Disable threaded rendering when showing widget outlines

Because these are drawn outside the window boundary, so it is not
technically thread-safe due to non-deterministic drawing order
pull/647/head
Jonathan G Rennison 3 months ago
parent 16589041f2
commit b2b96fff13

@ -3965,7 +3965,8 @@ void ViewportDoDraw(Viewport *vp, int left, int top, int right, int bottom, uint
}
_viewport_drawer_jobs++;
if (unlikely(HasBit(_viewport_debug_flags, VDF_DISABLE_THREAD))) {
extern bool _draw_widget_outlines;
if (unlikely(_draw_widget_outlines || HasBit(_viewport_debug_flags, VDF_DISABLE_THREAD))) {
ViewportDoDrawRenderJob(vp, _vdd.release());
} else {
_general_worker_pool.EnqueueJob([](void *data1, void *data2, void *data3) {
@ -4021,7 +4022,8 @@ static void ViewportDoDrawRenderJob(Viewport *vp, ViewportDrawerDynamic *vdd)
vdd->draw_jobs_active.store((uint)vdd->parent_sprite_sets.size(), std::memory_order_relaxed);
for (uint i = 1; i < (uint)vdd->parent_sprite_sets.size(); i++) {
if (unlikely(HasBit(_viewport_debug_flags, VDF_DISABLE_THREAD))) {
extern bool _draw_widget_outlines;
if (unlikely(_draw_widget_outlines || HasBit(_viewport_debug_flags, VDF_DISABLE_THREAD))) {
ViewportDoDrawRenderSubJob(vp, vdd, i);
} else {
_general_worker_pool.EnqueueJob([](void *data1, void *data2, void *data3) {

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