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fix issue #8357 by making json backtick regex greedy (#8528)

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- Description: Markdown code blocks in json response should not break
the parser
  - Issue: #8357

@baskaryan @hinthornw
This commit is contained in:
Bruno Bornsztein 2023-07-31 18:36:57 -05:00 committed by GitHub
parent 64d0a0fcc0
commit 5a490a79f4
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GPG Key ID: 4AEE18F83AFDEB23
2 changed files with 12 additions and 1 deletions
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2
libs/langchain/langchain/output_parsers/json.py
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@ -19,7 +19,7 @@ def parse_json_markdown(json_string: str) -> dict:
The parsed JSON object as a Python dictionary.
"""
# Try to find JSON string within triple backticks
match = re.search(r"```(json)?(.*?)```", json_string, re.DOTALL)
match = re.search(r"```(json)?(.*)```", json_string, re.DOTALL)
# If no match found, assume the entire string is a JSON string
if match is None:

11
libs/langchain/tests/unit_tests/output_parsers/test_json.py
View File

@ -54,6 +54,12 @@ TICKS_WITH_NEW_LINES_EVERYWHERE = """
"""
JSON_WITH_MARKDOWN_CODE_BLOCK = """```json
{
"foo": "```bar```"
}
```"""
NO_TICKS = """{
"foo": "bar"
}"""
@ -106,3 +112,8 @@ TEST_CASES = [
def test_parse_json(json_string: str) -> None:
parsed = parse_json_markdown(json_string)
assert parsed == {"foo": "bar"}
def test_parse_json_with_code_block() -> None:
parsed = parse_json_markdown(JSON_WITH_MARKDOWN_CODE_BLOCK)
assert parsed == {"foo": "```bar```"}