;\n assert_eq!(candidate(vec![1, 3, 5, 7, 4, 1, 6, 8]), 3);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 10]), 1);\n assert_eq!(candidate(vec![1, 5, 7, 9, 10]), 9);\n}\n", "solution": "/// Write a function to find the difference of the first even and first odd number of a given vector.\nfn diff_even_odd(list1: Vec) -> isize {\n let mut even: Option = None;\n let mut odd: Option = None;\n\n for num in &list1 {\n if even.is_none() && num % 2 == 0 {\n even = Some(*num);\n } else if odd.is_none() && num % 2 != 0 {\n odd = Some(*num);\n }\n\n if even.is_some() && odd.is_some() {\n break;\n }\n }\n\n match (even, odd) {\n (Some(e), Some(o)) => {\n if list1.iter().position(|&x| x == e) < list1.iter().position(|&x| x == o) {\n e - o\n } else {\n o - e\n }\n }\n _ => 0,\n }\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it always finds the first even number before the first odd number, regardless of their order in the input vector. This causes the function to return the wrong result when the first odd number appears before the first even number, as seen in the failed test case.", "The implementation is wrong because it tries to borrow the `list1` vector after it has been moved due to the implicit call to `.into_iter()` in the for loop. Since `Vec` does not implement the `Copy` trait, the ownership of `list1` is moved and it cannot be borrowed again later in the code. To fix this issue, consider iterating over a slice of the `Vec`'s content to avoid moving into the for loop by using `&list1` instead of `list1`."]} -{"name": "mbpp_274_even_binomial_Coeff_Sum", "language": "rs", "prompt": "/// Write a rsthon function that takes in a positive integer n and finds the sum of even index binomial coefficients.\nfn even_binomial_Coeff_Sum(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_274_even_binomial_Coeff_Sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "even_binomial_Coeff_Sum", "test": "}\n\nfn main() {\n let candidate = even_binomial_Coeff_Sum;\n assert_eq!(candidate(4), 8);\n assert_eq!(candidate(6), 32);\n assert_eq!(candidate(2), 2);\n}\n", "solution": "/// Write a rsthon function that takes in a positive integer n and finds the sum of even index binomial coefficients.\nfn even_binomial_Coeff_Sum(n: isize) -> isize {\n let mut sum = 0;\n let mut coeff = 1;\n\n for i in (0..=n).step_by(2) {\n sum += coeff;\n coeff = coeff * (n - i) * (n - i - 1) / ((i + 1) * (i + 2));\n }\n\n sum\n}", "is_solved": true, "reflections": ["The implementation of the even_binomial_Coeff_Sum function is incorrect because the calculation of the binomial coefficient is not properly updated in the loop. The formula used for updating the coefficient is incorrect, leading to wrong sums being calculated for the even index binomial coefficients. This is evident from the failed test cases where the output does not match the expected values.", "The implementation of the even_binomial_Coeff_Sum function is incorrect because it calculates the sum of all binomial coefficients, not just the ones with even indices. The error lies in the calculation of the coefficient, which does not properly account for even indices only. As a result, the function returns the sum of all binomial coefficients instead of the desired sum of even index binomial coefficients, causing the failed test cases.", "The implementation of the even_binomial_Coeff_Sum function is incorrect because the calculation of the binomial coefficient is not properly updated in the loop. The formula used for updating the coefficient is incorrect, leading to wrong sums being calculated for the even index binomial coefficients. This is evident from the failed test cases where the output does not match the expected values.", "The implementation of the even_binomial_Coeff_Sum function is incorrect because it calculates the sum of even index binomial coefficients using an incorrect formula. The coeff variable is updated incorrectly, causing the sum to be higher than expected, which leads to the failed test cases."]} -{"name": "mbpp_126_sum", "language": "rs", "prompt": "/// Write a rsthon function to find the sum of common divisors of two given numbers.\nfn sum(a: isize, b: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_126_sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sum", "test": "}\n\nfn main() {\n let candidate = sum;\n assert_eq!(candidate(10, 15), 6);\n assert_eq!(candidate(100, 150), 93);\n assert_eq!(candidate(4, 6), 3);\n}\n", "solution": "/// Write a rsthon function to find the sum of common divisors of two given numbers.\nfn sum(a: isize, b: isize) -> isize {\n let mut sum = 0;\n\n for i in 1..=(a.min(b)) {\n if a % i == 0 && b % i == 0 {\n sum += i;\n }\n }\n\n sum\n}", "is_solved": true, "reflections": ["The implementation of the sum function is incorrect because it calculates the sum of common divisors of two given numbers, but the failed test cases show that the function is not providing the expected output for certain inputs. The logic for finding common divisors and summing them up might be flawed, leading to incorrect results.", "The implementation is incorrect because it checks if the sum of common divisors is equal to either of the input numbers (a or b) and then sets the sum to the minimum of the two numbers. This condition is unnecessary and leads to incorrect results for some test cases, such as (6, 9) and (12, 18).", "The implementation of the sum function is incorrect because it calculates the sum of common divisors of two given numbers, but the failed tests indicate that the function is not returning the correct sum for certain input pairs. The logic for finding common divisors and adding them to the sum seems to be flawed, leading to incorrect results.", "The implementation of the sum function is incorrect because it checks if the sum of common divisors is equal to either of the input numbers (a or b) and then sets the sum to the minimum of the two input numbers. This condition is unnecessary and leads to incorrect results for some test cases, such as (6, 9) and (12, 18)."]} -{"name": "mbpp_769_Diff", "language": "rs", "prompt": "/// Write a rsthon function to get the difference between two vectors.\nfn Diff(li1: Vec, li2: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_769_Diff.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "Diff", "test": "}\n\nfn main() {\n let candidate = Diff;\n assert_eq!(candidate(vec![10, 15, 20, 25, 30, 35, 40], vec![25, 40, 35]), vec![10, 20, 30, 15]);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5], vec![6, 7, 1]), vec![2, 3, 4, 5, 6, 7]);\n assert_eq!(candidate(vec![1, 2, 3], vec![6, 7, 1]), vec![2, 3, 6, 7]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to get the difference between two vectors.\nfn Diff(li1: Vec, li2: Vec) -> Vec {\n let mut result: Vec = Vec::new();\n\n for i in 0..li1.len() {\n result.push(li1[i] - li2[i]);\n }\n\n result\n}"} -{"name": "mbpp_796_return_sum", "language": "rs", "prompt": "use std::collections::HashMap;\n\n/// Write function to find the sum of all items in the given HashMap.\nfn return_sum(dict: HashMap) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_796_return_sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "return_sum", "test": "}\n\nfn main() {\n let candidate = return_sum;\n assert_eq!(candidate(HashMap::from([(String::from(\"a\"), 100), (String::from(\"b\"), 200), (String::from(\"c\"), 300)])), 600);\n assert_eq!(candidate(HashMap::from([(String::from(\"a\"), 25), (String::from(\"b\"), 18), (String::from(\"c\"), 45)])), 88);\n assert_eq!(candidate(HashMap::from([(String::from(\"a\"), 36), (String::from(\"b\"), 39), (String::from(\"c\"), 49)])), 124);\n}\n", "is_solved": true, "reflections": [], "solution": "use std::collections::HashMap;\n\n/// Write function to find the sum of all items in the given HashMap.\nfn return_sum(dict: HashMap) -> isize {\n let mut sum = 0;\n for value in dict.values() {\n sum += value;\n }\n sum\n}"} -{"name": "mbpp_574_surfacearea_cylinder", "language": "rs", "prompt": "/// Write a function to find the surface area of a cylinder.\nfn surfacearea_cylinder(r: isize, h: isize) -> f64 {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_574_surfacearea_cylinder.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "surfacearea_cylinder", "test": "}\n\nfn main() {\n let candidate = surfacearea_cylinder;\n assert_eq!(candidate(10, 5), 942.45);\n assert_eq!(candidate(4, 5), 226.18800000000002);\n assert_eq!(candidate(4, 10), 351.848);\n}\n", "solution": "/// Write a function to find the surface area of a cylinder.\nfn surfacearea_cylinder(r: isize, h: isize) -> f64 {\n const PI: f64 = std::f64::consts::PI;\n let lateral_area = 2.0 * PI * (r as f64) * (h as f64);\n lateral_area\n}", "is_solved": true, "reflections": ["The implementation of the surfacearea_cylinder function is incorrect because it calculates the surface area as 2 * base_area + lateral_area, while the correct formula should be base_area + lateral_area. This results in an overestimation of the surface area, causing the failed test cases.", "The implementation of the surfacearea_cylinder function is incorrect because it only calculates the base area and the lateral area, but does not account for the top area of the cylinder. The surface area of a cylinder should include both the top and bottom base areas, as well as the lateral area. This is why the test cases are failing, as the calculated surface area is less than the expected values.", "The implementation of the surfacearea_cylinder function is incorrect because it calculates the surface area by adding the base area, top area, and lateral area. However, the expected results in the failed tests indicate that the surface area should only include the lateral area (2 * PI * r * h) and not the base and top areas. This leads to an overestimation of the surface area in the current implementation."]} -{"name": "mbpp_783_rgb_to_hsv", "language": "rs", "prompt": "/// Write a function to convert rgb color to hsv color. https://www.geeksforgeeks.org/program-change-rgb-color-model-hsv-color-model/\nfn rgb_to_hsv(r: isize, g: isize, b: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_783_rgb_to_hsv.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "rgb_to_hsv", "test": "}\n\nfn main() {\n let candidate = rgb_to_hsv;\n assert_eq!(candidate(255, 255, 255), vec![0.0, 0.0, 100.0]);\n assert_eq!(candidate(0, 215, 0), vec![120.0, 100.0, 84.31372549019608]);\n assert_eq!(candidate(10, 215, 110), vec![149.26829268292684, 95.34883720930233, 84.31372549019608]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to convert rgb color to hsv color. https://www.geeksforgeeks.org/program-change-rgb-color-model-hsv-color-model/\nfn rgb_to_hsv(r: isize, g: isize, b: isize) -> Vec {\n let r = r as f64 / 255.0;\n let g = g as f64 / 255.0;\n let b = b as f64 / 255.0;\n\n let max = r.max(g).max(b);\n let min = r.min(g).min(b);\n let diff = max - min;\n\n let h = if max == min {\n 0.0\n } else if max == r {\n 60.0 * (((g - b) / diff) % 6.0)\n } else if max == g {\n 60.0 * (((b - r) / diff) + 2.0)\n } else {\n 60.0 * (((r - g) / diff) + 4.0)\n };\n\n let s = if max == 0.0 {\n 0.0\n } else {\n diff / max\n };\n\n let v = max;\n\n vec![h, s, v]\n}"} -{"name": "mbpp_70_get_equal", "language": "rs", "prompt": "/// Write a function to find whether all the given vectors have equal length or not.\nfn get_equal(Input: Vec>) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_70_get_equal.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "get_equal", "test": "}\n\nfn main() {\n let candidate = get_equal;\n assert_eq!(candidate(vec![vec![11, 22, 33], vec![44, 55, 66]]), true);\n assert_eq!(candidate(vec![vec![1, 2, 3], vec![4, 5, 6, 7]]), false);\n assert_eq!(candidate(vec![vec![1, 2], vec![3, 4]]), true);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find whether all the given vectors have equal length or not.\nfn get_equal(Input: Vec>) -> bool {\n let length = Input[0].len();\n\n for vec in Input.iter() {\n if vec.len() != length {\n return false;\n }\n }\n\n true\n}"} -{"name": "mbpp_267_square_Sum", "language": "rs", "prompt": "/// Write a rsthon function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.\nfn square_Sum(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_267_square_Sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "square_Sum", "test": "}\n\nfn main() {\n let candidate = square_Sum;\n assert_eq!(candidate(2), 10);\n assert_eq!(candidate(3), 35);\n assert_eq!(candidate(4), 84);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.\nfn square_Sum(n: isize) -> isize {\n let mut sum = 0;\n let mut count = 0;\n let mut current = 1;\n\n while count < n {\n sum += current * current;\n count += 1;\n current += 2;\n }\n\n sum\n}"} -{"name": "mbpp_171_perimeter_pentagon", "language": "rs", "prompt": "/// Write a function to find the perimeter of a regular pentagon from the length of its sides.\nfn perimeter_pentagon(a: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_171_perimeter_pentagon.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "perimeter_pentagon", "test": "}\n\nfn main() {\n let candidate = perimeter_pentagon;\n assert_eq!(candidate(5), 25);\n assert_eq!(candidate(10), 50);\n assert_eq!(candidate(15), 75);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the perimeter of a regular pentagon from the length of its sides.\nfn perimeter_pentagon(a: isize) -> isize {\n a * 5\n}"} -{"name": "mbpp_164_are_equivalent", "language": "rs", "prompt": "/// Write a function to determine if the sum of the divisors of two integers are the same.\nfn are_equivalent(num1: isize, num2: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_164_are_equivalent.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "are_equivalent", "test": "}\n\nfn main() {\n let candidate = are_equivalent;\n assert_eq!(candidate(36, 57), false);\n assert_eq!(candidate(2, 4), false);\n assert_eq!(candidate(23, 47), true);\n}\n", "solution": "/// Write a function to determine if the sum of the divisors of two integers are the same.\nfn are_equivalent(num1: isize, num2: isize) -> bool {\n fn sum_of_divisors(num: isize) -> isize {\n let mut sum = 0;\n for i in 1..=((num as f64).sqrt() as isize) {\n if num % i == 0 {\n sum += i;\n if i != num / i {\n sum += num / i;\n }\n }\n }\n sum\n }\n\n sum_of_divisors(num1) == sum_of_divisors(num2)\n}", "is_solved": true, "reflections": ["The implementation of the `are_equivalent` function is incorrect because it only calculates the sum of divisors up to half of the given number. This causes the function to miss some divisors, leading to incorrect results for certain test cases, such as (15, 21) and (6, 28).", "The implementation of the `are_equivalent` function is incorrect because the `sum_of_divisors` function does not properly calculate the sum of divisors for the given numbers. Specifically, it fails to include the number itself as a divisor when it is not a perfect square, leading to incorrect results in the comparison of the sums.", "The implementation of the `are_equivalent` function is incorrect because it calculates the sum of divisors including the number itself, which is not the intended behavior. This causes the function to return false for cases where the sum of proper divisors (excluding the number itself) should be equal, leading to failed test cases like (15, 21) and (6, 28).", "The implementation of the `are_equivalent` function is incorrect because the `sum_of_divisors` function does not properly calculate the sum of divisors for the given numbers. Specifically, it fails to include the number itself as a divisor when it is not a perfect square, leading to incorrect results in some cases."]} -{"name": "mbpp_803_is_perfect_square", "language": "rs", "prompt": "/// Write a function to check whether the given number is a perfect square or not. https://www.geeksforgeeks.org/check-if-given-number-is-perfect-square-in-cpp/\nfn is_perfect_square(n: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_803_is_perfect_square.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_perfect_square", "test": "}\n\nfn main() {\n let candidate = is_perfect_square;\n assert_eq!(candidate(10), false);\n assert_eq!(candidate(36), true);\n assert_eq!(candidate(14), false);\n assert_eq!(candidate(196), true);\n assert_eq!(candidate(125), false);\n assert_eq!(candidate(15625), true);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check whether the given number is a perfect square or not. https://www.geeksforgeeks.org/check-if-given-number-is-perfect-square-in-cpp/\nfn is_perfect_square(n: isize) -> bool {\n if n < 0 {\n return false;\n }\n\n let mut i = 1;\n while i * i <= n {\n if i * i == n {\n return true;\n }\n i += 1;\n }\n\n false\n}"} -{"name": "mbpp_305_start_withp", "language": "rs", "prompt": "/// Write a function to return two words from a vector of words starting with letter 'p'.\nfn start_withp(words: Vec) -> (String, String) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_305_start_withp.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "start_withp", "test": "}\n\nfn main() {\n let candidate = start_withp;\n assert_eq!(candidate(vec![String::from(\"Python PHP\"), String::from(\"Java JavaScript\"), String::from(\"c c++\")]), (String::from(\"Python\"), String::from(\"PHP\")));\n assert_eq!(candidate(vec![String::from(\"Python Programming\"), String::from(\"Java Programming\")]), (String::from(\"Python\"), String::from(\"Programming\")));\n assert_eq!(candidate(vec![String::from(\"Pqrst Pqr\"), String::from(\"qrstuv\")]), (String::from(\"Pqrst\"), String::from(\"Pqr\")));\n}\n", "solution": "/// Write a function to return two words from a vector of words starting with letter 'p'.\nfn start_withp(words: Vec) -> (String, String) {\n let mut p_words = words\n .into_iter()\n .filter(|word| word.to_lowercase().starts_with('p'))\n .take(2)\n .collect::>();\n\n let first_word = p_words.get(0).cloned().unwrap_or_else(|| String::from(\"\"));\n let second_word = p_words.get(1).cloned().unwrap_or_else(|| String::from(\"\"));\n\n (first_word, second_word)\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it filters words starting with the letter 'p' without considering the case sensitivity. As a result, it returns words starting with an uppercase 'P' as well, causing the first failed test. Additionally, the function does not return the first two words starting with 'p' in the order they appear in the input vector, leading to the second failed test.", "The implementation is incorrect because it does not properly handle cases where the words in the input vector are not in lowercase. The function uses `to_lowercase()` only on the word being checked, but not on the character 'p', causing the filter to miss words starting with an uppercase 'P'. This leads to incorrect results in the failed test cases.", "The implementation is incorrect because it does not properly handle cases where the words in the input vector are not in lowercase. The function uses `to_lowercase()` only when checking if the word starts with 'p', but it does not convert the words in the output tuple to lowercase. This causes the function to return incorrect results when the input words have uppercase letters, as seen in the failed tests.", "The implementation is incorrect because it converts the words to lowercase before checking if they start with the letter 'p'. This causes words starting with an uppercase 'P' to be missed. Additionally, the function returns the words in lowercase, which may not match the expected output in the tests."]} -{"name": "mbpp_617_min_Jumps", "language": "rs", "prompt": "/// Write a function to check for the number of jumps required of given length to reach a point of form (d, 0) from origin in a 2d plane.\nfn min_Jumps(steps: (isize, isize), d: isize) -> f64 {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_617_min_Jumps.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "min_Jumps", "test": "}\n\nfn main() {\n let candidate = min_Jumps;\n assert_eq!(candidate((3, 4), 11), 3.5);\n assert_eq!(candidate((3, 4), 0), 0.0);\n assert_eq!(candidate((11, 14), 11), 1.0);\n}\n", "solution": "/// Write a function to check for the number of jumps required of given length to reach a point of form (d, 0) from origin in a 2d plane.\nfn min_Jumps(steps: (isize, isize), d: isize) -> f64 {\n let (x, y) = steps;\n\n if x == y {\n if d % x == 0 {\n return (d / x) as f64;\n } else {\n return f64::INFINITY;\n }\n }\n\n let mut min_jumps = f64::INFINITY;\n\n for i in 0..=d / x {\n let x_steps = i;\n let y_steps = (d - x * x_steps) as f64 / y as f64;\n\n if (x * x_steps + (y as f64 * y_steps).round() as isize) == d {\n let total_steps = x_steps as f64 + y_steps;\n if total_steps < min_jumps {\n min_jumps = total_steps;\n }\n }\n }\n\n min_jumps\n}", "is_solved": true, "reflections": ["The implementation is wrong because it does not handle cases where the step lengths are equal or when the second step length is greater than the first step length. This leads to division by zero or negative total steps, causing incorrect results and failed assertions.", "The implementation is incorrect because it does not properly handle cases where the steps have different values (x != y). The current approach calculates the total steps by dividing the distance by the difference between x and y, which leads to incorrect results and negative values in some cases. The logic needs to be revised to account for different step lengths and ensure the correct number of jumps is calculated.", "The implementation is incorrect because there is a type mismatch between `total_steps` and `min_jumps`. `total_steps` is of type `isize`, while `min_jumps` is of type `f64`. This causes a compilation error when comparing the two values in the if statement.", "The implementation is incorrect because it assumes that the number of jumps can only be integers, while the failed tests show that fractional jumps are possible. Additionally, the loop iterates over the wrong range, and the condition for checking if the current combination of steps reaches the target distance is flawed."]} -{"name": "mbpp_117_list_to_float", "language": "rs", "prompt": "/// Write a function to convert all possible convertible elements in a vector of vectors to floats.\nfn list_to_float(test_list: Vec<(String, String)>) -> Vec<(f64, f64)> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_117_list_to_float.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "list_to_float", "test": "}\n\nfn main() {\n let candidate = list_to_float;\n assert_eq!(candidate(vec![(String::from(\"3\"), String::from(\"4\")), (String::from(\"1\"), String::from(\"26.45\")), (String::from(\"7.32\"), String::from(\"8\")), (String::from(\"4\"), String::from(\"8\"))]), vec![(3.0, 4.0), (1.0, 26.45), (7.32, 8.0), (4.0, 8.0)]);\n assert_eq!(candidate(vec![(String::from(\"4\"), String::from(\"4\")), (String::from(\"2\"), String::from(\"27\")), (String::from(\"4.12\"), String::from(\"9\")), (String::from(\"7\"), String::from(\"11\"))]), vec![(4.0, 4.0), (2.0, 27.0), (4.12, 9.0), (7.0, 11.0)]);\n assert_eq!(candidate(vec![(String::from(\"6\"), String::from(\"78\")), (String::from(\"5\"), String::from(\"26.45\")), (String::from(\"1.33\"), String::from(\"4\")), (String::from(\"82\"), String::from(\"13\"))]), vec![(6.0, 78.0), (5.0, 26.45), (1.33, 4.0), (82.0, 13.0)]);\n}\n", "solution": "/// Write a function to convert all possible convertible elements in a vector of vectors to floats.\nfn list_to_float(test_list: Vec<(String, String)>) -> Vec<(f64, f64)> {\nlet mut float_list: Vec<(f64, f64)> = Vec::new();\n\n for (a, b) in test_list {\n if let (Ok(a_float), Ok(b_float)) = (a.parse::(), b.parse::()) {\n float_list.push((a_float, b_float));\n }\n }\n\n float_list\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it only adds a tuple to the float_list if both elements can be successfully parsed as f64. If one of the elements cannot be parsed, the tuple is skipped entirely. The expected behavior is to add the tuple with the convertible element and a default value (0.0) for the non-convertible element.", "The implementation is incorrect because it converts all elements in the input vector to floats, even if they are not convertible. This results in non-convertible elements being replaced with 0.0, and the output vector still contains these tuples. The failed test case expected the non-convertible tuple to be removed from the output, but the implementation did not do that.", "The implementation is incorrect because it only adds a tuple to the float_list if both elements can be successfully parsed as floats. If one of the elements cannot be parsed, the tuple is skipped entirely. This causes the test with (\"3.5\", \"not_a_float\") to fail, as it expects the tuple (3.5, 0.0) to be included in the output.", "The implementation is wrong because it converts non-convertible elements to 0.0 instead of skipping them. This causes the output to include tuples with 0.0 values, which is not the expected behavior as per the failed test case."]} -{"name": "mbpp_67_bell_number", "language": "rs", "prompt": "/// Write a function to find the number of ways to partition a set of Bell numbers.\nfn bell_number(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_67_bell_number.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "bell_number", "test": "}\n\nfn main() {\n let candidate = bell_number;\n assert_eq!(candidate(2), 2);\n assert_eq!(candidate(10), 115975);\n assert_eq!(candidate(56), 6775685320645824322581483068371419745979053216268760300);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the number of ways to partition a set of Bell numbers.\nfn bell_number(n: isize) -> isize {\n if n < 0 {\n panic!(\"Invalid input: n must be non-negative\");\n }\n\n let mut bell_matrix = vec![vec![0; (n + 1) as usize]; (n + 1) as usize];\n\n // Base case: B(0) = 1\n bell_matrix[0][0] = 1;\n\n for i in 1..=(n as usize) {\n // Explicitly fill the first element of the row\n bell_matrix[i][0] = bell_matrix[i - 1][i - 1];\n\n // Fill the remaining elements of the row\n for j in 1..=i {\n bell_matrix[i][j] = bell_matrix[i - 1][j - 1] + bell_matrix[i][j - 1];\n }\n }\n\n bell_matrix[n as usize][0]\n}"} -{"name": "mbpp_404_minimum", "language": "rs", "prompt": "/// Write a rsthon function to find the minimum of two numbers.\nfn minimum(a: isize, b: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_404_minimum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "minimum", "test": "}\n\nfn main() {\n let candidate = minimum;\n assert_eq!(candidate(1, 2), 1);\n assert_eq!(candidate(-5, -4), -5);\n assert_eq!(candidate(0, 0), 0);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the minimum of two numbers.\nfn minimum(a: isize, b: isize) -> isize {\n if a < b {\n a\n } else {\n b\n }\n}"} -{"name": "mbpp_14_find_Volume", "language": "rs", "prompt": "/// Write a rsthon function to find the volume of a triangular prism.\nfn find_Volume(l: isize, b: isize, h: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_14_find_Volume.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_Volume", "test": "}\n\nfn main() {\n let candidate = find_Volume;\n assert_eq!(candidate(10, 8, 6), 240);\n assert_eq!(candidate(3, 2, 2), 6);\n assert_eq!(candidate(1, 2, 1), 1);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the volume of a triangular prism.\nfn find_Volume(l: isize, b: isize, h: isize) -> isize {\n let volume = l * b * h / 2;\n volume\n}"} -{"name": "mbpp_8_square_nums", "language": "rs", "prompt": "/// Write a function to find squares of individual elements in a vector.\nfn square_nums(nums: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_8_square_nums.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "square_nums", "test": "}\n\nfn main() {\n let candidate = square_nums;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 10]), vec![1, 4, 9, 16, 25, 36, 49, 64, 81, 100]);\n assert_eq!(candidate(vec![10, 20, 30]), vec![100, 400, 900]);\n assert_eq!(candidate(vec![12, 15]), vec![144, 225]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find squares of individual elements in a vector.\nfn square_nums(nums: Vec) -> Vec {\n nums.into_iter().map(|num| num * num).collect()\n}"} -{"name": "mbpp_244_next_Perfect_Square", "language": "rs", "prompt": "/// Write a rsthon function to find the next perfect square greater than a given number.\nfn next_Perfect_Square(N: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_244_next_Perfect_Square.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "next_Perfect_Square", "test": "}\n\nfn main() {\n let candidate = next_Perfect_Square;\n assert_eq!(candidate(35), 36);\n assert_eq!(candidate(6), 9);\n assert_eq!(candidate(9), 16);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the next perfect square greater than a given number.\nfn next_Perfect_Square(N: isize) -> isize {\n let mut next_square = N + 1;\n\n while !is_perfect_square(next_square) {\n next_square += 1;\n }\n\n next_square\n}\n\nfn is_perfect_square(num: isize) -> bool {\n let root = (num as f64).sqrt() as isize;\n root * root == num\n}"} -{"name": "mbpp_292_find", "language": "rs", "prompt": "/// Write a rsthon function to find quotient of two numbers (rounded down to the nearest integer).\nfn find(n: isize, m: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_292_find.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find", "test": "}\n\nfn main() {\n let candidate = find;\n assert_eq!(candidate(10, 3), 3);\n assert_eq!(candidate(4, 2), 2);\n assert_eq!(candidate(20, 5), 4);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find quotient of two numbers (rounded down to the nearest integer).\nfn find(n: isize, m: isize) -> isize {\n if m == 0 {\n panic!(\"Division by zero is not allowed\");\n }\n n / m\n}"} -{"name": "mbpp_603_get_ludic", "language": "rs", "prompt": "/// Write a function to get all lucid numbers smaller than or equal to a given integer.\nfn get_ludic(n: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_603_get_ludic.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "get_ludic", "test": "}\n\nfn main() {\n let candidate = get_ludic;\n assert_eq!(candidate(10), vec![1, 2, 3, 5, 7]);\n assert_eq!(candidate(25), vec![1, 2, 3, 5, 7, 11, 13, 17, 23, 25]);\n assert_eq!(candidate(45), vec![1, 2, 3, 5, 7, 11, 13, 17, 23, 25, 29, 37, 41, 43]);\n}\n", "solution": "/// Write a function to get all lucid numbers smaller than or equal to a given integer.\nfn get_ludic(n: isize) -> Vec {\n let mut ludic_numbers = vec![1];\n let mut candidates: Vec = (2..=n).collect();\n\n while let Some(current) = candidates.first().copied() {\n ludic_numbers.push(current);\n candidates.retain(|&x| x == current || x % current != 0);\n }\n\n ludic_numbers\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it only generates odd numbers and checks if they are not already in the ludic_numbers vector. This approach does not follow the proper algorithm for generating ludic numbers, which involves sieving and removing multiples of the current ludic number. As a result, the output contains incorrect values and misses some of the actual ludic numbers.", "The implementation is incorrect because it is causing a timeout for test cases with input greater than 1. This indicates that the algorithm is inefficient and takes too long to compute the ludic numbers for larger input values. The filtering and mapping steps in the loop may be contributing to the performance issue.", "The implementation of the get_ludic function is incorrect because it is causing a timeout in the tests for larger input values. This indicates that the algorithm used is inefficient and takes too long to compute the ludic numbers for the given range. The issue likely lies in the way the candidates are filtered and retained in the loop.", "The implementation of the get_ludic function is incorrect because it causes a timeout for input values greater than 1. This is likely due to an inefficient filtering process in the while loop, which results in a significant performance issue when dealing with larger input values."]} -{"name": "mbpp_734_sum_Of_Subarray_Prod", "language": "rs", "prompt": "/// Write a rsthon function to find sum of products of all possible subvectors of a given vector. https://www.geeksforgeeks.org/sum-of-products-of-all-possible-subvectors/\nfn sum_Of_Subarray_Prod(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_734_sum_Of_Subarray_Prod.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sum_Of_Subarray_Prod", "test": "}\n\nfn main() {\n let candidate = sum_Of_Subarray_Prod;\n assert_eq!(candidate(vec![1, 2, 3]), 20);\n assert_eq!(candidate(vec![1, 2]), 5);\n assert_eq!(candidate(vec![1, 2, 3, 4]), 84);\n}\n", "solution": "/// Write a rsthon function to find sum of products of all possible subvectors of a given vector. https://www.geeksforgeeks.org/sum-of-products-of-all-possible-subvectors/\nfn sum_Of_Subarray_Prod(arr: Vec) -> isize {\n let n = arr.len();\n let mut sum = 0;\n\n for i in 1..=n {\n for combination in arr.iter().combinations(i) {\n let product = combination.into_iter().product::();\n sum += product;\n }\n }\n\n sum\n}", "is_solved": true, "reflections": ["The implementation of the sum_Of_Subarray_Prod function is incorrect because it only calculates the sum of products of contiguous subarrays, not all possible subvectors. The formula used in the function does not account for non-contiguous subvectors, which is why the test case with the input vector [2, 3, 4] fails.", "The implementation is incorrect because it calculates the sum of all subarrays instead of the sum of products of all possible subvectors. The inner loop should multiply the elements of the subvector and add the product to the sum, rather than just adding the elements directly.", "The implementation of the sum_Of_Subarray_Prod function is incorrect because it calculates the sum of products of all possible subarrays instead of subvectors. The function iterates through all subarrays and calculates their product, but it does not consider the products of individual elements and their combinations, which are also part of the subvectors. This leads to incorrect results in the failed test cases.", "The implementation of the sum_Of_Subarray_Prod function is incorrect because it calculates the sum of products of all possible contiguous subarrays instead of all possible subvectors. The function needs to be modified to consider all possible combinations of elements in the vector, not just contiguous subarrays, to correctly calculate the sum of products of all possible subvectors."]} -{"name": "mbpp_567_issort_list", "language": "rs", "prompt": "/// Write a function to check whether a specified vector is sorted or not.\nfn issort_list(list1: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_567_issort_list.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "issort_list", "test": "}\n\nfn main() {\n let candidate = issort_list;\n assert_eq!(candidate(vec![1, 2, 4, 6, 8, 10, 12, 14, 16, 17]), true);\n assert_eq!(candidate(vec![1, 2, 4, 6, 8, 10, 12, 14, 20, 17]), false);\n assert_eq!(candidate(vec![1, 2, 4, 6, 8, 10, 15, 14, 20]), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check whether a specified vector is sorted or not.\nfn issort_list(list1: Vec) -> bool {\n if list1.is_empty() {\n return true;\n }\n\n for i in 1..list1.len() {\n if list1[i - 1] > list1[i] {\n return false;\n }\n }\n\n true\n}"} -{"name": "mbpp_475_sort_counter", "language": "rs", "prompt": "use std::collections::HashMap;\n\n/// Write a function to sort a HashMap by value.\nfn sort_counter(dict1: HashMap) -> Vec<(String, isize)> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_475_sort_counter.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sort_counter", "test": "}\n\nfn main() {\n let candidate = sort_counter;\n assert_eq!(candidate(HashMap::from([(String::from(\"Math\"), 81), (String::from(\"Physics\"), 83), (String::from(\"Chemistry\"), 87)])), vec![(String::from(\"Chemistry\"), 87), (String::from(\"Physics\"), 83), (String::from(\"Math\"), 81)]);\n assert_eq!(candidate(HashMap::from([(String::from(\"Math\"), 400), (String::from(\"Physics\"), 300), (String::from(\"Chemistry\"), 250)])), vec![(String::from(\"Math\"), 400), (String::from(\"Physics\"), 300), (String::from(\"Chemistry\"), 250)]);\n assert_eq!(candidate(HashMap::from([(String::from(\"Math\"), 900), (String::from(\"Physics\"), 1000), (String::from(\"Chemistry\"), 1250)])), vec![(String::from(\"Chemistry\"), 1250), (String::from(\"Physics\"), 1000), (String::from(\"Math\"), 900)]);\n}\n", "is_solved": true, "reflections": [], "solution": "use std::collections::HashMap;\n\n/// Write a function to sort a HashMap by value.\nfn sort_counter(dict1: HashMap) -> Vec<(String, isize)> {\n let mut vec: Vec<(&String, &isize)> = dict1.iter().collect();\n vec.sort_by(|a, b| a.1.cmp(b.1));\n\n let sorted_vec: Vec<(String, isize)> = vec.into_iter().map(|(k, v)| (k.clone(), *v)).collect();\n sorted_vec\n}"} -{"name": "mbpp_560_union_elements", "language": "rs", "prompt": "/// Write a function to find the union of the elements of two given vectors and output them in sorted order.\nfn union_elements(test_tup1: Vec, test_tup2: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_560_union_elements.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "union_elements", "test": "}\n\nfn main() {\n let candidate = union_elements;\n assert_eq!(candidate(vec![3, 4, 5, 6], vec![5, 7, 4, 10]), vec![3, 4, 5, 6, 7, 10]);\n assert_eq!(candidate(vec![1, 2, 3, 4], vec![3, 4, 5, 6]), vec![1, 2, 3, 4, 5, 6]);\n assert_eq!(candidate(vec![11, 12, 13, 14], vec![13, 15, 16, 17]), vec![11, 12, 13, 14, 15, 16, 17]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the union of the elements of two given vectors and output them in sorted order.\nfn union_elements(test_tup1: Vec, test_tup2: Vec) -> Vec {\n let mut result: Vec = Vec::new();\n\n for elem in test_tup1.into_iter() {\n if !result.contains(&elem) {\n result.push(elem);\n }\n }\n\n for elem in test_tup2.into_iter() {\n if !result.contains(&elem) {\n result.push(elem);\n }\n }\n\n result.sort();\n result\n}"} -{"name": "mbpp_737_check_str", "language": "rs", "prompt": "/// Write a function to check whether the given string is starting with a vowel or not using regex.\nfn check_str(string: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_737_check_str.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "check_str", "test": "}\n\nfn main() {\n let candidate = check_str;\n assert_eq!(candidate(String::from(\"annie\")), true);\n assert_eq!(candidate(String::from(\"dawood\")), false);\n assert_eq!(candidate(String::from(\"Else\")), true);\n}\n", "solution": "/// Write a function to check whether the given string is starting with a vowel or not using regex.\nfn check_str(string: String) -> bool {\n use regex::Regex;\n let re = Regex::new(r\"^[aeiouAEIOU]\").unwrap();\n re.is_match(&string)\n}", "is_solved": true, "reflections": ["The implementation is incorrect because the `regex` crate is not declared or imported, causing the compiler to throw an error. To fix this issue, the `regex` crate should be added to the `Cargo.toml` file and imported using `use regex::Regex;` at the beginning of the code.", "The implementation is incorrect because the `regex` crate is not declared in the dependencies, causing an unresolved import error. To fix this, the `regex` crate should be added to the `Cargo.toml` file under the `[dependencies]` section.", "The implementation is incorrect because the `regex` crate is not declared and imported in the code. This leads to an unresolved import error when trying to use the `regex::Regex` module. To fix this issue, the `regex` crate should be added to the dependencies in the `Cargo.toml` file and properly imported in the code.", "The implementation is incorrect because the `regex` crate is not declared and imported in the code. This leads to an unresolved import error when trying to use the `regex::Regex` module. To fix this issue, the `regex` crate should be added to the dependencies in the `Cargo.toml` file and properly imported in the code."]} -{"name": "mbpp_626_triangle_area", "language": "rs", "prompt": "/// Write a rsthon function to find the area of the largest triangle that can be inscribed in a semicircle with a given radius.\nfn triangle_area(r: isize) -> Option {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_626_triangle_area.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "triangle_area", "test": "}\n\nfn main() {\n let candidate = triangle_area;\n assert_eq!(candidate(-1), None);\n assert_eq!(candidate(0), Some(0));\n assert_eq!(candidate(2), Some(4));\n}\n", "solution": "/// Write a rsthon function to find the area of the largest triangle that can be inscribed in a semicircle with a given radius.\nfn triangle_area(r: isize) -> Option {\n if r <= 0 {\n return None;\n }\n\n let area = r as f64 * r as f64;\n Some(area as isize)\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it calculates the area of the semicircle instead of the largest inscribed triangle. The formula used (r^2 * PI / 2) is for the semicircle area, not the triangle area. The correct formula for the largest inscribed triangle area should be (r^2)."]} -{"name": "mbpp_463_max_subarray_product", "language": "rs", "prompt": "/// Write a function to find the maximum product subvector of the given vector.\nfn max_subarray_product(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_463_max_subarray_product.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_subarray_product", "test": "}\n\nfn main() {\n let candidate = max_subarray_product;\n assert_eq!(candidate(vec![1, -2, -3, 0, 7, -8, -2]), 112);\n assert_eq!(candidate(vec![6, -3, -10, 0, 2]), 180);\n assert_eq!(candidate(vec![-2, -40, 0, -2, -3]), 80);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the maximum product subvector of the given vector.\nfn max_subarray_product(arr: Vec) -> isize {\n if arr.is_empty() {\n return 0;\n }\n\n let mut max_product = arr[0];\n let mut min_product = arr[0];\n let mut result = arr[0];\n\n for i in 1..arr.len() {\n if arr[i] < 0 {\n let temp = max_product;\n max_product = min_product;\n min_product = temp;\n }\n\n max_product = isize::max(arr[i], max_product * arr[i]);\n min_product = isize::min(arr[i], min_product * arr[i]);\n\n result = isize::max(result, max_product);\n }\n\n result\n}"} -{"name": "mbpp_223_is_majority", "language": "rs", "prompt": "/// Write a function that takes in a sorted vector, its length (n), and an element and returns whether the element is the majority element in the given sorted vector. (The majority element is the element that occurs more than n/2 times.)\nfn is_majority(arr: Vec, n: isize, x: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_223_is_majority.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_majority", "test": "}\n\nfn main() {\n let candidate = is_majority;\n assert_eq!(candidate(vec![1, 2, 3, 3, 3, 3, 10], 7, 3), true);\n assert_eq!(candidate(vec![1, 1, 2, 4, 4, 4, 6, 6], 8, 4), false);\n assert_eq!(candidate(vec![1, 1, 1, 2, 2], 5, 1), true);\n assert_eq!(candidate(vec![1, 1, 2, 2], 5, 1), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function that takes in a sorted vector, its length (n), and an element and returns whether the element is the majority element in the given sorted vector. (The majority element is the element that occurs more than n/2 times.)\nfn is_majority(arr: Vec, n: isize, x: isize) -> bool {\n let mut count = 0;\n\n for i in 0..n {\n if arr[i as usize] == x {\n count += 1;\n }\n }\n\n count > n / 2\n}"} -{"name": "mbpp_794_text_starta_endb", "language": "rs", "prompt": "/// Write a function that matches a string that has an 'a' followed by anything, ending in 'b'.\nfn text_starta_endb(text: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_794_text_starta_endb.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "text_starta_endb", "test": "}\n\nfn main() {\n let candidate = text_starta_endb;\n assert_eq!(candidate(String::from(\"aabbbb\")), true);\n assert_eq!(candidate(String::from(\"aabAbbbc\")), false);\n assert_eq!(candidate(String::from(\"accddbbjjj\")), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function that matches a string that has an 'a' followed by anything, ending in 'b'.\nfn text_starta_endb(text: String) -> bool {\n if text.starts_with('a') && text.ends_with('b') {\n return true;\n }\n false\n}"} -{"name": "mbpp_79_word_len", "language": "rs", "prompt": "/// Write a rsthon function to check whether the length of the word is odd or not.\nfn word_len(s: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_79_word_len.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "word_len", "test": "}\n\nfn main() {\n let candidate = word_len;\n assert_eq!(candidate(String::from(\"Hadoop\")), false);\n assert_eq!(candidate(String::from(\"great\")), true);\n assert_eq!(candidate(String::from(\"structure\")), true);\n}\n", "solution": "/// Write a rsthon function to check whether the length of the word is odd or not.\nfn word_len(s: String) -> bool {\n let length = s.chars().count();\n length % 2 != 0\n}", "is_solved": true, "reflections": ["The implementation of the word_len function is incorrect because it returns true when the length of the word is odd, and false when it is even. The failed test case \"world\" has an odd length of 5, but the expected result is false. The function should be modified to return the correct result based on the problem statement.", "The implementation of the `word_len` function is incorrect because it returns true when the length of the word is even, and false when the length is odd. The function should return true for odd lengths and false for even lengths.", "The implementation of the `word_len` function is incorrect because it returns true for odd-length words and false for even-length words. However, the failed test case expects the function to return false for the word \"world\", which has an odd length. The function should be modified to correctly handle the requirements of the problem statement.", "The implementation of the `word_len` function is incorrect because it returns true when the length of the word is even, and false when the length is odd. The function should return true for odd lengths and false for even lengths. The current implementation is the opposite of the desired behavior."]} -{"name": "mbpp_741_all_Characters_Same", "language": "rs", "prompt": "/// Write a rsthon function to check whether all the characters are same or not.\nfn all_Characters_Same(s: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_741_all_Characters_Same.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "all_Characters_Same", "test": "}\n\nfn main() {\n let candidate = all_Characters_Same;\n assert_eq!(candidate(String::from(\"python\")), false);\n assert_eq!(candidate(String::from(\"aaa\")), true);\n assert_eq!(candidate(String::from(\"data\")), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to check whether all the characters are same or not.\nfn all_Characters_Same(s: String) -> bool {\n if s.is_empty() {\n return true;\n }\n\n let first_char = s.chars().next().unwrap();\n for c in s.chars() {\n if c != first_char {\n return false;\n }\n }\n\n true\n}"} -{"name": "mbpp_775_odd_position", "language": "rs", "prompt": "/// Write a rsthon function to check whether every odd index contains odd numbers of a given vector.\nfn odd_position(nums: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_775_odd_position.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "odd_position", "test": "}\n\nfn main() {\n let candidate = odd_position;\n assert_eq!(candidate(vec![2, 1, 4, 3, 6, 7, 6, 3]), true);\n assert_eq!(candidate(vec![4, 1, 2]), true);\n assert_eq!(candidate(vec![1, 2, 3]), false);\n}\n", "solution": "/// Write a rsthon function to check whether every odd index contains odd numbers of a given vector.\nfn odd_position(nums: Vec) -> bool {\n let odd_indices_count = (1..nums.len()).step_by(2).count();\n odd_indices_count % 2 != 0\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it checks if the numbers at odd indices are odd, but the requirement is to check if there are odd numbers of elements at odd indices. The failed test case has all odd numbers, but the number of elements at odd indices is even (2, 4), which should return false, but the implementation returns true."]} -{"name": "mbpp_644_reverse_Array_Upto_K", "language": "rs", "prompt": "/// Write a rsthon function to reverse a vector upto a given position.\nfn reverse_Array_Upto_K(input: Vec, k: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_644_reverse_Array_Upto_K.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "reverse_Array_Upto_K", "test": "}\n\nfn main() {\n let candidate = reverse_Array_Upto_K;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6], 4), vec![4, 3, 2, 1, 5, 6]);\n assert_eq!(candidate(vec![4, 5, 6, 7], 2), vec![5, 4, 6, 7]);\n assert_eq!(candidate(vec![9, 8, 7, 6, 5], 3), vec![7, 8, 9, 6, 5]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to reverse a vector upto a given position.\nfn reverse_Array_Upto_K(input: Vec, k: isize) -> Vec {\n if k <= 0 {\n return input;\n }\n\n let k = k as usize;\n let mut result = input.clone();\n let mut start = 0;\n let mut end = k - 1;\n\n while start < end {\n result.swap(start, end);\n start += 1;\n end -= 1;\n }\n\n result\n}"} -{"name": "mbpp_588_big_diff", "language": "rs", "prompt": "/// Write a rsthon function to find the difference between largest and smallest value in a given vector.\nfn big_diff(nums: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_588_big_diff.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "big_diff", "test": "}\n\nfn main() {\n let candidate = big_diff;\n assert_eq!(candidate(vec![1, 2, 3, 4]), 3);\n assert_eq!(candidate(vec![4, 5, 12]), 8);\n assert_eq!(candidate(vec![9, 2, 3]), 7);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the difference between largest and smallest value in a given vector.\nfn big_diff(nums: Vec) -> isize {\n if nums.is_empty() {\n return 0;\n }\n\n let mut min_num = nums[0];\n let mut max_num = nums[0];\n\n for num in nums {\n if num < min_num {\n min_num = num;\n } else if num > max_num {\n max_num = num;\n }\n }\n\n max_num - min_num\n}"} -{"name": "mbpp_445_index_multiplication", "language": "rs", "prompt": "/// Write a function to perform index wise multiplication of vector elements in the given two vectors.\nfn index_multiplication(test_tup1: Vec>, test_tup2: Vec>) -> Vec> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_445_index_multiplication.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "index_multiplication", "test": "}\n\nfn main() {\n let candidate = index_multiplication;\n assert_eq!(candidate(vec![vec![1, 3], vec![4, 5], vec![2, 9], vec![1, 10]], vec![vec![6, 7], vec![3, 9], vec![1, 1], vec![7, 3]]), vec![vec![6, 21], vec![12, 45], vec![2, 9], vec![7, 30]]);\n assert_eq!(candidate(vec![vec![2, 4], vec![5, 6], vec![3, 10], vec![2, 11]], vec![vec![7, 8], vec![4, 10], vec![2, 2], vec![8, 4]]), vec![vec![14, 32], vec![20, 60], vec![6, 20], vec![16, 44]]);\n assert_eq!(candidate(vec![vec![3, 5], vec![6, 7], vec![4, 11], vec![3, 12]], vec![vec![8, 9], vec![5, 11], vec![3, 3], vec![9, 5]]), vec![vec![24, 45], vec![30, 77], vec![12, 33], vec![27, 60]]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to perform index wise multiplication of vector elements in the given two vectors.\nfn index_multiplication(test_tup1: Vec>, test_tup2: Vec>) -> Vec> {\n let mut result: Vec> = Vec::new();\n\n for i in 0..test_tup1.len() {\n let mut row: Vec = Vec::new();\n for j in 0..test_tup1[i].len() {\n row.push(test_tup1[i][j] * test_tup2[i][j]);\n }\n result.push(row);\n }\n\n result\n}"} -{"name": "mbpp_256_count_Primes_nums", "language": "rs", "prompt": "/// Write a rsthon function that takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\nfn count_Primes_nums(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_256_count_Primes_nums.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_Primes_nums", "test": "}\n\nfn main() {\n let candidate = count_Primes_nums;\n assert_eq!(candidate(5), 2);\n assert_eq!(candidate(10), 4);\n assert_eq!(candidate(100), 25);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function that takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\nfn count_Primes_nums(n: isize) -> isize {\n if n <= 2 {\n return 0;\n }\n\n let mut primes = vec![true; n as usize];\n primes[0] = false;\n primes[1] = false;\n\n for i in 2..((n as f64).sqrt().ceil() as usize) {\n if primes[i] {\n let mut j = i * i;\n while j < n as usize {\n primes[j] = false;\n j += i;\n }\n }\n }\n\n primes.into_iter().filter(|&prime| prime).count() as isize\n}"} -{"name": "mbpp_170_sum_range_list", "language": "rs", "prompt": "/// Write a function to find the sum of numbers in a vector within a range specified by two indices.\nfn sum_range_list(list1: Vec, m: isize, n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_170_sum_range_list.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sum_range_list", "test": "}\n\nfn main() {\n let candidate = sum_range_list;\n assert_eq!(candidate(vec![2, 1, 5, 6, 8, 3, 4, 9, 10, 11, 8, 12], 8, 10), 29);\n assert_eq!(candidate(vec![2, 1, 5, 6, 8, 3, 4, 9, 10, 11, 8, 12], 5, 7), 16);\n assert_eq!(candidate(vec![2, 1, 5, 6, 8, 3, 4, 9, 10, 11, 8, 12], 7, 10), 38);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the sum of numbers in a vector within a range specified by two indices.\nfn sum_range_list(list1: Vec, m: isize, n: isize) -> isize {\n let mut sum = 0;\n for i in m as usize..=n as usize {\n if i < list1.len() {\n sum += list1[i];\n }\n }\n sum\n}"} -{"name": "mbpp_71_comb_sort", "language": "rs", "prompt": "/// Write a function to sort a vector of elements.\nfn comb_sort(nums: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_71_comb_sort.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "comb_sort", "test": "}\n\nfn main() {\n let candidate = comb_sort;\n assert_eq!(candidate(vec![5, 15, 37, 25, 79]), vec![5, 15, 25, 37, 79]);\n assert_eq!(candidate(vec![41, 32, 15, 19, 22]), vec![15, 19, 22, 32, 41]);\n assert_eq!(candidate(vec![99, 15, 13, 47]), vec![13, 15, 47, 99]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to sort a vector of elements.\nfn comb_sort(nums: Vec) -> Vec {\n let mut nums = nums;\n let mut gap = nums.len();\n let shrink_factor = 1.3;\n let mut sorted = false;\n\n while !sorted {\n gap = (gap as f64 / shrink_factor).floor() as usize;\n if gap <= 1 {\n gap = 1;\n sorted = true;\n }\n\n let mut i = 0;\n while i + gap < nums.len() {\n if nums[i] > nums[i + gap] {\n nums.swap(i, i + gap);\n sorted = false;\n }\n i += 1;\n }\n }\n\n nums\n}"} -{"name": "mbpp_451_remove_whitespaces", "language": "rs", "prompt": "/// Write a function to remove all whitespaces from the given string.\nfn remove_whitespaces(text1: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_451_remove_whitespaces.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "remove_whitespaces", "test": "}\n\nfn main() {\n let candidate = remove_whitespaces;\n assert_eq!(candidate(String::from(\" Google Flutter \")), String::from(\"GoogleFlutter\"));\n assert_eq!(candidate(String::from(\" Google Dart \")), String::from(\"GoogleDart\"));\n assert_eq!(candidate(String::from(\" iOS Swift \")), String::from(\"iOSSwift\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to remove all whitespaces from the given string.\nfn remove_whitespaces(text1: String) -> String {\n text1.chars().filter(|c| !c.is_whitespace()).collect()\n}"} -{"name": "mbpp_747_lcs_of_three", "language": "rs", "prompt": "/// Write a function to find the longest common subsequence for the given three string sequence. https://www.geeksforgeeks.org/lcs-longest-common-subsequence-three-strings/\nfn lcs_of_three(X: String, Y: String, Z: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_747_lcs_of_three.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "lcs_of_three", "test": "}\n\nfn main() {\n let candidate = lcs_of_three;\n assert_eq!(candidate(String::from(\"AGGT12\"), String::from(\"12TXAYB\"), String::from(\"12XBA\")), 2);\n assert_eq!(candidate(String::from(\"Reels\"), String::from(\"Reelsfor\"), String::from(\"ReelsforReels\")), 5);\n assert_eq!(candidate(String::from(\"abcd1e2\"), String::from(\"bc12ea\"), String::from(\"bd1ea\")), 3);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the longest common subsequence for the given three string sequence. https://www.geeksforgeeks.org/lcs-longest-common-subsequence-three-strings/\nfn lcs_of_three(X: String, Y: String, Z: String) -> isize {\n let m = X.len();\n let n = Y.len();\n let o = Z.len();\n\n let mut dp = vec![vec![vec![0; o + 1]; n + 1]; m + 1];\n\n for i in 1..=m {\n for j in 1..=n {\n for k in 1..=o {\n if X.chars().nth(i - 1) == Y.chars().nth(j - 1) && X.chars().nth(i - 1) == Z.chars().nth(k - 1) {\n dp[i][j][k] = dp[i - 1][j - 1][k - 1] + 1;\n } else {\n dp[i][j][k] = std::cmp::max(dp[i - 1][j][k], std::cmp::max(dp[i][j - 1][k], dp[i][j][k - 1]));\n }\n }\n }\n }\n\n dp[m][n][o]\n}"} -{"name": "mbpp_257_swap_numbers", "language": "rs", "prompt": "/// Write a function that takes in two numbers and returns a vector with the second number and then the first number.\nfn swap_numbers(a: isize, b: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_257_swap_numbers.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "swap_numbers", "test": "}\n\nfn main() {\n let candidate = swap_numbers;\n assert_eq!(candidate(10, 20), vec![20, 10]);\n assert_eq!(candidate(15, 17), vec![17, 15]);\n assert_eq!(candidate(100, 200), vec![200, 100]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function that takes in two numbers and returns a vector with the second number and then the first number.\nfn swap_numbers(a: isize, b: isize) -> Vec {\n let mut swapped = Vec::new();\n swapped.push(b);\n swapped.push(a);\n swapped\n}"} -{"name": "mbpp_64_subject_marks", "language": "rs", "prompt": "/// Write a function to sort a vector of tuples using the second value of each tuple.\nfn subject_marks(subjectmarks: Vec<(String, isize)>) -> Vec<(String, isize)> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_64_subject_marks.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "subject_marks", "test": "}\n\nfn main() {\n let candidate = subject_marks;\n assert_eq!(candidate(vec![(String::from(\"English\"), 88), (String::from(\"Science\"), 90), (String::from(\"Maths\"), 97), (String::from(\"Social sciences\"), 82)]), vec![(String::from(\"Social sciences\"), 82), (String::from(\"English\"), 88), (String::from(\"Science\"), 90), (String::from(\"Maths\"), 97)]);\n assert_eq!(candidate(vec![(String::from(\"Telugu\"), 49), (String::from(\"Hindhi\"), 54), (String::from(\"Social\"), 33)]), vec![(String::from(\"Social\"), 33), (String::from(\"Telugu\"), 49), (String::from(\"Hindhi\"), 54)]);\n assert_eq!(candidate(vec![(String::from(\"Physics\"), 96), (String::from(\"Chemistry\"), 97), (String::from(\"Biology\"), 45)]), vec![(String::from(\"Biology\"), 45), (String::from(\"Physics\"), 96), (String::from(\"Chemistry\"), 97)]);\n}\n", "solution": "/// Write a function to sort a vector of tuples using the second value of each tuple.\nfn subject_marks(subjectmarks: Vec<(String, isize)>) -> Vec<(String, isize)> {\n let mut subjectmarks = subjectmarks;\n subjectmarks.sort_by(|a, b| a.1.cmp(&b.1));\n subjectmarks\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it tries to use the non-existent method `sorted_by` on `std::vec::IntoIter`. The correct method to use for sorting a vector is `sort_by`."]} -{"name": "mbpp_116_tuple_to_int", "language": "rs", "prompt": "/// Write a function to convert a given tuple of positive integers into a single integer.\nfn tuple_to_int(nums: (isize, isize, isize)) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_116_tuple_to_int.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "tuple_to_int", "test": "}\n\nfn main() {\n let candidate = tuple_to_int;\n assert_eq!(candidate((1, 2, 3)), 123);\n assert_eq!(candidate((4, 5, 6)), 456);\n assert_eq!(candidate((5, 6, 7)), 567);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to convert a given tuple of positive integers into a single integer.\nfn tuple_to_int(nums: (isize, isize, isize)) -> isize {\n let (a, b, c) = nums;\n let result = a * 100 + b * 10 + c;\n result\n}"} -{"name": "mbpp_479_first_Digit", "language": "rs", "prompt": "/// Write a rsthon function to find the first digit of a given number.\nfn first_Digit(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_479_first_Digit.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "first_Digit", "test": "}\n\nfn main() {\n let candidate = first_Digit;\n assert_eq!(candidate(123), 1);\n assert_eq!(candidate(456), 4);\n assert_eq!(candidate(12), 1);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the first digit of a given number.\nfn first_Digit(n: isize) -> isize {\n let mut num = n.abs();\n while num >= 10 {\n num /= 10;\n }\n num\n}"} -{"name": "mbpp_118_string_to_list", "language": "rs", "prompt": "/// Write a function to convert a string to a vector of strings split on the space character.\nfn string_to_list(string: String) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_118_string_to_list.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "string_to_list", "test": "}\n\nfn main() {\n let candidate = string_to_list;\n assert_eq!(candidate(String::from(\"python programming\")), vec![String::from(\"python\"), String::from(\"programming\")]);\n assert_eq!(candidate(String::from(\"lists tuples strings\")), vec![String::from(\"lists\"), String::from(\"tuples\"), String::from(\"strings\")]);\n assert_eq!(candidate(String::from(\"write a program\")), vec![String::from(\"write\"), String::from(\"a\"), String::from(\"program\")]);\n}\n", "solution": "/// Write a function to convert a string to a vector of strings split on the space character.\nfn string_to_list(string: String) -> Vec {\n string.split_whitespace()\n .map(|s| s.to_string())\n .collect()\n}", "is_solved": true, "reflections": ["The implementation is incorrect because the function is defined inside the main function, causing an unclosed delimiter error. The function should be defined outside the main function to fix the issue."]} -{"name": "mbpp_763_find_min_diff", "language": "rs", "prompt": "/// Write a rsthon function to find the minimum difference between any two elements in a given vector. https://www.geeksforgeeks.org/find-minimum-difference-pair/\nfn find_min_diff(arr: Vec, n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_763_find_min_diff.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_min_diff", "test": "}\n\nfn main() {\n let candidate = find_min_diff;\n assert_eq!(candidate(vec![1, 5, 3, 19, 18, 25], 6), 1);\n assert_eq!(candidate(vec![4, 3, 2, 6], 4), 1);\n assert_eq!(candidate(vec![30, 5, 20, 9], 4), 4);\n}\n", "solution": "/// Write a rsthon function to find the minimum difference between any two elements in a given vector. https://www.geeksforgeeks.org/find-minimum-difference-pair/\nfn find_min_diff(arr: Vec, n: isize) -> isize {\n if n == 0 {\n return 0;\n }\n\n let mut arr = arr;\n arr.sort();\n\n let mut min_diff = arr[1] - arr[0];\n\n for i in 1..(n as usize - 1) {\n let diff = arr[i + 1] - arr[i];\n if diff < min_diff {\n min_diff = diff;\n }\n }\n\n min_diff\n}", "is_solved": true, "reflections": ["The implementation is incorrect because the input vector `arr` is not declared as mutable, but the `sort()` method is called on it, which requires a mutable reference. To fix this issue, the input vector `arr` should be declared as mutable."]} -{"name": "mbpp_408_k_smallest_pairs", "language": "rs", "prompt": "/// Write a function to find k number of smallest pairs which consist of one element from the first vector and one element from the second vector.\nfn k_smallest_pairs(nums1: Vec, nums2: Vec, k: isize) -> Vec> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_408_k_smallest_pairs.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "k_smallest_pairs", "test": "}\n\nfn main() {\n let candidate = k_smallest_pairs;\n assert_eq!(candidate(vec![1, 3, 7], vec![2, 4, 6], 2), vec![vec![1, 2], vec![1, 4]]);\n assert_eq!(candidate(vec![1, 3, 7], vec![2, 4, 6], 1), vec![vec![1, 2]]);\n assert_eq!(candidate(vec![1, 3, 7], vec![2, 4, 6], 7), vec![vec![1, 2], vec![1, 4], vec![3, 2], vec![1, 6], vec![3, 4], vec![3, 6], vec![7, 2]]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find k number of smallest pairs which consist of one element from the first vector and one element from the second vector.\nfn k_smallest_pairs(nums1: Vec, nums2: Vec, k: isize) -> Vec> {\n let mut pairs: Vec> = Vec::new();\n\n for &num1 in nums1.iter() {\n for &num2 in nums2.iter() {\n pairs.push(vec![num1, num2]);\n }\n }\n\n pairs.sort_by_key(|pair| pair[0] + pair[1]);\n\n if k as usize > pairs.len() {\n return pairs;\n }\n\n pairs.into_iter().take(k as usize).collect()\n}"} -{"name": "mbpp_748_capital_words_spaces", "language": "rs", "prompt": "/// Write a function to put spaces between words starting with capital letters in a given string.\nfn capital_words_spaces(str1: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_748_capital_words_spaces.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "capital_words_spaces", "test": "}\n\nfn main() {\n let candidate = capital_words_spaces;\n assert_eq!(candidate(String::from(\"Python\")), String::from(\"Python\"));\n assert_eq!(candidate(String::from(\"PythonProgrammingExamples\")), String::from(\"Python Programming Examples\"));\n assert_eq!(candidate(String::from(\"GetReadyToBeCodingFreak\")), String::from(\"Get Ready To Be Coding Freak\"));\n}\n", "solution": "/// Write a function to put spaces between words starting with capital letters in a given string.\nfn capital_words_spaces(str1: String) -> String {\n let mut result = String::new();\n let chars = str1.chars().collect::>();\n\n for (i, c) in chars.iter().enumerate() {\n if i > 0 && c.is_uppercase() {\n if !chars[i - 1].is_uppercase() || (i < chars.len() - 1 && !chars[i + 1].is_uppercase()) {\n result.push(' ');\n }\n }\n result.push(*c);\n }\n\n result\n}", "is_solved": true, "reflections": ["The current implementation of the `capital_words_spaces` function incorrectly adds spaces between consecutive uppercase letters. This causes the function to fail when dealing with acronyms or initialisms, as seen in the failed test cases. The function needs to be modified to handle such cases correctly.", "The current implementation fails to handle cases where there are consecutive uppercase letters in the input string. It only adds a space when the current character is uppercase and the previous character is not uppercase, causing incorrect spacing when there are multiple uppercase letters together."]} -{"name": "mbpp_252_convert", "language": "rs", "prompt": "/// Write a rsthon function to convert complex numbers to polar coordinates.\nfn convert(numbers: isize) -> (f64, f64) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_252_convert.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "convert", "test": "}\n\nfn main() {\n let candidate = convert;\n assert_eq!(candidate(1), (1.0, 0.0));\n assert_eq!(candidate(4), (4.0, 0.0));\n assert_eq!(candidate(5), (5.0, 0.0));\n}\n", "solution": "/// Write a rsthon function to convert complex numbers to polar coordinates.\nfn convert(numbers: isize) -> (f64, f64) {\n let real = numbers as f64;\n let imaginary = 0.0;\n\n let radius = (real.powi(2) + imaginary.powi(2)).sqrt();\n let angle = imaginary.atan2(real);\n\n (radius, angle)\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it treats the input `numbers` as both the real and imaginary parts of the complex number, which is not the intended behavior. This leads to incorrect radius and angle calculations in the polar coordinates conversion.", "The implementation is wrong because it only handles real numbers and not complex numbers. The function takes an isize input instead of a complex number, and the imaginary part is always set to 0.0. Additionally, there is a type error due to ambiguous numeric type for the `imaginary` variable.", "The implementation is wrong because it only handles real numbers and does not account for the imaginary part of the complex number. Additionally, the function signature expects an isize input, which is not suitable for complex numbers. The error message indicates that the type of `imaginary` is ambiguous, but the main issue is the lack of support for complex numbers in the function.", "The implementation is wrong because it only handles real numbers and does not account for the imaginary part of the complex number. Additionally, the input parameter is of type `isize`, which is not suitable for complex numbers. The error message indicates that the type of `imaginary` is ambiguous and needs to be specified, but the main issue is that the function does not properly handle complex numbers."]} -{"name": "mbpp_436_neg_nos", "language": "rs", "prompt": "/// Write a rsthon function to return the negative numbers in a vector.\nfn neg_nos(list1: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_436_neg_nos.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "neg_nos", "test": "}\n\nfn main() {\n let candidate = neg_nos;\n assert_eq!(candidate(vec![-1, 4, 5, -6]), vec![-1, -6]);\n assert_eq!(candidate(vec![-1, -2, 3, 4]), vec![-1, -2]);\n assert_eq!(candidate(vec![-7, -6, 8, 9]), vec![-7, -6]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to return the negative numbers in a vector.\nfn neg_nos(list1: Vec) -> Vec {\n let mut neg_numbers = Vec::new();\n\n for num in list1 {\n if num < 0 {\n neg_numbers.push(num);\n }\n }\n\n neg_numbers\n}"} -{"name": "mbpp_397_median_numbers", "language": "rs", "prompt": "/// Write a function to find the median of three numbers.\nfn median_numbers(a: isize, b: isize, c: isize) -> f64 {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_397_median_numbers.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "median_numbers", "test": "}\n\nfn main() {\n let candidate = median_numbers;\n assert_eq!(candidate(25, 55, 65), 55.0);\n assert_eq!(candidate(20, 10, 30), 20.0);\n assert_eq!(candidate(15, 45, 75), 45.0);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the median of three numbers.\nfn median_numbers(a: isize, b: isize, c: isize) -> f64 {\n let mut nums = [a, b, c];\n nums.sort();\n nums[1] as f64\n}"} -{"name": "mbpp_745_divisible_by_digits", "language": "rs", "prompt": "/// Write a function to find numbers within a given range from startnum ti endnum where every number is divisible by every digit it contains. https://www.w3resource.com/rsthon-exercises/lambda/rsthon-lambda-exercise-24.php\nfn divisible_by_digits(startnum: isize, endnum: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_745_divisible_by_digits.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "divisible_by_digits", "test": "}\n\nfn main() {\n let candidate = divisible_by_digits;\n assert_eq!(candidate(1, 22), vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 15, 22]);\n assert_eq!(candidate(1, 15), vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 15]);\n assert_eq!(candidate(20, 25), vec![22, 24]);\n}\n", "solution": "/// Write a function to find numbers within a given range from startnum ti endnum where every number is divisible by every digit it contains. https://www.w3resource.com/rsthon-exercises/lambda/rsthon-lambda-exercise-24.php\nfn divisible_by_digits(startnum: isize, endnum: isize) -> Vec {\n let mut result = Vec::new();\n\n for num in startnum..=endnum {\n let mut divisible = true;\n let num_str = num.to_string();\n let digits = num_str.chars().filter_map(|c| c.to_digit(10)).map(|d| d as isize);\n\n for digit in digits {\n if digit == 0 || num % digit != 0 {\n divisible = false;\n break;\n }\n }\n\n if divisible && num_str.chars().all(|c| c.to_digit(10).unwrap() != 0 && num % c.to_digit(10).unwrap() as isize == 0) {\n result.push(num);\n }\n }\n\n result\n}", "is_solved": true, "reflections": ["The implementation is wrong because it creates a temporary value when converting the number to a string, which gets dropped before it can be used in the loop. This results in a borrow checker error. To fix this issue, a `let` binding should be used to create a longer-lived value for the string representation of the number.", "The implementation of the divisible_by_digits function is incorrect because it does not properly handle cases where the number contains a digit '0'. The function incorrectly marks the number as not divisible when it encounters a '0', causing it to skip valid numbers in the output. This leads to the failed test cases where the expected output does not match the actual output.", "The implementation of the divisible_by_digits function is incorrect because it does not properly handle cases where a number contains a digit that is not divisible by the number itself. The function is including numbers in the result vector that should not be there, as shown by the failed test cases. The logic for checking divisibility needs to be adjusted to exclude such numbers from the result.", "The implementation of the divisible_by_digits function is incorrect because it does not properly handle cases where the number contains a digit that is not divisible by the number itself. This leads to incorrect results being added to the output vector, causing the failed test cases."]} -{"name": "mbpp_554_Split", "language": "rs", "prompt": "/// Write a rsthon function which takes a vector of integers and only returns the odd ones.\nfn Split(list: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_554_Split.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "Split", "test": "}\n\nfn main() {\n let candidate = Split;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6]), vec![1, 3, 5]);\n assert_eq!(candidate(vec![10, 11, 12, 13]), vec![11, 13]);\n assert_eq!(candidate(vec![7, 8, 9, 1]), vec![7, 9, 1]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function which takes a vector of integers and only returns the odd ones.\nfn Split(list: Vec) -> Vec {\n let mut odd_numbers = Vec::new();\n\n for number in list {\n if number % 2 != 0 {\n odd_numbers.push(number);\n }\n }\n\n odd_numbers\n}"} -{"name": "mbpp_128_long_words", "language": "rs", "prompt": "/// Write a function to find words that are longer than n characters from a given vector of words.\nfn long_words(n: isize, str: String) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_128_long_words.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "long_words", "test": "}\n\nfn main() {\n let candidate = long_words;\n assert_eq!(candidate(3, String::from(\"python is a programming language\")), vec![String::from(\"python\"), String::from(\"programming\"), String::from(\"language\")]);\n assert_eq!(candidate(2, String::from(\"writing a program\")), vec![String::from(\"writing\"), String::from(\"program\")]);\n assert_eq!(candidate(5, String::from(\"sorting list\")), vec![String::from(\"sorting\")]);\n}\n", "solution": "/// Write a function to find words that are longer than n characters from a given vector of words.\nfn long_words(n: isize, str: String) -> Vec {\n let words: Vec = str.split_whitespace().map(|s| s.to_string()).collect();\n let mut long_words: Vec = Vec::new();\n\n for word in words {\n if word.len() > n as usize {\n long_words.push(word);\n }\n }\n\n long_words\n}", "is_solved": true, "reflections": ["The implementation of the `long_words` function is incorrect because it only returns words that have a length strictly greater than `n`. The test cases are failing because they expect words with a length equal to `n` to be included in the result. To fix the implementation, the condition in the if statement should be changed to `word.len() >= n as usize`.", "The implementation is incorrect because it includes words with a length equal to `n` in the result, while the problem statement asks for words longer than `n` characters. This causes the function to return extra words in the output, leading to failed test cases.", "The implementation of the `long_words` function is incorrect because it only returns words that have a length strictly greater than `n`. The test cases are failing because they expect words with a length equal to `n` to be included in the result. To fix the implementation, the condition in the if statement should be changed to `word.len() >= n as usize`.", "The implementation is incorrect because it includes words with length equal to n in the result, while the problem statement asks for words longer than n characters. This causes the function to return extra words in the output, leading to failed test cases."]} -{"name": "mbpp_69_is_sublist", "language": "rs", "prompt": "/// Write a function to check whether a vector contains the given subvector or not.\nfn is_sublist(l: Vec, s: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_69_is_sublist.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_sublist", "test": "}\n\nfn main() {\n let candidate = is_sublist;\n assert_eq!(candidate(vec![2, 4, 3, 5, 7], vec![3, 7]), false);\n assert_eq!(candidate(vec![2, 4, 3, 5, 7], vec![4, 3]), true);\n assert_eq!(candidate(vec![2, 4, 3, 5, 7], vec![1, 6]), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check whether a vector contains the given subvector or not.\nfn is_sublist(l: Vec, s: Vec) -> bool {\n if s.is_empty() {\n return true;\n }\n\n if l.len() < s.len() {\n return false;\n }\n\n for i in 0..=(l.len() - s.len()) {\n if l[i..i + s.len()] == s[..] {\n return true;\n }\n }\n\n false\n}"} -{"name": "mbpp_732_replace_specialchar", "language": "rs", "prompt": "/// Write a function to replace all occurrences of spaces, commas, or dots with a colon.\nfn replace_specialchar(text: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_732_replace_specialchar.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "replace_specialchar", "test": "}\n\nfn main() {\n let candidate = replace_specialchar;\n assert_eq!(candidate(String::from(\"Python language, Programming language.\")), String::from(\"Python:language::Programming:language:\"));\n assert_eq!(candidate(String::from(\"a b c,d e f\")), String::from(\"a:b:c:d:e:f\"));\n assert_eq!(candidate(String::from(\"ram reshma,ram rahim\")), String::from(\"ram:reshma:ram:rahim\"));\n}\n", "solution": "/// Write a function to replace all occurrences of spaces, commas, or dots with a colon.\nfn replace_specialchar(text: String) -> String {\n text.chars()\n .map(|c| match c {\n ' ' | ',' | '.' | '!' => ':',\n _ => c,\n })\n .collect()\n}", "is_solved": true, "reflections": ["The implementation is wrong because it uses the `replace` method with a closure, which is not the correct way to use this method. The `replace` method expects a pattern and a replacement string as arguments, not a closure. This results in a syntax error and an unclosed delimiter issue.", "The implementation is incorrect because it is placed inside the main function, causing an unclosed delimiter error. The function should be defined outside the main function to fix the issue.", "The implementation is incorrect because it does not replace all occurrences of spaces, commas, or dots with a colon as specified. The failed test case shows that the exclamation mark is not replaced, which indicates that the function does not handle other special characters besides spaces, commas, and dots."]} -{"name": "mbpp_141_pancake_sort", "language": "rs", "prompt": "/// Write a function to sort a vector of elements.\nfn pancake_sort(nums: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_141_pancake_sort.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "pancake_sort", "test": "}\n\nfn main() {\n let candidate = pancake_sort;\n assert_eq!(candidate(vec![15, 79, 25, 38, 69]), vec![15, 25, 38, 69, 79]);\n assert_eq!(candidate(vec![98, 12, 54, 36, 85]), vec![12, 36, 54, 85, 98]);\n assert_eq!(candidate(vec![41, 42, 32, 12, 23]), vec![12, 23, 32, 41, 42]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to sort a vector of elements.\nfn pancake_sort(nums: Vec) -> Vec {\n let mut nums = nums;\n let mut n = nums.len();\n\n while n > 1 {\n let mut max_idx = 0;\n\n for i in 1..n {\n if nums[i] > nums[max_idx] {\n max_idx = i;\n }\n }\n\n if max_idx != n - 1 {\n nums[0..=max_idx].reverse();\n nums[0..n].reverse();\n }\n\n n -= 1;\n }\n\n nums\n}"} -{"name": "mbpp_308_large_product", "language": "rs", "prompt": "/// Write a function to find the specified number of largest products from two given vectors, selecting one factor from each vector.\nfn large_product(nums1: Vec, nums2: Vec, N: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_308_large_product.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "large_product", "test": "}\n\nfn main() {\n let candidate = large_product;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6], vec![3, 6, 8, 9, 10, 6], 3), vec![60, 54, 50]);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6], vec![3, 6, 8, 9, 10, 6], 4), vec![60, 54, 50, 48]);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6], vec![3, 6, 8, 9, 10, 6], 5), vec![60, 54, 50, 48, 45]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the specified number of largest products from two given vectors, selecting one factor from each vector.\nfn large_product(nums1: Vec, nums2: Vec, N: isize) -> Vec {\n let mut products = Vec::new();\n\n for num1 in &nums1 {\n for num2 in &nums2 {\n products.push(num1 * num2);\n }\n }\n\n products.sort_unstable_by(|a, b| b.cmp(a));\n products.truncate(N as usize);\n\n products\n}"} -{"name": "mbpp_293_otherside_rightangle", "language": "rs", "prompt": "/// Write a function to find the third side of a right angled triangle.\nfn otherside_rightangle(w: isize, h: isize) -> f64 {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_293_otherside_rightangle.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "otherside_rightangle", "test": "}\n\nfn main() {\n let candidate = otherside_rightangle;\n assert_eq!(candidate(7, 8), 10.63014581273465);\n assert_eq!(candidate(3, 4), 5.0);\n assert_eq!(candidate(7, 15), 16.55294535724685);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the third side of a right angled triangle.\nfn otherside_rightangle(w: isize, h: isize) -> f64 {\n let w_squared = (w * w) as f64;\n let h_squared = (h * h) as f64;\n let other_side = (w_squared + h_squared).sqrt();\n other_side\n}"} -{"name": "mbpp_106_add_lists", "language": "rs", "prompt": "/// Write a function to append the given vector to the given tuples.\nfn add_lists(test_list: Vec, test_tup: (isize, isize)) -> (isize, isize, isize, isize, isize) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_106_add_lists.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "add_lists", "test": "}\n\nfn main() {\n let candidate = add_lists;\n assert_eq!(candidate(vec![5, 6, 7], (9, 10)), (9, 10, 5, 6, 7));\n assert_eq!(candidate(vec![6, 7, 8], (10, 11)), (10, 11, 6, 7, 8));\n assert_eq!(candidate(vec![7, 8, 9], (11, 12)), (11, 12, 7, 8, 9));\n}\n", "solution": "/// Write a function to append the given vector to the given tuples.\nfn add_lists(test_list: Vec, test_tup: (isize, isize)) -> (isize, isize, isize, isize, isize) {\n let (t1, t2) = test_tup;\n let mut result = (t1, t2, 0, 0, 0);\n\n for (i, item) in test_list.iter().enumerate() {\n if i < 3 {\n result = match i {\n 0 => (t1, t2, *item, result.3, result.4),\n 1 => (t1, t2, result.2, *item, result.4),\n 2 => (t1, t2, result.2, result.3, *item),\n _ => break,\n };\n } else {\n break;\n }\n }\n\n result\n}", "is_solved": true, "reflections": ["The implementation is wrong because it tries to assign a value to an invalid left-hand side expression. In Rust, tuple indexing with an expression like `result.2+i` is not allowed. Instead, the correct way to update the tuple elements is by using a match statement or creating a new tuple with the updated values."]} -{"name": "mbpp_720_add_dict_to_tuple", "language": "rs", "prompt": "use std::collections::HashMap;\n\n/// Write a function to add a HashMap to the tuple. The output should be a tuple.\nfn add_dict_to_tuple(test_tup: (isize, isize, isize), test_dict: HashMap) -> (isize, isize, isize, HashMap) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_720_add_dict_to_tuple.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "add_dict_to_tuple", "test": "}\n\nfn main() {\n let candidate = add_dict_to_tuple;\n assert_eq!(candidate((4, 5, 6), HashMap::from([(String::from(\"MSAM\"), 1), (String::from(\"is\"), 2), (String::from(\"best\"), 3)])), (4, 5, 6, HashMap::from([(String::from(\"MSAM\"), 1), (String::from(\"is\"), 2), (String::from(\"best\"), 3)])));\n assert_eq!(candidate((1, 2, 3), HashMap::from([(String::from(\"UTS\"), 2), (String::from(\"is\"), 3), (String::from(\"Worst\"), 4)])), (1, 2, 3, HashMap::from([(String::from(\"UTS\"), 2), (String::from(\"is\"), 3), (String::from(\"Worst\"), 4)])));\n assert_eq!(candidate((8, 9, 10), HashMap::from([(String::from(\"POS\"), 3), (String::from(\"is\"), 4), (String::from(\"Okay\"), 5)])), (8, 9, 10, HashMap::from([(String::from(\"POS\"), 3), (String::from(\"is\"), 4), (String::from(\"Okay\"), 5)])));\n}\n", "is_solved": true, "reflections": [], "solution": "use std::collections::HashMap;\n\n/// Write a function to add a HashMap to the tuple. The output should be a tuple.\nfn add_dict_to_tuple(test_tup: (isize, isize, isize), test_dict: HashMap) -> (isize, isize, isize, HashMap) {\n let (a, b, c) = test_tup;\n let result = (a, b, c, test_dict);\n result\n}"} -{"name": "mbpp_395_first_non_repeating_character", "language": "rs", "prompt": "/// Write a rsthon function to find the first non-repeated character in a given string.\nfn first_non_repeating_character(str1: String) -> Option {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_395_first_non_repeating_character.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "first_non_repeating_character", "test": "}\n\nfn main() {\n let candidate = first_non_repeating_character;\n assert_eq!(candidate(String::from(\"abcabc\")), None);\n assert_eq!(candidate(String::from(\"abc\")), Some(String::from(\"a\")));\n assert_eq!(candidate(String::from(\"ababc\")), Some(String::from(\"c\")));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the first non-repeated character in a given string.\nfn first_non_repeating_character(str1: String) -> Option {\n let mut char_count = std::collections::HashMap::new();\n\n for c in str1.chars() {\n let count = char_count.entry(c).or_insert(0);\n *count += 1;\n }\n\n for c in str1.chars() {\n if let Some(count) = char_count.get(&c) {\n if *count == 1 {\n return Some(c.to_string());\n }\n }\n }\n\n None\n}"} -{"name": "mbpp_9_find_Rotations", "language": "rs", "prompt": "/// Write a rsthon function to find the minimum number of rotations (greater than 0) required to get the same string.\nfn find_Rotations(str: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_9_find_Rotations.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_Rotations", "test": "}\n\nfn main() {\n let candidate = find_Rotations;\n assert_eq!(candidate(String::from(\"aaaa\")), 1);\n assert_eq!(candidate(String::from(\"ab\")), 2);\n assert_eq!(candidate(String::from(\"abc\")), 3);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the minimum number of rotations (greater than 0) required to get the same string.\nfn find_Rotations(str: String) -> isize {\n let len = str.len();\n let mut rotations = 1;\n let mut rotated_str = str.clone();\n\n while rotations <= len {\n rotated_str = format!(\"{}{}\", rotated_str.chars().last().unwrap(), &rotated_str[..len - 1]);\n\n if rotated_str == str {\n return rotations as isize;\n }\n\n rotations += 1;\n }\n\n -1\n}"} -{"name": "mbpp_792_count_list", "language": "rs", "prompt": "/// Write a rsthon function to count the number of vectors in a given number of vectors.\nfn count_list(input_list: Vec>) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_792_count_list.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_list", "test": "}\n\nfn main() {\n let candidate = count_list;\n assert_eq!(candidate(vec![vec![1, 3], vec![5, 7], vec![9, 11], vec![13, 15, 17]]), 4);\n assert_eq!(candidate(vec![vec![1, 2], vec![2, 3], vec![4, 5]]), 3);\n assert_eq!(candidate(vec![vec![1, 0], vec![2, 0]]), 2);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to count the number of vectors in a given number of vectors.\nfn count_list(input_list: Vec>) -> isize {\n let count = input_list.len() as isize;\n count\n}"} -{"name": "mbpp_477_is_lower", "language": "rs", "prompt": "/// Write a rsthon function to convert the given string to lower case.\nfn is_lower(string: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_477_is_lower.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_lower", "test": "}\n\nfn main() {\n let candidate = is_lower;\n assert_eq!(candidate(String::from(\"InValid\")), String::from(\"invalid\"));\n assert_eq!(candidate(String::from(\"TruE\")), String::from(\"true\"));\n assert_eq!(candidate(String::from(\"SenTenCE\")), String::from(\"sentence\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to convert the given string to lower case.\nfn is_lower(string: String) -> String {\n string.to_lowercase()\n}"} -{"name": "mbpp_422_find_Average_Of_Cube", "language": "rs", "prompt": "/// Write a rsthon function to find the average of cubes of first n natural numbers.\nfn find_Average_Of_Cube(n: isize) -> f64 {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_422_find_Average_Of_Cube.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_Average_Of_Cube", "test": "}\n\nfn main() {\n let candidate = find_Average_Of_Cube;\n assert_eq!(candidate(2), 4.5);\n assert_eq!(candidate(3), 12.0);\n assert_eq!(candidate(1), 1.0);\n}\n", "solution": "/// Write a rsthon function to find the average of cubes of first n natural numbers.\nfn find_Average_Of_Cube(n: isize) -> f64 {\n let mut sum: isize = 0;\n\n for i in 1..=n {\n sum += i.pow(3);\n }\n\n let average = sum as f64 / n as f64;\n average\n}", "is_solved": true, "reflections": ["The implementation of the find_Average_Of_Cube function is incorrect because it calculates the average of the sum of cubes of first n natural numbers, rather than the average of the cubes themselves. This leads to incorrect results for the failed test cases.", "The implementation of the find_Average_Of_Cube function is incorrect because it divides the sum of cubes by n twice, resulting in a wrong average calculation. The correct calculation should only divide the sum of cubes by n once.", "The implementation of the find_Average_Of_Cube function is incorrect because it calculates the average of the sum of cubes of first n natural numbers, rather than the average of the cubes themselves. This leads to incorrect results for the failed test cases.", "The implementation is incorrect because it calculates the average using the sum of the first n natural numbers instead of the total number of elements (n). The correct formula for average should be dividing the sum of cubes by n, not by (n * (n + 1) / 2)."]} -{"name": "mbpp_637_noprofit_noloss", "language": "rs", "prompt": "/// Write a function to check whether the given amount has no profit and no loss\nfn noprofit_noloss(actual_cost: isize, sale_amount: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_637_noprofit_noloss.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "noprofit_noloss", "test": "}\n\nfn main() {\n let candidate = noprofit_noloss;\n assert_eq!(candidate(1500, 1200), false);\n assert_eq!(candidate(100, 100), true);\n assert_eq!(candidate(2000, 5000), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check whether the given amount has no profit and no loss\nfn noprofit_noloss(actual_cost: isize, sale_amount: isize) -> bool {\n actual_cost == sale_amount\n}"} -{"name": "mbpp_557_toggle_string", "language": "rs", "prompt": "/// Write a function to toggle the case of all characters in a string.\nfn toggle_string(string: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_557_toggle_string.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "toggle_string", "test": "}\n\nfn main() {\n let candidate = toggle_string;\n assert_eq!(candidate(String::from(\"Python\")), String::from(\"pYTHON\"));\n assert_eq!(candidate(String::from(\"Pangram\")), String::from(\"pANGRAM\"));\n assert_eq!(candidate(String::from(\"LIttLE\")), String::from(\"liTTle\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to toggle the case of all characters in a string.\nfn toggle_string(string: String) -> String {\n string.chars()\n .map(|c| {\n if c.is_lowercase() {\n c.to_uppercase().collect::()\n } else {\n c.to_lowercase().collect::()\n }\n })\n .collect()\n}"} -{"name": "mbpp_786_right_insertion", "language": "rs", "prompt": "/// Write a function to locate the right insertion point for a specified value in sorted order.\nfn right_insertion(a: Vec, x: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_786_right_insertion.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "right_insertion", "test": "}\n\nfn main() {\n let candidate = right_insertion;\n assert_eq!(candidate(vec![1, 2, 4, 5], 6), 4);\n assert_eq!(candidate(vec![1, 2, 4, 5], 3), 2);\n assert_eq!(candidate(vec![1, 2, 4, 5], 7), 4);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to locate the right insertion point for a specified value in sorted order.\nfn right_insertion(a: Vec, x: isize) -> isize {\n let mut left = 0;\n let mut right = a.len();\n\n while left < right {\n let mid = left + (right - left) / 2;\n if x < a[mid] {\n right = mid;\n } else {\n left = mid + 1;\n }\n }\n\n left as isize\n}"} -{"name": "mbpp_807_first_odd", "language": "rs", "prompt": "/// Write a rsthon function to find the first odd number in a given vector of numbers.\nfn first_odd(nums: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_807_first_odd.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "first_odd", "test": "}\n\nfn main() {\n let candidate = first_odd;\n assert_eq!(candidate(vec![1, 3, 5]), 1);\n assert_eq!(candidate(vec![2, 4, 1, 3]), 1);\n assert_eq!(candidate(vec![8, 9, 1]), 9);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the first odd number in a given vector of numbers.\nfn first_odd(nums: Vec) -> isize {\n for num in nums {\n if num % 2 != 0 {\n return num;\n }\n }\n -1\n}"} -{"name": "mbpp_631_replace_spaces", "language": "rs", "prompt": "/// Write a function to replace whitespaces with an underscore and vice versa in a given string.\nfn replace_spaces(text: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_631_replace_spaces.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "replace_spaces", "test": "}\n\nfn main() {\n let candidate = replace_spaces;\n assert_eq!(candidate(String::from(\"Jumanji The Jungle\")), String::from(\"Jumanji_The_Jungle\"));\n assert_eq!(candidate(String::from(\"The_Avengers\")), String::from(\"The Avengers\"));\n assert_eq!(candidate(String::from(\"Fast and Furious\")), String::from(\"Fast_and_Furious\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to replace whitespaces with an underscore and vice versa in a given string.\nfn replace_spaces(text: String) -> String {\n text.chars()\n .map(|c| match c {\n ' ' => '_',\n '_' => ' ',\n _ => c,\n })\n .collect()\n}"} -{"name": "mbpp_573_unique_product", "language": "rs", "prompt": "/// Write a rsthon function to calculate the product of the unique numbers in a given vector.\nfn unique_product(list_data: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_573_unique_product.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "unique_product", "test": "}\n\nfn main() {\n let candidate = unique_product;\n assert_eq!(candidate(vec![10, 20, 30, 40, 20, 50, 60, 40]), 720000000);\n assert_eq!(candidate(vec![1, 2, 3, 1]), 6);\n assert_eq!(candidate(vec![7, 8, 9, 0, 1, 1]), 0);\n}\n", "solution": "/// Write a rsthon function to calculate the product of the unique numbers in a given vector.\nfn unique_product(list_data: Vec) -> isize {\n let unique_numbers: Vec = list_data.into_iter().collect::>().into_iter().collect();\n let mut product: isize = 1;\n let mut negative_count = 0;\n let mut max_negative = isize::MIN;\n\n for number in unique_numbers {\n if number < 0 {\n negative_count += 1;\n if number > max_negative {\n max_negative = number;\n }\n }\n product *= number;\n }\n\n if negative_count % 2 != 0 {\n product /= max_negative;\n }\n\n product\n}", "is_solved": true, "reflections": ["The implementation is incorrect because the `unique` method is not available for `std::vec::IntoIter`. This method is not part of the standard library, and thus cannot be used directly on the iterator.", "The implementation is incorrect because it calculates the product of unique numbers without considering the negative values properly. When there are an odd number of negative values, the product should be negative, but the current implementation returns a positive value.", "The implementation is incorrect because it does not handle the case where there are an odd number of negative values in the unique_numbers vector properly. Instead of removing one of the negative values before calculating the product, it just changes the sign of the final product, which leads to incorrect results.", "The implementation is incorrect because it does not handle the case where there are an odd number of negative values in the input vector properly. The code tries to remove the smallest negative value from the product when there is an odd number of negative values, but it should instead remove the largest negative value to maximize the product. This is why the test case `unique_product(vec![-2, 3, -4, 4])` fails, as the product should be 24, but the current implementation returns 96."]} -{"name": "mbpp_643_text_match_wordz_middle", "language": "rs", "prompt": "/// Write a function that checks if a strings contains 'z', except at the start and end of the word.\nfn text_match_wordz_middle(text: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_643_text_match_wordz_middle.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "text_match_wordz_middle", "test": "}\n\nfn main() {\n let candidate = text_match_wordz_middle;\n assert_eq!(candidate(String::from(\"pythonzabc.\")), true);\n assert_eq!(candidate(String::from(\"zxyabc.\")), false);\n assert_eq!(candidate(String::from(\" lang .\")), false);\n}\n", "solution": "/// Write a function that checks if a strings contains 'z', except at the start and end of the word.\nfn text_match_wordz_middle(text: String) -> bool {\n let chars = text.chars().collect::>();\n let len = chars.len();\n\n if len < 3 {\n return false;\n }\n\n for i in 1..len - 1 {\n if chars[i] == 'z' {\n return true;\n }\n }\n\n false\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it does not handle the case where the input string has a length of 3 and contains 'z' in the middle. The function returns false for strings with length less than or equal to 2, but it should also check for 'z' in the middle when the length is 3.", "The implementation of the text_match_wordz_middle function is incorrect because it does not properly handle cases where the input string has a 'z' in the middle but also has a 'z' at the beginning or end of the string. In such cases, the function returns false instead of true, as demonstrated by the failed test case with the input \"zoo\".", "The implementation of the text_match_wordz_middle function is incorrect because it does not properly handle cases where the 'z' character is at the second position of the string. The function only checks for 'z' in the middle of the string, but it should also consider 'z' at the second position as a valid case.", "The implementation of the text_match_wordz_middle function is incorrect because it does not properly handle the case when the 'z' is at the second position of the string. The function checks for 'z' in the middle of the string, but the additional condition to set found_z to true when chars[1] == 'z' is not necessary and causes the function to fail for cases like \"zoo\"."]} -{"name": "mbpp_299_max_aggregate", "language": "rs", "prompt": "/// Write a function to calculate the maximum aggregate from the vector of tuples.\nfn max_aggregate(stdata: Vec<(String, isize)>) -> (String, isize) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_299_max_aggregate.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_aggregate", "test": "}\n\nfn main() {\n let candidate = max_aggregate;\n assert_eq!(candidate(vec![(String::from(\"Juan Whelan\"), 90), (String::from(\"Sabah Colley\"), 88), (String::from(\"Peter Nichols\"), 7), (String::from(\"Juan Whelan\"), 122), (String::from(\"Sabah Colley\"), 84)]), (String::from(\"Juan Whelan\"), 212));\n assert_eq!(candidate(vec![(String::from(\"Juan Whelan\"), 50), (String::from(\"Sabah Colley\"), 48), (String::from(\"Peter Nichols\"), 37), (String::from(\"Juan Whelan\"), 22), (String::from(\"Sabah Colley\"), 14)]), (String::from(\"Juan Whelan\"), 72));\n assert_eq!(candidate(vec![(String::from(\"Juan Whelan\"), 10), (String::from(\"Sabah Colley\"), 20), (String::from(\"Peter Nichols\"), 30), (String::from(\"Juan Whelan\"), 40), (String::from(\"Sabah Colley\"), 50)]), (String::from(\"Sabah Colley\"), 70));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to calculate the maximum aggregate from the vector of tuples.\nfn max_aggregate(stdata: Vec<(String, isize)>) -> (String, isize) {\n let mut max_aggregate = (String::new(), isize::MIN);\n\n for data in stdata {\n if data.1 > max_aggregate.1 {\n max_aggregate = data;\n }\n }\n\n max_aggregate\n}"} -{"name": "mbpp_474_replace_char", "language": "rs", "prompt": "/// Write a function to replace characters in a string.\nfn replace_char(str1: String, ch: String, newch: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_474_replace_char.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "replace_char", "test": "}\n\nfn main() {\n let candidate = replace_char;\n assert_eq!(candidate(String::from(\"polygon\"), String::from(\"y\"), String::from(\"l\")), String::from(\"pollgon\"));\n assert_eq!(candidate(String::from(\"character\"), String::from(\"c\"), String::from(\"a\")), String::from(\"aharaater\"));\n assert_eq!(candidate(String::from(\"python\"), String::from(\"l\"), String::from(\"a\")), String::from(\"python\"));\n}\n", "solution": "/// Write a function to replace characters in a string.\nfn replace_char(str1: String, ch: String, newch: String) -> String {\n let mut new_str = String::new();\n\n for c in str1.chars() {\n if c.to_string() == ch {\n new_str.push_str(&newch);\n } else {\n new_str.push(c);\n }\n }\n\n new_str\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it only replaces the first occurrence of the character `ch` in the input string `str1`. The function should replace all occurrences of `ch` with `newch`. The failed test case demonstrates this issue, as it only replaces the first 'm' in \"programming\" instead of both 'm's.", "The implementation of the replace_char function is incorrect because it only replaces the first occurrence of the character 'ch' in the input string 'str1'. The failed test case demonstrates this issue, as it only replaces the first 'm' in \"programming\" instead of both occurrences.", "The implementation is wrong because it replaces all occurrences of the character `ch` with `newch`, instead of just the first occurrence. This causes the test with the input \"programming\" to fail, as both 'm's are replaced instead of just the first one.", "The implementation is incorrect because it only replaces the first occurrence of the character in the string. The function stops replacing characters after the first match due to the `replaced` variable. This causes the function to fail when there are multiple occurrences of the character to be replaced in the input string."]} -{"name": "mbpp_433_check_greater", "language": "rs", "prompt": "/// Write a function to check whether the entered number is greater than the elements of the given vector.\nfn check_greater(arr: Vec, number: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_433_check_greater.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "check_greater", "test": "}\n\nfn main() {\n let candidate = check_greater;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5], 4), false);\n assert_eq!(candidate(vec![2, 3, 4, 5, 6], 8), true);\n assert_eq!(candidate(vec![9, 7, 4, 8, 6, 1], 11), true);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check whether the entered number is greater than the elements of the given vector.\nfn check_greater(arr: Vec, number: isize) -> bool {\n for element in arr {\n if number <= element {\n return false;\n }\n }\n true\n}"} -{"name": "mbpp_427_change_date_format", "language": "rs", "prompt": "/// Write a function to convert a date of yyyy-mm-dd format to dd-mm-yyyy format.\nfn change_date_format(dt: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_427_change_date_format.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "change_date_format", "test": "}\n\nfn main() {\n let candidate = change_date_format;\n assert_eq!(candidate(String::from(\"2026-01-02\")), String::from(\"02-01-2026\"));\n assert_eq!(candidate(String::from(\"2020-11-13\")), String::from(\"13-11-2020\"));\n assert_eq!(candidate(String::from(\"2021-04-26\")), String::from(\"26-04-2021\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to convert a date of yyyy-mm-dd format to dd-mm-yyyy format.\nfn change_date_format(dt: String) -> String {\n let date_parts: Vec<&str> = dt.split('-').collect();\n format!(\"{}-{}-{}\", date_parts[2], date_parts[1], date_parts[0])\n}"} -{"name": "mbpp_442_positive_count", "language": "rs", "prompt": "/// Write a function to find the ration of positive numbers in a vector of integers.\nfn positive_count(nums: Vec) -> f64 {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_442_positive_count.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "positive_count", "test": "}\n\nfn main() {\n let candidate = positive_count;\n assert_eq!(candidate(vec![0, 1, 2, -1, -5, 6, 0, -3, -2, 3, 4, 6, 8]), 0.54);\n assert_eq!(candidate(vec![2, 1, 2, -1, -5, 6, 4, -3, -2, 3, 4, 6, 8]), 0.69);\n assert_eq!(candidate(vec![2, 4, -6, -9, 11, -12, 14, -5, 17]), 0.56);\n}\n", "solution": "/// Write a function to find the ration of positive numbers in a vector of integers.\nfn positive_count(nums: Vec) -> f64 {\n if nums.is_empty() {\n return 0.0;\n }\n\n let total_nums = nums.len() as f64;\n let mut positive_count = 0;\n\n for num in nums {\n if num > 0 {\n positive_count += 1;\n }\n }\n\n positive_count as f64 / total_nums\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it does not handle the case when the input vector is empty. Dividing by zero (total_nums) results in NaN, which causes the test to fail."]} -{"name": "mbpp_453_sumofFactors", "language": "rs", "prompt": "/// Write a rsthon function to find the sum of even factors of a number.\nfn sumofFactors(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_453_sumofFactors.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sumofFactors", "test": "}\n\nfn main() {\n let candidate = sumofFactors;\n assert_eq!(candidate(18), 26);\n assert_eq!(candidate(30), 48);\n assert_eq!(candidate(6), 8);\n}\n", "solution": "/// Write a rsthon function to find the sum of even factors of a number.\nfn sumofFactors(n: isize) -> isize {\n let mut sum = 0;\n\n for i in 1..=n {\n if n % i == 0 && i % 2 == 0 {\n sum += i;\n }\n }\n\n sum\n}", "is_solved": true, "reflections": ["The implementation of the sumofFactors function is incorrect because it does not properly calculate the sum of even factors for certain input values. The failed tests indicate that the function is not considering all the even factors of the input number, leading to incorrect results.", "The implementation of the sumofFactors function is incorrect because it does not properly handle cases where the number has multiple even factors. The loop only iterates up to the square root of the input number, which causes it to miss some even factors in certain cases, leading to incorrect results for the failed tests.", "The implementation of the sumofFactors function is incorrect because it iterates through all the factors of the given number 'n' and only adds the even factors to the sum. However, it does not consider the fact that the sum of even factors should also include the even factors of the odd factors of 'n'. This leads to incorrect results for some test cases, such as when 'n' is 6 or 15.", "The implementation of the sumofFactors function is incorrect because it is adding the even factors of the factors of the given number, instead of just adding the even factors of the given number itself. This causes the function to return incorrect results for some test cases, such as 6 and 15."]} -{"name": "mbpp_478_remove_lowercase", "language": "rs", "prompt": "/// Write a function to remove lowercase substrings from a given string.\nfn remove_lowercase(str1: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_478_remove_lowercase.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "remove_lowercase", "test": "}\n\nfn main() {\n let candidate = remove_lowercase;\n assert_eq!(candidate(String::from(\"PYTHon\")), String::from(\"PYTH\"));\n assert_eq!(candidate(String::from(\"FInD\")), String::from(\"FID\"));\n assert_eq!(candidate(String::from(\"STRinG\")), String::from(\"STRG\"));\n}\n", "solution": "/// Write a function to remove lowercase substrings from a given string.\nfn remove_lowercase(str1: String) -> String {\n let mut result = String::new();\n\n for c in str1.chars() {\n if c.is_uppercase() {\n result.push(c);\n }\n }\n\n result\n}", "is_solved": true, "reflections": ["The implementation of the remove_lowercase function is incorrect because it only removes lowercase characters and keeps uppercase characters. However, the failed test case expects the function to remove all characters that are part of a lowercase substring, not just the lowercase characters themselves. In the example \"RustGPT\", the function should remove the entire substring \"ust\" and not just the lowercase characters \"ust\", resulting in \"RGP\" instead of \"RGPT\".", "The implementation is wrong because it does not properly handle the removal of lowercase characters when they are followed by an uppercase character. The function only clears the `temp` string and pushes the uppercase character to the `result` string, but it does not remove the lowercase characters from the `result` string. This causes the function to fail in cases like \"RustGPT\", where the output should be \"RGP\" but it returns \"RGPT\" instead.", "The implementation is incorrect because it only removes lowercase characters and keeps uppercase characters. The task requires removing lowercase substrings, not individual lowercase characters. This is why the test \"RustGPT\" fails, as the function keeps the uppercase \"T\" instead of removing the entire \"ust\" substring.", "The implementation is wrong because it only removes lowercase characters that are immediately followed by an uppercase character. If a lowercase character is at the end of the string or followed by another lowercase character, it is not removed. This is why the test with input \"RustGPT\" fails, as the lowercase 't' is not removed from the output."]} -{"name": "mbpp_18_remove_dirty_chars", "language": "rs", "prompt": "/// Write a function to remove characters from the first string which are present in the second string.\nfn remove_dirty_chars(string: String, second_string: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_18_remove_dirty_chars.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "remove_dirty_chars", "test": "}\n\nfn main() {\n let candidate = remove_dirty_chars;\n assert_eq!(candidate(String::from(\"probasscurve\"), String::from(\"pros\")), String::from(\"bacuve\"));\n assert_eq!(candidate(String::from(\"digitalindia\"), String::from(\"talent\")), String::from(\"digiidi\"));\n assert_eq!(candidate(String::from(\"exoticmiles\"), String::from(\"toxic\")), String::from(\"emles\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to remove characters from the first string which are present in the second string.\nfn remove_dirty_chars(string: String, second_string: String) -> String {\n let mut clean_string = String::new();\n let second_string_chars: Vec = second_string.chars().collect();\n\n for c in string.chars() {\n if !second_string_chars.contains(&c) {\n clean_string.push(c);\n }\n }\n\n clean_string\n}"} -{"name": "mbpp_772_remove_length", "language": "rs", "prompt": "/// Write a function to remove all the words with k length in the given string.\nfn remove_length(test_str: String, K: isize) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_772_remove_length.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "remove_length", "test": "}\n\nfn main() {\n let candidate = remove_length;\n assert_eq!(candidate(String::from(\"The person is most value tet\"), 3), String::from(\"person is most value\"));\n assert_eq!(candidate(String::from(\"If you told me about this ok\"), 4), String::from(\"If you me about ok\"));\n assert_eq!(candidate(String::from(\"Forces of darkeness is come into the play\"), 4), String::from(\"Forces of darkeness is the\"));\n}\n", "solution": "/// Write a function to remove all the words with k length in the given string.\nfn remove_length(test_str: String, K: isize) -> String {\n let words: Vec<&str> = test_str.split_whitespace().collect();\n let filtered_words: Vec<&str> = words.into_iter().filter(|word| word.len() != K as usize).collect();\n filtered_words.join(\" \")\n}", "is_solved": true, "reflections": ["The implementation of the `remove_length` function is incorrect because it removes words with a length not equal to `K` instead of removing words with a length equal to `K`. This causes the function to return a string with the wrong words filtered out, leading to the failed test cases.", "The implementation of the `remove_length` function is incorrect because it filters out words whose length is not equal to `K`. This causes the function to keep words with the specified length `K` instead of removing them. The filter condition should be changed to `word.len() == K as usize` to correctly remove words with the specified length.", "The implementation of the `remove_length` function is incorrect because it filters out words whose length is not equal to `K`, instead of removing words with length equal to `K`. This causes the function to return a string with the wrong words removed, as demonstrated by the failed test cases.", "The implementation of the `remove_length` function is incorrect because it removes words with a length not equal to `K` instead of removing words with a length equal to `K`. This causes the function to return a string with the wrong words filtered out, leading to the failed test cases."]} -{"name": "mbpp_752_jacobsthal_num", "language": "rs", "prompt": "/// Write a function to find the nth jacobsthal number. https://www.geeksforgeeks.org/jacobsthal-and-jacobsthal-lucas-numbers/ 0, 1, 1, 3, 5, 11, 21, 43, 85, 171, 341, 683, 1365, 2731, ...\nfn jacobsthal_num(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_752_jacobsthal_num.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "jacobsthal_num", "test": "}\n\nfn main() {\n let candidate = jacobsthal_num;\n assert_eq!(candidate(5), 11);\n assert_eq!(candidate(2), 1);\n assert_eq!(candidate(4), 5);\n assert_eq!(candidate(13), 2731);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the nth jacobsthal number. https://www.geeksforgeeks.org/jacobsthal-and-jacobsthal-lucas-numbers/ 0, 1, 1, 3, 5, 11, 21, 43, 85, 171, 341, 683, 1365, 2731, ...\nfn jacobsthal_num(n: isize) -> isize {\n if n == 0 {\n return 0;\n } else if n == 1 {\n return 1;\n } else {\n return jacobsthal_num(n - 1) + 2 * jacobsthal_num(n - 2);\n }\n}"} -{"name": "mbpp_145_max_Abs_Diff", "language": "rs", "prompt": "/// Write a rsthon function to find the maximum difference between any two elements in a given vector.\nfn max_Abs_Diff(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_145_max_Abs_Diff.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_Abs_Diff", "test": "}\n\nfn main() {\n let candidate = max_Abs_Diff;\n assert_eq!(candidate(vec![2, 1, 5, 3]), 4);\n assert_eq!(candidate(vec![9, 3, 2, 5, 1]), 8);\n assert_eq!(candidate(vec![3, 2, 1]), 2);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the maximum difference between any two elements in a given vector.\nfn max_Abs_Diff(arr: Vec) -> isize {\n let mut max_diff = 0;\n let mut min_element = arr[0];\n let mut max_element = arr[0];\n\n for &num in arr.iter() {\n if num < min_element {\n min_element = num;\n } else if num > max_element {\n max_element = num;\n }\n }\n\n max_diff = max_element - min_element;\n max_diff\n}"} -{"name": "mbpp_572_two_unique_nums", "language": "rs", "prompt": "/// Write a rsthon function to remove duplicate numbers from a given number of vectors.\nfn two_unique_nums(nums: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_572_two_unique_nums.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "two_unique_nums", "test": "}\n\nfn main() {\n let candidate = two_unique_nums;\n assert_eq!(candidate(vec![1, 2, 3, 2, 3, 4, 5]), vec![1, 4, 5]);\n assert_eq!(candidate(vec![1, 2, 3, 2, 4, 5]), vec![1, 3, 4, 5]);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5]), vec![1, 2, 3, 4, 5]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to remove duplicate numbers from a given number of vectors.\nfn two_unique_nums(nums: Vec) -> Vec {\n let mut unique_nums = Vec::new();\n\n for num in nums {\n if !unique_nums.contains(&num) {\n unique_nums.push(num);\n }\n }\n\n unique_nums\n}"} -{"name": "mbpp_556_find_Odd_Pair", "language": "rs", "prompt": "/// Write a rsthon function to count the number of pairs whose xor value is odd.\nfn find_Odd_Pair(A: Vec, N: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_556_find_Odd_Pair.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_Odd_Pair", "test": "}\n\nfn main() {\n let candidate = find_Odd_Pair;\n assert_eq!(candidate(vec![5, 4, 7, 2, 1], 5), 6);\n assert_eq!(candidate(vec![7, 2, 8, 1, 0, 5, 11], 7), 12);\n assert_eq!(candidate(vec![1, 2, 3], 3), 2);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to count the number of pairs whose xor value is odd.\nfn find_Odd_Pair(A: Vec, N: isize) -> isize {\n let mut count = 0;\n\n for i in 0..(N as usize) {\n for j in (i + 1)..(N as usize) {\n if (A[i] ^ A[j]) % 2 != 0 {\n count += 1;\n }\n }\n }\n\n count\n}"} -{"name": "mbpp_306_max_sum_increasing_subseq", "language": "rs", "prompt": "/// Write a function to find the maximum sum of increasing subsequence from prefix until ith index and also including a given kth element which is after i, i.e., k > i .\nfn max_sum_increasing_subseq(a: Vec, n: isize, index: isize, k: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_306_max_sum_increasing_subseq.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_sum_increasing_subseq", "test": "}\n\nfn main() {\n let candidate = max_sum_increasing_subseq;\n assert_eq!(candidate(vec![1, 101, 2, 3, 100, 4, 5], 7, 4, 6), 11);\n assert_eq!(candidate(vec![1, 101, 2, 3, 100, 4, 5], 7, 2, 5), 7);\n assert_eq!(candidate(vec![11, 15, 19, 21, 26, 28, 31], 7, 2, 4), 71);\n}\n", "solution": "/// Write a function to find the maximum sum of increasing subsequence from prefix until ith index and also including a given kth element which is after i, i.e., k > i .\nfn max_sum_increasing_subseq(a: Vec, n: isize, index: isize, k: isize) -> isize {\n let mut dp = vec![0; n as usize];\n dp[0] = a[0];\n\n for i in 1..n as usize {\n dp[i] = a[i];\n for j in 0..i {\n if a[i] > a[j] {\n dp[i] = dp[i].max(dp[j] + a[i]);\n }\n }\n }\n\n let mut max_sum = 0;\n for i in 0..index as usize {\n if a[k as usize] > a[i] {\n max_sum = max_sum.max(dp[i]);\n }\n }\n\n // Include the kth element in the maximum sum\n max_sum += a[k as usize];\n\n // Recalculate the maximum sum of increasing subsequences after the kth element\n let mut dp_after_k = vec![0; (n - k) as usize];\n dp_after_k[0] = 0;\n\n for i in (k + 1) as usize..n as usize {\n dp_after_k[i - (k as usize)] = a[i];\n for j in (k as usize)..i {\n if a[i] > a[j] && a[j] > a[k as usize] {\n dp_after_k[i - (k as usize)] = dp_after_k[i - (k as usize)].max(dp_after_k[j - (k as usize)] + a[i]);\n }\n }\n }\n\n // Find the maximum sum of increasing subsequences after the kth element\n let mut max_sum_after_k = 0;\n for i in 0..(n - k) as usize {\n max_sum_after_k = max_sum_after_k.max(dp_after_k[i]);\n }\n\n // Check if there is a valid increasing subsequence after the kth element\n if max_sum_after_k > 0 {\n // Return the sum of the maximum sum of increasing subsequences before and after the kth element\n max_sum + max_sum_after_k\n } else {\n // If there is no valid increasing subsequence after the kth element, return the maximum sum of increasing subsequences before the kth element\n max_sum\n }\n}", "is_solved": true, "reflections": ["The current implementation is incorrect because it only finds the maximum sum of the increasing subsequence from the prefix until the ith index, but it does not ensure that the kth element is included in the subsequence. The function simply adds the kth element to the maximum sum found, which may not result in a valid increasing subsequence. This leads to incorrect results in the failed test cases.", "The current implementation is incorrect because it only considers the increasing subsequences from the prefix until the ith index and does not properly account for the inclusion of the kth element. The function calculates the maximum sum of increasing subsequences without considering the constraint that the kth element must be included in the final subsequence. This leads to incorrect results in the failed test cases.", "The implementation is incorrect because it calculates the maximum sum of increasing subsequences after the kth element separately and then adds it to the maximum sum before the kth element. This approach does not guarantee that the subsequences before and after the kth element are increasing. The function needs to be modified to ensure that the subsequences before and after the kth element are both increasing and include the kth element in the final sum.", "The current implementation is incorrect because it calculates the maximum sum of increasing subsequences before and after the kth element separately, but it does not ensure that the subsequences are continuous. This leads to incorrect results when the subsequences need to be combined to form a valid increasing subsequence that includes the kth element."]} -{"name": "mbpp_388_highest_Power_of_2", "language": "rs", "prompt": "/// Write a rsthon function to find the highest power of 2 that is less than or equal to n.\nfn highest_Power_of_2(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_388_highest_Power_of_2.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "highest_Power_of_2", "test": "}\n\nfn main() {\n let candidate = highest_Power_of_2;\n assert_eq!(candidate(10), 8);\n assert_eq!(candidate(19), 16);\n assert_eq!(candidate(32), 32);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the highest power of 2 that is less than or equal to n.\nfn highest_Power_of_2(n: isize) -> isize {\n let mut power = 1;\n while power * 2 <= n {\n power *= 2;\n }\n power\n}"} -{"name": "mbpp_401_add_nested_tuples", "language": "rs", "prompt": "/// Write a function to perform index wise addition of vector elements in the given two nested vectors.\nfn add_nested_tuples(test_tup1: Vec>, test_tup2: Vec>) -> Vec> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_401_add_nested_tuples.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "add_nested_tuples", "test": "}\n\nfn main() {\n let candidate = add_nested_tuples;\n assert_eq!(candidate(vec![vec![1, 3], vec![4, 5], vec![2, 9], vec![1, 10]], vec![vec![6, 7], vec![3, 9], vec![1, 1], vec![7, 3]]), vec![vec![7, 10], vec![7, 14], vec![3, 10], vec![8, 13]]);\n assert_eq!(candidate(vec![vec![2, 4], vec![5, 6], vec![3, 10], vec![2, 11]], vec![vec![7, 8], vec![4, 10], vec![2, 2], vec![8, 4]]), vec![vec![9, 12], vec![9, 16], vec![5, 12], vec![10, 15]]);\n assert_eq!(candidate(vec![vec![3, 5], vec![6, 7], vec![4, 11], vec![3, 12]], vec![vec![8, 9], vec![5, 11], vec![3, 3], vec![9, 5]]), vec![vec![11, 14], vec![11, 18], vec![7, 14], vec![12, 17]]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to perform index wise addition of vector elements in the given two nested vectors.\nfn add_nested_tuples(test_tup1: Vec>, test_tup2: Vec>) -> Vec> {\n let mut result: Vec> = Vec::new();\n\n for (i, inner_tup1) in test_tup1.iter().enumerate() {\n let mut inner_result: Vec = Vec::new();\n for (j, value) in inner_tup1.iter().enumerate() {\n inner_result.push(value + test_tup2[i][j]);\n }\n result.push(inner_result);\n }\n\n result\n}"} -{"name": "mbpp_435_last_Digit", "language": "rs", "prompt": "/// Write a rsthon function to find the last digit of a given number.\nfn last_Digit(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_435_last_Digit.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "last_Digit", "test": "}\n\nfn main() {\n let candidate = last_Digit;\n assert_eq!(candidate(123), 3);\n assert_eq!(candidate(25), 5);\n assert_eq!(candidate(30), 0);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the last digit of a given number.\nfn last_Digit(n: isize) -> isize {\n n.abs() % 10\n}"} -{"name": "mbpp_611_max_of_nth", "language": "rs", "prompt": "/// Write a function which given a matrix represented as a vector of vectors returns the max of the n'th column.\nfn max_of_nth(test_list: Vec>, N: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_611_max_of_nth.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_of_nth", "test": "}\n\nfn main() {\n let candidate = max_of_nth;\n assert_eq!(candidate(vec![vec![5, 6, 7], vec![1, 3, 5], vec![8, 9, 19]], 2), 19);\n assert_eq!(candidate(vec![vec![6, 7, 8], vec![2, 4, 6], vec![9, 10, 20]], 1), 10);\n assert_eq!(candidate(vec![vec![7, 8, 9], vec![3, 5, 7], vec![10, 11, 21]], 1), 11);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function which given a matrix represented as a vector of vectors returns the max of the n'th column.\nfn max_of_nth(test_list: Vec>, N: isize) -> isize {\n if test_list.is_empty() || N < 0 {\n return isize::MIN;\n }\n\n let mut max_value = isize::MIN;\n for row in test_list.iter() {\n if N as usize >= row.len() {\n continue;\n }\n if row[N as usize] > max_value {\n max_value = row[N as usize];\n }\n }\n\n max_value\n}"} -{"name": "mbpp_280_sequential_search", "language": "rs", "prompt": "/// Write a function that takes in a vector and element and returns a tuple containing a boolean that indicates if the element is in the vector and the index position of the element (or -1 if the element is not found).\nfn sequential_search(dlist: Vec, item: isize) -> (bool, isize) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_280_sequential_search.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sequential_search", "test": "}\n\nfn main() {\n let candidate = sequential_search;\n assert_eq!(candidate(vec![11, 23, 58, 31, 56, 77, 43, 12, 65, 19], 31), (true, 3));\n assert_eq!(candidate(vec![12, 32, 45, 62, 35, 47, 44, 61], 61), (true, 7));\n assert_eq!(candidate(vec![9, 10, 17, 19, 22, 39, 48, 56], 48), (true, 6));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function that takes in a vector and element and returns a tuple containing a boolean that indicates if the element is in the vector and the index position of the element (or -1 if the element is not found).\nfn sequential_search(dlist: Vec, item: isize) -> (bool, isize) {\n for (index, &element) in dlist.iter().enumerate() {\n if element == item {\n return (true, index as isize);\n }\n }\n (false, -1)\n}"} -{"name": "mbpp_576_is_Sub_Array", "language": "rs", "prompt": "/// Write a rsthon function to check whether a vector is subvector of another or not.\nfn is_Sub_Array(A: Vec, B: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_576_is_Sub_Array.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_Sub_Array", "test": "}\n\nfn main() {\n let candidate = is_Sub_Array;\n assert_eq!(candidate(vec![1, 4, 3, 5], vec![1, 2]), false);\n assert_eq!(candidate(vec![1, 2, 1], vec![1, 2, 1]), true);\n assert_eq!(candidate(vec![1, 0, 2, 2], vec![2, 2, 0]), false);\n}\n", "solution": "/// Write a rsthon function to check whether a vector is subvector of another or not.\nfn is_Sub_Array(A: Vec, B: Vec) -> bool {\n if A.len() < B.len() {\n return false;\n }\n\n for i in 0..=(A.len() - B.len()) {\n if A[i..i + B.len()] == B {\n return true;\n }\n }\n\n false\n}", "is_solved": true, "reflections": ["The current implementation is incorrect because it considers non-contiguous elements in the first vector (A) as a subarray of the second vector (B). The failed test case demonstrates this issue, as the function returns true for [1, 2, 3, 4] and [2, 4], even though [2, 4] is not a contiguous subarray of [1, 2, 3, 4]."]} -{"name": "mbpp_131_reverse_vowels", "language": "rs", "prompt": "/// Write a rsthon function to reverse only the vowels of a given string (where y is not a vowel).\nfn reverse_vowels(str1: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_131_reverse_vowels.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "reverse_vowels", "test": "}\n\nfn main() {\n let candidate = reverse_vowels;\n assert_eq!(candidate(String::from(\"Python\")), String::from(\"Python\"));\n assert_eq!(candidate(String::from(\"USA\")), String::from(\"ASU\"));\n assert_eq!(candidate(String::from(\"ab\")), String::from(\"ab\"));\n}\n", "solution": "/// Write a rsthon function to reverse only the vowels of a given string (where y is not a vowel).\nfn reverse_vowels(str1: String) -> String {\n let vowels = \"aeiouAEIOU\";\n let mut str_chars: Vec = str1.chars().collect();\n let mut i = 0;\n let mut j = str_chars.len() - 1;\n\n while i < j {\n if !vowels.contains(str_chars[i]) {\n i += 1;\n continue;\n }\n if !vowels.contains(str_chars[j]) {\n j -= 1;\n continue;\n }\n\n str_chars.swap(i, j);\n i += 1;\n j -= 1;\n }\n\n str_chars.into_iter().collect()\n}", "is_solved": true, "reflections": ["The implementation of the reverse_vowels function is incorrect because it does not handle the case where the input string contains uppercase vowels. The function only checks for lowercase vowels in the \"vowels\" variable, causing it to fail when encountering uppercase vowels.", "The implementation of the reverse_vowels function is incorrect because it does not properly handle cases where the input string contains uppercase vowels. The function only checks for lowercase vowels in the \"vowels\" variable, causing it to fail when encountering uppercase vowels. This issue is evident in the failed test case where the input string \"rust\" should return \"rast\", but the function returns the original string \"rust\" instead.", "The implementation of the reverse_vowels function is incorrect because it does not handle the case where the input string contains uppercase vowels. The function only checks for lowercase vowels in the \"vowels\" variable, causing it to fail when encountering uppercase vowels.", "The implementation of the reverse_vowels function is incorrect because it does not handle the case where the input string contains uppercase vowels. The function only checks for lowercase vowels in the \"vowels\" variable, causing it to fail when encountering uppercase vowels."]} -{"name": "mbpp_432_median_trapezium", "language": "rs", "prompt": "/// Write a function to find the median length of a trapezium.\nfn median_trapezium(base1: isize, base2: isize, height: isize) -> f64 {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_432_median_trapezium.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "median_trapezium", "test": "}\n\nfn main() {\n let candidate = median_trapezium;\n assert_eq!(candidate(15, 25, 35), 20.0);\n assert_eq!(candidate(10, 20, 30), 15.0);\n assert_eq!(candidate(6, 9, 4), 7.5);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the median length of a trapezium.\nfn median_trapezium(base1: isize, base2: isize, height: isize) -> f64 {\n let median = (base1 + base2) as f64 / 2.0;\n let area = median * height as f64;\n area / height as f64\n}"} -{"name": "mbpp_161_remove_elements", "language": "rs", "prompt": "/// Write a function to remove all elements from a given vector present in another vector.\nfn remove_elements(list1: Vec, list2: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_161_remove_elements.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "remove_elements", "test": "}\n\nfn main() {\n let candidate = remove_elements;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 10], vec![2, 4, 6, 8]), vec![1, 3, 5, 7, 9, 10]);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 10], vec![1, 3, 5, 7]), vec![2, 4, 6, 8, 9, 10]);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 10], vec![5, 7]), vec![1, 2, 3, 4, 6, 8, 9, 10]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to remove all elements from a given vector present in another vector.\nfn remove_elements(list1: Vec, list2: Vec) -> Vec {\n list1.into_iter().filter(|x| !list2.contains(x)).collect()\n}"} -{"name": "mbpp_597_find_kth", "language": "rs", "prompt": "/// Write a function to find kth element from the given two sorted vectors.\nfn find_kth(arr1: Vec, arr2: Vec, k: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_597_find_kth.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_kth", "test": "}\n\nfn main() {\n let candidate = find_kth;\n assert_eq!(candidate(vec![2, 3, 6, 7, 9], vec![1, 4, 8, 10], 5), 6);\n assert_eq!(candidate(vec![100, 112, 256, 349, 770], vec![72, 86, 113, 119, 265, 445, 892], 7), 256);\n assert_eq!(candidate(vec![3, 4, 7, 8, 10], vec![2, 5, 9, 11], 6), 8);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find kth element from the given two sorted vectors.\nfn find_kth(arr1: Vec, arr2: Vec, k: isize) -> isize {\n let mut i = 0;\n let mut j = 0;\n let mut count = 0;\n\n while i < arr1.len() && j < arr2.len() {\n if arr1[i] < arr2[j] {\n count += 1;\n if count == k {\n return arr1[i];\n }\n i += 1;\n } else {\n count += 1;\n if count == k {\n return arr2[j];\n }\n j += 1;\n }\n }\n\n while i < arr1.len() {\n count += 1;\n if count == k {\n return arr1[i];\n }\n i += 1;\n }\n\n while j < arr2.len() {\n count += 1;\n if count == k {\n return arr2[j];\n }\n j += 1;\n }\n\n panic!(\"k is out of bounds\");\n}"} -{"name": "mbpp_226_odd_values_string", "language": "rs", "prompt": "/// Write a rsthon function to remove the characters which have odd index values of a given string.\nfn odd_values_string(str: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_226_odd_values_string.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "odd_values_string", "test": "}\n\nfn main() {\n let candidate = odd_values_string;\n assert_eq!(candidate(String::from(\"abcdef\")), String::from(\"ace\"));\n assert_eq!(candidate(String::from(\"python\")), String::from(\"pto\"));\n assert_eq!(candidate(String::from(\"data\")), String::from(\"dt\"));\n assert_eq!(candidate(String::from(\"lambs\")), String::from(\"lms\"));\n}\n", "solution": "/// Write a rsthon function to remove the characters which have odd index values of a given string.\nfn odd_values_string(str: String) -> String {\n let mut result = String::new();\n\n for (index, character) in str.char_indices() {\n if index % 2 == 0 {\n result.push(character);\n }\n }\n\n result\n}", "is_solved": true, "reflections": ["The implementation of the odd_values_string function is incorrect because it removes characters with even index values instead of odd index values. The condition in the if statement should be `index % 2 != 0` to correctly remove characters with odd index values.", "The implementation of the `odd_values_string` function is incorrect because it removes characters with even index values instead of odd index values. The condition `index % 2 != 0` should be changed to `index % 2 == 0` to keep characters with even index values and remove characters with odd index values. This is why the failed tests have incorrect output, as the function is currently keeping the wrong characters.", "The implementation of the odd_values_string function is incorrect because it removes characters with even index values instead of odd index values. The condition in the if statement should be `index % 2 != 0` to correctly remove characters with odd index values.", "The implementation of the `odd_values_string` function is incorrect because it removes characters with even index values instead of odd index values. The condition `index % 2 != 0` should be changed to `index % 2 == 0` to keep characters with even index values and remove those with odd index values. This is why the failed tests have the opposite characters removed than expected."]} -{"name": "mbpp_269_ascii_value", "language": "rs", "prompt": "/// Write a function to find the ascii value of a character.\nfn ascii_value(k: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_269_ascii_value.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "ascii_value", "test": "}\n\nfn main() {\n let candidate = ascii_value;\n assert_eq!(candidate(String::from(\"A\")), 65);\n assert_eq!(candidate(String::from(\"R\")), 82);\n assert_eq!(candidate(String::from(\"S\")), 83);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the ascii value of a character.\nfn ascii_value(k: String) -> isize {\n let character = k.chars().next().unwrap_or('\\0');\n character as isize\n}"} -{"name": "mbpp_739_find_Index", "language": "rs", "prompt": "/// Write a rsthon function to find the index of smallest triangular number with n digits. https://www.geeksforgeeks.org/index-of-smallest-triangular-number-with-n-digits/\nfn find_Index(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_739_find_Index.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_Index", "test": "}\n\nfn main() {\n let candidate = find_Index;\n assert_eq!(candidate(2), 4);\n assert_eq!(candidate(3), 14);\n assert_eq!(candidate(4), 45);\n}\n", "solution": "/// Write a rsthon function to find the index of smallest triangular number with n digits. https://www.geeksforgeeks.org/index-of-smallest-triangular-number-with-n-digits/\nfn find_Index(n: isize) -> isize {\n let mut index = 1;\n let mut triangular_number = 1;\n let mut num_digits = 1;\n\n while num_digits < n {\n index += 1;\n triangular_number += index;\n num_digits = (triangular_number as f64).log10().floor() as isize + 1;\n }\n\n index\n}", "is_solved": true, "reflections": ["The implementation of the find_Index function is incorrect because it calculates the number of digits in the triangular number using logarithm, which may lead to inaccurate results due to floating-point rounding errors. This causes the function to return incorrect indices for the smallest triangular numbers with the given number of digits, as shown by the failed test cases.", "The implementation of the find_Index function is incorrect because it does not properly calculate the index of the smallest triangular number with n digits. The current logic only increments the index and triangular_number by 1 and checks the number of digits, which does not accurately represent the triangular number sequence. This leads to incorrect results for the given test cases.", "The implementation of the find_Index function is incorrect because it calculates the number of digits in the triangular number using logarithm, which may lead to inaccurate results due to floating-point rounding errors. This causes the function to return incorrect index values for the given number of digits, as shown by the failed test cases.", "The implementation of the find_Index function is incorrect because it does not properly calculate the index of the smallest triangular number with n digits. The current logic only increments the index and triangular_number by 1 and checks the number of digits, which leads to incorrect results for the given test cases. The algorithm needs to be revised to correctly calculate triangular numbers and find the smallest one with the desired number of digits."]} -{"name": "mbpp_19_test_duplicate", "language": "rs", "prompt": "/// Write a function to find whether a given vector of integers contains any duplicate element.\nfn test_duplicate(arraynums: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_19_test_duplicate.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "test_duplicate", "test": "}\n\nfn main() {\n let candidate = test_duplicate;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5]), false);\n assert_eq!(candidate(vec![1, 2, 3, 4, 4]), true);\n assert_eq!(candidate(vec![1, 1, 2, 2, 3, 3, 4, 4, 5]), true);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find whether a given vector of integers contains any duplicate element.\nfn test_duplicate(arraynums: Vec) -> bool {\n let mut nums_set = std::collections::HashSet::new();\n\n for num in arraynums {\n if nums_set.contains(&num) {\n return true;\n } else {\n nums_set.insert(num);\n }\n }\n\n false\n}"} -{"name": "mbpp_62_smallest_num", "language": "rs", "prompt": "/// Write a rsthon function to find smallest number in a vector.\nfn smallest_num(xs: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_62_smallest_num.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "smallest_num", "test": "}\n\nfn main() {\n let candidate = smallest_num;\n assert_eq!(candidate(vec![10, 20, 1, 45, 99]), 1);\n assert_eq!(candidate(vec![1, 2, 3]), 1);\n assert_eq!(candidate(vec![45, 46, 50, 60]), 45);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find smallest number in a vector.\nfn smallest_num(xs: Vec) -> isize {\n if xs.is_empty() {\n panic!(\"The input vector is empty\");\n }\n\n let mut smallest = xs[0];\n\n for &x in xs.iter() {\n if x < smallest {\n smallest = x;\n }\n }\n\n smallest\n}"} -{"name": "mbpp_746_sector_area", "language": "rs", "prompt": "/// Write a function to find area of a sector. The function takes the radius and angle as inputs. Function should return None if the angle is larger than 360 degrees.\nfn sector_area(r: isize, a: isize) -> Option {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_746_sector_area.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sector_area", "test": "}\n\nfn main() {\n let candidate = sector_area;\n assert_eq!(candidate(4, 45), Some(6.283185307179586));\n assert_eq!(candidate(9, 45), Some(31.808625617596654));\n assert_eq!(candidate(9, 361), None);\n}\n", "solution": "/// Write a function to find area of a sector. The function takes the radius and angle as inputs. Function should return None if the angle is larger than 360 degrees.\nfn sector_area(r: isize, a: isize) -> Option {\n if a > 360 {\n return None;\n }\n let angle_radians = (a as f64).to_radians();\n let proportion = angle_radians / (2.0 * std::f64::consts::PI);\n let area = (r as f64).powi(2) * std::f64::consts::PI * proportion;\n Some(area)\n}", "is_solved": true, "reflections": ["The implementation of the sector_area function is incorrect because it calculates the area using the angle in radians directly, without considering the proportion of the angle to a full circle (360 degrees). This leads to an overestimation of the sector area for angles smaller than 360 degrees.", "The implementation of the sector_area function is incorrect because it calculates the proportion of the circle using the angle in radians divided by 2 * PI, which is equivalent to the full circle in radians. This results in an incorrect area calculation for angles other than 360 degrees, as demonstrated by the failed test case.", "The implementation of the sector_area function is incorrect because it calculates the proportion of the circle using the angle in radians divided by 2 * PI, which is equivalent to the full circle in radians. This results in an incorrect area calculation for angles other than 360 degrees, as demonstrated by the failed test case.", "The implementation of the sector_area function is incorrect because it calculates the proportion of the circle using the angle in radians divided by 2 * PI, which is equivalent to the full circle in radians. This results in an incorrect area calculation for angles other than 360 degrees, as demonstrated by the failed test case."]} -{"name": "mbpp_142_count_samepair", "language": "rs", "prompt": "/// Write a function to count number items that are identical in the same position of three given vectors.\nfn count_samepair(list1: Vec, list2: Vec, list3: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_142_count_samepair.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_samepair", "test": "}\n\nfn main() {\n let candidate = count_samepair;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8], vec![2, 2, 3, 1, 2, 6, 7, 9], vec![2, 1, 3, 1, 2, 6, 7, 9]), 3);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8], vec![2, 2, 3, 1, 2, 6, 7, 8], vec![2, 1, 3, 1, 2, 6, 7, 8]), 4);\n assert_eq!(candidate(vec![1, 2, 3, 4, 2, 6, 7, 8], vec![2, 2, 3, 1, 2, 6, 7, 8], vec![2, 1, 3, 1, 2, 6, 7, 8]), 5);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to count number items that are identical in the same position of three given vectors.\nfn count_samepair(list1: Vec, list2: Vec, list3: Vec) -> isize {\n let mut count = 0;\n let min_length = list1.len().min(list2.len()).min(list3.len());\n\n for i in 0..min_length {\n if list1[i] == list2[i] && list2[i] == list3[i] {\n count += 1;\n }\n }\n\n count\n}"} -{"name": "mbpp_400_extract_freq", "language": "rs", "prompt": "/// Write a function to extract the number of unique tuples in the given vector.\nfn extract_freq(test_list: Vec<(isize, isize)>) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_400_extract_freq.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "extract_freq", "test": "}\n\nfn main() {\n let candidate = extract_freq;\n assert_eq!(candidate(vec![(3, 4), (1, 2), (4, 3), (5, 6)]), 3);\n assert_eq!(candidate(vec![(4, 15), (2, 3), (5, 4), (6, 7)]), 4);\n assert_eq!(candidate(vec![(5, 16), (2, 3), (6, 5), (6, 9)]), 4);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to extract the number of unique tuples in the given vector.\nfn extract_freq(test_list: Vec<(isize, isize)>) -> isize {\n let mut unique_tuples = std::collections::HashSet::new();\n\n for tuple in test_list {\n unique_tuples.insert(tuple);\n }\n\n unique_tuples.len() as isize\n}"} -{"name": "mbpp_135_hexagonal_num", "language": "rs", "prompt": "/// Write a function to find the nth hexagonal number.\nfn hexagonal_num(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_135_hexagonal_num.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "hexagonal_num", "test": "}\n\nfn main() {\n let candidate = hexagonal_num;\n assert_eq!(candidate(10), 190);\n assert_eq!(candidate(5), 45);\n assert_eq!(candidate(7), 91);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the nth hexagonal number.\nfn hexagonal_num(n: isize) -> isize {\n if n <= 0 {\n return 0;\n }\n n * (2 * n - 1)\n}"} -{"name": "mbpp_800_remove_all_spaces", "language": "rs", "prompt": "/// Write a function to remove all whitespaces from a string.\nfn remove_all_spaces(text: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_800_remove_all_spaces.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "remove_all_spaces", "test": "}\n\nfn main() {\n let candidate = remove_all_spaces;\n assert_eq!(candidate(String::from(\"python program\")), String::from(\"pythonprogram\"));\n assert_eq!(candidate(String::from(\"python programming language\")), String::from(\"pythonprogramminglanguage\"));\n assert_eq!(candidate(String::from(\"python program\")), String::from(\"pythonprogram\"));\n assert_eq!(candidate(String::from(\" python program\")), String::from(\"pythonprogram\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to remove all whitespaces from a string.\nfn remove_all_spaces(text: String) -> String {\n text.chars().filter(|c| !c.is_whitespace()).collect()\n}"} -{"name": "mbpp_127_multiply_int", "language": "rs", "prompt": "/// Write a function to multiply two integers.\nfn multiply_int(x: isize, y: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_127_multiply_int.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "multiply_int", "test": "}\n\nfn main() {\n let candidate = multiply_int;\n assert_eq!(candidate(10, 20), 200);\n assert_eq!(candidate(5, 10), 50);\n assert_eq!(candidate(4, 8), 32);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to multiply two integers.\nfn multiply_int(x: isize, y: isize) -> isize {\n x * y\n}"} -{"name": "mbpp_764_number_ctr", "language": "rs", "prompt": "/// Write a rsthon function to count number of digits in a given string.\nfn number_ctr(str: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_764_number_ctr.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "number_ctr", "test": "}\n\nfn main() {\n let candidate = number_ctr;\n assert_eq!(candidate(String::from(\"program2bedone\")), 1);\n assert_eq!(candidate(String::from(\"3wonders\")), 1);\n assert_eq!(candidate(String::from(\"123\")), 3);\n assert_eq!(candidate(String::from(\"3wond-1ers2\")), 3);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to count number of digits in a given string.\nfn number_ctr(str: String) -> isize {\n let mut count = 0;\n\n for c in str.chars() {\n if c.is_digit(10) {\n count += 1;\n }\n }\n\n count\n}"} -{"name": "mbpp_767_get_pairs_count", "language": "rs", "prompt": "/// Write a rsthon function to count the number of pairs whose sum is equal to ‘sum’. The funtion gets as input a vector of numbers and the sum,\nfn get_pairs_count(arr: Vec, sum: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_767_get_pairs_count.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "get_pairs_count", "test": "}\n\nfn main() {\n let candidate = get_pairs_count;\n assert_eq!(candidate(vec![1, 1, 1, 1], 2), 6);\n assert_eq!(candidate(vec![1, 5, 7, -1, 5], 6), 3);\n assert_eq!(candidate(vec![1, -2, 3], 1), 1);\n assert_eq!(candidate(vec![-1, -2, 3], -3), 1);\n}\n", "solution": "/// Write a rsthon function to count the number of pairs whose sum is equal to ‘sum’. The funtion gets as input a vector of numbers and the sum,\nfn get_pairs_count(arr: Vec, sum: isize) -> isize {\n let mut count = 0;\n let arr_len = arr.len();\n let mut seen = std::collections::HashMap::new();\n\n for i in 0..arr_len {\n let complement = sum - arr[i];\n if seen.contains_key(&complement) && seen[&complement] != i {\n count += 1;\n seen.remove(&complement);\n } else {\n seen.insert(arr[i], i);\n }\n }\n\n count\n}", "is_solved": true, "reflections": ["The implementation of the get_pairs_count function is incorrect because it only counts distinct pairs of elements whose sum is equal to the given 'sum'. However, it fails to handle cases where the same element can be used multiple times in different pairs to achieve the desired sum. This issue is evident in the failed test case, where the function should have counted two pairs (10, 1) and (-1, 12), but it only counted one pair.", "The implementation is incorrect because it counts the pairs only when the complement is already in the seen HashMap. This causes the function to miss some valid pairs when the complement appears later in the array.", "The implementation is incorrect because it unnecessarily iterates through the array twice, causing the count to be updated incorrectly. The second loop is decrementing the count and adding it back, which leads to incorrect results. The function should only iterate once through the array and update the count accordingly.", "The implementation is incorrect because it counts the pairs with the same elements twice. The function should only count distinct pairs, but it currently counts the same pair multiple times when the complement is equal to the current element in the array."]} -{"name": "mbpp_99_decimal_to_binary", "language": "rs", "prompt": "/// Write a function to convert the given decimal number to its binary equivalent, represented as a string with no leading zeros.\nfn decimal_to_binary(n: isize) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_99_decimal_to_binary.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "decimal_to_binary", "test": "}\n\nfn main() {\n let candidate = decimal_to_binary;\n assert_eq!(candidate(8), String::from(\"1000\"));\n assert_eq!(candidate(18), String::from(\"10010\"));\n assert_eq!(candidate(7), String::from(\"111\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to convert the given decimal number to its binary equivalent, represented as a string with no leading zeros.\nfn decimal_to_binary(n: isize) -> String {\n let mut binary = String::new();\n let mut num = n;\n\n if num == 0 {\n return \"0\".to_string();\n }\n\n while num > 0 {\n let remainder = num % 2;\n binary.insert(0, char::from_digit(remainder as u32, 10).unwrap());\n num /= 2;\n }\n\n binary\n}"} -{"name": "mbpp_119_search", "language": "rs", "prompt": "/// Write a rsthon function to find the element that appears only once in a sorted vector.\nfn search(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_119_search.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "search", "test": "}\n\nfn main() {\n let candidate = search;\n assert_eq!(candidate(vec![1, 1, 2, 2, 3]), 3);\n assert_eq!(candidate(vec![1, 1, 3, 3, 4, 4, 5, 5, 7, 7, 8]), 8);\n assert_eq!(candidate(vec![1, 2, 2, 3, 3, 4, 4]), 1);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the element that appears only once in a sorted vector.\nfn search(arr: Vec) -> isize {\n let mut i = 0;\n\n while i < arr.len() {\n if i == arr.len() - 1 || arr[i] != arr[i + 1] {\n return arr[i];\n }\n i += 2;\n }\n\n -1\n}"} -{"name": "mbpp_92_is_undulating", "language": "rs", "prompt": "/// Write a function to check whether the given number is undulating or not.\nfn is_undulating(n: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_92_is_undulating.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_undulating", "test": "}\n\nfn main() {\n let candidate = is_undulating;\n assert_eq!(candidate(1212121), true);\n assert_eq!(candidate(1991), false);\n assert_eq!(candidate(121), true);\n}\n", "solution": "/// Write a function to check whether the given number is undulating or not.\nfn is_undulating(n: isize) -> bool {\n if n < 100 {\n return false;\n }\n\n let digits: Vec<_> = n.to_string().chars().map(|c| c.to_digit(10).unwrap()).collect();\n let first_digit = digits[0];\n let second_digit = digits[1];\n\n if first_digit == second_digit {\n return false;\n }\n\n let mut valid_pattern = true;\n\n for i in (0..digits.len()).step_by(2) {\n if digits[i] != first_digit {\n valid_pattern = false;\n break;\n }\n }\n\n if valid_pattern {\n for i in (1..digits.len()).step_by(2) {\n if digits[i] != second_digit {\n return false;\n }\n }\n } else {\n valid_pattern = true;\n for i in (0..digits.len()).step_by(2) {\n if digits[i] != second_digit {\n valid_pattern = false;\n break;\n }\n }\n\n if valid_pattern {\n for i in (1..digits.len()).step_by(2) {\n if digits[i] != first_digit {\n return false;\n }\n }\n } else {\n return false;\n }\n }\n\n true\n}", "is_solved": true, "reflections": ["The implementation of the is_undulating function is incorrect because it checks if the first and second digits are equal and returns false if they are. This condition is not necessary for undulating numbers, as undulating numbers only require alternating digits. This causes the function to return false for valid undulating numbers like 121 and 373.", "The implementation of the `is_undulating` function is incorrect because it only checks if the odd and even indexed digits are equal to the first and second digits, respectively. It does not ensure that the first and second digits are different, which is a requirement for a number to be undulating. This causes the function to return false for valid undulating numbers like 121 and 373.", "The implementation of the is_undulating function is incorrect because it checks for alternating digits starting from the first and second digits, but it does not account for the possibility of the undulating pattern starting from the second and third digits. This causes the function to return false for valid undulating numbers like 121 and 373.", "The implementation is incorrect because it checks for the first digit's pattern in both odd and even positions, but it doesn't properly check for the second digit's pattern. As a result, the function returns false for valid undulating numbers like 121 and 373, where the second digit's pattern should be checked."]} -{"name": "mbpp_105_count", "language": "rs", "prompt": "/// Write a rsthon function to count true booleans in the given vector.\nfn count(lst: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_105_count.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count", "test": "}\n\nfn main() {\n let candidate = count;\n assert_eq!(candidate(vec![true, false, true]), 2);\n assert_eq!(candidate(vec![false, false]), 0);\n assert_eq!(candidate(vec![true, true, true]), 3);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to count true booleans in the given vector.\nfn count(lst: Vec) -> isize {\n let mut count = 0;\n for value in lst {\n if value {\n count += 1;\n }\n }\n count as isize\n}"} -{"name": "mbpp_766_pair_wise", "language": "rs", "prompt": "/// Write a function to return a vector of all pairs of consecutive items in a given vector.\nfn pair_wise(l1: Vec) -> Vec<(isize, isize)> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_766_pair_wise.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "pair_wise", "test": "}\n\nfn main() {\n let candidate = pair_wise;\n assert_eq!(candidate(vec![1, 1, 2, 3, 3, 4, 4, 5]), vec![(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]);\n assert_eq!(candidate(vec![1, 5, 7, 9, 10]), vec![(1, 5), (5, 7), (7, 9), (9, 10)]);\n assert_eq!(candidate(vec![5, 1, 9, 7, 10]), vec![(5, 1), (1, 9), (9, 7), (7, 10)]);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 10]), vec![(1, 2), (2, 3), (3, 4), (4, 5), (5, 6), (6, 7), (7, 8), (8, 9), (9, 10)]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to return a vector of all pairs of consecutive items in a given vector.\nfn pair_wise(l1: Vec) -> Vec<(isize, isize)> {\n let mut result = Vec::new();\n\n for i in 0..l1.len() - 1 {\n result.push((l1[i], l1[i + 1]));\n }\n\n result\n}"} -{"name": "mbpp_464_check_value", "language": "rs", "prompt": "use std::collections::HashMap;\n\n/// Write a function to check if all values are same in a HashMap.\nfn check_value(dict: HashMap, n: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_464_check_value.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "check_value", "test": "}\n\nfn main() {\n let candidate = check_value;\n assert_eq!(candidate(HashMap::from([(String::from(\"Cierra Vega\"), 12), (String::from(\"Alden Cantrell\"), 12), (String::from(\"Kierra Gentry\"), 12), (String::from(\"Pierre Cox\"), 12)]), 10), false);\n assert_eq!(candidate(HashMap::from([(String::from(\"Cierra Vega\"), 12), (String::from(\"Alden Cantrell\"), 12), (String::from(\"Kierra Gentry\"), 12), (String::from(\"Pierre Cox\"), 12)]), 12), true);\n assert_eq!(candidate(HashMap::from([(String::from(\"Cierra Vega\"), 12), (String::from(\"Alden Cantrell\"), 12), (String::from(\"Kierra Gentry\"), 12), (String::from(\"Pierre Cox\"), 12)]), 5), false);\n}\n", "is_solved": true, "reflections": [], "solution": "use std::collections::HashMap;\n\n/// Write a function to check if all values are same in a HashMap.\nfn check_value(dict: HashMap, n: isize) -> bool {\n for value in dict.values() {\n if *value != n {\n return false;\n }\n }\n true\n}"} -{"name": "mbpp_443_largest_neg", "language": "rs", "prompt": "/// Write a rsthon function to find the largest negative number from the given vector.\nfn largest_neg(list1: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_443_largest_neg.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "largest_neg", "test": "}\n\nfn main() {\n let candidate = largest_neg;\n assert_eq!(candidate(vec![1, 2, 3, -4, -6]), -6);\n assert_eq!(candidate(vec![1, 2, 3, -8, -9]), -9);\n assert_eq!(candidate(vec![1, 2, 3, 4, -1]), -1);\n}\n", "solution": "/// Write a rsthon function to find the largest negative number from the given vector.\nfn largest_neg(list1: Vec) -> isize {\n let mut largest_negative = None;\n\n for num in list1 {\n if num < 0 {\n match largest_negative {\n None => largest_negative = Some(num),\n Some(largest) => {\n if num > largest {\n largest_negative = Some(num);\n }\n }\n }\n }\n }\n\n match largest_negative {\n None => 0,\n Some(largest) => largest,\n }\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it initializes the `largest_negative` variable with the minimum value of `isize` (isize::MIN). When the input vector contains no negative numbers, the function returns this minimum value instead of 0, which is the expected output when there are no negative numbers in the input vector."]} -{"name": "mbpp_602_first_repeated_char", "language": "rs", "prompt": "/// Write a rsthon function to find the first repeated character in a given string.\nfn first_repeated_char(str1: String) -> Option {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_602_first_repeated_char.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "first_repeated_char", "test": "}\n\nfn main() {\n let candidate = first_repeated_char;\n assert_eq!(candidate(String::from(\"abcabc\")), Some(String::from(\"a\")));\n assert_eq!(candidate(String::from(\"abc\")), None);\n assert_eq!(candidate(String::from(\"123123\")), Some(String::from(\"1\")));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the first repeated character in a given string.\nfn first_repeated_char(str1: String) -> Option {\n let mut char_set = std::collections::HashSet::new();\n\n for c in str1.chars() {\n if char_set.contains(&c) {\n return Some(c.to_string());\n } else {\n char_set.insert(c);\n }\n }\n\n None\n}"} -{"name": "mbpp_770_odd_num_sum", "language": "rs", "prompt": "/// Write a rsthon function to find the sum of fourth power of first n odd natural numbers.\nfn odd_num_sum(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_770_odd_num_sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "odd_num_sum", "test": "}\n\nfn main() {\n let candidate = odd_num_sum;\n assert_eq!(candidate(2), 82);\n assert_eq!(candidate(3), 707);\n assert_eq!(candidate(4), 3108);\n}\n", "solution": "/// Write a rsthon function to find the sum of fourth power of first n odd natural numbers.\nfn odd_num_sum(n: isize) -> isize {\n let mut sum = 0;\n let mut count = 0;\n let mut num: i32 = 1;\n\n while count < n {\n let odd_num = 2 * count + 1;\n sum += odd_num.pow(4) as isize;\n count += 1;\n num += 2;\n }\n\n sum\n}", "is_solved": true, "reflections": ["The implementation is wrong because the numeric type of the variable `num` is ambiguous. The Rust compiler cannot determine the specific numeric type to use for the `pow` method. To fix this issue, a specific numeric type, such as `i32`, should be specified for the `num` variable.", "The implementation of the odd_num_sum function is incorrect because it starts with the first odd number (1) and adds the fourth power of the next odd number (3) without considering the first n odd numbers. Instead, it keeps adding the fourth power of odd numbers until the count reaches n. This results in an incorrect sum as it doesn't account for the first n odd numbers' fourth powers.", "The implementation of the odd_num_sum function is incorrect because it starts with the first odd number (1) and adds its fourth power to the sum, then increments the number by 2, effectively skipping even numbers. However, it does not account for the fact that it should only add the fourth power of the first n odd numbers. Instead, it adds the fourth power of consecutive odd numbers, leading to incorrect results for the given test cases.", "The implementation of the odd_num_sum function is incorrect because it starts with the first odd number (1) and adds the fourth power of the next odd number (3) without considering the actual position of the odd number in the sequence. This causes the sum to be higher than expected, as it includes extra odd numbers in the calculation."]} -{"name": "mbpp_424_extract_rear", "language": "rs", "prompt": "/// Write a function to extract only the rear index element of each string in the given tuple.\nfn extract_rear(test_tuple: (String, String, String)) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_424_extract_rear.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "extract_rear", "test": "}\n\nfn main() {\n let candidate = extract_rear;\n assert_eq!(candidate((String::from(\"Mers\"), String::from(\"for\"), String::from(\"Vers\"))), vec![String::from(\"s\"), String::from(\"r\"), String::from(\"s\")]);\n assert_eq!(candidate((String::from(\"Avenge\"), String::from(\"for\"), String::from(\"People\"))), vec![String::from(\"e\"), String::from(\"r\"), String::from(\"e\")]);\n assert_eq!(candidate((String::from(\"Gotta\"), String::from(\"get\"), String::from(\"go\"))), vec![String::from(\"a\"), String::from(\"t\"), String::from(\"o\")]);\n}\n", "solution": "/// Write a function to extract only the rear index element of each string in the given tuple.\nfn extract_rear(test_tuple: (String, String, String)) -> Vec {\n let mut result = Vec::new();\n\n for s in &[test_tuple.0, test_tuple.1, test_tuple.2] {\n if let Some(rear) = s.chars().last() {\n result.push(rear.to_string());\n }\n }\n\n result\n}", "is_solved": true, "reflections": ["The implementation is wrong because it tries to use a tuple as an iterator in the for loop, but tuples do not implement the `Iterator` trait. This causes the error, as the for loop expects an iterable object."]} -{"name": "mbpp_133_sum_negativenum", "language": "rs", "prompt": "/// Write a function to calculate the sum of the negative numbers of a given vector of numbers.\nfn sum_negativenum(nums: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_133_sum_negativenum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sum_negativenum", "test": "}\n\nfn main() {\n let candidate = sum_negativenum;\n assert_eq!(candidate(vec![2, 4, -6, -9, 11, -12, 14, -5, 17]), -32);\n assert_eq!(candidate(vec![10, 15, -14, 13, -18, 12, -20]), -52);\n assert_eq!(candidate(vec![19, -65, 57, 39, 152, -639, 121, 44, 90, -190]), -894);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to calculate the sum of the negative numbers of a given vector of numbers.\nfn sum_negativenum(nums: Vec) -> isize {\n let mut sum = 0;\n for num in nums {\n if num < 0 {\n sum += num;\n }\n }\n sum\n}"} -{"name": "mbpp_760_unique_Element", "language": "rs", "prompt": "/// Write a rsthon function to check whether a vector of numbers contains only one distinct element or not.\nfn unique_Element(arr: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_760_unique_Element.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "unique_Element", "test": "}\n\nfn main() {\n let candidate = unique_Element;\n assert_eq!(candidate(vec![1, 1, 1]), true);\n assert_eq!(candidate(vec![1, 2, 1, 2]), false);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5]), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to check whether a vector of numbers contains only one distinct element or not.\nfn unique_Element(arr: Vec) -> bool {\n if arr.is_empty() {\n return false;\n }\n\n let first_element = arr[0];\n for element in arr {\n if element != first_element {\n return false;\n }\n }\n\n true\n}"} -{"name": "mbpp_281_all_unique", "language": "rs", "prompt": "/// Write a rsthon function to check if the elements of a given vector are unique or not.\nfn all_unique(test_list: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_281_all_unique.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "all_unique", "test": "}\n\nfn main() {\n let candidate = all_unique;\n assert_eq!(candidate(vec![1, 2, 3]), true);\n assert_eq!(candidate(vec![1, 2, 1, 2]), false);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5]), true);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to check if the elements of a given vector are unique or not.\nfn all_unique(test_list: Vec) -> bool {\n let mut seen = std::collections::HashSet::new();\n\n for &value in test_list.iter() {\n if seen.contains(&value) {\n return false;\n } else {\n seen.insert(value);\n }\n }\n\n true\n}"} -{"name": "mbpp_406_find_Parity", "language": "rs", "prompt": "/// Write a rsthon function to find whether the parity of a given number is odd.\nfn find_Parity(x: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_406_find_Parity.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_Parity", "test": "}\n\nfn main() {\n let candidate = find_Parity;\n assert_eq!(candidate(12), false);\n assert_eq!(candidate(7), true);\n assert_eq!(candidate(10), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find whether the parity of a given number is odd.\nfn find_Parity(x: isize) -> bool {\n if x % 2 == 0 {\n return false;\n } else {\n return true;\n }\n}"} -{"name": "mbpp_562_Find_Max_Length", "language": "rs", "prompt": "/// Write a rsthon function to find the length of the longest subvectors.\nfn Find_Max_Length(lst: Vec>) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_562_Find_Max_Length.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "Find_Max_Length", "test": "}\n\nfn main() {\n let candidate = Find_Max_Length;\n assert_eq!(candidate(vec![vec![1], vec![1, 4], vec![5, 6, 7, 8]]), 4);\n assert_eq!(candidate(vec![vec![0, 1], vec![2, 2], vec![3, 2, 1]]), 3);\n assert_eq!(candidate(vec![vec![7], vec![22, 23], vec![13, 14, 15], vec![10, 20, 30, 40, 50]]), 5);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the length of the longest subvectors.\nfn Find_Max_Length(lst: Vec>) -> isize {\n let mut max_length = 0;\n\n for subvector in lst {\n let length = subvector.len();\n if length > max_length {\n max_length = length;\n }\n }\n\n max_length as isize\n}"} -{"name": "mbpp_87_merge_dictionaries_three", "language": "rs", "prompt": "use std::collections::HashMap;\n\n/// Write a function to merge three dictionaries into a single HashMap.\nfn merge_dictionaries_three(dict1: HashMap, dict2: HashMap, dict3: HashMap) -> HashMap {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_87_merge_dictionaries_three.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "merge_dictionaries_three", "test": "}\n\nfn main() {\n let candidate = merge_dictionaries_three;\n assert_eq!(candidate(HashMap::from([(String::from(\"R\"), String::from(\"Red\")), (String::from(\"B\"), String::from(\"Black\")), (String::from(\"P\"), String::from(\"Pink\"))]), HashMap::from([(String::from(\"G\"), String::from(\"Green\")), (String::from(\"W\"), String::from(\"White\"))]), HashMap::from([(String::from(\"O\"), String::from(\"Orange\")), (String::from(\"W\"), String::from(\"White\")), (String::from(\"B\"), String::from(\"Black\"))])), HashMap::from([(String::from(\"B\"), String::from(\"Black\")), (String::from(\"R\"), String::from(\"Red\")), (String::from(\"P\"), String::from(\"Pink\")), (String::from(\"G\"), String::from(\"Green\")), (String::from(\"W\"), String::from(\"White\")), (String::from(\"O\"), String::from(\"Orange\"))]));\n assert_eq!(candidate(HashMap::from([(String::from(\"R\"), String::from(\"Red\")), (String::from(\"B\"), String::from(\"Black\")), (String::from(\"P\"), String::from(\"Pink\"))]), HashMap::from([(String::from(\"G\"), String::from(\"Green\")), (String::from(\"W\"), String::from(\"White\"))]), HashMap::from([(String::from(\"L\"), String::from(\"lavender\")), (String::from(\"B\"), String::from(\"Blue\"))])), HashMap::from([(String::from(\"W\"), String::from(\"White\")), (String::from(\"P\"), String::from(\"Pink\")), (String::from(\"B\"), String::from(\"Black\")), (String::from(\"R\"), String::from(\"Red\")), (String::from(\"G\"), String::from(\"Green\")), (String::from(\"L\"), String::from(\"lavender\"))]));\n assert_eq!(candidate(HashMap::from([(String::from(\"R\"), String::from(\"Red\")), (String::from(\"B\"), String::from(\"Black\")), (String::from(\"P\"), String::from(\"Pink\"))]), HashMap::from([(String::from(\"L\"), String::from(\"lavender\")), (String::from(\"B\"), String::from(\"Blue\"))]), HashMap::from([(String::from(\"G\"), String::from(\"Green\")), (String::from(\"W\"), String::from(\"White\"))])), HashMap::from([(String::from(\"B\"), String::from(\"Black\")), (String::from(\"P\"), String::from(\"Pink\")), (String::from(\"R\"), String::from(\"Red\")), (String::from(\"G\"), String::from(\"Green\")), (String::from(\"L\"), String::from(\"lavender\")), (String::from(\"W\"), String::from(\"White\"))]));\n}\n", "is_solved": true, "reflections": [], "solution": "use std::collections::HashMap;\n\n/// Write a function to merge three dictionaries into a single HashMap.\nfn merge_dictionaries_three(dict1: HashMap, dict2: HashMap, dict3: HashMap) -> HashMap {\n let mut result = HashMap::new();\n\n for (key, value) in dict1 {\n result.insert(key, value);\n }\n\n for (key, value) in dict2 {\n result.insert(key, value);\n }\n\n for (key, value) in dict3 {\n result.insert(key, value);\n }\n\n result\n}"} -{"name": "mbpp_11_remove_Occ", "language": "rs", "prompt": "/// Write a rsthon function to remove first and last occurrence of a given character from the string.\nfn remove_Occ(s: String, ch: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_11_remove_Occ.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "remove_Occ", "test": "}\n\nfn main() {\n let candidate = remove_Occ;\n assert_eq!(candidate(String::from(\"hello\"), String::from(\"l\")), String::from(\"heo\"));\n assert_eq!(candidate(String::from(\"abcda\"), String::from(\"a\")), String::from(\"bcd\"));\n assert_eq!(candidate(String::from(\"PHP\"), String::from(\"P\")), String::from(\"H\"));\n}\n", "solution": "/// Write a rsthon function to remove first and last occurrence of a given character from the string.\nfn remove_Occ(s: String, ch: String) -> String {\n let first_occurrence = s.find(&ch);\n let last_occurrence = s.rfind(&ch);\n\n if let (Some(first), Some(last)) = (first_occurrence, last_occurrence) {\n let mut chars: Vec = s.chars().collect();\n chars.remove(first);\n if first != last {\n chars.remove(last - 1);\n }\n chars.into_iter().collect()\n } else {\n s\n }\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it does not properly handle the removal of the last occurrence when the character appears more than once. When removing the last occurrence, it subtracts 1 from the index, which causes it to remove the character before the actual last occurrence. This leads to incorrect results in the failed test cases.", "The implementation is incorrect because it does not properly handle the removal of the last occurrence when it comes after the first occurrence. The code subtracts 1 from the last occurrence index when removing the character, which causes it to remove the wrong character in some cases.", "The implementation is incorrect because it does not properly handle cases where the character to be removed appears more than twice in the string. When removing the last occurrence, it does not account for the fact that the index has shifted due to the removal of the first occurrence, causing it to remove the wrong character.", "The implementation is incorrect because it only removes the first occurrence and the character before the last occurrence, instead of removing the first and last occurrences of the given character. This leads to incorrect results when the character to be removed is not adjacent to the last occurrence."]} -{"name": "mbpp_751_check_min_heap", "language": "rs", "prompt": "/// Write a function to check if the given vector represents min heap or not. https://www.geeksforgeeks.org/how-to-check-if-a-given-vector-represents-a-binary-heap/\nfn check_min_heap(arr: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_751_check_min_heap.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "check_min_heap", "test": "}\n\nfn main() {\n let candidate = check_min_heap;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6]), true);\n assert_eq!(candidate(vec![2, 3, 4, 5, 10, 15]), true);\n assert_eq!(candidate(vec![2, 10, 4, 5, 3, 15]), false);\n}\n", "solution": "/// Write a function to check if the given vector represents min heap or not. https://www.geeksforgeeks.org/how-to-check-if-a-given-vector-represents-a-binary-heap/\nfn check_min_heap(arr: Vec) -> bool {\n fn is_min_heap(arr: &[isize], index: usize) -> bool {\n let n = arr.len();\n let left_child = 2 * index + 1;\n let right_child = 2 * index + 2;\n\n if left_child >= n {\n return true;\n }\n\n if arr[index] > arr[left_child] || (right_child < n && arr[index] > arr[right_child]) {\n return false;\n }\n\n let left_subtree = if left_child < n {\n is_min_heap(arr, left_child)\n } else {\n true\n };\n\n let right_subtree = if right_child < n {\n is_min_heap(arr, right_child)\n } else {\n true\n };\n\n if left_subtree && right_subtree {\n if left_child < n && arr[left_child] < arr[index] {\n return false;\n }\n if right_child < n && arr[right_child] < arr[index] {\n return false;\n }\n return true;\n } else {\n return false;\n }\n }\n\n is_min_heap(&arr, 0)\n}", "is_solved": true, "reflections": ["The implementation of the check_min_heap function is incorrect because it only checks if the parent node is greater than its children, but it does not ensure that the entire subtree rooted at the children also satisfies the min-heap property. This causes the function to return true for some cases where the input vector does not represent a min-heap, as demonstrated by the failed test case.", "The implementation is incorrect because it only checks if the current node is greater than its left and right children, but it doesn't ensure that the entire subtree rooted at the left and right children are also min heaps. The function should recursively check if both left and right subtrees are min heaps before returning true.", "The implementation is incorrect because it only checks if the current node is greater than its left and right children, but it does not ensure that the entire subtree rooted at the left and right children are min heaps. The function should recursively check if both left and right subtrees are min heaps before returning true. The failed test case has a valid min heap structure, but the function returns false because it does not properly check the entire subtree.", "The implementation is incorrect because it only checks if the current node is greater than its children, but it doesn't ensure that the children nodes are also following the min-heap property. The function returns true for a case where the min-heap property is not maintained throughout the entire tree, as seen in the failed test case."]} -{"name": "mbpp_578_interleave_lists", "language": "rs", "prompt": "/// Write a function to interleave 3 vectors of the same length into a single flat vector.\nfn interleave_lists(list1: Vec, list2: Vec, list3: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_578_interleave_lists.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "interleave_lists", "test": "}\n\nfn main() {\n let candidate = interleave_lists;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7], vec![10, 20, 30, 40, 50, 60, 70], vec![100, 200, 300, 400, 500, 600, 700]), vec![1, 10, 100, 2, 20, 200, 3, 30, 300, 4, 40, 400, 5, 50, 500, 6, 60, 600, 7, 70, 700]);\n assert_eq!(candidate(vec![10, 20], vec![15, 2], vec![5, 10]), vec![10, 15, 5, 20, 2, 10]);\n assert_eq!(candidate(vec![11, 44], vec![10, 15], vec![20, 5]), vec![11, 10, 20, 44, 15, 5]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to interleave 3 vectors of the same length into a single flat vector.\nfn interleave_lists(list1: Vec, list2: Vec, list3: Vec) -> Vec {\n let mut result = Vec::new();\n let len = list1.len();\n\n for i in 0..len {\n result.push(list1[i]);\n result.push(list2[i]);\n result.push(list3[i]);\n }\n\n result\n}"} -{"name": "mbpp_90_len_log", "language": "rs", "prompt": "/// Write a rsthon function to find the length of the longest word.\nfn len_log(list1: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_90_len_log.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "len_log", "test": "}\n\nfn main() {\n let candidate = len_log;\n assert_eq!(candidate(vec![String::from(\"python\"), String::from(\"PHP\"), String::from(\"bigdata\")]), 7);\n assert_eq!(candidate(vec![String::from(\"a\"), String::from(\"ab\"), String::from(\"abc\")]), 3);\n assert_eq!(candidate(vec![String::from(\"small\"), String::from(\"big\"), String::from(\"tall\")]), 5);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the length of the longest word.\nfn len_log(list1: Vec) -> isize {\n let mut max_len = 0;\n\n for word in list1 {\n if word.len() > max_len {\n max_len = word.len();\n }\n }\n\n max_len as isize\n}"} -{"name": "mbpp_452_loss_amount", "language": "rs", "prompt": "/// Write a function that gives loss amount on a sale if the given amount has loss else return 0.\nfn loss_amount(actual_cost: isize, sale_amount: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_452_loss_amount.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "loss_amount", "test": "}\n\nfn main() {\n let candidate = loss_amount;\n assert_eq!(candidate(1500, 1200), 0);\n assert_eq!(candidate(100, 200), 100);\n assert_eq!(candidate(2000, 5000), 3000);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function that gives loss amount on a sale if the given amount has loss else return 0.\nfn loss_amount(actual_cost: isize, sale_amount: isize) -> isize {\n if actual_cost > sale_amount {\n return actual_cost - sale_amount;\n } else {\n return 0;\n }\n}"} -{"name": "mbpp_798__sum", "language": "rs", "prompt": "/// Write a rsthon function to find the sum of a vector.\nfn _sum(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_798__sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "_sum", "test": "}\n\nfn main() {\n let candidate = _sum;\n assert_eq!(candidate(vec![1, 2, 3]), 6);\n assert_eq!(candidate(vec![15, 12, 13, 10]), 50);\n assert_eq!(candidate(vec![0, 1, 2]), 3);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the sum of a vector.\nfn _sum(arr: Vec) -> isize {\n let mut total: isize = 0;\n for num in arr {\n total += num;\n }\n total\n}"} -{"name": "mbpp_393_max_length_list", "language": "rs", "prompt": "/// Write a function to find the vector with maximum length.\nfn max_length_list(input_list: Vec>) -> (isize, Vec) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_393_max_length_list.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_length_list", "test": "}\n\nfn main() {\n let candidate = max_length_list;\n assert_eq!(candidate(vec![vec![0], vec![1, 3], vec![5, 7], vec![9, 11], vec![13, 15, 17]]), (3, vec![13, 15, 17]));\n assert_eq!(candidate(vec![vec![1, 2, 3, 4, 5], vec![1, 2, 3, 4], vec![1, 2, 3], vec![1, 2], vec![1]]), (5, vec![1, 2, 3, 4, 5]));\n assert_eq!(candidate(vec![vec![3, 4, 5], vec![6, 7, 8, 9], vec![10, 11, 12]]), (4, vec![6, 7, 8, 9]));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the vector with maximum length.\nfn max_length_list(input_list: Vec>) -> (isize, Vec) {\n let mut max_length = 0;\n let mut max_vector = Vec::new();\n\n for vector in input_list {\n let length = vector.len();\n if length > max_length {\n max_length = length;\n max_vector = vector;\n }\n }\n\n (max_length as isize, max_vector)\n}"} -{"name": "mbpp_272_rear_extract", "language": "rs", "prompt": "/// Write a function that takes in a vector of tuples and returns a vector containing the rear element of each tuple.\nfn rear_extract(test_list: Vec<(isize, String, isize)>) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_272_rear_extract.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "rear_extract", "test": "}\n\nfn main() {\n let candidate = rear_extract;\n assert_eq!(candidate(vec![(1, String::from(\"Rash\"), 21), (2, String::from(\"Varsha\"), 20), (3, String::from(\"Kil\"), 19)]), vec![21, 20, 19]);\n assert_eq!(candidate(vec![(1, String::from(\"Sai\"), 36), (2, String::from(\"Ayesha\"), 25), (3, String::from(\"Salman\"), 45)]), vec![36, 25, 45]);\n assert_eq!(candidate(vec![(1, String::from(\"Sudeep\"), 14), (2, String::from(\"Vandana\"), 36), (3, String::from(\"Dawood\"), 56)]), vec![14, 36, 56]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function that takes in a vector of tuples and returns a vector containing the rear element of each tuple.\nfn rear_extract(test_list: Vec<(isize, String, isize)>) -> Vec {\n let mut result = Vec::new();\n\n for tuple in test_list {\n result.push(tuple.2);\n }\n\n result\n}"} -{"name": "mbpp_564_count_Pairs", "language": "rs", "prompt": "/// Write a rsthon function which takes a vector of integers and counts the number of possible unordered pairs where both elements are unequal.\nfn count_Pairs(arr: Vec, n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_564_count_Pairs.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_Pairs", "test": "}\n\nfn main() {\n let candidate = count_Pairs;\n assert_eq!(candidate(vec![1, 2, 1], 3), 2);\n assert_eq!(candidate(vec![1, 1, 1, 1], 4), 0);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5], 5), 10);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function which takes a vector of integers and counts the number of possible unordered pairs where both elements are unequal.\nfn count_Pairs(arr: Vec, n: isize) -> isize {\n let mut count = 0;\n\n for i in 0..n {\n for j in i + 1..n {\n if arr[i as usize] != arr[j as usize] {\n count += 1;\n }\n }\n }\n\n count\n}"} -{"name": "mbpp_438_count_bidirectional", "language": "rs", "prompt": "/// Write a function to count bidirectional tuple pairs.\nfn count_bidirectional(test_list: Vec<(isize, isize)>) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_438_count_bidirectional.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_bidirectional", "test": "}\n\nfn main() {\n let candidate = count_bidirectional;\n assert_eq!(candidate(vec![(5, 6), (1, 2), (6, 5), (9, 1), (6, 5), (2, 1)]), 3);\n assert_eq!(candidate(vec![(5, 6), (1, 3), (6, 5), (9, 1), (6, 5), (2, 1)]), 2);\n assert_eq!(candidate(vec![(5, 6), (1, 2), (6, 5), (9, 2), (6, 5), (2, 1)]), 4);\n}\n", "solution": "/// Write a function to count bidirectional tuple pairs.\nfn count_bidirectional(test_list: Vec<(isize, isize)>) -> isize {\n let mut count = 0;\n let mut checked_pairs = Vec::new();\n\n for pair in &test_list {\n let reverse_pair = (pair.1, pair.0);\n if !checked_pairs.contains(pair) && !checked_pairs.contains(&reverse_pair) {\n if test_list.contains(&reverse_pair) {\n count += 1;\n checked_pairs.push(*pair);\n checked_pairs.push(reverse_pair);\n }\n }\n }\n\n count\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it counts a single tuple pair as a bidirectional pair, even if its reverse pair is not present in the input list. This causes the function to return a count of 1 for a single tuple pair, when it should return 0 if there is no matching reverse pair."]} -{"name": "mbpp_640_remove_parenthesis", "language": "rs", "prompt": "/// Write a function to remove the parenthesis and what is inbetween them from a string.\nfn remove_parenthesis(items: Vec) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_640_remove_parenthesis.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "remove_parenthesis", "test": "}\n\nfn main() {\n let candidate = remove_parenthesis;\n assert_eq!(candidate(vec![String::from(\"python (chrome)\")]), String::from(\"python\"));\n assert_eq!(candidate(vec![String::from(\"string(.abc)\")]), String::from(\"string\"));\n assert_eq!(candidate(vec![String::from(\"alpha(num)\")]), String::from(\"alpha\"));\n}\n", "solution": "/// Write a function to remove the parenthesis and what is inbetween them from a string.\nfn remove_parenthesis(items: Vec) -> String {\n let mut result = String::new();\n let mut open_parenthesis = 0;\n let mut space_needed = false;\n\n for (i, item) in items.iter().enumerate() {\n for ch in item.chars() {\n if ch == '(' {\n open_parenthesis += 1;\n } else if ch == ')' {\n if open_parenthesis > 0 {\n open_parenthesis -= 1;\n } else {\n result.push(ch);\n }\n } else if open_parenthesis == 0 {\n if space_needed && ch != ' ' {\n result.push(' ');\n }\n result.push(ch);\n space_needed = false;\n }\n }\n if i < items.len() - 1 && open_parenthesis == 0 {\n space_needed = true;\n }\n }\n\n result.trim().to_string()\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it does not handle spaces properly. When removing the parentheses and their content, it concatenates the remaining characters without preserving the spaces between them. This leads to the failed test cases where the expected output has spaces between the words.", "The implementation is incorrect because it adds an extra space after removing the parenthesis and its content, causing the output to have unnecessary spaces before and after the remaining words. This leads to the failed test cases where the output string does not match the expected result due to the extra spaces."]} -{"name": "mbpp_72_dif_Square", "language": "rs", "prompt": "/// Write a rsthon function to check whether the given number can be represented as the difference of two squares or not.\nfn dif_Square(n: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_72_dif_Square.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "dif_Square", "test": "}\n\nfn main() {\n let candidate = dif_Square;\n assert_eq!(candidate(5), true);\n assert_eq!(candidate(10), false);\n assert_eq!(candidate(15), true);\n}\n", "solution": "/// Write a rsthon function to check whether the given number can be represented as the difference of two squares or not.\nfn dif_Square(n: isize) -> bool {\n for i in 1..=((n as f64).sqrt() as isize) {\n let j = n - i * i;\n if (j as f64).sqrt().floor() as isize == (j as f64).sqrt() as isize {\n return true;\n }\n }\n false\n}", "is_solved": true, "reflections": ["The implementation is incorrect because there is a type mismatch in the comparison. The left side of the comparison is cast to `isize`, while the right side remains as `f64`. This causes a compilation error due to the mismatched types."]} -{"name": "mbpp_448_cal_sum", "language": "rs", "prompt": "/// Write a function to calculate the sum of perrin numbers.\nfn cal_sum(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_448_cal_sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "cal_sum", "test": "}\n\nfn main() {\n let candidate = cal_sum;\n assert_eq!(candidate(9), 49);\n assert_eq!(candidate(10), 66);\n assert_eq!(candidate(11), 88);\n}\n", "solution": "/// Write a function to calculate the sum of perrin numbers.\nfn cal_sum(n: isize) -> isize {\n if n <= 0 {\n return 0;\n }\n\n let mut a = 3;\n let mut b = 0;\n let mut c = 2;\n let mut sum = 0;\n\n for i in 0..n {\n match i {\n 0 => sum += a,\n 1 => sum += b,\n 2 => sum += c,\n _ => {\n let temp = a + c;\n a = b;\n b = c;\n c = temp;\n sum += c;\n }\n }\n }\n\n sum\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it starts summing the perrin numbers from the initial values of a, b, and c (0, 2, and 3), without considering the input value 'n'. This causes the sum to always be greater than the expected result, as it includes extra perrin numbers in the calculation.", "The implementation of the cal_sum function is incorrect because it calculates the sum of Fibonacci numbers instead of Perrin numbers. The initial values of a, b, and c should be 3, 0, and 2 respectively, and the calculation of the next number in the sequence should be done using the formula temp = a + c.", "The implementation of the cal_sum function is incorrect because it calculates the sum of the Perrin sequence incorrectly. The loop starts from 0 and adds the initial values of a, b, and c directly to the sum, causing an incorrect sum calculation. The correct approach should be to initialize the sum with the first three Perrin numbers and then update the sum with the new Perrin number in each iteration.", "The implementation of the cal_sum function is incorrect because it initializes the sum with the first three Perrin numbers (a, b, and c) before the loop starts. This causes the sum to be higher than expected for smaller values of n, and the loop iterates one less time than it should, resulting in incorrect sums for larger values of n."]} -{"name": "mbpp_96_divisor", "language": "rs", "prompt": "/// Write a rsthon function to find the number of divisors of a given integer.\nfn divisor(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_96_divisor.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "divisor", "test": "}\n\nfn main() {\n let candidate = divisor;\n assert_eq!(candidate(15), 4);\n assert_eq!(candidate(12), 6);\n assert_eq!(candidate(9), 3);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the number of divisors of a given integer.\nfn divisor(n: isize) -> isize {\n let mut count = 0;\n\n for i in 1..=n {\n if n % i == 0 {\n count += 1;\n }\n }\n\n count\n}"} -{"name": "mbpp_296_get_Inv_Count", "language": "rs", "prompt": "/// Write a rsthon function to count inversions in a vector.\nfn get_Inv_Count(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_296_get_Inv_Count.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "get_Inv_Count", "test": "}\n\nfn main() {\n let candidate = get_Inv_Count;\n assert_eq!(candidate(vec![1, 20, 6, 4, 5]), 5);\n assert_eq!(candidate(vec![1, 2, 1]), 1);\n assert_eq!(candidate(vec![1, 2, 5, 6, 1]), 3);\n}\n", "solution": "/// Write a rsthon function to count inversions in a vector.\nfn get_Inv_Count(arr: Vec) -> isize {\n fn merge_and_count(arr: &mut [isize], temp: &mut [isize], left: usize, mid: usize, right: usize) -> isize {\n let mut i = left;\n let mut j = mid;\n let mut k = left;\n let mut inv_count = 0isize;\n\n while i < mid && j <= right {\n if arr[i] <= arr[j] {\n temp[k] = arr[i];\n i += 1;\n } else {\n temp[k] = arr[j];\n inv_count += (mid - i) as isize;\n j += 1;\n }\n k += 1;\n }\n\n while i < mid {\n temp[k] = arr[i];\n i += 1;\n k += 1;\n }\n\n while j <= right {\n temp[k] = arr[j];\n j += 1;\n k += 1;\n }\n\n for i in left..=right {\n arr[i] = temp[i];\n }\n\n inv_count\n }\n\n fn merge_sort_and_count(arr: &mut [isize], temp: &mut [isize], left: usize, right: usize) -> isize {\n if left >= right {\n return 0;\n }\n\n let mid = (left + right) / 2;\n let left_count = merge_sort_and_count(arr, temp, left, mid);\n let right_count = merge_sort_and_count(arr, temp, mid + 1, right);\n let merge_count = merge_and_count(arr, temp, left, mid + 1, right);\n\n left_count + right_count + merge_count\n }\n\n let n = arr.len();\n let mut temp = vec![0; n];\n let mut arr = arr;\n merge_sort_and_count(&mut arr, &mut temp, 0, n - 1)\n}", "is_solved": true, "reflections": ["The current implementation of the get_Inv_Count function is incorrect because it only counts inversions in a simple nested loop, which does not account for all possible inversions in the input vector. This is evident from the failed test case, where the expected output is 12, but the function returns 10.", "The implementation is incorrect because there is a type mismatch between the expected return type `isize` and the actual type of `inv_count`, which is `usize`. The error occurs when trying to return `inv_count` in the `merge_and_count` function. To fix this issue, the type of `inv_count` should be changed to `isize` or a conversion should be performed before returning the value.", "The implementation is incorrect because the `arr` parameter in the `get_Inv_Count` function is not declared as mutable. Since the `merge_sort_and_count` function requires a mutable reference to `arr`, the code fails to compile. To fix this issue, the `arr` parameter should be declared as mutable in the `get_Inv_Count` function.", "The implementation of the `get_Inv_Count` function is incorrect because it fails to handle cases where there are duplicate elements in the input vector. The failed test case has duplicate elements, and the function returns an incorrect inversion count due to not accounting for these duplicates properly."]} -{"name": "mbpp_57_find_Max_Num", "language": "rs", "prompt": "/// Write a rsthon function to find the largest number that can be formed with the given vector of digits.\nfn find_Max_Num(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_57_find_Max_Num.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_Max_Num", "test": "}\n\nfn main() {\n let candidate = find_Max_Num;\n assert_eq!(candidate(vec![1, 2, 3]), 321);\n assert_eq!(candidate(vec![4, 5, 6, 1]), 6541);\n assert_eq!(candidate(vec![1, 2, 3, 9]), 9321);\n}\n", "solution": "/// Write a rsthon function to find the largest number that can be formed with the given vector of digits.\nfn find_Max_Num(arr: Vec) -> isize {\n let mut arr_str: Vec = arr.into_iter().map(|x| x.to_string()).collect();\n arr_str.sort_by(|a, b| {\n let ab = format!(\"{}{}\", a, b);\n let ba = format!(\"{}{}\", b, a);\n let ab_val = ab.parse::().unwrap();\n let ba_val = ba.parse::().unwrap();\n ba_val.cmp(&ab_val)\n });\n\n let arr_str_clone = arr_str.clone();\n let mut max_num: String = arr_str_clone.into_iter().collect();\n let mut max_val = max_num.parse::().unwrap();\n\n for i in 0..arr_str.len() - 1 {\n let mut temp_arr = arr_str.clone();\n temp_arr.swap(i, i + 1);\n let temp_num: String = temp_arr.into_iter().collect();\n let temp_val = temp_num.parse::().unwrap();\n if temp_val > max_val {\n max_val = temp_val;\n max_num = temp_num;\n }\n }\n\n max_val\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it sorts the digits based on their string concatenation, which does not always result in the correct order for forming the largest number. In the failed test case, the sorting method incorrectly orders the digits as 4, 3, 2, 1 instead of the correct order 4, 3, 1, 2, leading to the wrong output.", "The implementation is incorrect because it sorts the digits based on their concatenated string values, which does not always result in the correct order for forming the largest number. In the failed test case, the function sorts the digits as 4, 3, 2, 1, resulting in the number 4321, while the correct order should be 4, 3, 1, 2, forming the number 4312.", "The implementation is incorrect because it sorts the digits based on their combined values (ab and ba) in descending order. However, this approach does not always result in the largest possible number. In the failed test case, the function sorts the digits as 4, 3, 2, 1, forming the number 4321, while the correct answer should be 4312.", "The implementation is wrong because it tries to use `arr_str` after it has been moved on line 13. The `into_iter()` method call moves `arr_str`, making it inaccessible for further use. To fix this issue, you can clone `arr_str` before calling `into_iter()` to create a separate copy that can be used later in the loop."]} -{"name": "mbpp_614_cummulative_sum", "language": "rs", "prompt": "/// Write a function to find the cumulative sum of all the values that are present in the given vector of vectors.\nfn cummulative_sum(test_list: Vec>) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_614_cummulative_sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "cummulative_sum", "test": "}\n\nfn main() {\n let candidate = cummulative_sum;\n assert_eq!(candidate(vec![vec![1, 3], vec![5, 6, 7], vec![2, 6]]), 30);\n assert_eq!(candidate(vec![vec![2, 4], vec![6, 7, 8], vec![3, 7]]), 37);\n assert_eq!(candidate(vec![vec![3, 5], vec![7, 8, 9], vec![4, 8]]), 44);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the cumulative sum of all the values that are present in the given vector of vectors.\nfn cummulative_sum(test_list: Vec>) -> isize {\n let mut total_sum = 0;\n\n for inner_list in test_list {\n for value in inner_list {\n total_sum += value;\n }\n }\n\n total_sum\n}"} -{"name": "mbpp_623_nth_nums", "language": "rs", "prompt": "/// Write a function to compute the n-th power of each number in a vector.\nfn nth_nums(nums: Vec, n: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_623_nth_nums.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "nth_nums", "test": "}\n\nfn main() {\n let candidate = nth_nums;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 10], 2), vec![1, 4, 9, 16, 25, 36, 49, 64, 81, 100]);\n assert_eq!(candidate(vec![10, 20, 30], 3), vec![1000, 8000, 27000]);\n assert_eq!(candidate(vec![12, 15], 5), vec![248832, 759375]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to compute the n-th power of each number in a vector.\nfn nth_nums(nums: Vec, n: isize) -> Vec {\n nums.into_iter().map(|num| num.pow(n as u32)).collect()\n}"} -{"name": "mbpp_799_left_rotate", "language": "rs", "prompt": "/// Write a function to that rotate left bits by d bits a given number. We assume that the number is 32 bit.\nfn left_rotate(n: isize, d: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_799_left_rotate.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "left_rotate", "test": "}\n\nfn main() {\n let candidate = left_rotate;\n assert_eq!(candidate(16, 2), 64);\n assert_eq!(candidate(10, 2), 40);\n assert_eq!(candidate(99, 3), 792);\n assert_eq!(candidate(99, 3), 792);\n assert_eq!(candidate(1, 3), 8);\n assert_eq!(candidate(5, 3), 40);\n assert_eq!(candidate(29, 3), 232);\n}\n", "solution": "/// Write a function to that rotate left bits by d bits a given number. We assume that the number is 32 bit.\nfn left_rotate(n: isize, d: isize) -> isize {\n let bits = 32;\n let mask = (1 << bits) - 1;\n let d_mod = d % bits;\n let left_shift = (n << d_mod) & mask;\n let right_shift = ((n & mask) as u32).wrapping_shr(bits as u32 - d_mod as u32) as isize;\n let result = left_shift | right_shift;\n result\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it tries to assign a value to the function name `left_rotate` instead of returning the result. The assignment operation should be replaced with a return statement to return the correct result of the bitwise OR operation between `left_shift` and `right_shift`.", "The implementation of the left_rotate function is incorrect because it does not properly handle the case when the rotated bits wrap around the 32-bit boundary. The right_shift operation should be performed using an unsigned right shift (>>) instead of a signed right shift (>>), which causes the shifted bits to be filled with the sign bit, leading to incorrect results.", "The implementation of the left_rotate function is incorrect because it does not properly handle the case when the rotated bits wrap around the 32-bit boundary. The right_shift calculation is using an unsigned 32-bit integer, which causes the shifted bits to be lost when they should be wrapping around to the least significant bits. This results in incorrect output for the failed test cases.", "The implementation of the left_rotate function is incorrect because it is not properly handling the rotation of bits when the number of bits to rotate (d) is greater than the number of bits in the number (n). The right_shift calculation is not accounting for the correct number of bits to shift, causing the function to return incorrect results for the failed test cases."]} -{"name": "mbpp_247_lps", "language": "rs", "prompt": "/// Write a function to find the length of the longest palindromic subsequence in the given string.\nfn lps(str: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_247_lps.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "lps", "test": "}\n\nfn main() {\n let candidate = lps;\n assert_eq!(candidate(String::from(\"TENS FOR TENS\")), 5);\n assert_eq!(candidate(String::from(\"CARDIO FOR CARDS\")), 7);\n assert_eq!(candidate(String::from(\"PART OF THE JOURNEY IS PART\")), 9);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the length of the longest palindromic subsequence in the given string.\nfn lps(str: String) -> isize {\n let n = str.len();\n let chars: Vec = str.chars().collect();\n let mut dp = vec![vec![0; n]; n];\n\n for i in 0..n {\n dp[i][i] = 1;\n }\n\n for len in 2..=n {\n for i in 0..n - len + 1 {\n let j = i + len - 1;\n if chars[i] == chars[j] {\n dp[i][j] = dp[i + 1][j - 1] + 2;\n } else {\n dp[i][j] = isize::max(dp[i + 1][j], dp[i][j - 1]);\n }\n }\n }\n\n dp[0][n - 1]\n}"} -{"name": "mbpp_735_toggle_middle_bits", "language": "rs", "prompt": "/// Write a rsthon function to toggle bits of the number except the first and the last bit. https://www.geeksforgeeks.org/toggle-bits-number-expect-first-last-bits/\nfn toggle_middle_bits(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_735_toggle_middle_bits.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "toggle_middle_bits", "test": "}\n\nfn main() {\n let candidate = toggle_middle_bits;\n assert_eq!(candidate(9), 15);\n assert_eq!(candidate(10), 12);\n assert_eq!(candidate(11), 13);\n assert_eq!(candidate(65), 127);\n assert_eq!(candidate(77), 115);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to toggle bits of the number except the first and the last bit. https://www.geeksforgeeks.org/toggle-bits-number-expect-first-last-bits/\nfn toggle_middle_bits(n: isize) -> isize {\n let mut result = n;\n let mut position = 1;\n\n while (1 << position) < n {\n result ^= 1 << position;\n position += 1;\n }\n\n result &= !(1 << 0);\n result &= !(1 << (position - 1));\n\n result\n}"} -{"name": "mbpp_132_tup_string", "language": "rs", "prompt": "/// Write a function to convert a vector to a string.\nfn tup_string(tup1: Vec) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_132_tup_string.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "tup_string", "test": "}\n\nfn main() {\n let candidate = tup_string;\n assert_eq!(candidate(vec![String::from(\"e\"), String::from(\"x\"), String::from(\"e\"), String::from(\"r\"), String::from(\"c\"), String::from(\"i\"), String::from(\"s\"), String::from(\"e\"), String::from(\"s\")]), String::from(\"exercises\"));\n assert_eq!(candidate(vec![String::from(\"p\"), String::from(\"y\"), String::from(\"t\"), String::from(\"h\"), String::from(\"o\"), String::from(\"n\")]), String::from(\"python\"));\n assert_eq!(candidate(vec![String::from(\"p\"), String::from(\"r\"), String::from(\"o\"), String::from(\"g\"), String::from(\"r\"), String::from(\"a\"), String::from(\"m\")]), String::from(\"program\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to convert a vector to a string.\nfn tup_string(tup1: Vec) -> String {\n let mut result = String::new();\n for s in tup1 {\n result.push_str(&s);\n }\n result\n}"} -{"name": "mbpp_460_Extract", "language": "rs", "prompt": "/// Write a rsthon function to get the first element of each subvector.\nfn Extract(lst: Vec>) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_460_Extract.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "Extract", "test": "}\n\nfn main() {\n let candidate = Extract;\n assert_eq!(candidate(vec![vec![1, 2], vec![3, 4, 5], vec![6, 7, 8, 9]]), vec![1, 3, 6]);\n assert_eq!(candidate(vec![vec![1, 2, 3], vec![4, 5]]), vec![1, 4]);\n assert_eq!(candidate(vec![vec![9, 8, 1], vec![1, 2]]), vec![9, 1]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to get the first element of each subvector.\nfn Extract(lst: Vec>) -> Vec {\n let mut result: Vec = Vec::new();\n\n for subvector in lst {\n if !subvector.is_empty() {\n result.push(subvector[0]);\n }\n }\n\n result\n}"} -{"name": "mbpp_606_radian_degree", "language": "rs", "prompt": "/// Write a function to convert degrees to radians.\nfn radian_degree(degree: isize) -> f64 {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_606_radian_degree.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "radian_degree", "test": "}\n\nfn main() {\n let candidate = radian_degree;\n assert_eq!(candidate(90), 1.5707963267948966);\n assert_eq!(candidate(60), 1.0471975511965976);\n assert_eq!(candidate(120), 2.0943951023931953);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to convert degrees to radians.\nfn radian_degree(degree: isize) -> f64 {\n let radians = (degree as f64) * std::f64::consts::PI / 180.0;\n radians\n}"} -{"name": "mbpp_167_next_power_of_2", "language": "rs", "prompt": "/// Write a rsthon function to find the smallest power of 2 greater than or equal to n.\nfn next_power_of_2(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_167_next_power_of_2.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "next_power_of_2", "test": "}\n\nfn main() {\n let candidate = next_power_of_2;\n assert_eq!(candidate(0), 1);\n assert_eq!(candidate(5), 8);\n assert_eq!(candidate(17), 32);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the smallest power of 2 greater than or equal to n.\nfn next_power_of_2(n: isize) -> isize {\n let mut power = 1;\n while power < n {\n power *= 2;\n }\n power\n}"} -{"name": "mbpp_756_text_match_zero_one", "language": "rs", "prompt": "/// Write a function that matches a string that has an 'a' followed by one or more 'b's. https://www.w3resource.com/rsthon-exercises/re/rsthon-re-exercise-3.php\nfn text_match_zero_one(text: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_756_text_match_zero_one.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "text_match_zero_one", "test": "}\n\nfn main() {\n let candidate = text_match_zero_one;\n assert_eq!(candidate(String::from(\"ac\")), false);\n assert_eq!(candidate(String::from(\"dc\")), false);\n assert_eq!(candidate(String::from(\"abbbba\")), true);\n assert_eq!(candidate(String::from(\"dsabbbba\")), true);\n assert_eq!(candidate(String::from(\"asbbbba\")), false);\n assert_eq!(candidate(String::from(\"abaaa\")), true);\n}\n", "solution": "/// Write a function that matches a string that has an 'a' followed by one or more 'b's. https://www.w3resource.com/rsthon-exercises/re/rsthon-re-exercise-3.php\nfn text_match_zero_one(text: String) -> bool {\n use regex::Regex;\n let re = Regex::new(r\"a+b+\").unwrap();\n re.is_match(&text)\n}", "is_solved": true, "reflections": ["The implementation is incorrect because the `regex` crate is not declared or imported, causing the compiler to throw an error. To fix this issue, the `regex` crate needs to be added to the dependencies in Cargo.toml and imported using `use regex::Regex;` at the beginning of the code.", "The implementation is incorrect because the `regex` crate is not declared in the dependencies, causing an unresolved import error. To fix this issue, the `regex` crate should be added to the Cargo.toml file under the dependencies section.", "The implementation is incorrect because the `regex` crate is not declared in the dependencies, causing an unresolved import error. To fix this issue, the `regex` crate should be added to the project's dependencies in the Cargo.toml file.", "The implementation is wrong because the `regex` crate is not declared in the dependencies, causing an unresolved import error. To fix this, the `regex` crate should be added to the Cargo.toml file under the dependencies section."]} -{"name": "mbpp_633_pair_xor_Sum", "language": "rs", "prompt": "/// Write a rsthon function to find the sum of xor of all pairs of numbers in the given vector.\nfn pair_xor_Sum(arr: Vec, n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_633_pair_xor_Sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "pair_xor_Sum", "test": "}\n\nfn main() {\n let candidate = pair_xor_Sum;\n assert_eq!(candidate(vec![5, 9, 7, 6], 4), 47);\n assert_eq!(candidate(vec![7, 3, 5], 3), 12);\n assert_eq!(candidate(vec![7, 3], 2), 4);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the sum of xor of all pairs of numbers in the given vector.\nfn pair_xor_Sum(arr: Vec, n: isize) -> isize {\n let mut xor_sum = 0;\n\n for i in 0..n {\n for j in i + 1..n {\n xor_sum += arr[i as usize] ^ arr[j as usize];\n }\n }\n\n xor_sum\n}"} -{"name": "mbpp_458_rectangle_area", "language": "rs", "prompt": "/// Write a function to find the area of a rectangle.\nfn rectangle_area(l: isize, b: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_458_rectangle_area.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "rectangle_area", "test": "}\n\nfn main() {\n let candidate = rectangle_area;\n assert_eq!(candidate(10, 20), 200);\n assert_eq!(candidate(10, 5), 50);\n assert_eq!(candidate(4, 2), 8);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the area of a rectangle.\nfn rectangle_area(l: isize, b: isize) -> isize {\n l * b\n}"} -{"name": "mbpp_738_geometric_sum", "language": "rs", "prompt": "/// Write a function to calculate the geometric sum of n-1. https://www.w3resource.com/rsthon-exercises/data-structures-and-algorithms/rsthon-recursion-exercise-9.php\nfn geometric_sum(n: isize) -> f64 {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_738_geometric_sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "geometric_sum", "test": "}\n\nfn main() {\n let candidate = geometric_sum;\n assert_eq!(candidate(7), 1.9921875);\n assert_eq!(candidate(4), 1.9375);\n assert_eq!(candidate(8), 1.99609375);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to calculate the geometric sum of n-1. https://www.w3resource.com/rsthon-exercises/data-structures-and-algorithms/rsthon-recursion-exercise-9.php\nfn geometric_sum(n: isize) -> f64 {\n if n == 0 {\n return 0.0;\n } else {\n return 1.0 / (2f64.powi(n as i32 - 1)) + geometric_sum(n - 1);\n }\n}"} -{"name": "mbpp_426_filter_oddnumbers", "language": "rs", "prompt": "/// Write a function to filter odd numbers.\nfn filter_oddnumbers(nums: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_426_filter_oddnumbers.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "filter_oddnumbers", "test": "}\n\nfn main() {\n let candidate = filter_oddnumbers;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 10]), vec![1, 3, 5, 7, 9]);\n assert_eq!(candidate(vec![10, 20, 45, 67, 84, 93]), vec![45, 67, 93]);\n assert_eq!(candidate(vec![5, 7, 9, 8, 6, 4, 3]), vec![5, 7, 9, 3]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to filter odd numbers.\nfn filter_oddnumbers(nums: Vec) -> Vec {\n nums.into_iter().filter(|&num| num % 2 != 0).collect()\n}"} -{"name": "mbpp_437_remove_odd", "language": "rs", "prompt": "/// Write a function to remove odd characters in a string.\nfn remove_odd(str1: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_437_remove_odd.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "remove_odd", "test": "}\n\nfn main() {\n let candidate = remove_odd;\n assert_eq!(candidate(String::from(\"python\")), String::from(\"yhn\"));\n assert_eq!(candidate(String::from(\"program\")), String::from(\"rga\"));\n assert_eq!(candidate(String::from(\"language\")), String::from(\"agae\"));\n}\n", "solution": "/// Write a function to remove odd characters in a string.\nfn remove_odd(str1: String) -> String {\n let mut result = String::new();\n for (index, ch) in str1.char_indices() {\n if index % 2 == 0 {\n result.push(ch);\n }\n }\n result\n}", "is_solved": true, "reflections": ["The implementation of the remove_odd function is incorrect because it removes characters at even indices instead of odd indices. The function should only keep characters at odd indices, but currently, it keeps characters at even indices, causing the failed test case.", "The implementation of the `remove_odd` function is incorrect because it removes characters at even indices instead of odd indices. The conditional statement in the loop checks if the index is odd (`index % 2 != 0`) and then pushes the character to the result string, causing the function to return a string with only even-indexed characters.", "The implementation of the remove_odd function is incorrect because it removes even-indexed characters instead of odd-indexed characters. The function should remove characters at odd indices (1, 3, 5, etc.), but it currently removes characters at even indices (0, 2, 4, etc.).", "The implementation of the `remove_odd` function is incorrect because it removes characters at even indices instead of odd ones. The conditional statement `if index % 2 == 1` should be changed to `if index % 2 == 0` to correctly remove odd characters and pass the failed tests."]} -{"name": "mbpp_227_min_of_three", "language": "rs", "prompt": "/// Write a function to find minimum of three numbers.\nfn min_of_three(a: isize, b: isize, c: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_227_min_of_three.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "min_of_three", "test": "}\n\nfn main() {\n let candidate = min_of_three;\n assert_eq!(candidate(10, 20, 0), 0);\n assert_eq!(candidate(19, 15, 18), 15);\n assert_eq!(candidate(-10, -20, -30), -30);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find minimum of three numbers.\nfn min_of_three(a: isize, b: isize, c: isize) -> isize {\n if a <= b && a <= c {\n a\n } else if b <= a && b <= c {\n b\n } else {\n c\n }\n}"} -{"name": "mbpp_172_count_occurance", "language": "rs", "prompt": "/// Write a function to count the number of occurence of the string 'std' in a given string.\nfn count_occurance(s: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_172_count_occurance.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_occurance", "test": "}\n\nfn main() {\n let candidate = count_occurance;\n assert_eq!(candidate(String::from(\"letstdlenstdporstd\")), 3);\n assert_eq!(candidate(String::from(\"truststdsolensporsd\")), 1);\n assert_eq!(candidate(String::from(\"makestdsostdworthit\")), 2);\n assert_eq!(candidate(String::from(\"stds\")), 1);\n assert_eq!(candidate(String::from(\"\")), 0);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to count the number of occurence of the string 'std' in a given string.\nfn count_occurance(s: String) -> isize {\n let mut count = 0;\n let search_str = \"std\";\n let search_str_len = search_str.len();\n\n for i in 0..s.len() - search_str_len + 1 {\n if &s[i..i + search_str_len] == search_str {\n count += 1;\n }\n }\n\n count\n}"} -{"name": "mbpp_434_text_match_one", "language": "rs", "prompt": "/// Write a function that matches a string that has an a followed by one or more b's.\nfn text_match_one(text: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_434_text_match_one.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "text_match_one", "test": "}\n\nfn main() {\n let candidate = text_match_one;\n assert_eq!(candidate(String::from(\"ac\")), false);\n assert_eq!(candidate(String::from(\"dc\")), false);\n assert_eq!(candidate(String::from(\"abba\")), true);\n}\n", "solution": "/// Write a function that matches a string that has an a followed by one or more b's.\nfn text_match_one(text: String) -> bool {\n use regex::Regex;\n let pattern = Regex::new(r\"a+b+\").unwrap();\n pattern.is_match(&text)\n}", "is_solved": true, "reflections": ["The implementation is wrong because the `regex` crate is not declared or imported, causing the compiler to throw an error. To fix this issue, the `regex` crate needs to be added to the `Cargo.toml` file and imported using `use regex::Regex;` at the beginning of the code.", "The implementation is wrong because the `regex` crate is not declared in the dependencies, causing an unresolved import error. To fix this issue, the `regex` crate should be added to the project's `Cargo.toml` file under the `[dependencies]` section.", "The implementation is wrong because the `regex` crate is not declared in the dependencies, causing an unresolved import error. To fix this issue, the `regex` crate should be added to the project's `Cargo.toml` file under the `[dependencies]` section.", "The implementation is wrong because the `regex` crate is not declared in the dependencies, causing an unresolved import error. To fix this, the `regex` crate should be added to the Cargo.toml file and imported correctly."]} -{"name": "mbpp_291_count_no_of_ways", "language": "rs", "prompt": "/// Write a function to find out the number of ways of painting the fence such that at most 2 adjacent posts have the same color for the given fence with n posts and k colors.\nfn count_no_of_ways(n: isize, k: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_291_count_no_of_ways.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_no_of_ways", "test": "}\n\nfn main() {\n let candidate = count_no_of_ways;\n assert_eq!(candidate(2, 4), 16);\n assert_eq!(candidate(3, 2), 6);\n assert_eq!(candidate(4, 4), 228);\n}\n", "solution": "/// Write a function to find out the number of ways of painting the fence such that at most 2 adjacent posts have the same color for the given fence with n posts and k colors.\nfn count_no_of_ways(n: isize, k: isize) -> isize {\n if n == 0 {\n return 0;\n }\n if n == 1 {\n return k;\n }\n\n let mut same_color = k;\n let mut diff_color = k * (k - 1);\n let mut total_ways = same_color + diff_color;\n\n for _ in 3..=n {\n let prev_same_color = same_color;\n same_color = diff_color;\n diff_color = (prev_same_color + diff_color) * (k - 1);\n total_ways = same_color + diff_color;\n }\n\n total_ways\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it does not properly handle the case when there are more than 3 posts and more than 2 colors. The calculation for `diff_color` should be based on the previous `diff_color` and `same_color` values, not the `total_ways`. This leads to an overestimation of the number of ways to paint the fence when n > 3 and k > 2.", "The implementation is incorrect because it does not properly handle the calculation of the number of ways to paint the fence when there are more than 2 posts. The logic for updating `same_color` and `diff_color` variables is flawed, leading to incorrect results for cases with 3 or more posts.", "The implementation of the count_no_of_ways function is incorrect because it does not properly handle the calculation of the total number of ways to paint the fence when there are more than 2 posts. The error lies in the calculation of the same_color, diff_color, and total_ways variables within the loop. The subtraction of prev_same_color from total_ways is causing an incorrect count of the possible ways to paint the fence.", "The implementation is incorrect because it does not properly handle the case when there are more than 3 fence posts. The calculation for `diff_color` should be based on the previous `diff_color` and `same_color` values, not the previous `total_ways`. This leads to an overestimation of the number of ways to paint the fence when n > 3."]} -{"name": "mbpp_471_find_remainder", "language": "rs", "prompt": "/// Write a rsthon function to find the product of the vector multiplication modulo n.\nfn find_remainder(arr: Vec, n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_471_find_remainder.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_remainder", "test": "}\n\nfn main() {\n let candidate = find_remainder;\n assert_eq!(candidate(vec![100, 10, 5, 25, 35, 14], 11), 9);\n assert_eq!(candidate(vec![1, 1, 1], 1), 0);\n assert_eq!(candidate(vec![1, 2, 1], 2), 0);\n}\n", "solution": "/// Write a rsthon function to find the product of the vector multiplication modulo n.\nfn find_remainder(arr: Vec, n: isize) -> isize {\n let mut product: isize = 1;\n\n for num in arr {\n product = (product * num) % n;\n }\n\n if product < 0 {\n product += n;\n }\n\n product % n\n}", "is_solved": true, "reflections": ["The implementation of the find_remainder function is incorrect because it does not handle cases where the modulo operation results in a remainder that is not equal to zero. In the failed test case, the product of the vector elements is 120, and the remainder when divided by 10 should be 4, but the function returns 0 instead. This indicates that the function is not properly calculating the remainder for certain input values.", "The implementation of the find_remainder function is incorrect because it does not handle cases where the product of the vector elements is not evenly divisible by the modulo n. In the failed test case, the product of the vector elements is 120, and the remainder when divided by 10 should be 4, but the function returns 0 instead. This indicates that the function is not calculating the remainder correctly in certain cases.", "The implementation of the find_remainder function is incorrect because it does not handle cases where the product of the vector elements is divisible by n, but the remainder is not zero. In the failed test case, the product is 120, which is divisible by 10, but the remainder should be 4. The function needs to be updated to correctly calculate the remainder in such cases.", "The implementation of the find_remainder function is incorrect because it does not handle cases where the product of the vector multiplication is equal to the modulo value (n). In such cases, the function returns 0 instead of the correct remainder. This is due to the condition `if product == 0 { product = n; }`, which should be removed to fix the issue."]} -{"name": "mbpp_808_check_K", "language": "rs", "prompt": "/// Write a function to check if the given tuples contain the k or not.\nfn check_K(test_tup: Vec, K: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_808_check_K.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "check_K", "test": "}\n\nfn main() {\n let candidate = check_K;\n assert_eq!(candidate(vec![10, 4, 5, 6, 8], 6), true);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6], 7), false);\n assert_eq!(candidate(vec![7, 8, 9, 44, 11, 12], 11), true);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check if the given tuples contain the k or not.\nfn check_K(test_tup: Vec, K: isize) -> bool {\n for value in test_tup {\n if value == K {\n return true;\n }\n }\n false\n}"} -{"name": "mbpp_68_is_Monotonic", "language": "rs", "prompt": "/// Write a rsthon function to check whether the given vector is monotonic or not.\nfn is_Monotonic(A: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_68_is_Monotonic.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_Monotonic", "test": "}\n\nfn main() {\n let candidate = is_Monotonic;\n assert_eq!(candidate(vec![6, 5, 4, 4]), true);\n assert_eq!(candidate(vec![1, 2, 2, 3]), true);\n assert_eq!(candidate(vec![1, 3, 2]), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to check whether the given vector is monotonic or not.\nfn is_Monotonic(A: Vec) -> bool {\n if A.len() < 2 {\n return true;\n }\n\n let mut increasing = None;\n\n for i in 1..A.len() {\n if A[i - 1] == A[i] {\n continue;\n }\n\n if increasing.is_none() {\n increasing = Some(A[i - 1] < A[i]);\n } else if increasing.unwrap() != (A[i - 1] < A[i]) {\n return false;\n }\n }\n\n true\n}"} -{"name": "mbpp_430_parabola_directrix", "language": "rs", "prompt": "/// Write a function to find the directrix of a parabola.\nfn parabola_directrix(a: isize, b: isize, c: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_430_parabola_directrix.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "parabola_directrix", "test": "}\n\nfn main() {\n let candidate = parabola_directrix;\n assert_eq!(candidate(5, 3, 2), -198);\n assert_eq!(candidate(9, 8, 4), -2336);\n assert_eq!(candidate(2, 4, 6), -130);\n}\n", "solution": "/// Write a function to find the directrix of a parabola.\nfn parabola_directrix(a: isize, b: isize, c: isize) -> isize {\n let directrix = (c as f64 - (b as f64).powi(2) / (4.0 * a as f64)) / (2.0 * a as f64);\n directrix.round() as isize\n}", "is_solved": true, "reflections": ["The implementation of the parabola_directrix function is incorrect because it uses integer division, which truncates the result, leading to inaccurate directrix calculations. This is evident in the failed test cases where the expected output does not match the actual output.", "The implementation of the parabola_directrix function is incorrect because it calculates the directrix using the formula for the vertex of a parabola instead of the directrix. This leads to incorrect results for the given test cases.", "The implementation of the parabola_directrix function is incorrect because it uses the wrong formula to calculate the directrix. The formula used is (c - a) / (4 * a), but it should be (c - a^2) / (4 * a) to correctly calculate the directrix of a parabola. This error leads to incorrect results in the failed test cases.", "The implementation of the parabola_directrix function is incorrect because it uses the wrong formula to calculate the directrix. The formula used in the function calculates the vertex of the parabola, not the directrix. This is why the function fails the provided test cases."]} -{"name": "mbpp_618_div_list", "language": "rs", "prompt": "/// Write a function to divide two vectors element wise.\nfn div_list(nums1: Vec, nums2: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_618_div_list.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "div_list", "test": "}\n\nfn main() {\n let candidate = div_list;\n assert_eq!(candidate(vec![4, 5, 6], vec![1, 2, 3]), vec![4.0, 2.5, 2.0]);\n assert_eq!(candidate(vec![3, 2], vec![1, 4]), vec![3.0, 0.5]);\n assert_eq!(candidate(vec![90, 120], vec![50, 70]), vec![1.8, 1.7142857142857142]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to divide two vectors element wise.\nfn div_list(nums1: Vec, nums2: Vec) -> Vec {\n let mut result = Vec::new();\n\n for (num1, num2) in nums1.iter().zip(nums2.iter()) {\n if *num2 != 0 {\n result.push(*num1 as f64 / *num2 as f64);\n } else {\n result.push(std::f64::INFINITY);\n }\n }\n\n result\n}"} -{"name": "mbpp_421_concatenate_tuple", "language": "rs", "prompt": "/// Write a function to concatenate each element of tuple by the delimiter.\nfn concatenate_tuple(test_tup: (String, String, isize, String)) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_421_concatenate_tuple.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "concatenate_tuple", "test": "}\n\nfn main() {\n let candidate = concatenate_tuple;\n assert_eq!(candidate((String::from(\"ID\"), String::from(\"is\"), 4, String::from(\"UTS\"))), String::from(\"ID-is-4-UTS\"));\n assert_eq!(candidate((String::from(\"QWE\"), String::from(\"is\"), 4, String::from(\"RTY\"))), String::from(\"QWE-is-4-RTY\"));\n assert_eq!(candidate((String::from(\"ZEN\"), String::from(\"is\"), 4, String::from(\"OP\"))), String::from(\"ZEN-is-4-OP\"));\n}\n", "solution": "/// Write a function to concatenate each element of tuple by the delimiter.\nfn concatenate_tuple(test_tup: (String, String, isize, String)) -> String {\n let (a, b, c, d) = test_tup;\n format!(\"{},{},{},{}\", a, b, c, d)\n}", "is_solved": true, "reflections": ["The implementation is wrong because there is an extra pair of curly braces in the format string, which expects 5 arguments, but only 4 arguments (a, b, c, d) are provided. This causes a mismatch between the number of placeholders and the actual arguments, leading to the error.", "The implementation is wrong because it does not include the delimiter when concatenating the elements of the tuple. Instead, it directly concatenates the elements without any separation, causing the test cases to fail."]} -{"name": "mbpp_750_add_tuple", "language": "rs", "prompt": "/// Write a function to add the given tuple to the given vector.\nfn add_tuple(test_list: Vec, test_tup: (isize, isize)) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_750_add_tuple.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "add_tuple", "test": "}\n\nfn main() {\n let candidate = add_tuple;\n assert_eq!(candidate(vec![5, 6, 7], (9, 10)), vec![5, 6, 7, 9, 10]);\n assert_eq!(candidate(vec![6, 7, 8], (10, 11)), vec![6, 7, 8, 10, 11]);\n assert_eq!(candidate(vec![7, 8, 9], (11, 12)), vec![7, 8, 9, 11, 12]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to add the given tuple to the given vector.\nfn add_tuple(test_list: Vec, test_tup: (isize, isize)) -> Vec {\n let mut result = test_list.clone();\n result.push(test_tup.0);\n result.push(test_tup.1);\n result\n}"} -{"name": "mbpp_304_find_Element", "language": "rs", "prompt": "/// Write a rsthon function to find element at a given index after number of rotations.\nfn find_Element(arr: Vec, ranges: Vec>, rotations: isize, index: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_304_find_Element.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_Element", "test": "}\n\nfn main() {\n let candidate = find_Element;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5], vec![vec![0, 2], vec![0, 3]], 2, 1), 3);\n assert_eq!(candidate(vec![1, 2, 3, 4], vec![vec![0, 1], vec![0, 2]], 1, 2), 3);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6], vec![vec![0, 1], vec![0, 2]], 1, 1), 1);\n}\n", "solution": "/// Write a rsthon function to find element at a given index after number of rotations.\nfn find_Element(arr: Vec, ranges: Vec>, rotations: isize, index: isize) -> isize {\n let mut arr = arr;\n let n = arr.len();\n let mut temp: Vec = vec![0; n];\n\n // Apply rotations\n for r in &ranges {\n let (left, right) = (r[0] as usize, r[1] as usize);\n let k = rotations % (right - left + 1) as isize;\n\n // Copy the current range to temp\n for i in 0..=right - left {\n temp[i] = arr[left + i];\n }\n\n // Rotate the range in temp\n for i in 0..=right - left {\n let new_index = (i + k as usize) % (right - left + 1);\n temp[new_index] = arr[left + i];\n }\n\n // Copy the rotated range back to arr\n for i in 0..=right - left {\n arr[left + i] = temp[i];\n }\n }\n\n // Return the element at the given index\n arr[index as usize]\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it does not handle multiple rotations properly. The rotations are applied sequentially, but the current implementation does not account for the effect of previous rotations on the subsequent ones. This leads to incorrect results when there are multiple rotations in the input.", "The implementation is incorrect because it does not handle multiple rotations properly. The rotations are applied sequentially, but the previous rotations are not taken into account when calculating the new index for the elements in the array. This leads to incorrect results when there are multiple rotations, as seen in the failed test cases.", "The implementation is wrong because it tries to use the `ranges` variable after it has been moved. The `ranges` variable is moved in the first `for` loop when calling `ranges.into_iter()`. Later, when trying to iterate over `ranges` again using `ranges.iter().rev()`, the compiler throws an error because `ranges` has already been moved. To fix this issue, consider iterating over a slice of the `Vec>`'s content to avoid moving into the `for` loop.", "The implementation is incorrect because it applies the rotations twice, once in the forward direction and then again in the reverse direction, which essentially cancels out the rotations. This leads to the original array being returned without any rotations applied, causing the failed test cases."]} -{"name": "mbpp_740_tuple_to_dict", "language": "rs", "prompt": "use std::collections::HashMap;\n\n/// Write a function to convert the given tuple to a key-value HashMap using adjacent elements. https://www.geeksforgeeks.org/rsthon-convert-tuple-to-adjacent-pair-HashMap/\nfn tuple_to_dict(test_tup: (isize, isize, isize, isize, isize, isize)) -> HashMap {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_740_tuple_to_dict.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "tuple_to_dict", "test": "}\n\nfn main() {\n let candidate = tuple_to_dict;\n assert_eq!(candidate((1, 5, 7, 10, 13, 5)), HashMap::from([(1, 5), (7, 10), (13, 5)]));\n assert_eq!(candidate((1, 2, 3, 4, 5, 6)), HashMap::from([(1, 2), (3, 4), (5, 6)]));\n assert_eq!(candidate((7, 8, 9, 10, 11, 12)), HashMap::from([(7, 8), (9, 10), (11, 12)]));\n}\n", "is_solved": true, "reflections": [], "solution": "use std::collections::HashMap;\n\n/// Write a function to convert the given tuple to a key-value HashMap using adjacent elements. https://www.geeksforgeeks.org/rsthon-convert-tuple-to-adjacent-pair-HashMap/\nfn tuple_to_dict(test_tup: (isize, isize, isize, isize, isize, isize)) -> HashMap {\n let mut result = HashMap::new();\n let tuple_elements = [test_tup.0, test_tup.1, test_tup.2, test_tup.3, test_tup.4, test_tup.5];\n\n for i in (0..tuple_elements.len() - 1).step_by(2) {\n result.insert(tuple_elements[i], tuple_elements[i + 1]);\n }\n\n result\n}"} -{"name": "mbpp_627_find_First_Missing", "language": "rs", "prompt": "/// Write a rsthon function to find the smallest missing number from a sorted vector of natural numbers.\nfn find_First_Missing(array: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_627_find_First_Missing.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_First_Missing", "test": "}\n\nfn main() {\n let candidate = find_First_Missing;\n assert_eq!(candidate(vec![0, 1, 2, 3]), 4);\n assert_eq!(candidate(vec![0, 1, 2, 6, 9]), 3);\n assert_eq!(candidate(vec![2, 3, 5, 8, 9]), 0);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the smallest missing number from a sorted vector of natural numbers.\nfn find_First_Missing(array: Vec) -> isize {\n let mut prev = 0;\n\n for num in array {\n if num > 0 {\n if num - prev > 1 {\n return prev + 1;\n }\n prev = num;\n }\n }\n\n return prev + 1;\n}"} -{"name": "mbpp_165_count_char_position", "language": "rs", "prompt": "/// Write a function to count the number of characters in a string that occur at the same position in the string as in the English alphabet (case insensitive).\nfn count_char_position(str1: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_165_count_char_position.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_char_position", "test": "}\n\nfn main() {\n let candidate = count_char_position;\n assert_eq!(candidate(String::from(\"xbcefg\")), 2);\n assert_eq!(candidate(String::from(\"ABcED\")), 3);\n assert_eq!(candidate(String::from(\"AbgdeF\")), 5);\n}\n", "solution": "/// Write a function to count the number of characters in a string that occur at the same position in the string as in the English alphabet (case insensitive).\nfn count_char_position(str1: String) -> isize {\n let mut count = 0;\n\n for (i, c) in str1.chars().enumerate() {\n if c.is_alphabetic() {\n let c_lower = c.to_ascii_lowercase();\n let alphabet_position = (c_lower as u8) - (b'a') + 1;\n if alphabet_position == (i as u8) + 1 {\n count += 1;\n }\n }\n }\n\n count\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it does not handle uppercase characters properly. The function converts the input string to lowercase, but it does not adjust the alphabet position calculation for uppercase characters. As a result, the function fails to count the characters that occur at the same position in the string as in the English alphabet when they are uppercase.", "The implementation of count_char_position is incorrect because it only counts characters that match their position in the alphabet when the input string is in lowercase. It fails to handle uppercase characters properly, causing the function to return incorrect results for strings containing uppercase characters, as demonstrated by the failed tests.", "The implementation is incorrect because it only counts characters that match their position in the alphabet when the input string is in lowercase. It fails to handle uppercase characters properly, causing the function to return incorrect results for strings containing uppercase characters, as seen in the failed tests.", "The implementation is incorrect because it does not handle non-alphabetic characters properly. When encountering a non-alphabetic character, the calculation for `alphabet_position` results in an incorrect value, causing the comparison to fail even if the character's position matches its position in the alphabet. This issue is evident in the failed test cases, where non-alphabetic characters are present in the input strings."]} -{"name": "mbpp_589_perfect_squares", "language": "rs", "prompt": "/// Write a function to find perfect squares between two given numbers.\nfn perfect_squares(a: isize, b: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_589_perfect_squares.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "perfect_squares", "test": "}\n\nfn main() {\n let candidate = perfect_squares;\n assert_eq!(candidate(1, 30), vec![1, 4, 9, 16, 25]);\n assert_eq!(candidate(50, 100), vec![64, 81, 100]);\n assert_eq!(candidate(100, 200), vec![100, 121, 144, 169, 196]);\n}\n", "solution": "/// Write a function to find perfect squares between two given numbers.\nfn perfect_squares(a: isize, b: isize) -> Vec {\n let mut result = Vec::new();\n\n if a > b {\n return result;\n }\n\n for i in (a as f64).sqrt().ceil() as isize..=(b as f64).sqrt().floor() as isize {\n if i > 0 {\n result.push(i * i);\n }\n }\n\n result\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it does not handle the case when both input numbers are 0. In this case, the function should return an empty vector, but it returns a vector containing 0 instead. This is because the loop starts at 0 and includes 0 as a perfect square."]} -{"name": "mbpp_736_left_insertion", "language": "rs", "prompt": "/// Write a function to locate the left insertion point for a specified value in sorted order. https://www.w3resource.com/rsthon-exercises/data-structures-and-algorithms/rsthon-data-structure-exercise-24.php\nfn left_insertion(a: Vec, x: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_736_left_insertion.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "left_insertion", "test": "}\n\nfn main() {\n let candidate = left_insertion;\n assert_eq!(candidate(vec![1, 2, 4, 5], 6), 4);\n assert_eq!(candidate(vec![1, 2, 4, 5], 3), 2);\n assert_eq!(candidate(vec![1, 2, 4, 5], 7), 4);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to locate the left insertion point for a specified value in sorted order. https://www.w3resource.com/rsthon-exercises/data-structures-and-algorithms/rsthon-data-structure-exercise-24.php\nfn left_insertion(a: Vec, x: isize) -> isize {\n let mut left: isize = 0;\n let mut right: isize = a.len() as isize - 1;\n\n while left <= right {\n let mid = left + (right - left) / 2;\n\n if a[mid as usize] < x {\n left = mid + 1;\n } else {\n right = mid - 1;\n }\n }\n\n left\n}"} +{"name": "mbpp_234_volume_cube", "language": "rs", "prompt": "/// Write a function to find the volume of a cube given its side length.\nfn volume_cube(l: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_234_volume_cube.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "volume_cube", "test": "\n\nfn main() {\n let candidate = volume_cube;\n assert_eq!(candidate(3), 27);\n assert_eq!(candidate(2), 8);\n assert_eq!(candidate(5), 125);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the volume of a cube given its side length.\nfn volume_cube(l: isize) -> isize {\n l.pow(3)\n}"} +{"name": "mbpp_89_closest_num", "language": "rs", "prompt": "/// Write a function to find the closest smaller number than n.\nfn closest_num(N: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_89_closest_num.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "closest_num", "test": "\n\nfn main() {\n let candidate = closest_num;\n assert_eq!(candidate(11), 10);\n assert_eq!(candidate(7), 6);\n assert_eq!(candidate(12), 11);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the closest smaller number than n.\nfn closest_num(N: isize) -> isize {\n let mut closest = N - 1;\n\n while closest >= 0 {\n if closest < N {\n return closest;\n }\n closest -= 1;\n }\n\n 0\n}"} +{"name": "mbpp_245_max_sum", "language": "rs", "prompt": "/// Write a function that takes a vector and finds the maximum sum of a bitonic subsequence for the given vector, where a sequence is bitonic if it is first increasing and then decreasing.\nfn max_sum(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_245_max_sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_sum", "test": "\n\nfn main() {\n let candidate = max_sum;\n assert_eq!(candidate(vec![1, 15, 51, 45, 33, 100, 12, 18, 9]), 194);\n assert_eq!(candidate(vec![80, 60, 30, 40, 20, 10]), 210);\n assert_eq!(candidate(vec![2, 3, 14, 16, 21, 23, 29, 30]), 138);\n}\n", "solution": "/// Write a function that takes a vector and finds the maximum sum of a bitonic subsequence for the given vector, where a sequence is bitonic if it is first increasing and then decreasing.\nfn max_sum(arr: Vec) -> isize {\n let n = arr.len();\n if n == 0 {\n return 0;\n }\n\n let mut inc = vec![0; n];\n let mut dec = vec![0; n];\n\n inc[0] = arr[0];\n dec[n - 1] = arr[n - 1];\n\n for i in 1..n {\n inc[i] = arr[i];\n for j in 0..i {\n if arr[i] > arr[j] {\n inc[i] = inc[i].max(inc[j] + arr[i]);\n }\n }\n }\n\n for i in (0..n - 1).rev() {\n dec[i] = arr[i];\n for j in i + 1..n {\n if arr[i] > arr[j] {\n dec[i] = dec[i].max(dec[j] + arr[i]);\n }\n }\n }\n\n let mut max_sum = inc[0] + dec[0] - arr[0];\n for i in 1..n {\n max_sum = max_sum.max(inc[i] + dec[i] - arr[i]);\n }\n\n for i in 0..n {\n for j in i + 1..n {\n if arr[j] > arr[i] {\n let temp_sum = inc[i] + dec[j];\n max_sum = max_sum.max(temp_sum);\n }\n }\n }\n\n max_sum\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it calculates the maximum sum of a bitonic subsequence by only considering increasing and decreasing subsequences separately. This approach does not account for cases where the optimal bitonic subsequence has a different structure, leading to incorrect results in some test cases.", "The implementation is incorrect because it calculates the maximum sum of bitonic subsequences by considering only the cases where the peak element is included in the sum. It does not account for cases where the peak element is not part of the optimal bitonic subsequence, leading to incorrect results in some test cases.", "The implementation is incorrect because it calculates the maximum sum of bitonic subsequences by considering all possible combinations of increasing and decreasing subsequences, without ensuring that the sequence is first increasing and then decreasing. This leads to incorrect results in some test cases, as the function may return the sum of non-bitonic subsequences.", "The implementation is incorrect because it calculates the maximum sum of bitonic subsequences by considering only the cases where the peak element is included in both increasing and decreasing subsequences. It does not account for cases where the peak element is not shared between the increasing and decreasing subsequences, leading to incorrect results in some test cases."]} +{"name": "mbpp_77_is_Diff", "language": "rs", "prompt": "/// Write a rsthon function to find whether a number is divisible by 11.\nfn is_Diff(n: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_77_is_Diff.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_Diff", "test": "\n\nfn main() {\n let candidate = is_Diff;\n assert_eq!(candidate(12345), false);\n assert_eq!(candidate(1212112), true);\n assert_eq!(candidate(1212), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find whether a number is divisible by 11.\nfn is_Diff(n: isize) -> bool {\n if n.abs() % 11 == 0 {\n return true;\n } else {\n return false;\n }\n}"} +{"name": "mbpp_123_amicable_numbers_sum", "language": "rs", "prompt": "/// Write a function to sum all amicable numbers from 1 to a specified number.\nfn amicable_numbers_sum(limit: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_123_amicable_numbers_sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "amicable_numbers_sum", "test": "\n\nfn main() {\n let candidate = amicable_numbers_sum;\n assert_eq!(candidate(999), 504);\n assert_eq!(candidate(9999), 31626);\n assert_eq!(candidate(99), 0);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to sum all amicable numbers from 1 to a specified number.\nfn amicable_numbers_sum(limit: isize) -> isize {\n fn sum_of_divisors(n: isize) -> isize {\n let mut sum = 1;\n let mut i = 2;\n while i * i <= n {\n if n % i == 0 {\n sum += i;\n if i * i != n {\n sum += n / i;\n }\n }\n i += 1;\n }\n sum\n }\n\n let mut amicable_sum = 0;\n for i in 2..limit {\n let a = sum_of_divisors(i);\n let b = sum_of_divisors(a);\n if i == b && i != a {\n amicable_sum += i;\n }\n }\n amicable_sum\n}"} +{"name": "mbpp_420_cube_Sum", "language": "rs", "prompt": "/// Write a rsthon function to find the cube sum of first n even natural numbers.\nfn cube_Sum(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_420_cube_Sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "cube_Sum", "test": "\n\nfn main() {\n let candidate = cube_Sum;\n assert_eq!(candidate(2), 72);\n assert_eq!(candidate(3), 288);\n assert_eq!(candidate(4), 800);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the cube sum of first n even natural numbers.\nfn cube_Sum(n: isize) -> isize {\n let mut sum = 0;\n\n for i in 1..=n {\n let even_number = 2 * i;\n let cube = even_number * even_number * even_number;\n sum += cube;\n }\n\n sum\n}"} +{"name": "mbpp_20_is_woodall", "language": "rs", "prompt": "/// Write a function to check if the given number is woodball or not.\nfn is_woodall(x: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_20_is_woodall.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_woodall", "test": "\n\nfn main() {\n let candidate = is_woodall;\n assert_eq!(candidate(383), true);\n assert_eq!(candidate(254), false);\n assert_eq!(candidate(200), false);\n}\n", "is_solved": false, "reflections": ["The implementation has several type mismatch issues. The function uses `i32` and `u32` types in arithmetic operations, but the `Mul` trait is not implemented for `i32`. Additionally, the function compares `i32` values with the `isize` input parameter, causing further type mismatch errors. To fix these issues, ensure consistent use of integer types and perform necessary conversions when comparing or performing arithmetic operations.", "The implementation of the is_woodall function is incorrect because the condition to check if a number is a Woodall number is inside the while loop, but it should be checked after the loop increments the value of 'n'. Due to this, the function is unable to identify valid Woodall numbers and returns false for them, causing the failed test cases.", "The implementation of the is_woodall function is incorrect because it does not properly calculate the Woodall numbers. The formula used in the function is (2^n * n) - 1, but the correct formula for Woodall numbers is (2^n * (n - 1)) - 1. This causes the function to return false for valid Woodall numbers like 6 and 12, leading to the failed tests.", "The implementation of the is_woodall function is incorrect because it does not properly calculate the Woodall numbers. The formula used in the function is off by one, as it should be (2^n * (n - 1)) - 1 instead of (2^n * (n - 1)) - 1. This causes the function to fail for valid Woodall numbers like 1, 6, and 12."], "solution": "/// Write a function to check if the given number is woodball or not.\nfn is_woodall(x: isize) -> bool {\n let mut n = 1;\n while (2_isize.pow(n as u32) * (n - 1)) - 1 < x {\n n += 1;\n }\n (2_isize.pow(n as u32) * (n - 1)) - 1 == x\n}"} +{"name": "mbpp_805_max_sum_list", "language": "rs", "prompt": "/// Write a function that returns the vector in a vector of vectors whose sum of elements is the highest.\nfn max_sum_list(lists: Vec>) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_805_max_sum_list.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_sum_list", "test": "\n\nfn main() {\n let candidate = max_sum_list;\n assert_eq!(candidate(vec![vec![1, 2, 3], vec![4, 5, 6], vec![10, 11, 12], vec![7, 8, 9]]), vec![10, 11, 12]);\n assert_eq!(candidate(vec![vec![3, 2, 1], vec![6, 5, 4], vec![12, 11, 10]]), vec![12, 11, 10]);\n assert_eq!(candidate(vec![vec![2, 3, 1]]), vec![2, 3, 1]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function that returns the vector in a vector of vectors whose sum of elements is the highest.\nfn max_sum_list(lists: Vec>) -> Vec {\n let mut max_sum = None;\n let mut max_list = Vec::new();\n\n for list in lists {\n let sum: isize = list.iter().sum();\n if max_sum.is_none() || sum > max_sum.unwrap() {\n max_sum = Some(sum);\n max_list = list;\n }\n }\n\n max_list\n}"} +{"name": "mbpp_806_max_run_uppercase", "language": "rs", "prompt": "/// Write a function to find maximum run of uppercase characters in the given string.\nfn max_run_uppercase(test_str: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_806_max_run_uppercase.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_run_uppercase", "test": "\n\nfn main() {\n let candidate = max_run_uppercase;\n assert_eq!(candidate(String::from(\"GeMKSForGERksISBESt\")), 5);\n assert_eq!(candidate(String::from(\"PrECIOusMOVemENTSYT\")), 6);\n assert_eq!(candidate(String::from(\"GooGLEFluTTER\")), 4);\n}\n", "solution": "/// Write a function to find maximum run of uppercase characters in the given string.\nfn max_run_uppercase(test_str: String) -> isize {\n let mut max_run = 0;\n let mut current_run = 0;\n\n for c in test_str.chars() {\n if c.is_uppercase() {\n current_run += 1;\n if current_run > max_run {\n max_run = current_run;\n }\n } else {\n current_run = 0;\n }\n }\n\n max_run as isize\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it counts the uppercase characters incorrectly. It does not reset the current_run counter properly, leading to an overcount of consecutive uppercase characters in some cases and an undercount in others. This causes the function to fail multiple test cases.", "The implementation of max_run_uppercase is incorrect because it does not properly handle the counting of consecutive uppercase characters. It seems to be off by one in some cases, causing the failed test cases. Additionally, it does not reset the current_run counter when encountering a non-uppercase character, leading to incorrect results.", "The implementation is incorrect because it counts the first uppercase character in the string as part of the current run, even if it's not part of a consecutive sequence of uppercase characters. This causes the function to return a higher count than the actual maximum run of uppercase characters in the given string.", "The implementation is incorrect because it does not properly handle the cases when the string starts with an uppercase character or when there are no uppercase characters in the string. The current logic incorrectly initializes the `current_run` value, leading to incorrect results in these cases."]} +{"name": "mbpp_455_check_monthnumb_number", "language": "rs", "prompt": "/// Write a function to check whether the given month number contains 31 days or not.\nfn check_monthnumb_number(monthnum2: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_455_check_monthnumb_number.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "check_monthnumb_number", "test": "\n\nfn main() {\n let candidate = check_monthnumb_number;\n assert_eq!(candidate(5), true);\n assert_eq!(candidate(2), false);\n assert_eq!(candidate(6), false);\n}\n", "solution": "/// Write a function to check whether the given month number contains 31 days or not.\nfn check_monthnumb_number(monthnum2: isize) -> bool {\n match monthnum2 {\n 1 | 3 | 5 | 7 | 8 | 10 | 12 => true,\n 4 | 6 | 9 | 11 => false,\n _ => false,\n }\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it panics when an invalid month number is provided, instead of returning false as expected by the failed test. The function should be updated to return false for invalid month numbers."]} +{"name": "mbpp_577_last_Digit_Factorial", "language": "rs", "prompt": "/// Write a rsthon function to find the last digit in factorial of a given number.\nfn last_Digit_Factorial(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_577_last_Digit_Factorial.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "last_Digit_Factorial", "test": "\n\nfn main() {\n let candidate = last_Digit_Factorial;\n assert_eq!(candidate(4), 4);\n assert_eq!(candidate(21), 0);\n assert_eq!(candidate(30), 0);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the last digit in factorial of a given number.\nfn last_Digit_Factorial(n: isize) -> isize {\n if n < 0 {\n return -1;\n }\n\n if n == 0 || n == 1 {\n return 1;\n }\n\n let mut last_digit = 1;\n for i in 2..=n {\n last_digit = (last_digit * i) % 10;\n }\n\n last_digit\n}"} +{"name": "mbpp_555_difference", "language": "rs", "prompt": "/// Write a rsthon function to find the difference between the sum of cubes of the first n natural numbers and the sum of the first n natural numbers.\nfn difference(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_555_difference.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "difference", "test": "\n\nfn main() {\n let candidate = difference;\n assert_eq!(candidate(3), 30);\n assert_eq!(candidate(5), 210);\n assert_eq!(candidate(2), 6);\n}\n", "is_solved": false, "reflections": ["The implementation is wrong because the formula for sum_of_cubes and sum_of_natural_numbers are swapped. The sum_of_cubes should use the formula n * (n + 1) * (2 * n + 1) / 6, and the sum_of_natural_numbers should use the formula (n * (n + 1) / 2).pow(2). This causes the difference calculation to be incorrect, leading to failed test cases.", "The implementation of the `difference` function is incorrect because it calculates the sum of cubes and the sum of natural numbers using incorrect formulas. The formula for the sum of cubes should be (n * (n + 1) / 2)^2, and the formula for the sum of natural numbers should be n * (n + 1) * (2 * n + 1) / 6. The current implementation has these formulas swapped, causing the function to produce incorrect results.", "The implementation is incorrect because the formula for sum_of_cubes and sum_of_natural_numbers are swapped. The sum_of_cubes should use the formula n * (n + 1) * (2 * n + 1) / 6, and the sum_of_natural_numbers should use the formula (n * (n + 1) / 2).pow(2). This causes the difference calculation to produce incorrect results.", "The implementation of the `difference` function is incorrect because it calculates the difference between the sum of cubes and the sum of natural numbers in the wrong order. The function should return the difference between the square of the sum of the first n natural numbers and the sum of the cubes of the first n natural numbers, but it currently returns the difference in the opposite order. This is why the test cases are failing."], "solution": "/// Write a rsthon function to find the difference between the sum of cubes of the first n natural numbers and the sum of the first n natural numbers.\nfn difference(n: isize) -> isize {\n let sum_of_cubes = n * (n + 1) * (2 * n + 1) / 6;\n let sum_of_natural_numbers = (n * (n + 1) / 2).pow(2);\n\n sum_of_natural_numbers - sum_of_cubes\n}"} +{"name": "mbpp_456_reverse_string_list", "language": "rs", "prompt": "/// Write a function to reverse each string in a given vector of string values.\nfn reverse_string_list(stringlist: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_456_reverse_string_list.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "reverse_string_list", "test": "\n\nfn main() {\n let candidate = reverse_string_list;\n assert_eq!(candidate(vec![String::from(\"Red\"), String::from(\"Green\"), String::from(\"Blue\"), String::from(\"White\"), String::from(\"Black\")]), vec![String::from(\"deR\"), String::from(\"neerG\"), String::from(\"eulB\"), String::from(\"etihW\"), String::from(\"kcalB\")]);\n assert_eq!(candidate(vec![String::from(\"john\"), String::from(\"amal\"), String::from(\"joel\"), String::from(\"george\")]), vec![String::from(\"nhoj\"), String::from(\"lama\"), String::from(\"leoj\"), String::from(\"egroeg\")]);\n assert_eq!(candidate(vec![String::from(\"jack\"), String::from(\"john\"), String::from(\"mary\")]), vec![String::from(\"kcaj\"), String::from(\"nhoj\"), String::from(\"yram\")]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to reverse each string in a given vector of string values.\nfn reverse_string_list(stringlist: Vec) -> Vec {\n stringlist.into_iter().map(|s| s.chars().rev().collect()).collect()\n}"} +{"name": "mbpp_12_sort_matrix", "language": "rs", "prompt": "/// Write a function to sort a given matrix in ascending order according to the sum of its rows.\nfn sort_matrix(M: Vec>) -> Vec> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_12_sort_matrix.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sort_matrix", "test": "\n\nfn main() {\n let candidate = sort_matrix;\n assert_eq!(candidate(vec![vec![1, 2, 3], vec![2, 4, 5], vec![1, 1, 1]]), vec![vec![1, 1, 1], vec![1, 2, 3], vec![2, 4, 5]]);\n assert_eq!(candidate(vec![vec![1, 2, 3], vec![-2, 4, -5], vec![1, -1, 1]]), vec![vec![-2, 4, -5], vec![1, -1, 1], vec![1, 2, 3]]);\n assert_eq!(candidate(vec![vec![5, 8, 9], vec![6, 4, 3], vec![2, 1, 4]]), vec![vec![2, 1, 4], vec![6, 4, 3], vec![5, 8, 9]]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to sort a given matrix in ascending order according to the sum of its rows.\nfn sort_matrix(M: Vec>) -> Vec> {\n let mut sorted_matrix = M.clone();\n sorted_matrix.sort_by_key(|row| row.iter().sum::());\n sorted_matrix\n}"} +{"name": "mbpp_584_find_adverbs", "language": "rs", "prompt": "/// Write a function to find the first adverb ending with ly and its positions in a given string.\nfn find_adverbs(text: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_584_find_adverbs.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_adverbs", "test": "\n\nfn main() {\n let candidate = find_adverbs;\n assert_eq!(candidate(String::from(\"Clearly, he has no excuse for such behavior.\")), String::from(\"0-7: Clearly\"));\n assert_eq!(candidate(String::from(\"Please handle the situation carefuly\")), String::from(\"28-36: carefuly\"));\n assert_eq!(candidate(String::from(\"Complete the task quickly\")), String::from(\"18-25: quickly\"));\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because it returns the adverb with its position in the format \"adverb at position X\", while the expected format is \"adverb (X)\". Additionally, the position is off by one in some cases, as it counts words instead of considering the actual position of the adverb in the sentence.", "The implementation is incorrect because it calculates the position of the adverb based on the sum of the lengths of the words and spaces encountered so far. This leads to incorrect position values in the output. The position should be calculated based on the index of the adverb in the sentence (1-based index), not the character position.", "The implementation is incorrect because it calculates the position of the adverb in the given string based on the index of the words in the split string, rather than the actual position of the adverb in the original string. This causes the position to be off by one or more depending on the number of spaces before the adverb.", "The implementation is incorrect because it calculates the position of the adverb in the text based on the length of the words and spaces, rather than counting the actual position of the words in the sentence. This leads to incorrect position values in the output, causing the failed test cases."], "solution": "/// Write a function to find the first adverb ending with ly and its positions in a given string.\nfn find_adverbs(text: String) -> String {\n let words = text.split_whitespace();\n let mut result = String::new();\n let mut position = 1;\n\n for word in words {\n if word.ends_with(\"ly\") {\n let index = text.find(word).unwrap();\n result = format!(\"{} ({})\", word, position);\n break;\n }\n position += 1;\n }\n\n result\n}"} +{"name": "mbpp_86_centered_hexagonal_number", "language": "rs", "prompt": "/// Write a function to find nth centered hexagonal number.\nfn centered_hexagonal_number(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_86_centered_hexagonal_number.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "centered_hexagonal_number", "test": "\n\nfn main() {\n let candidate = centered_hexagonal_number;\n assert_eq!(candidate(10), 271);\n assert_eq!(candidate(2), 7);\n assert_eq!(candidate(9), 217);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find nth centered hexagonal number.\nfn centered_hexagonal_number(n: isize) -> isize {\n if n <= 0 {\n return 0;\n }\n (3 * n * (n - 1)) + 1\n}"} +{"name": "mbpp_130_max_occurrences", "language": "rs", "prompt": "/// Write a function to find the item with maximum frequency in a given vector.\nfn max_occurrences(nums: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_130_max_occurrences.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_occurrences", "test": "\n\nfn main() {\n let candidate = max_occurrences;\n assert_eq!(candidate(vec![2, 3, 8, 4, 7, 9, 8, 2, 6, 5, 1, 6, 1, 2, 3, 2, 4, 6, 9, 1, 2]), 2);\n assert_eq!(candidate(vec![2, 3, 8, 4, 7, 9, 8, 7, 9, 15, 14, 10, 12, 13, 16, 18]), 8);\n assert_eq!(candidate(vec![10, 20, 20, 30, 40, 90, 80, 50, 30, 20, 50, 10]), 20);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the item with maximum frequency in a given vector.\nfn max_occurrences(nums: Vec) -> isize {\n let mut occurrences = std::collections::HashMap::new();\n\n for num in nums {\n let count = occurrences.entry(num).or_insert(0);\n *count += 1;\n }\n\n let mut max_occurrences = 0;\n let mut max_num = 0;\n\n for (num, count) in occurrences {\n if count > max_occurrences {\n max_occurrences = count;\n max_num = num;\n }\n }\n\n max_num\n}"} +{"name": "mbpp_742_area_tetrahedron", "language": "rs", "prompt": "/// Write a function to caluclate the area of a tetrahedron.\nfn area_tetrahedron(side: isize) -> f64 {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_742_area_tetrahedron.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "area_tetrahedron", "test": "\n\nfn main() {\n let candidate = area_tetrahedron;\n assert_eq!(candidate(3), 15.588457268119894);\n assert_eq!(candidate(20), 692.8203230275509);\n assert_eq!(candidate(10), 173.20508075688772);\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because it calculates the area of an equilateral triangle instead of the surface area of a tetrahedron. The surface area of a tetrahedron should be calculated as the area of one equilateral triangle multiplied by 4, since a tetrahedron has four equilateral triangle faces.", "The implementation is incorrect because it calculates the surface area of the tetrahedron instead of the volume. The failed tests show that the output values are much larger than the expected volume values, indicating that the surface area is being calculated.", "The implementation is incorrect because it calculates the volume of the tetrahedron instead of the surface area. The formula used is for volume, not area, which is why the test cases are failing.", "The implementation is incorrect because it calculates the area of an equilateral triangle instead of the volume of a tetrahedron. The formula used is for the area of an equilateral triangle (side^2 * sqrt(3) / 4), while the correct formula for the volume of a tetrahedron is (side^3 * sqrt(2) / 12). This is why the test cases are failing."], "solution": "/// Write a function to caluclate the area of a tetrahedron.\nfn area_tetrahedron(side: isize) -> f64 {\n let sqrt_2 = (2.0 as f64).sqrt();\n let volume_tetrahedron = (side * side * side) as f64 * sqrt_2 / 12.0;\n volume_tetrahedron\n}"} +{"name": "mbpp_610_remove_kth_element", "language": "rs", "prompt": "/// Write a rsthon function which takes a vector and returns a vector with the same elements, but the k'th element removed.\nfn remove_kth_element(list1: Vec, L: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_610_remove_kth_element.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "remove_kth_element", "test": "\n\nfn main() {\n let candidate = remove_kth_element;\n assert_eq!(candidate(vec![1, 1, 2, 3, 4, 4, 5, 1], 3), vec![1, 1, 3, 4, 4, 5, 1]);\n assert_eq!(candidate(vec![0, 0, 1, 2, 3, 4, 4, 5, 6, 6, 6, 7, 8, 9, 4, 4], 4), vec![0, 0, 1, 3, 4, 4, 5, 6, 6, 6, 7, 8, 9, 4, 4]);\n assert_eq!(candidate(vec![10, 10, 15, 19, 18, 18, 17, 26, 26, 17, 18, 10], 5), vec![10, 10, 15, 19, 18, 17, 26, 26, 17, 18, 10]);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a rsthon function which takes a vector and returns a vector with the same elements, but the k'th element removed.\nfn remove_kth_element(list1: Vec, L: isize) -> Vec {\n let mut result = Vec::new();\n let k = L as usize;\n\n for (index, &item) in list1.iter().enumerate() {\n if index != k {\n result.push(item);\n }\n }\n\n result\n}"} +{"name": "mbpp_394_check_distinct", "language": "rs", "prompt": "/// Write a function to check if given vector contains no duplicates.\nfn check_distinct(test_tup: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_394_check_distinct.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "check_distinct", "test": "\n\nfn main() {\n let candidate = check_distinct;\n assert_eq!(candidate(vec![1, 4, 5, 6, 1, 4]), false);\n assert_eq!(candidate(vec![1, 4, 5, 6]), true);\n assert_eq!(candidate(vec![2, 3, 4, 5, 6]), true);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check if given vector contains no duplicates.\nfn check_distinct(test_tup: Vec) -> bool {\n let mut seen = std::collections::HashSet::new();\n\n for &value in test_tup.iter() {\n if seen.contains(&value) {\n return false;\n } else {\n seen.insert(value);\n }\n }\n\n true\n}"} +{"name": "mbpp_793_last", "language": "rs", "prompt": "/// Write a rsthon function to find the last position of an element in a sorted vector.\nfn last(arr: Vec, x: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_793_last.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "last", "test": "\n\nfn main() {\n let candidate = last;\n assert_eq!(candidate(vec![1, 2, 3], 1), 0);\n assert_eq!(candidate(vec![1, 1, 1, 2, 3, 4], 1), 2);\n assert_eq!(candidate(vec![2, 3, 2, 3, 6, 8, 9], 3), 3);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the last position of an element in a sorted vector.\nfn last(arr: Vec, x: isize) -> isize {\n if arr.is_empty() {\n return -1;\n }\n\n let mut left = 0;\n let mut right = arr.len() - 1;\n let mut result = -1;\n\n while left <= right {\n let mid = left + (right - left) / 2;\n\n if arr[mid] == x {\n result = mid as isize;\n left = mid + 1;\n } else if arr[mid] < x {\n left = mid + 1;\n } else {\n right = mid - 1;\n }\n }\n\n result\n}"} +{"name": "mbpp_728_sum_list", "language": "rs", "prompt": "/// Write a function takes as input two vectors [a_1,...,a_n], [b_1,...,b_n] and returns [a_1+b_1,...,a_n+b_n].\nfn sum_list(lst1: Vec, lst2: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_728_sum_list.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sum_list", "test": "\n\nfn main() {\n let candidate = sum_list;\n assert_eq!(candidate(vec![10, 20, 30], vec![15, 25, 35]), vec![25, 45, 65]);\n assert_eq!(candidate(vec![1, 2, 3], vec![5, 6, 7]), vec![6, 8, 10]);\n assert_eq!(candidate(vec![15, 20, 30], vec![15, 45, 75]), vec![30, 65, 105]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function takes as input two vectors [a_1,...,a_n], [b_1,...,b_n] and returns [a_1+b_1,...,a_n+b_n].\nfn sum_list(lst1: Vec, lst2: Vec) -> Vec {\n let mut result: Vec = Vec::new();\n\n for (a, b) in lst1.iter().zip(lst2.iter()) {\n result.push(a + b);\n }\n\n result\n}"} +{"name": "mbpp_566_sum_digits", "language": "rs", "prompt": "/// Write a function to get the sum of the digits of a non-negative integer.\nfn sum_digits(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_566_sum_digits.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sum_digits", "test": "\n\nfn main() {\n let candidate = sum_digits;\n assert_eq!(candidate(345), 12);\n assert_eq!(candidate(12), 3);\n assert_eq!(candidate(97), 16);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to get the sum of the digits of a non-negative integer.\nfn sum_digits(n: isize) -> isize {\n assert!(n >= 0, \"Input must be a non-negative integer\");\n\n let mut sum = 0;\n let mut num = n;\n\n while num > 0 {\n sum += num % 10;\n num /= 10;\n }\n\n sum\n}"} +{"name": "mbpp_290_max_length", "language": "rs", "prompt": "/// Write a function to find the vector of maximum length in a vector of vectors.\nfn max_length(list1: Vec>) -> (isize, Vec) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_290_max_length.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_length", "test": "\n\nfn main() {\n let candidate = max_length;\n assert_eq!(candidate(vec![vec![0], vec![1, 3], vec![5, 7], vec![9, 11], vec![13, 15, 17]]), (3, vec![13, 15, 17]));\n assert_eq!(candidate(vec![vec![1], vec![5, 7], vec![10, 12, 14, 15]]), (4, vec![10, 12, 14, 15]));\n assert_eq!(candidate(vec![vec![5], vec![15, 20, 25]]), (3, vec![15, 20, 25]));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the vector of maximum length in a vector of vectors.\nfn max_length(list1: Vec>) -> (isize, Vec) {\n let mut max_length = 0;\n let mut max_vector = Vec::new();\n\n for vec in list1 {\n let length = vec.len();\n if length > max_length {\n max_length = length;\n max_vector = vec;\n }\n }\n\n (max_length as isize, max_vector)\n}"} +{"name": "mbpp_628_replace_spaces", "language": "rs", "prompt": "/// Write a function to replace all spaces in the given string with '%20'.\nfn replace_spaces(string: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_628_replace_spaces.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "replace_spaces", "test": "\n\nfn main() {\n let candidate = replace_spaces;\n assert_eq!(candidate(String::from(\"My Name is Dawood\")), String::from(\"My%20Name%20is%20Dawood\"));\n assert_eq!(candidate(String::from(\"I am a Programmer\")), String::from(\"I%20am%20a%20Programmer\"));\n assert_eq!(candidate(String::from(\"I love Coding\")), String::from(\"I%20love%20Coding\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to replace all spaces in the given string with '%20'.\nfn replace_spaces(string: String) -> String {\n string.replace(\" \", \"%20\")\n}"} +{"name": "mbpp_417_group_tuples", "language": "rs", "prompt": "/// Write a function to find common first element in given vector of vectors.\nfn group_tuples(Input: Vec>) -> Vec> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_417_group_tuples.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "group_tuples", "test": "\n\nfn main() {\n let candidate = group_tuples;\n assert_eq!(candidate(vec![vec![String::from(\"x\"), String::from(\"y\")], vec![String::from(\"x\"), String::from(\"z\")], vec![String::from(\"w\"), String::from(\"t\")]]), vec![vec![String::from(\"x\"), String::from(\"y\"), String::from(\"z\")], vec![String::from(\"w\"), String::from(\"t\")]]);\n assert_eq!(candidate(vec![vec![String::from(\"a\"), String::from(\"b\")], vec![String::from(\"a\"), String::from(\"c\")], vec![String::from(\"d\"), String::from(\"e\")]]), vec![vec![String::from(\"a\"), String::from(\"b\"), String::from(\"c\")], vec![String::from(\"d\"), String::from(\"e\")]]);\n assert_eq!(candidate(vec![vec![String::from(\"f\"), String::from(\"g\")], vec![String::from(\"f\"), String::from(\"g\")], vec![String::from(\"h\"), String::from(\"i\")]]), vec![vec![String::from(\"f\"), String::from(\"g\"), String::from(\"g\")], vec![String::from(\"h\"), String::from(\"i\")]]);\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because the `HashMap` type is not found in the current scope. This is because the `std::collections::HashMap` module has not been imported. To fix this issue, the `HashMap` module needs to be imported by adding `use std::collections::HashMap;` at the beginning of the code.", "The implementation is wrong because the function is trying to push a `Vec>` into the `result` vector, which is of type `Vec>`. The types are mismatched, causing the error. The function should push the inner vectors of `group` into the `result` vector instead of the entire `group`.", "The implementation is incorrect because it is not merging the groups with the same first element into a single vector. Instead, it is just appending the groups to the result vector, maintaining their original structure. This causes the failed test cases, as the expected output has the groups with the same first element combined into one vector.", "The implementation is incorrect because it is not grouping the input vectors based on their first element properly. Instead of appending the entire group to the existing group, it is creating a new vector with the first element and each subsequent element, causing duplicates of the first element in the output. This leads to failed assertions where the expected output does not match the actual output."], "solution": "/// Write a function to find common first element in given vector of vectors.\nfn group_tuples(Input: Vec>) -> Vec> {\n use std::collections::HashMap;\n\n let mut result: Vec> = Vec::new();\n\n // Create a hashmap to store the first elements and their corresponding groups\n let mut groups: HashMap>> = HashMap::new();\n\n // Iterate through the input vector of vectors\n for group in Input {\n if let Some(first_element) = group.first() {\n // If the first element is already in the hashmap, add the group to its corresponding vector\n if let Some(existing_group) = groups.get_mut(first_element) {\n existing_group.push(group);\n } else {\n // If the first element is not in the hashmap, create a new entry with the group\n groups.insert(first_element.clone(), vec![group]);\n }\n }\n }\n\n // Add the grouped vectors to the result vector\n for (_, group) in groups {\n let mut combined_group: Vec = Vec::new();\n for inner_group in group {\n combined_group.extend(inner_group);\n }\n result.push(combined_group);\n }\n\n result\n}"} +{"name": "mbpp_286_max_sub_array_sum_repeated", "language": "rs", "prompt": "/// Write a function to find the largest sum of a contiguous vector in the modified vector which is formed by repeating the given vector k times.\nfn max_sub_array_sum_repeated(a: Vec, n: isize, k: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_286_max_sub_array_sum_repeated.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_sub_array_sum_repeated", "test": "\n\nfn main() {\n let candidate = max_sub_array_sum_repeated;\n assert_eq!(candidate(vec![10, 20, -30, -1], 4, 3), 30);\n assert_eq!(candidate(vec![-1, 10, 20], 3, 2), 59);\n assert_eq!(candidate(vec![-1, -2, -3], 3, 3), -1);\n}\n", "solution": "/// Write a function to find the largest sum of a contiguous vector in the modified vector which is formed by repeating the given vector k times.\nfn max_sub_array_sum_repeated(a: Vec, n: isize, k: isize) -> isize {\n let mut max_so_far = a[0];\n let mut curr_max = a[0];\n\n for i in 1..(n as usize) {\n curr_max = isize::max(a[i], curr_max + a[i]);\n max_so_far = isize::max(max_so_far, curr_max);\n }\n\n if k == 1 {\n return max_so_far;\n }\n\n let mut prefix_sum = a[0];\n let mut suffix_sum = a[(n - 1) as usize];\n let mut max_prefix_sum = prefix_sum;\n let mut max_suffix_sum = suffix_sum;\n\n for i in 1..(n as usize) {\n prefix_sum += a[i];\n max_prefix_sum = isize::max(max_prefix_sum, prefix_sum);\n\n suffix_sum += a[((n - (i as isize) - 1) as usize)];\n max_suffix_sum = isize::max(max_suffix_sum, suffix_sum);\n }\n\n let total_sum = prefix_sum;\n let max_sum_with_k = isize::max(max_so_far, max_prefix_sum + max_suffix_sum + (total_sum * (k - 2)));\n\n if k > 2 {\n let max_sum_with_k_minus_1 = isize::max(max_so_far, max_prefix_sum + max_suffix_sum + (total_sum * (k - 3)));\n return isize::max(max_sum_with_k, max_sum_with_k_minus_1);\n }\n\n max_sum_with_k\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it tries to subtract a `usize` from an `isize`, which is not allowed. The error occurs at line 25, where the expression `(n - i - 1)` has a mismatched type, as `n` is an `isize` and `i` is a `usize`. The subtraction operation is not implemented for these types, causing the compilation error.", "The implementation is incorrect because it does not properly handle cases where the maximum subarray sum is formed by combining elements from different repetitions of the input vector. Additionally, it does not handle cases where the maximum subarray sum is formed by a subarray that spans across the original vector's boundaries. This leads to incorrect results for some test cases, as seen in the failed tests.", "The implementation is incorrect because it does not properly handle cases where the maximum subarray sum is formed by combining elements from different repetitions of the input vector. Additionally, the calculation for max_sum_with_k_minus_1 is incorrect, as it should multiply total_sum by (k - 2) instead of (k - 3). This leads to incorrect results for some test cases.", "The implementation is incorrect because it does not properly handle cases where the maximum sum is achieved by combining prefix and suffix sums with the total sum of the vector. The calculation for `max_sum_with_k_minus_1` is also incorrect, as it uses the same formula as `max_sum_with_k`, which does not account for the difference in repetitions. This leads to incorrect results in some test cases."]} +{"name": "mbpp_66_pos_count", "language": "rs", "prompt": "/// Write a rsthon function to count the number of positive numbers in a vector.\nfn pos_count(list: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_66_pos_count.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "pos_count", "test": "\n\nfn main() {\n let candidate = pos_count;\n assert_eq!(candidate(vec![1, -2, 3, -4]), 2);\n assert_eq!(candidate(vec![3, 4, 5, -1]), 3);\n assert_eq!(candidate(vec![1, 2, 3, 4]), 4);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to count the number of positive numbers in a vector.\nfn pos_count(list: Vec) -> isize {\n let mut count = 0;\n\n for num in list {\n if num > 0 {\n count += 1;\n }\n }\n\n count\n}"} +{"name": "mbpp_450_extract_string", "language": "rs", "prompt": "/// Write a function to extract specified size of strings from a given vector of string values.\nfn extract_string(str: Vec, l: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_450_extract_string.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "extract_string", "test": "\n\nfn main() {\n let candidate = extract_string;\n assert_eq!(candidate(vec![String::from(\"Python\"), String::from(\"list\"), String::from(\"exercises\"), String::from(\"practice\"), String::from(\"solution\")], 8), vec![String::from(\"practice\"), String::from(\"solution\")]);\n assert_eq!(candidate(vec![String::from(\"Python\"), String::from(\"list\"), String::from(\"exercises\"), String::from(\"practice\"), String::from(\"solution\")], 6), vec![String::from(\"Python\")]);\n assert_eq!(candidate(vec![String::from(\"Python\"), String::from(\"list\"), String::from(\"exercises\"), String::from(\"practice\"), String::from(\"solution\")], 9), vec![String::from(\"exercises\")]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to extract specified size of strings from a given vector of string values.\nfn extract_string(str: Vec, l: isize) -> Vec {\n let mut result = Vec::new();\n\n for s in str {\n if s.len() as isize == l {\n result.push(s);\n }\n }\n\n result\n}"} +{"name": "mbpp_444_trim_tuple", "language": "rs", "prompt": "/// Write a function to trim each vector by k in the given vectors.\nfn trim_tuple(test_list: Vec>, K: isize) -> Vec> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_444_trim_tuple.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "trim_tuple", "test": "\n\nfn main() {\n let candidate = trim_tuple;\n assert_eq!(candidate(vec![vec![5, 3, 2, 1, 4], vec![3, 4, 9, 2, 1], vec![9, 1, 2, 3, 5], vec![4, 8, 2, 1, 7]], 2), vec![vec![2], vec![9], vec![2], vec![2]]);\n assert_eq!(candidate(vec![vec![5, 3, 2, 1, 4], vec![3, 4, 9, 2, 1], vec![9, 1, 2, 3, 5], vec![4, 8, 2, 1, 7]], 1), vec![vec![3, 2, 1], vec![4, 9, 2], vec![1, 2, 3], vec![8, 2, 1]]);\n assert_eq!(candidate(vec![vec![7, 8, 4, 9], vec![11, 8, 12, 4], vec![4, 1, 7, 8], vec![3, 6, 9, 7]], 1), vec![vec![8, 4], vec![8, 12], vec![1, 7], vec![6, 9]]);\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because it trims the vectors to the length of K instead of removing K elements from each vector. This results in the output vectors having incorrect lengths and elements, causing the test cases to fail.", "The implementation is incorrect because it removes the first K elements from each vector instead of trimming each vector by K elements, leaving the remaining elements intact. This causes the output to be different from the expected results in the failed tests.", "The implementation is incorrect because it trims the vectors to the length of K instead of removing K elements from each vector. This results in the output vectors having the wrong lengths and elements, causing the test cases to fail.", "The implementation is incorrect because it removes the first K elements from each vector instead of trimming each vector by K elements. This causes the output to have the wrong elements remaining in the vectors after the trimming operation."], "solution": "/// Write a function to trim each vector by k in the given vectors.\nfn trim_tuple(test_list: Vec>, K: isize) -> Vec> {\n test_list\n .into_iter()\n .map(|mut vec| {\n if vec.len() > K as usize {\n vec.truncate(K as usize);\n }\n vec\n })\n .collect()\n}"} +{"name": "mbpp_439_multiple_to_single", "language": "rs", "prompt": "/// Write a function to join a vector of multiple integers into a single integer.\nfn multiple_to_single(L: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_439_multiple_to_single.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "multiple_to_single", "test": "\n\nfn main() {\n let candidate = multiple_to_single;\n assert_eq!(candidate(vec![11, 33, 50]), 113350);\n assert_eq!(candidate(vec![-1, 2, 3, 4, 5, 6]), -123456);\n assert_eq!(candidate(vec![10, 15, 20, 25]), 10152025);\n}\n", "solution": "/// Write a function to join a vector of multiple integers into a single integer.\nfn multiple_to_single(L: Vec) -> isize {\n let mut result = String::new();\n for num in L {\n result.push_str(&num.to_string());\n }\n if result.is_empty() {\n return 0;\n }\n result.parse::().unwrap()\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it does not handle the case when the input vector is empty. When the input vector is empty, the `result` string remains empty, and calling `unwrap()` on an empty string while trying to parse it as an integer results in a `ParseIntError`."]} +{"name": "mbpp_162_sum_series", "language": "rs", "prompt": "/// Write a function to calculate the sum (n - 2*i) from i=0 to n // 2, for instance n + (n-2) + (n-4)... (until n-x =< 0).\nfn sum_series(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_162_sum_series.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sum_series", "test": "\n\nfn main() {\n let candidate = sum_series;\n assert_eq!(candidate(6), 12);\n assert_eq!(candidate(10), 30);\n assert_eq!(candidate(9), 25);\n}\n", "is_solved": false, "reflections": ["The implementation of the sum_series function is incorrect because it calculates the sum using a while loop with the condition (n - 2 * i >= 0). This condition causes the loop to stop one iteration early, resulting in a lower sum than expected. This is evident in the failed test case where the output is 2550 instead of the expected 2600.", "The implementation of the sum_series function is incorrect because it adds an extra term (n - 2 * i) after the while loop, causing the sum to be off by one term. This results in the failed test cases where the output is one less than the expected value.", "The implementation of the sum_series function is incorrect because it uses a strict inequality (>) in the while loop condition, causing the loop to terminate one iteration early when n is an even number. This results in the final term (n - 2*i) not being added to the sum when it should be, leading to an incorrect output for even values of n.", "The implementation of the sum_series function is incorrect because it calculates the sum of the series (n - 2*i) only until the value of n - 2*i is greater than or equal to 0. This causes the function to miss the last term in the series when n is an even number, leading to an incorrect result for the test case with n = 100."], "solution": "/// Write a function to calculate the sum (n - 2*i) from i=0 to n // 2, for instance n + (n-2) + (n-4)... (until n-x =< 0).\nfn sum_series(n: isize) -> isize {\n let mut sum = 0;\n let mut i = 0;\n\n while n - 2 * i >= 0 {\n sum += n - 2 * i;\n i += 1;\n }\n\n if n % 2 == 0 {\n sum += n / 2;\n }\n\n sum\n}"} +{"name": "mbpp_224_count_Set_Bits", "language": "rs", "prompt": "/// Write a rsthon function to count the number of set bits (binary digits with value 1) in a given number.\nfn count_Set_Bits(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_224_count_Set_Bits.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_Set_Bits", "test": "\n\nfn main() {\n let candidate = count_Set_Bits;\n assert_eq!(candidate(2), 1);\n assert_eq!(candidate(4), 1);\n assert_eq!(candidate(6), 2);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to count the number of set bits (binary digits with value 1) in a given number.\nfn count_Set_Bits(n: isize) -> isize {\n let mut count = 0;\n let mut num = n;\n\n while num > 0 {\n count += num & 1;\n num >>= 1;\n }\n\n count as isize\n}"} +{"name": "mbpp_309_maximum", "language": "rs", "prompt": "/// Write a rsthon function to find the maximum of two numbers.\nfn maximum(a: isize, b: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_309_maximum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "maximum", "test": "\n\nfn main() {\n let candidate = maximum;\n assert_eq!(candidate(5, 10), 10);\n assert_eq!(candidate(-1, -2), -1);\n assert_eq!(candidate(9, 7), 9);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the maximum of two numbers.\nfn maximum(a: isize, b: isize) -> isize {\n if a > b {\n a\n } else {\n b\n }\n}"} +{"name": "mbpp_632_move_zero", "language": "rs", "prompt": "/// Write a rsthon function to move all zeroes to the end of the given vector.\nfn move_zero(num_list: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_632_move_zero.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "move_zero", "test": "\n\nfn main() {\n let candidate = move_zero;\n assert_eq!(candidate(vec![1, 0, 2, 0, 3, 4]), vec![1, 2, 3, 4, 0, 0]);\n assert_eq!(candidate(vec![2, 3, 2, 0, 0, 4, 0, 5, 0]), vec![2, 3, 2, 4, 5, 0, 0, 0, 0]);\n assert_eq!(candidate(vec![0, 1, 0, 1, 1]), vec![1, 1, 1, 0, 0]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to move all zeroes to the end of the given vector.\nfn move_zero(num_list: Vec) -> Vec {\n let mut non_zero_elements: Vec = Vec::new();\n let mut zero_count = 0;\n\n for num in num_list {\n if num == 0 {\n zero_count += 1;\n } else {\n non_zero_elements.push(num);\n }\n }\n\n for _ in 0..zero_count {\n non_zero_elements.push(0);\n }\n\n non_zero_elements\n}"} +{"name": "mbpp_168_frequency", "language": "rs", "prompt": "/// Write a function to count the number of occurrences of a number in a given vector.\nfn frequency(a: Vec, x: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_168_frequency.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "frequency", "test": "\n\nfn main() {\n let candidate = frequency;\n assert_eq!(candidate(vec![1, 2, 3], 4), 0);\n assert_eq!(candidate(vec![1, 2, 2, 3, 3, 3, 4], 3), 3);\n assert_eq!(candidate(vec![0, 1, 2, 3, 1, 2], 1), 2);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to count the number of occurrences of a number in a given vector.\nfn frequency(a: Vec, x: isize) -> isize {\n let mut count = 0;\n for &num in a.iter() {\n if num == x {\n count += 1;\n }\n }\n count\n}"} +{"name": "mbpp_749_sort_numeric_strings", "language": "rs", "prompt": "/// Write a function to sort a given vector of strings of numbers numerically. https://www.geeksforgeeks.org/rsthon-sort-numeric-strings-in-a-vector/\nfn sort_numeric_strings(nums_str: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_749_sort_numeric_strings.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sort_numeric_strings", "test": "\n\nfn main() {\n let candidate = sort_numeric_strings;\n assert_eq!(candidate(vec![String::from(\"4\"), String::from(\"12\"), String::from(\"45\"), String::from(\"7\"), String::from(\"0\"), String::from(\"100\"), String::from(\"200\"), String::from(\"-12\"), String::from(\"-500\")]), vec![-500, -12, 0, 4, 7, 12, 45, 100, 200]);\n assert_eq!(candidate(vec![String::from(\"2\"), String::from(\"3\"), String::from(\"8\"), String::from(\"4\"), String::from(\"7\"), String::from(\"9\"), String::from(\"8\"), String::from(\"2\"), String::from(\"6\"), String::from(\"5\"), String::from(\"1\"), String::from(\"6\"), String::from(\"1\"), String::from(\"2\"), String::from(\"3\"), String::from(\"4\"), String::from(\"6\"), String::from(\"9\"), String::from(\"1\"), String::from(\"2\")]), vec![1, 1, 1, 2, 2, 2, 2, 3, 3, 4, 4, 5, 6, 6, 6, 7, 8, 8, 9, 9]);\n assert_eq!(candidate(vec![String::from(\"1\"), String::from(\"3\"), String::from(\"5\"), String::from(\"7\"), String::from(\"1\"), String::from(\"3\"), String::from(\"13\"), String::from(\"15\"), String::from(\"17\"), String::from(\"5\"), String::from(\"7 \"), String::from(\"9\"), String::from(\"1\"), String::from(\"11\")]), vec![1, 1, 1, 3, 3, 5, 5, 7, 7, 9, 11, 13, 15, 17]);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a function to sort a given vector of strings of numbers numerically. https://www.geeksforgeeks.org/rsthon-sort-numeric-strings-in-a-vector/\nfn sort_numeric_strings(nums_str: Vec) -> Vec {\n let mut nums: Vec = nums_str.into_iter().map(|s| s.parse::().unwrap()).collect();\n nums.sort();\n nums\n}"} +{"name": "mbpp_97_frequency_lists", "language": "rs", "prompt": "use std::collections::HashMap;\n\n/// Write a function to find frequency of each element in a flattened vector of vectors, returned in a HashMap.\nfn frequency_lists(list1: Vec>) -> HashMap {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_97_frequency_lists.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "frequency_lists", "test": "\n\nfn main() {\n let candidate = frequency_lists;\n assert_eq!(candidate(vec![vec![1, 2, 3, 2], vec![4, 5, 6, 2], vec![7, 8, 9, 5]]), HashMap::from([(1, 1), (2, 3), (3, 1), (4, 1), (5, 2), (6, 1), (7, 1), (8, 1), (9, 1)]));\n assert_eq!(candidate(vec![vec![1, 2, 3, 4], vec![5, 6, 7, 8], vec![9, 10, 11, 12]]), HashMap::from([(1, 1), (2, 1), (3, 1), (4, 1), (5, 1), (6, 1), (7, 1), (8, 1), (9, 1), (10, 1), (11, 1), (12, 1)]));\n assert_eq!(candidate(vec![vec![20, 30, 40, 17], vec![18, 16, 14, 13], vec![10, 20, 30, 40]]), HashMap::from([(20, 2), (30, 2), (40, 2), (17, 1), (18, 1), (16, 1), (14, 1), (13, 1), (10, 1)]));\n}\n", "is_solved": true, "reflections": [], "solution": "use std::collections::HashMap;\n\n/// Write a function to find frequency of each element in a flattened vector of vectors, returned in a HashMap.\nfn frequency_lists(list1: Vec>) -> HashMap {\n let mut frequency_map: HashMap = HashMap::new();\n\n for sublist in list1 {\n for element in sublist {\n let count = frequency_map.entry(element).or_insert(0);\n *count += 1;\n }\n }\n\n frequency_map\n}"} +{"name": "mbpp_429_and_tuples", "language": "rs", "prompt": "/// Write a function to extract the elementwise and tuples from the given two tuples.\nfn and_tuples(test_tup1: (isize, isize, isize, isize), test_tup2: (isize, isize, isize, isize)) -> (isize, isize, isize, isize) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_429_and_tuples.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "and_tuples", "test": "\n\nfn main() {\n let candidate = and_tuples;\n assert_eq!(candidate((10, 4, 6, 9), (5, 2, 3, 3)), (0, 0, 2, 1));\n assert_eq!(candidate((1, 2, 3, 4), (5, 6, 7, 8)), (1, 2, 3, 0));\n assert_eq!(candidate((8, 9, 11, 12), (7, 13, 14, 17)), (0, 9, 10, 0));\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because it performs bitwise AND operation on the corresponding elements of the input tuples, instead of returning the elementwise AND of the tuples as a whole. The failed test cases show that the output is not as expected, indicating that the bitwise AND operation is not the correct approach for this problem.", "The implementation is wrong because it only returns the first tuple if both tuples are equal, otherwise it returns a tuple with all zeros. The function should extract the elementwise and tuples from the given two tuples, but it does not perform this operation.", "The implementation is incorrect because it is placed inside the main function, causing an unclosed delimiter error. The function should be defined outside the main function to avoid this issue.", "The implementation is wrong because it uses the bitwise AND operator (&) to combine the elements of the tuples, which results in incorrect output values. The test cases are failing because the expected output does not match the actual output produced by the function."], "solution": "/// Write a function to extract the elementwise and tuples from the given two tuples.\nfn and_tuples(test_tup1: (isize, isize, isize, isize), test_tup2: (isize, isize, isize, isize)) -> (isize, isize, isize, isize) {\n (\n test_tup1.0.min(test_tup2.0),\n test_tup1.1.min(test_tup2.1),\n test_tup1.2.min(test_tup2.2),\n test_tup1.3.min(test_tup2.3),\n )"} +{"name": "mbpp_759_is_decimal", "language": "rs", "prompt": "/// Write a function to check whether a given string is a decimal number with a precision of 2.\nfn is_decimal(num: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_759_is_decimal.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_decimal", "test": "\n\nfn main() {\n let candidate = is_decimal;\n assert_eq!(candidate(String::from(\"123.11\")), true);\n assert_eq!(candidate(String::from(\"e666.86\")), false);\n assert_eq!(candidate(String::from(\"3.124587\")), false);\n assert_eq!(candidate(String::from(\"1.11\")), true);\n assert_eq!(candidate(String::from(\"1.1.11\")), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check whether a given string is a decimal number with a precision of 2.\nfn is_decimal(num: String) -> bool {\n if num.is_empty() {\n return false;\n }\n\n let mut decimal_point_count = 0;\n let mut digits_after_decimal = 0;\n\n for (i, c) in num.chars().enumerate() {\n if c == '.' {\n decimal_point_count += 1;\n if decimal_point_count > 1 {\n return false;\n }\n } else if c.is_digit(10) {\n if decimal_point_count == 1 {\n digits_after_decimal += 1;\n if digits_after_decimal > 2 {\n return false;\n }\n }\n } else {\n return false;\n }\n }\n\n decimal_point_count == 1 && digits_after_decimal == 2\n}"} +{"name": "mbpp_599_sum_average", "language": "rs", "prompt": "/// Write a function to find sum and average of first n natural numbers.\nfn sum_average(number: isize) -> (isize, f64) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_599_sum_average.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sum_average", "test": "\n\nfn main() {\n let candidate = sum_average;\n assert_eq!(candidate(10), (55, 5.5));\n assert_eq!(candidate(15), (120, 8.0));\n assert_eq!(candidate(20), (210, 10.5));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find sum and average of first n natural numbers.\nfn sum_average(number: isize) -> (isize, f64) {\n let sum = (number * (number + 1)) / 2;\n let average = sum as f64 / number as f64;\n (sum, average)\n}"} +{"name": "mbpp_804_is_product_even", "language": "rs", "prompt": "/// Write a function to check whether the product of numbers in a vector is even or not.\nfn is_product_even(arr: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_804_is_product_even.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_product_even", "test": "\n\nfn main() {\n let candidate = is_product_even;\n assert_eq!(candidate(vec![1, 2, 3]), true);\n assert_eq!(candidate(vec![1, 2, 1, 4]), true);\n assert_eq!(candidate(vec![1, 1]), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check whether the product of numbers in a vector is even or not.\nfn is_product_even(arr: Vec) -> bool {\n let mut product = 1;\n\n for num in arr {\n product *= num;\n if product % 2 == 0 {\n return true;\n }\n }\n\n false\n}"} +{"name": "mbpp_103_eulerian_num", "language": "rs", "prompt": "/// Write a function to find the Eulerian number a(n, m).\nfn eulerian_num(n: isize, m: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_103_eulerian_num.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "eulerian_num", "test": "\n\nfn main() {\n let candidate = eulerian_num;\n assert_eq!(candidate(3, 1), 4);\n assert_eq!(candidate(4, 1), 11);\n assert_eq!(candidate(5, 3), 26);\n}\n", "solution": "/// Write a function to find the Eulerian number a(n, m).\nfn eulerian_num(n: isize, m: isize) -> isize {\n if m == 0 || m == n - 1 {\n return 1;\n }\n if m < 0 || m >= n {\n return 0;\n }\n (n - m) * eulerian_num(n - 1, m - 1) + (m + 1) * eulerian_num(n - 1, m)\n}", "is_solved": true, "reflections": ["The implementation of the eulerian_num function is incorrect because it calculates the sum of products of k and the recursive calls to eulerian_num for all values of k in the range 1 to n. This does not follow the correct formula for calculating Eulerian numbers, which leads to incorrect results for the failed test cases.", "The implementation of the eulerian_num function is incorrect because it does not follow the correct formula for calculating Eulerian numbers. The current formula used in the function is causing the output to be much larger than the expected values, as seen in the failed test cases.", "The implementation of the eulerian_num function is incorrect because it does not follow the correct formula for calculating Eulerian numbers. The current formula used in the function is causing the output to be much larger than the expected values, as seen in the failed test cases.", "The implementation of the eulerian_num function is incorrect because the formula used to calculate the Eulerian number is not accurate. The failed test cases indicate that the function is producing incorrect results for various input values of n and m. The formula needs to be revised to correctly compute the Eulerian number."]} +{"name": "mbpp_635_heap_sort", "language": "rs", "prompt": "/// Write a function to sort the given vector.\nfn heap_sort(iterable: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_635_heap_sort.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "heap_sort", "test": "\n\nfn main() {\n let candidate = heap_sort;\n assert_eq!(candidate(vec![1, 3, 5, 7, 9, 2, 4, 6, 8, 0]), vec![0, 1, 2, 3, 4, 5, 6, 7, 8, 9]);\n assert_eq!(candidate(vec![25, 35, 22, 85, 14, 65, 75, 25, 58]), vec![14, 22, 25, 25, 35, 58, 65, 75, 85]);\n assert_eq!(candidate(vec![7, 1, 9, 5]), vec![1, 5, 7, 9]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to sort the given vector.\nfn heap_sort(iterable: Vec) -> Vec {\n let mut heap = iterable.clone();\n let length = heap.len();\n\n // Build the max heap\n for i in (0..length / 2).rev() {\n max_heapify(&mut heap, i, length);\n }\n\n // Extract elements from the heap\n for i in (1..length).rev() {\n heap.swap(0, i);\n max_heapify(&mut heap, 0, i);\n }\n\n heap\n}\n\nfn max_heapify(heap: &mut Vec, i: usize, length: usize) {\n let left = 2 * i + 1;\n let right = 2 * i + 2;\n let mut largest = i;\n\n if left < length && heap[left] > heap[largest] {\n largest = left;\n }\n\n if right < length && heap[right] > heap[largest] {\n largest = right;\n }\n\n if largest != i {\n heap.swap(i, largest);\n max_heapify(heap, largest, length);\n }\n}"} +{"name": "mbpp_270_sum_even_and_even_index", "language": "rs", "prompt": "/// Write a rsthon function to find the sum of even numbers at even positions of a vector.\nfn sum_even_and_even_index(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_270_sum_even_and_even_index.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sum_even_and_even_index", "test": "\n\nfn main() {\n let candidate = sum_even_and_even_index;\n assert_eq!(candidate(vec![5, 6, 12, 1, 18, 8]), 30);\n assert_eq!(candidate(vec![3, 20, 17, 9, 2, 10, 18, 13, 6, 18]), 26);\n assert_eq!(candidate(vec![5, 6, 12, 1]), 12);\n}\n", "solution": "/// Write a rsthon function to find the sum of even numbers at even positions of a vector.\nfn sum_even_and_even_index(arr: Vec) -> isize {\n let mut sum = 0;\n\n for (index, &value) in arr.iter().enumerate() {\n if index % 2 == 0 && value % 2 == 0 {\n sum += value;\n }\n }\n\n sum\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it only considers even numbers at even positions, while the goal is to find the sum of even numbers at even positions. The current implementation checks if both the index and the value are even, which is not the requirement. This causes the function to fail in cases where there are even numbers at odd positions or odd numbers at even positions.", "The implementation is incorrect because it only checks for even indices and adds the value at that index to the sum, without considering whether the value itself is even. This leads to incorrect results when the value at an even index is odd, as it still gets added to the sum.", "The implementation is incorrect because it only considers even numbers at even positions, while the goal is to find the sum of even numbers at even positions. The current implementation checks if both the index and the value are even, which is not the desired behavior.", "The implementation is incorrect because it only checks for even indices and adds the value at that index to the sum, without considering if the value itself is even. This causes the function to return the sum of all values at even indices, rather than the sum of even values at even indices."]} +{"name": "mbpp_787_text_match_three", "language": "rs", "prompt": "/// Write a function that matches a string that has an a followed by three 'b'.\nfn text_match_three(text: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_787_text_match_three.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "text_match_three", "test": "\n\nfn main() {\n let candidate = text_match_three;\n assert_eq!(candidate(String::from(\"ac\")), false);\n assert_eq!(candidate(String::from(\"dc\")), false);\n assert_eq!(candidate(String::from(\"abbbba\")), true);\n assert_eq!(candidate(String::from(\"caacabbbba\")), true);\n}\n", "solution": "/// Write a function that matches a string that has an a followed by three 'b'.\nfn text_match_three(text: String) -> bool {\n let pattern = \"abbb\";\n\n for (i, _) in text.char_indices() {\n if i + pattern.len() <= text.len() && &text[i..i + pattern.len()] == pattern {\n return true;\n }\n }\n\n false\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it is looking for the pattern \"abb\" exactly three times in the input string. However, the requirement is to match a string that has an 'a' followed by three 'b's, which is the pattern \"abbb\". The function should be updated to search for the correct pattern and return true if it is found."]} +{"name": "mbpp_765_is_polite", "language": "rs", "prompt": "/// Write a function to find nth polite number. geeksforgeeks.org/n-th-polite-number/\nfn is_polite(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_765_is_polite.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_polite", "test": "\n\nfn main() {\n let candidate = is_polite;\n assert_eq!(candidate(7), 11);\n assert_eq!(candidate(4), 7);\n assert_eq!(candidate(9), 13);\n}\n", "solution": "/// Write a function to find nth polite number. geeksforgeeks.org/n-th-polite-number/\nfn is_polite(n: isize) -> isize {\n let mut count = 0;\n let mut i = 1;\n\n while count < n {\n i += 1;\n\n if i & (i - 1) != 0 {\n count += 1;\n }\n }\n\n i\n}", "is_solved": true, "reflections": ["The implementation of the `is_polite` function is incorrect because it calculates the count of ways a number can be represented as a sum of consecutive integers, rather than finding the nth polite number. The failed tests indicate that the function is not returning the expected polite numbers for the given input values.", "The implementation of the is_polite function is incorrect because it does not properly find the nth polite number. The current logic is incrementing the count for every number that can be represented as the sum of consecutive integers, but it does not account for the fact that some numbers can be represented in multiple ways. This causes the function to return incorrect results for certain input values, as demonstrated by the failed test cases.", "The implementation of the is_polite function is incorrect because it does not properly calculate the nth polite number. The current logic counts the number of ways a number can be represented as a sum of consecutive integers, but it does not check if the number is a power of 2, which is a requirement for a number to be impolite. As a result, the function returns incorrect values for the given test cases."]} +{"name": "mbpp_459_remove_uppercase", "language": "rs", "prompt": "/// Write a function to remove uppercase substrings from a given string.\nfn remove_uppercase(str1: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_459_remove_uppercase.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "remove_uppercase", "test": "\n\nfn main() {\n let candidate = remove_uppercase;\n assert_eq!(candidate(String::from(\"cAstyoUrFavoRitETVshoWs\")), String::from(\"cstyoravoitshos\"));\n assert_eq!(candidate(String::from(\"wAtchTheinTernEtrAdIo\")), String::from(\"wtchheinerntrdo\"));\n assert_eq!(candidate(String::from(\"VoicESeaRchAndreComMendaTionS\")), String::from(\"oiceachndreomendaion\"));\n}\n", "solution": "/// Write a function to remove uppercase substrings from a given string.\nfn remove_uppercase(str1: String) -> String {\n let mut result = String::new();\n let mut current_uppercase = String::new();\n\n for c in str1.chars() {\n if c.is_uppercase() {\n current_uppercase.push(c);\n } else {\n current_uppercase.clear();\n result.push(c);\n }\n }\n\n result\n}", "is_solved": true, "reflections": ["The implementation of the remove_uppercase function is incorrect because it removes all uppercase characters from the input string, including those that are part of a substring. This causes the function to fail the test case where the expected output should preserve the lowercase characters of the uppercase substrings.", "The implementation is incorrect because it only removes the uppercase characters and not the entire uppercase substring. The function is only checking for individual uppercase characters and removing them, instead of identifying and removing continuous sequences of uppercase characters. This is why the test \"MixedCaseExample\" fails, as it only removes the uppercase characters \"M\", \"C\", and \"E\" instead of the whole substrings \"M\", \"C\", and \"E\".", "The implementation is incorrect because it only removes uppercase characters if they are part of a continuous uppercase substring. If an uppercase character is followed by a lowercase character, the uppercase character is not removed. This is evident in the failed test case where \"MixedCaseExample\" should return \"ixedaseample\", but it returns \"ixedasexample\" instead.", "The implementation is incorrect because it removes all uppercase characters from the input string, but it should only remove uppercase substrings. The failed test case demonstrates that the function removes individual uppercase characters instead of the entire uppercase substring."]} +{"name": "mbpp_16_text_lowercase_underscore", "language": "rs", "prompt": "/// Write a function to that returns true if the input string contains sequences of lowercase letters joined with an underscore and false otherwise.\nfn text_lowercase_underscore(text: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_16_text_lowercase_underscore.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "text_lowercase_underscore", "test": "\n\nfn main() {\n let candidate = text_lowercase_underscore;\n assert_eq!(candidate(String::from(\"aab_cbbbc\")), true);\n assert_eq!(candidate(String::from(\"aab_Abbbc\")), false);\n assert_eq!(candidate(String::from(\"Aaab_abbbc\")), false);\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because the `Regex` type is undeclared and not imported. This causes a compilation error. To fix this issue, the `regex` crate should be added to the dependencies and the `Regex` type should be imported using `use regex::Regex;`.", "The implementation is incorrect because the `regex` crate is not declared or imported, causing an unresolved import error. To fix this issue, the `regex` crate needs to be added to the project's dependencies and properly imported.", "The implementation is incorrect because the `regex` crate is not declared or imported, causing an unresolved import error. To fix this issue, the `regex` crate needs to be added to the project's dependencies and properly imported.", "The implementation is incorrect because the `regex` crate is not declared or imported, causing an unresolved import error. To fix this issue, the `regex` crate needs to be added to the project's dependencies and imported properly."], "solution": "/// Write a function to that returns true if the input string contains sequences of lowercase letters joined with an underscore and false otherwise.\nfn text_lowercase_underscore(text: String) -> bool {\n use regex::Regex;\n let pattern = Regex::new(r\"^[a-z]+(_[a-z]+)*$\").unwrap();\n pattern.is_match(&text)\n}"} +{"name": "mbpp_731_lateralsurface_cone", "language": "rs", "prompt": "/// Write a function to find the lateral surface area of a cone given radius r and the height h.\nfn lateralsurface_cone(r: isize, h: isize) -> f64 {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_731_lateralsurface_cone.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "lateralsurface_cone", "test": "\n\nfn main() {\n let candidate = lateralsurface_cone;\n assert_eq!(candidate(5, 12), 204.20352248333654);\n assert_eq!(candidate(10, 15), 566.3586699569488);\n assert_eq!(candidate(19, 17), 1521.8090132193388);\n}\n", "is_solved": false, "reflections": ["The implementation of the lateralsurface_cone function is incorrect because it does not round the calculated lateral surface area to two decimal places. The unit tests are comparing the output to rounded values, causing the assertions to fail.", "The implementation of the `lateralsurface_cone` function is incorrect because it calculates the slant height using the wrong formula. The current formula squares the radius and height before adding them together, which is not the correct way to calculate the slant height of a cone. This leads to incorrect lateral surface area calculations, causing the failed test cases.", "The implementation of the lateralsurface_cone function is incorrect because it divides the calculated lateral surface area by 2.0, which is not part of the formula for finding the lateral surface area of a cone. This causes the function to return incorrect results for the given test cases.", "The implementation of the `lateralsurface_cone` function is incorrect because it calculates the slant height using the wrong formula. The current formula calculates the square of the slant height instead of the actual slant height. This leads to incorrect lateral surface area calculations, causing the failed test cases."], "solution": "/// Write a function to find the lateral surface area of a cone given radius r and the height h.\nfn lateralsurface_cone(r: isize, h: isize) -> f64 {\n let slant_height_squared = (r * r) + (h * h) as f64;\n let slant_height = slant_height_squared.sqrt();\n let lateral_surface_area = std::f64::consts::PI * r as f64 * slant_height;\n let lateral_surface_area = (lateral_surface_area * 100.0).round() / 100.0;\n lateral_surface_area\n}"} +{"name": "mbpp_802_count_rotation", "language": "rs", "prompt": "/// Write a rsthon function to count the number of rotations required to generate a sorted vector. https://www.geeksforgeeks.org/count-of-rotations-required-to-generate-a-sorted-vector/\nfn count_rotation(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_802_count_rotation.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_rotation", "test": "\n\nfn main() {\n let candidate = count_rotation;\n assert_eq!(candidate(vec![3, 2, 1]), 1);\n assert_eq!(candidate(vec![4, 5, 1, 2, 3]), 2);\n assert_eq!(candidate(vec![7, 8, 9, 1, 2, 3]), 3);\n assert_eq!(candidate(vec![1, 2, 3]), 0);\n assert_eq!(candidate(vec![1, 3, 2]), 2);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a rsthon function to count the number of rotations required to generate a sorted vector. https://www.geeksforgeeks.org/count-of-rotations-required-to-generate-a-sorted-vector/\nfn count_rotation(arr: Vec) -> isize {\n let n = arr.len();\n let mut min_index = 0;\n\n for i in 1..n {\n if arr[i] < arr[min_index] {\n min_index = i;\n }\n }\n\n min_index as isize\n}"} +{"name": "mbpp_782_odd_length_sum", "language": "rs", "prompt": "/// Write a rsthon function to find the sum of all odd length subvectors. https://www.geeksforgeeks.org/sum-of-all-odd-length-subvectors/\nfn odd_length_sum(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_782_odd_length_sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "odd_length_sum", "test": "\n\nfn main() {\n let candidate = odd_length_sum;\n assert_eq!(candidate(vec![1, 2, 4]), 14);\n assert_eq!(candidate(vec![1, 2, 1, 2]), 15);\n assert_eq!(candidate(vec![1, 7]), 8);\n}\n", "is_solved": false, "reflections": ["The implementation of the odd_length_sum function is incorrect because it calculates the sum of all subvectors, not just the ones with odd length. The condition to check if the length is odd is not working properly, causing the function to include even length subvectors in the sum as well. This leads to incorrect results for some test cases.", "The implementation is incorrect because it resets the `temp_sum` to 0 when the length of the subvector is even. This causes the function to miss some odd length subvectors and results in an incorrect sum. The function should not reset `temp_sum` and should only add it to the final sum when the subvector length is odd.", "The implementation of the odd_length_sum function is incorrect because it calculates the sum of all subvectors, not just the odd length ones. The inner loop adds all elements from the current index to the end of the array, and the condition `(j - i + 1) % 2 != 0` does not effectively filter out even length subvectors. This leads to incorrect results in the failed test cases.", "The implementation is incorrect because it calculates the sum of all subvectors with even lengths as well as odd lengths. This is due to the use of `step_by(2)` in the second loop, which causes it to include subvectors of even lengths in the calculation. As a result, the function returns a higher sum than expected for the failed test cases."], "solution": "/// Write a rsthon function to find the sum of all odd length subvectors. https://www.geeksforgeeks.org/sum-of-all-odd-length-subvectors/\nfn odd_length_sum(arr: Vec) -> isize {\n let n = arr.len();\n let mut sum = 0;\n\n for i in 0..n {\n for j in (i..n).step_by(2) {\n let mut temp_sum = 0;\n for k in i..=j {\n temp_sum += arr[k];\n }\n sum += temp_sum;\n }\n }\n\n for i in 0..n {\n for j in (i+1..n).step_by(2) {\n let mut temp_sum = 0;\n for k in i..=j {\n temp_sum += arr[k];\n }\n sum -= temp_sum;\n }\n }\n\n sum\n}"} +{"name": "mbpp_470_add_pairwise", "language": "rs", "prompt": "/// Write a function to find the pairwise addition of the neighboring elements of the given tuple.\nfn add_pairwise(test_tup: (isize, isize, isize, isize, isize)) -> (isize, isize, isize, isize) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_470_add_pairwise.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "add_pairwise", "test": "\n\nfn main() {\n let candidate = add_pairwise;\n assert_eq!(candidate((1, 5, 7, 8, 10)), (6, 12, 15, 18));\n assert_eq!(candidate((2, 6, 8, 9, 11)), (8, 14, 17, 20));\n assert_eq!(candidate((3, 7, 9, 10, 12)), (10, 16, 19, 22));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the pairwise addition of the neighboring elements of the given tuple.\nfn add_pairwise(test_tup: (isize, isize, isize, isize, isize)) -> (isize, isize, isize, isize) {\n let (a, b, c, d, e) = test_tup;\n let sum1 = a + b;\n let sum2 = b + c;\n let sum3 = c + d;\n let sum4 = d + e;\n\n (sum1, sum2, sum3, sum4)\n}"} +{"name": "mbpp_17_square_perimeter", "language": "rs", "prompt": "/// Write a function that returns the perimeter of a square given its side length as input.\nfn square_perimeter(a: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_17_square_perimeter.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "square_perimeter", "test": "\n\nfn main() {\n let candidate = square_perimeter;\n assert_eq!(candidate(10), 40);\n assert_eq!(candidate(5), 20);\n assert_eq!(candidate(4), 16);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function that returns the perimeter of a square given its side length as input.\nfn square_perimeter(a: isize) -> isize {\n 4 * a\n}"} +{"name": "mbpp_228_all_Bits_Set_In_The_Given_Range", "language": "rs", "prompt": "/// Write a rsthon function to check whether all the bits are unset in the given range or not.\nfn all_Bits_Set_In_The_Given_Range(n: isize, l: isize, r: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_228_all_Bits_Set_In_The_Given_Range.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "all_Bits_Set_In_The_Given_Range", "test": "\n\nfn main() {\n let candidate = all_Bits_Set_In_The_Given_Range;\n assert_eq!(candidate(4, 1, 2), true);\n assert_eq!(candidate(17, 2, 4), true);\n assert_eq!(candidate(39, 4, 6), false);\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because it checks if all bits are set in the given range, instead of checking if all bits are unset. The function returns false when a bit is unset, but it should return false when a bit is set.", "The function implementation is incorrect because it checks if all bits are unset (0) in the given range, instead of checking if all bits are set (1) as required. The function returns false when it encounters a set bit, whereas it should return false when it encounters an unset bit.", "The function implementation is incorrect because it checks if all bits are set in the given range, rather than checking if all bits are unset. The condition `(n & (1 << i)) == 0` should be changed to check for unset bits instead of set bits.", "The function implementation is incorrect because it checks if all bits are unset in the given range, rather than checking if all bits are set as required. The condition in the if statement should be checking for equality to 0, not inequality. This is causing the function to return false for cases where all bits are set in the given range."], "solution": "/// Write a rsthon function to check whether all the bits are unset in the given range or not.\nfn all_Bits_Set_In_The_Given_Range(n: isize, l: isize, r: isize) -> bool {\n for i in l..=r {\n if (n & (1 << i)) == 0 {\n return false;\n }\n }\n true\n}"} +{"name": "mbpp_447_cube_nums", "language": "rs", "prompt": "/// Write a function to find cubes of individual elements in a vector.\nfn cube_nums(nums: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_447_cube_nums.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "cube_nums", "test": "\n\nfn main() {\n let candidate = cube_nums;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 10]), vec![1, 8, 27, 64, 125, 216, 343, 512, 729, 1000]);\n assert_eq!(candidate(vec![10, 20, 30]), vec![1000, 8000, 27000]);\n assert_eq!(candidate(vec![12, 15]), vec![1728, 3375]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find cubes of individual elements in a vector.\nfn cube_nums(nums: Vec) -> Vec {\n nums.into_iter().map(|num| num * num * num).collect()\n}"} +{"name": "mbpp_261_division_elements", "language": "rs", "prompt": "/// Write a function that takes in two tuples and performs mathematical division operation element-wise across the given tuples.\nfn division_elements(test_tup1: (isize, isize, isize, isize), test_tup2: (isize, isize, isize, isize)) -> (isize, isize, isize, isize) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_261_division_elements.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "division_elements", "test": "\n\nfn main() {\n let candidate = division_elements;\n assert_eq!(candidate((10, 4, 6, 9), (5, 2, 3, 3)), (2, 2, 2, 3));\n assert_eq!(candidate((12, 6, 8, 16), (6, 3, 4, 4)), (2, 2, 2, 4));\n assert_eq!(candidate((20, 14, 36, 18), (5, 7, 6, 9)), (4, 2, 6, 2));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function that takes in two tuples and performs mathematical division operation element-wise across the given tuples.\nfn division_elements(test_tup1: (isize, isize, isize, isize), test_tup2: (isize, isize, isize, isize)) -> (isize, isize, isize, isize) {\n let result = (\n test_tup1.0 / test_tup2.0,\n test_tup1.1 / test_tup2.1,\n test_tup1.2 / test_tup2.2,\n test_tup1.3 / test_tup2.3,\n );\n\n result\n}"} +{"name": "mbpp_581_surface_Area", "language": "rs", "prompt": "/// Write a rsthon function to find the surface area of a square rsramid with a given base edge and height.\nfn surface_Area(b: isize, s: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_581_surface_Area.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "surface_Area", "test": "\n\nfn main() {\n let candidate = surface_Area;\n assert_eq!(candidate(3, 4), 33);\n assert_eq!(candidate(4, 5), 56);\n assert_eq!(candidate(1, 2), 5);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the surface area of a square rsramid with a given base edge and height.\nfn surface_Area(b: isize, s: isize) -> isize {\n let base_area = b * b;\n let lateral_area = 4 * (b * s) / 2;\n let surface_area = base_area + lateral_area;\n surface_area\n}"} +{"name": "mbpp_283_validate", "language": "rs", "prompt": "/// Write a rsthon function takes in an integer and check whether the frequency of each digit in the integer is less than or equal to the digit itself.\nfn validate(n: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_283_validate.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "validate", "test": "\n\nfn main() {\n let candidate = validate;\n assert_eq!(candidate(1234), true);\n assert_eq!(candidate(51241), false);\n assert_eq!(candidate(321), true);\n}\n", "is_solved": false, "reflections": ["The implementation of the `validate` function is incorrect because it checks if the frequency of each digit is less than or equal to the index `i` instead of the digit itself. This causes the function to return true for cases like 4444 and 122, where the frequency of the digits is greater than the digits themselves.", "The implementation of the `validate` function is incorrect because it checks if the frequency of a digit is greater than the digit itself, instead of checking if the frequency is greater than or equal to the digit. This causes the function to return true for cases where the frequency is equal to the digit, leading to failed test cases like `validate(4444)` and `validate(122)`.", "The implementation of the `validate` function is incorrect because it checks if the frequency of each digit is strictly less than the digit itself. However, the problem statement requires checking if the frequency is less than or equal to the digit. The condition in the loop should be changed to `freq[i] > i` instead of `freq[i] >= i`. This is causing the function to return false for valid cases, leading to the failed tests.", "The implementation of the `validate` function is incorrect because it checks if the frequency of a digit is greater than the digit itself, instead of checking if the frequency is greater than or equal to the digit. This causes the function to return true for cases like 4444 and 122, where the frequency of the digits is equal to the digits themselves, leading to failed test cases."], "solution": "/// Write a rsthon function takes in an integer and check whether the frequency of each digit in the integer is less than or equal to the digit itself.\nfn validate(n: isize) -> bool {\n let mut freq = vec![0; 10];\n\n for c in n.to_string().chars() {\n let digit = c.to_digit(10).unwrap() as usize;\n freq[digit] += 1;\n }\n\n for i in 0..10 {\n if freq[i] > 0 && freq[i] >= i {\n return false;\n }\n }\n\n true\n}"} +{"name": "mbpp_101_kth_element", "language": "rs", "prompt": "/// Write a function to find the kth element in the given vector using 1-based indexing.\nfn kth_element(arr: Vec, k: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_101_kth_element.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "kth_element", "test": "\n\nfn main() {\n let candidate = kth_element;\n assert_eq!(candidate(vec![12, 3, 5, 7, 19], 2), 3);\n assert_eq!(candidate(vec![17, 24, 8, 23], 3), 8);\n assert_eq!(candidate(vec![16, 21, 25, 36, 4], 4), 36);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the kth element in the given vector using 1-based indexing.\nfn kth_element(arr: Vec, k: isize) -> isize {\n if k > 0 && k as usize <= arr.len() {\n arr[(k - 1) as usize]\n } else {\n panic!(\"Index out of bounds: The given index k is not within the range of the vector.\");\n }\n}"} +{"name": "mbpp_461_upper_ctr", "language": "rs", "prompt": "/// Write a rsthon function to count the upper case characters in a given string.\nfn upper_ctr(str: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_461_upper_ctr.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "upper_ctr", "test": "\n\nfn main() {\n let candidate = upper_ctr;\n assert_eq!(candidate(String::from(\"PYthon\")), 1);\n assert_eq!(candidate(String::from(\"BigData\")), 1);\n assert_eq!(candidate(String::from(\"program\")), 0);\n}\n", "is_solved": false, "reflections": ["The implementation of the upper_ctr function is incorrect because it counts the whitespace character as an uppercase character. This causes the function to return a higher count than expected when the input string contains spaces.", "The implementation of the upper_ctr function is incorrect because it counts whitespace characters as uppercase characters when they are not. This leads to an incorrect count of uppercase characters in the input string, as seen in the failed test case.", "The implementation of the upper_ctr function is incorrect because it counts the whitespace character as an uppercase character. This causes the function to return a higher count than expected when the input string contains spaces.", "The implementation of the upper_ctr function is incorrect because it counts uppercase characters and non-alphabetic characters (such as digits and symbols) as long as they are not whitespace. This leads to an incorrect count of uppercase characters in strings containing non-alphabetic characters. In the failed test case, the function counts an extra non-alphabetic character as an uppercase character, resulting in an output of 5 instead of the expected 4."], "solution": "/// Write a rsthon function to count the upper case characters in a given string.\nfn upper_ctr(str: String) -> isize {\n let mut count = 0;\n for c in str.chars() {\n if c.is_uppercase() && c.is_alphabetic() {\n count += 1;\n }\n }\n count as isize\n}"} +{"name": "mbpp_593_removezero_ip", "language": "rs", "prompt": "/// Write a function to remove leading zeroes from an ip address.\nfn removezero_ip(ip: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_593_removezero_ip.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "removezero_ip", "test": "\n\nfn main() {\n let candidate = removezero_ip;\n assert_eq!(candidate(String::from(\"216.08.094.196\")), String::from(\"216.8.94.196\"));\n assert_eq!(candidate(String::from(\"12.01.024\")), String::from(\"12.1.24\"));\n assert_eq!(candidate(String::from(\"216.08.094.0196\")), String::from(\"216.8.94.196\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to remove leading zeroes from an ip address.\nfn removezero_ip(ip: String) -> String {\n let mut result = String::new();\n let octets = ip.split('.').collect::>();\n\n for (i, octet) in octets.iter().enumerate() {\n let trimmed_octet = octet.trim_start_matches('0');\n let cleaned_octet = if trimmed_octet.is_empty() { \"0\" } else { trimmed_octet };\n\n if i != 0 {\n result.push('.');\n }\n result.push_str(cleaned_octet);\n }\n\n result\n}"} +{"name": "mbpp_788_new_tuple", "language": "rs", "prompt": "/// Write a function to create a new tuple from the given string and vector.\nfn new_tuple(test_list: Vec, test_str: String) -> (String, String, String) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_788_new_tuple.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "new_tuple", "test": "\n\nfn main() {\n let candidate = new_tuple;\n assert_eq!(candidate(vec![String::from(\"WEB\"), String::from(\"is\")], String::from(\"best\")), (String::from(\"WEB\"), String::from(\"is\"), String::from(\"best\")));\n assert_eq!(candidate(vec![String::from(\"We\"), String::from(\"are\")], String::from(\"Developers\")), (String::from(\"We\"), String::from(\"are\"), String::from(\"Developers\")));\n assert_eq!(candidate(vec![String::from(\"Part\"), String::from(\"is\")], String::from(\"Wrong\")), (String::from(\"Part\"), String::from(\"is\"), String::from(\"Wrong\")));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to create a new tuple from the given string and vector.\nfn new_tuple(test_list: Vec, test_str: String) -> (String, String, String) {\n if test_list.len() >= 2 {\n let first = test_list[0].clone();\n let second = test_list[1].clone();\n (first, second, test_str)\n } else {\n panic!(\"The input vector must have at least 2 elements.\");\n }\n}"} +{"name": "mbpp_777_find_sum", "language": "rs", "prompt": "/// Write a rsthon function to find the sum of non-repeated elements in a given vector.\nfn find_sum(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_777_find_sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_sum", "test": "\n\nfn main() {\n let candidate = find_sum;\n assert_eq!(candidate(vec![1, 2, 3, 1, 1, 4, 5, 6]), 21);\n assert_eq!(candidate(vec![1, 10, 9, 4, 2, 10, 10, 45, 4]), 71);\n assert_eq!(candidate(vec![12, 10, 9, 45, 2, 10, 10, 45, 10]), 78);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a rsthon function to find the sum of non-repeated elements in a given vector.\nfn find_sum(arr: Vec) -> isize {\n let mut unique_elements = Vec::new();\n\n for &num in arr.iter() {\n if unique_elements.contains(&num) {\n unique_elements.retain(|&x| x != num);\n } else {\n unique_elements.push(num);\n }\n }\n\n unique_elements.iter().sum()\n}"} +{"name": "mbpp_586_split_Arr", "language": "rs", "prompt": "/// Write a rsthon function to split a vector at the nth eelment and add the first part to the end.\nfn split_Arr(l: Vec, n: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_586_split_Arr.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "split_Arr", "test": "\n\nfn main() {\n let candidate = split_Arr;\n assert_eq!(candidate(vec![12, 10, 5, 6, 52, 36], 2), vec![5, 6, 52, 36, 12, 10]);\n assert_eq!(candidate(vec![1, 2, 3, 4], 1), vec![2, 3, 4, 1]);\n assert_eq!(candidate(vec![0, 1, 2, 3, 4, 5, 6, 7], 3), vec![3, 4, 5, 6, 7, 0, 1, 2]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to split a vector at the nth eelment and add the first part to the end.\nfn split_Arr(l: Vec, n: isize) -> Vec {\n let mut result = Vec::new();\n let len = l.len();\n\n for i in (n as usize)..len {\n result.push(l[i]);\n }\n\n for i in 0..(n as usize) {\n result.push(l[i]);\n }\n\n result\n}"} +{"name": "mbpp_104_sort_sublists", "language": "rs", "prompt": "/// Write a function to sort each subvector of strings in a given vector of vectors.\nfn sort_sublists(input_list: Vec>) -> Vec> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_104_sort_sublists.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sort_sublists", "test": "\n\nfn main() {\n let candidate = sort_sublists;\n assert_eq!(candidate(vec![vec![String::from(\"green\"), String::from(\"orange\")], vec![String::from(\"black\"), String::from(\"white\")], vec![String::from(\"white\"), String::from(\"black\"), String::from(\"orange\")]]), vec![vec![String::from(\"green\"), String::from(\"orange\")], vec![String::from(\"black\"), String::from(\"white\")], vec![String::from(\"black\"), String::from(\"orange\"), String::from(\"white\")]]);\n assert_eq!(candidate(vec![vec![String::from(\" red \"), String::from(\"green\")], vec![String::from(\"blue \"), String::from(\" black\")], vec![String::from(\" orange\"), String::from(\"brown\")]]), vec![vec![String::from(\" red \"), String::from(\"green\")], vec![String::from(\" black\"), String::from(\"blue \")], vec![String::from(\" orange\"), String::from(\"brown\")]]);\n assert_eq!(candidate(vec![vec![String::from(\"zilver\"), String::from(\"gold\")], vec![String::from(\"magnesium\"), String::from(\"aluminium\")], vec![String::from(\"steel\"), String::from(\"bronze\")]]), vec![vec![String::from(\"gold\"), String::from(\"zilver\")], vec![String::from(\"aluminium\"), String::from(\"magnesium\")], vec![String::from(\"bronze\"), String::from(\"steel\")]]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to sort each subvector of strings in a given vector of vectors.\nfn sort_sublists(input_list: Vec>) -> Vec> {\n let mut sorted_list = input_list.clone();\n for sublist in sorted_list.iter_mut() {\n sublist.sort();\n }\n sorted_list\n}"} +{"name": "mbpp_472_check_Consecutive", "language": "rs", "prompt": "/// Write a rsthon function to check whether the given vector contains consecutive numbers or not.\nfn check_Consecutive(l: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_472_check_Consecutive.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "check_Consecutive", "test": "\n\nfn main() {\n let candidate = check_Consecutive;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5]), true);\n assert_eq!(candidate(vec![1, 2, 3, 5, 6]), false);\n assert_eq!(candidate(vec![1, 2, 1]), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to check whether the given vector contains consecutive numbers or not.\nfn check_Consecutive(l: Vec) -> bool {\n if l.len() < 2 {\n return false;\n }\n\n let mut sorted_l = l.clone();\n sorted_l.sort();\n\n for i in 1..sorted_l.len() {\n if sorted_l[i] - sorted_l[i - 1] != 1 {\n return false;\n }\n }\n\n true\n}"} +{"name": "mbpp_310_string_to_tuple", "language": "rs", "prompt": "/// Write a function to convert a given string to a vector of characters.\nfn string_to_tuple(str1: String) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_310_string_to_tuple.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "string_to_tuple", "test": "\n\nfn main() {\n let candidate = string_to_tuple;\n assert_eq!(candidate(String::from(\"python 3.0\")), vec![String::from(\"p\"), String::from(\"y\"), String::from(\"t\"), String::from(\"h\"), String::from(\"o\"), String::from(\"n\"), String::from(\"3\"), String::from(\".\"), String::from(\"0\")]);\n assert_eq!(candidate(String::from(\"item1\")), vec![String::from(\"i\"), String::from(\"t\"), String::from(\"e\"), String::from(\"m\"), String::from(\"1\")]);\n assert_eq!(candidate(String::from(\"15.10\")), vec![String::from(\"1\"), String::from(\"5\"), String::from(\".\"), String::from(\"1\"), String::from(\"0\")]);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a function to convert a given string to a vector of characters.\nfn string_to_tuple(str1: String) -> Vec {\n str1.chars().map(|c| c.to_string()).collect()\n}"} +{"name": "mbpp_266_lateralsurface_cube", "language": "rs", "prompt": "/// Write a function to find the lateral surface area of a cube given its side length.\nfn lateralsurface_cube(l: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_266_lateralsurface_cube.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "lateralsurface_cube", "test": "\n\nfn main() {\n let candidate = lateralsurface_cube;\n assert_eq!(candidate(5), 100);\n assert_eq!(candidate(9), 324);\n assert_eq!(candidate(10), 400);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the lateral surface area of a cube given its side length.\nfn lateralsurface_cube(l: isize) -> isize {\n let lateral_area = 4 * l * l;\n lateral_area\n}"} +{"name": "mbpp_271_even_Power_Sum", "language": "rs", "prompt": "/// Write a rsthon function that takes in an integer n and finds the sum of the first n even natural numbers that are raised to the fifth power.\nfn even_Power_Sum(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_271_even_Power_Sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "even_Power_Sum", "test": "\n\nfn main() {\n let candidate = even_Power_Sum;\n assert_eq!(candidate(2), 1056);\n assert_eq!(candidate(3), 8832);\n assert_eq!(candidate(1), 32);\n}\n", "solution": "/// Write a rsthon function that takes in an integer n and finds the sum of the first n even natural numbers that are raised to the fifth power.\nfn even_Power_Sum(n: isize) -> isize {\n let mut sum = 0;\n for i in 1..=n {\n let even_num = i * 2;\n let power_five = even_num.pow(5);\n sum += power_five;\n }\n sum\n}", "is_solved": true, "reflections": ["The implementation of the even_Power_Sum function is incorrect because it calculates the sum of the first n even numbers raised to the fifth power, but the tests are expecting the sum of the first n even natural numbers raised to the fifth power. The difference is that the function should start with the first even natural number (2) instead of the first even number (0). This causes the calculated sums to be higher than the expected values in the failed tests.", "The implementation of the even_Power_Sum function is incorrect because it calculates the sum of the first n even numbers raised to the fifth power, rather than the sum of the first n even natural numbers raised to the fifth power. The difference is that the function should start with the first even natural number (2) and not just the first even number (1 * 2). This causes the sum to be incorrect for the failed test cases.", "The implementation of the even_Power_Sum function is incorrect because it starts the loop at 0 and adds 2 to the even number calculation. This causes the function to skip the first even number (2) and include an extra even number at the end, leading to incorrect results.", "The implementation of the even_Power_Sum function is incorrect because it calculates the sum of the first n even numbers raised to the fifth power, rather than the sum of the first n even natural numbers raised to the fifth power. The difference is that the function should start with the first even natural number (2) and not the first even number (0). This causes the sum to be higher than expected, leading to the failed test cases."]} +{"name": "mbpp_238_number_of_substrings", "language": "rs", "prompt": "/// Write a rsthon function to count the number of non-empty substrings of a given string.\nfn number_of_substrings(str: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_238_number_of_substrings.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "number_of_substrings", "test": "\n\nfn main() {\n let candidate = number_of_substrings;\n assert_eq!(candidate(String::from(\"abc\")), 6);\n assert_eq!(candidate(String::from(\"abcd\")), 10);\n assert_eq!(candidate(String::from(\"abcde\")), 15);\n}\n", "solution": "/// Write a rsthon function to count the number of non-empty substrings of a given string.\nfn number_of_substrings(str: String) -> isize {\n let n = str.len();\n ((n * (n + 1)) / 2).try_into().unwrap()\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it returns a `usize` instead of the expected `isize` return type. The function calculates the number of non-empty substrings correctly, but the type mismatch causes a compilation error. To fix this, the result should be converted from `usize` to `isize` using the `try_into().unwrap()` method."]} +{"name": "mbpp_592_sum_Of_product", "language": "rs", "prompt": "/// Write a rsthon function to find the sum of the product of consecutive binomial co-efficients.\nfn sum_Of_product(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_592_sum_Of_product.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sum_Of_product", "test": "\n\nfn main() {\n let candidate = sum_Of_product;\n assert_eq!(candidate(3), 15);\n assert_eq!(candidate(4), 56);\n assert_eq!(candidate(1), 1);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the sum of the product of consecutive binomial co-efficients.\nfn sum_Of_product(n: isize) -> isize {\n let mut sum = 0;\n for i in 0..n {\n let binomial_product = binomial_coefficient(n, i) * binomial_coefficient(n, i + 1);\n sum += binomial_product;\n }\n sum\n}\n\nfn binomial_coefficient(n: isize, k: isize) -> isize {\n let mut result = 1;\n for i in 0..k {\n result *= n - i;\n result /= i + 1;\n }\n result\n}"} +{"name": "mbpp_74_is_samepatterns", "language": "rs", "prompt": "/// Write a function to check whether it follows the sequence given in the patterns vector.\nfn is_samepatterns(colors: Vec, patterns: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_74_is_samepatterns.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_samepatterns", "test": "\n\nfn main() {\n let candidate = is_samepatterns;\n assert_eq!(candidate(vec![String::from(\"red\"), String::from(\"green\"), String::from(\"green\")], vec![String::from(\"a\"), String::from(\"b\"), String::from(\"b\")]), true);\n assert_eq!(candidate(vec![String::from(\"red\"), String::from(\"green\"), String::from(\"greenn\")], vec![String::from(\"a\"), String::from(\"b\"), String::from(\"b\")]), false);\n assert_eq!(candidate(vec![String::from(\"red\"), String::from(\"green\"), String::from(\"greenn\")], vec![String::from(\"a\"), String::from(\"b\")]), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check whether it follows the sequence given in the patterns vector.\nfn is_samepatterns(colors: Vec, patterns: Vec) -> bool {\n if colors.len() != patterns.len() {\n return false;\n }\n\n let mut color_map = std::collections::HashMap::new();\n let mut pattern_map = std::collections::HashMap::new();\n\n for (color, pattern) in colors.iter().zip(patterns.iter()) {\n if !color_map.contains_key(color) {\n color_map.insert(color, pattern);\n } else if color_map[color] != pattern {\n return false;\n }\n\n if !pattern_map.contains_key(pattern) {\n pattern_map.insert(pattern, color);\n } else if pattern_map[pattern] != color {\n return false;\n }\n }\n\n true\n}"} +{"name": "mbpp_415_max_Product", "language": "rs", "prompt": "/// Write a rsthon function to find a pair with highest product from a given vector of integers.\nfn max_Product(arr: Vec) -> (isize, isize) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_415_max_Product.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_Product", "test": "\n\nfn main() {\n let candidate = max_Product;\n assert_eq!(candidate(vec![1, 2, 3, 4, 7, 0, 8, 4]), (7, 8));\n assert_eq!(candidate(vec![0, -1, -2, -4, 5, 0, -6]), (-4, -6));\n assert_eq!(candidate(vec![1, 2, 3]), (2, 3));\n}\n", "solution": "/// Write a rsthon function to find a pair with highest product from a given vector of integers.\nfn max_Product(arr: Vec) -> (isize, isize) {\n let mut max_product = std::isize::MIN;\n let mut pair = (0, 0);\n\n for i in 0..arr.len() {\n for j in i + 1..arr.len() {\n let product = arr[i] * arr[j];\n if product > max_product {\n max_product = product;\n pair = (arr[i], arr[j]);\n }\n }\n }\n\n pair\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it does not handle the case where the highest product is obtained from two negative numbers. In the failed test, the correct pair should be (-1, -2) since their product is 2, but the implementation returns (-3, -4) because it only considers the largest absolute values.", "The implementation is incorrect because it does not handle the case where the highest product is obtained from two negative numbers. The function first tries to find the maximum product using positive numbers, and if it fails, it looks for the minimum product, which is not the correct approach. Instead, the function should consider all pairs of numbers, regardless of their signs, to find the highest product.", "The implementation is incorrect because it does not handle the case where the highest product is obtained from two negative numbers. In the failed test case, the correct pair should be (-1, -2) since their product is 2, but the implementation returns (-3, -4) because it only considers the largest absolute values.", "The implementation is incorrect because it first tries to find the maximum product among positive numbers and only then checks for negative numbers if no positive product is found. This approach fails when the highest product is obtained from a pair of negative numbers, as seen in the failed test case. The function should consider all pairs, both positive and negative, while calculating the maximum product."]} +{"name": "mbpp_781_count_divisors", "language": "rs", "prompt": "/// Write a rsthon function to check whether the count of divisors is even. https://www.w3resource.com/rsthon-exercises/basic/rsthon-basic-1-exercise-24.php\nfn count_divisors(n: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_781_count_divisors.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_divisors", "test": "\n\nfn main() {\n let candidate = count_divisors;\n assert_eq!(candidate(10), true);\n assert_eq!(candidate(100), false);\n assert_eq!(candidate(125), true);\n}\n", "solution": "/// Write a rsthon function to check whether the count of divisors is even. https://www.w3resource.com/rsthon-exercises/basic/rsthon-basic-1-exercise-24.php\nfn count_divisors(n: isize) -> bool {\n let mut count = 0;\n\n for i in 1..=((n as f64).sqrt() as isize) {\n if n % i == 0 {\n count += 1;\n if i != n / i {\n count += 1;\n }\n }\n }\n\n if count == 0 {\n return false;\n }\n\n count % 2 == 0\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it only checks for divisors up to the square root of the input number, which causes it to miss some divisors and incorrectly calculate the count. This leads to wrong results for some test cases, such as 3, 2, 4, and 15.", "The implementation of the count_divisors function is incorrect because it counts the total number of divisors for a given number and checks if the count is even. However, the function should check if the count of divisors is even, not the total number of divisors. This leads to incorrect results for some test cases, such as 3, 2, 4, and 15.", "The implementation of the count_divisors function is incorrect because it is counting the divisors of the input number and checking if the count is even. However, the problem statement asks to check whether the count of divisors is even, not the count itself. The failed tests indicate that the function is not accurately determining if the count of divisors is even or odd.", "The implementation of the count_divisors function is incorrect because it checks if the count of divisors minus 1 is even, instead of checking if the count itself is even. This leads to incorrect results for some input values, such as the failed test case with input 6."]} +{"name": "mbpp_441_surfacearea_cube", "language": "rs", "prompt": "/// Write a function to find the surface area of a cube of a given size.\nfn surfacearea_cube(l: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_441_surfacearea_cube.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "surfacearea_cube", "test": "\n\nfn main() {\n let candidate = surfacearea_cube;\n assert_eq!(candidate(5), 150);\n assert_eq!(candidate(3), 54);\n assert_eq!(candidate(10), 600);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the surface area of a cube of a given size.\nfn surfacearea_cube(l: isize) -> isize {\n let area = 6 * l * l;\n area\n}"} +{"name": "mbpp_396_check_char", "language": "rs", "prompt": "/// Write a function to check whether the given string starts and ends with the same character or not.\nfn check_char(string: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_396_check_char.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "check_char", "test": "\n\nfn main() {\n let candidate = check_char;\n assert_eq!(candidate(String::from(\"abba\")), String::from(\"Valid\"));\n assert_eq!(candidate(String::from(\"a\")), String::from(\"Valid\"));\n assert_eq!(candidate(String::from(\"abcd\")), String::from(\"Invalid\"));\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because it returns the strings \"True\" and \"False\" with the first letter capitalized, while the unit tests expect the strings \"true\" and \"false\" with all lowercase letters. This causes the tests to fail due to the case difference."], "solution": "/// Write a function to check whether the given string starts and ends with the same character or not.\nfn check_char(string: String) -> String {\n if string.is_empty() {\n return \"Empty string\".to_string();\n }\n\n let first_char = string.chars().next().unwrap();\n let last_char = string.chars().last().unwrap();\n\n if first_char == last_char {\n \"true\".to_string()\n } else {\n \"false\".to_string()\n }\n}"} +{"name": "mbpp_757_count_reverse_pairs", "language": "rs", "prompt": "/// Write a function to count the pairs of reverse strings in the given string vector. https://www.geeksforgeeks.org/rsthon-program-to-count-the-pairs-of-reverse-strings/\nfn count_reverse_pairs(test_list: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_757_count_reverse_pairs.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_reverse_pairs", "test": "\n\nfn main() {\n let candidate = count_reverse_pairs;\n assert_eq!(candidate(vec![String::from(\"julia\"), String::from(\"best\"), String::from(\"tseb\"), String::from(\"for\"), String::from(\"ailuj\")]), 2);\n assert_eq!(candidate(vec![String::from(\"geeks\"), String::from(\"best\"), String::from(\"for\"), String::from(\"skeeg\")]), 1);\n assert_eq!(candidate(vec![String::from(\"makes\"), String::from(\"best\"), String::from(\"sekam\"), String::from(\"for\"), String::from(\"rof\")]), 2);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to count the pairs of reverse strings in the given string vector. https://www.geeksforgeeks.org/rsthon-program-to-count-the-pairs-of-reverse-strings/\nfn count_reverse_pairs(test_list: Vec) -> isize {\n let mut count = 0;\n\n for i in 0..test_list.len() {\n for j in i + 1..test_list.len() {\n if test_list[i].chars().rev().collect::() == test_list[j] {\n count += 1;\n }\n }\n }\n\n count\n}"} +{"name": "mbpp_75_find_tuples", "language": "rs", "prompt": "/// Write a function to find tuples which have all elements divisible by k from the given vector of tuples.\nfn find_tuples(test_list: Vec<(isize, isize, isize)>, K: isize) -> Vec<(isize, isize, isize)> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_75_find_tuples.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_tuples", "test": "\n\nfn main() {\n let candidate = find_tuples;\n assert_eq!(candidate(vec![(6, 24, 12), (7, 9, 6), (12, 18, 21)], 6), vec![(6, 24, 12)]);\n assert_eq!(candidate(vec![(5, 25, 30), (4, 2, 3), (7, 8, 9)], 5), vec![(5, 25, 30)]);\n assert_eq!(candidate(vec![(7, 9, 16), (8, 16, 4), (19, 17, 18)], 4), vec![(8, 16, 4)]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find tuples which have all elements divisible by k from the given vector of tuples.\nfn find_tuples(test_list: Vec<(isize, isize, isize)>, K: isize) -> Vec<(isize, isize, isize)> {\n let mut result: Vec<(isize, isize, isize)> = Vec::new();\n\n for tuple in test_list.iter() {\n if tuple.0 % K == 0 && tuple.1 % K == 0 && tuple.2 % K == 0 {\n result.push(*tuple);\n }\n }\n\n result\n}"} +{"name": "mbpp_785_tuple_str_int", "language": "rs", "prompt": "/// Write a function to convert tuple string to integer tuple.\nfn tuple_str_int(test_str: String) -> (isize, isize, isize) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_785_tuple_str_int.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "tuple_str_int", "test": "\n\nfn main() {\n let candidate = tuple_str_int;\n assert_eq!(candidate(String::from(\"(7, 8, 9)\")), (7, 8, 9));\n assert_eq!(candidate(String::from(\"(1, 2, 3)\")), (1, 2, 3));\n assert_eq!(candidate(String::from(\"(4, 5, 6)\")), (4, 5, 6));\n assert_eq!(candidate(String::from(\"(7, 81, 19)\")), (7, 81, 19));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to convert tuple string to integer tuple.\nfn tuple_str_int(test_str: String) -> (isize, isize, isize) {\n let mut numbers = test_str\n .trim_start_matches('(')\n .trim_end_matches(')')\n .split(',')\n .map(|s| s.trim().parse::())\n .collect::, _>>()\n .unwrap_or_default();\n\n if numbers.len() == 3 {\n (numbers[0], numbers[1], numbers[2])\n } else {\n (0, 0, 0)\n }\n}"} +{"name": "mbpp_776_count_vowels", "language": "rs", "prompt": "/// Write a function to count those characters which have vowels as their neighbors in the given string.\nfn count_vowels(test_str: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_776_count_vowels.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_vowels", "test": "\n\nfn main() {\n let candidate = count_vowels;\n assert_eq!(candidate(String::from(\"bestinstareels\")), 7);\n assert_eq!(candidate(String::from(\"partofthejourneyistheend\")), 12);\n assert_eq!(candidate(String::from(\"amazonprime\")), 5);\n}\n", "is_solved": false, "reflections": ["The implementation of the count_vowels function is incorrect because it only checks if the characters before and after the current character are vowels, but it doesn't check if the current character itself is not a vowel. This causes the function to miss cases where a non-vowel character is surrounded by vowels, as seen in the failed test case with the input \"hello\".", "The current implementation of the count_vowels function is incorrect because it does not properly handle cases where the first or last character of the string has vowels as neighbors. This is due to the loop starting at index 1 and ending at index chars.len() - 2, which excludes the first and last characters from being considered. This causes the failed test cases for \"hello\" and \"aeiou\".", "The implementation is incorrect because it counts characters with only one vowel neighbor at the beginning and end of the string. Additionally, it does not count characters with vowel neighbors if the character itself is a vowel. This leads to incorrect counts for cases like \"education\", \"world\", and \"aeiou\".", "The implementation of the count_vowels function is incorrect because it only counts characters with vowels as neighbors if both neighbors are vowels. The function should count characters with at least one vowel as a neighbor. This is why the test case \"hello\" fails, as it only has one vowel neighbor for the character 'e'."], "solution": "/// Write a function to count those characters which have vowels as their neighbors in the given string.\nfn count_vowels(test_str: String) -> isize {\n let vowels = ['a', 'e', 'i', 'o', 'u'];\n let mut count = 0;\n let chars: Vec = test_str.chars().collect();\n\n if chars.len() < 3 {\n return 0;\n }\n\n for i in 1..chars.len() - 1 {\n if vowels.contains(&chars[i - 1]) || vowels.contains(&chars[i + 1]) {\n count += 1;\n }\n }\n\n count\n}"} +{"name": "mbpp_277_dict_filter", "language": "rs", "prompt": "use std::collections::HashMap;\n\n/// Write a function that takes in a HashMap and integer n and filters the HashMap to only include entries with values greater than or equal to n.\nfn dict_filter(dict: HashMap, n: isize) -> HashMap {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_277_dict_filter.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "dict_filter", "test": "\n\nfn main() {\n let candidate = dict_filter;\n assert_eq!(candidate(HashMap::from([(String::from(\"Cierra Vega\"), 175), (String::from(\"Alden Cantrell\"), 180), (String::from(\"Kierra Gentry\"), 165), (String::from(\"Pierre Cox\"), 190)]), 170), HashMap::from([(String::from(\"Cierra Vega\"), 175), (String::from(\"Alden Cantrell\"), 180), (String::from(\"Pierre Cox\"), 190)]));\n assert_eq!(candidate(HashMap::from([(String::from(\"Cierra Vega\"), 175), (String::from(\"Alden Cantrell\"), 180), (String::from(\"Kierra Gentry\"), 165), (String::from(\"Pierre Cox\"), 190)]), 180), HashMap::from([(String::from(\"Alden Cantrell\"), 180), (String::from(\"Pierre Cox\"), 190)]));\n assert_eq!(candidate(HashMap::from([(String::from(\"Cierra Vega\"), 175), (String::from(\"Alden Cantrell\"), 180), (String::from(\"Kierra Gentry\"), 165), (String::from(\"Pierre Cox\"), 190)]), 190), HashMap::from([(String::from(\"Pierre Cox\"), 190)]));\n}\n", "is_solved": true, "reflections": [], "solution": "use std::collections::HashMap;\n\n/// Write a function that takes in a HashMap and integer n and filters the HashMap to only include entries with values greater than or equal to n.\nfn dict_filter(dict: HashMap, n: isize) -> HashMap {\n dict.into_iter()\n .filter(|(_, value)| *value >= n)\n .collect()\n}"} +{"name": "mbpp_468_max_product", "language": "rs", "prompt": "/// Write a function to find the maximum product formed by multiplying numbers of an increasing subsequence of that vector.\nfn max_product(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_468_max_product.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_product", "test": "\n\nfn main() {\n let candidate = max_product;\n assert_eq!(candidate(vec![3, 100, 4, 5, 150, 6]), 3000);\n assert_eq!(candidate(vec![4, 42, 55, 68, 80]), 50265600);\n assert_eq!(candidate(vec![10, 22, 9, 33, 21, 50, 41, 60]), 2460);\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because it only considers the maximum product formed by multiplying numbers of an increasing subsequence that includes the current element. It does not account for the possibility that the maximum product might be formed by skipping some elements in the increasing subsequence. This leads to incorrect results when there are negative numbers or zeros in the input vector.", "The implementation is incorrect because it only considers the maximum product formed by multiplying the current element with the previous maximum product. It does not account for the possibility of skipping some elements in the subsequence to achieve a higher product. This leads to incorrect results when there are better subsequences that can be formed by skipping elements.", "The implementation is incorrect because it calculates the maximum product by considering all subsequences, not just increasing subsequences. This leads to incorrect results when there are decreasing subsequences with higher products. The loop that calculates the maximum product should only consider increasing subsequences.", "The implementation is incorrect because it only considers the maximum product formed by multiplying the current element with the previous elements in the increasing subsequence. It does not account for the possibility of skipping some elements to form a higher product. This leads to incorrect results when there are negative numbers or zeros in the input vector, as seen in the failed test cases."], "solution": "/// Write a function to find the maximum product formed by multiplying numbers of an increasing subsequence of that vector.\nfn max_product(arr: Vec) -> isize {\n if arr.is_empty() {\n return 0;\n }\n\n let n = arr.len();\n let mut dp = vec![0; n];\n dp[0] = arr[0];\n let mut max_product = dp[0];\n\n for i in 1..n {\n dp[i] = arr[i];\n for j in 0..i {\n if arr[i] > arr[j] {\n dp[i] = dp[i].max(dp[j] * arr[i]);\n }\n }\n max_product = max_product.max(dp[i]);\n }\n\n // Find the maximum product considering skipping some elements\n for i in 0..n {\n for j in i + 2..n {\n if arr[j] > arr[i] {\n max_product = max_product.max(dp[i] * arr[j]);\n }\n }\n }\n\n max_product\n}"} +{"name": "mbpp_279_is_num_decagonal", "language": "rs", "prompt": "/// Write a function to find the nth decagonal number.\nfn is_num_decagonal(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_279_is_num_decagonal.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_num_decagonal", "test": "\n\nfn main() {\n let candidate = is_num_decagonal;\n assert_eq!(candidate(3), 27);\n assert_eq!(candidate(7), 175);\n assert_eq!(candidate(10), 370);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the nth decagonal number.\nfn is_num_decagonal(n: isize) -> isize {\n if n <= 0 {\n return 0;\n }\n n * (4 * n - 3)\n}"} +{"name": "mbpp_3_is_not_prime", "language": "rs", "prompt": "/// Write a rsthon function to identify non-prime numbers.\nfn is_not_prime(n: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_3_is_not_prime.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_not_prime", "test": "\n\nfn main() {\n let candidate = is_not_prime;\n assert_eq!(candidate(2), false);\n assert_eq!(candidate(10), true);\n assert_eq!(candidate(35), true);\n assert_eq!(candidate(37), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to identify non-prime numbers.\nfn is_not_prime(n: isize) -> bool {\n if n <= 1 {\n return true;\n }\n\n for i in 2..((n as f64).sqrt() as isize + 1) {\n if n % i == 0 {\n return true;\n }\n }\n\n false\n}"} +{"name": "mbpp_88_freq_count", "language": "rs", "prompt": "use std::collections::HashMap;\n\n/// Write a function to get the frequency of all the elements in a vector, returned as a HashMap.\nfn freq_count(list1: Vec) -> HashMap {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_88_freq_count.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "freq_count", "test": "\n\nfn main() {\n let candidate = freq_count;\n assert_eq!(candidate(vec![10, 10, 10, 10, 20, 20, 20, 20, 40, 40, 50, 50, 30]), HashMap::from([(10, 4), (20, 4), (40, 2), (50, 2), (30, 1)]));\n assert_eq!(candidate(vec![1, 2, 3, 4, 3, 2, 4, 1, 3, 1, 4]), HashMap::from([(1, 3), (2, 2), (3, 3), (4, 3)]));\n assert_eq!(candidate(vec![5, 6, 7, 4, 9, 10, 4, 5, 6, 7, 9, 5]), HashMap::from([(10, 1), (5, 3), (6, 2), (7, 2), (4, 2), (9, 2)]));\n}\n", "is_solved": true, "reflections": [], "solution": "use std::collections::HashMap;\n\n/// Write a function to get the frequency of all the elements in a vector, returned as a HashMap.\nfn freq_count(list1: Vec) -> HashMap {\n let mut frequency_map: HashMap = HashMap::new();\n\n for element in list1 {\n let count = frequency_map.entry(element).or_insert(0);\n *count += 1;\n }\n\n frequency_map\n}"} +{"name": "mbpp_259_maximize_elements", "language": "rs", "prompt": "/// Write a function to maximize the given two vectors.\nfn maximize_elements(test_tup1: Vec>, test_tup2: Vec>) -> Vec> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_259_maximize_elements.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "maximize_elements", "test": "\n\nfn main() {\n let candidate = maximize_elements;\n assert_eq!(candidate(vec![vec![1, 3], vec![4, 5], vec![2, 9], vec![1, 10]], vec![vec![6, 7], vec![3, 9], vec![1, 1], vec![7, 3]]), vec![vec![6, 7], vec![4, 9], vec![2, 9], vec![7, 10]]);\n assert_eq!(candidate(vec![vec![2, 4], vec![5, 6], vec![3, 10], vec![2, 11]], vec![vec![7, 8], vec![4, 10], vec![2, 2], vec![8, 4]]), vec![vec![7, 8], vec![5, 10], vec![3, 10], vec![8, 11]]);\n assert_eq!(candidate(vec![vec![3, 5], vec![6, 7], vec![4, 11], vec![3, 12]], vec![vec![8, 9], vec![5, 11], vec![3, 3], vec![9, 5]]), vec![vec![8, 9], vec![6, 11], vec![4, 11], vec![9, 12]]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to maximize the given two vectors.\nfn maximize_elements(test_tup1: Vec>, test_tup2: Vec>) -> Vec> {\n let mut result: Vec> = Vec::new();\n\n for i in 0..test_tup1.len() {\n let mut row: Vec = Vec::new();\n for j in 0..test_tup1[i].len() {\n row.push(std::cmp::max(test_tup1[i][j], test_tup2[i][j]));\n }\n result.push(row);\n }\n\n result\n}"} +{"name": "mbpp_285_text_match_two_three", "language": "rs", "prompt": "/// Write a function that checks whether a string contains the 'a' character followed by two or three 'b' characters.\nfn text_match_two_three(text: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_285_text_match_two_three.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "text_match_two_three", "test": "\n\nfn main() {\n let candidate = text_match_two_three;\n assert_eq!(candidate(String::from(\"ac\")), false);\n assert_eq!(candidate(String::from(\"dc\")), false);\n assert_eq!(candidate(String::from(\"abbbba\")), true);\n}\n", "is_solved": false, "reflections": ["The implementation is wrong because there is an unclosed delimiter in the code, causing a syntax error. Additionally, the `regex` crate is used without being declared or imported, leading to a failed resolution of the `regex::Regex` module.", "The implementation is wrong because the `regex` crate is not declared or imported, causing the compiler to throw an error. To fix this issue, the `regex` crate should be added to the `Cargo.toml` file and imported using `use regex::Regex;` at the beginning of the code.", "The implementation is wrong because the `regex` crate is not declared and imported, causing an unresolved import error. To fix this issue, the `regex` crate should be added to the `Cargo.toml` file and properly imported in the code.", "The implementation is wrong because the `regex` crate is not imported or declared in the code, causing an unresolved import error. To fix this issue, the `regex` crate should be added to the project's dependencies and properly imported."], "solution": "/// Write a function that checks whether a string contains the 'a' character followed by two or three 'b' characters.\nfn text_match_two_three(text: String) -> bool {\n use regex::Regex;\n let pattern = Regex::new(r\"a{1}b{2,3}\").unwrap();\n pattern.is_match(&text)\n}"} +{"name": "mbpp_721_maxAverageOfPath", "language": "rs", "prompt": "/// Given a square matrix of size N*N given as a vector of vectors, where each cell is associated with a specific cost. A path is defined as a specific sequence of cells that starts from the top-left cell move only right or down and ends on bottom right cell. We want to find a path with the maximum average over all existing paths. Average is computed as total cost divided by the number of cells visited in the path.\nfn maxAverageOfPath(cost: Vec>) -> f64 {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_721_maxAverageOfPath.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "maxAverageOfPath", "test": "\n\nfn main() {\n let candidate = maxAverageOfPath;\n assert_eq!(candidate(vec![vec![1, 2, 3], vec![6, 5, 4], vec![7, 3, 9]]), 5.2);\n assert_eq!(candidate(vec![vec![2, 3, 4], vec![7, 6, 5], vec![8, 4, 10]]), 6.2);\n assert_eq!(candidate(vec![vec![3, 4, 5], vec![8, 7, 6], vec![9, 5, 11]]), 7.2);\n assert_eq!(candidate(vec![vec![1, 2, 3], vec![4, 5, 6], vec![7, 8, 9]]), 5.8);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Given a square matrix of size N*N given as a vector of vectors, where each cell is associated with a specific cost. A path is defined as a specific sequence of cells that starts from the top-left cell move only right or down and ends on bottom right cell. We want to find a path with the maximum average over all existing paths. Average is computed as total cost divided by the number of cells visited in the path.\nfn maxAverageOfPath(cost: Vec>) -> f64 {\n let n = cost.len();\n let mut dp = vec![vec![0.0; n]; n];\n\n dp[0][0] = cost[0][0] as f64;\n\n for i in 1..n {\n dp[i][0] = dp[i - 1][0] + cost[i][0] as f64;\n }\n\n for j in 1..n {\n dp[0][j] = dp[0][j - 1] + cost[0][j] as f64;\n }\n\n for i in 1..n {\n for j in 1..n {\n dp[i][j] = f64::max(dp[i - 1][j], dp[i][j - 1]) + cost[i][j] as f64;\n }\n }\n\n dp[n - 1][n - 1] / (2 * n - 1) as f64\n}"} +{"name": "mbpp_797_sum_in_range", "language": "rs", "prompt": "/// Write a rsthon function to find the sum of all odd natural numbers within the range l and r.\nfn sum_in_range(l: isize, r: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_797_sum_in_range.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sum_in_range", "test": "\n\nfn main() {\n let candidate = sum_in_range;\n assert_eq!(candidate(2, 5), 8);\n assert_eq!(candidate(5, 7), 12);\n assert_eq!(candidate(7, 13), 40);\n}\n", "solution": "/// Write a rsthon function to find the sum of all odd natural numbers within the range l and r.\nfn sum_in_range(l: isize, r: isize) -> isize {\n let mut sum = 0;\n let mut start = l;\n\n if start % 2 == 0 {\n start += 1;\n }\n\n for i in (start..=r).step_by(2) {\n if i % 2 != 0 {\n sum += i;\n }\n }\n sum\n}", "is_solved": true, "reflections": ["The implementation of the sum_in_range function is incorrect because it does not properly handle cases where the lower bound (l) is an odd number. In these cases, the function calculates the sum of all odd numbers within the range, but it is off by one. This is evident from the failed test cases where the lower bound is an odd number (7 and 3).", "The implementation of the sum_in_range function is incorrect because it does not properly handle cases where the range starts with an odd number. In these cases, the function calculates the sum of odd numbers one less than the expected value. This is because the starting value is incremented by 1 when it is even, causing the function to skip the first odd number in the range when the range starts with an odd number.", "The implementation of the sum_in_range function is incorrect because it does not properly handle the initial value of the sum when the starting number is odd. The current implementation adds the starting number to the sum only if it's odd, but then it also increments the starting number by 2 before entering the loop. This causes the first odd number to be skipped in the loop, resulting in an incorrect sum for certain test cases.", "The implementation of the sum_in_range function is incorrect because it does not properly handle cases where the range starts with an odd number. In these cases, the function calculates the sum of odd numbers one less than the expected range, causing the output to be lower than the expected result."]} +{"name": "mbpp_4_heap_queue_largest", "language": "rs", "prompt": "/// Write a function to find the n largest integers from a given vector of numbers, returned in descending order.\nfn heap_queue_largest(nums: Vec, n: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_4_heap_queue_largest.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "heap_queue_largest", "test": "\n\nfn main() {\n let candidate = heap_queue_largest;\n assert_eq!(candidate(vec![25, 35, 22, 85, 14, 65, 75, 22, 58], 3), vec![85, 75, 65]);\n assert_eq!(candidate(vec![25, 35, 22, 85, 14, 65, 75, 22, 58], 2), vec![85, 75]);\n assert_eq!(candidate(vec![25, 35, 22, 85, 14, 65, 75, 22, 58], 5), vec![85, 75, 65, 58, 35]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the n largest integers from a given vector of numbers, returned in descending order.\nfn heap_queue_largest(nums: Vec, n: isize) -> Vec {\n use std::cmp::Reverse;\n use std::collections::BinaryHeap;\n\n let mut heap = BinaryHeap::with_capacity(n as usize);\n let mut result = Vec::with_capacity(n as usize);\n\n for num in nums {\n if heap.len() < n as usize {\n heap.push(Reverse(num));\n } else if let Some(&Reverse(min)) = heap.peek() {\n if num > min {\n heap.pop();\n heap.push(Reverse(num));\n }\n }\n }\n\n while let Some(Reverse(val)) = heap.pop() {\n result.push(val);\n }\n\n result.reverse();\n result\n}"} +{"name": "mbpp_120_max_product_tuple", "language": "rs", "prompt": "/// Write a function to find the maximum absolute product between numbers in pairs of tuples within a given vector.\nfn max_product_tuple(list1: Vec<(isize, isize)>) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_120_max_product_tuple.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_product_tuple", "test": "\n\nfn main() {\n let candidate = max_product_tuple;\n assert_eq!(candidate(vec![(2, 7), (2, 6), (1, 8), (4, 9)]), 36);\n assert_eq!(candidate(vec![(10, 20), (15, 2), (5, 10)]), 200);\n assert_eq!(candidate(vec![(11, 44), (10, 15), (20, 5), (12, 9)]), 484);\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because it calculates the product of the absolute values of the individual elements in the tuples, rather than calculating the product of the tuples first and then taking the absolute value. This leads to incorrect results when there are negative numbers involved in the tuples.", "The implementation is incorrect because it calculates the product using the sum of the products of the individual elements in the tuples, rather than the product of the absolute values of the tuples. This leads to incorrect results when the signs of the elements in the tuples are different.", "The implementation is incorrect because it calculates the sum of the absolute products of the individual elements in the tuples, rather than the absolute value of the product of the tuples. This leads to incorrect results when the signs of the elements in the tuples are different, as the sum of the absolute products does not represent the maximum absolute product between the tuple pairs.", "The implementation is incorrect because it calculates the product using the sum of the products of the individual elements in the tuples, rather than the product of the absolute values of the tuples. This leads to incorrect results when the signs of the elements in the tuples are different."], "solution": "/// Write a function to find the maximum absolute product between numbers in pairs of tuples within a given vector.\nfn max_product_tuple(list1: Vec<(isize, isize)>) -> isize {\n let mut max_product = 0;\n\n for i in 0..list1.len() {\n for j in i + 1..list1.len() {\n let product = (list1[i].0 * list1[j].0).abs() + (list1[i].1 * list1[j].1).abs();\n if product > max_product {\n max_product = product;\n }\n }\n }\n\n max_product\n}"} +{"name": "mbpp_230_replace_blank", "language": "rs", "prompt": "/// Write a function that takes in a string and character, replaces blank spaces in the string with the character, and returns the string.\nfn replace_blank(str1: String, char: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_230_replace_blank.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "replace_blank", "test": "\n\nfn main() {\n let candidate = replace_blank;\n assert_eq!(candidate(String::from(\"hello people\"), String::from(\"@\")), String::from(\"hello@people\"));\n assert_eq!(candidate(String::from(\"python program language\"), String::from(\"$\")), String::from(\"python$program$language\"));\n assert_eq!(candidate(String::from(\"blank space\"), String::from(\"-\")), String::from(\"blank-space\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function that takes in a string and character, replaces blank spaces in the string with the character, and returns the string.\nfn replace_blank(str1: String, char: String) -> String {\n str1.replace(\" \", &char)\n}"} +{"name": "mbpp_600_is_Even", "language": "rs", "prompt": "/// Write a rsthon function to check whether the given number is even or not.\nfn is_Even(n: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_600_is_Even.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_Even", "test": "\n\nfn main() {\n let candidate = is_Even;\n assert_eq!(candidate(1), false);\n assert_eq!(candidate(2), true);\n assert_eq!(candidate(3), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to check whether the given number is even or not.\nfn is_Even(n: isize) -> bool {\n if n % 2 == 0 {\n return true;\n } else {\n return false;\n }\n}"} +{"name": "mbpp_440_find_adverb_position", "language": "rs", "prompt": "/// Write a function to find the first adverb and their positions in a given sentence.\nfn find_adverb_position(text: String) -> (isize, isize, String) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_440_find_adverb_position.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_adverb_position", "test": "\n\nfn main() {\n let candidate = find_adverb_position;\n assert_eq!(candidate(String::from(\"clearly!! we can see the sky\")), (0, 7, String::from(\"clearly\")));\n assert_eq!(candidate(String::from(\"seriously!! there are many roses\")), (0, 9, String::from(\"seriously\")));\n assert_eq!(candidate(String::from(\"unfortunately!! sita is going to home\")), (0, 13, String::from(\"unfortunately\")));\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because it only checks for a limited set of predefined adverbs, and it does not account for all possible adverbs in the input text. Additionally, the position returned is based on the character count rather than the word count, causing a mismatch in the expected output.", "The implementation is incorrect because it returns the same value for both position indices, which should be different as they represent the starting and ending positions of the adverb in the sentence. Additionally, the function fails to find adverbs that are the last word in the sentence, as it only checks for words ending with \"ly\" followed by a whitespace.", "The implementation is incorrect because it returns the character positions of the adverb in the sentence instead of the word positions. The tests are failing because they expect the word positions, but the function returns the character positions where the adverb starts and ends.", "The implementation is incorrect because it returns the same value for both the word index and the character position of the adverb in the sentence. The function should return the word index and the character position separately, accounting for spaces between words."], "solution": "/// Write a function to find the first adverb and their positions in a given sentence.\nfn find_adverb_position(text: String) -> (isize, isize, String) {\n let words: Vec<&str> = text.split_whitespace().collect();\n let mut position: isize = 0;\n\n for (index, word) in words.iter().enumerate() {\n if word.ends_with(\"ly\") || word.ends_with(\"ly.\") {\n let clean_word = word.trim_end_matches('.');\n return (index as isize, position, clean_word.to_string());\n }\n position += (word.len() + 1) as isize;\n }\n\n (-1, -1, String::new())\n}"} +{"name": "mbpp_773_occurance_substring", "language": "rs", "prompt": "/// Write a function to find the occurrence and position of the substrings within a string. Return None if there is no match.\nfn occurance_substring(text: String, pattern: String) -> Option<(String, isize, isize)> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_773_occurance_substring.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "occurance_substring", "test": "\n\nfn main() {\n let candidate = occurance_substring;\n assert_eq!(candidate(String::from(\"python programming, python language\"), String::from(\"python\")), Some((String::from(\"python\"), 0, 6)));\n assert_eq!(candidate(String::from(\"python programming,programming language\"), String::from(\"programming\")), Some((String::from(\"programming\"), 7, 18)));\n assert_eq!(candidate(String::from(\"python programming,programming language\"), String::from(\"language\")), Some((String::from(\"language\"), 31, 39)));\n assert_eq!(candidate(String::from(\"c++ programming, c++ language\"), String::from(\"python\")), None);\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because it only returns the first occurrence of the pattern in the text, along with its start and end positions. The expected output should include the total number of occurrences and the position of the last occurrence, as indicated by the failed tests.", "The implementation is incorrect because it only returns the last position of the substring in the text, rather than the first occurrence as expected by the tests. The function should be modified to return the position of the first occurrence of the substring."], "solution": "/// Write a function to find the occurrence and position of the substrings within a string. Return None if there is no match.\nfn occurance_substring(text: String, pattern: String) -> Option<(String, isize, isize)> {\n if text.is_empty() || pattern.is_empty() {\n return None;\n }\n\n let text_len = text.len();\n let pattern_len = pattern.len();\n\n if text_len < pattern_len {\n return None;\n }\n\n let mut count = 0;\n let mut first_position = None;\n\n for i in 0..=(text_len - pattern_len) {\n if &text[i..(i + pattern_len)] == pattern {\n count += 1;\n if first_position.is_none() {\n first_position = Some(i);\n }\n }\n }\n\n if count > 0 {\n return Some((pattern.clone(), count as isize, first_position.unwrap() as isize));\n }\n\n None\n}"} +{"name": "mbpp_239_get_total_number_of_sequences", "language": "rs", "prompt": "/// Write a function that takes in positive integers m and n and finds the number of possible sequences of length n, such that each element is a positive integer and is greater than or equal to twice the previous element but less than or equal to m.\nfn get_total_number_of_sequences(m: isize, n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_239_get_total_number_of_sequences.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "get_total_number_of_sequences", "test": "\n\nfn main() {\n let candidate = get_total_number_of_sequences;\n assert_eq!(candidate(10, 4), 4);\n assert_eq!(candidate(5, 2), 6);\n assert_eq!(candidate(16, 3), 84);\n}\n", "solution": "/// Write a function that takes in positive integers m and n and finds the number of possible sequences of length n, such that each element is a positive integer and is greater than or equal to twice the previous element but less than or equal to m.\nfn get_total_number_of_sequences(m: isize, n: isize) -> isize {\n if m <= 0 || n <= 0 {\n return 0;\n }\n\n let mut dp = vec![vec![0; (n + 1) as usize]; (m + 1) as usize];\n\n for i in 1..=(m as usize) {\n dp[i][1] = 1;\n }\n\n for i in 1..=(m as usize) {\n for j in 2..=(n as usize) {\n let mut sum = 0;\n for k in 1..=((i + 1) / 2) {\n if k * 2 <= i {\n sum += dp[k][j - 1];\n }\n }\n dp[i][j] = sum;\n }\n }\n\n let mut result = 0;\n for i in 1..=(m as usize) {\n result += dp[i][n as usize];\n }\n\n result\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it does not properly calculate the number of possible sequences that meet the given conditions. The dynamic programming approach used in the function is not accounting for the requirement that each element should be greater than or equal to twice the previous element. This leads to incorrect results in the failed test cases.", "The implementation of the get_total_number_of_sequences function is incorrect because it does not properly calculate the number of possible sequences that meet the given conditions. The issue lies in the loop that calculates the sum of the previous elements in the dp array. The loop should start from the previous element divided by 2 and go up to the current element, but the current implementation starts from 1 and goes up to the current element divided by 2. This results in incorrect calculations for the dp array, leading to wrong results for the test cases.", "The implementation is incorrect because it does not properly calculate the number of sequences that meet the condition of each element being greater than or equal to twice the previous element. The loop that calculates the sum of the previous elements in the dp table is not considering the condition, leading to an overestimation of the possible sequences.", "The implementation is incorrect because it calculates the sum of all possible sequences without considering the condition that each element should be greater than or equal to twice the previous element. The current implementation overcounts the number of valid sequences, leading to incorrect results."]} +{"name": "mbpp_412_remove_odd", "language": "rs", "prompt": "/// Write a rsthon function to remove odd numbers from a given vector.\nfn remove_odd(l: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_412_remove_odd.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "remove_odd", "test": "\n\nfn main() {\n let candidate = remove_odd;\n assert_eq!(candidate(vec![1, 2, 3]), vec![2]);\n assert_eq!(candidate(vec![2, 4, 6]), vec![2, 4, 6]);\n assert_eq!(candidate(vec![10, 20, 3]), vec![10, 20]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to remove odd numbers from a given vector.\nfn remove_odd(l: Vec) -> Vec {\n let mut even_numbers = Vec::new();\n\n for number in l {\n if number % 2 == 0 {\n even_numbers.push(number);\n }\n }\n\n even_numbers\n}"} +{"name": "mbpp_414_overlapping", "language": "rs", "prompt": "/// Write a rsthon function to check whether any value in a sequence exists in a sequence or not.\nfn overlapping(list1: Vec, list2: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_414_overlapping.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "overlapping", "test": "\n\nfn main() {\n let candidate = overlapping;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5], vec![6, 7, 8, 9]), false);\n assert_eq!(candidate(vec![1, 2, 3], vec![4, 5, 6]), false);\n assert_eq!(candidate(vec![1, 4, 5], vec![1, 4, 5]), true);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to check whether any value in a sequence exists in a sequence or not.\nfn overlapping(list1: Vec, list2: Vec) -> bool {\n for item in &list1 {\n if list2.contains(item) {\n return true;\n }\n }\n false\n}"} +{"name": "mbpp_160_find_solution", "language": "rs", "prompt": "/// Write a function that returns integers x and y that satisfy ax + by = n as a tuple, or return None if no solution exists.\nfn find_solution(a: isize, b: isize, n: isize) -> Option<(isize, isize)> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_160_find_solution.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_solution", "test": "\n\nfn main() {\n let candidate = find_solution;\n assert_eq!(candidate(2, 3, 7), Some((2, 1)));\n assert_eq!(candidate(4, 2, 7), None);\n assert_eq!(candidate(1, 13, 17), Some((4, 1)));\n}\n", "solution": "/// Write a function that returns integers x and y that satisfy ax + by = n as a tuple, or return None if no solution exists.\nfn find_solution(a: isize, b: isize, n: isize) -> Option<(isize, isize)> {\n let mut smallest_solution = None;\n let mut smallest_sum = std::isize::MAX;\n\n for x in -n..=n {\n for y in -n..=n {\n if a * x + b * y == n {\n let sum = x.abs() + y.abs();\n if sum < smallest_sum {\n smallest_solution = Some((x, y));\n smallest_sum = sum;\n }\n }\n }\n }\n\n if let Some((x, y)) = smallest_solution {\n if a * x + b * y == n {\n return Some((x, y));\n }\n }\n\n None\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it returns the first pair of integers (x, y) that satisfy the equation ax + by = n, without considering the smallest non-negative solution. This leads to incorrect results and failed test cases, as the returned solution may have negative values when a non-negative solution exists.", "The implementation is incorrect because it finds a valid solution (x, y) that satisfies ax + by = n, but it does not return the solution with the smallest x value when multiple solutions exist. Instead, it returns the solution with the smallest sum of x and y, which is not the desired output.", "The implementation is incorrect because it only searches for solutions within the range of 0 to n for both x and y. This limits the possible solutions and may return incorrect results. Additionally, the function does not consider negative values for x and y, which could also be valid solutions.", "The implementation is incorrect because it finds a solution with the smallest sum of absolute values of x and y, but it does not guarantee the correct order of x and y in the tuple. Additionally, the function may return a solution when it should return None, as it does not properly handle cases where no valid solution exists."]} +{"name": "mbpp_559_max_sub_array_sum", "language": "rs", "prompt": "/// Write a function to find the sum of the largest contiguous subvector in the given vector.\nfn max_sub_array_sum(a: Vec, size: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_559_max_sub_array_sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_sub_array_sum", "test": "\n\nfn main() {\n let candidate = max_sub_array_sum;\n assert_eq!(candidate(vec![-2, -3, 4, -1, -2, 1, 5, -3], 8), 7);\n assert_eq!(candidate(vec![-3, -4, 5, -2, -3, 2, 6, -4], 8), 8);\n assert_eq!(candidate(vec![-4, -5, 6, -3, -4, 3, 7, -5], 8), 10);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the sum of the largest contiguous subvector in the given vector.\nfn max_sub_array_sum(a: Vec, size: isize) -> isize {\n let mut max_so_far = a[0];\n let mut curr_max = a[0];\n\n for i in 1..size as usize {\n curr_max = isize::max(a[i], curr_max + a[i]);\n max_so_far = isize::max(max_so_far, curr_max);\n }\n\n max_so_far\n}"} +{"name": "mbpp_809_check_smaller", "language": "rs", "prompt": "/// Write a function to check if each element of second tuple is smaller than its corresponding element in the first tuple.\nfn check_smaller(test_tup1: (isize, isize, isize), test_tup2: (isize, isize, isize)) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_809_check_smaller.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "check_smaller", "test": "\n\nfn main() {\n let candidate = check_smaller;\n assert_eq!(candidate((1, 2, 3), (2, 3, 4)), false);\n assert_eq!(candidate((4, 5, 6), (3, 4, 5)), true);\n assert_eq!(candidate((11, 12, 13), (10, 11, 12)), true);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check if each element of second tuple is smaller than its corresponding element in the first tuple.\nfn check_smaller(test_tup1: (isize, isize, isize), test_tup2: (isize, isize, isize)) -> bool {\n if test_tup2.0 < test_tup1.0 && test_tup2.1 < test_tup1.1 && test_tup2.2 < test_tup1.2 {\n return true;\n }\n false\n}"} +{"name": "mbpp_629_Split", "language": "rs", "prompt": "/// Write a rsthon function to find even numbers from a vector of numbers.\nfn Split(list: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_629_Split.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "Split", "test": "\n\nfn main() {\n let candidate = Split;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5]), vec![2, 4]);\n assert_eq!(candidate(vec![4, 5, 6, 7, 8, 0, 1]), vec![4, 6, 8, 0]);\n assert_eq!(candidate(vec![8, 12, 15, 19]), vec![8, 12]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find even numbers from a vector of numbers.\nfn Split(list: Vec) -> Vec {\n let mut even_numbers = Vec::new();\n\n for number in list {\n if number % 2 == 0 {\n even_numbers.push(number);\n }\n }\n\n even_numbers\n}"} +{"name": "mbpp_723_count_same_pair", "language": "rs", "prompt": "/// The input is defined as two vectors of the same length. Write a function to count indices where the vectors have the same values.\nfn count_same_pair(nums1: Vec, nums2: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_723_count_same_pair.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_same_pair", "test": "\n\nfn main() {\n let candidate = count_same_pair;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8], vec![2, 2, 3, 1, 2, 6, 7, 9]), 4);\n assert_eq!(candidate(vec![0, 1, 2, -1, -5, 6, 0, -3, -2, 3, 4, 6, 8], vec![2, 1, 2, -1, -5, 6, 4, -3, -2, 3, 4, 6, 8]), 11);\n assert_eq!(candidate(vec![2, 4, -6, -9, 11, -12, 14, -5, 17], vec![2, 1, 2, -1, -5, 6, 4, -3, -2, 3, 4, 6, 8]), 1);\n assert_eq!(candidate(vec![0, 1, 1, 2], vec![0, 1, 2, 2]), 3);\n}\n", "is_solved": true, "reflections": [], "solution": "/// The input is defined as two vectors of the same length. Write a function to count indices where the vectors have the same values.\nfn count_same_pair(nums1: Vec, nums2: Vec) -> isize {\n let mut count = 0;\n for i in 0..nums1.len() {\n if nums1[i] == nums2[i] {\n count += 1;\n }\n }\n count\n}"} +{"name": "mbpp_242_count_charac", "language": "rs", "prompt": "/// Write a function to count the total number of characters in a string.\nfn count_charac(str1: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_242_count_charac.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_charac", "test": "\n\nfn main() {\n let candidate = count_charac;\n assert_eq!(candidate(String::from(\"python programming\")), 18);\n assert_eq!(candidate(String::from(\"language\")), 8);\n assert_eq!(candidate(String::from(\"words\")), 5);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to count the total number of characters in a string.\nfn count_charac(str1: String) -> isize {\n let count = str1.chars().count() as isize;\n count\n}"} +{"name": "mbpp_616_tuple_modulo", "language": "rs", "prompt": "/// Write a function which takes two tuples of the same length and performs the element wise modulo.\nfn tuple_modulo(test_tup1: (isize, isize, isize, isize), test_tup2: (isize, isize, isize, isize)) -> (isize, isize, isize, isize) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_616_tuple_modulo.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "tuple_modulo", "test": "\n\nfn main() {\n let candidate = tuple_modulo;\n assert_eq!(candidate((10, 4, 5, 6), (5, 6, 7, 5)), (0, 4, 5, 1));\n assert_eq!(candidate((11, 5, 6, 7), (6, 7, 8, 6)), (5, 5, 6, 1));\n assert_eq!(candidate((12, 6, 7, 8), (7, 8, 9, 7)), (5, 6, 7, 1));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function which takes two tuples of the same length and performs the element wise modulo.\nfn tuple_modulo(test_tup1: (isize, isize, isize, isize), test_tup2: (isize, isize, isize, isize)) -> (isize, isize, isize, isize) {\n let result = (\n test_tup1.0 % test_tup2.0,\n test_tup1.1 % test_tup2.1,\n test_tup1.2 % test_tup2.2,\n test_tup1.3 % test_tup2.3,\n );\n\n result\n}"} +{"name": "mbpp_583_catalan_number", "language": "rs", "prompt": "/// Write a function which returns nth catalan number.\nfn catalan_number(num: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_583_catalan_number.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "catalan_number", "test": "\n\nfn main() {\n let candidate = catalan_number;\n assert_eq!(candidate(10), 16796);\n assert_eq!(candidate(9), 4862);\n assert_eq!(candidate(7), 429);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function which returns nth catalan number.\nfn catalan_number(num: isize) -> isize {\n if num <= 1 {\n return 1;\n }\n\n let mut result = 0;\n for i in 0..num {\n result += catalan_number(i) * catalan_number(num - i - 1);\n }\n\n result\n}"} +{"name": "mbpp_129_magic_square_test", "language": "rs", "prompt": "/// Write a function to calculate whether the matrix is a magic square.\nfn magic_square_test(my_matrix: Vec>) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_129_magic_square_test.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "magic_square_test", "test": "\n\nfn main() {\n let candidate = magic_square_test;\n assert_eq!(candidate(vec![vec![7, 12, 1, 14], vec![2, 13, 8, 11], vec![16, 3, 10, 5], vec![9, 6, 15, 4]]), true);\n assert_eq!(candidate(vec![vec![2, 7, 6], vec![9, 5, 1], vec![4, 3, 8]]), true);\n assert_eq!(candidate(vec![vec![2, 7, 6], vec![9, 5, 1], vec![4, 3, 7]]), false);\n}\n", "solution": "/// Write a function to calculate whether the matrix is a magic square.\nfn magic_square_test(my_matrix: Vec>) -> bool {\n let n = my_matrix.len();\n let magic_sum = (n * (n * n + 1)) / 2;\n let magic_sum_isize = magic_sum as isize;\n\n // Check rows\n for row in &my_matrix {\n let row_sum: isize = row.iter().sum();\n if row_sum != magic_sum_isize {\n return false;\n }\n }\n\n // Check columns\n for i in 0..n {\n let mut col_sum = 0;\n for j in 0..n {\n col_sum += my_matrix[j][i];\n }\n if col_sum != magic_sum_isize {\n return false;\n }\n }\n\n // Check diagonals\n let mut diag1_sum = 0;\n let mut diag2_sum = 0;\n for i in 0..n {\n diag1_sum += my_matrix[i][i];\n diag2_sum += my_matrix[i][n - i - 1];\n }\n if diag1_sum != magic_sum_isize || diag2_sum != magic_sum_isize {\n return false;\n }\n\n true\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it has mismatched types when comparing sums. The `magic_sum` variable is of type `usize`, while the row, column, and diagonal sums are of type `isize`. To fix this issue, either convert `magic_sum` to `isize` or the other sums to `usize` before making the comparisons."]} +{"name": "mbpp_61_count_Substrings", "language": "rs", "prompt": "/// Write a rsthon function to count the number of substrings with the sum of digits equal to their length.\nfn count_Substrings(s: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_61_count_Substrings.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_Substrings", "test": "\n\nfn main() {\n let candidate = count_Substrings;\n assert_eq!(candidate(String::from(\"112112\")), 6);\n assert_eq!(candidate(String::from(\"111\")), 6);\n assert_eq!(candidate(String::from(\"1101112\")), 12);\n}\n", "solution": "/// Write a rsthon function to count the number of substrings with the sum of digits equal to their length.\nfn count_Substrings(s: String) -> isize {\n let mut count = 0;\n let chars: Vec = s.chars().collect();\n\n for i in 0..chars.len() {\n let mut sum = 0;\n for j in i..chars.len() {\n if let Some(digit) = chars[j].to_digit(10) {\n sum += digit;\n }\n if sum == (j - i + 1) as u32 {\n count += 1;\n }\n }\n }\n\n count as isize\n}", "is_solved": true, "reflections": ["The implementation of the count_Substrings function is incorrect because it is counting all substrings with a sum of digits equal to their length, but it is not resetting the sum variable when it should. As a result, the function is over-counting the number of valid substrings, leading to incorrect results in the failed test cases.", "The implementation of the count_Substrings function is incorrect because it stops counting substrings as soon as it finds one with the sum of digits equal to its length. This causes the function to miss other valid substrings that also meet the criteria. The 'break' statement inside the inner loop should be removed to fix this issue.", "The implementation is incorrect because it counts all substrings with the sum of digits equal to their length, but it does not reset the sum variable when moving to the next starting position. This causes the count to be higher than expected, as it accumulates the sum from previous substrings.", "The implementation of the count_Substrings function is incorrect because it does not properly handle cases where there are multiple substrings with the sum of digits equal to their length. The current logic stops counting as soon as the sum becomes greater than the length, which causes it to miss valid substrings."]} +{"name": "mbpp_287_square_Sum", "language": "rs", "prompt": "/// Write a rsthon function takes in an integer n and returns the sum of squares of first n even natural numbers.\nfn square_Sum(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_287_square_Sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "square_Sum", "test": "\n\nfn main() {\n let candidate = square_Sum;\n assert_eq!(candidate(2), 20);\n assert_eq!(candidate(3), 56);\n assert_eq!(candidate(4), 120);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a rsthon function takes in an integer n and returns the sum of squares of first n even natural numbers.\nfn square_Sum(n: isize) -> isize {\n let mut sum = 0;\n\n for i in 0..(n * 2) {\n if i % 2 == 0 {\n sum += i * i;\n }\n }\n\n sum\n}"} +{"name": "mbpp_93_power", "language": "rs", "prompt": "/// Write a function to calculate the value of 'a' to the power 'b'.\nfn power(a: isize, b: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_93_power.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "power", "test": "\n\nfn main() {\n let candidate = power;\n assert_eq!(candidate(3, 4), 81);\n assert_eq!(candidate(2, 3), 8);\n assert_eq!(candidate(5, 5), 3125);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to calculate the value of 'a' to the power 'b'.\nfn power(a: isize, b: isize) -> isize {\n let mut result = 1;\n for _ in 0..b {\n result *= a;\n }\n result\n}"} +{"name": "mbpp_607_find_literals", "language": "rs", "prompt": "/// Write a function to search a string for a regex pattern. The function should return the matching subtring, a start index and an end index.\nfn find_literals(text: String, pattern: String) -> (String, isize, isize) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_607_find_literals.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_literals", "test": "\n\nfn main() {\n let candidate = find_literals;\n assert_eq!(candidate(String::from(\"The quick brown fox jumps over the lazy dog.\"), String::from(\"fox\")), (String::from(\"fox\"), 16, 19));\n assert_eq!(candidate(String::from(\"Its been a very crazy procedure right\"), String::from(\"crazy\")), (String::from(\"crazy\"), 16, 21));\n assert_eq!(candidate(String::from(\"Hardest choices required strongest will\"), String::from(\"will\")), (String::from(\"will\"), 35, 39));\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because the `regex` crate is not declared or imported properly, causing an unresolved import error. To fix this issue, the `regex` crate should be added to the `Cargo.toml` file and imported at the beginning of the code file.", "The implementation is incorrect because the `regex` crate is not declared or imported properly, causing an unresolved import error. To fix this issue, the `regex` crate needs to be added to the `Cargo.toml` file and imported correctly at the beginning of the code.", "The implementation is incorrect because the `regex` crate is not declared or imported in the current scope, causing an unresolved import error. To fix this issue, the `regex` crate should be added to the `Cargo.toml` file and imported at the beginning of the code file.", "The implementation is incorrect because the `regex` crate is not declared or imported properly, causing an unresolved import error. To fix this, the `regex` crate should be added to the `Cargo.toml` file and imported at the beginning of the code file."], "solution": "/// Write a function to search a string for a regex pattern. The function should return the matching subtring, a start index and an end index.\nfn find_literals(text: String, pattern: String) -> (String, isize, isize) {\n use regex::Regex;\n\n let re = match Regex::new(&pattern) {\n Ok(re) => re,\n Err(_) => return (String::new(), -1, -1),\n };\n\n if let Some(mat) = re.find(&text) {\n let start = mat.start() as isize;\n let end = mat.end() as isize;\n let matched = mat.as_str().to_string();\n return (matched, start, end);\n }\n\n (String::new(), -1, -1)\n}"} +{"name": "mbpp_94_index_minimum", "language": "rs", "prompt": "/// Given a vector of tuples, write a function that returns the first value of the tuple with the smallest second value.\nfn index_minimum(test_list: Vec<(String, isize)>) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_94_index_minimum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "index_minimum", "test": "\n\nfn main() {\n let candidate = index_minimum;\n assert_eq!(candidate(vec![(String::from(\"Rash\"), 143), (String::from(\"Manjeet\"), 200), (String::from(\"Varsha\"), 100)]), String::from(\"Varsha\"));\n assert_eq!(candidate(vec![(String::from(\"Yash\"), 185), (String::from(\"Dawood\"), 125), (String::from(\"Sanya\"), 175)]), String::from(\"Dawood\"));\n assert_eq!(candidate(vec![(String::from(\"Sai\"), 345), (String::from(\"Salman\"), 145), (String::from(\"Ayesha\"), 96)]), String::from(\"Ayesha\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Given a vector of tuples, write a function that returns the first value of the tuple with the smallest second value.\nfn index_minimum(test_list: Vec<(String, isize)>) -> String {\n let mut min_index = 0;\n let mut min_value = test_list[0].1;\n\n for (index, tuple) in test_list.iter().enumerate() {\n if tuple.1 < min_value {\n min_value = tuple.1;\n min_index = index;\n }\n }\n\n test_list[min_index].0.clone()\n}"} +{"name": "mbpp_138_is_Sum_Of_Powers_Of_Two", "language": "rs", "prompt": "/// Write a rsthon function to check whether the given number can be represented as sum of non-zero powers of 2 or not.\nfn is_Sum_Of_Powers_Of_Two(n: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_138_is_Sum_Of_Powers_Of_Two.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_Sum_Of_Powers_Of_Two", "test": "\n\nfn main() {\n let candidate = is_Sum_Of_Powers_Of_Two;\n assert_eq!(candidate(10), true);\n assert_eq!(candidate(7), false);\n assert_eq!(candidate(14), true);\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because the function argument `n` is immutable, and an attempt is made to modify it with the bitwise right shift assignment operation `n >>= 1;`. To fix this issue, the argument should be made mutable by declaring it as `mut n`.", "The implementation is incorrect because it checks if the given number is a power of 2, not if it can be represented as a sum of non-zero powers of 2. The failed test case (6) can be represented as the sum of 2^1 and 2^2, but the current implementation returns false since 6 is not a power of 2.", "The implementation of the is_Sum_Of_Powers_Of_Two function is incorrect because it does not properly check if the given number can be represented as a sum of non-zero powers of 2. The current logic divides the number by 2 if it's even and subtracts 1 if it's odd, which does not guarantee that the number is a sum of distinct powers of 2. This is evident in the failed test case where the input is 7, which is not a sum of distinct powers of 2, but the function returns true.", "The implementation is incorrect because it checks if the number of set bits (1s) in the binary representation of the input number is greater than 1. This logic fails for cases where the input number is a power of 2 (e.g., 8 or 2) and for cases where the input number is one less than a power of 2 (e.g., 7). The function should instead check if the input number can be represented as a sum of distinct non-zero powers of 2."], "solution": "/// Write a rsthon function to check whether the given number can be represented as sum of non-zero powers of 2 or not.\nfn is_Sum_Of_Powers_Of_Two(n: isize) -> bool {\n if n <= 0 {\n return false;\n }\n\n let mut num = n;\n let mut count = 0;\n\n while num > 0 {\n if num % 2 == 1 {\n count += 1;\n }\n num >>= 1;\n }\n\n count >= 1 && (n & (n - 1)) != 0\n}"} +{"name": "mbpp_594_diff_even_odd", "language": "rs", "prompt": "/// Write a function to find the difference of the first even and first odd number of a given vector.\nfn diff_even_odd(list1: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_594_diff_even_odd.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "diff_even_odd", "test": "\n\nfn main() {\n let candidate = diff_even_odd;\n assert_eq!(candidate(vec![1, 3, 5, 7, 4, 1, 6, 8]), 3);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 10]), 1);\n assert_eq!(candidate(vec![1, 5, 7, 9, 10]), 9);\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because it stops searching for even and odd numbers as soon as both are found, regardless of their order in the vector. This causes the function to return the difference between the first even and first odd numbers it encounters, rather than the difference between the first even and first odd numbers in the given order.", "The implementation is wrong because it tries to borrow the `list1` vector after it has been moved due to the implicit call to `.into_iter()` in the for loop. To fix this issue, you should iterate over a slice of the `Vec`'s content by using `&list1` instead of `list1` in the for loop. This will avoid moving the vector into the loop and allow you to borrow it later in the code.", "The implementation is incorrect because it resets the even and odd variables to None if the first even number found appears after the first odd number. This causes the function to not return the correct difference between the first even and first odd numbers in some cases, as it keeps searching for a new pair where the even number comes before the odd number.", "The implementation is incorrect because it stops searching for even and odd numbers as soon as both are found, regardless of their order in the vector. This causes the function to return the wrong result when the first even number appears before the first odd number, as seen in the failed test case."], "solution": "/// Write a function to find the difference of the first even and first odd number of a given vector.\nfn diff_even_odd(list1: Vec) -> isize {\n let mut even: Option = None;\n let mut odd: Option = None;\n\n for num in &list1 {\n if even.is_none() && num % 2 == 0 {\n even = Some(*num);\n } else if odd.is_none() && num % 2 != 0 {\n odd = Some(*num);\n }\n\n if even.is_some() && odd.is_some() {\n if list1.iter().position(|&x| x == even.unwrap()) < list1.iter().position(|&x| x == odd.unwrap()) {\n break;\n } else {\n even = None;\n odd = None;\n }\n }\n }\n\n match (even, odd) {\n (Some(e), Some(o)) => e - o,\n _ => 0,\n }\n}"} +{"name": "mbpp_274_even_binomial_Coeff_Sum", "language": "rs", "prompt": "/// Write a rsthon function that takes in a positive integer n and finds the sum of even index binomial coefficients.\nfn even_binomial_Coeff_Sum(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_274_even_binomial_Coeff_Sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "even_binomial_Coeff_Sum", "test": "\n\nfn main() {\n let candidate = even_binomial_Coeff_Sum;\n assert_eq!(candidate(4), 8);\n assert_eq!(candidate(6), 32);\n assert_eq!(candidate(2), 2);\n}\n", "solution": "/// Write a rsthon function that takes in a positive integer n and finds the sum of even index binomial coefficients.\nfn even_binomial_Coeff_Sum(n: isize) -> isize {\n fn binomial_coeff(n: isize, k: isize) -> isize {\n if k == 0 || k == n {\n return 1;\n }\n binomial_coeff(n - 1, k - 1) + binomial_coeff(n - 1, k)\n }\n\n let mut sum = 0;\n let mut i = 0;\n\n while i <= n {\n if i % 2 == 0 {\n sum += binomial_coeff(n, i);\n }\n i += 2;\n }\n\n sum\n}", "is_solved": true, "reflections": ["The implementation is wrong because the argument `k` in the `binomial_coeff` function is immutable, and the code tries to assign a new value to it. To fix this issue, the argument `k` should be made mutable by adding the `mut` keyword before it in the function definition.", "The implementation of the even_binomial_Coeff_Sum function is incorrect because it calculates the sum of all binomial coefficients, not just the ones with even indices. This leads to incorrect results for the failed test cases, as the sum includes odd index binomial coefficients as well.", "The implementation of the even_binomial_Coeff_Sum function is incorrect because it is summing up the binomial coefficients for all even indices, but it is not considering the correct formula for the sum of even index binomial coefficients. The failed tests indicate that the function is returning higher values than expected, which suggests that the logic for calculating the sum is flawed.", "The implementation is wrong because the `binomial_coeff` function is not defined or imported in the current scope. This results in a compilation error as the compiler cannot find the function to calculate the binomial coefficient."]} +{"name": "mbpp_126_sum", "language": "rs", "prompt": "/// Write a rsthon function to find the sum of common divisors of two given numbers.\nfn sum(a: isize, b: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_126_sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sum", "test": "\n\nfn main() {\n let candidate = sum;\n assert_eq!(candidate(10, 15), 6);\n assert_eq!(candidate(100, 150), 93);\n assert_eq!(candidate(4, 6), 3);\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because it calculates the sum of common divisors, but the failed test case expects the greatest common divisor. The function should be modified to return the greatest common divisor instead of the sum of common divisors.", "The implementation is incorrect because it calculates the greatest common divisor (GCD) of the two given numbers instead of finding the sum of their common divisors. The failed test cases show that the output is the GCD, not the sum of common divisors as required.", "The implementation of the sum function is incorrect because it does not properly calculate the sum of common divisors for certain input pairs, as demonstrated by the failed test case (6, 8). The function is only considering divisors up to the minimum of the two input numbers, which may exclude some common divisors.", "The implementation is incorrect because it tries to use the `sqrt` method on an `isize` type, which is not supported. The `sqrt` method is available for floating-point types like `f32` and `f64`, but not for integer types like `isize`."], "solution": "/// Write a rsthon function to find the sum of common divisors of two given numbers.\nfn sum(a: isize, b: isize) -> isize {\n let mut common_divisors_sum = 0;\n let max_divisor = ((a * b) as f64).sqrt().ceil() as isize;\n\n for i in 1..=max_divisor {\n if a % i == 0 && b % i == 0 {\n common_divisors_sum += i;\n if i != a / i && i != b / i {\n common_divisors_sum += a / i;\n }\n }\n }\n\n common_divisors_sum\n}"} +{"name": "mbpp_769_Diff", "language": "rs", "prompt": "/// Write a rsthon function to get the difference between two vectors.\nfn Diff(li1: Vec, li2: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_769_Diff.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "Diff", "test": "\n\nfn main() {\n let candidate = Diff;\n assert_eq!(candidate(vec![10, 15, 20, 25, 30, 35, 40], vec![25, 40, 35]), vec![10, 20, 30, 15]);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5], vec![6, 7, 1]), vec![2, 3, 4, 5, 6, 7]);\n assert_eq!(candidate(vec![1, 2, 3], vec![6, 7, 1]), vec![2, 3, 6, 7]);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a rsthon function to get the difference between two vectors.\nfn Diff(li1: Vec, li2: Vec) -> Vec {\n let mut result: Vec = Vec::new();\n\n for i in 0..li1.len() {\n result.push(li1[i] - li2[i]);\n }\n\n result\n}"} +{"name": "mbpp_796_return_sum", "language": "rs", "prompt": "use std::collections::HashMap;\n\n/// Write function to find the sum of all items in the given HashMap.\nfn return_sum(dict: HashMap) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_796_return_sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "return_sum", "test": "\n\nfn main() {\n let candidate = return_sum;\n assert_eq!(candidate(HashMap::from([(String::from(\"a\"), 100), (String::from(\"b\"), 200), (String::from(\"c\"), 300)])), 600);\n assert_eq!(candidate(HashMap::from([(String::from(\"a\"), 25), (String::from(\"b\"), 18), (String::from(\"c\"), 45)])), 88);\n assert_eq!(candidate(HashMap::from([(String::from(\"a\"), 36), (String::from(\"b\"), 39), (String::from(\"c\"), 49)])), 124);\n}\n", "is_solved": true, "reflections": [], "solution": "use std::collections::HashMap;\n\n/// Write function to find the sum of all items in the given HashMap.\nfn return_sum(dict: HashMap) -> isize {\n let mut sum = 0;\n for value in dict.values() {\n sum += value;\n }\n sum\n}"} +{"name": "mbpp_574_surfacearea_cylinder", "language": "rs", "prompt": "/// Write a function to find the surface area of a cylinder.\nfn surfacearea_cylinder(r: isize, h: isize) -> f64 {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_574_surfacearea_cylinder.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "surfacearea_cylinder", "test": "\n\nfn main() {\n let candidate = surfacearea_cylinder;\n assert_eq!(candidate(10, 5), 942.45);\n assert_eq!(candidate(4, 5), 226.18800000000002);\n assert_eq!(candidate(4, 10), 351.848);\n}\n", "is_solved": false, "reflections": ["The implementation of the surfacearea_cylinder function is incorrect because it calculates the surface area as 2 times the base area plus the lateral area. The correct formula for the surface area of a cylinder is the sum of the base areas and the lateral area, not twice the base areas. This error causes the function to return incorrect results for the given test cases.", "The implementation of the surfacearea_cylinder function is incorrect because it calculates the surface area by adding the base area twice instead of adding the base area and the top area. This results in an overestimation of the surface area, causing the failed test cases.", "The implementation is wrong because it calculates the surface area of a cylinder by adding the base area, top area, and lateral area. However, the expected results in the failed tests are calculated using only the lateral area of the cylinder, which is incorrect. The correct formula for the surface area of a cylinder is 2 * pi * r * (r + h), where r is the radius and h is the height.", "The implementation of the surfacearea_cylinder function is incorrect because it calculates the surface area using the formula 2 * pi * radius * (radius + height), which is actually the formula for the lateral surface area of a cylinder plus the area of one base. The correct formula for the total surface area of a cylinder is 2 * pi * radius * (radius + height / 2). This error in the formula is causing the function to return incorrect results for the failed test cases."], "solution": "/// Write a function to find the surface area of a cylinder.\nfn surfacearea_cylinder(r: isize, h: isize) -> f64 {\n let pi = std::f64::consts::PI;\n let radius = r as f64;\n let height = h as f64;\n\n let surface_area = 2.0 * pi * radius * (radius + height / 2.0);\n surface_area\n}"} +{"name": "mbpp_783_rgb_to_hsv", "language": "rs", "prompt": "/// Write a function to convert rgb color to hsv color. https://www.geeksforgeeks.org/program-change-rgb-color-model-hsv-color-model/\nfn rgb_to_hsv(r: isize, g: isize, b: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_783_rgb_to_hsv.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "rgb_to_hsv", "test": "\n\nfn main() {\n let candidate = rgb_to_hsv;\n assert_eq!(candidate(255, 255, 255), vec![0.0, 0.0, 100.0]);\n assert_eq!(candidate(0, 215, 0), vec![120.0, 100.0, 84.31372549019608]);\n assert_eq!(candidate(10, 215, 110), vec![149.26829268292684, 95.34883720930233, 84.31372549019608]);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a function to convert rgb color to hsv color. https://www.geeksforgeeks.org/program-change-rgb-color-model-hsv-color-model/\nfn rgb_to_hsv(r: isize, g: isize, b: isize) -> Vec {\n let r = r as f64 / 255.0;\n let g = g as f64 / 255.0;\n let b = b as f64 / 255.0;\n\n let max = r.max(g).max(b);\n let min = r.min(g).min(b);\n let diff = max - min;\n\n let h = if max == min {\n 0.0\n } else if max == r {\n 60.0 * (((g - b) / diff) % 6.0)\n } else if max == g {\n 60.0 * (((b - r) / diff) + 2.0)\n } else {\n 60.0 * (((r - g) / diff) + 4.0)\n };\n\n let s = if max == 0.0 {\n 0.0\n } else {\n diff / max\n };\n\n let v = max;\n\n vec![h, s, v]\n}"} +{"name": "mbpp_70_get_equal", "language": "rs", "prompt": "/// Write a function to find whether all the given vectors have equal length or not.\nfn get_equal(Input: Vec>) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_70_get_equal.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "get_equal", "test": "\n\nfn main() {\n let candidate = get_equal;\n assert_eq!(candidate(vec![vec![11, 22, 33], vec![44, 55, 66]]), true);\n assert_eq!(candidate(vec![vec![1, 2, 3], vec![4, 5, 6, 7]]), false);\n assert_eq!(candidate(vec![vec![1, 2], vec![3, 4]]), true);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find whether all the given vectors have equal length or not.\nfn get_equal(Input: Vec>) -> bool {\n let length = Input[0].len();\n\n for vec in Input.iter() {\n if vec.len() != length {\n return false;\n }\n }\n\n true\n}"} +{"name": "mbpp_267_square_Sum", "language": "rs", "prompt": "/// Write a rsthon function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.\nfn square_Sum(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_267_square_Sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "square_Sum", "test": "\n\nfn main() {\n let candidate = square_Sum;\n assert_eq!(candidate(2), 10);\n assert_eq!(candidate(3), 35);\n assert_eq!(candidate(4), 84);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function that takes in an integer n and returns the sum of the squares of the first n odd natural numbers.\nfn square_Sum(n: isize) -> isize {\n let mut sum = 0;\n let mut count = 0;\n let mut current = 1;\n\n while count < n {\n sum += current * current;\n count += 1;\n current += 2;\n }\n\n sum\n}"} +{"name": "mbpp_171_perimeter_pentagon", "language": "rs", "prompt": "/// Write a function to find the perimeter of a regular pentagon from the length of its sides.\nfn perimeter_pentagon(a: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_171_perimeter_pentagon.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "perimeter_pentagon", "test": "\n\nfn main() {\n let candidate = perimeter_pentagon;\n assert_eq!(candidate(5), 25);\n assert_eq!(candidate(10), 50);\n assert_eq!(candidate(15), 75);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the perimeter of a regular pentagon from the length of its sides.\nfn perimeter_pentagon(a: isize) -> isize {\n 5 * a\n}"} +{"name": "mbpp_164_are_equivalent", "language": "rs", "prompt": "/// Write a function to determine if the sum of the divisors of two integers are the same.\nfn are_equivalent(num1: isize, num2: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_164_are_equivalent.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "are_equivalent", "test": "\n\nfn main() {\n let candidate = are_equivalent;\n assert_eq!(candidate(36, 57), false);\n assert_eq!(candidate(2, 4), false);\n assert_eq!(candidate(23, 47), true);\n}\n", "solution": "/// Write a function to determine if the sum of the divisors of two integers are the same.\nfn are_equivalent(num1: isize, num2: isize) -> bool {\n fn sum_of_divisors(num: isize) -> isize {\n let mut sum = 0;\n let sqrt_num = (num as f64).sqrt() as isize;\n for i in 1..=sqrt_num {\n if num % i == 0 {\n sum += i;\n if i != num / i && i != 1 {\n sum += num / i;\n }\n }\n }\n if sqrt_num * sqrt_num == num {\n sum += sqrt_num;\n }\n sum\n }\n\n sum_of_divisors(num1) == sum_of_divisors(num2)\n}", "is_solved": true, "reflections": ["The implementation of the `are_equivalent` function is incorrect because it does not properly calculate the sum of divisors for each number. The function `sum_of_divisors` only considers divisors up to half of the given number, which causes it to miss some divisors, leading to incorrect results in the comparison.", "The implementation of the `are_equivalent` function is incorrect because the `sum_of_divisors` function does not properly calculate the sum of divisors for the given numbers. Specifically, it fails to include the number itself as a divisor when it is a perfect square, leading to incorrect results for certain test cases.", "The implementation of the `are_equivalent` function is incorrect because it calculates the sum of divisors including the number itself. This causes the function to return false for cases where the sum of proper divisors (excluding the number itself) are the same, such as (15, 21) and (6, 28).", "The implementation of the `are_equivalent` function is incorrect because the `sum_of_divisors` function does not properly calculate the sum of divisors for the given numbers. Specifically, it fails to include the number itself as a divisor when the square root of the number is an integer, causing the sum of divisors to be incorrect for some cases. This leads to incorrect results for the failing tests."]} +{"name": "mbpp_803_is_perfect_square", "language": "rs", "prompt": "/// Write a function to check whether the given number is a perfect square or not. https://www.geeksforgeeks.org/check-if-given-number-is-perfect-square-in-cpp/\nfn is_perfect_square(n: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_803_is_perfect_square.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_perfect_square", "test": "\n\nfn main() {\n let candidate = is_perfect_square;\n assert_eq!(candidate(10), false);\n assert_eq!(candidate(36), true);\n assert_eq!(candidate(14), false);\n assert_eq!(candidate(196), true);\n assert_eq!(candidate(125), false);\n assert_eq!(candidate(15625), true);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check whether the given number is a perfect square or not. https://www.geeksforgeeks.org/check-if-given-number-is-perfect-square-in-cpp/\nfn is_perfect_square(n: isize) -> bool {\n if n < 0 {\n return false;\n }\n\n let mut i = 1;\n while i * i <= n {\n if i * i == n {\n return true;\n }\n i += 1;\n }\n\n false\n}"} +{"name": "mbpp_305_start_withp", "language": "rs", "prompt": "/// Write a function to return two words from a vector of words starting with letter 'p'.\nfn start_withp(words: Vec) -> (String, String) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_305_start_withp.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "start_withp", "test": "\n\nfn main() {\n let candidate = start_withp;\n assert_eq!(candidate(vec![String::from(\"Python PHP\"), String::from(\"Java JavaScript\"), String::from(\"c c++\")]), (String::from(\"Python\"), String::from(\"PHP\")));\n assert_eq!(candidate(vec![String::from(\"Python Programming\"), String::from(\"Java Programming\")]), (String::from(\"Python\"), String::from(\"Programming\")));\n assert_eq!(candidate(vec![String::from(\"Pqrst Pqr\"), String::from(\"qrstuv\")]), (String::from(\"Pqrst\"), String::from(\"Pqr\")));\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a function to return two words from a vector of words starting with letter 'p'.\nfn start_withp(words: Vec) -> (String, String) {\n let mut p_words = words.into_iter().filter(|word| word.starts_with('p')).take(2).collect::>();\n\n let first_word = p_words.get(0).cloned().unwrap_or_else(|| String::from(\"\"));\n let second_word = p_words.get(1).cloned().unwrap_or_else(|| String::from(\"\"));\n\n (first_word, second_word)\n}"} +{"name": "mbpp_617_min_Jumps", "language": "rs", "prompt": "/// Write a function to check for the number of jumps required of given length to reach a point of form (d, 0) from origin in a 2d plane.\nfn min_Jumps(steps: (isize, isize), d: isize) -> f64 {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_617_min_Jumps.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "min_Jumps", "test": "\n\nfn main() {\n let candidate = min_Jumps;\n assert_eq!(candidate((3, 4), 11), 3.5);\n assert_eq!(candidate((3, 4), 0), 0.0);\n assert_eq!(candidate((11, 14), 11), 1.0);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a function to check for the number of jumps required of given length to reach a point of form (d, 0) from origin in a 2d plane.\nfn min_Jumps(steps: (isize, isize), d: isize) -> f64 {\n let (x, y) = steps;\n let total_steps = (x.abs() + y.abs()) as f64;\n let min_jumps = (d as f64 / total_steps).ceil();\n min_jumps\n}"} +{"name": "mbpp_117_list_to_float", "language": "rs", "prompt": "/// Write a function to convert all possible convertible elements in a vector of vectors to floats.\nfn list_to_float(test_list: Vec<(String, String)>) -> Vec<(f64, f64)> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_117_list_to_float.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "list_to_float", "test": "\n\nfn main() {\n let candidate = list_to_float;\n assert_eq!(candidate(vec![(String::from(\"3\"), String::from(\"4\")), (String::from(\"1\"), String::from(\"26.45\")), (String::from(\"7.32\"), String::from(\"8\")), (String::from(\"4\"), String::from(\"8\"))]), vec![(3.0, 4.0), (1.0, 26.45), (7.32, 8.0), (4.0, 8.0)]);\n assert_eq!(candidate(vec![(String::from(\"4\"), String::from(\"4\")), (String::from(\"2\"), String::from(\"27\")), (String::from(\"4.12\"), String::from(\"9\")), (String::from(\"7\"), String::from(\"11\"))]), vec![(4.0, 4.0), (2.0, 27.0), (4.12, 9.0), (7.0, 11.0)]);\n assert_eq!(candidate(vec![(String::from(\"6\"), String::from(\"78\")), (String::from(\"5\"), String::from(\"26.45\")), (String::from(\"1.33\"), String::from(\"4\")), (String::from(\"82\"), String::from(\"13\"))]), vec![(6.0, 78.0), (5.0, 26.45), (1.33, 4.0), (82.0, 13.0)]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to convert all possible convertible elements in a vector of vectors to floats.\nfn list_to_float(test_list: Vec<(String, String)>) -> Vec<(f64, f64)> {\n test_list.into_iter()\n .map(|(a, b)| {\n let a_float = a.parse::().unwrap_or(0.0);\n let b_float = b.parse::().unwrap_or(0.0);\n (a_float, b_float)\n })\n .collect()\n}"} +{"name": "mbpp_67_bell_number", "language": "rs", "prompt": "/// Write a function to find the number of ways to partition a set of Bell numbers.\nfn bell_number(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_67_bell_number.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "bell_number", "test": "\n\nfn main() {\n let candidate = bell_number;\n assert_eq!(candidate(2), 2);\n assert_eq!(candidate(10), 115975);\n assert_eq!(candidate(56), 6775685320645824322581483068371419745979053216268760300);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a function to find the number of ways to partition a set of Bell numbers.\nfn bell_number(n: isize) -> isize {\n if n < 0 {\n panic!(\"Invalid input: n must be non-negative\");\n }\n\n let mut bell = vec![vec![0; (n + 1) as usize]; (n + 1) as usize];\n\n bell[0][0] = 1;\n for i in 1..=(n as usize) {\n bell[i][0] = bell[i - 1][i - 1];\n\n for j in 1..=i {\n bell[i][j] = bell[i - 1][j - 1] + bell[i][j - 1];\n }\n }\n\n bell[n as usize][0]\n}"} +{"name": "mbpp_404_minimum", "language": "rs", "prompt": "/// Write a rsthon function to find the minimum of two numbers.\nfn minimum(a: isize, b: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_404_minimum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "minimum", "test": "\n\nfn main() {\n let candidate = minimum;\n assert_eq!(candidate(1, 2), 1);\n assert_eq!(candidate(-5, -4), -5);\n assert_eq!(candidate(0, 0), 0);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the minimum of two numbers.\nfn minimum(a: isize, b: isize) -> isize {\n if a < b {\n a\n } else {\n b\n }\n}"} +{"name": "mbpp_14_find_Volume", "language": "rs", "prompt": "/// Write a rsthon function to find the volume of a triangular prism.\nfn find_Volume(l: isize, b: isize, h: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_14_find_Volume.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_Volume", "test": "\n\nfn main() {\n let candidate = find_Volume;\n assert_eq!(candidate(10, 8, 6), 240);\n assert_eq!(candidate(3, 2, 2), 6);\n assert_eq!(candidate(1, 2, 1), 1);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the volume of a triangular prism.\nfn find_Volume(l: isize, b: isize, h: isize) -> isize {\n let volume = l * b * h / 2;\n volume\n}"} +{"name": "mbpp_8_square_nums", "language": "rs", "prompt": "/// Write a function to find squares of individual elements in a vector.\nfn square_nums(nums: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_8_square_nums.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "square_nums", "test": "\n\nfn main() {\n let candidate = square_nums;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 10]), vec![1, 4, 9, 16, 25, 36, 49, 64, 81, 100]);\n assert_eq!(candidate(vec![10, 20, 30]), vec![100, 400, 900]);\n assert_eq!(candidate(vec![12, 15]), vec![144, 225]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find squares of individual elements in a vector.\nfn square_nums(nums: Vec) -> Vec {\n nums.into_iter().map(|x| x * x).collect()\n}"} +{"name": "mbpp_244_next_Perfect_Square", "language": "rs", "prompt": "/// Write a rsthon function to find the next perfect square greater than a given number.\nfn next_Perfect_Square(N: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_244_next_Perfect_Square.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "next_Perfect_Square", "test": "\n\nfn main() {\n let candidate = next_Perfect_Square;\n assert_eq!(candidate(35), 36);\n assert_eq!(candidate(6), 9);\n assert_eq!(candidate(9), 16);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the next perfect square greater than a given number.\nfn next_Perfect_Square(N: isize) -> isize {\n let mut next_square = N + 1;\n\n while !is_perfect_square(next_square) {\n next_square += 1;\n }\n\n next_square\n}\n\nfn is_perfect_square(num: isize) -> bool {\n let root = (num as f64).sqrt() as isize;\n root * root == num\n}"} +{"name": "mbpp_292_find", "language": "rs", "prompt": "/// Write a rsthon function to find quotient of two numbers (rounded down to the nearest integer).\nfn find(n: isize, m: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_292_find.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find", "test": "\n\nfn main() {\n let candidate = find;\n assert_eq!(candidate(10, 3), 3);\n assert_eq!(candidate(4, 2), 2);\n assert_eq!(candidate(20, 5), 4);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find quotient of two numbers (rounded down to the nearest integer).\nfn find(n: isize, m: isize) -> isize {\n if m == 0 {\n panic!(\"Division by zero is not allowed\");\n }\n n / m\n}"} +{"name": "mbpp_603_get_ludic", "language": "rs", "prompt": "/// Write a function to get all lucid numbers smaller than or equal to a given integer.\nfn get_ludic(n: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_603_get_ludic.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "get_ludic", "test": "\n\nfn main() {\n let candidate = get_ludic;\n assert_eq!(candidate(10), vec![1, 2, 3, 5, 7]);\n assert_eq!(candidate(25), vec![1, 2, 3, 5, 7, 11, 13, 17, 23, 25]);\n assert_eq!(candidate(45), vec![1, 2, 3, 5, 7, 11, 13, 17, 23, 25, 29, 37, 41, 43]);\n}\n", "is_solved": false, "reflections": ["The implementation is wrong because it tries to perform a modulo operation between a `usize` and an `isize` type, which is not allowed. The `enumerate()` function returns a tuple with the index as a `usize`, and the `ludic` variable is of type `isize`. The `Rem` trait is not implemented for this combination of types, causing the mismatched types and the \"cannot mod `usize` by `isize`\" errors.", "The implementation of the get_ludic function is incorrect because it causes a timeout for the failed test cases. This indicates that the function is taking too long to compute the ludic numbers, likely due to an inefficient algorithm or an infinite loop. The filtering and enumeration steps in the while loop may be causing the performance issue.", "The implementation of the get_ludic function is incorrect because it causes a timeout for some test cases. This is likely due to an inefficient algorithm or an infinite loop in the code. The function is not able to generate the correct ludic numbers within a reasonable time for the given input values.", "The implementation of the `get_ludic` function is incorrect because it causes a timeout for test cases with input values greater than 1. This is likely due to an inefficient algorithm or an infinite loop in the code, preventing the function from returning the expected results within a reasonable time frame."], "solution": "/// Write a function to get all lucid numbers smaller than or equal to a given integer.\nfn get_ludic(n: isize) -> Vec {\n let mut ludic_numbers = vec![1];\n let mut candidates: Vec = (2..=n).collect();\n\n while let Some(ludic) = candidates.first().cloned() {\n ludic_numbers.push(ludic);\n candidates.retain(|&x| x == ludic || x % ludic != 0);\n }\n\n ludic_numbers\n}"} +{"name": "mbpp_734_sum_Of_Subarray_Prod", "language": "rs", "prompt": "/// Write a rsthon function to find sum of products of all possible subvectors of a given vector. https://www.geeksforgeeks.org/sum-of-products-of-all-possible-subvectors/\nfn sum_Of_Subarray_Prod(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_734_sum_Of_Subarray_Prod.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sum_Of_Subarray_Prod", "test": "\n\nfn main() {\n let candidate = sum_Of_Subarray_Prod;\n assert_eq!(candidate(vec![1, 2, 3]), 20);\n assert_eq!(candidate(vec![1, 2]), 5);\n assert_eq!(candidate(vec![1, 2, 3, 4]), 84);\n}\n", "solution": "/// Write a rsthon function to find sum of products of all possible subvectors of a given vector. https://www.geeksforgeeks.org/sum-of-products-of-all-possible-subvectors/\nfn sum_Of_Subarray_Prod(arr: Vec) -> isize {\n let n = arr.len();\n let mut sum = 0;\n\n for i in 0..n {\n let mut product = 1;\n for j in i..n {\n product *= arr[j];\n sum += product;\n }\n }\n\n sum\n}", "is_solved": true, "reflections": ["The implementation of the sum_Of_Subarray_Prod function is incorrect because it does not properly calculate the sum of products of all possible subvectors. The current formula `(i as isize + 1) * (n as isize - i as isize)` does not account for all the combinations of subvectors and their products. This is evident from the failed test cases where the expected output does not match the actual output.", "The implementation is incorrect because it calculates the sum of products of all possible subarrays instead of subvectors. The current implementation considers only contiguous elements, while subvectors can have non-contiguous elements. This leads to incorrect results for the given test cases.", "The implementation of the sum_Of_Subarray_Prod function is incorrect because it calculates the sum of products of all possible subsets of the given vector, not the sum of products of all possible subvectors. The difference is that subsets can have elements that are not contiguous in the original vector, while subvectors must have contiguous elements. The failed tests indicate that the function is not handling the contiguous elements requirement correctly.", "The current implementation calculates the sum of products of all possible subarrays, not subvectors. It iterates through all possible subarrays and calculates their product, then adds it to the sum. This approach does not account for the overlapping elements in subvectors, which leads to incorrect results for the given test cases."]} +{"name": "mbpp_567_issort_list", "language": "rs", "prompt": "/// Write a function to check whether a specified vector is sorted or not.\nfn issort_list(list1: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_567_issort_list.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "issort_list", "test": "\n\nfn main() {\n let candidate = issort_list;\n assert_eq!(candidate(vec![1, 2, 4, 6, 8, 10, 12, 14, 16, 17]), true);\n assert_eq!(candidate(vec![1, 2, 4, 6, 8, 10, 12, 14, 20, 17]), false);\n assert_eq!(candidate(vec![1, 2, 4, 6, 8, 10, 15, 14, 20]), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check whether a specified vector is sorted or not.\nfn issort_list(list1: Vec) -> bool {\n if list1.is_empty() {\n return true;\n }\n\n for i in 1..list1.len() {\n if list1[i - 1] > list1[i] {\n return false;\n }\n }\n\n true\n}"} +{"name": "mbpp_475_sort_counter", "language": "rs", "prompt": "use std::collections::HashMap;\n\n/// Write a function to sort a HashMap by value.\nfn sort_counter(dict1: HashMap) -> Vec<(String, isize)> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_475_sort_counter.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sort_counter", "test": "\n\nfn main() {\n let candidate = sort_counter;\n assert_eq!(candidate(HashMap::from([(String::from(\"Math\"), 81), (String::from(\"Physics\"), 83), (String::from(\"Chemistry\"), 87)])), vec![(String::from(\"Chemistry\"), 87), (String::from(\"Physics\"), 83), (String::from(\"Math\"), 81)]);\n assert_eq!(candidate(HashMap::from([(String::from(\"Math\"), 400), (String::from(\"Physics\"), 300), (String::from(\"Chemistry\"), 250)])), vec![(String::from(\"Math\"), 400), (String::from(\"Physics\"), 300), (String::from(\"Chemistry\"), 250)]);\n assert_eq!(candidate(HashMap::from([(String::from(\"Math\"), 900), (String::from(\"Physics\"), 1000), (String::from(\"Chemistry\"), 1250)])), vec![(String::from(\"Chemistry\"), 1250), (String::from(\"Physics\"), 1000), (String::from(\"Math\"), 900)]);\n}\n", "is_solved": false, "reflections": [], "solution": "use std::collections::HashMap;\n\n/// Write a function to sort a HashMap by value.\nfn sort_counter(dict1: HashMap) -> Vec<(String, isize)> {\n let mut vec: Vec<(&String, &isize)> = dict1.iter().collect();\n vec.sort_by(|a, b| a.1.cmp(b.1));\n\n vec.into_iter().map(|(k, v)| (k.clone(), *v)).collect()\n}"} +{"name": "mbpp_560_union_elements", "language": "rs", "prompt": "/// Write a function to find the union of the elements of two given vectors and output them in sorted order.\nfn union_elements(test_tup1: Vec, test_tup2: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_560_union_elements.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "union_elements", "test": "\n\nfn main() {\n let candidate = union_elements;\n assert_eq!(candidate(vec![3, 4, 5, 6], vec![5, 7, 4, 10]), vec![3, 4, 5, 6, 7, 10]);\n assert_eq!(candidate(vec![1, 2, 3, 4], vec![3, 4, 5, 6]), vec![1, 2, 3, 4, 5, 6]);\n assert_eq!(candidate(vec![11, 12, 13, 14], vec![13, 15, 16, 17]), vec![11, 12, 13, 14, 15, 16, 17]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the union of the elements of two given vectors and output them in sorted order.\nfn union_elements(test_tup1: Vec, test_tup2: Vec) -> Vec {\n let mut result: Vec = Vec::new();\n\n for elem in test_tup1.into_iter() {\n if !result.contains(&elem) {\n result.push(elem);\n }\n }\n\n for elem in test_tup2.into_iter() {\n if !result.contains(&elem) {\n result.push(elem);\n }\n }\n\n result.sort();\n result\n}"} +{"name": "mbpp_737_check_str", "language": "rs", "prompt": "/// Write a function to check whether the given string is starting with a vowel or not using regex.\nfn check_str(string: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_737_check_str.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "check_str", "test": "\n\nfn main() {\n let candidate = check_str;\n assert_eq!(candidate(String::from(\"annie\")), true);\n assert_eq!(candidate(String::from(\"dawood\")), false);\n assert_eq!(candidate(String::from(\"Else\")), true);\n}\n", "is_solved": false, "reflections": ["The implementation is wrong because the `regex` crate is not declared or imported, causing the compiler to throw an error. To fix this issue, the `regex` crate needs to be added to the `Cargo.toml` file and imported using `use regex::Regex;` at the beginning of the code.", "The implementation is incorrect because the `regex` crate is not declared or imported in the current scope, causing an unresolved import error. To fix this issue, the `regex` crate should be added to the project's dependencies and properly imported.", "The implementation is incorrect because the `regex` crate is not declared or imported in the current scope, causing an unresolved import error. To fix this issue, the `regex` crate needs to be added to the project's dependencies and properly imported.", "The implementation is incorrect because the `regex` crate is not declared or imported in the current scope, causing an unresolved import error. To fix this issue, the `regex` crate needs to be added to the project's dependencies and properly imported."], "solution": "/// Write a function to check whether the given string is starting with a vowel or not using regex.\nfn check_str(string: String) -> bool {\n use regex::Regex;\n let re = Regex::new(r\"^[aeiouAEIOU]\").unwrap();\n re.is_match(&string)\n}"} +{"name": "mbpp_626_triangle_area", "language": "rs", "prompt": "/// Write a rsthon function to find the area of the largest triangle that can be inscribed in a semicircle with a given radius.\nfn triangle_area(r: isize) -> Option {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_626_triangle_area.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "triangle_area", "test": "\n\nfn main() {\n let candidate = triangle_area;\n assert_eq!(candidate(-1), None);\n assert_eq!(candidate(0), Some(0));\n assert_eq!(candidate(2), Some(4));\n}\n", "is_solved": false, "reflections": ["The implementation of the triangle_area function is incorrect because it calculates the area using the formula for the area of a circle (r * r * PI) instead of the formula for the area of an inscribed triangle in a semicircle (0.5 * base * height). The base and height of the inscribed triangle are both equal to the diameter of the semicircle, which is 2 * r. The failed test case demonstrates that the function returns an incorrect area for the inscribed triangle.", "The implementation of the triangle_area function is incorrect because it calculates the area using the square of the diameter instead of using the correct formula for the area of an inscribed triangle in a semicircle, which is (1/2) * base * height. In this case, the base is the diameter and the height is the radius. The current implementation results in an incorrect area calculation, as shown in the failed test."], "solution": "/// Write a rsthon function to find the area of the largest triangle that can be inscribed in a semicircle with a given radius.\nfn triangle_area(r: isize) -> Option {\n if r <= 0 {\n return None;\n }\n\n let diameter = 2 * r;\n let area = 0.5 * (diameter * r) as f64;\n Some(area as isize)\n}"} +{"name": "mbpp_463_max_subarray_product", "language": "rs", "prompt": "/// Write a function to find the maximum product subvector of the given vector.\nfn max_subarray_product(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_463_max_subarray_product.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_subarray_product", "test": "\n\nfn main() {\n let candidate = max_subarray_product;\n assert_eq!(candidate(vec![1, -2, -3, 0, 7, -8, -2]), 112);\n assert_eq!(candidate(vec![6, -3, -10, 0, 2]), 180);\n assert_eq!(candidate(vec![-2, -40, 0, -2, -3]), 80);\n}\n", "solution": "/// Write a function to find the maximum product subvector of the given vector.\nfn max_subarray_product(arr: Vec) -> isize {\n use std::cmp::{max, min};\n\n if arr.is_empty() {\n return 0;\n }\n\n let mut max_product = arr[0];\n let mut min_product = arr[0];\n let mut result = arr[0];\n\n for i in 1..arr.len() {\n if arr[i] < 0 {\n let temp = max_product;\n max_product = min_product;\n min_product = temp;\n }\n\n max_product = max(arr[i], max_product * arr[i]);\n min_product = min(arr[i], min_product * arr[i]);\n\n result = max(result, max_product);\n }\n\n result\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it fails to import and use the `max` and `min` functions from the `std::cmp` module. These functions are necessary for comparing and updating the maximum and minimum product values during the iteration through the input vector. To fix this issue, the `max` and `min` functions should be imported from the `std::cmp` module and used correctly in the implementation."]} +{"name": "mbpp_223_is_majority", "language": "rs", "prompt": "/// Write a function that takes in a sorted vector, its length (n), and an element and returns whether the element is the majority element in the given sorted vector. (The majority element is the element that occurs more than n/2 times.)\nfn is_majority(arr: Vec, n: isize, x: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_223_is_majority.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_majority", "test": "\n\nfn main() {\n let candidate = is_majority;\n assert_eq!(candidate(vec![1, 2, 3, 3, 3, 3, 10], 7, 3), true);\n assert_eq!(candidate(vec![1, 1, 2, 4, 4, 4, 6, 6], 8, 4), false);\n assert_eq!(candidate(vec![1, 1, 1, 2, 2], 5, 1), true);\n assert_eq!(candidate(vec![1, 1, 2, 2], 5, 1), false);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a function that takes in a sorted vector, its length (n), and an element and returns whether the element is the majority element in the given sorted vector. (The majority element is the element that occurs more than n/2 times.)\nfn is_majority(arr: Vec, n: isize, x: isize) -> bool {\n let mut count = 0;\n\n for i in 0..n {\n if arr[i as usize] == x {\n count += 1;\n }\n }\n\n count > n / 2\n}"} +{"name": "mbpp_794_text_starta_endb", "language": "rs", "prompt": "/// Write a function that matches a string that has an 'a' followed by anything, ending in 'b'.\nfn text_starta_endb(text: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_794_text_starta_endb.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "text_starta_endb", "test": "\n\nfn main() {\n let candidate = text_starta_endb;\n assert_eq!(candidate(String::from(\"aabbbb\")), true);\n assert_eq!(candidate(String::from(\"aabAbbbc\")), false);\n assert_eq!(candidate(String::from(\"accddbbjjj\")), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function that matches a string that has an 'a' followed by anything, ending in 'b'.\nfn text_starta_endb(text: String) -> bool {\n if text.starts_with('a') && text.ends_with('b') {\n return true;\n }\n false\n}"} +{"name": "mbpp_79_word_len", "language": "rs", "prompt": "/// Write a rsthon function to check whether the length of the word is odd or not.\nfn word_len(s: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_79_word_len.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "word_len", "test": "\n\nfn main() {\n let candidate = word_len;\n assert_eq!(candidate(String::from(\"Hadoop\")), false);\n assert_eq!(candidate(String::from(\"great\")), true);\n assert_eq!(candidate(String::from(\"structure\")), true);\n}\n", "solution": "/// Write a rsthon function to check whether the length of the word is odd or not.\nfn word_len(s: String) -> bool {\n let length = s.chars().count();\n length % 2 != 0\n}", "is_solved": true, "reflections": ["The implementation of the word_len function is incorrect because it returns true when the length of the word is odd and false when it is even. However, the failed tests indicate that the expected output should be true for even lengths and false for odd lengths. The function's logic needs to be reversed to match the expected output.", "The implementation of the `word_len` function is incorrect because it returns true if the length of the word is even, and false if the length is odd. The function should return true if the length is odd and false if it is even, which is the opposite of the current behavior.", "The implementation of the `word_len` function is incorrect because it returns true when the length of the word is odd and false when the length is even. However, the failed tests indicate that the function should return true for even lengths and false for odd lengths. The logic for determining odd or even lengths needs to be reversed.", "The implementation of the `word_len` function is incorrect because it returns true if the length of the word is even, and false if the length is odd. The function should return true if the length is odd and false if the length is even, which is the opposite of the current behavior."]} +{"name": "mbpp_741_all_Characters_Same", "language": "rs", "prompt": "/// Write a rsthon function to check whether all the characters are same or not.\nfn all_Characters_Same(s: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_741_all_Characters_Same.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "all_Characters_Same", "test": "\n\nfn main() {\n let candidate = all_Characters_Same;\n assert_eq!(candidate(String::from(\"python\")), false);\n assert_eq!(candidate(String::from(\"aaa\")), true);\n assert_eq!(candidate(String::from(\"data\")), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to check whether all the characters are same or not.\nfn all_Characters_Same(s: String) -> bool {\n if s.is_empty() {\n return true;\n }\n\n let first_char = s.chars().next().unwrap();\n for c in s.chars() {\n if c != first_char {\n return false;\n }\n }\n\n true\n}"} +{"name": "mbpp_775_odd_position", "language": "rs", "prompt": "/// Write a rsthon function to check whether every odd index contains odd numbers of a given vector.\nfn odd_position(nums: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_775_odd_position.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "odd_position", "test": "\n\nfn main() {\n let candidate = odd_position;\n assert_eq!(candidate(vec![2, 1, 4, 3, 6, 7, 6, 3]), true);\n assert_eq!(candidate(vec![4, 1, 2]), true);\n assert_eq!(candidate(vec![1, 2, 3]), false);\n}\n", "solution": "/// Write a rsthon function to check whether every odd index contains odd numbers of a given vector.\nfn odd_position(nums: Vec) -> bool {\n for (index, num) in nums.iter().enumerate() {\n if index % 2 != 0 && num % 2 == 0 {\n return false;\n }\n }\n true\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it checks if the number at an odd index is even and returns false if it is. However, the function should return false if the number at an odd index is odd. The current implementation returns true for the failed test case because all odd indices have odd numbers, but the function should return false in this case.", "The implementation is incorrect because it returns false when it encounters an odd number at an odd index, whereas it should return false when an even number is found at an odd index. The condition in the if statement needs to be changed to check for even numbers at odd indices.", "The implementation is incorrect because it checks if the number at an odd index is even and returns false if it is. However, the function should return false if the number at an odd index is odd. The current implementation returns true for the failed test case because all odd indices have odd numbers, but the function should return false in this case.", "The implementation is incorrect because it returns false when it encounters an odd number at an odd index, whereas it should return false when an even number is found at an odd index. The function should continue checking all odd indices and only return true if all odd indices contain odd numbers."]} +{"name": "mbpp_644_reverse_Array_Upto_K", "language": "rs", "prompt": "/// Write a rsthon function to reverse a vector upto a given position.\nfn reverse_Array_Upto_K(input: Vec, k: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_644_reverse_Array_Upto_K.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "reverse_Array_Upto_K", "test": "\n\nfn main() {\n let candidate = reverse_Array_Upto_K;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6], 4), vec![4, 3, 2, 1, 5, 6]);\n assert_eq!(candidate(vec![4, 5, 6, 7], 2), vec![5, 4, 6, 7]);\n assert_eq!(candidate(vec![9, 8, 7, 6, 5], 3), vec![7, 8, 9, 6, 5]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to reverse a vector upto a given position.\nfn reverse_Array_Upto_K(input: Vec, k: isize) -> Vec {\n if k <= 0 {\n return input;\n }\n\n let k = k as usize;\n let mut result = input.clone();\n let mut start = 0;\n let mut end = k - 1;\n\n while start < end {\n result.swap(start, end);\n start += 1;\n end -= 1;\n }\n\n result\n}"} +{"name": "mbpp_588_big_diff", "language": "rs", "prompt": "/// Write a rsthon function to find the difference between largest and smallest value in a given vector.\nfn big_diff(nums: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_588_big_diff.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "big_diff", "test": "\n\nfn main() {\n let candidate = big_diff;\n assert_eq!(candidate(vec![1, 2, 3, 4]), 3);\n assert_eq!(candidate(vec![4, 5, 12]), 8);\n assert_eq!(candidate(vec![9, 2, 3]), 7);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the difference between largest and smallest value in a given vector.\nfn big_diff(nums: Vec) -> isize {\n if nums.is_empty() {\n return 0;\n }\n\n let mut min_num = nums[0];\n let mut max_num = nums[0];\n\n for num in nums {\n if num < min_num {\n min_num = num;\n } else if num > max_num {\n max_num = num;\n }\n }\n\n max_num - min_num\n}"} +{"name": "mbpp_445_index_multiplication", "language": "rs", "prompt": "/// Write a function to perform index wise multiplication of vector elements in the given two vectors.\nfn index_multiplication(test_tup1: Vec>, test_tup2: Vec>) -> Vec> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_445_index_multiplication.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "index_multiplication", "test": "\n\nfn main() {\n let candidate = index_multiplication;\n assert_eq!(candidate(vec![vec![1, 3], vec![4, 5], vec![2, 9], vec![1, 10]], vec![vec![6, 7], vec![3, 9], vec![1, 1], vec![7, 3]]), vec![vec![6, 21], vec![12, 45], vec![2, 9], vec![7, 30]]);\n assert_eq!(candidate(vec![vec![2, 4], vec![5, 6], vec![3, 10], vec![2, 11]], vec![vec![7, 8], vec![4, 10], vec![2, 2], vec![8, 4]]), vec![vec![14, 32], vec![20, 60], vec![6, 20], vec![16, 44]]);\n assert_eq!(candidate(vec![vec![3, 5], vec![6, 7], vec![4, 11], vec![3, 12]], vec![vec![8, 9], vec![5, 11], vec![3, 3], vec![9, 5]]), vec![vec![24, 45], vec![30, 77], vec![12, 33], vec![27, 60]]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to perform index wise multiplication of vector elements in the given two vectors.\nfn index_multiplication(test_tup1: Vec>, test_tup2: Vec>) -> Vec> {\n let mut result: Vec> = Vec::new();\n\n for i in 0..test_tup1.len() {\n let mut row: Vec = Vec::new();\n for j in 0..test_tup1[i].len() {\n row.push(test_tup1[i][j] * test_tup2[i][j]);\n }\n result.push(row);\n }\n\n result\n}"} +{"name": "mbpp_256_count_Primes_nums", "language": "rs", "prompt": "/// Write a rsthon function that takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\nfn count_Primes_nums(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_256_count_Primes_nums.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_Primes_nums", "test": "\n\nfn main() {\n let candidate = count_Primes_nums;\n assert_eq!(candidate(5), 2);\n assert_eq!(candidate(10), 4);\n assert_eq!(candidate(100), 25);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function that takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\nfn count_Primes_nums(n: isize) -> isize {\n if n <= 2 {\n return 0;\n }\n\n let mut primes = vec![true; n as usize];\n primes[0] = false;\n primes[1] = false;\n\n for i in 2..((n as f64).sqrt().ceil() as usize) {\n if primes[i] {\n let mut j = i * i;\n while j < n as usize {\n primes[j] = false;\n j += i;\n }\n }\n }\n\n primes.into_iter().filter(|&prime| prime).count() as isize\n}"} +{"name": "mbpp_170_sum_range_list", "language": "rs", "prompt": "/// Write a function to find the sum of numbers in a vector within a range specified by two indices.\nfn sum_range_list(list1: Vec, m: isize, n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_170_sum_range_list.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sum_range_list", "test": "\n\nfn main() {\n let candidate = sum_range_list;\n assert_eq!(candidate(vec![2, 1, 5, 6, 8, 3, 4, 9, 10, 11, 8, 12], 8, 10), 29);\n assert_eq!(candidate(vec![2, 1, 5, 6, 8, 3, 4, 9, 10, 11, 8, 12], 5, 7), 16);\n assert_eq!(candidate(vec![2, 1, 5, 6, 8, 3, 4, 9, 10, 11, 8, 12], 7, 10), 38);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the sum of numbers in a vector within a range specified by two indices.\nfn sum_range_list(list1: Vec, m: isize, n: isize) -> isize {\n let mut sum: isize = 0;\n\n for i in m as usize..=n as usize {\n if i < list1.len() {\n sum += list1[i];\n }\n }\n\n sum\n}"} +{"name": "mbpp_71_comb_sort", "language": "rs", "prompt": "/// Write a function to sort a vector of elements.\nfn comb_sort(nums: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_71_comb_sort.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "comb_sort", "test": "\n\nfn main() {\n let candidate = comb_sort;\n assert_eq!(candidate(vec![5, 15, 37, 25, 79]), vec![5, 15, 25, 37, 79]);\n assert_eq!(candidate(vec![41, 32, 15, 19, 22]), vec![15, 19, 22, 32, 41]);\n assert_eq!(candidate(vec![99, 15, 13, 47]), vec![13, 15, 47, 99]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to sort a vector of elements.\nfn comb_sort(nums: Vec) -> Vec {\n let mut nums = nums;\n let mut gap = nums.len();\n let shrink_factor = 1.3;\n let mut sorted = false;\n\n while !sorted {\n gap = (gap as f64 / shrink_factor).floor() as usize;\n if gap <= 1 {\n gap = 1;\n sorted = true;\n }\n\n let mut i = 0;\n while i + gap < nums.len() {\n if nums[i] > nums[i + gap] {\n nums.swap(i, i + gap);\n sorted = false;\n }\n i += 1;\n }\n }\n\n nums\n}"} +{"name": "mbpp_451_remove_whitespaces", "language": "rs", "prompt": "/// Write a function to remove all whitespaces from the given string.\nfn remove_whitespaces(text1: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_451_remove_whitespaces.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "remove_whitespaces", "test": "\n\nfn main() {\n let candidate = remove_whitespaces;\n assert_eq!(candidate(String::from(\" Google Flutter \")), String::from(\"GoogleFlutter\"));\n assert_eq!(candidate(String::from(\" Google Dart \")), String::from(\"GoogleDart\"));\n assert_eq!(candidate(String::from(\" iOS Swift \")), String::from(\"iOSSwift\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to remove all whitespaces from the given string.\nfn remove_whitespaces(text1: String) -> String {\n text1.chars().filter(|c| !c.is_whitespace()).collect()\n}"} +{"name": "mbpp_747_lcs_of_three", "language": "rs", "prompt": "/// Write a function to find the longest common subsequence for the given three string sequence. https://www.geeksforgeeks.org/lcs-longest-common-subsequence-three-strings/\nfn lcs_of_three(X: String, Y: String, Z: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_747_lcs_of_three.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "lcs_of_three", "test": "\n\nfn main() {\n let candidate = lcs_of_three;\n assert_eq!(candidate(String::from(\"AGGT12\"), String::from(\"12TXAYB\"), String::from(\"12XBA\")), 2);\n assert_eq!(candidate(String::from(\"Reels\"), String::from(\"Reelsfor\"), String::from(\"ReelsforReels\")), 5);\n assert_eq!(candidate(String::from(\"abcd1e2\"), String::from(\"bc12ea\"), String::from(\"bd1ea\")), 3);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the longest common subsequence for the given three string sequence. https://www.geeksforgeeks.org/lcs-longest-common-subsequence-three-strings/\nfn lcs_of_three(X: String, Y: String, Z: String) -> isize {\n let m = X.len();\n let n = Y.len();\n let o = Z.len();\n\n let mut dp = vec![vec![vec![0; o + 1]; n + 1]; m + 1];\n\n for i in 1..=m {\n for j in 1..=n {\n for k in 1..=o {\n if X.chars().nth(i - 1) == Y.chars().nth(j - 1) && Y.chars().nth(j - 1) == Z.chars().nth(k - 1) {\n dp[i][j][k] = 1 + dp[i - 1][j - 1][k - 1];\n } else {\n dp[i][j][k] = std::cmp::max(dp[i - 1][j][k], std::cmp::max(dp[i][j - 1][k], dp[i][j][k - 1]));\n }\n }\n }\n }\n\n dp[m][n][o]\n}"} +{"name": "mbpp_257_swap_numbers", "language": "rs", "prompt": "/// Write a function that takes in two numbers and returns a vector with the second number and then the first number.\nfn swap_numbers(a: isize, b: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_257_swap_numbers.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "swap_numbers", "test": "\n\nfn main() {\n let candidate = swap_numbers;\n assert_eq!(candidate(10, 20), vec![20, 10]);\n assert_eq!(candidate(15, 17), vec![17, 15]);\n assert_eq!(candidate(100, 200), vec![200, 100]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function that takes in two numbers and returns a vector with the second number and then the first number.\nfn swap_numbers(a: isize, b: isize) -> Vec {\n let mut swapped_numbers = Vec::new();\n swapped_numbers.push(b);\n swapped_numbers.push(a);\n swapped_numbers\n}"} +{"name": "mbpp_64_subject_marks", "language": "rs", "prompt": "/// Write a function to sort a vector of tuples using the second value of each tuple.\nfn subject_marks(subjectmarks: Vec<(String, isize)>) -> Vec<(String, isize)> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_64_subject_marks.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "subject_marks", "test": "\n\nfn main() {\n let candidate = subject_marks;\n assert_eq!(candidate(vec![(String::from(\"English\"), 88), (String::from(\"Science\"), 90), (String::from(\"Maths\"), 97), (String::from(\"Social sciences\"), 82)]), vec![(String::from(\"Social sciences\"), 82), (String::from(\"English\"), 88), (String::from(\"Science\"), 90), (String::from(\"Maths\"), 97)]);\n assert_eq!(candidate(vec![(String::from(\"Telugu\"), 49), (String::from(\"Hindhi\"), 54), (String::from(\"Social\"), 33)]), vec![(String::from(\"Social\"), 33), (String::from(\"Telugu\"), 49), (String::from(\"Hindhi\"), 54)]);\n assert_eq!(candidate(vec![(String::from(\"Physics\"), 96), (String::from(\"Chemistry\"), 97), (String::from(\"Biology\"), 45)]), vec![(String::from(\"Biology\"), 45), (String::from(\"Physics\"), 96), (String::from(\"Chemistry\"), 97)]);\n}\n", "solution": "/// Write a function to sort a vector of tuples using the second value of each tuple.\nfn subject_marks(subjectmarks: Vec<(String, isize)>) -> Vec<(String, isize)> {\n let mut subjectmarks = subjectmarks;\n subjectmarks.sort_by(|a, b| a.1.cmp(&b.1));\n subjectmarks\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it tries to use the non-existent method `sorted_by` on `std::vec::IntoIter`. The correct method to use for sorting a vector is `sort_by`."]} +{"name": "mbpp_116_tuple_to_int", "language": "rs", "prompt": "/// Write a function to convert a given tuple of positive integers into a single integer.\nfn tuple_to_int(nums: (isize, isize, isize)) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_116_tuple_to_int.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "tuple_to_int", "test": "\n\nfn main() {\n let candidate = tuple_to_int;\n assert_eq!(candidate((1, 2, 3)), 123);\n assert_eq!(candidate((4, 5, 6)), 456);\n assert_eq!(candidate((5, 6, 7)), 567);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to convert a given tuple of positive integers into a single integer.\nfn tuple_to_int(nums: (isize, isize, isize)) -> isize {\n let (a, b, c) = nums;\n let result = a * 100 + b * 10 + c;\n result\n}"} +{"name": "mbpp_479_first_Digit", "language": "rs", "prompt": "/// Write a rsthon function to find the first digit of a given number.\nfn first_Digit(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_479_first_Digit.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "first_Digit", "test": "\n\nfn main() {\n let candidate = first_Digit;\n assert_eq!(candidate(123), 1);\n assert_eq!(candidate(456), 4);\n assert_eq!(candidate(12), 1);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the first digit of a given number.\nfn first_Digit(n: isize) -> isize {\n let mut num = n.abs();\n while num >= 10 {\n num /= 10;\n }\n num\n}"} +{"name": "mbpp_118_string_to_list", "language": "rs", "prompt": "/// Write a function to convert a string to a vector of strings split on the space character.\nfn string_to_list(string: String) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_118_string_to_list.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "string_to_list", "test": "\n\nfn main() {\n let candidate = string_to_list;\n assert_eq!(candidate(String::from(\"python programming\")), vec![String::from(\"python\"), String::from(\"programming\")]);\n assert_eq!(candidate(String::from(\"lists tuples strings\")), vec![String::from(\"lists\"), String::from(\"tuples\"), String::from(\"strings\")]);\n assert_eq!(candidate(String::from(\"write a program\")), vec![String::from(\"write\"), String::from(\"a\"), String::from(\"program\")]);\n}\n", "solution": "/// Write a function to convert a string to a vector of strings split on the space character.\nfn string_to_list(string: String) -> Vec {\n if string.is_empty() {\n return vec![String::new()];\n }\n\n string.split_whitespace()\n .map(|s| s.to_string())\n .collect()\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it contains an unclosed delimiter. The function `string_to_list` is defined inside the `main` function, causing a mismatch in the indentation and delimiters. This results in a compilation error.", "The implementation of the string_to_list function is incorrect because it does not handle the case when the input string is empty. In this case, the function returns an empty vector instead of a vector containing an empty string."]} +{"name": "mbpp_763_find_min_diff", "language": "rs", "prompt": "/// Write a rsthon function to find the minimum difference between any two elements in a given vector. https://www.geeksforgeeks.org/find-minimum-difference-pair/\nfn find_min_diff(arr: Vec, n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_763_find_min_diff.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_min_diff", "test": "\n\nfn main() {\n let candidate = find_min_diff;\n assert_eq!(candidate(vec![1, 5, 3, 19, 18, 25], 6), 1);\n assert_eq!(candidate(vec![4, 3, 2, 6], 4), 1);\n assert_eq!(candidate(vec![30, 5, 20, 9], 4), 4);\n}\n", "solution": "/// Write a rsthon function to find the minimum difference between any two elements in a given vector. https://www.geeksforgeeks.org/find-minimum-difference-pair/\nfn find_min_diff(arr: Vec, n: isize) -> isize {\n if n == 0 {\n return 0;\n }\n\n let mut arr_sorted = arr.clone();\n arr_sorted.sort();\n\n let mut min_diff = isize::MAX;\n\n for i in 0..(n as usize - 1) {\n let diff = (arr_sorted[i + 1] - arr_sorted[i]).abs();\n if diff < min_diff {\n min_diff = diff;\n }\n }\n\n min_diff\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it calculates the difference between adjacent elements in the sorted array, which may not always result in the minimum difference between any two elements in the original array. The failed test case demonstrates this issue, where the minimum difference should be 9, but the function returns 10.", "The implementation is incorrect because it calculates the minimum difference between all pairs of elements in the sorted array, instead of just comparing adjacent elements. In a sorted array, the minimum difference will always be between adjacent elements, so the inner loop is unnecessary and leads to incorrect results in some cases.", "The implementation is incorrect because it calculates the absolute difference between adjacent elements in the sorted array, which may not always result in the minimum difference between any two elements. In the failed test case, the minimum difference is between 21 and 10, but the implementation calculates the difference between 10 and 0, resulting in an incorrect output.", "The implementation is incorrect because it calculates the difference between all pairs of elements in the sorted array, which is unnecessary and inefficient. Instead, it should only compare adjacent elements in the sorted array, as the minimum difference will always be between adjacent elements. The failed test case highlights this issue, as the implementation returns a larger difference than the actual minimum difference."]} +{"name": "mbpp_408_k_smallest_pairs", "language": "rs", "prompt": "/// Write a function to find k number of smallest pairs which consist of one element from the first vector and one element from the second vector.\nfn k_smallest_pairs(nums1: Vec, nums2: Vec, k: isize) -> Vec> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_408_k_smallest_pairs.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "k_smallest_pairs", "test": "\n\nfn main() {\n let candidate = k_smallest_pairs;\n assert_eq!(candidate(vec![1, 3, 7], vec![2, 4, 6], 2), vec![vec![1, 2], vec![1, 4]]);\n assert_eq!(candidate(vec![1, 3, 7], vec![2, 4, 6], 1), vec![vec![1, 2]]);\n assert_eq!(candidate(vec![1, 3, 7], vec![2, 4, 6], 7), vec![vec![1, 2], vec![1, 4], vec![3, 2], vec![1, 6], vec![3, 4], vec![3, 6], vec![7, 2]]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find k number of smallest pairs which consist of one element from the first vector and one element from the second vector.\nfn k_smallest_pairs(nums1: Vec, nums2: Vec, k: isize) -> Vec> {\n let mut pairs: Vec> = Vec::new();\n\n for i in 0..nums1.len() {\n for j in 0..nums2.len() {\n pairs.push(vec![nums1[i], nums2[j]]);\n }\n }\n\n pairs.sort_by_key(|pair| pair[0] + pair[1]);\n\n if k as usize > pairs.len() {\n return pairs;\n }\n\n pairs.into_iter().take(k as usize).collect()\n}"} +{"name": "mbpp_748_capital_words_spaces", "language": "rs", "prompt": "/// Write a function to put spaces between words starting with capital letters in a given string.\nfn capital_words_spaces(str1: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_748_capital_words_spaces.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "capital_words_spaces", "test": "\n\nfn main() {\n let candidate = capital_words_spaces;\n assert_eq!(candidate(String::from(\"Python\")), String::from(\"Python\"));\n assert_eq!(candidate(String::from(\"PythonProgrammingExamples\")), String::from(\"Python Programming Examples\"));\n assert_eq!(candidate(String::from(\"GetReadyToBeCodingFreak\")), String::from(\"Get Ready To Be Coding Freak\"));\n}\n", "solution": "/// Write a function to put spaces between words starting with capital letters in a given string.\nfn capital_words_spaces(str1: String) -> String {\n let mut result = String::new();\n let chars = str1.chars().collect::>();\n\n for (i, c) in chars.iter().enumerate() {\n if i > 0 && c.is_uppercase() {\n if !chars[i - 1].is_uppercase() || (i < chars.len() - 1 && !chars[i + 1].is_uppercase()) {\n result.push(' ');\n }\n }\n result.push(*c);\n }\n\n result\n}", "is_solved": true, "reflections": ["The current implementation of the `capital_words_spaces` function is incorrect because it adds a space before every uppercase letter, without considering consecutive uppercase letters as a single word (e.g., \"GPT\"). This leads to incorrect spacing in the output, as seen in the failed test case.", "The current implementation fails to handle cases where there are consecutive uppercase letters in the input string. It only adds a space when the current character is uppercase and the previous character is not uppercase. This causes the function to incorrectly group consecutive uppercase letters together, as seen in the failed test cases \"This Is ATest\" and \"Rust GPTIs Great\"."]} +{"name": "mbpp_252_convert", "language": "rs", "prompt": "/// Write a rsthon function to convert complex numbers to polar coordinates.\nfn convert(numbers: isize) -> (f64, f64) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_252_convert.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "convert", "test": "\n\nfn main() {\n let candidate = convert;\n assert_eq!(candidate(1), (1.0, 0.0));\n assert_eq!(candidate(4), (4.0, 0.0));\n assert_eq!(candidate(5), (5.0, 0.0));\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a rsthon function to convert complex numbers to polar coordinates.\nfn convert(numbers: isize) -> (f64, f64) {\n let real = numbers as f64;\n let imaginary = numbers as f64;\n\n let radius = (real.powi(2) + imaginary.powi(2)).sqrt();\n let angle = imaginary.atan2(real);\n\n (radius, angle)\n}"} +{"name": "mbpp_436_neg_nos", "language": "rs", "prompt": "/// Write a rsthon function to return the negative numbers in a vector.\nfn neg_nos(list1: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_436_neg_nos.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "neg_nos", "test": "\n\nfn main() {\n let candidate = neg_nos;\n assert_eq!(candidate(vec![-1, 4, 5, -6]), vec![-1, -6]);\n assert_eq!(candidate(vec![-1, -2, 3, 4]), vec![-1, -2]);\n assert_eq!(candidate(vec![-7, -6, 8, 9]), vec![-7, -6]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to return the negative numbers in a vector.\nfn neg_nos(list1: Vec) -> Vec {\n let mut neg_numbers = Vec::new();\n\n for num in list1 {\n if num < 0 {\n neg_numbers.push(num);\n }\n }\n\n neg_numbers\n}"} +{"name": "mbpp_397_median_numbers", "language": "rs", "prompt": "/// Write a function to find the median of three numbers.\nfn median_numbers(a: isize, b: isize, c: isize) -> f64 {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_397_median_numbers.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "median_numbers", "test": "\n\nfn main() {\n let candidate = median_numbers;\n assert_eq!(candidate(25, 55, 65), 55.0);\n assert_eq!(candidate(20, 10, 30), 20.0);\n assert_eq!(candidate(15, 45, 75), 45.0);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the median of three numbers.\nfn median_numbers(a: isize, b: isize, c: isize) -> f64 {\n let mut nums = [a, b, c];\n nums.sort();\n nums[1] as f64\n}"} +{"name": "mbpp_745_divisible_by_digits", "language": "rs", "prompt": "/// Write a function to find numbers within a given range from startnum ti endnum where every number is divisible by every digit it contains. https://www.w3resource.com/rsthon-exercises/lambda/rsthon-lambda-exercise-24.php\nfn divisible_by_digits(startnum: isize, endnum: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_745_divisible_by_digits.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "divisible_by_digits", "test": "\n\nfn main() {\n let candidate = divisible_by_digits;\n assert_eq!(candidate(1, 22), vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 15, 22]);\n assert_eq!(candidate(1, 15), vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 15]);\n assert_eq!(candidate(20, 25), vec![22, 24]);\n}\n", "solution": "/// Write a function to find numbers within a given range from startnum ti endnum where every number is divisible by every digit it contains. https://www.w3resource.com/rsthon-exercises/lambda/rsthon-lambda-exercise-24.php\nfn divisible_by_digits(startnum: isize, endnum: isize) -> Vec {\n let mut result = Vec::new();\n\n for num in startnum..=endnum {\n let num_str = num.to_string();\n let digits = num_str.chars().filter_map(|c| c.to_digit(10)).map(|d| d as isize);\n\n let divisible = digits.clone().all(|d| d != 0 && num % d == 0);\n\n if divisible {\n result.push(num);\n }\n }\n\n result\n}", "is_solved": true, "reflections": ["The implementation is wrong because it creates a temporary value when converting the number to a string, which gets dropped before it can be used in the loop. This causes a borrow checker error. To fix this issue, a `let` binding should be used to create a longer-lived value for the string representation of the number.", "The implementation of the divisible_by_digits function is incorrect because it is not properly handling numbers with a digit '0'. When a number contains a '0', the function immediately sets divisible to false and breaks the loop, causing the number to be excluded from the result even if it should be included. This leads to incorrect results in the failed test cases.", "The implementation is incorrect because it filters out numbers with a digit '0' by using the `continue` statement. This causes the function to skip numbers that should be included in the result, such as 101, 102, 105, 108, and others. Additionally, it incorrectly includes numbers like 11 in the result, which should be excluded as they are not divisible by their digits.", "The implementation is incorrect because it considers numbers with a digit '0' as valid results, which should be excluded. This is due to the condition `d == 0 || num % d == 0` in the `all()` function, which allows numbers with '0' to pass the divisibility check."]} +{"name": "mbpp_554_Split", "language": "rs", "prompt": "/// Write a rsthon function which takes a vector of integers and only returns the odd ones.\nfn Split(list: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_554_Split.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "Split", "test": "\n\nfn main() {\n let candidate = Split;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6]), vec![1, 3, 5]);\n assert_eq!(candidate(vec![10, 11, 12, 13]), vec![11, 13]);\n assert_eq!(candidate(vec![7, 8, 9, 1]), vec![7, 9, 1]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function which takes a vector of integers and only returns the odd ones.\nfn Split(list: Vec) -> Vec {\n let mut odd_numbers = Vec::new();\n\n for number in list {\n if number % 2 != 0 {\n odd_numbers.push(number);\n }\n }\n\n odd_numbers\n}"} +{"name": "mbpp_128_long_words", "language": "rs", "prompt": "/// Write a function to find words that are longer than n characters from a given vector of words.\nfn long_words(n: isize, str: String) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_128_long_words.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "long_words", "test": "\n\nfn main() {\n let candidate = long_words;\n assert_eq!(candidate(3, String::from(\"python is a programming language\")), vec![String::from(\"python\"), String::from(\"programming\"), String::from(\"language\")]);\n assert_eq!(candidate(2, String::from(\"writing a program\")), vec![String::from(\"writing\"), String::from(\"program\")]);\n assert_eq!(candidate(5, String::from(\"sorting list\")), vec![String::from(\"sorting\")]);\n}\n", "solution": "/// Write a function to find words that are longer than n characters from a given vector of words.\nfn long_words(n: isize, str: String) -> Vec {\n let words: Vec = str.split_whitespace().map(|s| s.to_string()).collect();\n let mut long_words: Vec = Vec::new();\n\n for word in words {\n if word.len() > n as usize {\n long_words.push(word);\n }\n }\n\n long_words\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it returns words with a length greater than the given `n` instead of exactly `n` characters long. This causes the failed test to include \"this\" and \"test\" in the output, as their lengths are greater than 3.", "The implementation is incorrect because it only adds words to the `long_words` vector if their length is exactly equal to `n`. However, the goal is to find words that are longer than `n` characters. The condition in the if statement should be changed to check if the word length is greater than `n`.", "The implementation is incorrect because it returns words that are longer than n characters, but the test case expects words that are exactly n characters long. The condition in the if statement should be changed to check for words with length equal to n instead of greater than n.", "The implementation is incorrect because it only adds words to the `long_words` vector if their length is exactly equal to `n`. However, the goal is to find words that are longer than `n` characters. The condition in the if statement should be changed to check if the word length is greater than `n`."]} +{"name": "mbpp_69_is_sublist", "language": "rs", "prompt": "/// Write a function to check whether a vector contains the given subvector or not.\nfn is_sublist(l: Vec, s: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_69_is_sublist.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_sublist", "test": "\n\nfn main() {\n let candidate = is_sublist;\n assert_eq!(candidate(vec![2, 4, 3, 5, 7], vec![3, 7]), false);\n assert_eq!(candidate(vec![2, 4, 3, 5, 7], vec![4, 3]), true);\n assert_eq!(candidate(vec![2, 4, 3, 5, 7], vec![1, 6]), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check whether a vector contains the given subvector or not.\nfn is_sublist(l: Vec, s: Vec) -> bool {\n if s.is_empty() {\n return true;\n }\n\n if l.len() < s.len() {\n return false;\n }\n\n for i in 0..=(l.len() - s.len()) {\n if l[i..i + s.len()] == s[..] {\n return true;\n }\n }\n\n false\n}"} +{"name": "mbpp_732_replace_specialchar", "language": "rs", "prompt": "/// Write a function to replace all occurrences of spaces, commas, or dots with a colon.\nfn replace_specialchar(text: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_732_replace_specialchar.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "replace_specialchar", "test": "\n\nfn main() {\n let candidate = replace_specialchar;\n assert_eq!(candidate(String::from(\"Python language, Programming language.\")), String::from(\"Python:language::Programming:language:\"));\n assert_eq!(candidate(String::from(\"a b c,d e f\")), String::from(\"a:b:c:d:e:f\"));\n assert_eq!(candidate(String::from(\"ram reshma,ram rahim\")), String::from(\"ram:reshma:ram:rahim\"));\n}\n", "solution": "/// Write a function to replace all occurrences of spaces, commas, or dots with a colon.\nfn replace_specialchar(text: String) -> String {\n text.chars()\n .map(|c| if c == ' ' || c == ',' || c == '.' { ':' } else { c })\n .collect()\n}", "is_solved": true, "reflections": ["The implementation is wrong because it uses the `replace` method with a closure, which is not the correct way to use this method. The `replace` method expects a pattern and a replacement string as arguments, not a closure. This syntax error causes an unclosed delimiter issue in the code.", "The implementation is incorrect because it is defined inside the main function, causing an unclosed delimiter error. The function should be defined outside the main function to fix the issue."]} +{"name": "mbpp_141_pancake_sort", "language": "rs", "prompt": "/// Write a function to sort a vector of elements.\nfn pancake_sort(nums: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_141_pancake_sort.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "pancake_sort", "test": "\n\nfn main() {\n let candidate = pancake_sort;\n assert_eq!(candidate(vec![15, 79, 25, 38, 69]), vec![15, 25, 38, 69, 79]);\n assert_eq!(candidate(vec![98, 12, 54, 36, 85]), vec![12, 36, 54, 85, 98]);\n assert_eq!(candidate(vec![41, 42, 32, 12, 23]), vec![12, 23, 32, 41, 42]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to sort a vector of elements.\nfn pancake_sort(nums: Vec) -> Vec {\n let mut nums = nums;\n let mut n = nums.len();\n\n while n > 1 {\n let mut max_idx = 0;\n\n for i in 1..n {\n if nums[i] > nums[max_idx] {\n max_idx = i;\n }\n }\n\n if max_idx != n - 1 {\n nums[0..=max_idx].reverse();\n nums[0..n].reverse();\n }\n\n n -= 1;\n }\n\n nums\n}"} +{"name": "mbpp_308_large_product", "language": "rs", "prompt": "/// Write a function to find the specified number of largest products from two given vectors, selecting one factor from each vector.\nfn large_product(nums1: Vec, nums2: Vec, N: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_308_large_product.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "large_product", "test": "\n\nfn main() {\n let candidate = large_product;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6], vec![3, 6, 8, 9, 10, 6], 3), vec![60, 54, 50]);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6], vec![3, 6, 8, 9, 10, 6], 4), vec![60, 54, 50, 48]);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6], vec![3, 6, 8, 9, 10, 6], 5), vec![60, 54, 50, 48, 45]);\n}\n", "solution": "/// Write a function to find the specified number of largest products from two given vectors, selecting one factor from each vector.\nfn large_product(nums1: Vec, nums2: Vec, N: isize) -> Vec {\nlet mut products = Vec::new();\n\n for num1 in &nums1 {\n for num2 in &nums2 {\n let product = num1 * num2;\n products.push(product);\n }\n }\n\n products.sort_unstable_by(|a, b| b.cmp(a));\n\n products.truncate(N as usize);\n\n products\n}", "is_solved": true, "reflections": ["The implementation is wrong because it does not handle duplicate products correctly. When calculating the products, it pushes all possible combinations into the vector, including duplicates. This leads to an incorrect result when truncating the vector to the specified number of largest products, as it may include duplicate values instead of the unique largest products.", "The implementation is incorrect because it uses a HashSet to store and check for unique products, which causes it to skip some valid products when there are duplicates. This leads to incorrect results when the specified number of largest products (N) is greater than the number of unique products found.", "The implementation is wrong because it does not handle duplicate products correctly. When there are duplicate products, the function pushes them into the result vector multiple times, causing the output to have incorrect values.", "The implementation is incorrect because it uses a HashSet to store and filter out duplicate products, which causes some valid products to be skipped. This results in an incorrect output when the specified number of largest products (N) is greater than the unique products found."]} +{"name": "mbpp_293_otherside_rightangle", "language": "rs", "prompt": "/// Write a function to find the third side of a right angled triangle.\nfn otherside_rightangle(w: isize, h: isize) -> f64 {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_293_otherside_rightangle.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "otherside_rightangle", "test": "\n\nfn main() {\n let candidate = otherside_rightangle;\n assert_eq!(candidate(7, 8), 10.63014581273465);\n assert_eq!(candidate(3, 4), 5.0);\n assert_eq!(candidate(7, 15), 16.55294535724685);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the third side of a right angled triangle.\nfn otherside_rightangle(w: isize, h: isize) -> f64 {\n let w_squared = (w * w) as f64;\n let h_squared = (h * h) as f64;\n let other_side = (w_squared + h_squared).sqrt();\n other_side\n}"} +{"name": "mbpp_106_add_lists", "language": "rs", "prompt": "/// Write a function to append the given vector to the given tuples.\nfn add_lists(test_list: Vec, test_tup: (isize, isize)) -> (isize, isize, isize, isize, isize) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_106_add_lists.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "add_lists", "test": "\n\nfn main() {\n let candidate = add_lists;\n assert_eq!(candidate(vec![5, 6, 7], (9, 10)), (9, 10, 5, 6, 7));\n assert_eq!(candidate(vec![6, 7, 8], (10, 11)), (10, 11, 6, 7, 8));\n assert_eq!(candidate(vec![7, 8, 9], (11, 12)), (11, 12, 7, 8, 9));\n}\n", "solution": "/// Write a function to append the given vector to the given tuples.\nfn add_lists(test_list: Vec, test_tup: (isize, isize)) -> (isize, isize, isize, isize, isize) {\n let (t1, t2) = test_tup;\n let mut result = (t1, t2, 0, 0, 0);\n\n for (i, item) in test_list.iter().enumerate() {\n if i == 0 {\n result.2 = *item;\n } else if i == 1 {\n result.3 = *item;\n } else if i == 2 {\n result.4 = *item;\n } else {\n break;\n }\n }\n\n result\n}", "is_solved": true, "reflections": ["The implementation is wrong because it only assigns the last element of the input vector to the third position of the result tuple, and leaves the fourth and fifth positions as 0. The if-else conditions inside the loop should be updated to correctly assign the elements of the input vector to the corresponding positions in the result tuple."]} +{"name": "mbpp_720_add_dict_to_tuple", "language": "rs", "prompt": "use std::collections::HashMap;\n\n/// Write a function to add a HashMap to the tuple. The output should be a tuple.\nfn add_dict_to_tuple(test_tup: (isize, isize, isize), test_dict: HashMap) -> (isize, isize, isize, HashMap) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_720_add_dict_to_tuple.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "add_dict_to_tuple", "test": "\n\nfn main() {\n let candidate = add_dict_to_tuple;\n assert_eq!(candidate((4, 5, 6), HashMap::from([(String::from(\"MSAM\"), 1), (String::from(\"is\"), 2), (String::from(\"best\"), 3)])), (4, 5, 6, HashMap::from([(String::from(\"MSAM\"), 1), (String::from(\"is\"), 2), (String::from(\"best\"), 3)])));\n assert_eq!(candidate((1, 2, 3), HashMap::from([(String::from(\"UTS\"), 2), (String::from(\"is\"), 3), (String::from(\"Worst\"), 4)])), (1, 2, 3, HashMap::from([(String::from(\"UTS\"), 2), (String::from(\"is\"), 3), (String::from(\"Worst\"), 4)])));\n assert_eq!(candidate((8, 9, 10), HashMap::from([(String::from(\"POS\"), 3), (String::from(\"is\"), 4), (String::from(\"Okay\"), 5)])), (8, 9, 10, HashMap::from([(String::from(\"POS\"), 3), (String::from(\"is\"), 4), (String::from(\"Okay\"), 5)])));\n}\n", "is_solved": true, "reflections": [], "solution": "use std::collections::HashMap;\n\n/// Write a function to add a HashMap to the tuple. The output should be a tuple.\nfn add_dict_to_tuple(test_tup: (isize, isize, isize), test_dict: HashMap) -> (isize, isize, isize, HashMap) {\n let (a, b, c) = test_tup;\n let result = (a, b, c, test_dict);\n result\n}"} +{"name": "mbpp_395_first_non_repeating_character", "language": "rs", "prompt": "/// Write a rsthon function to find the first non-repeated character in a given string.\nfn first_non_repeating_character(str1: String) -> Option {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_395_first_non_repeating_character.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "first_non_repeating_character", "test": "\n\nfn main() {\n let candidate = first_non_repeating_character;\n assert_eq!(candidate(String::from(\"abcabc\")), None);\n assert_eq!(candidate(String::from(\"abc\")), Some(String::from(\"a\")));\n assert_eq!(candidate(String::from(\"ababc\")), Some(String::from(\"c\")));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the first non-repeated character in a given string.\nfn first_non_repeating_character(str1: String) -> Option {\n let mut char_count = std::collections::HashMap::new();\n\n for c in str1.chars() {\n let count = char_count.entry(c).or_insert(0);\n *count += 1;\n }\n\n for c in str1.chars() {\n if let Some(count) = char_count.get(&c) {\n if *count == 1 {\n return Some(c.to_string());\n }\n }\n }\n\n None\n}"} +{"name": "mbpp_9_find_Rotations", "language": "rs", "prompt": "/// Write a rsthon function to find the minimum number of rotations (greater than 0) required to get the same string.\nfn find_Rotations(str: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_9_find_Rotations.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_Rotations", "test": "\n\nfn main() {\n let candidate = find_Rotations;\n assert_eq!(candidate(String::from(\"aaaa\")), 1);\n assert_eq!(candidate(String::from(\"ab\")), 2);\n assert_eq!(candidate(String::from(\"abc\")), 3);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the minimum number of rotations (greater than 0) required to get the same string.\nfn find_Rotations(str: String) -> isize {\n let len = str.len();\n let mut rotations = 1;\n let mut rotated_str = str.clone();\n\n while rotations <= len {\n rotated_str = format!(\"{}{}\", rotated_str.chars().nth(len - 1).unwrap(), &rotated_str[..len - 1]);\n if rotated_str == str {\n return rotations as isize;\n }\n rotations += 1;\n }\n\n -1\n}"} +{"name": "mbpp_792_count_list", "language": "rs", "prompt": "/// Write a rsthon function to count the number of vectors in a given number of vectors.\nfn count_list(input_list: Vec>) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_792_count_list.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_list", "test": "\n\nfn main() {\n let candidate = count_list;\n assert_eq!(candidate(vec![vec![1, 3], vec![5, 7], vec![9, 11], vec![13, 15, 17]]), 4);\n assert_eq!(candidate(vec![vec![1, 2], vec![2, 3], vec![4, 5]]), 3);\n assert_eq!(candidate(vec![vec![1, 0], vec![2, 0]]), 2);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to count the number of vectors in a given number of vectors.\nfn count_list(input_list: Vec>) -> isize {\n let count = input_list.len() as isize;\n count\n}"} +{"name": "mbpp_477_is_lower", "language": "rs", "prompt": "/// Write a rsthon function to convert the given string to lower case.\nfn is_lower(string: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_477_is_lower.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_lower", "test": "\n\nfn main() {\n let candidate = is_lower;\n assert_eq!(candidate(String::from(\"InValid\")), String::from(\"invalid\"));\n assert_eq!(candidate(String::from(\"TruE\")), String::from(\"true\"));\n assert_eq!(candidate(String::from(\"SenTenCE\")), String::from(\"sentence\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to convert the given string to lower case.\nfn is_lower(string: String) -> String {\n string.to_lowercase()\n}"} +{"name": "mbpp_422_find_Average_Of_Cube", "language": "rs", "prompt": "/// Write a rsthon function to find the average of cubes of first n natural numbers.\nfn find_Average_Of_Cube(n: isize) -> f64 {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_422_find_Average_Of_Cube.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_Average_Of_Cube", "test": "\n\nfn main() {\n let candidate = find_Average_Of_Cube;\n assert_eq!(candidate(2), 4.5);\n assert_eq!(candidate(3), 12.0);\n assert_eq!(candidate(1), 1.0);\n}\n", "is_solved": false, "reflections": ["The implementation of the find_Average_Of_Cube function is incorrect because it calculates the average of the sum of cubes of first n natural numbers, rather than the average of the cubes themselves. This leads to incorrect results for the failed test cases.", "The implementation is incorrect because it calculates the average using the sum of the first n natural numbers (n * (n + 1) / 2) instead of the total number of elements (n). This leads to incorrect average values for the cubes of the first n natural numbers.", "The implementation of the find_Average_Of_Cube function is incorrect because it calculates the sum of cubes of first n natural numbers and then divides it by n to find the average. However, the correct formula to find the average of cubes of first n natural numbers is (n * (n + 1) / 2)^2. The current implementation does not use this formula, leading to incorrect results for some test cases.", "The implementation of the find_Average_Of_Cube function is incorrect because it calculates the average of the squares of the first n natural numbers instead of the cubes. The formula used in the function is for the square of the sum of the first n natural numbers, not the sum of the cubes. This leads to incorrect results for the failed test cases."], "solution": "/// Write a rsthon function to find the average of cubes of first n natural numbers.\nfn find_Average_Of_Cube(n: isize) -> f64 {\n let sum_of_cubes = (n * (n + 1) * (2 * n + 1)) / 6;\n let average = sum_of_cubes as f64 / n as f64;\n average\n}"} +{"name": "mbpp_637_noprofit_noloss", "language": "rs", "prompt": "/// Write a function to check whether the given amount has no profit and no loss\nfn noprofit_noloss(actual_cost: isize, sale_amount: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_637_noprofit_noloss.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "noprofit_noloss", "test": "\n\nfn main() {\n let candidate = noprofit_noloss;\n assert_eq!(candidate(1500, 1200), false);\n assert_eq!(candidate(100, 100), true);\n assert_eq!(candidate(2000, 5000), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check whether the given amount has no profit and no loss\nfn noprofit_noloss(actual_cost: isize, sale_amount: isize) -> bool {\n actual_cost == sale_amount\n}"} +{"name": "mbpp_557_toggle_string", "language": "rs", "prompt": "/// Write a function to toggle the case of all characters in a string.\nfn toggle_string(string: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_557_toggle_string.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "toggle_string", "test": "\n\nfn main() {\n let candidate = toggle_string;\n assert_eq!(candidate(String::from(\"Python\")), String::from(\"pYTHON\"));\n assert_eq!(candidate(String::from(\"Pangram\")), String::from(\"pANGRAM\"));\n assert_eq!(candidate(String::from(\"LIttLE\")), String::from(\"liTTle\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to toggle the case of all characters in a string.\nfn toggle_string(string: String) -> String {\n string.chars()\n .map(|c| {\n if c.is_lowercase() {\n c.to_uppercase().collect::()\n } else {\n c.to_lowercase().collect::()\n }\n })\n .collect()\n}"} +{"name": "mbpp_786_right_insertion", "language": "rs", "prompt": "/// Write a function to locate the right insertion point for a specified value in sorted order.\nfn right_insertion(a: Vec, x: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_786_right_insertion.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "right_insertion", "test": "\n\nfn main() {\n let candidate = right_insertion;\n assert_eq!(candidate(vec![1, 2, 4, 5], 6), 4);\n assert_eq!(candidate(vec![1, 2, 4, 5], 3), 2);\n assert_eq!(candidate(vec![1, 2, 4, 5], 7), 4);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to locate the right insertion point for a specified value in sorted order.\nfn right_insertion(a: Vec, x: isize) -> isize {\n let mut left = 0;\n let mut right = a.len();\n\n while left < right {\n let mid = left + (right - left) / 2;\n if x < a[mid] {\n right = mid;\n } else {\n left = mid + 1;\n }\n }\n\n left as isize\n}"} +{"name": "mbpp_807_first_odd", "language": "rs", "prompt": "/// Write a rsthon function to find the first odd number in a given vector of numbers.\nfn first_odd(nums: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_807_first_odd.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "first_odd", "test": "\n\nfn main() {\n let candidate = first_odd;\n assert_eq!(candidate(vec![1, 3, 5]), 1);\n assert_eq!(candidate(vec![2, 4, 1, 3]), 1);\n assert_eq!(candidate(vec![8, 9, 1]), 9);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the first odd number in a given vector of numbers.\nfn first_odd(nums: Vec) -> isize {\n for num in nums {\n if num % 2 != 0 {\n return num;\n }\n }\n -1\n}"} +{"name": "mbpp_631_replace_spaces", "language": "rs", "prompt": "/// Write a function to replace whitespaces with an underscore and vice versa in a given string.\nfn replace_spaces(text: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_631_replace_spaces.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "replace_spaces", "test": "\n\nfn main() {\n let candidate = replace_spaces;\n assert_eq!(candidate(String::from(\"Jumanji The Jungle\")), String::from(\"Jumanji_The_Jungle\"));\n assert_eq!(candidate(String::from(\"The_Avengers\")), String::from(\"The Avengers\"));\n assert_eq!(candidate(String::from(\"Fast and Furious\")), String::from(\"Fast_and_Furious\"));\n}\n", "solution": "/// Write a function to replace whitespaces with an underscore and vice versa in a given string.\nfn replace_spaces(text: String) -> String {\ntext.chars()\n .map(|c| match c {\n ' ' => '_',\n '_' => ' ',\n _ => c,\n })\n .collect::()\n .replace(\"_ \", \" \")\n .replace(\" _\", \" \")}", "is_solved": true, "reflections": ["The implementation is incorrect because it only replaces the first occurrence of a space or underscore. When there are multiple spaces or underscores in the input string, the function does not replace all of them as expected, causing the test to fail.", "The implementation is incorrect because it contains an unclosed delimiter, which is causing a syntax error. The function `replace_spaces` is defined inside the `main` function, which is not properly closed. This issue needs to be fixed by properly closing the `main` function or moving the `replace_spaces` function outside of it.", "The implementation is incorrect because it tries to handle consecutive underscores and spaces by replacing them with a combination of space and underscore. This causes the function to fail when there are mixed spaces and underscores in the input string, as it doesn't properly handle the conversion between them.", "The implementation is incorrect because it only replaces one type of character at a time. When it encounters a string with both spaces and underscores, it doesn't replace them simultaneously, leading to incorrect output."]} +{"name": "mbpp_573_unique_product", "language": "rs", "prompt": "/// Write a rsthon function to calculate the product of the unique numbers in a given vector.\nfn unique_product(list_data: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_573_unique_product.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "unique_product", "test": "\n\nfn main() {\n let candidate = unique_product;\n assert_eq!(candidate(vec![10, 20, 30, 40, 20, 50, 60, 40]), 720000000);\n assert_eq!(candidate(vec![1, 2, 3, 1]), 6);\n assert_eq!(candidate(vec![7, 8, 9, 0, 1, 1]), 0);\n}\n", "solution": "/// Write a rsthon function to calculate the product of the unique numbers in a given vector.\nfn unique_product(list_data: Vec) -> isize {\n let unique_numbers: Vec = list_data.into_iter().collect::>().into_iter().collect();\n let product: isize = unique_numbers.into_iter().product();\n product\n}", "is_solved": true, "reflections": ["The implementation is wrong because there is no `unique` method available for `std::vec::IntoIter` in the Rust standard library. This causes a compilation error. To fix this issue, an alternative method should be used to obtain unique elements from the vector, such as using a HashSet or filtering duplicates manually."]} +{"name": "mbpp_643_text_match_wordz_middle", "language": "rs", "prompt": "/// Write a function that checks if a strings contains 'z', except at the start and end of the word.\nfn text_match_wordz_middle(text: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_643_text_match_wordz_middle.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "text_match_wordz_middle", "test": "\n\nfn main() {\n let candidate = text_match_wordz_middle;\n assert_eq!(candidate(String::from(\"pythonzabc.\")), true);\n assert_eq!(candidate(String::from(\"zxyabc.\")), false);\n assert_eq!(candidate(String::from(\" lang .\")), false);\n}\n", "solution": "/// Write a function that checks if a strings contains 'z', except at the start and end of the word.\nfn text_match_wordz_middle(text: String) -> bool {\n let chars = text.chars().collect::>();\n let len = chars.len();\n\n if len <= 1 {\n return false;\n }\n\n for i in 1..len {\n if chars[i] == 'z' && i != len - 1 {\n return true;\n }\n }\n\n false\n}", "is_solved": true, "reflections": ["The implementation of the text_match_wordz_middle function is incorrect because it only checks for the presence of 'z' in the middle of the string, but it does not account for the case when the string has a length of 3 and 'z' is in the middle. This is why the test with the input \"zoo\" fails.", "The implementation is incorrect because it does not handle the case when the input string has a length of 2. The function only checks for lengths of 1 and 3, causing it to skip the case when the input string has a length of 2 and contains 'z' in the middle.", "The implementation is incorrect because it has unnecessary special cases for lengths 2 and 3, which cause the function to return incorrect results for some inputs. The main loop should be sufficient to handle all cases, as it checks for 'z' in the middle of the string while excluding the first and last characters.", "The implementation is incorrect because it checks for 'z' in the middle of the string but excludes the second to last character. The loop should iterate until `len`, not `len - 1`, to include the second to last character in the search."]} +{"name": "mbpp_299_max_aggregate", "language": "rs", "prompt": "/// Write a function to calculate the maximum aggregate from the vector of tuples.\nfn max_aggregate(stdata: Vec<(String, isize)>) -> (String, isize) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_299_max_aggregate.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_aggregate", "test": "\n\nfn main() {\n let candidate = max_aggregate;\n assert_eq!(candidate(vec![(String::from(\"Juan Whelan\"), 90), (String::from(\"Sabah Colley\"), 88), (String::from(\"Peter Nichols\"), 7), (String::from(\"Juan Whelan\"), 122), (String::from(\"Sabah Colley\"), 84)]), (String::from(\"Juan Whelan\"), 212));\n assert_eq!(candidate(vec![(String::from(\"Juan Whelan\"), 50), (String::from(\"Sabah Colley\"), 48), (String::from(\"Peter Nichols\"), 37), (String::from(\"Juan Whelan\"), 22), (String::from(\"Sabah Colley\"), 14)]), (String::from(\"Juan Whelan\"), 72));\n assert_eq!(candidate(vec![(String::from(\"Juan Whelan\"), 10), (String::from(\"Sabah Colley\"), 20), (String::from(\"Peter Nichols\"), 30), (String::from(\"Juan Whelan\"), 40), (String::from(\"Sabah Colley\"), 50)]), (String::from(\"Sabah Colley\"), 70));\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a function to calculate the maximum aggregate from the vector of tuples.\nfn max_aggregate(stdata: Vec<(String, isize)>) -> (String, isize) {\n let mut max_aggregate = (String::new(), isize::MIN);\n\n for data in stdata {\n if data.1 > max_aggregate.1 {\n max_aggregate = data;\n }\n }\n\n max_aggregate\n}"} +{"name": "mbpp_474_replace_char", "language": "rs", "prompt": "/// Write a function to replace characters in a string.\nfn replace_char(str1: String, ch: String, newch: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_474_replace_char.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "replace_char", "test": "\n\nfn main() {\n let candidate = replace_char;\n assert_eq!(candidate(String::from(\"polygon\"), String::from(\"y\"), String::from(\"l\")), String::from(\"pollgon\"));\n assert_eq!(candidate(String::from(\"character\"), String::from(\"c\"), String::from(\"a\")), String::from(\"aharaater\"));\n assert_eq!(candidate(String::from(\"python\"), String::from(\"l\"), String::from(\"a\")), String::from(\"python\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to replace characters in a string.\nfn replace_char(str1: String, ch: String, newch: String) -> String {\n let mut new_str = String::new();\n for c in str1.chars() {\n if c.to_string() == ch {\n new_str.push_str(&newch);\n } else {\n new_str.push(c);\n }\n }\n new_str\n}"} +{"name": "mbpp_433_check_greater", "language": "rs", "prompt": "/// Write a function to check whether the entered number is greater than the elements of the given vector.\nfn check_greater(arr: Vec, number: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_433_check_greater.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "check_greater", "test": "\n\nfn main() {\n let candidate = check_greater;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5], 4), false);\n assert_eq!(candidate(vec![2, 3, 4, 5, 6], 8), true);\n assert_eq!(candidate(vec![9, 7, 4, 8, 6, 1], 11), true);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check whether the entered number is greater than the elements of the given vector.\nfn check_greater(arr: Vec, number: isize) -> bool {\n for elem in arr {\n if number <= elem {\n return false;\n }\n }\n true\n}"} +{"name": "mbpp_427_change_date_format", "language": "rs", "prompt": "/// Write a function to convert a date of yyyy-mm-dd format to dd-mm-yyyy format.\nfn change_date_format(dt: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_427_change_date_format.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "change_date_format", "test": "\n\nfn main() {\n let candidate = change_date_format;\n assert_eq!(candidate(String::from(\"2026-01-02\")), String::from(\"02-01-2026\"));\n assert_eq!(candidate(String::from(\"2020-11-13\")), String::from(\"13-11-2020\"));\n assert_eq!(candidate(String::from(\"2021-04-26\")), String::from(\"26-04-2021\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to convert a date of yyyy-mm-dd format to dd-mm-yyyy format.\nfn change_date_format(dt: String) -> String {\n let date_parts: Vec<&str> = dt.split('-').collect();\n if date_parts.len() == 3 {\n format!(\"{}-{}-{}\", date_parts[2], date_parts[1], date_parts[0])\n } else {\n String::from(\"Invalid date format\")\n }\n}"} +{"name": "mbpp_442_positive_count", "language": "rs", "prompt": "/// Write a function to find the ration of positive numbers in a vector of integers.\nfn positive_count(nums: Vec) -> f64 {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_442_positive_count.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "positive_count", "test": "\n\nfn main() {\n let candidate = positive_count;\n assert_eq!(candidate(vec![0, 1, 2, -1, -5, 6, 0, -3, -2, 3, 4, 6, 8]), 0.54);\n assert_eq!(candidate(vec![2, 1, 2, -1, -5, 6, 4, -3, -2, 3, 4, 6, 8]), 0.69);\n assert_eq!(candidate(vec![2, 4, -6, -9, 11, -12, 14, -5, 17]), 0.56);\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect when handling an empty vector as input. In this case, the function tries to divide by zero, resulting in a NaN (Not a Number) value. The function should check for an empty vector and return 0.0 directly to avoid this issue."], "solution": "/// Write a function to find the ration of positive numbers in a vector of integers.\nfn positive_count(nums: Vec) -> f64 {\n if nums.is_empty() {\n return 0.0;\n }\n\n let total_nums = nums.len() as f64;\n let mut positive_count = 0;\n\n for num in nums {\n if num > 0 {\n positive_count += 1;\n }\n }\n\n positive_count as f64 / total_nums\n}"} +{"name": "mbpp_453_sumofFactors", "language": "rs", "prompt": "/// Write a rsthon function to find the sum of even factors of a number.\nfn sumofFactors(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_453_sumofFactors.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sumofFactors", "test": "\n\nfn main() {\n let candidate = sumofFactors;\n assert_eq!(candidate(18), 26);\n assert_eq!(candidate(30), 48);\n assert_eq!(candidate(6), 8);\n}\n", "solution": "/// Write a rsthon function to find the sum of even factors of a number.\nfn sumofFactors(n: isize) -> isize {\n let mut sum = 0;\n\n for i in 1..=((n as f64).sqrt() as isize) {\n if n % i == 0 {\n if i % 2 == 0 {\n sum += i;\n }\n let other_factor = n / i;\n if other_factor != i && other_factor % 2 == 0 {\n sum += other_factor;\n }\n }\n }\n\n sum\n}", "is_solved": true, "reflections": ["The implementation of the sumofFactors function is incorrect because it does not properly calculate the sum of even factors for certain input values, as demonstrated by the failed test case for the input 20. The issue likely lies in the loop or the conditions used to determine if a factor is even and should be included in the sum.", "The implementation of the sumofFactors function is incorrect because it does not properly account for all even factors of the input number. The loop only checks factors up to n/2, which may miss some even factors, leading to an incorrect sum. This issue is evident in the failed test case for the input 20, where the function returns 36 instead of the correct sum of 42.", "The implementation of the sumofFactors function is incorrect because it only considers factors up to the square root of the input number. This approach misses some even factors that are greater than the square root, leading to an incorrect sum. The failed test case for the input 20 demonstrates this issue, as the function returns 36 instead of the correct sum of 42.", "The implementation of the sumofFactors function is incorrect because it iterates through all numbers from 1 to n, inclusive, and adds even factors to the sum. However, this approach is inefficient and may lead to incorrect results, as seen in the failed test case where the sum of even factors of 20 is calculated as 36 instead of the correct value, 42."]} +{"name": "mbpp_478_remove_lowercase", "language": "rs", "prompt": "/// Write a function to remove lowercase substrings from a given string.\nfn remove_lowercase(str1: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_478_remove_lowercase.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "remove_lowercase", "test": "\n\nfn main() {\n let candidate = remove_lowercase;\n assert_eq!(candidate(String::from(\"PYTHon\")), String::from(\"PYTH\"));\n assert_eq!(candidate(String::from(\"FInD\")), String::from(\"FID\"));\n assert_eq!(candidate(String::from(\"STRinG\")), String::from(\"STRG\"));\n}\n", "solution": "/// Write a function to remove lowercase substrings from a given string.\nfn remove_lowercase(str1: String) -> String {\n let mut result = String::new();\n let mut temp = String::new();\n\n for c in str1.chars() {\n if c.is_lowercase() {\n temp.push(c);\n } else {\n if !temp.is_empty() {\n temp.clear();\n }\n result.push(c);\n }\n }\n\n result\n}", "is_solved": true, "reflections": ["The implementation of the remove_lowercase function is incorrect because it only removes lowercase characters and keeps uppercase characters. However, the failed test case expects the function to remove lowercase substrings, not just individual lowercase characters. As a result, the function does not produce the expected output for the given test case.", "The implementation is wrong because it does not properly handle the removal of lowercase characters when they are followed by an uppercase character. The current implementation only clears the `temp` string when an uppercase character is encountered, but it does not remove the lowercase characters from the final result. This causes the last lowercase character before an uppercase character to be included in the output, leading to the failed test case.", "The implementation of the remove_lowercase function is incorrect because it does not properly handle the removal of consecutive lowercase characters. In the failed test case, it should have removed \"ust\" from \"RustGPT\" to return \"RGP\", but it returned \"RGPT\" instead. This indicates that the function is not correctly identifying and removing all lowercase characters in the input string.", "The implementation of the remove_lowercase function is incorrect because it only removes lowercase characters and keeps uppercase characters. However, the failed test case expects the function to remove lowercase substrings, not just individual lowercase characters. As a result, the function does not produce the expected output for the given test case."]} +{"name": "mbpp_18_remove_dirty_chars", "language": "rs", "prompt": "/// Write a function to remove characters from the first string which are present in the second string.\nfn remove_dirty_chars(string: String, second_string: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_18_remove_dirty_chars.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "remove_dirty_chars", "test": "\n\nfn main() {\n let candidate = remove_dirty_chars;\n assert_eq!(candidate(String::from(\"probasscurve\"), String::from(\"pros\")), String::from(\"bacuve\"));\n assert_eq!(candidate(String::from(\"digitalindia\"), String::from(\"talent\")), String::from(\"digiidi\"));\n assert_eq!(candidate(String::from(\"exoticmiles\"), String::from(\"toxic\")), String::from(\"emles\"));\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because it only checks for the presence of characters from the second string in the first string and removes them. However, it does not account for duplicate characters in the second string, which may cause some characters to be removed even if they should not be. In the failed test case, the character 'r' is removed from the first string even though it only appears once in the second string, resulting in the incorrect output \"ust\" instead of \"u\".", "The implementation is incorrect because it removes characters from the second string once they are matched, causing it to not remove all occurrences of the characters in the first string. This leads to incorrect results when there are multiple instances of a character in the first string that should be removed.", "The implementation is incorrect because it only removes characters from the first string that are present in the second string without considering duplicates. In the failed test case, the character 'r' is removed, but the other characters 'u', 's', and 't' are not removed since they only appear once in the second string.", "The implementation is incorrect because it only removes characters from the first string that are present in the second string, but it does not account for duplicate characters in the second string. As a result, the function fails to remove all instances of the characters from the first string, leading to incorrect output in some cases."], "solution": "/// Write a function to remove characters from the first string which are present in the second string.\nfn remove_dirty_chars(string: String, second_string: String) -> String {\n let mut clean_string = String::new();\n let second_string_chars: Vec = second_string.chars().collect();\n\n for c in string.chars() {\n if !second_string_chars.contains(&c) {\n clean_string.push(c);\n }\n }\n\n let mut final_string = String::new();\n for c in clean_string.chars() {\n if !final_string.contains(c) {\n final_string.push(c);\n }\n }\n\n final_string\n}"} +{"name": "mbpp_772_remove_length", "language": "rs", "prompt": "/// Write a function to remove all the words with k length in the given string.\nfn remove_length(test_str: String, K: isize) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_772_remove_length.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "remove_length", "test": "\n\nfn main() {\n let candidate = remove_length;\n assert_eq!(candidate(String::from(\"The person is most value tet\"), 3), String::from(\"person is most value\"));\n assert_eq!(candidate(String::from(\"If you told me about this ok\"), 4), String::from(\"If you me about ok\"));\n assert_eq!(candidate(String::from(\"Forces of darkeness is come into the play\"), 4), String::from(\"Forces of darkeness is the\"));\n}\n", "is_solved": false, "reflections": ["The implementation of the `remove_length` function is incorrect because it does not properly handle cases where the input string contains punctuation marks or special characters. The function only splits the input string based on whitespace, which causes it to fail when there are words with the specified length that are followed by punctuation marks or special characters. This leads to incorrect results in the failed test cases.", "The implementation is incorrect because it fails to properly handle cases where the word length matches the given length 'K'. The split function is not effectively removing punctuation, causing the filtering process to consider words with punctuation as different lengths. This leads to incorrect output in the test cases.", "The implementation is incorrect because it contains an unclosed delimiter, which is causing a syntax error. The main function is missing its opening curly brace, and the function remove_length is incorrectly indented inside the main function's comment block. This causes the compiler to be unable to match the opening and closing braces properly, resulting in the error.", "The implementation is incorrect because it fails to properly filter out words of the specified length (K). The issue lies in the filtering process, where it also considers punctuation characters as part of the word length. This causes the function to not remove words that should be removed, as seen in the failed test cases."], "solution": "/// Write a function to remove all the words with k length in the given string.\nfn remove_length(test_str: String, K: isize) -> String {\n let words: Vec<&str> = test_str.split_whitespace().collect();\n let filtered_words: Vec = words\n .into_iter()\n .filter(|word| {\n let cleaned_word: String = word.chars().filter(|c| !c.is_ascii_punctuation()).collect();\n cleaned_word.len() != K as usize\n })\n .map(|word| {\n let cleaned_word: String = word.chars().filter(|c| !c.is_ascii_punctuation()).collect();\n cleaned_word\n })\n .collect();\n filtered_words.join(\" \")"} +{"name": "mbpp_752_jacobsthal_num", "language": "rs", "prompt": "/// Write a function to find the nth jacobsthal number. https://www.geeksforgeeks.org/jacobsthal-and-jacobsthal-lucas-numbers/ 0, 1, 1, 3, 5, 11, 21, 43, 85, 171, 341, 683, 1365, 2731, ...\nfn jacobsthal_num(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_752_jacobsthal_num.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "jacobsthal_num", "test": "\n\nfn main() {\n let candidate = jacobsthal_num;\n assert_eq!(candidate(5), 11);\n assert_eq!(candidate(2), 1);\n assert_eq!(candidate(4), 5);\n assert_eq!(candidate(13), 2731);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the nth jacobsthal number. https://www.geeksforgeeks.org/jacobsthal-and-jacobsthal-lucas-numbers/ 0, 1, 1, 3, 5, 11, 21, 43, 85, 171, 341, 683, 1365, 2731, ...\nfn jacobsthal_num(n: isize) -> isize {\n if n == 0 {\n return 0;\n } else if n == 1 {\n return 1;\n } else {\n return jacobsthal_num(n - 1) + 2 * jacobsthal_num(n - 2);\n }\n}"} +{"name": "mbpp_145_max_Abs_Diff", "language": "rs", "prompt": "/// Write a rsthon function to find the maximum difference between any two elements in a given vector.\nfn max_Abs_Diff(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_145_max_Abs_Diff.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_Abs_Diff", "test": "\n\nfn main() {\n let candidate = max_Abs_Diff;\n assert_eq!(candidate(vec![2, 1, 5, 3]), 4);\n assert_eq!(candidate(vec![9, 3, 2, 5, 1]), 8);\n assert_eq!(candidate(vec![3, 2, 1]), 2);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the maximum difference between any two elements in a given vector.\nfn max_Abs_Diff(arr: Vec) -> isize {\n let mut max_diff = 0;\n let mut min_element = arr[0];\n let mut max_element = arr[0];\n\n for &num in arr.iter() {\n if num < min_element {\n min_element = num;\n } else if num > max_element {\n max_element = num;\n }\n }\n\n max_diff = max_element - min_element;\n max_diff\n}"} +{"name": "mbpp_572_two_unique_nums", "language": "rs", "prompt": "/// Write a rsthon function to remove duplicate numbers from a given number of vectors.\nfn two_unique_nums(nums: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_572_two_unique_nums.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "two_unique_nums", "test": "\n\nfn main() {\n let candidate = two_unique_nums;\n assert_eq!(candidate(vec![1, 2, 3, 2, 3, 4, 5]), vec![1, 4, 5]);\n assert_eq!(candidate(vec![1, 2, 3, 2, 4, 5]), vec![1, 3, 4, 5]);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5]), vec![1, 2, 3, 4, 5]);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a rsthon function to remove duplicate numbers from a given number of vectors.\nfn two_unique_nums(nums: Vec) -> Vec {\n let mut unique_nums = Vec::new();\n\n for num in nums {\n if !unique_nums.contains(&num) {\n unique_nums.push(num);\n }\n }\n\n unique_nums\n}"} +{"name": "mbpp_556_find_Odd_Pair", "language": "rs", "prompt": "/// Write a rsthon function to count the number of pairs whose xor value is odd.\nfn find_Odd_Pair(A: Vec, N: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_556_find_Odd_Pair.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_Odd_Pair", "test": "\n\nfn main() {\n let candidate = find_Odd_Pair;\n assert_eq!(candidate(vec![5, 4, 7, 2, 1], 5), 6);\n assert_eq!(candidate(vec![7, 2, 8, 1, 0, 5, 11], 7), 12);\n assert_eq!(candidate(vec![1, 2, 3], 3), 2);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to count the number of pairs whose xor value is odd.\nfn find_Odd_Pair(A: Vec, N: isize) -> isize {\n let mut count = 0;\n\n for i in 0..(N as usize) {\n for j in (i + 1)..(N as usize) {\n if (A[i] ^ A[j]) % 2 != 0 {\n count += 1;\n }\n }\n }\n\n count\n}"} +{"name": "mbpp_306_max_sum_increasing_subseq", "language": "rs", "prompt": "/// Write a function to find the maximum sum of increasing subsequence from prefix until ith index and also including a given kth element which is after i, i.e., k > i .\nfn max_sum_increasing_subseq(a: Vec, n: isize, index: isize, k: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_306_max_sum_increasing_subseq.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_sum_increasing_subseq", "test": "\n\nfn main() {\n let candidate = max_sum_increasing_subseq;\n assert_eq!(candidate(vec![1, 101, 2, 3, 100, 4, 5], 7, 4, 6), 11);\n assert_eq!(candidate(vec![1, 101, 2, 3, 100, 4, 5], 7, 2, 5), 7);\n assert_eq!(candidate(vec![11, 15, 19, 21, 26, 28, 31], 7, 2, 4), 71);\n}\n", "is_solved": false, "reflections": ["The current implementation is incorrect because it only considers the increasing subsequences ending at the ith index and does not account for the subsequences that include the kth element. This leads to incorrect results when the maximum sum increasing subsequence should include the kth element.", "The implementation is incorrect because it calculates the maximum sum of increasing subsequences twice, once for the prefix until ith index and again for the kth element. This leads to an overestimation of the maximum sum, as it essentially adds the kth element twice in the final result. The correct approach should only calculate the maximum sum of increasing subsequences once, considering both the prefix until ith index and the kth element together.", "The current implementation is incorrect because it calculates the maximum sum of increasing subsequences without properly considering the inclusion of the kth element. The second loop that was commented out is necessary to ensure the kth element is included in the calculation. However, it should be modified to start from the given index instead of 0 to avoid calculating the maximum sum twice.", "The implementation is incorrect because it calculates the maximum sum of increasing subsequences for all elements in the range [0, k] instead of only considering the subsequences ending at index i and including the kth element. This leads to incorrect results when the kth element should be included in the increasing subsequence."], "solution": "/// Write a function to find the maximum sum of increasing subsequence from prefix until ith index and also including a given kth element which is after i, i.e., k > i .\nfn max_sum_increasing_subseq(a: Vec, n: isize, index: isize, k: isize) -> isize {\n let mut dp = vec![0; n as usize];\n dp[0] = a[0];\n\n for i in 1..n as usize {\n dp[i] = a[i];\n for j in 0..i {\n if a[i] > a[j] {\n dp[i] = dp[i].max(dp[j] + a[i]);\n }\n }\n }\n\n let mut max_sum = 0;\n for i in 0..index as usize {\n if a[k as usize] > a[i] {\n max_sum = max_sum.max(dp[i] + a[k as usize]);\n }\n }\n\n // Include the kth element in the increasing subsequence\n for i in index as usize..k as usize {\n if a[k as usize] > a[i] {\n max_sum = max_sum.max(dp[i] + a[k as usize]);\n }\n }\n\n // Exclude the kth element from the increasing subsequence\n let mut max_sum_without_k = 0;\n for i in 0..index as usize {\n max_sum_without_k = max_sum_without_k.max(dp[i]);\n }\n\n max_sum.max(max_sum_without_k)\n}"} +{"name": "mbpp_388_highest_Power_of_2", "language": "rs", "prompt": "/// Write a rsthon function to find the highest power of 2 that is less than or equal to n.\nfn highest_Power_of_2(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_388_highest_Power_of_2.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "highest_Power_of_2", "test": "\n\nfn main() {\n let candidate = highest_Power_of_2;\n assert_eq!(candidate(10), 8);\n assert_eq!(candidate(19), 16);\n assert_eq!(candidate(32), 32);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the highest power of 2 that is less than or equal to n.\nfn highest_Power_of_2(n: isize) -> isize {\n let mut power = 1;\n while power * 2 <= n {\n power *= 2;\n }\n power\n}"} +{"name": "mbpp_401_add_nested_tuples", "language": "rs", "prompt": "/// Write a function to perform index wise addition of vector elements in the given two nested vectors.\nfn add_nested_tuples(test_tup1: Vec>, test_tup2: Vec>) -> Vec> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_401_add_nested_tuples.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "add_nested_tuples", "test": "\n\nfn main() {\n let candidate = add_nested_tuples;\n assert_eq!(candidate(vec![vec![1, 3], vec![4, 5], vec![2, 9], vec![1, 10]], vec![vec![6, 7], vec![3, 9], vec![1, 1], vec![7, 3]]), vec![vec![7, 10], vec![7, 14], vec![3, 10], vec![8, 13]]);\n assert_eq!(candidate(vec![vec![2, 4], vec![5, 6], vec![3, 10], vec![2, 11]], vec![vec![7, 8], vec![4, 10], vec![2, 2], vec![8, 4]]), vec![vec![9, 12], vec![9, 16], vec![5, 12], vec![10, 15]]);\n assert_eq!(candidate(vec![vec![3, 5], vec![6, 7], vec![4, 11], vec![3, 12]], vec![vec![8, 9], vec![5, 11], vec![3, 3], vec![9, 5]]), vec![vec![11, 14], vec![11, 18], vec![7, 14], vec![12, 17]]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to perform index wise addition of vector elements in the given two nested vectors.\nfn add_nested_tuples(test_tup1: Vec>, test_tup2: Vec>) -> Vec> {\n let mut result: Vec> = Vec::new();\n\n for (i, inner_tup1) in test_tup1.iter().enumerate() {\n let mut inner_result: Vec = Vec::new();\n for (j, value) in inner_tup1.iter().enumerate() {\n inner_result.push(value + test_tup2[i][j]);\n }\n result.push(inner_result);\n }\n\n result\n}"} +{"name": "mbpp_435_last_Digit", "language": "rs", "prompt": "/// Write a rsthon function to find the last digit of a given number.\nfn last_Digit(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_435_last_Digit.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "last_Digit", "test": "\n\nfn main() {\n let candidate = last_Digit;\n assert_eq!(candidate(123), 3);\n assert_eq!(candidate(25), 5);\n assert_eq!(candidate(30), 0);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the last digit of a given number.\nfn last_Digit(n: isize) -> isize {\n n.abs() % 10\n}"} +{"name": "mbpp_611_max_of_nth", "language": "rs", "prompt": "/// Write a function which given a matrix represented as a vector of vectors returns the max of the n'th column.\nfn max_of_nth(test_list: Vec>, N: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_611_max_of_nth.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_of_nth", "test": "\n\nfn main() {\n let candidate = max_of_nth;\n assert_eq!(candidate(vec![vec![5, 6, 7], vec![1, 3, 5], vec![8, 9, 19]], 2), 19);\n assert_eq!(candidate(vec![vec![6, 7, 8], vec![2, 4, 6], vec![9, 10, 20]], 1), 10);\n assert_eq!(candidate(vec![vec![7, 8, 9], vec![3, 5, 7], vec![10, 11, 21]], 1), 11);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function which given a matrix represented as a vector of vectors returns the max of the n'th column.\nfn max_of_nth(test_list: Vec>, N: isize) -> isize {\n if test_list.is_empty() || N < 0 {\n return isize::MIN;\n }\n\n let mut max_value = isize::MIN;\n for row in test_list.iter() {\n if N as usize >= row.len() {\n continue;\n }\n max_value = max_value.max(row[N as usize]);\n }\n\n max_value\n}"} +{"name": "mbpp_280_sequential_search", "language": "rs", "prompt": "/// Write a function that takes in a vector and element and returns a tuple containing a boolean that indicates if the element is in the vector and the index position of the element (or -1 if the element is not found).\nfn sequential_search(dlist: Vec, item: isize) -> (bool, isize) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_280_sequential_search.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sequential_search", "test": "\n\nfn main() {\n let candidate = sequential_search;\n assert_eq!(candidate(vec![11, 23, 58, 31, 56, 77, 43, 12, 65, 19], 31), (true, 3));\n assert_eq!(candidate(vec![12, 32, 45, 62, 35, 47, 44, 61], 61), (true, 7));\n assert_eq!(candidate(vec![9, 10, 17, 19, 22, 39, 48, 56], 48), (true, 6));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function that takes in a vector and element and returns a tuple containing a boolean that indicates if the element is in the vector and the index position of the element (or -1 if the element is not found).\nfn sequential_search(dlist: Vec, item: isize) -> (bool, isize) {\n for (index, &value) in dlist.iter().enumerate() {\n if value == item {\n return (true, index as isize);\n }\n }\n (false, -1)\n}"} +{"name": "mbpp_576_is_Sub_Array", "language": "rs", "prompt": "/// Write a rsthon function to check whether a vector is subvector of another or not.\nfn is_Sub_Array(A: Vec, B: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_576_is_Sub_Array.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_Sub_Array", "test": "\n\nfn main() {\n let candidate = is_Sub_Array;\n assert_eq!(candidate(vec![1, 4, 3, 5], vec![1, 2]), false);\n assert_eq!(candidate(vec![1, 2, 1], vec![1, 2, 1]), true);\n assert_eq!(candidate(vec![1, 0, 2, 2], vec![2, 2, 0]), false);\n}\n", "solution": "/// Write a rsthon function to check whether a vector is subvector of another or not.\nfn is_Sub_Array(A: Vec, B: Vec) -> bool {\n if A.len() < B.len() {\n return false;\n }\n\n let mut i = 0;\n let mut j = 0;\n\n while i < A.len() - B.len() + 1 {\n if A[i..i + B.len()] == B {\n return true;\n }\n i += 1;\n }\n\n false\n}", "is_solved": true, "reflections": ["The current implementation incorrectly identifies non-contiguous subarrays as valid subarrays. It does not ensure that the elements in the subarray B are in the same order and contiguous in array A. This causes the failed test case where B has elements [2, 4] which are not contiguous in A [1, 2, 3, 4]."]} +{"name": "mbpp_131_reverse_vowels", "language": "rs", "prompt": "/// Write a rsthon function to reverse only the vowels of a given string (where y is not a vowel).\nfn reverse_vowels(str1: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_131_reverse_vowels.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "reverse_vowels", "test": "\n\nfn main() {\n let candidate = reverse_vowels;\n assert_eq!(candidate(String::from(\"Python\")), String::from(\"Python\"));\n assert_eq!(candidate(String::from(\"USA\")), String::from(\"ASU\"));\n assert_eq!(candidate(String::from(\"ab\")), String::from(\"ab\"));\n}\n", "solution": "/// Write a rsthon function to reverse only the vowels of a given string (where y is not a vowel).\nfn reverse_vowels(str1: String) -> String {\n let vowels = \"aeiouAEIOU\";\n let mut str_chars: Vec = str1.chars().collect();\n let mut i = 0;\n let mut j = str_chars.len() - 1;\n\n while i < j {\n if !vowels.contains(str_chars[i]) {\n i += 1;\n continue;\n }\n if !vowels.contains(str_chars[j]) {\n j -= 1;\n continue;\n }\n\n str_chars.swap(i, j);\n i += 1;\n j -= 1;\n }\n\n str_chars.into_iter().collect()\n}", "is_solved": true, "reflections": ["The implementation of the reverse_vowels function is incorrect because it fails to properly reverse the vowels in the input string for certain test cases. The issue likely lies in the handling of the vowel swapping logic or the conditions for identifying vowels within the string.", "The implementation of the reverse_vowels function is incorrect because it fails to reverse the vowels in the given test cases. The issue lies in the fact that the function does not properly identify and swap the vowels in the input string, leading to incorrect output.", "The implementation is incorrect because it only swaps vowels when they are different in their lowercase form. This causes the function to skip swapping vowels if they are the same, even if they have different cases (e.g., 'E' and 'e'). This leads to incorrect results in some test cases.", "The implementation of the reverse_vowels function is incorrect because it fails to properly reverse the vowels in the input string. The failed test cases indicate that the function does not swap the vowels as expected, resulting in the output being the same as the input string. This suggests that there might be an issue with the vowel detection or the swapping logic within the function."]} +{"name": "mbpp_432_median_trapezium", "language": "rs", "prompt": "/// Write a function to find the median length of a trapezium.\nfn median_trapezium(base1: isize, base2: isize, height: isize) -> f64 {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_432_median_trapezium.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "median_trapezium", "test": "\n\nfn main() {\n let candidate = median_trapezium;\n assert_eq!(candidate(15, 25, 35), 20.0);\n assert_eq!(candidate(10, 20, 30), 15.0);\n assert_eq!(candidate(6, 9, 4), 7.5);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the median length of a trapezium.\nfn median_trapezium(base1: isize, base2: isize, height: isize) -> f64 {\n let median = (base1 + base2) as f64 / 2.0;\n let area = median * height as f64;\n area / height as f64\n}"} +{"name": "mbpp_161_remove_elements", "language": "rs", "prompt": "/// Write a function to remove all elements from a given vector present in another vector.\nfn remove_elements(list1: Vec, list2: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_161_remove_elements.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "remove_elements", "test": "\n\nfn main() {\n let candidate = remove_elements;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 10], vec![2, 4, 6, 8]), vec![1, 3, 5, 7, 9, 10]);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 10], vec![1, 3, 5, 7]), vec![2, 4, 6, 8, 9, 10]);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 10], vec![5, 7]), vec![1, 2, 3, 4, 6, 8, 9, 10]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to remove all elements from a given vector present in another vector.\nfn remove_elements(list1: Vec, list2: Vec) -> Vec {\n list1.into_iter().filter(|x| !list2.contains(x)).collect()\n}"} +{"name": "mbpp_597_find_kth", "language": "rs", "prompt": "/// Write a function to find kth element from the given two sorted vectors.\nfn find_kth(arr1: Vec, arr2: Vec, k: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_597_find_kth.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_kth", "test": "\n\nfn main() {\n let candidate = find_kth;\n assert_eq!(candidate(vec![2, 3, 6, 7, 9], vec![1, 4, 8, 10], 5), 6);\n assert_eq!(candidate(vec![100, 112, 256, 349, 770], vec![72, 86, 113, 119, 265, 445, 892], 7), 256);\n assert_eq!(candidate(vec![3, 4, 7, 8, 10], vec![2, 5, 9, 11], 6), 8);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find kth element from the given two sorted vectors.\nfn find_kth(arr1: Vec, arr2: Vec, k: isize) -> isize {\n let mut i = 0;\n let mut j = 0;\n let mut count = 0;\n\n while i < arr1.len() && j < arr2.len() {\n if arr1[i] < arr2[j] {\n count += 1;\n if count == k {\n return arr1[i];\n }\n i += 1;\n } else {\n count += 1;\n if count == k {\n return arr2[j];\n }\n j += 1;\n }\n }\n\n while i < arr1.len() {\n count += 1;\n if count == k {\n return arr1[i];\n }\n i += 1;\n }\n\n while j < arr2.len() {\n count += 1;\n if count == k {\n return arr2[j];\n }\n j += 1;\n }\n\n panic!(\"k is out of bounds\");\n}"} +{"name": "mbpp_226_odd_values_string", "language": "rs", "prompt": "/// Write a rsthon function to remove the characters which have odd index values of a given string.\nfn odd_values_string(str: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_226_odd_values_string.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "odd_values_string", "test": "\n\nfn main() {\n let candidate = odd_values_string;\n assert_eq!(candidate(String::from(\"abcdef\")), String::from(\"ace\"));\n assert_eq!(candidate(String::from(\"python\")), String::from(\"pto\"));\n assert_eq!(candidate(String::from(\"data\")), String::from(\"dt\"));\n assert_eq!(candidate(String::from(\"lambs\")), String::from(\"lms\"));\n}\n", "solution": "/// Write a rsthon function to remove the characters which have odd index values of a given string.\nfn odd_values_string(str: String) -> String {\n let mut result = String::new();\n\n for (index, character) in str.char_indices() {\n if index % 2 == 0 {\n result.push(character);\n }\n }\n\n result\n}", "is_solved": true, "reflections": ["The implementation of the odd_values_string function is incorrect because it removes characters with even index values instead of odd index values. The condition in the if statement should be `index % 2 != 0` to correctly remove characters with odd index values.", "The implementation of the odd_values_string function is incorrect because it removes characters with even index values instead of odd index values. The condition in the if statement should be `index % 2 == 0` to keep characters with even index values, as the goal is to remove characters with odd index values.", "The implementation of the odd_values_string function is incorrect because it removes characters with even index values instead of odd index values. The condition in the if statement should be `index % 2 != 0` to correctly remove characters with odd index values.", "The implementation of the `odd_values_string` function is incorrect because it removes characters with even index values instead of odd index values. The condition `index % 2 != 0` should be changed to `index % 2 == 0` to keep characters with even index values and remove those with odd index values. This is why the failed tests have the opposite characters removed than expected."]} +{"name": "mbpp_269_ascii_value", "language": "rs", "prompt": "/// Write a function to find the ascii value of a character.\nfn ascii_value(k: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_269_ascii_value.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "ascii_value", "test": "\n\nfn main() {\n let candidate = ascii_value;\n assert_eq!(candidate(String::from(\"A\")), 65);\n assert_eq!(candidate(String::from(\"R\")), 82);\n assert_eq!(candidate(String::from(\"S\")), 83);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the ascii value of a character.\nfn ascii_value(k: String) -> isize {\n let character = k.chars().next().unwrap_or('\\0');\n character as isize\n}"} +{"name": "mbpp_739_find_Index", "language": "rs", "prompt": "/// Write a rsthon function to find the index of smallest triangular number with n digits. https://www.geeksforgeeks.org/index-of-smallest-triangular-number-with-n-digits/\nfn find_Index(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_739_find_Index.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_Index", "test": "\n\nfn main() {\n let candidate = find_Index;\n assert_eq!(candidate(2), 4);\n assert_eq!(candidate(3), 14);\n assert_eq!(candidate(4), 45);\n}\n", "solution": "/// Write a rsthon function to find the index of smallest triangular number with n digits. https://www.geeksforgeeks.org/index-of-smallest-triangular-number-with-n-digits/\nfn find_Index(n: isize) -> isize {\n let mut index = 1;\n let mut triangular_number = 1;\n\n while triangular_number < 10isize.pow((n - 1) as u32) {\n index += 1;\n triangular_number += index;\n }\n\n index\n}", "is_solved": true, "reflections": ["The implementation of the find_Index function is incorrect because it stops when the triangular_number is less than 10^(n-1), which means it stops one step earlier than it should. This causes the function to return an index that corresponds to a triangular number with fewer digits than expected, leading to the failed test cases.", "The implementation of the find_Index function is incorrect because it does not properly calculate the smallest triangular number with n digits. The condition in the while loop and the additional check after the loop are not sufficient to find the correct index. As a result, the function fails for cases like n=1, n=4, and n=5, providing incorrect index values.", "The implementation is incorrect because it uses two separate while loops to find the index of the smallest triangular number with n digits. The first while loop stops when the triangular number is greater than or equal to 10^(n-1), and the second while loop stops when the triangular number is greater than or equal to 10^n. This approach leads to incorrect results as it doesn't properly calculate the smallest triangular number with n digits.", "The implementation of the find_Index function is incorrect because it does not properly calculate the smallest triangular number with n digits. The two while loops in the function are not correctly handling the conditions for finding the smallest triangular number, causing the function to return incorrect index values for the given test cases."]} +{"name": "mbpp_19_test_duplicate", "language": "rs", "prompt": "/// Write a function to find whether a given vector of integers contains any duplicate element.\nfn test_duplicate(arraynums: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_19_test_duplicate.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "test_duplicate", "test": "\n\nfn main() {\n let candidate = test_duplicate;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5]), false);\n assert_eq!(candidate(vec![1, 2, 3, 4, 4]), true);\n assert_eq!(candidate(vec![1, 1, 2, 2, 3, 3, 4, 4, 5]), true);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find whether a given vector of integers contains any duplicate element.\nfn test_duplicate(arraynums: Vec) -> bool {\n let mut nums_set = std::collections::HashSet::new();\n\n for num in arraynums {\n if nums_set.contains(&num) {\n return true;\n } else {\n nums_set.insert(num);\n }\n }\n\n false\n}"} +{"name": "mbpp_62_smallest_num", "language": "rs", "prompt": "/// Write a rsthon function to find smallest number in a vector.\nfn smallest_num(xs: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_62_smallest_num.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "smallest_num", "test": "\n\nfn main() {\n let candidate = smallest_num;\n assert_eq!(candidate(vec![10, 20, 1, 45, 99]), 1);\n assert_eq!(candidate(vec![1, 2, 3]), 1);\n assert_eq!(candidate(vec![45, 46, 50, 60]), 45);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find smallest number in a vector.\nfn smallest_num(xs: Vec) -> isize {\n if xs.is_empty() {\n panic!(\"The input vector is empty.\");\n }\n\n let mut smallest = xs[0];\n\n for &x in xs.iter() {\n if x < smallest {\n smallest = x;\n }\n }\n\n smallest\n}"} +{"name": "mbpp_746_sector_area", "language": "rs", "prompt": "/// Write a function to find area of a sector. The function takes the radius and angle as inputs. Function should return None if the angle is larger than 360 degrees.\nfn sector_area(r: isize, a: isize) -> Option {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_746_sector_area.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sector_area", "test": "\n\nfn main() {\n let candidate = sector_area;\n assert_eq!(candidate(4, 45), Some(6.283185307179586));\n assert_eq!(candidate(9, 45), Some(31.808625617596654));\n assert_eq!(candidate(9, 361), None);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find area of a sector. The function takes the radius and angle as inputs. Function should return None if the angle is larger than 360 degrees.\nfn sector_area(r: isize, a: isize) -> Option {\n if a > 360 {\n return None;\n }\n let angle_radians = (a as f64).to_radians();\n let area = (r as f64).powi(2) * angle_radians / 2.0;\n Some(area)\n}"} +{"name": "mbpp_142_count_samepair", "language": "rs", "prompt": "/// Write a function to count number items that are identical in the same position of three given vectors.\nfn count_samepair(list1: Vec, list2: Vec, list3: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_142_count_samepair.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_samepair", "test": "\n\nfn main() {\n let candidate = count_samepair;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8], vec![2, 2, 3, 1, 2, 6, 7, 9], vec![2, 1, 3, 1, 2, 6, 7, 9]), 3);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8], vec![2, 2, 3, 1, 2, 6, 7, 8], vec![2, 1, 3, 1, 2, 6, 7, 8]), 4);\n assert_eq!(candidate(vec![1, 2, 3, 4, 2, 6, 7, 8], vec![2, 2, 3, 1, 2, 6, 7, 8], vec![2, 1, 3, 1, 2, 6, 7, 8]), 5);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to count number items that are identical in the same position of three given vectors.\nfn count_samepair(list1: Vec, list2: Vec, list3: Vec) -> isize {\n let mut count = 0;\n let min_length = list1.len().min(list2.len()).min(list3.len());\n\n for i in 0..min_length {\n if list1[i] == list2[i] && list2[i] == list3[i] {\n count += 1;\n }\n }\n\n count\n}"} +{"name": "mbpp_400_extract_freq", "language": "rs", "prompt": "/// Write a function to extract the number of unique tuples in the given vector.\nfn extract_freq(test_list: Vec<(isize, isize)>) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_400_extract_freq.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "extract_freq", "test": "\n\nfn main() {\n let candidate = extract_freq;\n assert_eq!(candidate(vec![(3, 4), (1, 2), (4, 3), (5, 6)]), 3);\n assert_eq!(candidate(vec![(4, 15), (2, 3), (5, 4), (6, 7)]), 4);\n assert_eq!(candidate(vec![(5, 16), (2, 3), (6, 5), (6, 9)]), 4);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a function to extract the number of unique tuples in the given vector.\nfn extract_freq(test_list: Vec<(isize, isize)>) -> isize {\n let mut unique_tuples = std::collections::HashSet::new();\n\n for tuple in test_list {\n unique_tuples.insert(tuple);\n }\n\n unique_tuples.len() as isize\n}"} +{"name": "mbpp_135_hexagonal_num", "language": "rs", "prompt": "/// Write a function to find the nth hexagonal number.\nfn hexagonal_num(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_135_hexagonal_num.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "hexagonal_num", "test": "\n\nfn main() {\n let candidate = hexagonal_num;\n assert_eq!(candidate(10), 190);\n assert_eq!(candidate(5), 45);\n assert_eq!(candidate(7), 91);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the nth hexagonal number.\nfn hexagonal_num(n: isize) -> isize {\n if n <= 0 {\n return 0;\n }\n n * (2 * n - 1)\n}"} +{"name": "mbpp_800_remove_all_spaces", "language": "rs", "prompt": "/// Write a function to remove all whitespaces from a string.\nfn remove_all_spaces(text: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_800_remove_all_spaces.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "remove_all_spaces", "test": "\n\nfn main() {\n let candidate = remove_all_spaces;\n assert_eq!(candidate(String::from(\"python program\")), String::from(\"pythonprogram\"));\n assert_eq!(candidate(String::from(\"python programming language\")), String::from(\"pythonprogramminglanguage\"));\n assert_eq!(candidate(String::from(\"python program\")), String::from(\"pythonprogram\"));\n assert_eq!(candidate(String::from(\" python program\")), String::from(\"pythonprogram\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to remove all whitespaces from a string.\nfn remove_all_spaces(text: String) -> String {\n text.chars().filter(|c| !c.is_whitespace()).collect()\n}"} +{"name": "mbpp_127_multiply_int", "language": "rs", "prompt": "/// Write a function to multiply two integers.\nfn multiply_int(x: isize, y: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_127_multiply_int.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "multiply_int", "test": "\n\nfn main() {\n let candidate = multiply_int;\n assert_eq!(candidate(10, 20), 200);\n assert_eq!(candidate(5, 10), 50);\n assert_eq!(candidate(4, 8), 32);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to multiply two integers.\nfn multiply_int(x: isize, y: isize) -> isize {\n x * y\n}"} +{"name": "mbpp_764_number_ctr", "language": "rs", "prompt": "/// Write a rsthon function to count number of digits in a given string.\nfn number_ctr(str: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_764_number_ctr.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "number_ctr", "test": "\n\nfn main() {\n let candidate = number_ctr;\n assert_eq!(candidate(String::from(\"program2bedone\")), 1);\n assert_eq!(candidate(String::from(\"3wonders\")), 1);\n assert_eq!(candidate(String::from(\"123\")), 3);\n assert_eq!(candidate(String::from(\"3wond-1ers2\")), 3);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to count number of digits in a given string.\nfn number_ctr(str: String) -> isize {\n let mut count = 0;\n\n for c in str.chars() {\n if c.is_digit(10) {\n count += 1;\n }\n }\n\n count\n}"} +{"name": "mbpp_767_get_pairs_count", "language": "rs", "prompt": "/// Write a rsthon function to count the number of pairs whose sum is equal to ‘sum’. The funtion gets as input a vector of numbers and the sum,\nfn get_pairs_count(arr: Vec, sum: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_767_get_pairs_count.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "get_pairs_count", "test": "\n\nfn main() {\n let candidate = get_pairs_count;\n assert_eq!(candidate(vec![1, 1, 1, 1], 2), 6);\n assert_eq!(candidate(vec![1, 5, 7, -1, 5], 6), 3);\n assert_eq!(candidate(vec![1, -2, 3], 1), 1);\n assert_eq!(candidate(vec![-1, -2, 3], -3), 1);\n}\n", "solution": "/// Write a rsthon function to count the number of pairs whose sum is equal to ‘sum’. The funtion gets as input a vector of numbers and the sum,\nfn get_pairs_count(arr: Vec, sum: isize) -> isize {\n let mut count = 0;\n let arr_len = arr.len();\n\n // Count the number of occurrences of each element in the array\n let mut occurrences = std::collections::HashMap::new();\n for &num in &arr {\n *occurrences.entry(num).or_insert(0) += 1;\n }\n\n for i in 0..arr_len {\n let complement = sum - arr[i];\n if let Some(&occurrence) = occurrences.get(&complement) {\n count += occurrence;\n }\n\n // If the target sum is formed by two identical elements, decrement the count only if the occurrence is greater than 1\n if complement == arr[i] && occurrences[&complement] > 1 {\n count -= 1;\n }\n }\n\n // Divide the final count by 2, as each pair is counted twice\n count / 2\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it only counts unique pairs of elements whose sum is equal to the target sum. In the failed test case, there are two identical elements (10) that can form a valid pair with -1, but the current implementation only counts one of them.", "The implementation is incorrect because it double counts the pairs when the target sum is even and can be formed by two identical elements. The first part of the code counts all pairs, and the second part adds the count of pairs formed by identical elements again. This leads to incorrect results in cases where the target sum can be formed by two identical elements.", "The provided error message is not related to the function implementation itself, but rather to the surrounding code structure. The error indicates that there is an unclosed delimiter in the code, which is likely caused by mismatched or misplaced curly braces. To fix this issue, ensure that all opening and closing braces are properly matched and indented.", "The implementation is incorrect because it decrements the count when the target sum is formed by two identical elements. This causes an issue when there are multiple pairs with the same elements that add up to the target sum, as it incorrectly reduces the count. This is evident in the failed test case where the correct output should be 2, but the implementation returns 1."]} +{"name": "mbpp_99_decimal_to_binary", "language": "rs", "prompt": "/// Write a function to convert the given decimal number to its binary equivalent, represented as a string with no leading zeros.\nfn decimal_to_binary(n: isize) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_99_decimal_to_binary.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "decimal_to_binary", "test": "\n\nfn main() {\n let candidate = decimal_to_binary;\n assert_eq!(candidate(8), String::from(\"1000\"));\n assert_eq!(candidate(18), String::from(\"10010\"));\n assert_eq!(candidate(7), String::from(\"111\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to convert the given decimal number to its binary equivalent, represented as a string with no leading zeros.\nfn decimal_to_binary(n: isize) -> String {\n let mut binary = String::new();\n let mut num = n;\n\n if num == 0 {\n return \"0\".to_string();\n }\n\n while num > 0 {\n let remainder = num % 2;\n binary.insert(0, (remainder as u8 + '0' as u8) as char);\n num /= 2;\n }\n\n binary\n}"} +{"name": "mbpp_119_search", "language": "rs", "prompt": "/// Write a rsthon function to find the element that appears only once in a sorted vector.\nfn search(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_119_search.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "search", "test": "\n\nfn main() {\n let candidate = search;\n assert_eq!(candidate(vec![1, 1, 2, 2, 3]), 3);\n assert_eq!(candidate(vec![1, 1, 3, 3, 4, 4, 5, 5, 7, 7, 8]), 8);\n assert_eq!(candidate(vec![1, 2, 2, 3, 3, 4, 4]), 1);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the element that appears only once in a sorted vector.\nfn search(arr: Vec) -> isize {\n let mut i = 0;\n\n while i < arr.len() {\n if i == arr.len() - 1 || arr[i] != arr[i + 1] {\n return arr[i];\n }\n i += 2;\n }\n\n -1\n}"} +{"name": "mbpp_92_is_undulating", "language": "rs", "prompt": "/// Write a function to check whether the given number is undulating or not.\nfn is_undulating(n: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_92_is_undulating.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_undulating", "test": "\n\nfn main() {\n let candidate = is_undulating;\n assert_eq!(candidate(1212121), true);\n assert_eq!(candidate(1991), false);\n assert_eq!(candidate(121), true);\n}\n", "solution": "/// Write a function to check whether the given number is undulating or not.\nfn is_undulating(n: isize) -> bool {\n if n < 100 {\n return false;\n }\n\n let digits: Vec<_> = n.to_string().chars().collect();\n let first_digit = digits[0];\n let second_digit = digits[1];\n\n if first_digit == second_digit {\n return false;\n }\n\n for i in (0..digits.len()).step_by(2) {\n if digits[i] != first_digit {\n return false;\n }\n }\n\n for i in (1..digits.len()).step_by(2) {\n if digits[i] != second_digit {\n return false;\n }\n }\n\n true\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it checks for alternating digits by comparing them to the first and second digits, but it does not ensure that the pattern is strictly undulating (i.e., the same two digits are repeated). As a result, the function returns false for valid undulating numbers like 989, 121, and 373."]} +{"name": "mbpp_105_count", "language": "rs", "prompt": "/// Write a rsthon function to count true booleans in the given vector.\nfn count(lst: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_105_count.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count", "test": "\n\nfn main() {\n let candidate = count;\n assert_eq!(candidate(vec![true, false, true]), 2);\n assert_eq!(candidate(vec![false, false]), 0);\n assert_eq!(candidate(vec![true, true, true]), 3);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to count true booleans in the given vector.\nfn count(lst: Vec) -> isize {\n let mut count = 0;\n for value in lst {\n if value {\n count += 1;\n }\n }\n count as isize\n}"} +{"name": "mbpp_766_pair_wise", "language": "rs", "prompt": "/// Write a function to return a vector of all pairs of consecutive items in a given vector.\nfn pair_wise(l1: Vec) -> Vec<(isize, isize)> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_766_pair_wise.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "pair_wise", "test": "\n\nfn main() {\n let candidate = pair_wise;\n assert_eq!(candidate(vec![1, 1, 2, 3, 3, 4, 4, 5]), vec![(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]);\n assert_eq!(candidate(vec![1, 5, 7, 9, 10]), vec![(1, 5), (5, 7), (7, 9), (9, 10)]);\n assert_eq!(candidate(vec![5, 1, 9, 7, 10]), vec![(5, 1), (1, 9), (9, 7), (7, 10)]);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 10]), vec![(1, 2), (2, 3), (3, 4), (4, 5), (5, 6), (6, 7), (7, 8), (8, 9), (9, 10)]);\n}\n", "solution": "/// Write a function to return a vector of all pairs of consecutive items in a given vector.\nfn pair_wise(l1: Vec) -> Vec<(isize, isize)> {\n let mut pairs = Vec::new();\n\n if l1.is_empty() {\n return pairs;\n }\n\n for i in 0..l1.len() - 1 {\n pairs.push((l1[i], l1[i + 1]));\n }\n\n pairs\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it does not handle the case when the input vector is empty. The loop range is calculated as `0..l1.len() - 1`, which causes an overflow when the length of the input vector is 0. This results in a panic and the test fails."]} +{"name": "mbpp_464_check_value", "language": "rs", "prompt": "use std::collections::HashMap;\n\n/// Write a function to check if all values are same in a HashMap.\nfn check_value(dict: HashMap, n: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_464_check_value.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "check_value", "test": "\n\nfn main() {\n let candidate = check_value;\n assert_eq!(candidate(HashMap::from([(String::from(\"Cierra Vega\"), 12), (String::from(\"Alden Cantrell\"), 12), (String::from(\"Kierra Gentry\"), 12), (String::from(\"Pierre Cox\"), 12)]), 10), false);\n assert_eq!(candidate(HashMap::from([(String::from(\"Cierra Vega\"), 12), (String::from(\"Alden Cantrell\"), 12), (String::from(\"Kierra Gentry\"), 12), (String::from(\"Pierre Cox\"), 12)]), 12), true);\n assert_eq!(candidate(HashMap::from([(String::from(\"Cierra Vega\"), 12), (String::from(\"Alden Cantrell\"), 12), (String::from(\"Kierra Gentry\"), 12), (String::from(\"Pierre Cox\"), 12)]), 5), false);\n}\n", "is_solved": true, "reflections": [], "solution": "use std::collections::HashMap;\n\n/// Write a function to check if all values are same in a HashMap.\nfn check_value(dict: HashMap, n: isize) -> bool {\n for value in dict.values() {\n if *value != n {\n return false;\n }\n }\n true\n}"} +{"name": "mbpp_443_largest_neg", "language": "rs", "prompt": "/// Write a rsthon function to find the largest negative number from the given vector.\nfn largest_neg(list1: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_443_largest_neg.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "largest_neg", "test": "\n\nfn main() {\n let candidate = largest_neg;\n assert_eq!(candidate(vec![1, 2, 3, -4, -6]), -6);\n assert_eq!(candidate(vec![1, 2, 3, -8, -9]), -9);\n assert_eq!(candidate(vec![1, 2, 3, 4, -1]), -1);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a rsthon function to find the largest negative number from the given vector.\nfn largest_neg(list1: Vec) -> isize {\n let mut largest_negative = isize::MIN;\n\n for num in list1 {\n if num < 0 && num > largest_negative {\n largest_negative = num;\n }\n }\n\n largest_negative\n}"} +{"name": "mbpp_602_first_repeated_char", "language": "rs", "prompt": "/// Write a rsthon function to find the first repeated character in a given string.\nfn first_repeated_char(str1: String) -> Option {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_602_first_repeated_char.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "first_repeated_char", "test": "\n\nfn main() {\n let candidate = first_repeated_char;\n assert_eq!(candidate(String::from(\"abcabc\")), Some(String::from(\"a\")));\n assert_eq!(candidate(String::from(\"abc\")), None);\n assert_eq!(candidate(String::from(\"123123\")), Some(String::from(\"1\")));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the first repeated character in a given string.\nfn first_repeated_char(str1: String) -> Option {\n let mut char_set = std::collections::HashSet::new();\n\n for c in str1.chars() {\n if char_set.contains(&c) {\n return Some(c.to_string());\n } else {\n char_set.insert(c);\n }\n }\n\n None\n}"} +{"name": "mbpp_770_odd_num_sum", "language": "rs", "prompt": "/// Write a rsthon function to find the sum of fourth power of first n odd natural numbers.\nfn odd_num_sum(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_770_odd_num_sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "odd_num_sum", "test": "\n\nfn main() {\n let candidate = odd_num_sum;\n assert_eq!(candidate(2), 82);\n assert_eq!(candidate(3), 707);\n assert_eq!(candidate(4), 3108);\n}\n", "solution": "/// Write a rsthon function to find the sum of fourth power of first n odd natural numbers.\nfn odd_num_sum(n: isize) -> isize {\n (1..=(2 * n)).filter(|x| x % 2 != 0).map(|x| x.pow(4)).sum()\n}", "is_solved": true, "reflections": ["The implementation is wrong because the numeric type of the variable `num` is ambiguous. The Rust compiler cannot determine the specific numeric type for `num` when calling the `pow` method. To fix this issue, a specific numeric type, such as `i32`, should be specified for the `num` variable.", "The initial implementation of the `odd_num_sum` function is incorrect because it does not properly calculate the sum of the fourth power of the first n odd natural numbers. The loop increments the `num` variable by 2, but it does not account for the fact that the first n odd numbers should be calculated using the formula (2 * x - 1). As a result, the function produces incorrect results for the given test cases.", "The implementation is incorrect because it calculates the sum of the fourth power of first n odd numbers using the formula (2 * x - 1).pow(4) as isize, which results in incorrect values for the sum. The correct implementation should use the formula (2 * x - 1).pow(4) without casting to isize.", "The implementation of the odd_num_sum function is incorrect because it calculates the sum of the fourth power of the first n odd numbers, but it does not account for the fact that the input n represents the number of odd numbers to sum, not the range of numbers to iterate through. As a result, the function is summing up fewer odd numbers than expected, leading to incorrect results in the failed tests."]} +{"name": "mbpp_424_extract_rear", "language": "rs", "prompt": "/// Write a function to extract only the rear index element of each string in the given tuple.\nfn extract_rear(test_tuple: (String, String, String)) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_424_extract_rear.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "extract_rear", "test": "\n\nfn main() {\n let candidate = extract_rear;\n assert_eq!(candidate((String::from(\"Mers\"), String::from(\"for\"), String::from(\"Vers\"))), vec![String::from(\"s\"), String::from(\"r\"), String::from(\"s\")]);\n assert_eq!(candidate((String::from(\"Avenge\"), String::from(\"for\"), String::from(\"People\"))), vec![String::from(\"e\"), String::from(\"r\"), String::from(\"e\")]);\n assert_eq!(candidate((String::from(\"Gotta\"), String::from(\"get\"), String::from(\"go\"))), vec![String::from(\"a\"), String::from(\"t\"), String::from(\"o\")]);\n}\n", "solution": "/// Write a function to extract only the rear index element of each string in the given tuple.\nfn extract_rear(test_tuple: (String, String, String)) -> Vec {\n let mut result = Vec::new();\n\n let (s1, s2, s3) = test_tuple;\n\n if let Some(last_char) = s1.chars().last() {\n result.push(last_char.to_string());\n }\n if let Some(last_char) = s2.chars().last() {\n result.push(last_char.to_string());\n }\n if let Some(last_char) = s3.chars().last() {\n result.push(last_char.to_string());\n }\n\n result\n}", "is_solved": true, "reflections": ["The implementation is wrong because it tries to use a tuple as an iterator in the for loop, but tuples do not implement the `Iterator` trait. This causes a compilation error. To fix this, the elements of the tuple should be accessed individually or converted into an iterable data structure like a slice or a vector."]} +{"name": "mbpp_133_sum_negativenum", "language": "rs", "prompt": "/// Write a function to calculate the sum of the negative numbers of a given vector of numbers.\nfn sum_negativenum(nums: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_133_sum_negativenum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sum_negativenum", "test": "\n\nfn main() {\n let candidate = sum_negativenum;\n assert_eq!(candidate(vec![2, 4, -6, -9, 11, -12, 14, -5, 17]), -32);\n assert_eq!(candidate(vec![10, 15, -14, 13, -18, 12, -20]), -52);\n assert_eq!(candidate(vec![19, -65, 57, 39, 152, -639, 121, 44, 90, -190]), -894);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to calculate the sum of the negative numbers of a given vector of numbers.\nfn sum_negativenum(nums: Vec) -> isize {\n let mut sum = 0;\n for num in nums {\n if num < 0 {\n sum += num;\n }\n }\n sum\n}"} +{"name": "mbpp_760_unique_Element", "language": "rs", "prompt": "/// Write a rsthon function to check whether a vector of numbers contains only one distinct element or not.\nfn unique_Element(arr: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_760_unique_Element.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "unique_Element", "test": "\n\nfn main() {\n let candidate = unique_Element;\n assert_eq!(candidate(vec![1, 1, 1]), true);\n assert_eq!(candidate(vec![1, 2, 1, 2]), false);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5]), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to check whether a vector of numbers contains only one distinct element or not.\nfn unique_Element(arr: Vec) -> bool {\n if arr.is_empty() {\n return false;\n }\n\n let first_element = arr[0];\n for element in arr {\n if element != first_element {\n return false;\n }\n }\n\n true\n}"} +{"name": "mbpp_281_all_unique", "language": "rs", "prompt": "/// Write a rsthon function to check if the elements of a given vector are unique or not.\nfn all_unique(test_list: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_281_all_unique.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "all_unique", "test": "\n\nfn main() {\n let candidate = all_unique;\n assert_eq!(candidate(vec![1, 2, 3]), true);\n assert_eq!(candidate(vec![1, 2, 1, 2]), false);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5]), true);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to check if the elements of a given vector are unique or not.\nfn all_unique(test_list: Vec) -> bool {\n let mut seen = std::collections::HashSet::new();\n\n for &item in test_list.iter() {\n if seen.contains(&item) {\n return false;\n } else {\n seen.insert(item);\n }\n }\n\n true\n}"} +{"name": "mbpp_406_find_Parity", "language": "rs", "prompt": "/// Write a rsthon function to find whether the parity of a given number is odd.\nfn find_Parity(x: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_406_find_Parity.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_Parity", "test": "\n\nfn main() {\n let candidate = find_Parity;\n assert_eq!(candidate(12), false);\n assert_eq!(candidate(7), true);\n assert_eq!(candidate(10), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find whether the parity of a given number is odd.\nfn find_Parity(x: isize) -> bool {\n if x % 2 == 0 {\n return false;\n } else {\n return true;\n }\n}"} +{"name": "mbpp_562_Find_Max_Length", "language": "rs", "prompt": "/// Write a rsthon function to find the length of the longest subvectors.\nfn Find_Max_Length(lst: Vec>) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_562_Find_Max_Length.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "Find_Max_Length", "test": "\n\nfn main() {\n let candidate = Find_Max_Length;\n assert_eq!(candidate(vec![vec![1], vec![1, 4], vec![5, 6, 7, 8]]), 4);\n assert_eq!(candidate(vec![vec![0, 1], vec![2, 2], vec![3, 2, 1]]), 3);\n assert_eq!(candidate(vec![vec![7], vec![22, 23], vec![13, 14, 15], vec![10, 20, 30, 40, 50]]), 5);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the length of the longest subvectors.\nfn Find_Max_Length(lst: Vec>) -> isize {\n let mut max_length = 0;\n\n for subvector in lst {\n let length = subvector.len();\n if length > max_length {\n max_length = length;\n }\n }\n\n max_length as isize\n}"} +{"name": "mbpp_87_merge_dictionaries_three", "language": "rs", "prompt": "use std::collections::HashMap;\n\n/// Write a function to merge three dictionaries into a single HashMap.\nfn merge_dictionaries_three(dict1: HashMap, dict2: HashMap, dict3: HashMap) -> HashMap {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_87_merge_dictionaries_three.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "merge_dictionaries_three", "test": "\n\nfn main() {\n let candidate = merge_dictionaries_three;\n assert_eq!(candidate(HashMap::from([(String::from(\"R\"), String::from(\"Red\")), (String::from(\"B\"), String::from(\"Black\")), (String::from(\"P\"), String::from(\"Pink\"))]), HashMap::from([(String::from(\"G\"), String::from(\"Green\")), (String::from(\"W\"), String::from(\"White\"))]), HashMap::from([(String::from(\"O\"), String::from(\"Orange\")), (String::from(\"W\"), String::from(\"White\")), (String::from(\"B\"), String::from(\"Black\"))])), HashMap::from([(String::from(\"B\"), String::from(\"Black\")), (String::from(\"R\"), String::from(\"Red\")), (String::from(\"P\"), String::from(\"Pink\")), (String::from(\"G\"), String::from(\"Green\")), (String::from(\"W\"), String::from(\"White\")), (String::from(\"O\"), String::from(\"Orange\"))]));\n assert_eq!(candidate(HashMap::from([(String::from(\"R\"), String::from(\"Red\")), (String::from(\"B\"), String::from(\"Black\")), (String::from(\"P\"), String::from(\"Pink\"))]), HashMap::from([(String::from(\"G\"), String::from(\"Green\")), (String::from(\"W\"), String::from(\"White\"))]), HashMap::from([(String::from(\"L\"), String::from(\"lavender\")), (String::from(\"B\"), String::from(\"Blue\"))])), HashMap::from([(String::from(\"W\"), String::from(\"White\")), (String::from(\"P\"), String::from(\"Pink\")), (String::from(\"B\"), String::from(\"Black\")), (String::from(\"R\"), String::from(\"Red\")), (String::from(\"G\"), String::from(\"Green\")), (String::from(\"L\"), String::from(\"lavender\"))]));\n assert_eq!(candidate(HashMap::from([(String::from(\"R\"), String::from(\"Red\")), (String::from(\"B\"), String::from(\"Black\")), (String::from(\"P\"), String::from(\"Pink\"))]), HashMap::from([(String::from(\"L\"), String::from(\"lavender\")), (String::from(\"B\"), String::from(\"Blue\"))]), HashMap::from([(String::from(\"G\"), String::from(\"Green\")), (String::from(\"W\"), String::from(\"White\"))])), HashMap::from([(String::from(\"B\"), String::from(\"Black\")), (String::from(\"P\"), String::from(\"Pink\")), (String::from(\"R\"), String::from(\"Red\")), (String::from(\"G\"), String::from(\"Green\")), (String::from(\"L\"), String::from(\"lavender\")), (String::from(\"W\"), String::from(\"White\"))]));\n}\n", "is_solved": false, "reflections": [], "solution": "use std::collections::HashMap;\n\n/// Write a function to merge three dictionaries into a single HashMap.\nfn merge_dictionaries_three(dict1: HashMap, dict2: HashMap, dict3: HashMap) -> HashMap {\n let mut result = HashMap::new();\n\n for (key, value) in dict1 {\n result.insert(key, value);\n }\n\n for (key, value) in dict2 {\n result.insert(key, value);\n }\n\n for (key, value) in dict3 {\n result.insert(key, value);\n }\n\n result\n}"} +{"name": "mbpp_11_remove_Occ", "language": "rs", "prompt": "/// Write a rsthon function to remove first and last occurrence of a given character from the string.\nfn remove_Occ(s: String, ch: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_11_remove_Occ.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "remove_Occ", "test": "\n\nfn main() {\n let candidate = remove_Occ;\n assert_eq!(candidate(String::from(\"hello\"), String::from(\"l\")), String::from(\"heo\"));\n assert_eq!(candidate(String::from(\"abcda\"), String::from(\"a\")), String::from(\"bcd\"));\n assert_eq!(candidate(String::from(\"PHP\"), String::from(\"P\")), String::from(\"H\"));\n}\n", "solution": "/// Write a rsthon function to remove first and last occurrence of a given character from the string.\nfn remove_Occ(s: String, ch: String) -> String {\n let first_occurrence = s.find(&ch);\n let last_occurrence = s.rfind(&ch);\n\n if let (Some(first), Some(last)) = (first_occurrence, last_occurrence) {\n let mut chars: Vec = s.chars().collect();\n chars.remove(first);\n if first != last {\n chars.remove(last - 1);\n }\n return chars.into_iter().collect();\n }\n\n s\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it does not properly handle the removal of the last occurrence when it is not the same as the first occurrence. When removing the last occurrence, the index is not adjusted to account for the removal of the first occurrence, causing the wrong character to be removed in some cases. This leads to the failed test cases where the expected output does not match the actual output.", "The implementation is incorrect because it removes the character at the index `last - 1 - (if first < last { 1 } else { 0 })` instead of simply removing the character at the index `last`. This causes the function to remove the wrong character when the last occurrence of the given character is not at the end of the string.", "The implementation is incorrect because it does not properly handle the removal of the last occurrence when it is not the same as the first occurrence. When removing the first occurrence, the indices of the characters after it shift by one, so when removing the last occurrence, the function should remove the character at the index `last - 1`. However, this logic is incorrect as it causes the removal of the character before the last occurrence instead of the last occurrence itself.", "The implementation is incorrect because it does not properly handle the removal of the last occurrence when it comes after the first occurrence. The code subtracts 1 from the last occurrence index, which causes it to remove the character before the actual last occurrence. Additionally, the conditional subtraction of 1 when first < last is unnecessary and contributes to the error."]} +{"name": "mbpp_751_check_min_heap", "language": "rs", "prompt": "/// Write a function to check if the given vector represents min heap or not. https://www.geeksforgeeks.org/how-to-check-if-a-given-vector-represents-a-binary-heap/\nfn check_min_heap(arr: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_751_check_min_heap.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "check_min_heap", "test": "\n\nfn main() {\n let candidate = check_min_heap;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6]), true);\n assert_eq!(candidate(vec![2, 3, 4, 5, 10, 15]), true);\n assert_eq!(candidate(vec![2, 10, 4, 5, 3, 15]), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check if the given vector represents min heap or not. https://www.geeksforgeeks.org/how-to-check-if-a-given-vector-represents-a-binary-heap/\nfn check_min_heap(arr: Vec) -> bool {\n let n = arr.len();\n\n for i in 0..n / 2 {\n let left_child = 2 * i + 1;\n let right_child = 2 * i + 2;\n\n if left_child < n && arr[i] > arr[left_child] {\n return false;\n }\n\n if right_child < n && arr[i] > arr[right_child] {\n return false;\n }\n }\n\n true\n}"} +{"name": "mbpp_578_interleave_lists", "language": "rs", "prompt": "/// Write a function to interleave 3 vectors of the same length into a single flat vector.\nfn interleave_lists(list1: Vec, list2: Vec, list3: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_578_interleave_lists.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "interleave_lists", "test": "\n\nfn main() {\n let candidate = interleave_lists;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7], vec![10, 20, 30, 40, 50, 60, 70], vec![100, 200, 300, 400, 500, 600, 700]), vec![1, 10, 100, 2, 20, 200, 3, 30, 300, 4, 40, 400, 5, 50, 500, 6, 60, 600, 7, 70, 700]);\n assert_eq!(candidate(vec![10, 20], vec![15, 2], vec![5, 10]), vec![10, 15, 5, 20, 2, 10]);\n assert_eq!(candidate(vec![11, 44], vec![10, 15], vec![20, 5]), vec![11, 10, 20, 44, 15, 5]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to interleave 3 vectors of the same length into a single flat vector.\nfn interleave_lists(list1: Vec, list2: Vec, list3: Vec) -> Vec {\n let mut result = Vec::new();\n let len = list1.len();\n\n for i in 0..len {\n result.push(list1[i]);\n result.push(list2[i]);\n result.push(list3[i]);\n }\n\n result\n}"} +{"name": "mbpp_90_len_log", "language": "rs", "prompt": "/// Write a rsthon function to find the length of the longest word.\nfn len_log(list1: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_90_len_log.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "len_log", "test": "\n\nfn main() {\n let candidate = len_log;\n assert_eq!(candidate(vec![String::from(\"python\"), String::from(\"PHP\"), String::from(\"bigdata\")]), 7);\n assert_eq!(candidate(vec![String::from(\"a\"), String::from(\"ab\"), String::from(\"abc\")]), 3);\n assert_eq!(candidate(vec![String::from(\"small\"), String::from(\"big\"), String::from(\"tall\")]), 5);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the length of the longest word.\nfn len_log(list1: Vec) -> isize {\n let mut max_len = 0;\n\n for word in list1 {\n if word.len() > max_len {\n max_len = word.len();\n }\n }\n\n max_len as isize\n}"} +{"name": "mbpp_452_loss_amount", "language": "rs", "prompt": "/// Write a function that gives loss amount on a sale if the given amount has loss else return 0.\nfn loss_amount(actual_cost: isize, sale_amount: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_452_loss_amount.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "loss_amount", "test": "\n\nfn main() {\n let candidate = loss_amount;\n assert_eq!(candidate(1500, 1200), 0);\n assert_eq!(candidate(100, 200), 100);\n assert_eq!(candidate(2000, 5000), 3000);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a function that gives loss amount on a sale if the given amount has loss else return 0.\nfn loss_amount(actual_cost: isize, sale_amount: isize) -> isize {\n if actual_cost > sale_amount {\n return actual_cost - sale_amount;\n } else {\n return 0;\n }\n}"} +{"name": "mbpp_798__sum", "language": "rs", "prompt": "/// Write a rsthon function to find the sum of a vector.\nfn _sum(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_798__sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "_sum", "test": "\n\nfn main() {\n let candidate = _sum;\n assert_eq!(candidate(vec![1, 2, 3]), 6);\n assert_eq!(candidate(vec![15, 12, 13, 10]), 50);\n assert_eq!(candidate(vec![0, 1, 2]), 3);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the sum of a vector.\nfn _sum(arr: Vec) -> isize {\n let mut total: isize = 0;\n for num in arr {\n total += num;\n }\n total\n}"} +{"name": "mbpp_393_max_length_list", "language": "rs", "prompt": "/// Write a function to find the vector with maximum length.\nfn max_length_list(input_list: Vec>) -> (isize, Vec) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_393_max_length_list.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_length_list", "test": "\n\nfn main() {\n let candidate = max_length_list;\n assert_eq!(candidate(vec![vec![0], vec![1, 3], vec![5, 7], vec![9, 11], vec![13, 15, 17]]), (3, vec![13, 15, 17]));\n assert_eq!(candidate(vec![vec![1, 2, 3, 4, 5], vec![1, 2, 3, 4], vec![1, 2, 3], vec![1, 2], vec![1]]), (5, vec![1, 2, 3, 4, 5]));\n assert_eq!(candidate(vec![vec![3, 4, 5], vec![6, 7, 8, 9], vec![10, 11, 12]]), (4, vec![6, 7, 8, 9]));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the vector with maximum length.\nfn max_length_list(input_list: Vec>) -> (isize, Vec) {\n let mut max_length = 0;\n let mut max_vector = Vec::new();\n\n for vector in input_list {\n let length = vector.len() as isize;\n if length > max_length {\n max_length = length;\n max_vector = vector;\n }\n }\n\n (max_length, max_vector)\n}"} +{"name": "mbpp_272_rear_extract", "language": "rs", "prompt": "/// Write a function that takes in a vector of tuples and returns a vector containing the rear element of each tuple.\nfn rear_extract(test_list: Vec<(isize, String, isize)>) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_272_rear_extract.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "rear_extract", "test": "\n\nfn main() {\n let candidate = rear_extract;\n assert_eq!(candidate(vec![(1, String::from(\"Rash\"), 21), (2, String::from(\"Varsha\"), 20), (3, String::from(\"Kil\"), 19)]), vec![21, 20, 19]);\n assert_eq!(candidate(vec![(1, String::from(\"Sai\"), 36), (2, String::from(\"Ayesha\"), 25), (3, String::from(\"Salman\"), 45)]), vec![36, 25, 45]);\n assert_eq!(candidate(vec![(1, String::from(\"Sudeep\"), 14), (2, String::from(\"Vandana\"), 36), (3, String::from(\"Dawood\"), 56)]), vec![14, 36, 56]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function that takes in a vector of tuples and returns a vector containing the rear element of each tuple.\nfn rear_extract(test_list: Vec<(isize, String, isize)>) -> Vec {\n let mut result = Vec::new();\n\n for tuple in test_list {\n result.push(tuple.2);\n }\n\n result\n}"} +{"name": "mbpp_564_count_Pairs", "language": "rs", "prompt": "/// Write a rsthon function which takes a vector of integers and counts the number of possible unordered pairs where both elements are unequal.\nfn count_Pairs(arr: Vec, n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_564_count_Pairs.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_Pairs", "test": "\n\nfn main() {\n let candidate = count_Pairs;\n assert_eq!(candidate(vec![1, 2, 1], 3), 2);\n assert_eq!(candidate(vec![1, 1, 1, 1], 4), 0);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5], 5), 10);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function which takes a vector of integers and counts the number of possible unordered pairs where both elements are unequal.\nfn count_Pairs(arr: Vec, n: isize) -> isize {\n let mut count = 0;\n\n for i in 0..n {\n for j in i + 1..n {\n if arr[i as usize] != arr[j as usize] {\n count += 1;\n }\n }\n }\n\n count\n}"} +{"name": "mbpp_438_count_bidirectional", "language": "rs", "prompt": "/// Write a function to count bidirectional tuple pairs.\nfn count_bidirectional(test_list: Vec<(isize, isize)>) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_438_count_bidirectional.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_bidirectional", "test": "\n\nfn main() {\n let candidate = count_bidirectional;\n assert_eq!(candidate(vec![(5, 6), (1, 2), (6, 5), (9, 1), (6, 5), (2, 1)]), 3);\n assert_eq!(candidate(vec![(5, 6), (1, 3), (6, 5), (9, 1), (6, 5), (2, 1)]), 2);\n assert_eq!(candidate(vec![(5, 6), (1, 2), (6, 5), (9, 2), (6, 5), (2, 1)]), 4);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a function to count bidirectional tuple pairs.\nfn count_bidirectional(test_list: Vec<(isize, isize)>) -> isize {\n let mut count = 0;\n let mut checked_pairs = Vec::new();\n\n for pair in &test_list {\n if !checked_pairs.contains(pair) {\n let reverse_pair = (pair.1, pair.0);\n if test_list.contains(&reverse_pair) {\n count += 1;\n checked_pairs.push(*pair);\n checked_pairs.push(reverse_pair);\n }\n }\n }\n\n count\n}"} +{"name": "mbpp_640_remove_parenthesis", "language": "rs", "prompt": "/// Write a function to remove the parenthesis and what is inbetween them from a string.\nfn remove_parenthesis(items: Vec) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_640_remove_parenthesis.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "remove_parenthesis", "test": "\n\nfn main() {\n let candidate = remove_parenthesis;\n assert_eq!(candidate(vec![String::from(\"python (chrome)\")]), String::from(\"python\"));\n assert_eq!(candidate(vec![String::from(\"string(.abc)\")]), String::from(\"string\"));\n assert_eq!(candidate(vec![String::from(\"alpha(num)\")]), String::from(\"alpha\"));\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a function to remove the parenthesis and what is inbetween them from a string.\nfn remove_parenthesis(items: Vec) -> String {\n let mut result = String::new();\n let mut open_parenthesis = 0;\n\n for item in items {\n for ch in item.chars() {\n if ch == '(' {\n open_parenthesis += 1;\n } else if ch == ')' {\n if open_parenthesis > 0 {\n open_parenthesis -= 1;\n } else {\n result.push(ch);\n }\n } else if open_parenthesis == 0 {\n result.push(ch);\n }\n }\n }\n\n result\n}"} +{"name": "mbpp_72_dif_Square", "language": "rs", "prompt": "/// Write a rsthon function to check whether the given number can be represented as the difference of two squares or not.\nfn dif_Square(n: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_72_dif_Square.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "dif_Square", "test": "\n\nfn main() {\n let candidate = dif_Square;\n assert_eq!(candidate(5), true);\n assert_eq!(candidate(10), false);\n assert_eq!(candidate(15), true);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a rsthon function to check whether the given number can be represented as the difference of two squares or not.\nfn dif_Square(n: isize) -> bool {\n for i in 1..=((n as f64).sqrt() as isize) {\n let j = n - i * i;\n let j_sqrt = (j as f64).sqrt() as isize;\n\n if j_sqrt * j_sqrt == j {\n return true;\n }\n }\n false\n}"} +{"name": "mbpp_448_cal_sum", "language": "rs", "prompt": "/// Write a function to calculate the sum of perrin numbers.\nfn cal_sum(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_448_cal_sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "cal_sum", "test": "\n\nfn main() {\n let candidate = cal_sum;\n assert_eq!(candidate(9), 49);\n assert_eq!(candidate(10), 66);\n assert_eq!(candidate(11), 88);\n}\n", "is_solved": false, "reflections": ["The implementation of the cal_sum function is incorrect because it starts summing the perrin numbers from the wrong index. The loop should start from index 1 instead of 3, and the initial sum should be set to 0. This causes the function to miss some perrin numbers in the sum, leading to incorrect results in the failed tests.", "The implementation of the cal_sum function is incorrect because it does not follow the correct formula for calculating Perrin numbers. The function calculates the sum of a sequence of numbers, but it does not use the correct formula for generating the Perrin sequence (P(n) = P(n-2) + P(n-3)). As a result, the function produces incorrect sums for the given test cases.", "The implementation of the cal_sum function is incorrect because it starts the Perrin sequence with the wrong initial values. The correct initial values should be 3, 0, 2, but the function starts with 3, 0, 2, 5, which causes the sum to be calculated incorrectly. This leads to the failed test cases, as the function does not produce the expected results for the given inputs.", "The implementation of the cal_sum function is incorrect because it starts the Perrin sequence with the wrong initial values. The correct initial values should be a = 3, b = 0, and c = 2, but the function starts with a = 3, b = 0, and c = 2. This causes the sum to be calculated incorrectly, leading to the failed test cases."], "solution": "/// Write a function to calculate the sum of perrin numbers.\nfn cal_sum(n: isize) -> isize {\n if n <= 0 {\n return 0;\n }\n\n let mut a = 3;\n let mut b = 0;\n let mut c = 2;\n let mut sum = a + b + c;\n\n for i in 4..=n {\n let temp = a + b;\n a = b;\n b = c;\n c = temp;\n sum += c;\n }\n\n sum\n}"} +{"name": "mbpp_96_divisor", "language": "rs", "prompt": "/// Write a rsthon function to find the number of divisors of a given integer.\nfn divisor(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_96_divisor.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "divisor", "test": "\n\nfn main() {\n let candidate = divisor;\n assert_eq!(candidate(15), 4);\n assert_eq!(candidate(12), 6);\n assert_eq!(candidate(9), 3);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the number of divisors of a given integer.\nfn divisor(n: isize) -> isize {\n let mut count = 0;\n\n for i in 1..=n {\n if n % i == 0 {\n count += 1;\n }\n }\n\n count\n}"} +{"name": "mbpp_296_get_Inv_Count", "language": "rs", "prompt": "/// Write a rsthon function to count inversions in a vector.\nfn get_Inv_Count(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_296_get_Inv_Count.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "get_Inv_Count", "test": "\n\nfn main() {\n let candidate = get_Inv_Count;\n assert_eq!(candidate(vec![1, 20, 6, 4, 5]), 5);\n assert_eq!(candidate(vec![1, 2, 1]), 1);\n assert_eq!(candidate(vec![1, 2, 5, 6, 1]), 3);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to count inversions in a vector.\nfn get_Inv_Count(arr: Vec) -> isize {\n let mut inv_count = 0;\n let n = arr.len();\n\n for i in 0..n {\n for j in i + 1..n {\n if arr[i] > arr[j] {\n inv_count += 1;\n }\n }\n }\n\n inv_count\n}"} +{"name": "mbpp_57_find_Max_Num", "language": "rs", "prompt": "/// Write a rsthon function to find the largest number that can be formed with the given vector of digits.\nfn find_Max_Num(arr: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_57_find_Max_Num.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_Max_Num", "test": "\n\nfn main() {\n let candidate = find_Max_Num;\n assert_eq!(candidate(vec![1, 2, 3]), 321);\n assert_eq!(candidate(vec![4, 5, 6, 1]), 6541);\n assert_eq!(candidate(vec![1, 2, 3, 9]), 9321);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the largest number that can be formed with the given vector of digits.\nfn find_Max_Num(arr: Vec) -> isize {\n let mut arr_str: Vec = arr.into_iter().map(|x| x.to_string()).collect();\n arr_str.sort_by(|a, b| (b.clone() + a).cmp(&(a.clone() + b)));\n\n let max_num: String = arr_str.into_iter().collect();\n max_num.parse::().unwrap()\n}"} +{"name": "mbpp_614_cummulative_sum", "language": "rs", "prompt": "/// Write a function to find the cumulative sum of all the values that are present in the given vector of vectors.\nfn cummulative_sum(test_list: Vec>) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_614_cummulative_sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "cummulative_sum", "test": "\n\nfn main() {\n let candidate = cummulative_sum;\n assert_eq!(candidate(vec![vec![1, 3], vec![5, 6, 7], vec![2, 6]]), 30);\n assert_eq!(candidate(vec![vec![2, 4], vec![6, 7, 8], vec![3, 7]]), 37);\n assert_eq!(candidate(vec![vec![3, 5], vec![7, 8, 9], vec![4, 8]]), 44);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the cumulative sum of all the values that are present in the given vector of vectors.\nfn cummulative_sum(test_list: Vec>) -> isize {\n let mut total_sum = 0;\n for inner_list in test_list {\n for value in inner_list {\n total_sum += value;\n }\n }\n total_sum\n}"} +{"name": "mbpp_623_nth_nums", "language": "rs", "prompt": "/// Write a function to compute the n-th power of each number in a vector.\nfn nth_nums(nums: Vec, n: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_623_nth_nums.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "nth_nums", "test": "\n\nfn main() {\n let candidate = nth_nums;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 10], 2), vec![1, 4, 9, 16, 25, 36, 49, 64, 81, 100]);\n assert_eq!(candidate(vec![10, 20, 30], 3), vec![1000, 8000, 27000]);\n assert_eq!(candidate(vec![12, 15], 5), vec![248832, 759375]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to compute the n-th power of each number in a vector.\nfn nth_nums(nums: Vec, n: isize) -> Vec {\n nums.into_iter().map(|num| num.pow(n as u32)).collect()\n}"} +{"name": "mbpp_799_left_rotate", "language": "rs", "prompt": "/// Write a function to that rotate left bits by d bits a given number. We assume that the number is 32 bit.\nfn left_rotate(n: isize, d: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_799_left_rotate.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "left_rotate", "test": "\n\nfn main() {\n let candidate = left_rotate;\n assert_eq!(candidate(16, 2), 64);\n assert_eq!(candidate(10, 2), 40);\n assert_eq!(candidate(99, 3), 792);\n assert_eq!(candidate(99, 3), 792);\n assert_eq!(candidate(1, 3), 8);\n assert_eq!(candidate(5, 3), 40);\n assert_eq!(candidate(29, 3), 232);\n}\n", "solution": "/// Write a function to that rotate left bits by d bits a given number. We assume that the number is 32 bit.\nfn left_rotate(n: isize, d: isize) -> isize {\n let d = d % 32;\n let left_shift = (n << d) as u32;\n let right_shift = (n as u32) >> (32 - d);\n ((left_shift | right_shift) as isize)\n}", "is_solved": true, "reflections": ["The implementation of the left_rotate function is incorrect because it uses arithmetic right shift (>>) instead of logical right shift (>>>). This causes sign extension, which leads to incorrect results when rotating negative numbers or numbers with the most significant bit set.", "The implementation of the left_rotate function is incorrect because it does not properly handle the case when the bits being rotated cross the boundary between the most significant bit and the least significant bit. This causes the function to produce incorrect results when rotating bits that are close to the boundary, as demonstrated by the failed test cases.", "The implementation of the left_rotate function is incorrect because it does not properly handle the case when the left shift causes the bits to wrap around. The mask used to limit the result to 32 bits is causing the loss of the wrapped bits, leading to incorrect results in the failed test cases.", "The implementation of the left_rotate function is incorrect because it is casting the left_shift and right_shift values to u32 and isize types, respectively, before performing the bitwise OR operation. This causes the final result to be incorrect when the leftmost bits are shifted and should wrap around to the right side of the number. The casting should be done after the bitwise OR operation to ensure the correct result."]} +{"name": "mbpp_247_lps", "language": "rs", "prompt": "/// Write a function to find the length of the longest palindromic subsequence in the given string.\nfn lps(str: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_247_lps.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "lps", "test": "\n\nfn main() {\n let candidate = lps;\n assert_eq!(candidate(String::from(\"TENS FOR TENS\")), 5);\n assert_eq!(candidate(String::from(\"CARDIO FOR CARDS\")), 7);\n assert_eq!(candidate(String::from(\"PART OF THE JOURNEY IS PART\")), 9);\n}\n", "solution": "/// Write a function to find the length of the longest palindromic subsequence in the given string.\nfn lps(str: String) -> isize {\n if str.is_empty() {\n return 0;\n }\n\n let n = str.len();\n let chars: Vec = str.chars().collect();\n let mut dp = vec![vec![0; n]; n];\n\n for i in 0..n {\n dp[i][i] = 1;\n }\n\n for len in 2..=n {\n for i in 0..n - len + 1 {\n let j = i + len - 1;\n if chars[i] == chars[j] {\n dp[i][j] = dp[i + 1][j - 1] + 2;\n } else {\n dp[i][j] = isize::max(dp[i + 1][j], dp[i][j - 1]);\n }\n }\n }\n\n dp[0][n - 1]\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it does not handle the case when the input string is empty. The code tries to access an element in the `dp` array with an index of 0 when the length of the array is also 0, causing an \"index out of bounds\" error."]} +{"name": "mbpp_735_toggle_middle_bits", "language": "rs", "prompt": "/// Write a rsthon function to toggle bits of the number except the first and the last bit. https://www.geeksforgeeks.org/toggle-bits-number-expect-first-last-bits/\nfn toggle_middle_bits(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_735_toggle_middle_bits.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "toggle_middle_bits", "test": "\n\nfn main() {\n let candidate = toggle_middle_bits;\n assert_eq!(candidate(9), 15);\n assert_eq!(candidate(10), 12);\n assert_eq!(candidate(11), 13);\n assert_eq!(candidate(65), 127);\n assert_eq!(candidate(77), 115);\n}\n", "solution": "/// Write a rsthon function to toggle bits of the number except the first and the last bit. https://www.geeksforgeeks.org/toggle-bits-number-expect-first-last-bits/\nfn toggle_middle_bits(n: isize) -> isize {\n if n <= 3 {\n return n;\n }\n\n let mut result = n;\n let mut position = 1;\n\n while (1 << (position + 1)) <= n {\n result ^= 1 << position;\n position += 1;\n }\n\n result\n}", "is_solved": true, "reflections": ["The implementation of the toggle_middle_bits function is incorrect because it toggles all bits except the first and the last bit, but it also modifies the last bit in the process. The code first toggles all bits, then tries to restore the last bit to its original state, but this approach is flawed and leads to incorrect results for some test cases, such as when n is 7 or 5.", "The implementation of the toggle_middle_bits function is incorrect because it toggles the bits of the number starting from the second bit until the condition (1 << (position + 1)) is less than the input number 'n'. This causes the last bit to be skipped, and the function does not toggle the bits as expected. The failed tests indicate that the function is not properly toggling the middle bits while preserving the first and last bits.", "The implementation of the toggle_middle_bits function is incorrect because it toggles the bits of the number except the first and the last bit, but it does not properly handle the edge cases when the number has only two bits or less. The while loop condition should be modified to ensure that the position does not exceed the second to last bit, and the function should return the original number if it has two bits or less.", "The implementation of the toggle_middle_bits function is incorrect because it is toggling the bits in the wrong positions. The while loop condition checks if the shifted value is less than the input number, causing it to skip the last bit that should be toggled. Additionally, the function does not handle cases where the input number has more than two bits correctly, leading to incorrect results for numbers like 5 and 7."]} +{"name": "mbpp_132_tup_string", "language": "rs", "prompt": "/// Write a function to convert a vector to a string.\nfn tup_string(tup1: Vec) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_132_tup_string.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "tup_string", "test": "\n\nfn main() {\n let candidate = tup_string;\n assert_eq!(candidate(vec![String::from(\"e\"), String::from(\"x\"), String::from(\"e\"), String::from(\"r\"), String::from(\"c\"), String::from(\"i\"), String::from(\"s\"), String::from(\"e\"), String::from(\"s\")]), String::from(\"exercises\"));\n assert_eq!(candidate(vec![String::from(\"p\"), String::from(\"y\"), String::from(\"t\"), String::from(\"h\"), String::from(\"o\"), String::from(\"n\")]), String::from(\"python\"));\n assert_eq!(candidate(vec![String::from(\"p\"), String::from(\"r\"), String::from(\"o\"), String::from(\"g\"), String::from(\"r\"), String::from(\"a\"), String::from(\"m\")]), String::from(\"program\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to convert a vector to a string.\nfn tup_string(tup1: Vec) -> String {\n let mut result = String::new();\n for s in tup1 {\n result.push_str(&s);\n }\n result\n}"} +{"name": "mbpp_460_Extract", "language": "rs", "prompt": "/// Write a rsthon function to get the first element of each subvector.\nfn Extract(lst: Vec>) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_460_Extract.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "Extract", "test": "\n\nfn main() {\n let candidate = Extract;\n assert_eq!(candidate(vec![vec![1, 2], vec![3, 4, 5], vec![6, 7, 8, 9]]), vec![1, 3, 6]);\n assert_eq!(candidate(vec![vec![1, 2, 3], vec![4, 5]]), vec![1, 4]);\n assert_eq!(candidate(vec![vec![9, 8, 1], vec![1, 2]]), vec![9, 1]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to get the first element of each subvector.\nfn Extract(lst: Vec>) -> Vec {\n let mut result: Vec = Vec::new();\n\n for subvector in lst {\n if !subvector.is_empty() {\n result.push(subvector[0]);\n }\n }\n\n result\n}"} +{"name": "mbpp_606_radian_degree", "language": "rs", "prompt": "/// Write a function to convert degrees to radians.\nfn radian_degree(degree: isize) -> f64 {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_606_radian_degree.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "radian_degree", "test": "\n\nfn main() {\n let candidate = radian_degree;\n assert_eq!(candidate(90), 1.5707963267948966);\n assert_eq!(candidate(60), 1.0471975511965976);\n assert_eq!(candidate(120), 2.0943951023931953);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to convert degrees to radians.\nfn radian_degree(degree: isize) -> f64 {\n let radians = (degree as f64) * std::f64::consts::PI / 180.0;\n radians\n}"} +{"name": "mbpp_167_next_power_of_2", "language": "rs", "prompt": "/// Write a rsthon function to find the smallest power of 2 greater than or equal to n.\nfn next_power_of_2(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_167_next_power_of_2.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "next_power_of_2", "test": "\n\nfn main() {\n let candidate = next_power_of_2;\n assert_eq!(candidate(0), 1);\n assert_eq!(candidate(5), 8);\n assert_eq!(candidate(17), 32);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the smallest power of 2 greater than or equal to n.\nfn next_power_of_2(n: isize) -> isize {\n let mut power = 1;\n while power < n {\n power *= 2;\n }\n power\n}"} +{"name": "mbpp_756_text_match_zero_one", "language": "rs", "prompt": "/// Write a function that matches a string that has an 'a' followed by one or more 'b's. https://www.w3resource.com/rsthon-exercises/re/rsthon-re-exercise-3.php\nfn text_match_zero_one(text: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_756_text_match_zero_one.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "text_match_zero_one", "test": "\n\nfn main() {\n let candidate = text_match_zero_one;\n assert_eq!(candidate(String::from(\"ac\")), false);\n assert_eq!(candidate(String::from(\"dc\")), false);\n assert_eq!(candidate(String::from(\"abbbba\")), true);\n assert_eq!(candidate(String::from(\"dsabbbba\")), true);\n assert_eq!(candidate(String::from(\"asbbbba\")), false);\n assert_eq!(candidate(String::from(\"abaaa\")), true);\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because the `regex` crate is not declared or imported, causing the compiler to throw an error. To fix this issue, the `regex` crate needs to be added to the dependencies in Cargo.toml and imported using `use regex::Regex;` at the beginning of the code.", "The implementation is incorrect because the `regex` crate is not declared in the dependencies, causing an unresolved import error. To fix this, the `regex` crate should be added to the Cargo.toml file under the dependencies section.", "The implementation is incorrect because the `regex` crate is not declared in the dependencies, causing an unresolved import error. To fix this, the `regex` crate should be added to the `Cargo.toml` file under the `[dependencies]` section.", "The implementation is incorrect because the `regex` crate is not declared in the dependencies, causing an unresolved import error. To fix this issue, the `regex` crate should be added to the project's `Cargo.toml` file under the `[dependencies]` section."], "solution": "/// Write a function that matches a string that has an 'a' followed by one or more 'b's. https://www.w3resource.com/rsthon-exercises/re/rsthon-re-exercise-3.php\nfn text_match_zero_one(text: String) -> bool {\n use regex::Regex;\n let re = Regex::new(r\"a+b+\").unwrap();\n re.is_match(&text)\n}"} +{"name": "mbpp_633_pair_xor_Sum", "language": "rs", "prompt": "/// Write a rsthon function to find the sum of xor of all pairs of numbers in the given vector.\nfn pair_xor_Sum(arr: Vec, n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_633_pair_xor_Sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "pair_xor_Sum", "test": "\n\nfn main() {\n let candidate = pair_xor_Sum;\n assert_eq!(candidate(vec![5, 9, 7, 6], 4), 47);\n assert_eq!(candidate(vec![7, 3, 5], 3), 12);\n assert_eq!(candidate(vec![7, 3], 2), 4);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the sum of xor of all pairs of numbers in the given vector.\nfn pair_xor_Sum(arr: Vec, n: isize) -> isize {\n let mut xor_sum = 0;\n\n for i in 0..n {\n for j in i+1..n {\n xor_sum += arr[i as usize] ^ arr[j as usize];\n }\n }\n\n xor_sum\n}"} +{"name": "mbpp_458_rectangle_area", "language": "rs", "prompt": "/// Write a function to find the area of a rectangle.\nfn rectangle_area(l: isize, b: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_458_rectangle_area.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "rectangle_area", "test": "\n\nfn main() {\n let candidate = rectangle_area;\n assert_eq!(candidate(10, 20), 200);\n assert_eq!(candidate(10, 5), 50);\n assert_eq!(candidate(4, 2), 8);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the area of a rectangle.\nfn rectangle_area(l: isize, b: isize) -> isize {\n let area = l * b;\n area\n}"} +{"name": "mbpp_738_geometric_sum", "language": "rs", "prompt": "/// Write a function to calculate the geometric sum of n-1. https://www.w3resource.com/rsthon-exercises/data-structures-and-algorithms/rsthon-recursion-exercise-9.php\nfn geometric_sum(n: isize) -> f64 {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_738_geometric_sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "geometric_sum", "test": "\n\nfn main() {\n let candidate = geometric_sum;\n assert_eq!(candidate(7), 1.9921875);\n assert_eq!(candidate(4), 1.9375);\n assert_eq!(candidate(8), 1.99609375);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a function to calculate the geometric sum of n-1. https://www.w3resource.com/rsthon-exercises/data-structures-and-algorithms/rsthon-recursion-exercise-9.php\nfn geometric_sum(n: isize) -> f64 {\n if n == 0 {\n return 0.0;\n }\n let n = n as f64;\n let sum = 1.0 / (2f64.powf(n - 1.0)) + geometric_sum((n - 1.0) as isize);\n sum\n}"} +{"name": "mbpp_426_filter_oddnumbers", "language": "rs", "prompt": "/// Write a function to filter odd numbers.\nfn filter_oddnumbers(nums: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_426_filter_oddnumbers.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "filter_oddnumbers", "test": "\n\nfn main() {\n let candidate = filter_oddnumbers;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 10]), vec![1, 3, 5, 7, 9]);\n assert_eq!(candidate(vec![10, 20, 45, 67, 84, 93]), vec![45, 67, 93]);\n assert_eq!(candidate(vec![5, 7, 9, 8, 6, 4, 3]), vec![5, 7, 9, 3]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to filter odd numbers.\nfn filter_oddnumbers(nums: Vec) -> Vec {\n nums.into_iter().filter(|&num| num % 2 != 0).collect()\n}"} +{"name": "mbpp_437_remove_odd", "language": "rs", "prompt": "/// Write a function to remove odd characters in a string.\nfn remove_odd(str1: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_437_remove_odd.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "remove_odd", "test": "\n\nfn main() {\n let candidate = remove_odd;\n assert_eq!(candidate(String::from(\"python\")), String::from(\"yhn\"));\n assert_eq!(candidate(String::from(\"program\")), String::from(\"rga\"));\n assert_eq!(candidate(String::from(\"language\")), String::from(\"agae\"));\n}\n", "solution": "/// Write a function to remove odd characters in a string.\nfn remove_odd(str1: String) -> String {\n let mut result = String::new();\n for (index, ch) in str1.char_indices() {\n if index % 2 != 0 {\n result.push(ch);\n }\n }\n result\n}", "is_solved": true, "reflections": ["The implementation of the remove_odd function is incorrect because it removes even-indexed characters instead of odd-indexed characters. The condition in the if statement should be `index % 2 != 0` to correctly remove odd characters.", "The implementation of the remove_odd function is incorrect because it removes characters at even indices instead of odd indices. The conditional statement in the loop checks if the index is odd (index % 2 != 0) and pushes the character to the result string, which is the opposite of the desired behavior.", "The implementation of the remove_odd function is incorrect because it removes characters at even indices instead of odd indices. The function should remove characters at odd indices to produce the correct output.", "The implementation of the remove_odd function is incorrect because it removes even-indexed characters instead of odd-indexed characters. The condition in the if statement should be `index % 2 != 0` to correctly remove odd characters."]} +{"name": "mbpp_227_min_of_three", "language": "rs", "prompt": "/// Write a function to find minimum of three numbers.\nfn min_of_three(a: isize, b: isize, c: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_227_min_of_three.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "min_of_three", "test": "\n\nfn main() {\n let candidate = min_of_three;\n assert_eq!(candidate(10, 20, 0), 0);\n assert_eq!(candidate(19, 15, 18), 15);\n assert_eq!(candidate(-10, -20, -30), -30);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find minimum of three numbers.\nfn min_of_three(a: isize, b: isize, c: isize) -> isize {\n if a <= b && a <= c {\n a\n } else if b <= a && b <= c {\n b\n } else {\n c\n }\n}"} +{"name": "mbpp_172_count_occurance", "language": "rs", "prompt": "/// Write a function to count the number of occurence of the string 'std' in a given string.\nfn count_occurance(s: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_172_count_occurance.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_occurance", "test": "\n\nfn main() {\n let candidate = count_occurance;\n assert_eq!(candidate(String::from(\"letstdlenstdporstd\")), 3);\n assert_eq!(candidate(String::from(\"truststdsolensporsd\")), 1);\n assert_eq!(candidate(String::from(\"makestdsostdworthit\")), 2);\n assert_eq!(candidate(String::from(\"stds\")), 1);\n assert_eq!(candidate(String::from(\"\")), 0);\n}\n", "solution": "/// Write a function to count the number of occurence of the string 'std' in a given string.\nfn count_occurance(s: String) -> isize {\n let mut count = 0;\n let search_str = \"std\";\n let search_str_len = search_str.len();\n\n if s.len() >= search_str_len {\n for i in 0..s.len() - search_str_len + 1 {\n if &s[i..i + search_str_len] == search_str {\n count += 1;\n }\n }\n }\n\n count\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it does not handle the case when the input string is empty. The loop range calculation causes an overflow when subtracting `search_str_len` from the length of an empty string. This results in a panic and the test fails."]} +{"name": "mbpp_434_text_match_one", "language": "rs", "prompt": "/// Write a function that matches a string that has an a followed by one or more b's.\nfn text_match_one(text: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_434_text_match_one.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "text_match_one", "test": "\n\nfn main() {\n let candidate = text_match_one;\n assert_eq!(candidate(String::from(\"ac\")), false);\n assert_eq!(candidate(String::from(\"dc\")), false);\n assert_eq!(candidate(String::from(\"abba\")), true);\n}\n", "is_solved": false, "reflections": ["The implementation is wrong because the `regex` crate is not declared or imported, causing the compiler to throw an error. To fix this issue, the `regex` crate needs to be added to the `Cargo.toml` file and imported using `use regex::Regex;` at the beginning of the code.", "The implementation is wrong because the `regex` crate is not declared in the dependencies, causing an unresolved import error. To fix this, the `regex` crate should be added to the Cargo.toml file under the dependencies section.", "The implementation is wrong because the `regex` crate is not declared in the dependencies, causing an unresolved import error. To fix this issue, the `regex` crate should be added to the project's `Cargo.toml` file under the `[dependencies]` section.", "The implementation is wrong because the `regex` crate is not declared in the dependencies, causing an unresolved import error. To fix this issue, the `regex` crate should be added to the Cargo.toml file as a dependency."], "solution": "/// Write a function that matches a string that has an a followed by one or more b's.\nfn text_match_one(text: String) -> bool {\n use regex::Regex;\n let pattern = Regex::new(r\"a+b+\").unwrap();\n pattern.is_match(&text)\n}"} +{"name": "mbpp_291_count_no_of_ways", "language": "rs", "prompt": "/// Write a function to find out the number of ways of painting the fence such that at most 2 adjacent posts have the same color for the given fence with n posts and k colors.\nfn count_no_of_ways(n: isize, k: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_291_count_no_of_ways.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_no_of_ways", "test": "\n\nfn main() {\n let candidate = count_no_of_ways;\n assert_eq!(candidate(2, 4), 16);\n assert_eq!(candidate(3, 2), 6);\n assert_eq!(candidate(4, 4), 228);\n}\n", "solution": "/// Write a function to find out the number of ways of painting the fence such that at most 2 adjacent posts have the same color for the given fence with n posts and k colors.\nfn count_no_of_ways(n: isize, k: isize) -> isize {\n if n == 0 {\n return 0;\n }\n if n == 1 {\n return k;\n }\n\n let mut same_color = k;\n let mut diff_color = k * (k - 1);\n let mut total_ways = same_color + diff_color;\n\n for _ in 3..=n {\n let prev_same_color = same_color;\n same_color = diff_color;\n diff_color = total_ways * (k - 1);\n total_ways = same_color + diff_color;\n }\n\n total_ways\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it does not properly handle the case where there are more than two adjacent posts with the same color. The current logic calculates the total number of ways without considering the constraint of at most 2 adjacent posts having the same color, leading to an overestimation of the total number of ways. This is evident in the failed test cases where the output is greater than the expected value.", "The implementation is incorrect because it incorrectly calculates the number of ways to paint the fence with different colors. The diff_color calculation should be based on the total_ways of the previous iteration, not the sum of same_color and diff_color. This leads to an overestimation of the total number of ways to paint the fence, causing the failed test cases.", "The implementation is incorrect because it calculates the number of ways to paint the fence with the wrong formula for updating the `diff_color` variable. Instead of multiplying the total ways by (k - 1), it should multiply the previous `diff_color` by (k - 1) and add the previous `same_color` multiplied by (k - 2). This error leads to incorrect results for cases with more than 2 fence posts and more than 2 colors.", "The implementation of the count_no_of_ways function is incorrect because it does not properly calculate the number of ways to paint the fence with the given constraints. The calculation for updating the diff_color variable is incorrect, as it does not account for the correct number of ways to paint the fence with different colors. This leads to incorrect results for the failing test cases."]} +{"name": "mbpp_471_find_remainder", "language": "rs", "prompt": "/// Write a rsthon function to find the product of the vector multiplication modulo n.\nfn find_remainder(arr: Vec, n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_471_find_remainder.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_remainder", "test": "\n\nfn main() {\n let candidate = find_remainder;\n assert_eq!(candidate(vec![100, 10, 5, 25, 35, 14], 11), 9);\n assert_eq!(candidate(vec![1, 1, 1], 1), 0);\n assert_eq!(candidate(vec![1, 2, 1], 2), 0);\n}\n", "solution": "/// Write a rsthon function to find the product of the vector multiplication modulo n.\nfn find_remainder(arr: Vec, n: isize) -> isize {\n let mut product: isize = 1;\n\n for num in arr {\n product = (product * num) % n;\n }\n\n product\n}", "is_solved": true, "reflections": ["The implementation of the find_remainder function is incorrect because it does not handle cases where the product of the vector elements is equal to the modulo value (n). In such cases, the function returns 0 instead of the correct remainder. This is evident from the failed test case where the input vector is [4, 5, 6] and n is 10. The expected output is 4, but the function returns 0.", "The implementation of the find_remainder function is incorrect because it returns the value of 'n' when the product is 0, instead of returning 0 as the remainder. This causes the function to fail the tests where the expected output is 0.", "The implementation of the find_remainder function is incorrect because it does not handle cases where the product of the vector elements is equal to the modulo value (n). In such cases, the function returns 0 instead of the correct remainder. This is evident from the failed test case where the input vector is [4, 5, 6] and n is 10, the expected output is 4, but the function returns 0.", "The implementation is incorrect because it returns `n` when the product is 0, which causes the function to fail for cases where the expected result is actually 0. Additionally, the function may return incorrect results for other cases due to this unnecessary condition."]} +{"name": "mbpp_808_check_K", "language": "rs", "prompt": "/// Write a function to check if the given tuples contain the k or not.\nfn check_K(test_tup: Vec, K: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_808_check_K.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "check_K", "test": "\n\nfn main() {\n let candidate = check_K;\n assert_eq!(candidate(vec![10, 4, 5, 6, 8], 6), true);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6], 7), false);\n assert_eq!(candidate(vec![7, 8, 9, 44, 11, 12], 11), true);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check if the given tuples contain the k or not.\nfn check_K(test_tup: Vec, K: isize) -> bool {\n for value in test_tup {\n if value == K {\n return true;\n }\n }\n false\n}"} +{"name": "mbpp_68_is_Monotonic", "language": "rs", "prompt": "/// Write a rsthon function to check whether the given vector is monotonic or not.\nfn is_Monotonic(A: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_68_is_Monotonic.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_Monotonic", "test": "\n\nfn main() {\n let candidate = is_Monotonic;\n assert_eq!(candidate(vec![6, 5, 4, 4]), true);\n assert_eq!(candidate(vec![1, 2, 2, 3]), true);\n assert_eq!(candidate(vec![1, 3, 2]), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to check whether the given vector is monotonic or not.\nfn is_Monotonic(A: Vec) -> bool {\n if A.len() < 2 {\n return true;\n }\n\n let mut increasing = None;\n\n for i in 1..A.len() {\n if A[i - 1] == A[i] {\n continue;\n }\n\n if increasing.is_none() {\n increasing = Some(A[i - 1] < A[i]);\n } else if increasing.unwrap() != (A[i - 1] < A[i]) {\n return false;\n }\n }\n\n true\n}"} +{"name": "mbpp_430_parabola_directrix", "language": "rs", "prompt": "/// Write a function to find the directrix of a parabola.\nfn parabola_directrix(a: isize, b: isize, c: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_430_parabola_directrix.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "parabola_directrix", "test": "\n\nfn main() {\n let candidate = parabola_directrix;\n assert_eq!(candidate(5, 3, 2), -198);\n assert_eq!(candidate(9, 8, 4), -2336);\n assert_eq!(candidate(2, 4, 6), -130);\n}\n", "is_solved": false, "reflections": ["The implementation of the parabola_directrix function is incorrect because it calculates the directrix using the formula `c - (b * b) / (4 * a)`, which is actually the formula for the vertex of a parabola. This leads to incorrect results for the directrix in the failed test cases.", "The implementation of the parabola_directrix function is incorrect because it uses integer division instead of floating-point division, which leads to inaccurate results. Additionally, the formula for the directrix calculation is not properly parenthesized, causing the order of operations to be incorrect.", "The implementation of the parabola_directrix function is incorrect because it does not properly calculate the directrix of the parabola. The formula used in the function is incorrect, leading to wrong results and failed test cases.", "The implementation of the parabola_directrix function is incorrect because it calculates the directrix using the formula `c - (b * b) / (4.0 * a)`, which is actually the formula for the vertex of a parabola. The correct formula for the directrix should be `c - (b * b) / (4.0 * a) - 1 / (4.0 * a)`. This mistake leads to incorrect results in the failed test cases."], "solution": "/// Write a function to find the directrix of a parabola.\nfn parabola_directrix(a: isize, b: isize, c: isize) -> isize {\n let a = a as f64;\n let b = b as f64;\n let c = c as f64;\n let directrix = c - (b * b) / (4.0 * a) - 1.0 / (4.0 * a);\n directrix.round() as isize\n}"} +{"name": "mbpp_618_div_list", "language": "rs", "prompt": "/// Write a function to divide two vectors element wise.\nfn div_list(nums1: Vec, nums2: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_618_div_list.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "div_list", "test": "\n\nfn main() {\n let candidate = div_list;\n assert_eq!(candidate(vec![4, 5, 6], vec![1, 2, 3]), vec![4.0, 2.5, 2.0]);\n assert_eq!(candidate(vec![3, 2], vec![1, 4]), vec![3.0, 0.5]);\n assert_eq!(candidate(vec![90, 120], vec![50, 70]), vec![1.8, 1.7142857142857142]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to divide two vectors element wise.\nfn div_list(nums1: Vec, nums2: Vec) -> Vec {\n let mut result = Vec::new();\n\n for (num1, num2) in nums1.iter().zip(nums2.iter()) {\n if *num2 != 0 {\n result.push(*num1 as f64 / *num2 as f64);\n } else {\n result.push(std::f64::INFINITY);\n }\n }\n\n result\n}"} +{"name": "mbpp_421_concatenate_tuple", "language": "rs", "prompt": "/// Write a function to concatenate each element of tuple by the delimiter.\nfn concatenate_tuple(test_tup: (String, String, isize, String)) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_421_concatenate_tuple.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "concatenate_tuple", "test": "\n\nfn main() {\n let candidate = concatenate_tuple;\n assert_eq!(candidate((String::from(\"ID\"), String::from(\"is\"), 4, String::from(\"UTS\"))), String::from(\"ID-is-4-UTS\"));\n assert_eq!(candidate((String::from(\"QWE\"), String::from(\"is\"), 4, String::from(\"RTY\"))), String::from(\"QWE-is-4-RTY\"));\n assert_eq!(candidate((String::from(\"ZEN\"), String::from(\"is\"), 4, String::from(\"OP\"))), String::from(\"ZEN-is-4-OP\"));\n}\n", "is_solved": false, "reflections": ["The implementation is wrong because it has 5 placeholders in the format string, but only provides 4 arguments (a, b, c, d). The delimiter is missing between the elements, causing the error.", "The implementation is wrong because there is a missing formatting specifier for the delimiter in the format! macro. This causes the delimiter variable to be unused and the compiler to raise an error. To fix this, a formatting specifier should be added for the delimiter between the last two elements.", "The implementation is incorrect because it uses a hyphen \"-\" as the delimiter instead of a comma \",\". This causes the output to not match the expected results in the failed tests, as they expect the elements to be separated by commas."], "solution": "/// Write a function to concatenate each element of tuple by the delimiter.\nfn concatenate_tuple(test_tup: (String, String, isize, String)) -> String {\n let (a, b, c, d) = test_tup;\n let delimiter = \",\";\n format!(\"{}{}{}{}{}{}{}\", a, delimiter, b, delimiter, c, delimiter, d)\n}"} +{"name": "mbpp_750_add_tuple", "language": "rs", "prompt": "/// Write a function to add the given tuple to the given vector.\nfn add_tuple(test_list: Vec, test_tup: (isize, isize)) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_750_add_tuple.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "add_tuple", "test": "\n\nfn main() {\n let candidate = add_tuple;\n assert_eq!(candidate(vec![5, 6, 7], (9, 10)), vec![5, 6, 7, 9, 10]);\n assert_eq!(candidate(vec![6, 7, 8], (10, 11)), vec![6, 7, 8, 10, 11]);\n assert_eq!(candidate(vec![7, 8, 9], (11, 12)), vec![7, 8, 9, 11, 12]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to add the given tuple to the given vector.\nfn add_tuple(test_list: Vec, test_tup: (isize, isize)) -> Vec {\n let mut result = test_list.clone();\n result.push(test_tup.0);\n result.push(test_tup.1);\n result\n}"} +{"name": "mbpp_304_find_Element", "language": "rs", "prompt": "/// Write a rsthon function to find element at a given index after number of rotations.\nfn find_Element(arr: Vec, ranges: Vec>, rotations: isize, index: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_304_find_Element.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_Element", "test": "\n\nfn main() {\n let candidate = find_Element;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5], vec![vec![0, 2], vec![0, 3]], 2, 1), 3);\n assert_eq!(candidate(vec![1, 2, 3, 4], vec![vec![0, 1], vec![0, 2]], 1, 2), 3);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6], vec![vec![0, 1], vec![0, 2]], 1, 1), 1);\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because it does not handle multiple rotations properly. The code applies all rotations at once, which leads to incorrect results when there are multiple rotations. Additionally, the code does not account for the possibility of negative rotations, which could cause the array to rotate in the opposite direction.", "The implementation is incorrect because it does not handle the rotations properly when the range does not start from the beginning of the array. The rotation logic is flawed, causing the function to return incorrect elements at the given index after applying the rotations. This is evident from the failed test cases where the range does not start at 0.", "The implementation is incorrect because it does not handle multiple rotations properly. The current implementation applies each rotation independently, which leads to incorrect results when there are multiple rotations. The logic for calculating the final position of elements after multiple rotations needs to be revised to account for the combined effect of all rotations.", "The implementation is incorrect because it calculates the total rotations for each range independently and applies them one by one. This approach does not account for the overlapping ranges and their combined effect on the final array. As a result, the function fails to produce the correct output for test cases with multiple overlapping ranges."], "solution": "/// Write a rsthon function to find element at a given index after number of rotations.\nfn find_Element(arr: Vec, ranges: Vec>, rotations: isize, index: isize) -> isize {\n let mut arr = arr;\n let n = arr.len();\n let mut temp: Vec = vec![0; n];\n\n // Calculate the total rotations for each range\n let mut total_rotations: Vec = vec![0; ranges.len()];\n for i in 0..ranges.len() {\n total_rotations[i] = rotations % (ranges[i][1] - ranges[i][0] + 1);\n }\n\n // Apply rotations one by one\n for i in 0..ranges.len() {\n let (left, right) = (ranges[i][0] as usize, ranges[i][1] as usize);\n let k = total_rotations[i];\n\n // Handle negative rotations\n let k = if k < 0 { (right - left + 1) as isize + k } else { k };\n\n // Rotate the elements within the range\n for j in 0..=right - left {\n temp[j] = arr[(left + j + k as usize) % (right - left + 1) + left];\n }\n\n // Update the original array with the rotated elements\n for j in 0..=right - left {\n arr[left + j] = temp[j];\n }\n }\n\n // Apply the rotations for overlapping ranges\n for i in 0..ranges.len() {\n for j in i + 1..ranges.len() {\n if ranges[i][1] >= ranges[j][0] {\n let overlap_start = ranges[j][0] as usize;\n let overlap_end = ranges[i][1] as usize;\n let k = total_rotations[j];\n\n // Rotate the elements within the overlapping range\n for m in 0..=overlap_end - overlap_start {\n temp[m] = arr[(overlap_start + m + k as usize) % (overlap_end - overlap_start + 1) + overlap_start];\n }\n\n // Update the original array with the rotated elements\n for m in 0..=overlap_end - overlap_start {\n arr[overlap_start + m] = temp[m];\n }\n }\n }\n }\n\n // Return the element at the given index\n arr[index as usize]\n}"} +{"name": "mbpp_740_tuple_to_dict", "language": "rs", "prompt": "use std::collections::HashMap;\n\n/// Write a function to convert the given tuple to a key-value HashMap using adjacent elements. https://www.geeksforgeeks.org/rsthon-convert-tuple-to-adjacent-pair-HashMap/\nfn tuple_to_dict(test_tup: (isize, isize, isize, isize, isize, isize)) -> HashMap {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_740_tuple_to_dict.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "tuple_to_dict", "test": "\n\nfn main() {\n let candidate = tuple_to_dict;\n assert_eq!(candidate((1, 5, 7, 10, 13, 5)), HashMap::from([(1, 5), (7, 10), (13, 5)]));\n assert_eq!(candidate((1, 2, 3, 4, 5, 6)), HashMap::from([(1, 2), (3, 4), (5, 6)]));\n assert_eq!(candidate((7, 8, 9, 10, 11, 12)), HashMap::from([(7, 8), (9, 10), (11, 12)]));\n}\n", "is_solved": true, "reflections": [], "solution": "use std::collections::HashMap;\n\n/// Write a function to convert the given tuple to a key-value HashMap using adjacent elements. https://www.geeksforgeeks.org/rsthon-convert-tuple-to-adjacent-pair-HashMap/\nfn tuple_to_dict(test_tup: (isize, isize, isize, isize, isize, isize)) -> HashMap {\n let mut result = HashMap::new();\n let tuple_elements = [test_tup.0, test_tup.1, test_tup.2, test_tup.3, test_tup.4, test_tup.5];\n\n for i in (0..tuple_elements.len() - 1).step_by(2) {\n result.insert(tuple_elements[i], tuple_elements[i + 1]);\n }\n\n result\n}"} +{"name": "mbpp_627_find_First_Missing", "language": "rs", "prompt": "/// Write a rsthon function to find the smallest missing number from a sorted vector of natural numbers.\nfn find_First_Missing(array: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_627_find_First_Missing.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_First_Missing", "test": "\n\nfn main() {\n let candidate = find_First_Missing;\n assert_eq!(candidate(vec![0, 1, 2, 3]), 4);\n assert_eq!(candidate(vec![0, 1, 2, 6, 9]), 3);\n assert_eq!(candidate(vec![2, 3, 5, 8, 9]), 0);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a rsthon function to find the smallest missing number from a sorted vector of natural numbers.\nfn find_First_Missing(array: Vec) -> isize {\n let mut prev = 0;\n\n for num in array {\n if num > 0 {\n if num - prev > 1 {\n return prev + 1;\n }\n prev = num;\n }\n }\n\n return prev + 1;\n}"} +{"name": "mbpp_165_count_char_position", "language": "rs", "prompt": "/// Write a function to count the number of characters in a string that occur at the same position in the string as in the English alphabet (case insensitive).\nfn count_char_position(str1: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_165_count_char_position.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_char_position", "test": "\n\nfn main() {\n let candidate = count_char_position;\n assert_eq!(candidate(String::from(\"xbcefg\")), 2);\n assert_eq!(candidate(String::from(\"ABcED\")), 3);\n assert_eq!(candidate(String::from(\"AbgdeF\")), 5);\n}\n", "solution": "/// Write a function to count the number of characters in a string that occur at the same position in the string as in the English alphabet (case insensitive).\nfn count_char_position(str1: String) -> isize {\n let mut count = 0;\n\n for (i, c) in str1.chars().enumerate() {\n let position = i + 1;\n let c = c.to_ascii_lowercase();\n\n if c.is_ascii_alphabetic() {\n let char_code = c as u8 - b'a' + 1;\n\n if position == char_code as usize {\n count += 1;\n }\n }\n }\n\n count as isize\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it does not handle uppercase characters and non-alphabetic characters properly. The function fails to count uppercase characters that match their position in the alphabet, and it causes an overflow error when encountering non-alphabetic characters due to the subtraction operation.", "The implementation is incorrect because it does not handle the case where characters are uppercase properly. The function only counts characters that match their position in the alphabet when they are lowercase, but it should also count them when they are uppercase. This causes the function to fail the tests with \"Alphabet\" and \"RustGPT\" as input.", "The implementation is incorrect because it does not handle the case where characters in the input string are uppercase. The function converts the character to lowercase before checking if it's an alphabetic character, but it does not do the same when calculating the character's position in the alphabet. This causes the function to fail when encountering uppercase characters that should be counted.", "The implementation of the count_char_position function is incorrect because it does not handle the case when the input string contains uppercase characters. The function only counts characters that match their position in the alphabet when they are lowercase. This causes the function to fail the tests with \"Alphabet\" and \"RustGPT\" as input, where the correct characters are in uppercase."]} +{"name": "mbpp_589_perfect_squares", "language": "rs", "prompt": "/// Write a function to find perfect squares between two given numbers.\nfn perfect_squares(a: isize, b: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_589_perfect_squares.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "perfect_squares", "test": "\n\nfn main() {\n let candidate = perfect_squares;\n assert_eq!(candidate(1, 30), vec![1, 4, 9, 16, 25]);\n assert_eq!(candidate(50, 100), vec![64, 81, 100]);\n assert_eq!(candidate(100, 200), vec![100, 121, 144, 169, 196]);\n}\n", "solution": "/// Write a function to find perfect squares between two given numbers.\nfn perfect_squares(a: isize, b: isize) -> Vec {\n let mut result = Vec::new();\n\n for i in (a as f64).sqrt().ceil() as isize..=(b as f64).sqrt().floor() as isize {\n if i > 0 {\n result.push(i * i);\n }\n }\n\n result\n}", "is_solved": true, "reflections": ["The implementation is incorrect when the input range includes 0, as it considers 0 as a perfect square. The function should be modified to exclude 0 from the result when calculating perfect squares."]} +{"name": "mbpp_736_left_insertion", "language": "rs", "prompt": "/// Write a function to locate the left insertion point for a specified value in sorted order. https://www.w3resource.com/rsthon-exercises/data-structures-and-algorithms/rsthon-data-structure-exercise-24.php\nfn left_insertion(a: Vec, x: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_736_left_insertion.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "left_insertion", "test": "\n\nfn main() {\n let candidate = left_insertion;\n assert_eq!(candidate(vec![1, 2, 4, 5], 6), 4);\n assert_eq!(candidate(vec![1, 2, 4, 5], 3), 2);\n assert_eq!(candidate(vec![1, 2, 4, 5], 7), 4);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to locate the left insertion point for a specified value in sorted order. https://www.w3resource.com/rsthon-exercises/data-structures-and-algorithms/rsthon-data-structure-exercise-24.php\nfn left_insertion(a: Vec, x: isize) -> isize {\n let mut left: isize = 0;\n let mut right: isize = a.len() as isize - 1;\n\n while left <= right {\n let mid = left + (right - left) / 2;\n\n if a[mid as usize] < x {\n left = mid + 1;\n } else {\n right = mid - 1;\n }\n }\n\n left\n}"} +{"name": "mbpp_63_max_difference", "language": "rs", "prompt": "/// Write a function to find the maximum difference between available pairs in the given tuple vector.\nfn max_difference(test_list: Vec<(isize, isize)>) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_63_max_difference.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "max_difference", "test": "\n\nfn main() {\n let candidate = max_difference;\n assert_eq!(candidate(vec![(3, 5), (1, 7), (10, 3), (1, 2)]), 7);\n assert_eq!(candidate(vec![(4, 6), (2, 17), (9, 13), (11, 12)]), 15);\n assert_eq!(candidate(vec![(12, 35), (21, 27), (13, 23), (41, 22)]), 23);\n}\n", "is_solved": false, "reflections": ["The implementation is wrong because it calculates the absolute difference between the elements of each tuple, rather than finding the maximum difference between all available pairs in the given tuple vector. This leads to incorrect results for the failed test cases, as the function only considers the differences within each tuple, not across all tuples.", "The implementation is incorrect because it calculates the maximum difference between the global minimum and maximum values in the entire tuple vector, rather than finding the maximum difference between the pairs in each tuple. This leads to incorrect results when the maximum difference is not between the global minimum and maximum values.", "The implementation is wrong because it calculates the absolute difference between the elements of each tuple, rather than finding the maximum difference between all available pairs in the given tuple vector. This leads to incorrect results for the failed test cases, as the function only considers the differences within each tuple, not across all tuples.", "The implementation is incorrect because it calculates the maximum and minimum differences between the elements of each tuple, and then subtracts the minimum difference from the maximum difference. This does not give the maximum difference between any two pairs in the given tuple vector. Instead, it gives the difference between the largest and smallest differences found in the individual tuples."], "solution": "/// Write a function to find the maximum difference between available pairs in the given tuple vector.\nfn max_difference(test_list: Vec<(isize, isize)>) -> isize {\n let mut max_diff = isize::MIN;\n\n for (a1, b1) in &test_list {\n for (a2, b2) in &test_list {\n let diff = ((a1 - b1) - (a2 - b2)).abs();\n max_diff = max_diff.max(diff);\n }\n }\n\n max_diff\n}"} +{"name": "mbpp_264_dog_age", "language": "rs", "prompt": "/// Write a function to calculate a dog's age in dog's years.\nfn dog_age(h_age: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_264_dog_age.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "dog_age", "test": "\n\nfn main() {\n let candidate = dog_age;\n assert_eq!(candidate(12), 61);\n assert_eq!(candidate(15), 73);\n assert_eq!(candidate(24), 109);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a function to calculate a dog's age in dog's years.\nfn dog_age(h_age: isize) -> isize {\n h_age * 7\n}"} +{"name": "mbpp_273_substract_elements", "language": "rs", "prompt": "/// Write a function that takes in two tuples and subtracts the elements of the first tuple by the elements of the second tuple with the same index.\nfn substract_elements(test_tup1: (isize, isize, isize), test_tup2: (isize, isize, isize)) -> (isize, isize, isize) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_273_substract_elements.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "substract_elements", "test": "\n\nfn main() {\n let candidate = substract_elements;\n assert_eq!(candidate((10, 4, 5), (2, 5, 18)), (8, -1, -13));\n assert_eq!(candidate((11, 2, 3), (24, 45, 16)), (-13, -43, -13));\n assert_eq!(candidate((7, 18, 9), (10, 11, 12)), (-3, 7, -3));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function that takes in two tuples and subtracts the elements of the first tuple by the elements of the second tuple with the same index.\nfn substract_elements(test_tup1: (isize, isize, isize), test_tup2: (isize, isize, isize)) -> (isize, isize, isize) {\n let result = (\n test_tup1.0 - test_tup2.0,\n test_tup1.1 - test_tup2.1,\n test_tup1.2 - test_tup2.2,\n );\n\n result\n}"} +{"name": "mbpp_83_get_Char", "language": "rs", "prompt": "/// Write a rsthon function to find the character made by adding the ASCII value of all the characters of the given string modulo 26.\nfn get_Char(strr: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_83_get_Char.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "get_Char", "test": "\n\nfn main() {\n let candidate = get_Char;\n assert_eq!(candidate(String::from(\"abc\")), String::from(\"f\"));\n assert_eq!(candidate(String::from(\"gfg\")), String::from(\"t\"));\n assert_eq!(candidate(String::from(\"ab\")), String::from(\"c\"));\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because it calculates the resulting character using the uppercase 'A' as the base, which causes the output to be in uppercase instead of lowercase. Additionally, the modulo operation should be performed with 26 as the divisor, but the ASCII value of the characters should be adjusted to start from 0 (i.e., 'a' or 'A' should be 0, 'b' or 'B' should be 1, etc.) before performing the sum and modulo operations.", "The implementation of the `get_Char` function is incorrect because it does not account for the ASCII value of the characters when calculating the sum. Instead, it only calculates the difference between the character and 'a'. This leads to incorrect results when the input string contains characters other than 'a' to 'z'.", "The implementation is incorrect because it calculates the sum of the ASCII values of all characters in the input string without considering the modulo 26 operation during the summation. This leads to incorrect results when the sum of ASCII values exceeds the range of a single character. The modulo 26 operation should be applied during the summation to ensure the correct character is returned.", "The implementation of the `get_Char` function is incorrect because it calculates the sum of the ASCII values of the characters in the input string modulo 26, but it does not account for adding the ASCII value of 'a' back to the result before converting it to a character. This causes the function to return incorrect results for some test cases, such as \"xyz\" and \"HelloWorld\"."], "solution": "/// Write a rsthon function to find the character made by adding the ASCII value of all the characters of the given string modulo 26.\nfn get_Char(strr: String) -> String {\n let mut sum = 0;\n\n for c in strr.chars() {\n let lower_c = c.to_ascii_lowercase();\n sum = (sum + (lower_c as u32 - 'a' as u32)) % 26;\n }\n\n let result = ((sum + ('a' as u32)) % 26) + ('a' as u32);\n let result_char = result as u8 as char;\n\n result_char.to_string()\n}"} +{"name": "mbpp_91_find_substring", "language": "rs", "prompt": "/// Write a function to check if a string is present as a substring in a given vector of string values.\nfn find_substring(str1: Vec, sub_str: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_91_find_substring.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_substring", "test": "\n\nfn main() {\n let candidate = find_substring;\n assert_eq!(candidate(vec![String::from(\"red\"), String::from(\"black\"), String::from(\"white\"), String::from(\"green\"), String::from(\"orange\")], String::from(\"ack\")), true);\n assert_eq!(candidate(vec![String::from(\"red\"), String::from(\"black\"), String::from(\"white\"), String::from(\"green\"), String::from(\"orange\")], String::from(\"abc\")), false);\n assert_eq!(candidate(vec![String::from(\"red\"), String::from(\"black\"), String::from(\"white\"), String::from(\"green\"), String::from(\"orange\")], String::from(\"ange\")), true);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check if a string is present as a substring in a given vector of string values.\nfn find_substring(str1: Vec, sub_str: String) -> bool {\n for s in str1.iter() {\n if s.contains(&sub_str) {\n return true;\n }\n }\n false\n}"} +{"name": "mbpp_100_next_smallest_palindrome", "language": "rs", "prompt": "/// Write a function to find the next smallest palindrome of a specified integer, returned as an integer.\nfn next_smallest_palindrome(num: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_100_next_smallest_palindrome.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "next_smallest_palindrome", "test": "\n\nfn main() {\n let candidate = next_smallest_palindrome;\n assert_eq!(candidate(99), 101);\n assert_eq!(candidate(1221), 1331);\n assert_eq!(candidate(120), 121);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the next smallest palindrome of a specified integer, returned as an integer.\nfn next_smallest_palindrome(num: isize) -> isize {\n let mut next_num = num + 1;\n\n while !is_palindrome(next_num) {\n next_num += 1;\n }\n\n next_num\n}\n\nfn is_palindrome(num: isize) -> bool {\n let num_str = num.to_string();\n let reversed_str = num_str.chars().rev().collect::();\n\n num_str == reversed_str\n}"} +{"name": "mbpp_282_sub_list", "language": "rs", "prompt": "/// Write a function to subtract two vectors element-wise.\nfn sub_list(nums1: Vec, nums2: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_282_sub_list.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sub_list", "test": "\n\nfn main() {\n let candidate = sub_list;\n assert_eq!(candidate(vec![1, 2, 3], vec![4, 5, 6]), vec![-3, -3, -3]);\n assert_eq!(candidate(vec![1, 2], vec![3, 4]), vec![-2, -2]);\n assert_eq!(candidate(vec![90, 120], vec![50, 70]), vec![40, 50]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to subtract two vectors element-wise.\nfn sub_list(nums1: Vec, nums2: Vec) -> Vec {\n nums1.iter().zip(nums2.iter()).map(|(a, b)| a - b).collect()\n}"} +{"name": "mbpp_790_even_position", "language": "rs", "prompt": "/// Write a rsthon function to check whether every even index contains even numbers of a given vector.\nfn even_position(nums: Vec) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_790_even_position.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "even_position", "test": "\n\nfn main() {\n let candidate = even_position;\n assert_eq!(candidate(vec![3, 2, 1]), false);\n assert_eq!(candidate(vec![1, 2, 3]), false);\n assert_eq!(candidate(vec![2, 1, 4]), true);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to check whether every even index contains even numbers of a given vector.\nfn even_position(nums: Vec) -> bool {\n for i in (0..nums.len()).step_by(2) {\n if nums[i] % 2 != 0 {\n return false;\n }\n }\n true\n}"} +{"name": "mbpp_411_snake_to_camel", "language": "rs", "prompt": "/// Write a function to convert the given snake case string to camel case string.\nfn snake_to_camel(word: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_411_snake_to_camel.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "snake_to_camel", "test": "\n\nfn main() {\n let candidate = snake_to_camel;\n assert_eq!(candidate(String::from(\"android_tv\")), String::from(\"AndroidTv\"));\n assert_eq!(candidate(String::from(\"google_pixel\")), String::from(\"GooglePixel\"));\n assert_eq!(candidate(String::from(\"apple_watch\")), String::from(\"AppleWatch\"));\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a function to convert the given snake case string to camel case string.\nfn snake_to_camel(word: String) -> String {\n let mut camel_case = String::new();\n let mut to_upper = false;\n\n for c in word.chars() {\n if c == '_' {\n to_upper = true;\n } else if to_upper {\n camel_case.push(c.to_ascii_uppercase());\n to_upper = false;\n } else {\n camel_case.push(c);\n }\n }\n\n camel_case\n}"} +{"name": "mbpp_56_checks", "language": "rs", "prompt": "/// Write a rsthon function to check if a given number is one less than twice its reverse.\nfn checks(n: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_56_checks.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "checks", "test": "\n\nfn main() {\n let candidate = checks;\n assert_eq!(candidate(70), false);\n assert_eq!(candidate(23), false);\n assert_eq!(candidate(73), true);\n}\n", "solution": "/// Write a rsthon function to check if a given number is one less than twice its reverse.\nfn checks(n: isize) -> bool {\n let reversed_n: isize = n.to_string().chars().rev().collect::().parse().unwrap();\n return n == (2 * reversed_n) - 1;\n}", "is_solved": true, "reflections": ["The implementation of the `checks` function is incorrect because it checks if the given number `n` is equal to one less than twice its reverse. However, the problem statement asks to check if the given number is one less than twice its reverse. This means the function should return true when `n` is one less than twice its reverse, but it currently returns false.", "The implementation of the `checks` function is incorrect because it checks if `n + 1` is equal to `2 * reversed_n`. However, the problem statement asks to check if the given number is one less than twice its reverse. Therefore, the function should check if `n` is equal to `(2 * reversed_n) - 1`.", "The implementation of the `checks` function is incorrect because it checks if the given number `n` is equal to one less than twice its reverse. However, the problem statement asks to check if the given number is one less than twice its reverse. This discrepancy in the logic causes the function to fail the test case `checks(52)`.", "The implementation of the `checks` function is incorrect because it checks if `n + 1` is equal to `2 * reversed_n`. However, the problem statement asks to check if the given number is one less than twice its reverse. Therefore, the function should check if `n` is equal to `(2 * reversed_n) - 1`."]} +{"name": "mbpp_724_power_base_sum", "language": "rs", "prompt": "/// Write a function that takes base and power as arguments and calculate the sum of all digits of the base to the specified power.\nfn power_base_sum(base: isize, power: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_724_power_base_sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "power_base_sum", "test": "\n\nfn main() {\n let candidate = power_base_sum;\n assert_eq!(candidate(2, 100), 115);\n assert_eq!(candidate(8, 10), 37);\n assert_eq!(candidate(8, 15), 62);\n assert_eq!(candidate(3, 3), 9);\n}\n", "is_solved": false, "reflections": ["The implementation of the power_base_sum function is incorrect because it calculates the sum of the digits of the result of raising the base to the specified power, rather than the sum of all digits of the base raised to each power from 1 to the specified power. This is why the test with input (4, 4) fails, as the function returns the sum of the digits of 4^4 (256) which is 13, instead of the expected sum of all digits of 4 raised to powers 1 to 4, which is 16.", "The implementation is incorrect because the type of `digits_sum` cannot be inferred by the Rust compiler. To fix this issue, you need to provide an explicit type annotation for the `digits_sum` variable.", "The implementation of the power_base_sum function is incorrect because it calculates the sum of the digits for each power from 1 to the specified power, and then adds them together. The correct approach should be to calculate the base raised to the specified power first, and then find the sum of its digits. The current implementation accumulates the sum of digits for all intermediate powers, leading to incorrect results.", "The implementation of the power_base_sum function is incorrect because it calculates the sum of the digits of the result of base raised to the power, rather than the sum of all digits of the base to the specified power. This leads to incorrect results for certain test cases, such as the failed test with input (4, 4), where the expected output is 16, but the function returns 13."], "solution": "/// Write a function that takes base and power as arguments and calculate the sum of all digits of the base to the specified power.\nfn power_base_sum(base: isize, power: isize) -> isize {\n let mut sum = 0;\n for i in 1..=power {\n let result = base.pow(i as u32);\n let digits_sum: isize = result\n .to_string()\n .chars()\n .map(|c| c.to_digit(10).unwrap() as isize)\n .sum();\n sum += digits_sum;\n }\n sum\n}"} +{"name": "mbpp_268_find_star_num", "language": "rs", "prompt": "/// Write a function to find the n'th star number.\nfn find_star_num(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_268_find_star_num.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_star_num", "test": "\n\nfn main() {\n let candidate = find_star_num;\n assert_eq!(candidate(3), 37);\n assert_eq!(candidate(4), 73);\n assert_eq!(candidate(5), 121);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the n'th star number.\nfn find_star_num(n: isize) -> isize {\n if n < 1 {\n panic!(\"n must be a positive integer\");\n }\n\n (6 * n * (n - 1)) + 1\n}"} +{"name": "mbpp_251_insert_element", "language": "rs", "prompt": "/// Write a function that takes in a vector and an element and inserts the element before each element in the vector, and returns the resulting vector.\nfn insert_element(list: Vec, element: String) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_251_insert_element.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "insert_element", "test": "\n\nfn main() {\n let candidate = insert_element;\n assert_eq!(candidate(vec![String::from(\"Red\"), String::from(\"Green\"), String::from(\"Black\")], String::from(\"c\")), vec![String::from(\"c\"), String::from(\"Red\"), String::from(\"c\"), String::from(\"Green\"), String::from(\"c\"), String::from(\"Black\")]);\n assert_eq!(candidate(vec![String::from(\"python\"), String::from(\"java\")], String::from(\"program\")), vec![String::from(\"program\"), String::from(\"python\"), String::from(\"program\"), String::from(\"java\")]);\n assert_eq!(candidate(vec![String::from(\"happy\"), String::from(\"sad\")], String::from(\"laugh\")), vec![String::from(\"laugh\"), String::from(\"happy\"), String::from(\"laugh\"), String::from(\"sad\")]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function that takes in a vector and an element and inserts the element before each element in the vector, and returns the resulting vector.\nfn insert_element(list: Vec, element: String) -> Vec {\n let mut result = Vec::new();\n\n for item in list {\n result.push(element.clone());\n result.push(item);\n }\n\n result\n}"} +{"name": "mbpp_428_shell_sort", "language": "rs", "prompt": "/// Write a function to sort the given vector by using shell sort.\nfn shell_sort(my_list: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_428_shell_sort.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "shell_sort", "test": "\n\nfn main() {\n let candidate = shell_sort;\n assert_eq!(candidate(vec![12, 23, 4, 5, 3, 2, 12, 81, 56, 95]), vec![2, 3, 4, 5, 12, 12, 23, 56, 81, 95]);\n assert_eq!(candidate(vec![24, 22, 39, 34, 87, 73, 68]), vec![22, 24, 34, 39, 68, 73, 87]);\n assert_eq!(candidate(vec![32, 30, 16, 96, 82, 83, 74]), vec![16, 30, 32, 74, 82, 83, 96]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to sort the given vector by using shell sort.\nfn shell_sort(my_list: Vec) -> Vec {\n let mut my_list = my_list;\n let n = my_list.len();\n let mut gap = n / 2;\n\n while gap > 0 {\n for i in gap..n {\n let temp = my_list[i];\n let mut j = i;\n\n while j >= gap && my_list[j - gap] > temp {\n my_list[j] = my_list[j - gap];\n j -= gap;\n }\n\n my_list[j] = temp;\n }\n\n gap /= 2;\n }\n\n my_list\n}"} +{"name": "mbpp_476_big_sum", "language": "rs", "prompt": "/// Write a rsthon function to find the sum of the largest and smallest value in a given vector.\nfn big_sum(nums: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_476_big_sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "big_sum", "test": "\n\nfn main() {\n let candidate = big_sum;\n assert_eq!(candidate(vec![1, 2, 3]), 4);\n assert_eq!(candidate(vec![-1, 2, 3, 4]), 3);\n assert_eq!(candidate(vec![2, 3, 6]), 8);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find the sum of the largest and smallest value in a given vector.\nfn big_sum(nums: Vec) -> isize {\n if nums.is_empty() {\n return 0;\n }\n\n let mut min_num = nums[0];\n let mut max_num = nums[0];\n\n for num in nums {\n if num < min_num {\n min_num = num;\n }\n if num > max_num {\n max_num = num;\n }\n }\n\n min_num + max_num\n}"} +{"name": "mbpp_454_text_match_wordz", "language": "rs", "prompt": "/// Write a function that matches a word containing 'z'.\nfn text_match_wordz(text: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_454_text_match_wordz.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "text_match_wordz", "test": "\n\nfn main() {\n let candidate = text_match_wordz;\n assert_eq!(candidate(String::from(\"pythonz.\")), true);\n assert_eq!(candidate(String::from(\"xyz.\")), true);\n assert_eq!(candidate(String::from(\" lang .\")), false);\n}\n", "is_solved": false, "reflections": ["The implementation is wrong because the `regex` crate is not declared or imported, causing the compiler to throw an error. To fix this issue, the `regex` crate needs to be added to the `Cargo.toml` file and imported using `use regex::Regex;` at the beginning of the code.", "The implementation is wrong because the `regex` crate is not declared and imported properly. This causes an unresolved import error when trying to use the `Regex` struct from the `regex` crate. To fix this issue, the `regex` crate should be added to the `Cargo.toml` file and imported correctly at the beginning of the code.", "The implementation is wrong because the `regex` crate is not declared in the dependencies, causing an unresolved import error. To fix this issue, the `regex` crate should be added to the project's `Cargo.toml` file under the `[dependencies]` section.", "The implementation is wrong because the `regex` crate is not declared and imported in the code. This leads to an unresolved import error when trying to use the `Regex` struct from the `regex` crate. To fix this issue, the `regex` crate should be added to the dependencies in the `Cargo.toml` file and properly imported in the code."], "solution": "/// Write a function that matches a word containing 'z'.\nfn text_match_wordz(text: String) -> bool {\n use regex::Regex;\n let pattern = Regex::new(r\"\\b\\w*z\\w*\\b\").unwrap();\n pattern.is_match(&text)\n}"} +{"name": "mbpp_605_prime_num", "language": "rs", "prompt": "/// Write a function to check if the given integer is a prime number.\nfn prime_num(num: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_605_prime_num.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "prime_num", "test": "\n\nfn main() {\n let candidate = prime_num;\n assert_eq!(candidate(13), true);\n assert_eq!(candidate(7), true);\n assert_eq!(candidate(-1010), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check if the given integer is a prime number.\nfn prime_num(num: isize) -> bool {\n if num <= 1 {\n return false;\n }\n\n for i in 2..((num as f64).sqrt() as isize + 1) {\n if num % i == 0 {\n return false;\n }\n }\n\n true\n}"} +{"name": "mbpp_108_merge_sorted_list", "language": "rs", "prompt": "/// Write a function to merge three vectors into a single sorted vector.\nfn merge_sorted_list(num1: Vec, num2: Vec, num3: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_108_merge_sorted_list.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "merge_sorted_list", "test": "\n\nfn main() {\n let candidate = merge_sorted_list;\n assert_eq!(candidate(vec![25, 24, 15, 4, 5, 29, 110], vec![19, 20, 11, 56, 25, 233, 154], vec![24, 26, 54, 48]), vec![4, 5, 11, 15, 19, 20, 24, 24, 25, 25, 26, 29, 48, 54, 56, 110, 154, 233]);\n assert_eq!(candidate(vec![1, 3, 5, 6, 8, 9], vec![2, 5, 7, 11], vec![1, 4, 7, 8, 12]), vec![1, 1, 2, 3, 4, 5, 5, 6, 7, 7, 8, 8, 9, 11, 12]);\n assert_eq!(candidate(vec![18, 14, 10, 9, 8, 7, 9, 3, 2, 4, 1], vec![25, 35, 22, 85, 14, 65, 75, 25, 58], vec![12, 74, 9, 50, 61, 41]), vec![1, 2, 3, 4, 7, 8, 9, 9, 9, 10, 12, 14, 14, 18, 22, 25, 25, 35, 41, 50, 58, 61, 65, 74, 75, 85]);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a function to merge three vectors into a single sorted vector.\nfn merge_sorted_list(num1: Vec, num2: Vec, num3: Vec) -> Vec {\n let mut result: Vec = Vec::new();\n let mut i = 0;\n let mut j = 0;\n let mut k = 0;\n\n while i < num1.len() || j < num2.len() || k < num3.len() {\n let mut min_val = isize::MAX;\n\n if i < num1.len() && num1[i] < min_val {\n min_val = num1[i];\n }\n if j < num2.len() && num2[j] < min_val {\n min_val = num2[j];\n }\n if k < num3.len() && num3[k] < min_val {\n min_val = num3[k];\n }\n\n if i < num1.len() && num1[i] == min_val {\n i += 1;\n } else if j < num2.len() && num2[j] == min_val {\n j += 1;\n } else if k < num3.len() && num3[k] == min_val {\n k += 1;\n }\n\n result.push(min_val);\n }\n\n result\n}"} +{"name": "mbpp_639_sample_nam", "language": "rs", "prompt": "/// Write a function to sum the length of the names of a given vector of names after removing the names that start with a lowercase letter.\nfn sample_nam(sample_names: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_639_sample_nam.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sample_nam", "test": "\n\nfn main() {\n let candidate = sample_nam;\n assert_eq!(candidate(vec![String::from(\"sally\"), String::from(\"Dylan\"), String::from(\"rebecca\"), String::from(\"Diana\"), String::from(\"Joanne\"), String::from(\"keith\")]), 16);\n assert_eq!(candidate(vec![String::from(\"php\"), String::from(\"res\"), String::from(\"Python\"), String::from(\"abcd\"), String::from(\"Java\"), String::from(\"aaa\")]), 10);\n assert_eq!(candidate(vec![String::from(\"abcd\"), String::from(\"Python\"), String::from(\"abba\"), String::from(\"aba\")]), 6);\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because it only checks if the first character of the name is uppercase, but it doesn't remove the names that start with a lowercase letter. As a result, the function still counts the length of names starting with lowercase letters, causing the failed test cases.", "The implementation is incorrect because it does not properly handle the case where a name starts with an uppercase letter followed by lowercase letters. The function currently adds the length of the entire name, including the lowercase letters, to the sum. This causes the sum to be larger than expected, as seen in the failed test cases.", "The implementation is incorrect because it only counts the consecutive uppercase characters in the names that start with an uppercase letter, instead of counting the entire length of the name. This leads to incorrect results in the failed test cases.", "The implementation of the sample_nam function is incorrect because it does not properly handle the case where a name starts with an uppercase letter but has a lowercase letter immediately after it. This causes the function to include the length of such names in the sum, leading to incorrect results in the failed tests."], "solution": "/// Write a function to sum the length of the names of a given vector of names after removing the names that start with a lowercase letter.\nfn sample_nam(sample_names: Vec) -> isize {\n let mut sum = 0;\n for name in sample_names {\n if !name.is_empty() && name.chars().next().unwrap().is_uppercase() {\n let mut all_uppercase = true;\n for c in name.chars().skip(1) {\n if c.is_lowercase() {\n all_uppercase = false;\n break;\n }\n }\n if all_uppercase {\n sum += name.len();\n }\n }\n }\n sum as isize\n}"} +{"name": "mbpp_409_min_product_tuple", "language": "rs", "prompt": "/// Write a function to find the minimum product from the pairs of tuples within a given vector.\nfn min_product_tuple(list1: Vec<(isize, isize)>) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_409_min_product_tuple.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "min_product_tuple", "test": "\n\nfn main() {\n let candidate = min_product_tuple;\n assert_eq!(candidate(vec![(2, 7), (2, 6), (1, 8), (4, 9)]), 8);\n assert_eq!(candidate(vec![(10, 20), (15, 2), (5, 10)]), 30);\n assert_eq!(candidate(vec![(11, 44), (10, 15), (20, 5), (12, 9)]), 100);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the minimum product from the pairs of tuples within a given vector.\nfn min_product_tuple(list1: Vec<(isize, isize)>) -> isize {\n let mut min_product = std::isize::MAX;\n\n for &(a, b) in &list1 {\n let product = a * b;\n if product < min_product {\n min_product = product;\n }\n }\n\n min_product\n}"} +{"name": "mbpp_591_swap_List", "language": "rs", "prompt": "/// Write a rsthon function to interchange the first and last elements in a vector.\nfn swap_List(newList: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_591_swap_List.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "swap_List", "test": "\n\nfn main() {\n let candidate = swap_List;\n assert_eq!(candidate(vec![12, 35, 9, 56, 24]), vec![24, 35, 9, 56, 12]);\n assert_eq!(candidate(vec![1, 2, 3]), vec![3, 2, 1]);\n assert_eq!(candidate(vec![4, 5, 6]), vec![6, 5, 4]);\n}\n", "solution": "/// Write a rsthon function to interchange the first and last elements in a vector.\nfn swap_List(newList: Vec) -> Vec {\n if newList.is_empty() {\n return newList;\n }\n\n let mut swapped_list = newList.clone();\n let first_element = swapped_list[0];\n let last_element = swapped_list[swapped_list.len() - 1];\n let last_index = swapped_list.len() - 1;\n\n swapped_list[0] = last_element;\n swapped_list[last_index] = first_element;\n\n swapped_list\n}", "is_solved": true, "reflections": ["The implementation is wrong because it tries to borrow `swapped_list` as both mutable and immutable at the same time, which is not allowed in Rust. This occurs when trying to access the last element of the vector to set its value to `first_element`. To fix this issue, the length of the vector should be stored in a separate variable before performing the swap operation."]} +{"name": "mbpp_84_sequence", "language": "rs", "prompt": "/// Write a function to find the nth number in the newman conway sequence.\nfn sequence(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_84_sequence.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sequence", "test": "\n\nfn main() {\n let candidate = sequence;\n assert_eq!(candidate(10), 6);\n assert_eq!(candidate(2), 1);\n assert_eq!(candidate(3), 2);\n}\n", "solution": "/// Write a function to find the nth number in the newman conway sequence.\nfn sequence(n: isize) -> isize {\n if n <= 0 {\n panic!(\"n must be a positive integer\");\n }\n\n if n == 1 || n == 2 {\n return 1;\n }\n\n let mut seq = vec![0; n as usize];\n seq[0] = 1;\n seq[1] = 1;\n\n for i in 3..=n {\n let idx = i as usize;\n seq[idx - 1] = seq[(seq[idx - 2] - 1) as usize] + seq[(idx - seq[idx - 2] - 1) as usize];\n }\n\n seq[n as usize - 1] as isize\n}", "is_solved": true, "reflections": ["The implementation is wrong because it returns a `usize` instead of the expected `isize` return type. The error occurs at the last line of the function where the value from the sequence vector is returned without converting it to `isize`.", "The implementation is incorrect because it starts the loop from 3 instead of 2, causing the sequence to be calculated incorrectly for values of n greater than 2. This results in the function returning 1 for all test cases where n > 2, leading to the failed assertions.", "The implementation is incorrect because it calculates the sequence values using the wrong indices. The loop starts at index 2 instead of 3, causing the sequence to be calculated incorrectly from the beginning, leading to incorrect results for all test cases except when n is 1 or 2.", "The implementation of the sequence function is incorrect because it is not calculating the Newman-Conway sequence values properly. The issue lies in the loop where the sequence values are being calculated, specifically in the indexing of the seq vector. This results in incorrect values being returned for n > 2, causing the failed test cases."]} +{"name": "mbpp_260_newman_prime", "language": "rs", "prompt": "/// Write a function to find the nth newman–shanks–williams prime number.\nfn newman_prime(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_260_newman_prime.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "newman_prime", "test": "\n\nfn main() {\n let candidate = newman_prime;\n assert_eq!(candidate(3), 7);\n assert_eq!(candidate(4), 17);\n assert_eq!(candidate(5), 41);\n}\n", "solution": "/// Write a function to find the nth newman–shanks–williams prime number.\nfn newman_prime(n: isize) -> isize {\n if n < 0 {\n panic!(\"Invalid input: n must be non-negative\");\n }\n\n if n == 0 || n == 1 {\n return 1;\n }\n\n let mut prev = 1;\n let mut current = 1;\n\n for _ in 2..=n {\n let next = 2 * current + prev;\n prev = current;\n current = next;\n }\n\n current\n}", "is_solved": true, "reflections": ["The implementation of the `newman_prime` function is incorrect because it calculates the Newman-Shanks-Williams (NSW) numbers instead of the Newman-Shanks-Williams prime numbers. The NSW numbers follow a different sequence than the prime numbers in the series, which is causing the failed test cases.", "The implementation is incorrect because it calculates the nth prime number and then tries to generate the nth Newman-Shanks-Williams prime using those prime numbers. However, the Newman-Shanks-Williams prime sequence is not directly related to prime numbers. The implementation should follow the correct formula for generating Newman-Shanks-Williams primes, which is S(n) = 2*S(n-1) + S(n-2) with S(0) = S(1) = 1.", "The implementation of the newman_prime function is incorrect because it calculates the Newman-Shanks-Williams (NSW) numbers instead of the nth Newman-Shanks-Williams prime number. The function returns the nth NSW number, which is not necessarily prime, causing the failed test cases.", "The implementation of the `newman_prime` function is incorrect because it is checking for prime numbers instead of calculating the nth Newman-Shanks-Williams prime number. The function should follow the formula S(n) = 2 * S(n-1) + S(n-2) for n > 1, and not involve prime number checking. This is why the failed tests do not produce the expected results."]} +{"name": "mbpp_565_split", "language": "rs", "prompt": "/// Write a rsthon function to split a string into characters.\nfn split(word: String) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_565_split.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "split", "test": "\n\nfn main() {\n let candidate = split;\n assert_eq!(candidate(String::from(\"python\")), vec![String::from(\"p\"), String::from(\"y\"), String::from(\"t\"), String::from(\"h\"), String::from(\"o\"), String::from(\"n\")]);\n assert_eq!(candidate(String::from(\"Name\")), vec![String::from(\"N\"), String::from(\"a\"), String::from(\"m\"), String::from(\"e\")]);\n assert_eq!(candidate(String::from(\"program\")), vec![String::from(\"p\"), String::from(\"r\"), String::from(\"o\"), String::from(\"g\"), String::from(\"r\"), String::from(\"a\"), String::from(\"m\")]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to split a string into characters.\nfn split(word: String) -> Vec {\n let chars = word.chars().map(|c| c.to_string()).collect::>();\n chars\n}"} +{"name": "mbpp_753_min_k", "language": "rs", "prompt": "/// Write a function to find minimum k records from tuple vector. https://www.geeksforgeeks.org/rsthon-find-minimum-k-records-from-tuple-vector/ - in this case a verbatim cors of test cases\nfn min_k(test_list: Vec<(String, isize)>, K: isize) -> Vec<(String, isize)> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_753_min_k.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "min_k", "test": "\n\nfn main() {\n let candidate = min_k;\n assert_eq!(candidate(vec![(String::from(\"Manjeet\"), 10), (String::from(\"Akshat\"), 4), (String::from(\"Akash\"), 2), (String::from(\"Nikhil\"), 8)], 2), vec![(String::from(\"Akash\"), 2), (String::from(\"Akshat\"), 4)]);\n assert_eq!(candidate(vec![(String::from(\"Sanjeev\"), 11), (String::from(\"Angat\"), 5), (String::from(\"Akash\"), 3), (String::from(\"Nepin\"), 9)], 3), vec![(String::from(\"Akash\"), 3), (String::from(\"Angat\"), 5), (String::from(\"Nepin\"), 9)]);\n assert_eq!(candidate(vec![(String::from(\"tanmay\"), 14), (String::from(\"Amer\"), 11), (String::from(\"Ayesha\"), 9), (String::from(\"SKD\"), 16)], 1), vec![(String::from(\"Ayesha\"), 9)]);\n}\n", "solution": "/// Write a function to find minimum k records from tuple vector. https://www.geeksforgeeks.org/rsthon-find-minimum-k-records-from-tuple-vector/ - in this case a verbatim cors of test cases\nfn min_k(test_list: Vec<(String, isize)>, K: isize) -> Vec<(String, isize)> {\n let mut sorted_list = test_list.clone();\n sorted_list.sort_by_key(|x| x.1);\n sorted_list.into_iter()\n .take(K as usize)\n .collect()\n}", "is_solved": true, "reflections": ["The implementation is wrong because it tries to use the `sorted_by_key` method on an `IntoIter` struct, which does not have this method available. This results in a compilation error. To fix this issue, the correct method should be used to sort the vector by the specified key."]} +{"name": "mbpp_113_check_integer", "language": "rs", "prompt": "/// Write a function to check if a string represents an integer or not.\nfn check_integer(text: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_113_check_integer.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "check_integer", "test": "\n\nfn main() {\n let candidate = check_integer;\n assert_eq!(candidate(String::from(\"python\")), false);\n assert_eq!(candidate(String::from(\"1\")), true);\n assert_eq!(candidate(String::from(\"12345\")), true);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check if a string represents an integer or not.\nfn check_integer(text: String) -> bool {\n text.chars().all(|c| c.is_digit(10) || c == '-' || c == '+')\n}"} +{"name": "mbpp_743_rotate_right", "language": "rs", "prompt": "/// Write a function to rotate a given vector by specified number of items to the right direction. https://www.geeksforgeeks.org/rsthon-program-right-rotate-vector-n/\nfn rotate_right(list: Vec, m: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_743_rotate_right.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "rotate_right", "test": "\n\nfn main() {\n let candidate = rotate_right;\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 10], 3), vec![8, 9, 10, 1, 2, 3, 4, 5, 6, 7]);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 10], 2), vec![9, 10, 1, 2, 3, 4, 5, 6, 7, 8]);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 10], 5), vec![6, 7, 8, 9, 10, 1, 2, 3, 4, 5]);\n}\n", "solution": "/// Write a function to rotate a given vector by specified number of items to the right direction. https://www.geeksforgeeks.org/rsthon-program-right-rotate-vector-n/\nfn rotate_right(list: Vec, m: isize) -> Vec {\n let len = list.len();\n let m = if m >= 0 {\n (m as usize) % len\n } else {\n ((len as isize) + m) as usize % len\n };\n let mut result = Vec::with_capacity(len);\n\n for i in 0..len {\n let index = (len - m + i) % len;\n result.push(list[index]);\n }\n\n result\n}", "is_solved": true, "reflections": ["The implementation is incorrect when handling negative rotation values. It does not account for the left rotation when the input `m` is negative, causing the output to be incorrect for such cases."]} +{"name": "mbpp_598_armstrong_number", "language": "rs", "prompt": "/// Write a function to check whether the given number is armstrong or not.\nfn armstrong_number(number: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_598_armstrong_number.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "armstrong_number", "test": "\n\nfn main() {\n let candidate = armstrong_number;\n assert_eq!(candidate(153), true);\n assert_eq!(candidate(259), false);\n assert_eq!(candidate(4458), false);\n}\n", "solution": "/// Write a function to check whether the given number is armstrong or not.\nfn armstrong_number(number: isize) -> bool {\n let num_str = number.to_string();\n let num_len = num_str.len() as u32;\n let mut sum = 0;\n\n for ch in num_str.chars() {\n let digit = ch.to_digit(10).unwrap() as isize;\n sum += digit.pow(num_len);\n }\n\n sum == number\n}", "is_solved": true, "reflections": ["The implementation of the armstrong_number function is incorrect because it considers single-digit numbers as Armstrong numbers. This is due to the fact that the function calculates the sum of the digits raised to the power of the number of digits, and for single-digit numbers, this will always result in the original number. The failed test case with input 9 highlights this issue.", "The implementation of the armstrong_number function is incorrect because it returns false for single-digit numbers, including 0 and 1. However, single-digit numbers are considered Armstrong numbers since the sum of their digits raised to the power of the number of digits (1 in this case) is equal to the number itself.", "The implementation of the armstrong_number function is incorrect because it considers single-digit numbers as Armstrong numbers. The function calculates the sum of the digits raised to the power of the number of digits, and for single-digit numbers, this will always result in the original number, causing the function to return true.", "The implementation is incorrect because it returns false for single-digit numbers, including 0 and 1, which are actually Armstrong numbers. The condition `if number < 10 { return false; }` should be removed or modified to correctly handle single-digit numbers."]} +{"name": "mbpp_229_re_arrange_array", "language": "rs", "prompt": "/// Write a function that takes in a vector and an integer n, and re-arranges the first n elements of the given vector so that all negative elements appear before positive ones, and where the relative order among negative and positive elements is preserved.\nfn re_arrange_array(arr: Vec, n: isize) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_229_re_arrange_array.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "re_arrange_array", "test": "\n\nfn main() {\n let candidate = re_arrange_array;\n assert_eq!(candidate(vec![-1, 2, -3, 4, 5, 6, -7, 8, 9], 9), vec![-1, -3, -7, 4, 5, 6, 2, 8, 9]);\n assert_eq!(candidate(vec![12, -14, -26, 13, 15], 5), vec![-14, -26, 12, 13, 15]);\n assert_eq!(candidate(vec![10, 24, 36, -42, -39, -78, 85], 7), vec![-42, -39, -78, 10, 24, 36, 85]);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a function that takes in a vector and an integer n, and re-arranges the first n elements of the given vector so that all negative elements appear before positive ones, and where the relative order among negative and positive elements is preserved.\nfn re_arrange_array(arr: Vec, n: isize) -> Vec {\n let mut neg: Vec = Vec::new();\n let mut pos: Vec = Vec::new();\n\n for i in 0..n as usize {\n if arr[i] < 0 {\n neg.push(arr[i]);\n } else {\n pos.push(arr[i]);\n }\n }\n\n neg.extend(pos);\n neg.extend(&arr[n as usize..]);\n\n neg\n}"} +{"name": "mbpp_638_wind_chill", "language": "rs", "prompt": "/// Write a function to calculate the wind chill index rounded to the next integer given the wind velocity in km/h and a temperature in celsius.\nfn wind_chill(v: isize, t: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_638_wind_chill.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "wind_chill", "test": "\n\nfn main() {\n let candidate = wind_chill;\n assert_eq!(candidate(120, 35), 40);\n assert_eq!(candidate(40, 20), 19);\n assert_eq!(candidate(10, 8), 6);\n}\n", "solution": "/// Write a function to calculate the wind chill index rounded to the next integer given the wind velocity in km/h and a temperature in celsius.\nfn wind_chill(v: isize, t: isize) -> isize {\n let wind_chill_index = 13.12 + 0.6215 * t as f64 - 11.37 * (v as f64).powf(0.16) + 0.3965 * t as f64 * (v as f64).powf(0.16);\n if wind_chill_index > 0.0 {\n (wind_chill_index + 0.5).floor() as isize\n } else {\n (wind_chill_index - 0.5).ceil() as isize\n }\n}", "is_solved": true, "reflections": ["The implementation of the wind_chill function is incorrect because the formula used to calculate the wind chill index is not properly implemented. The exponents and parentheses are misplaced, leading to incorrect results in the failed test cases.", "The implementation of the wind_chill function is incorrect because it does not produce the expected output for the given test cases. The formula used in the function might be incorrect or the rounding method might not be working as intended. This leads to discrepancies between the expected and actual results in the failed test cases.", "The implementation of the wind_chill function is incorrect because it does not properly calculate the wind chill index according to the given formula. The rounding logic is also flawed, causing the function to return incorrect values for the provided test cases.", "The implementation of the wind_chill function is incorrect because it does not produce the expected output for the given test cases. The formula used in the function might be incorrect or not properly applied, causing the calculated wind chill index to be off by a few integers. This leads to failed assertions in the provided test cases."]} +{"name": "mbpp_608_bell_Number", "language": "rs", "prompt": "/// Write a rsthon function to find nth bell number.\nfn bell_Number(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_608_bell_Number.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "bell_Number", "test": "\n\nfn main() {\n let candidate = bell_Number;\n assert_eq!(candidate(2), 2);\n assert_eq!(candidate(3), 5);\n assert_eq!(candidate(4), 15);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to find nth bell number.\nfn bell_Number(n: isize) -> isize {\n if n == 0 {\n return 1;\n }\n\n let mut bell_matrix = vec![vec![0; (n + 1) as usize]; (n + 1) as usize];\n bell_matrix[0][0] = 1;\n\n for i in 1..=n as usize {\n bell_matrix[i][0] = bell_matrix[i - 1][i - 1];\n\n for j in 1..=i {\n bell_matrix[i][j] = bell_matrix[i - 1][j - 1] + bell_matrix[i][j - 1];\n }\n }\n\n bell_matrix[n as usize][0]\n}"} +{"name": "mbpp_295_sum_div", "language": "rs", "prompt": "/// Write a function to return the sum of all divisors of a number.\nfn sum_div(number: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_295_sum_div.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sum_div", "test": "\n\nfn main() {\n let candidate = sum_div;\n assert_eq!(candidate(8), 7);\n assert_eq!(candidate(12), 16);\n assert_eq!(candidate(7), 1);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a function to return the sum of all divisors of a number.\nfn sum_div(number: isize) -> isize {\n let mut sum = 0;\n\n for i in 1..=(number / 2) {\n if number % i == 0 {\n sum += i;\n }\n }\n\n sum + number\n}"} +{"name": "mbpp_630_get_coordinates", "language": "rs", "prompt": "/// Write a function to extract all the adjacent coordinates of the given coordinate tuple.\nfn get_coordinates(test_tup: (isize, isize)) -> Vec> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_630_get_coordinates.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "get_coordinates", "test": "\n\nfn main() {\n let candidate = get_coordinates;\n assert_eq!(candidate((3, 4)), vec![vec![2, 3], vec![2, 4], vec![2, 5], vec![3, 3], vec![3, 4], vec![3, 5], vec![4, 3], vec![4, 4], vec![4, 5]]);\n assert_eq!(candidate((4, 5)), vec![vec![3, 4], vec![3, 5], vec![3, 6], vec![4, 4], vec![4, 5], vec![4, 6], vec![5, 4], vec![5, 5], vec![5, 6]]);\n assert_eq!(candidate((5, 6)), vec![vec![4, 5], vec![4, 6], vec![4, 7], vec![5, 5], vec![5, 6], vec![5, 7], vec![6, 5], vec![6, 6], vec![6, 7]]);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a function to extract all the adjacent coordinates of the given coordinate tuple.\nfn get_coordinates(test_tup: (isize, isize)) -> Vec> {\n let (x, y) = test_tup;\n let mut coordinates = Vec::new();\n\n coordinates.push(vec![x - 1, y]);\n coordinates.push(vec![x + 1, y]);\n coordinates.push(vec![x, y - 1]);\n coordinates.push(vec![x, y + 1]);\n\n coordinates\n}"} +{"name": "mbpp_579_find_dissimilar", "language": "rs", "prompt": "/// Write a function to find the dissimilar elements in the given two tuples.\nfn find_dissimilar(test_tup1: (isize, isize, isize, isize), test_tup2: (isize, isize, isize, isize)) -> (isize, isize, isize, isize) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_579_find_dissimilar.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_dissimilar", "test": "\n\nfn main() {\n let candidate = find_dissimilar;\n assert_eq!(candidate((3, 4, 5, 6), (5, 7, 4, 10)), (3, 6, 7, 10));\n assert_eq!(candidate((1, 2, 3, 4), (7, 2, 3, 9)), (1, 4, 7, 9));\n assert_eq!(candidate((21, 11, 25, 26), (26, 34, 21, 36)), (34, 36, 11, 25));\n}\n", "is_solved": false, "reflections": ["The implementation is wrong because it tries to call the `iter()` method on an `isize` type, which is not possible as `isize` does not have an `iter()` method. Additionally, the code attempts to index into a tuple using a variable, which is not allowed in Rust.", "The implementation is wrong because it tries to index into tuple elements using the syntax `test_tup1.0[i]`, which is not valid for tuples in Rust. Additionally, the code attempts to index into the `dissimilar_elements` tuple, which is also incorrect. The correct way to access tuple elements is by using the dot notation followed by the index, like `test_tup1.0`.", "The implementation is wrong because it only stores the dissimilar elements from the first tuple and does not calculate the difference between the elements of the two tuples. As a result, the output does not match the expected results in the failed tests.", "The implementation is incorrect because it calculates the difference between the elements of the tuples instead of finding the dissimilar elements. The subtraction operation does not provide the correct result for dissimilar elements, as seen in the failed test case."], "solution": "/// Write a function to find the dissimilar elements in the given two tuples.\nfn find_dissimilar(test_tup1: (isize, isize, isize, isize), test_tup2: (isize, isize, isize, isize)) -> (isize, isize, isize, isize) {\n let mut dissimilar_elements = (0, 0, 0, 0);\n\n dissimilar_elements.0 = if test_tup1.0 != test_tup2.0 { test_tup1.0 } else { 0 };\n dissimilar_elements.1 = if test_tup1.1 != test_tup2.1 { test_tup1.1 } else { 0 };\n dissimilar_elements.2 = if test_tup1.2 != test_tup2.2 { test_tup1.2 } else { 0 };\n dissimilar_elements.3 = if test_tup1.3 != test_tup2.3 { test_tup1.3 } else { 0 };\n\n dissimilar_elements\n}"} +{"name": "mbpp_125_find_length", "language": "rs", "prompt": "/// Write a function to find the maximum difference between the number of 0s and number of 1s in any sub-string of the given binary string.\nfn find_length(string: String) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_125_find_length.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_length", "test": "\n\nfn main() {\n let candidate = find_length;\n assert_eq!(candidate(String::from(\"11000010001\")), 6);\n assert_eq!(candidate(String::from(\"10111\")), 1);\n assert_eq!(candidate(String::from(\"11011101100101\")), 2);\n}\n", "solution": "/// Write a function to find the maximum difference between the number of 0s and number of 1s in any sub-string of the given binary string.\nfn find_length(string: String) -> isize {\n let mut max_diff = 0;\n let mut current_diff: i32 = 0;\n\n for c in string.chars() {\n if c == '0' {\n current_diff += 1;\n } else if c == '1' {\n current_diff -= 1;\n }\n\n max_diff = std::cmp::max(max_diff, current_diff.abs());\n\n if current_diff < 0 {\n current_diff = 0;\n }\n }\n\n max_diff as isize\n}", "is_solved": true, "reflections": ["The current implementation is incorrect because it only considers the difference between the number of 0s and 1s in a continuous sequence, resetting the current_diff to 0 whenever it becomes negative. This approach fails to account for sub-strings with alternating 0s and 1s, where the difference between the number of 0s and 1s is 0.", "The implementation is incorrect because it calculates the maximum difference between the number of 0s and 1s in the entire string, rather than in any sub-string. Additionally, there is an error due to the ambiguous numeric type for `current_diff`. The type should be specified, such as `isize`, to resolve this issue.", "The implementation is incorrect because it only considers the difference between the number of 0s and 1s when there are more 0s than 1s in a sub-string. It does not account for cases where there are equal numbers of 0s and 1s, leading to incorrect results for the failed tests.", "The implementation is incorrect because it has an unclosed delimiter error and an ambiguous numeric type error. The unclosed delimiter error is due to mismatched indentation, and the ambiguous numeric type error occurs because the `abs()` method is called on `current_diff` without specifying its type. To fix these issues, correct the indentation and specify a type for `current_diff`, such as `i32`."]} +{"name": "mbpp_771_check_expression", "language": "rs", "prompt": "/// Write a function to check if the given expression is balanced or not. https://www.geeksforgeeks.org/check-for-balanced-parentheses-in-an-expression/\nfn check_expression(exp: String) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_771_check_expression.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "check_expression", "test": "\n\nfn main() {\n let candidate = check_expression;\n assert_eq!(candidate(String::from(\"{()}[{}]\")), true);\n assert_eq!(candidate(String::from(\"{()}[{]\")), false);\n assert_eq!(candidate(String::from(\"{()}[{}][]({})\")), true);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check if the given expression is balanced or not. https://www.geeksforgeeks.org/check-for-balanced-parentheses-in-an-expression/\nfn check_expression(exp: String) -> bool {\n let mut stack: Vec = Vec::new();\n\n for ch in exp.chars() {\n match ch {\n '(' | '[' | '{' => stack.push(ch),\n ')' | ']' | '}' => {\n if stack.is_empty() {\n return false;\n }\n let top = stack.pop().unwrap();\n if !is_matching_pair(top, ch) {\n return false;\n }\n }\n _ => continue,\n }\n }\n\n stack.is_empty()\n}\n\nfn is_matching_pair(open: char, close: char) -> bool {\n match (open, close) {\n ('(', ')') | ('[', ']') | ('{', '}') => true,\n _ => false,\n }\n}"} +{"name": "mbpp_801_test_three_equal", "language": "rs", "prompt": "/// Write a rsthon function to count the number of equal numbers from three given integers.\nfn test_three_equal(x: isize, y: isize, z: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_801_test_three_equal.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "test_three_equal", "test": "\n\nfn main() {\n let candidate = test_three_equal;\n assert_eq!(candidate(1, 1, 1), 3);\n assert_eq!(candidate(-1, -2, -3), 0);\n assert_eq!(candidate(1, 2, 2), 2);\n}\n", "solution": "/// Write a rsthon function to count the number of equal numbers from three given integers.\nfn test_three_equal(x: isize, y: isize, z: isize) -> isize {\n if x == y && y == z {\n 3\n } else if x == y || y == z || x == z {\n 2\n } else {\n 0\n }\n}", "is_solved": true, "reflections": ["The implementation of the test_three_equal function is incorrect because it counts the number of equal pairs instead of the number of equal numbers. When there are only two equal numbers, the function returns 1 instead of the expected 2. This causes the failed test cases where only two numbers are equal."]} +{"name": "mbpp_389_find_lucas", "language": "rs", "prompt": "/// Write a function to find the n'th lucas number.\nfn find_lucas(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_389_find_lucas.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_lucas", "test": "\n\nfn main() {\n let candidate = find_lucas;\n assert_eq!(candidate(9), 76);\n assert_eq!(candidate(4), 7);\n assert_eq!(candidate(3), 4);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the n'th lucas number.\nfn find_lucas(n: isize) -> isize {\n if n == 0 {\n return 2;\n } else if n == 1 {\n return 1;\n } else {\n let mut a = 2;\n let mut b = 1;\n let mut lucas = 0;\n\n for _ in 2..=n {\n lucas = a + b;\n a = b;\n b = lucas;\n }\n\n return lucas;\n }\n}"} +{"name": "mbpp_102_snake_to_camel", "language": "rs", "prompt": "/// Write a function to convert a snake case string to camel case string.\nfn snake_to_camel(word: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_102_snake_to_camel.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "snake_to_camel", "test": "\n\nfn main() {\n let candidate = snake_to_camel;\n assert_eq!(candidate(String::from(\"python_program\")), String::from(\"PythonProgram\"));\n assert_eq!(candidate(String::from(\"python_language\")), String::from(\"PythonLanguage\"));\n assert_eq!(candidate(String::from(\"programming_language\")), String::from(\"ProgrammingLanguage\"));\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a function to convert a snake case string to camel case string.\nfn snake_to_camel(word: String) -> String {\n let mut camel_word = String::new();\n let mut to_upper = false;\n\n for c in word.chars() {\n if c == '_' {\n to_upper = true;\n } else if to_upper {\n camel_word.push(c.to_ascii_uppercase());\n to_upper = false;\n } else {\n camel_word.push(c);\n }\n }\n\n camel_word\n}"} +{"name": "mbpp_604_reverse_words", "language": "rs", "prompt": "/// Write a function to reverse words seperated by spaces in a given string.\nfn reverse_words(s: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_604_reverse_words.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "reverse_words", "test": "\n\nfn main() {\n let candidate = reverse_words;\n assert_eq!(candidate(String::from(\"python program\")), String::from(\"program python\"));\n assert_eq!(candidate(String::from(\"java language\")), String::from(\"language java\"));\n assert_eq!(candidate(String::from(\"indian man\")), String::from(\"man indian\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to reverse words seperated by spaces in a given string.\nfn reverse_words(s: String) -> String {\n let words: Vec<&str> = s.split_whitespace().collect();\n let mut reversed_words = Vec::new();\n\n for word in words.iter().rev() {\n reversed_words.push(*word);\n }\n\n reversed_words.join(\" \")\n}"} +{"name": "mbpp_624_is_upper", "language": "rs", "prompt": "/// Write a rsthon function to convert a given string to uppercase.\nfn is_upper(string: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_624_is_upper.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_upper", "test": "\n\nfn main() {\n let candidate = is_upper;\n assert_eq!(candidate(String::from(\"person\")), String::from(\"PERSON\"));\n assert_eq!(candidate(String::from(\"final\")), String::from(\"FINAL\"));\n assert_eq!(candidate(String::from(\"Valid\")), String::from(\"VALID\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to convert a given string to uppercase.\nfn is_upper(string: String) -> String {\n string.to_uppercase()\n}"} +{"name": "mbpp_558_digit_distance_nums", "language": "rs", "prompt": "/// Write a rsthon function to find the sum of the per-digit difference between two integers.\nfn digit_distance_nums(n1: isize, n2: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_558_digit_distance_nums.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "digit_distance_nums", "test": "\n\nfn main() {\n let candidate = digit_distance_nums;\n assert_eq!(candidate(1, 2), 1);\n assert_eq!(candidate(23, 56), 6);\n assert_eq!(candidate(123, 256), 7);\n}\n", "solution": "/// Write a rsthon function to find the sum of the per-digit difference between two integers.\nfn digit_distance_nums(n1: isize, n2: isize) -> isize {\n let n1_digits = n1.to_string().chars().map(|c| c.to_digit(10).unwrap() as isize).collect::>();\n let n2_digits = n2.to_string().chars().map(|c| c.to_digit(10).unwrap() as isize).collect::>();\n\n let mut sum = 0;\n for (n1_digit, n2_digit) in n1_digits.iter().zip(n2_digits.iter()) {\n let diff = (n1_digit - n2_digit).abs();\n sum += diff;\n }\n\n sum\n}", "is_solved": true, "reflections": ["The implementation of the digit_distance_nums function is incorrect because it calculates the sum of the absolute differences between the corresponding digits of the two input numbers. However, the problem statement asks for the sum of the per-digit differences, which means the sum of the differences between each pair of digits in the two numbers. The current implementation does not account for this distinction, leading to incorrect results in the failed tests.", "The implementation is incorrect because it calculates the sum of differences between all pairs of digits from the two numbers, excluding the ones with the same index, and then subtracts the sum of differences between digits with the same index. This approach does not provide the correct sum of per-digit differences between the two integers, as demonstrated by the failed tests.", "The implementation of the digit_distance_nums function is incorrect because it calculates the sum of the absolute differences between the corresponding digits of the two input numbers. However, the problem statement asks for the sum of the per-digit differences, which means we should be summing the differences between each digit in the first number and each digit in the second number. The current implementation only considers the differences between digits at the same position in both numbers.", "The implementation is incorrect because it calculates the sum of differences between all possible pairs of digits from the two numbers, instead of comparing the digits at the same position in both numbers. This leads to an inflated sum, causing the failed test cases."]} +{"name": "mbpp_615_average_tuple", "language": "rs", "prompt": "/// Write a function which takes a vectors of vectors and returns the average value for each subvector as a vector.\nfn average_tuple(nums: Vec>) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_615_average_tuple.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "average_tuple", "test": "\n\nfn main() {\n let candidate = average_tuple;\n assert_eq!(candidate(vec![vec![10, 10, 10, 12], vec![30, 45, 56, 45], vec![81, 80, 39, 32], vec![1, 2, 3, 4]]), vec![30.5, 34.25, 27.0, 23.25]);\n assert_eq!(candidate(vec![vec![1, 1, -5], vec![30, -15, 56], vec![81, -60, -39], vec![-10, 2, 3]]), vec![25.5, -18.0, 3.75]);\n assert_eq!(candidate(vec![vec![100, 100, 100, 120], vec![300, 450, 560, 450], vec![810, 800, 390, 320], vec![10, 20, 30, 40]]), vec![305.0, 342.5, 270.0, 232.5]);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a function which takes a vectors of vectors and returns the average value for each subvector as a vector.\nfn average_tuple(nums: Vec>) -> Vec {\n let mut averages: Vec = Vec::new();\n\n for subvector in nums {\n let sum: isize = subvector.iter().sum();\n let count = subvector.len() as f64;\n let average = sum as f64 / count;\n averages.push(average);\n }\n\n averages\n}"} +{"name": "mbpp_166_find_even_pair", "language": "rs", "prompt": "/// Write a function that counts the number of pairs of integers in a vector that xor to an even number.\nfn find_even_pair(A: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_166_find_even_pair.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_even_pair", "test": "\n\nfn main() {\n let candidate = find_even_pair;\n assert_eq!(candidate(vec![5, 4, 7, 2, 1]), 4);\n assert_eq!(candidate(vec![7, 2, 8, 1, 0, 5, 11]), 9);\n assert_eq!(candidate(vec![1, 2, 3]), 1);\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because it checks if the result of the XOR operation is divisible by 2 to determine if it's even. However, this approach does not guarantee the correct count of pairs with even XOR results. Instead, the function should check if both numbers in the pair have the same parity (both even or both odd) to ensure the XOR result is even.", "The implementation is incorrect because it checks if both numbers in a pair are even or both are odd, instead of checking if their XOR result is even. This leads to incorrect counts for pairs that XOR to an even number when one number is even and the other is odd.", "The implementation is incorrect because it checks if the result of the XOR operation between two integers is divisible by 2, instead of checking if the result is an even number. This leads to incorrect counts of pairs that XOR to an even number, causing the failed test cases.", "The implementation is incorrect because it counts pairs where the XOR result is an odd number instead of an even number. The condition `(A[i] ^ A[j]) & 1 == 0` checks if the least significant bit is 0, which indicates an odd number. To fix the implementation, the condition should check for even numbers by comparing the least significant bit to 1."], "solution": "/// Write a function that counts the number of pairs of integers in a vector that xor to an even number.\nfn find_even_pair(A: Vec) -> isize {\n let mut count = 0;\n\n for i in 0..A.len() {\n for j in i + 1..A.len() {\n if (A[i] ^ A[j]) & 1 == 1 {\n count += 1;\n }\n }\n }\n\n count\n}"} +{"name": "mbpp_58_opposite_Signs", "language": "rs", "prompt": "/// Write a rsthon function to check whether the given two integers have opposite sign or not.\nfn opposite_Signs(x: isize, y: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_58_opposite_Signs.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "opposite_Signs", "test": "\n\nfn main() {\n let candidate = opposite_Signs;\n assert_eq!(candidate(1, -2), true);\n assert_eq!(candidate(3, 2), false);\n assert_eq!(candidate(-10, -10), false);\n assert_eq!(candidate(-2, 2), true);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to check whether the given two integers have opposite sign or not.\nfn opposite_Signs(x: isize, y: isize) -> bool {\n if x < 0 && y > 0 || x > 0 && y < 0 {\n return true;\n } else {\n return false;\n }\n}"} +{"name": "mbpp_569_sort_sublists", "language": "rs", "prompt": "/// Write a function to sort each subvector of strings in a given vector of vectors.\nfn sort_sublists(list1: Vec>) -> Vec> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_569_sort_sublists.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "sort_sublists", "test": "\n\nfn main() {\n let candidate = sort_sublists;\n assert_eq!(candidate(vec![vec![String::from(\"green\"), String::from(\"orange\")], vec![String::from(\"black\"), String::from(\"white\")], vec![String::from(\"white\"), String::from(\"black\"), String::from(\"orange\")]]), vec![vec![String::from(\"green\"), String::from(\"orange\")], vec![String::from(\"black\"), String::from(\"white\")], vec![String::from(\"black\"), String::from(\"orange\"), String::from(\"white\")]]);\n assert_eq!(candidate(vec![vec![String::from(\"green\"), String::from(\"orange\")], vec![String::from(\"black\")], vec![String::from(\"green\"), String::from(\"orange\")], vec![String::from(\"white\")]]), vec![vec![String::from(\"green\"), String::from(\"orange\")], vec![String::from(\"black\")], vec![String::from(\"green\"), String::from(\"orange\")], vec![String::from(\"white\")]]);\n assert_eq!(candidate(vec![vec![String::from(\"a\"), String::from(\"b\")], vec![String::from(\"d\"), String::from(\"c\")], vec![String::from(\"g\"), String::from(\"h\")], vec![String::from(\"f\"), String::from(\"e\")]]), vec![vec![String::from(\"a\"), String::from(\"b\")], vec![String::from(\"c\"), String::from(\"d\")], vec![String::from(\"g\"), String::from(\"h\")], vec![String::from(\"e\"), String::from(\"f\")]]);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to sort each subvector of strings in a given vector of vectors.\nfn sort_sublists(list1: Vec>) -> Vec> {\n let mut sorted_list = list1.clone();\n for sublist in sorted_list.iter_mut() {\n sublist.sort();\n }\n sorted_list\n}"} +{"name": "mbpp_255_combinations_colors", "language": "rs", "prompt": "/// Write a function that takes in a vector and length n, and generates all combinations (with repetition) of the elements of the vector and returns a vector with a vector for each combination.\nfn combinations_colors(l: Vec, n: isize) -> Vec> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_255_combinations_colors.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "combinations_colors", "test": "\n\nfn main() {\n let candidate = combinations_colors;\n assert_eq!(candidate(vec![String::from(\"Red\"), String::from(\"Green\"), String::from(\"Blue\")], 1), vec![vec![String::from(\"Red\")], vec![String::from(\"Green\")], vec![String::from(\"Blue\")]]);\n assert_eq!(candidate(vec![String::from(\"Red\"), String::from(\"Green\"), String::from(\"Blue\")], 2), vec![vec![String::from(\"Red\"), String::from(\"Red\")], vec![String::from(\"Red\"), String::from(\"Green\")], vec![String::from(\"Red\"), String::from(\"Blue\")], vec![String::from(\"Green\"), String::from(\"Green\")], vec![String::from(\"Green\"), String::from(\"Blue\")], vec![String::from(\"Blue\"), String::from(\"Blue\")]]);\n assert_eq!(candidate(vec![String::from(\"Red\"), String::from(\"Green\"), String::from(\"Blue\")], 3), vec![vec![String::from(\"Red\"), String::from(\"Red\"), String::from(\"Red\")], vec![String::from(\"Red\"), String::from(\"Red\"), String::from(\"Green\")], vec![String::from(\"Red\"), String::from(\"Red\"), String::from(\"Blue\")], vec![String::from(\"Red\"), String::from(\"Green\"), String::from(\"Green\")], vec![String::from(\"Red\"), String::from(\"Green\"), String::from(\"Blue\")], vec![String::from(\"Red\"), String::from(\"Blue\"), String::from(\"Blue\")], vec![String::from(\"Green\"), String::from(\"Green\"), String::from(\"Green\")], vec![String::from(\"Green\"), String::from(\"Green\"), String::from(\"Blue\")], vec![String::from(\"Green\"), String::from(\"Blue\"), String::from(\"Blue\")], vec![String::from(\"Blue\"), String::from(\"Blue\"), String::from(\"Blue\")]]);\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because the order of the combinations in the output does not match the expected order in the test cases. The algorithm generates combinations in a different order than the one specified in the test cases, causing the assertions to fail.", "The implementation of the `combinations_colors` function is incorrect because it does not generate all possible combinations with repetition. The issue lies in the loop where it only considers elements with an index greater than or equal to the current index, causing it to miss some combinations. This is evident in the failed test cases where combinations like [\"blue\", \"red\"] and [\"green\", \"red\"] are missing from the output."], "solution": "/// Write a function that takes in a vector and length n, and generates all combinations (with repetition) of the elements of the vector and returns a vector with a vector for each combination.\nfn combinations_colors(l: Vec, n: isize) -> Vec> {\n if n <= 0 {\n return vec![vec![]];\n }\n\n let mut result = Vec::new();\n let mut stack = vec![(0, vec![])];\n\n while let Some((index, mut combination)) = stack.pop() {\n if combination.len() == n as usize {\n result.push(combination);\n } else {\n for i in (0..l.len()).rev() {\n let mut new_combination = combination.clone();\n new_combination.push(l[i].clone());\n stack.push((index, new_combination));\n }\n }\n }\n\n result\n}"} +{"name": "mbpp_619_move_num", "language": "rs", "prompt": "/// Write a function to move all the numbers to the end of the given string.\nfn move_num(test_str: String) -> String {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_619_move_num.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "move_num", "test": "\n\nfn main() {\n let candidate = move_num;\n assert_eq!(candidate(String::from(\"I1love143you55three3000thousand\")), String::from(\"Iloveyouthreethousand1143553000\"));\n assert_eq!(candidate(String::from(\"Avengers124Assemble\")), String::from(\"AvengersAssemble124\"));\n assert_eq!(candidate(String::from(\"Its11our12path13to14see15things16do17things\")), String::from(\"Itsourpathtoseethingsdothings11121314151617\"));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to move all the numbers to the end of the given string.\nfn move_num(test_str: String) -> String {\n let mut num_str = String::new();\n let mut non_num_str = String::new();\n\n for c in test_str.chars() {\n if c.is_numeric() {\n num_str.push(c);\n } else {\n non_num_str.push(c);\n }\n }\n\n non_num_str.push_str(&num_str);\n non_num_str\n}"} +{"name": "mbpp_249_intersection_array", "language": "rs", "prompt": "/// Write a function to find the intersection of two vectors.\nfn intersection_array(array_nums1: Vec, array_nums2: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_249_intersection_array.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "intersection_array", "test": "\n\nfn main() {\n let candidate = intersection_array;\n assert_eq!(candidate(vec![1, 2, 3, 5, 7, 8, 9, 10], vec![1, 2, 4, 8, 9]), vec![1, 2, 8, 9]);\n assert_eq!(candidate(vec![1, 2, 3, 5, 7, 8, 9, 10], vec![3, 5, 7, 9]), vec![3, 5, 7, 9]);\n assert_eq!(candidate(vec![1, 2, 3, 5, 7, 8, 9, 10], vec![10, 20, 30, 40]), vec![10]);\n}\n", "solution": "/// Write a function to find the intersection of two vectors.\nfn intersection_array(array_nums1: Vec, array_nums2: Vec) -> Vec {\n use std::collections::HashSet;\n\n let mut result: Vec = Vec::new();\n let set_nums1: HashSet = array_nums1.into_iter().collect();\n let set_nums2: HashSet = array_nums2.into_iter().collect();\n\n for num in set_nums1.intersection(&set_nums2) {\n result.push(*num);\n }\n\n result.sort();\n result\n}", "is_solved": true, "reflections": ["The implementation is wrong because the `HashSet` type is not found in the current scope. To fix this issue, the `HashSet` struct needs to be imported from the `std::collections` module by adding `use std::collections::HashSet;` at the beginning of the code."]} +{"name": "mbpp_250_count_X", "language": "rs", "prompt": "/// Write a rsthon function that takes in a tuple and an element and counts the occcurences of the element in the vector.\nfn count_X(tup: Vec, x: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_250_count_X.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "count_X", "test": "\n\nfn main() {\n let candidate = count_X;\n assert_eq!(candidate(vec![10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2], 4), 0);\n assert_eq!(candidate(vec![10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2], 10), 3);\n assert_eq!(candidate(vec![10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2], 8), 4);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function that takes in a tuple and an element and counts the occcurences of the element in the vector.\nfn count_X(tup: Vec, x: isize) -> isize {\n let mut count = 0;\n for item in tup.iter() {\n if *item == x {\n count += 1;\n }\n }\n count\n}"} +{"name": "mbpp_622_get_median", "language": "rs", "prompt": "/// Write a function to find the median of two sorted vectors of same size.\nfn get_median(arr1: Vec, arr2: Vec, n: isize) -> f64 {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_622_get_median.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "get_median", "test": "\n\nfn main() {\n let candidate = get_median;\n assert_eq!(candidate(vec![1, 12, 15, 26, 38], vec![2, 13, 17, 30, 45], 5), 16.0);\n assert_eq!(candidate(vec![2, 4, 8, 9], vec![7, 13, 19, 28], 4), 8.5);\n assert_eq!(candidate(vec![3, 6, 14, 23, 36, 42], vec![2, 18, 27, 39, 49, 55], 6), 25.0);\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because it assumes that the median will always be the average of the two middle elements after merging the two sorted vectors. However, this is not always the case, as demonstrated by the failed test case where the median is actually one of the middle elements (10) and not the average of the two middle elements (10.5).", "The implementation is incorrect because it does not properly handle cases where the median is formed by elements from both input arrays. The function only updates m1 and m2 based on the smallest element found in either array, which can lead to incorrect median calculations when elements from both arrays contribute to the median. This is evident in the failed test cases where the expected median is not equal to the calculated median.", "The implementation is incorrect because it causes an \"index out of bounds\" error when trying to access elements in the input vectors. This is due to the loop running for 2 * n iterations, which can cause the index i or j to go beyond the length of the input vectors.", "The implementation is incorrect because it calculates the median based on the assumption that the input vectors are of the same size and that the median is always at the middle of the combined sorted array. However, this approach fails when the median is not at the middle of the combined array, as seen in the failed test cases. The algorithm needs to be modified to correctly find the median of the two sorted vectors regardless of their relative ordering."], "solution": "/// Write a function to find the median of two sorted vectors of same size.\nfn get_median(arr1: Vec, arr2: Vec, n: isize) -> f64 {\n let mut i = 0;\n let mut j = 0;\n let mut m1 = -1;\n let mut m2 = -1;\n\n for _ in 0..=(n as usize) {\n if i == n as usize {\n m1 = m2;\n m2 = arr2[j];\n j += 1;\n } else if j == n as usize {\n m1 = m2;\n m2 = arr1[i];\n i += 1;\n } else if arr1[i] < arr2[j] {\n m1 = m2;\n m2 = arr1[i];\n i += 1;\n } else {\n m1 = m2;\n m2 = arr2[j];\n j += 1;\n }\n }\n\n if (n % 2) == 0 {\n return (m1 as f64 + m2 as f64) / 2.0;\n } else {\n return m2 as f64;\n }\n}"} +{"name": "mbpp_80_tetrahedral_number", "language": "rs", "prompt": "/// Write a function to find the nth tetrahedral number.\nfn tetrahedral_number(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_80_tetrahedral_number.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "tetrahedral_number", "test": "\n\nfn main() {\n let candidate = tetrahedral_number;\n assert_eq!(candidate(5), 35);\n assert_eq!(candidate(6), 56);\n assert_eq!(candidate(7), 84);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the nth tetrahedral number.\nfn tetrahedral_number(n: isize) -> isize {\n if n <= 0 {\n return 0;\n }\n n * (n + 1) * (n + 2) / 6\n}"} +{"name": "mbpp_780_find_combinations", "language": "rs", "prompt": "/// Write a function to find the combinations of sums with tuples in the given tuple vector. https://www.geeksforgeeks.org/rsthon-combinations-of-sum-with-tuples-in-tuple-vector/\nfn find_combinations(test_list: Vec<(isize, isize)>) -> Vec<(isize, isize)> {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_780_find_combinations.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_combinations", "test": "\n\nfn main() {\n let candidate = find_combinations;\n assert_eq!(candidate(vec![(2, 4), (6, 7), (5, 1), (6, 10)]), vec![(8, 11), (7, 5), (8, 14), (11, 8), (12, 17), (11, 11)]);\n assert_eq!(candidate(vec![(3, 5), (7, 8), (6, 2), (7, 11)]), vec![(10, 13), (9, 7), (10, 16), (13, 10), (14, 19), (13, 13)]);\n assert_eq!(candidate(vec![(4, 6), (8, 9), (7, 3), (8, 12)]), vec![(12, 15), (11, 9), (12, 18), (15, 12), (16, 21), (15, 15)]);\n}\n", "is_solved": false, "reflections": [], "solution": "/// Write a function to find the combinations of sums with tuples in the given tuple vector. https://www.geeksforgeeks.org/rsthon-combinations-of-sum-with-tuples-in-tuple-vector/\nfn find_combinations(test_list: Vec<(isize, isize)>) -> Vec<(isize, isize)> {\n let mut result: Vec<(isize, isize)> = Vec::new();\n\n for i in 0..test_list.len() {\n for j in i + 1..test_list.len() {\n let sum1 = test_list[i].0 + test_list[j].0;\n let sum2 = test_list[i].1 + test_list[j].1;\n result.push((sum1, sum2));\n }\n }\n\n result.sort();\n result.dedup();\n result\n}"} +{"name": "mbpp_733_find_first_occurrence", "language": "rs", "prompt": "/// Write a function to find the index of the first occurrence of a given number in a sorted vector.\nfn find_first_occurrence(A: Vec, x: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_733_find_first_occurrence.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "find_first_occurrence", "test": "\n\nfn main() {\n let candidate = find_first_occurrence;\n assert_eq!(candidate(vec![2, 5, 5, 5, 6, 6, 8, 9, 9, 9], 5), 1);\n assert_eq!(candidate(vec![2, 3, 5, 5, 6, 6, 8, 9, 9, 9], 5), 2);\n assert_eq!(candidate(vec![2, 4, 1, 5, 6, 6, 8, 9, 9, 9], 6), 4);\n}\n", "solution": "/// Write a function to find the index of the first occurrence of a given number in a sorted vector.\nfn find_first_occurrence(A: Vec, x: isize) -> isize {\n if A.is_empty() {\n return -1;\n }\n\n let mut left = 0;\n let mut right = A.len() - 1;\n let mut result = -1;\n\n while left <= right {\n let mid = left + (right - left) / 2;\n\n if A[mid] == x {\n result = mid as isize;\n if mid == 0 {\n break;\n }\n right = mid - 1;\n } else if A[mid] < x {\n left = mid + 1;\n } else {\n right = mid - 1;\n }\n }\n\n result\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it causes an integer overflow when updating the value of `right` in the case where the target value is found at the first index. When `mid` is 0 and `A[mid]` equals the target value, the code tries to set `right` to `mid - 1`, which results in an overflow since `right` is an unsigned integer."]} +{"name": "mbpp_6_differ_At_One_Bit_Pos", "language": "rs", "prompt": "/// Write a rsthon function to check whether the two numbers differ at one bit position only or not.\nfn differ_At_One_Bit_Pos(a: isize, b: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_6_differ_At_One_Bit_Pos.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "differ_At_One_Bit_Pos", "test": "\n\nfn main() {\n let candidate = differ_At_One_Bit_Pos;\n assert_eq!(candidate(13, 9), true);\n assert_eq!(candidate(15, 8), false);\n assert_eq!(candidate(2, 4), false);\n assert_eq!(candidate(2, 3), true);\n assert_eq!(candidate(5, 1), true);\n assert_eq!(candidate(1, 5), true);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a rsthon function to check whether the two numbers differ at one bit position only or not.\nfn differ_At_One_Bit_Pos(a: isize, b: isize) -> bool {\n let xor = a ^ b;\n return xor.count_ones() == 1;\n}"} +{"name": "mbpp_762_check_monthnumber_number", "language": "rs", "prompt": "/// Write a function to check whether the given month number contains 30 days or not. Months are given as number from 1 to 12.\nfn check_monthnumber_number(monthnum3: isize) -> bool {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_762_check_monthnumber_number.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "check_monthnumber_number", "test": "\n\nfn main() {\n let candidate = check_monthnumber_number;\n assert_eq!(candidate(6), true);\n assert_eq!(candidate(2), false);\n assert_eq!(candidate(12), false);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to check whether the given month number contains 30 days or not. Months are given as number from 1 to 12.\nfn check_monthnumber_number(monthnum3: isize) -> bool {\n match monthnum3 {\n 4 | 6 | 9 | 11 => true,\n _ => false,\n }\n}"} +{"name": "mbpp_625_swap_List", "language": "rs", "prompt": "/// Write a rsthon function to interchange the first and last element in a given vector.\nfn swap_List(newList: Vec) -> Vec {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_625_swap_List.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "swap_List", "test": "\n\nfn main() {\n let candidate = swap_List;\n assert_eq!(candidate(vec![1, 2, 3]), vec![3, 2, 1]);\n assert_eq!(candidate(vec![1, 2, 3, 4, 4]), vec![4, 2, 3, 4, 1]);\n assert_eq!(candidate(vec![4, 5, 6]), vec![6, 5, 4]);\n}\n", "solution": "/// Write a rsthon function to interchange the first and last element in a given vector.\nfn swap_List(newList: Vec) -> Vec {\n if newList.is_empty() {\n return newList;\n }\n\n let mut swapped_list = newList.clone();\n let first_element = swapped_list[0];\n let last_element = swapped_list[swapped_list.len() - 1];\n let last_index = swapped_list.len() - 1;\n\n swapped_list[0] = last_element;\n swapped_list[last_index] = first_element;\n\n swapped_list\n}", "is_solved": true, "reflections": ["The implementation is wrong because it tries to borrow `swapped_list` as both mutable and immutable at the same time, which is not allowed in Rust. This occurs when trying to access the last element of the vector to set its value to `first_element`. To fix this issue, the length of the vector should be stored in a separate variable before performing the swap operation."]} +{"name": "mbpp_392_get_max_sum", "language": "rs", "prompt": "/// Write a function to find the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\nfn get_max_sum(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_392_get_max_sum.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "get_max_sum", "test": "\n\nfn main() {\n let candidate = get_max_sum;\n assert_eq!(candidate(60), 106);\n assert_eq!(candidate(10), 12);\n assert_eq!(candidate(2), 2);\n}\n", "solution": "/// Write a function to find the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\nfn get_max_sum(n: isize) -> isize {\n if n <= 0 {\n return 0;\n }\n\n let n2 = get_max_sum((n as f64 / 2.0).ceil() as isize);\n let n3 = get_max_sum((n as f64 / 3.0).ceil() as isize);\n let n4 = get_max_sum((n as f64 / 4.0).ceil() as isize);\n let n5 = get_max_sum((n as f64 / 5.0).ceil() as isize);\n\n n.max(n2 + n3 + n4 + n5)\n}", "is_solved": false, "reflections": ["The implementation of the get_max_sum function is incorrect because it does not account for the possibility of integer division truncation, which can lead to suboptimal results. This is evident in the failed test case where the expected result is 94, but the function returns 86."]} +{"name": "mbpp_784_mul_even_odd", "language": "rs", "prompt": "/// Write a function to find the product of first even and odd number of a given vector.\nfn mul_even_odd(list1: Vec) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_784_mul_even_odd.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "mul_even_odd", "test": "\n\nfn main() {\n let candidate = mul_even_odd;\n assert_eq!(candidate(vec![1, 3, 5, 7, 4, 1, 6, 8]), 4);\n assert_eq!(candidate(vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 10]), 2);\n assert_eq!(candidate(vec![1, 5, 7, 9, 10]), 10);\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because it only finds the first even and odd numbers in the given vector and multiplies them. However, the problem statement asks for the product of the first even and odd numbers, which means the product of all even numbers and all odd numbers separately. The current implementation does not account for this, causing the failed test cases.", "The implementation is incorrect because it calculates the product of all even numbers and the product of all odd numbers in the given vector, and then multiplies these two products together. However, the task requires finding the product of the first even and first odd number in the vector. The current implementation does not account for this, leading to incorrect results in the failed tests.", "The implementation is incorrect because it returns 0 when either the first even or odd number is not found in the given vector. This causes the function to fail in cases where the vector contains only even or odd numbers. Additionally, the function calculates the product of the first even and odd numbers found, rather than the product of the first even and first odd numbers in the vector.", "The implementation is incorrect because it returns 1 when either an even or an odd number is not found in the given vector. This causes the function to fail in cases where the vector contains only even or only odd numbers. Additionally, the function calculates the product of the first even and odd numbers, rather than the product of all even and odd numbers in the vector."], "solution": "/// Write a function to find the product of first even and odd number of a given vector.\nfn mul_even_odd(list1: Vec) -> isize {\n let mut even_product: isize = 1;\n let mut odd_product: isize = 1;\n\n for num in list1 {\n if num % 2 == 0 {\n even_product *= num;\n } else {\n odd_product *= num;\n }\n }\n\n even_product * odd_product\n}"} +{"name": "mbpp_109_odd_Equivalent", "language": "rs", "prompt": "/// Write a rsthon function to find the number of numbers with an odd value when rotating a binary string the given number of times.\nfn odd_Equivalent(s: String, n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_109_odd_Equivalent.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "odd_Equivalent", "test": "\n\nfn main() {\n let candidate = odd_Equivalent;\n assert_eq!(candidate(String::from(\"011001\"), 6), 3);\n assert_eq!(candidate(String::from(\"11011\"), 5), 4);\n assert_eq!(candidate(String::from(\"1010\"), 4), 2);\n}\n", "is_solved": false, "reflections": ["The implementation is incorrect because it only rotates the binary string 'n' times, which may lead to duplicate rotations and incorrect counting of odd decimal values. The function should instead rotate the binary string until all unique rotations are considered, ensuring that each rotation is only counted once.", "The implementation is incorrect because it only considers rotations equal to the length of the input string. This causes it to miss some unique rotations when the given number of rotations 'n' is not equal to the length of the input string. As a result, the function fails to count all odd values for certain test cases.", "The implementation is incorrect because it only considers rotations up to the given number 'n', instead of considering all unique rotations of the binary string. This leads to an incorrect count of odd decimal values, as some unique rotations are not being considered in the calculation.", "The implementation is incorrect because it only considers rotations equal to the length of the string, which may not cover all possible rotations specified by the input 'n'. Additionally, the function does not account for duplicate rotations when 'n' is greater than the length of the string. This leads to incorrect counts of odd decimal values for certain test cases."], "solution": "/// Write a rsthon function to find the number of numbers with an odd value when rotating a binary string the given number of times.\nfn odd_Equivalent(s: String, n: isize) -> isize {\n let mut count = 0;\n let mut s = s.chars().collect::>();\n let len = s.len();\n let mut unique_rotations = std::collections::HashSet::new();\n\n for i in 0..n {\n let index = (i as usize) % len;\n let last_char = s.remove(index);\n s.push(last_char);\n\n let binary_string = s.iter().collect::();\n if unique_rotations.insert(binary_string.clone()) {\n let decimal_value = isize::from_str_radix(&binary_string, 2).unwrap();\n\n if decimal_value % 2 != 0 {\n count += 1;\n }\n }\n }\n\n count\n}"} +{"name": "mbpp_95_Find_Min_Length", "language": "rs", "prompt": "/// Write a rsthon function to find the length of the smallest vector in a vector of vectors.\nfn Find_Min_Length(lst: Vec>) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_95_Find_Min_Length.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "Find_Min_Length", "test": "\n\nfn main() {\n let candidate = Find_Min_Length;\n assert_eq!(candidate(vec![vec![1], vec![1, 2]]), 1);\n assert_eq!(candidate(vec![vec![1, 2], vec![1, 2, 3], vec![1, 2, 3, 4]]), 2);\n assert_eq!(candidate(vec![vec![3, 3, 3], vec![4, 4, 4, 4]]), 3);\n}\n", "solution": "/// Write a rsthon function to find the length of the smallest vector in a vector of vectors.\nfn Find_Min_Length(lst: Vec>) -> isize {\n if lst.is_empty() {\n return 0;\n }\n\n let mut min_length = lst[0].len() as isize;\n\n for vec in lst.iter() {\n let length = vec.len() as isize;\n if length < min_length {\n min_length = length;\n }\n if min_length == 1 {\n break;\n }\n }\n\n min_length\n}", "is_solved": true, "reflections": ["The implementation is incorrect because it initializes the `min_length` variable with the maximum value of `isize`. This causes the function to return incorrect results when the smallest vector length is smaller than the maximum value of `isize`. In the failed test case, the smallest vector length is 1, but the function returns 1 as the minimum length instead of the expected 2.", "The implementation of the Find_Min_Length function is incorrect because it initializes the min_length variable with the length of the first vector in the input list. This causes the function to return an incorrect result when the smallest vector is the first one in the list, as it doesn't update the min_length variable correctly.", "The implementation is incorrect because it does not handle the case where the smallest vector is at the beginning or in the middle of the input vector. The function starts with the first vector's length as the minimum length and only updates it if a smaller length is found in the subsequent vectors, causing it to miss the smallest length if it's not at the end.", "The implementation is incorrect because it does not handle the case where the smallest vector has a length of 1. The function only updates the minimum length if the current vector's length is strictly less than the current minimum length, so it never updates when the smallest length is 1 and the initial minimum length is also 1."]} +{"name": "mbpp_399_bitwise_xor", "language": "rs", "prompt": "/// Write a function to perform the mathematical bitwise xor operation across the given tuples.\nfn bitwise_xor(test_tup1: (isize, isize, isize, isize), test_tup2: (isize, isize, isize, isize)) -> (isize, isize, isize, isize) {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_399_bitwise_xor.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "bitwise_xor", "test": "\n\nfn main() {\n let candidate = bitwise_xor;\n assert_eq!(candidate((10, 4, 6, 9), (5, 2, 3, 3)), (15, 6, 5, 10));\n assert_eq!(candidate((11, 5, 7, 10), (6, 3, 4, 4)), (13, 6, 3, 14));\n assert_eq!(candidate((12, 6, 8, 11), (7, 4, 5, 6)), (11, 2, 13, 13));\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to perform the mathematical bitwise xor operation across the given tuples.\nfn bitwise_xor(test_tup1: (isize, isize, isize, isize), test_tup2: (isize, isize, isize, isize)) -> (isize, isize, isize, isize) {\n let xor_tup1 = test_tup1.0 ^ test_tup2.0;\n let xor_tup2 = test_tup1.1 ^ test_tup2.1;\n let xor_tup3 = test_tup1.2 ^ test_tup2.2;\n let xor_tup4 = test_tup1.3 ^ test_tup2.3;\n\n (xor_tup1, xor_tup2, xor_tup3, xor_tup4)\n}"} +{"name": "mbpp_641_is_nonagonal", "language": "rs", "prompt": "/// Write a function to find the nth nonagonal number.\nfn is_nonagonal(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_641_is_nonagonal.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_nonagonal", "test": "\n\nfn main() {\n let candidate = is_nonagonal;\n assert_eq!(candidate(10), 325);\n assert_eq!(candidate(15), 750);\n assert_eq!(candidate(18), 1089);\n}\n", "solution": "/// Write a function to find the nth nonagonal number.\nfn is_nonagonal(n: isize) -> isize {\n if n <= 0 {\n return 0;\n }\n let nonagonal_number = n * (7 * n - 5) / 2;\n nonagonal_number\n}", "is_solved": true, "reflections": ["The implementation of the is_nonagonal function is incorrect because it uses the wrong formula to calculate nonagonal numbers. The formula used is `n * (7 * n - 5) / 2`, which produces incorrect results for the given test cases.", "The implementation of the is_nonagonal function is incorrect because it uses the wrong formula to calculate the nth nonagonal number. The formula used is `n * (5 * n - 3) / 2`, but it should be `n * (7 * n - 5) / 2`. This is causing the function to return incorrect results for the given test cases.", "The implementation of the is_nonagonal function is incorrect because it uses the wrong formula to calculate nonagonal numbers. The formula used is `n * (7 * n - 5) / 2`, but the correct formula should be `n * (5 * n - 3) / 2`. This is causing the function to return incorrect nonagonal numbers, as shown by the failed tests.", "The implementation of the is_nonagonal function is incorrect because it uses the wrong formula to calculate the nth nonagonal number. The formula used is `n * (5 * n - 3) / 2`, but it should be `n * (7 * n - 5) / 2`. This is causing the function to return incorrect results for the given test cases."]} +{"name": "mbpp_59_is_octagonal", "language": "rs", "prompt": "/// Write a function to find the nth octagonal number.\nfn is_octagonal(n: isize) -> isize {\n", "doctests": "transform", "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/mbpp-typed/mbpp_59_is_octagonal.py", "prompt_terminology": "reworded", "stop_tokens": ["\n}"], "entry_point": "is_octagonal", "test": "\n\nfn main() {\n let candidate = is_octagonal;\n assert_eq!(candidate(5), 65);\n assert_eq!(candidate(10), 280);\n assert_eq!(candidate(15), 645);\n}\n", "is_solved": true, "reflections": [], "solution": "/// Write a function to find the nth octagonal number.\nfn is_octagonal(n: isize) -> isize {\n if n <= 0 {\n return 0;\n }\n n * (3 * n - 2)\n}"}