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PHP HTTP server
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plugins/php/phphttp.fish
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87
plugins/php/phphttp.fish
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# PHP HTTP server.
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function phphttp
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set -l port 8000
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set -l path
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set -l host 127.0.0.1
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# Ignore argument for slice.
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set argv $argv ignore
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# Process options. I think that fish should have some builtin for
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# option parsing, but it doesn't.
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while count $argv > /dev/null
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set -l option $argv[1]
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switch $option
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# When two hyphens appear, stop processing, while removing
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# hyphens from $argv.
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case --
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set argv $argv[2..-1]
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break
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# Public mode.
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case -p\* --p --pu --pub --publ --publi --public p public
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if test $host = 0
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echo phphttp: Duplicate option --public >&2
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end
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set host 0
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# Help.
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case -h\* --h --he --hel --help '-\?' h help
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echo 'phphttp [--public] <port=8000> <path=.>'
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return
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# Anything else stops processing.
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case \*
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break
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end
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# Check if the option was one letter.
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switch $option
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case --\*
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# Doesn't count as single option
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case -\?\?\*
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set argv[1] -(expr substr $argv[1] 3 length $argv[1])
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continue
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end
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set argv $argv[2..-1]
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end
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if test (count $argv[1..-1]) -ge 4
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echo 'phphttp: Expected up to two arguments, got '(math (count $argv) - 1)'.' >&2
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return
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end
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# argv is bigger by 1 because of "ignore" argument.
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if test (count $argv) -ge 2
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# Check legality of first argument
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switch $argv[1]
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# Fine values
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case {0,1,2,3,4,5,6,7,8,9}\*
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# Do nothing
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case \*
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# The dev team thinks of everything. Or something.
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if test -d $argv[1]
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if test (count $argv) -eq 2
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echo "phphttp: directory specified without port." >&2
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else
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echo "phphttp: swapped directory and port arguments." >&2
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end
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return
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else
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echo "phphttp: $argv[1] is not a port." >&2
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return
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end
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end
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set port $argv[1]
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end
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if test (count $argv) -eq 3
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set path -t$argv[2]
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end
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php -S$host:$port $path
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end
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