LinkedList Find Length Source

[What It Is](#what-it-is) ## What It Is For example, the function should return 5 for linked list `[1 -> 3 -> 1 -> 2 -> 1]` ![Preview Thumbnail](https://raw.githubusercontent.com/Dentrax/Data-Structures-with-Go/master/linked-list-find-length/resources/find-length.png) METHOD 1 (Iterative Solution) -------------------------- * 1) Initialize count as 0 * 2) Initialize a node pointer, current = head. * 3) Do following while current is not NULL a) current = current -> next b) count++; * 4) Return count > * Input: Linked List = `[1 -> 3 -> 1 -> 2 -> 1]` > * Output: count of nodes is `5` **Algorithm Complexity** | Complexity | Notation | | ----------------- |:---------:| | `Time Complexity` | `O(n)` |