Archives/easy_rust
2
0
Fork 0
mirror of https://github.com/Dhghomon/easy_rust synced 2024-11-15 18:13:23 +00:00
Code Issues Packages Projects Releases Wiki Activity

Merge pull request #66 from Arcadie/fix-typos

Browse Source 
Fix minor typos and code snippet comments
This commit is contained in:
Dhghomon 2020-08-18 22:41:01 +09:00 committed by GitHub
commit 706129e61a
No known key found for this signature in database
GPG Key ID: 4AEE18F83AFDEB23
1 changed files with 4 additions and 4 deletions
Show Stats Download Patch File Download Diff File Expand all files Collapse all files

8
README.md
View File

@ -11509,7 +11509,7 @@ fn main() {
This will print `You will live in Kiev`. This will print `You will live in Kiev`.
`unreachable!()` is also nice for the programmer because it reminds you that some part of the code is unreachable. And of course, if it's not unreachable and the compiler calls `.unreachable()`, the program will panic. `unreachable!()` is also nice for the programmer because it reminds you that some part of the code is unreachable. And of course, if it's not unreachable and the compiler calls `unreachable!()`, the program will panic.
Also, if you ever have unreachable code that the compiler knows about, it will tell you. Here is a quick example: Also, if you ever have unreachable code that the compiler knows about, it will tell you. Here is a quick example:
@ -11679,7 +11679,7 @@ Now that we are using Rust on the computer, we can start working with files. You
You might remember that if you want to use the `?` operator, it has to return a `Result` in the function it is in. If you can't remember the error type, you can just give it nothing and let the compiler tell you. Let's try that with a function that tries to make a number with `.parse()`. You might remember that if you want to use the `?` operator, it has to return a `Result` in the function it is in. If you can't remember the error type, you can just give it nothing and let the compiler tell you. Let's try that with a function that tries to make a number with `.parse()`.
```rust ```rust
`` ⚠️ // ⚠️
fn give_number(input: &str) -> Result<i32, ()> { fn give_number(input: &str) -> Result<i32, ()> {
input.parse::<i32>() input.parse::<i32>()
} }
@ -11730,7 +11730,7 @@ Ok(5)
So now we want to use `?` to just give us the value if it works, and the error if it doesn't. But how to do this in `fn main()`? If we try to use `?` in main, it won't work. So now we want to use `?` to just give us the value if it works, and the error if it doesn't. But how to do this in `fn main()`? If we try to use `?` in main, it won't work.
```rust ```rust
`` ⚠️ // ⚠️
use std::num::ParseIntError; use std::num::ParseIntError;
fn give_number(input: &str) -> Result<i32, ParseIntError> { fn give_number(input: &str) -> Result<i32, ParseIntError> {
@ -11913,7 +11913,7 @@ If you go to [the page for OpenOptions](https://doc.rust-lang.org/std/fs/struct.
Then at the end you use `.open()` with the file name, and that will give you a `Result`. Let's look at one example: Then at the end you use `.open()` with the file name, and that will give you a `Result`. Let's look at one example:
```rust ```rust
`` ⚠️ // ⚠️
use std::fs; use std::fs;
use std::fs::OpenOptions; use std::fs::OpenOptions;