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Added instructions for rust

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Mike Goelzer 2018-09-12 16:56:01 -07:00
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@ -32,7 +32,9 @@ node js-dht-test/index.js /ip4/127.0.0.1/tcp/9876/ipfs/QmehVYruznbyDZuHBV4vEHESp
**Directory**: `pubsub`
**What it demonstrates**: Two Go nodes are created and run a chat server using a shared PubSub topic. **TODO**: Should be a Go node and a JS node, once I get the two Go nodes version working.
**What it demonstrates**: Two Go peers, one JS peer, and one Rust peer are all created and run a chat server using a shared PubSub topic. Typing text in any peer sends it to all the other peers.
(**TODO**: eliminate centralized bootstrapper; any peer should be able to bootstrap from any other peer and peers should be able to start in any order)
**First terminal**: Create the bootstrapper node
@ -61,8 +63,20 @@ node index.js /ip4/127.0.0.1/tcp/9876/ipfs/QmehVYruznbyDZuHBV4vEHESpDevMoAovET6a
This JS peer will fire off a hello message every few seconds, which the other two subscribing nodes can see.
If you return to the second terminal and type a message, the bootstrapper and JS peers will both print that message.
**Fourth terminal**: Createa a Rust peer to connect to the bootstrap node and then subscribe and publish on the topic:
In short, you have a chat app on a private libp2p network.
```
cd pubsub/rust
cargo run /ip4/0.0.0.0/tcp/9879
# Wait for it to start up
/dial /ip4/127.0.0.1/tcp/9876
# Now type any message to publish
```
The Rust peer listens on the CLI-specified port (9879 in the above example), and then the `/dial` command causes it to dial out to the boostrap host. (TODO: rust-libp2p#471) It is now subscribed to the same topic as the other peers.
If you return to the second, third or fourth terminals and type a message, the bootstrapper and the other 2 peers will all print your message.
In short, you have a chat app on a private libp2p network using PubSub.
_Acknowledgements: @jhiesey for DHT (content & peer routing) JS+Go interop, @stebalien for PubSub_