new idiom: mem::replace

pull/31/head
Andre Bogus 8 years ago
parent 3d748b1adc
commit 31b282ad9f

@ -0,0 +1,83 @@
# `mem::replace` to keep owned values in changed enums
## Description
Say we have a `&mut MyEnum` which has (at least) two variants,
`A { name: String, x: u8 }` and `B { name: String }`. Now we want to change
`MyEnum::A` to a `B` if `x` is zero, while keeping `MyEnum::B` intact.
We can do this without cloning the `name`.
## Example
```rust
use std::mem;
fn a_to_b(e: &mut MyEnum) {
// we mutably borrow `e` here. This precludes us from changing it directly
// as in `*e = ...`, because the borrow checker won't allow it. Of course
// we could just take a reference to `name` and clone that, but why pay an
// extra allocation for something we already have?
let have_name = match *e {
MyEnum::A(ref mut name, x) if x == 0 => {
// this takes out our `name` and put in an empty String instead
// note that empty strings don't allocate
Some(mem::replace(name, "".to_string()))
}
// nothing to do in all other cases
_ => None
};
// the mutable borrow ends here, so we can change `e`
if let Some(name) = have_name { *e = MyEnum::B { name } }
}
```
## Motivation
When working with enums, we may want to change an enum value in place, perhaps
to another variant. This is usually done in two phases to keep the borrow
checker happy. In the first phase, we observe the existing value and look at
its parts to decide what to do next. In the second phase we may conditionally
change the value (as in the example above).
The borrow checker won't allow us to take out `name` of the enum (because
*something* must be there. We could of course `.clone()` name and put the clone
into our `MyEnum::B`, but that would be an instance of the [Clone to satisfy
the borrow checker] antipattern. Anyway, we can avoid the extra allocation by
changing `e` with only a mutable borrow.
`mem::replace` lets us swap out the value, replacing it with something else. In
this case, we put in an empty `String`, which does not need to allocate. As a
result, we get the original `name` *as an owned value*. We can wrap this in
an `Option` or another enum that we can destructure in the next step to put the
contained values into our mutably borrowed enum.
## Advantages
Look ma, no allocation! Also you may feel like Indiana Jones while doing it.
## Disadvantages
This gets a bit wordy. Getting it wrong repeatedly will make you hate the
borrow checker. The compiler may fail to optimize away the double store,
resulting in reduced performance as opposed to what you'd do in unsafe
languages.
## Discussion
This pattern is only of interest in Rust. In GC'd languages, you'd take the
reference to the value by default (and the GC would keep track of refs), and in
other low-level languages like C you'd simply alias the pointer and fix things
later.
However, in Rust, we have to do a little more work to do this. An owned value
may only have one owner, so to take it out, we need to put something back in
like Indiana Jones, replacing the artifact with a bag of sand.
## See also
This gets rid of the [Clone to satisfy the borrow checker] antipattern in a
specific case.
[Clone to satisfy the borrow checker]()
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