{ "cells": [ { "cell_type": "markdown", "metadata": {}, "source": [ "# LLM Symbolic Math \n", "This notebook showcases using LLMs and Python to Solve Algebraic Equations." ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "### Calculating the limit of an equation" ] }, { "cell_type": "code", "execution_count": 18, "metadata": {}, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "\n", "\n", "\u001b[1m> Entering new LLMSymbolicMathChain chain...\u001b[0m\n", "What is the limit of sin(x) / x as x goes to 0?\u001b[32;1m\u001b[1;3mAnswer: 1\u001b[0m\n", "\u001b[1m> Finished chain.\u001b[0m\n" ] }, { "data": { "text/plain": [ "'Answer: 1'" ] }, "execution_count": 18, "metadata": {}, "output_type": "execute_result" } ], "source": [ "from langchain.llms import OpenAI\n", "from langchain.chains.llm_symbolic_math.base import LLMSymbolicMathChain\n", "\n", "llm = OpenAI(temperature=0)\n", "llm_symbolic_math = LLMSymbolicMathChain.from_llm(llm, verbose=True)\n", "\n", "llm_symbolic_math.run(\"What is the limit of sin(x) / x as x goes to 0?\")" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "### Calculating an integral" ] }, { "cell_type": "code", "execution_count": 19, "metadata": {}, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "\n", "\n", "\u001b[1m> Entering new LLMSymbolicMathChain chain...\u001b[0m\n", "What is the integral of e^-x from 0 to infinity?\u001b[32;1m\u001b[1;3mAnswer: 1\u001b[0m\n", "\u001b[1m> Finished chain.\u001b[0m\n" ] }, { "data": { "text/plain": [ "'Answer: 1'" ] }, "execution_count": 19, "metadata": {}, "output_type": "execute_result" } ], "source": [ "llm_symbolic_math.run(\"What is the integral of e^-x from 0 to infinity?\")" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "### Calculating an algebraic equation" ] }, { "cell_type": "code", "execution_count": 20, "metadata": {}, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "\n", "\n", "\u001b[1m> Entering new LLMSymbolicMathChain chain...\u001b[0m\n", "What are the solutions to this equation x**2 - x?\u001b[32;1m\u001b[1;3mAnswer: 0 and 1.\u001b[0m\n", "\u001b[1m> Finished chain.\u001b[0m\n" ] }, { "data": { "text/plain": [ "'Answer: 0 and 1.'" ] }, "execution_count": 20, "metadata": {}, "output_type": "execute_result" } ], "source": [ "llm_symbolic_math.run(\"What are the solutions to this equation x**2 - x?\")" ] }, { "cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": [] } ], "metadata": { "kernelspec": { "display_name": "Python 3 (ipykernel)", "language": "python", "name": "python3" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 3 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython3", "version": "3.11.4" } }, "nbformat": 4, "nbformat_minor": 2 }