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(svn r21919) -Fix: Converting an expensive rail type to a cheap one could give more money than removing and rebuilding cost

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planetmaker 2011-01-27 00:38:12 +00:00
parent 62e5afcdf8
commit 5e82fee690
1 changed files with 14 additions and 18 deletions
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32
src/rail.h
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@ -337,26 +337,22 @@ static inline Money RailClearCost(RailType railtype)
*/
static inline Money RailConvertCost(RailType from, RailType to)
{
/* rail -> el. rail
* calculate the price as 5 / 4 of (cost build el. rail) - (cost build rail)
* (the price of workers to get to place is that 1/4)
*/
if (HasPowerOnRail(from, to)) {
Money cost = ((RailBuildCost(to) - RailBuildCost(from)) * 5) >> 2;
if (cost != 0) return cost;
/* Get the costs for removing and building anew
* A conversion can never be more costly */
Money rebuildcost = RailBuildCost(to) + RailClearCost(from);
/* Conversion between somewhat compatible railtypes:
* Pay 1/8 of the target rail cost (labour costs) and additionally any difference in the
* build costs, if the target type is more expensive (material upgrade costs).
* Upgrade can never be more expensive than re-building. */
if (HasPowerOnRail(from, to) || HasPowerOnRail(to, from)) {
Money upgradecost = RailBuildCost(to) / 8 + max((Money)0, RailBuildCost(to) - RailBuildCost(from));
return min(upgradecost, rebuildcost);
}
/* el. rail -> rail
* calculate the price as 1 / 4 of (cost build el. rail) - (cost build rail)
* (the price of workers is 1 / 4 + price of copper sold to a recycle center)
*/
if (HasPowerOnRail(to, from)) {
Money cost = (RailBuildCost(from) - RailBuildCost(to)) >> 2;
if (cost != 0) return cost;
}
/* make the price the same as remove + build new type */
return RailBuildCost(to) + RailClearCost(from);
/* make the price the same as remove + build new type for rail types
* which are not compatible in any way */
return rebuildcost;
}
void DrawTrainDepotSprite(int x, int y, int image, RailType railtype);